Unit 11 — Acids and bases
Intro video — Recognizing, defining, and naming acids and bases

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Lesson 1 of 45 · ABS-001

What acids are like
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Wonder this:

Bite into a lemon wedge and your mouth puckers. Splash vinegar onto a salad and the same sharp tang hits. Two very different foods, one identical jolt — something the two share is causing it.

This unit is about that shared something. The first step is learning the three behaviors that give the family away.

The idea

Lemon juice and vinegar taste sour because each contains an 'acid'.

Acids share three observable properties.

First property: foods that contain an acid taste sour.

The acid property profile

PropertyWhat you observe
Taste, in foodssour
Blue litmus paper — a dye-coated test stripturns red
Active metal, such as zincbubbles of hydrogen gas form
Three observable properties shared by acids.

Second property: acids change the color of 'litmus paper' — a test strip coated with a plant dye.

Dip blue litmus paper into an acid and the paper turns red.

Third property: an acid reacts with an active metal, such as zinc or magnesium, and the reaction releases hydrogen gas.

You will see the hydrogen as streams of gas bubbles rising off the metal.

The taste facts here describe everyday foods only — laboratory acids are never tasted or touched, because they can burn skin and eyes.

Worked examples

Worked example 1. Grapefruit juice makes your lips pucker with a sour taste. What does the sour taste tell you the juice contains?

Step 1

Answer: an acid.

Worked example 2. A drop of an acid solution lands on blue litmus paper. What color does the paper turn?

Step 1

Answer: red.

You can now state the shared observable properties of acids: foods containing them taste sour, they turn blue litmus paper red, and they react with active metals to release hydrogen gas.

Check your understanding

Foods that contain an acid share which taste?

ASourcorrect
BSalty
This option is wrong — you matched the taste of table salt — saltiness is not part of the acid profile; foods containing an acid taste sour.
CSweet
This option is wrong — you matched the taste of sugar — sweetness is not part of the acid profile; foods containing an acid taste sour.
DMetallic
This option is wrong — you borrowed from the metal reaction — acids react with active metals, but the taste of acid-containing foods is sour.
The first line of the acid profile is taste: foods that contain an acid taste sour. Lemon juice and vinegar are the everyday examples.
Check your understanding

An acid is tested with litmus paper. Which result shows the acid at work?

ABlue litmus paper turns red.correct
BBlue litmus paper stays blue.
This option is wrong — you expected no change — an acid actively changes the strip, turning blue litmus red.
CBlue litmus paper turns colorless.
This option is wrong — you had the dye bleach away — litmus swaps color, and in an acid the blue strip turns red.
DRed litmus paper turns colorless.
This option is wrong — you had the dye bleach away — litmus swaps color rather than losing it; the acid response is blue litmus turning red.
Litmus paper is a test strip coated with a plant dye. Dip blue litmus paper into an acid and the paper turns red.
Check your understanding

A piece of magnesium ribbon is dropped into an acid solution, and bubbles of gas stream off the metal. Which gas is being released?

AHydrogencorrect
BOxygen
This option is wrong — you picked the wrong gas — the gas an acid releases from an active metal is hydrogen.
CCarbon dioxide
This option is wrong — you recalled the fizz of a soft drink — carbon dioxide is a different fizz; an acid on an active metal releases hydrogen.
DWater vapor
This option is wrong — you treated the bubbles as boiling — the bubbles are a new gas made by the reaction: hydrogen.
An acid reacts with an active metal such as magnesium. The reaction releases hydrogen gas, which you see as bubbles streaming off the metal.

Lesson 2 of 45 · ABS-002

What bases are like
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You have seen the three-property profile that gives acids away. A second family of substances has its own profile — in one way the mirror image of the acids'.

The idea

Soapy water feels slippery because it contains a 'base'.

Bases share three observable properties.

First property: foods that contain a base taste bitter — unsweetened cocoa owes its bitterness to bases.

The base property profile

PropertyWhat you observe
Taste, in foodsbitter
Feel of the solutionslippery
Red litmus paperturns blue
Three observable properties shared by bases.

Second property: a solution of a base feels slippery between the fingers, the way soapy water does.

Third property: a base turns red litmus paper blue — the reverse of the acid response.

As with acids, the taste and feel facts describe everyday foods and household materials — laboratory bases are never tasted or touched, because they can burn skin and eyes.

Worked examples

Worked example 1. Milk of magnesia, an upset-stomach remedy, tastes bitter. What does the bitter taste tell you it contains?

Step 1

Answer: a base.

Worked example 2. A drop of a base solution lands on red litmus paper. What color does the paper turn?

Step 1

Answer: blue.

You can now state the shared observable properties of bases: foods containing them taste bitter, their solutions feel slippery, and they turn red litmus paper blue.

Check your understanding

Foods that contain a base share which taste?

ABittercorrect
BSour
This option is wrong — you swapped the two taste profiles — sour signals an acid; foods containing a base taste bitter.
CSweet
This option is wrong — you matched the taste of sugar — sweetness belongs to neither profile; foods containing a base taste bitter.
DSalty
This option is wrong — you matched the taste of table salt — saltiness belongs to neither profile; foods containing a base taste bitter.
The first line of the base profile is taste: foods that contain a base taste bitter. Unsweetened cocoa is the everyday example.
Check your understanding

A dish-soap solution is rubbed between gloved fingers. Which base-profile property is being felt?

AIts slippery feelcorrect
BIts sour taste
This option is wrong — you reached for the acid profile — and for a taste, when the test described is touch; the base property felt here is slipperiness.
CIts color change
This option is wrong — you reached for the litmus line — no test strip is involved; the property felt between the fingers is the slippery feel.
DIts release of gas bubbles
This option is wrong — you borrowed the acid-metal reaction — releasing hydrogen from metals is an acid property, and the base property here is the slippery feel.
A solution of a base feels slippery between the fingers. Soapy water is the everyday example of that feel.
Check your understanding

A base is tested with litmus paper. Which result shows the base at work?

ARed litmus paper turns blue.correct
BBlue litmus paper turns red.
This option is wrong — you gave the acid response — a base works in the reverse direction, turning red litmus blue.
CRed litmus paper stays red.
This option is wrong — you expected no change — a base actively changes the strip, turning red litmus blue.
DRed litmus paper turns colorless.
This option is wrong — you had the dye bleach away — litmus swaps between red and blue; in a base the red strip turns blue.
A base turns red litmus paper blue. That is the reverse of the acid response, which turns blue litmus red.

Lesson 3 of 45 · ABS-003

Acid or base from properties
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Wonder this:

A storeroom shelf holds an unlabeled bottle of clear liquid. You cannot taste it, and you must not touch it. The two property profiles can still identify it.

You have seen the acid profile and the base profile. This lesson uses them to classify a substance from its observed behavior.

The idea

Classify an unknown by matching its observed properties against the two profiles.

A sour taste in a food points to an acid.

Matching observations to the two profiles

ObservationPoints to
sour taste, in foodsan acid
bitter taste, in foodsa base
blue litmus paper turns redan acid
red litmus paper turns bluea base
solution feels slipperya base
hydrogen gas from an active metalan acid
Each profile observation points to one family.

A bitter taste in a food points to a base.

Turning blue litmus paper red points to an acid.

Turning red litmus paper blue points to a base.

A slippery feel points to a base.

Releasing hydrogen gas from an active metal points to an acid.

One clear profile observation is enough — a solution that turns blue litmus paper red is an acid.

Worked examples

Worked example 1. A drain-clearing solution feels slippery through gloves and turns red litmus paper blue. Classify it.

Step 1

A slippery feel points to a base.

Step 2

Turning red litmus paper blue points to a base.

Step 3

Both observations sit in the base profile, so the solution is a base.

Worked example 2. A rust-removing liquid poured over a strip of zinc makes bubbles of hydrogen gas stream off the metal. Classify the liquid.

Step 1

Releasing hydrogen gas from an active metal points to an acid.

Step 2

The liquid is an acid.

You can now classify a substance as an acid or a base from a supplied set of observed properties.

Check your understanding

A glass cleaner turns red litmus paper blue. Classify the cleaner.

AA basecorrect
BAn acid
This option is wrong — you swapped the litmus directions — turning red litmus blue is the base observation; an acid turns blue litmus red.
CBoth an acid and a base
This option is wrong — you stacked the profiles — the observation sits in one profile only, the base's.
DNeither an acid nor a base
This option is wrong — you dismissed the observation — turning red litmus blue is a profile observation, and one clear observation is enough to classify.
Match the observation to a profile. Turning red litmus paper blue points to a base. One clear profile observation is enough, so the cleaner is a base.
Check your understanding

The table shows one observation for each of four solutions, W, X, Y, and Z. Which solution is an acid?

Observations of four solutions

SolutionObservation
Wfeels slippery through gloves
Xturns blue litmus paper red
Ychanges neither litmus color
Zturns red litmus paper blue
ASolution Xcorrect
BSolution W
This option is wrong — you filed the slippery feel under acids — a slippery feel points to a base.
CSolution Y
This option is wrong — you classified from no change — a solution that changes neither litmus color has shown no profile observation at all.
DSolution Z
This option is wrong — you swapped the litmus directions — red litmus turning blue points to a base; the acid observation is blue litmus turning red.
Read each row against the profiles. Solution X turns blue litmus paper red, and that observation points to an acid. W is slippery (a base), Z turns red litmus blue (a base), and Y shows no profile observation.
Check your understanding

A pickling liquid drizzled on a salad tastes sharply sour. Classify the substance behind the taste.

AAn acidcorrect
BA base
This option is wrong — you swapped the taste lines — bitter is the base taste; a sour taste in a food points to an acid.
CBoth an acid and a base
This option is wrong — you stacked the profiles — sourness sits in one profile only, the acid's.
DNeither an acid nor a base
This option is wrong — you dismissed the observation — a sour taste in a food is a profile observation, and one clear observation is enough to classify.
Match the observation to a profile. A sour taste in a food points to an acid. So the pickling liquid contains an acid.

Lesson 4 of 45 · ABS-004

Common acids
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You have seen what acids do. Four particular acids appear so often — in stomachs, garages, factories, and kitchens — that their names and formulas are worth memorizing now.

The idea

'Hydrochloric acid' is HCl — the acid your stomach makes to digest food.

'Sulfuric acid' is H₂SO₄ — the acid inside car batteries.

Four common acids

NameFormulaWhere you meet it
hydrochloric acidHClstomach acid
sulfuric acidH₂SO₄car batteries
nitric acidHNO₃fertilizer manufacture
acetic acidCH₃COOHvinegar
The four common acids of this course: name, formula, and one everyday use.

'Nitric acid' is HNO₃ — used in huge amounts to make fertilizers.

'Acetic acid' is CH₃COOH — the acid that gives vinegar its sour taste.

Three of the four formulas begin with H; acetic acid's formula is the odd one out, written CH₃COOH.

Bottled laboratory acids like these are never tasted or touched — the vinegar fact is about food, not lab bottles.

Worked examples

Worked example 1. Which acid is inside a car battery, and what is its formula?

Step 1

Answer: sulfuric acid, H₂SO₄.

Worked example 2. What is the name of the acid CH₃COOH?

Step 1

Answer: acetic acid — the acid in vinegar.

You can now state the name, formula, and a common use for each of the common acids hydrochloric acid (HCl), sulfuric acid (H₂SO₄), nitric acid (HNO₃), and acetic acid (CH₃COOH).

Check your understanding

Write the chemical formula of sulfuric acid.

Accepted answer: H₂SO₄
Sulfuric acid is H₂SO₄ — two hydrogens, one sulfur, four oxygens. It is the acid inside car batteries.
Check your understanding

Which acid does your stomach make to digest food?

AHydrochloric acid, HClcorrect
BSulfuric acid, H₂SO₄
This option is wrong — you matched the wrong roster row — sulfuric acid is the car-battery acid; the stomach makes hydrochloric acid, HCl.
CNitric acid, HNO₃
This option is wrong — you matched the wrong roster row — nitric acid is the fertilizer-making acid; the stomach makes hydrochloric acid, HCl.
DAcetic acid, CH₃COOH
This option is wrong — you matched the wrong roster row — acetic acid is the vinegar acid; the stomach makes hydrochloric acid, HCl.
Hydrochloric acid, HCl, is the acid your stomach makes to digest food.
Check your understanding

What is the name of the acid with the formula HNO₃?

ANitric acidcorrect
BHydrochloric acid
This option is wrong — you matched the wrong roster row — hydrochloric acid is HCl; HNO₃ is nitric acid.
CSulfuric acid
This option is wrong — you matched the wrong roster row — sulfuric acid is H₂SO₄; HNO₃ is nitric acid.
DAcetic acid
This option is wrong — you matched the wrong roster row — acetic acid is CH₃COOH; HNO₃ is nitric acid.
HNO₃ is nitric acid — one hydrogen, one nitrogen, three oxygens. It is used in huge amounts to make fertilizers.

Lesson 5 of 45 · ABS-005

Common bases
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You have seen the four common acids. Four common bases are worth memorizing the same way — name, formula, and one place you meet each.

The idea

'Sodium hydroxide' is NaOH — the base in drain cleaners.

'Potassium hydroxide' is KOH — used to make liquid soaps.

Four common bases

NameFormulaWhere you meet it
sodium hydroxideNaOHdrain cleaners
potassium hydroxideKOHliquid soaps
calcium hydroxideCa(OH)₂slaked lime for acidic soil
ammoniaNH₃glass cleaners
The four common bases of this course: name, formula, and one everyday use.

'Calcium hydroxide' is Ca(OH)₂ — sold as slaked lime and spread on fields to treat overly acidic soil.

'Ammonia' is NH₃ — the base in many glass cleaners.

Three of the four are metal hydroxides — a metal paired with OH; ammonia is the odd one out, with no metal and no OH in its formula.

Drain cleaner and the other products owe their power to these bases — never touch them, because they burn skin and eyes.

Worked examples

Worked example 1. What is the name of the base Ca(OH)₂?

Step 1

Answer: calcium hydroxide — slaked lime.

Worked example 2. Which of the four common bases contains no metal?

Step 1

Answer: ammonia, NH₃.

You can now state the name, formula, and a common use for each of the common bases sodium hydroxide (NaOH), potassium hydroxide (KOH), calcium hydroxide (Ca(OH)₂), and ammonia (NH₃).

Check your understanding

Write the chemical formula of sodium hydroxide.

Accepted answer: NaOH
Sodium hydroxide is NaOH — sodium paired with the hydroxide unit, OH. It is the base in drain cleaners.
Check your understanding

Which base is spread on farm fields as slaked lime to treat overly acidic soil?

ACalcium hydroxide, Ca(OH)₂correct
BSodium hydroxide, NaOH
This option is wrong — you matched the wrong roster row — sodium hydroxide is the drain-cleaner base; slaked lime is calcium hydroxide, Ca(OH)₂.
CPotassium hydroxide, KOH
This option is wrong — you matched the wrong roster row — potassium hydroxide is the liquid-soap base; slaked lime is calcium hydroxide, Ca(OH)₂.
DAmmonia, NH₃
This option is wrong — you matched the wrong roster row — ammonia is the glass-cleaner base; slaked lime is calcium hydroxide, Ca(OH)₂.
Calcium hydroxide, Ca(OH)₂, is sold as slaked lime. Farmers spread it on fields to treat overly acidic soil.
Check your understanding

What is the name of the base with the formula NH₃?

AAmmoniacorrect
BNitric acid
This option is wrong — you matched the other nitrogen compound — HNO₃ is nitric acid; the base NH₃ is ammonia.
CSodium hydroxide
This option is wrong — you matched the wrong roster row — sodium hydroxide is NaOH; NH₃ is ammonia.
DPotassium hydroxide
This option is wrong — you matched the wrong roster row — potassium hydroxide is KOH; NH₃ is ammonia.
NH₃ is ammonia — the base in many glass cleaners. It is the odd one out of the four: no metal and no OH in its formula.

Lesson 6 of 45 · ABS-006

Acid or base from a formula
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You have seen four common acids and four common bases by name. Their formulas follow patterns you can use on compounds you have never met.

The idea

Look at where hydrogen sits in the formula.

An acid's formula is written with H first — HCl, H₂SO₄, and HNO₃ all lead with hydrogen.

Reading a formula as acid or base

What the formula showsClassificationExamples
H written firstacidHCl, HNO₃
ends in OHbaseKOH, Ca(OH)₂
memorized exceptionH₂O is neitherH₂O
memorized exceptionNH₃ is a baseNH₃
Two patterns and two memorized exceptions.

A common base's formula ends in OH — NaOH, KOH, and Ca(OH)₂ all finish with the hydroxide unit.

A formula like Ca(OH)₂ still counts as ending in OH — the subscript outside the parentheses just counts the OH units.

Two formulas break the patterns, and you memorize them.

H₂O is written with H first but is not an acid — it is just water.

NH₃ does not end in OH, but it is a base — ammonia.

Worked examples

Worked example 1. Identify H₂S as an acid or a base from its formula.

Step 1

The formula is written with H first, and H₂S is not one of the two memorized exceptions.

Step 2

H₂S is an acid.

Worked example 2. Identify Ba(OH)₂ as an acid or a base from its formula.

Step 1

The formula ends in OH — the subscript 2 outside the parentheses counts two OH units.

Step 2

Ba(OH)₂ is a base.

You can now identify a compound as an acid or a base from its formula, using the pattern that acid formulas are written with H first and common base formulas end in OH, with water (H₂O) and ammonia (NH₃) named as the exceptions to memorize.

Check your understanding

Which of these four formulas belongs to an acid?

AHIcorrect
BLiOH
This option is wrong — you matched the wrong pattern — a formula ending in OH belongs to a base; the acid pattern is H written first, as in HI.
CNH₃
This option is wrong — you misfiled an exception — NH₃ is the memorized base; the acid here is the H-first formula HI.
DH₂O
This option is wrong — you applied the H-first pattern to the memorized exception — H₂O is just water, neither an acid nor a base.
The acid pattern: the formula is written with H first. HI leads with hydrogen and is not an exception, so HI is an acid. LiOH ends in OH (a base), NH₃ is the memorized base, and H₂O is the memorized neither.
Check your understanding

Which of these four formulas belongs to a base?

ASr(OH)₂correct
BH₂CO₃
This option is wrong — you matched the wrong pattern — H₂CO₃ is written with H first, which marks an acid.
CHF
This option is wrong — you matched the wrong pattern — HF is written with H first, which marks an acid.
DH₂O
This option is wrong — you promoted the memorized exception — H₂O is just water, neither an acid nor a base.
The base pattern: the formula ends in OH. Sr(OH)₂ ends in OH — the subscript 2 just counts the two OH units — so it is a base. H₂CO₃ and HF lead with hydrogen (acids), and H₂O is the memorized neither.
Check your understanding

Two formulas: HCN and CsOH. Which classification pair is correct?

AHCN is an acid and CsOH is a base.correct
BHCN is a base and CsOH is an acid.
This option is wrong — you swapped the two patterns — H written first marks the acid (HCN), and ending in OH marks the base (CsOH).
CHCN and CsOH are both acids.
This option is wrong — you counted CsOH's hydrogen as acid-marking — the H in CsOH sits inside the OH ending, which marks a base.
DHCN and CsOH are both bases.
This option is wrong — you filed the H-first formula as a base — HCN leads with hydrogen, which marks an acid.
Apply each pattern separately. HCN is written with H first, so HCN is an acid. CsOH ends in OH, so CsOH is a base.

Lesson 7 of 45 · ABS-007

Arrhenius acids
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Wonder this:

Lemon juice, vinegar, and the digestive juice in your stomach come from completely different places and have completely different formulas. Yet all three show the same property profile. Identical behavior from different substances needs a shared cause.

You have seen the acid property profile, and you have seen how dissolved compounds split into ions in water. Those two ideas meet here.

The idea

Dissolve HCl in water and it splits into two ions: H⁺ and Cl⁻.

The equation is HCl → H⁺ + Cl⁻.

A two-panel particle diagram. In the first panel an HCl unit sits among water molecules. In the second panel it has split into a labeled H plus ion and a labeled Cl minus ion. The equation HCl gives H plus and Cl minus appears beneath.An acid releasing ions in waterHCl dissolving in waterHClthe released ionsH⁺Cl⁻HCl → H⁺ + Cl⁻
In water, HCl splits into H⁺ and Cl⁻. The released H⁺ is the source of the shared acid properties.

Dissolve any acid in water and the same kind of thing happens: it releases hydrogen ions, H⁺.

A hydrogen ion is a hydrogen atom that has lost its one electron, leaving a particle with a 1+ charge.

The Swedish chemist Svante Arrhenius made this the definition: an 'Arrhenius acid' is a substance that releases hydrogen ions (H⁺) when it dissolves in water.

The released H⁺ is the same particle no matter which acid it came from.

That is why every acid shows the same property profile — the H⁺ itself is the source of the shared properties.

Worked examples

Worked example 1. Nitric acid, HNO₃, dissolves in water. Which two ions does it release?

Step 1

Answer: H⁺ and NO₃⁻ — the nitrate ion.

Worked example 2. Why does every acid solution turn blue litmus paper red?

Step 1

Answer: because every acid releases the same ion in water — H⁺ — and the H⁺ is the source of the shared acid properties.

You can now state that, in the Arrhenius definition, an acid is a substance that releases hydrogen ions (H⁺) when it dissolves in water, and that this released H⁺ is the source of the shared acid properties.

Check your understanding

In the Arrhenius definition, every acid releases the same ion when it dissolves in water. Write the ion's formula.

Accepted answer: H⁺
An Arrhenius acid is a substance that releases hydrogen ions (H⁺) when it dissolves in water. The H⁺ is a hydrogen atom that has lost its one electron.
Check your understanding

What does the Arrhenius definition say an acid does?

AIt releases hydrogen ions, H⁺, when it dissolves in water.correct
BIt releases hydrogen gas, H₂, when it dissolves in water.
This option is wrong — you swapped the ion for the gas — H₂ appears when an acid meets an active metal; in plain water an acid releases H⁺ ions.
CIt soaks up the hydrogen ions already present in water.
This option is wrong — you ran the definition backwards — an Arrhenius acid is the SOURCE of the H⁺, not a sponge for it.
DIt splits the water molecules into hydrogen and oxygen.
This option is wrong — you had the acid attack the water — it is the acid itself that splits, releasing H⁺.
An Arrhenius acid is a substance that releases hydrogen ions (H⁺) when it dissolves in water. HCl → H⁺ + Cl⁻ is the model example.
Check your understanding

The acid HBr dissolves in water. Which pair of ions forms?

AH⁺ and Br⁻correct
BH⁻ and Br⁺
This option is wrong — you flipped both charges — the hydrogen leaves as the 1+ ion, and bromine takes the 1− charge.
CH⁺ and Br⁺
This option is wrong — you made both ions positive — HBr is neutral overall, so the 1+ of H⁺ must be balanced by Br⁻.
DH₂ and Br₂
This option is wrong — you split the acid into gases — dissolving splits an acid into IONS: H⁺ and Br⁻.
Dissolve an acid in water and it releases hydrogen ions. HBr → H⁺ + Br⁻. The two charges cancel: (1+) + (1−) = 0, matching the neutral HBr.

Lesson 8 of 45 · ABS-008

Arrhenius bases
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You have seen that every acid owes its shared properties to one released ion, H⁺. The base profile has the same kind of explanation, with a different ion.

The idea

Dissolve NaOH in water and it splits into two ions: Na⁺ and OH⁻.

The equation is NaOH → Na⁺ + OH⁻.

A two-panel particle diagram. In the first panel an NaOH unit sits among water molecules. In the second panel it has split into a labeled Na plus ion and a labeled OH minus ion. The equation NaOH gives Na plus and OH minus appears beneath.A base releasing ions in waterNaOH dissolving in waterHClthe released ionsH⁺Cl⁻NaOH → Na⁺ + OH⁻
In water, NaOH splits into Na⁺ and OH⁻. The released OH⁻ is the source of the shared base properties.

OH⁻ is the hydroxide ion you met among the polyatomic ions — it is also called the 'hydroxyl' ion.

Dissolve any common base in water and it releases hydroxide ions, OH⁻.

An 'Arrhenius base' is a substance that releases hydroxide ions (OH⁻) when it dissolves in water.

The released OH⁻ is the same particle no matter which base it came from.

That is why every base shows the same property profile — the OH⁻ itself is the source of the shared properties.

Worked examples

Worked example 1. KOH dissolves in water. Which two ions does it release?

Step 1

Answer: K⁺ and OH⁻.

Worked example 2. Why do all base solutions turn red litmus paper blue?

Step 1

Answer: because every base releases the same ion in water — OH⁻ — and the OH⁻ is the source of the shared base properties.

You can now state that, in the Arrhenius definition, a base is a substance that releases hydroxide ions (OH⁻, also called hydroxyl ions) when it dissolves in water, and that this released OH⁻ is the source of the shared base properties.

Check your understanding

In the Arrhenius definition, every base releases the same ion when it dissolves in water. Write the ion's formula.

Accepted answer: OH⁻
An Arrhenius base is a substance that releases hydroxide ions (OH⁻) when it dissolves in water. OH⁻ is also called the hydroxyl ion.
Check your understanding

What does the Arrhenius definition say a base does?

AIt releases hydroxide ions, OH⁻, when it dissolves in water.correct
BIt releases hydrogen ions, H⁺, when it dissolves in water.
This option is wrong — you gave the acid definition — releasing H⁺ marks an Arrhenius acid; a base releases OH⁻.
CIt soaks up the hydroxide ions already present in water.
This option is wrong — you ran the definition backwards — an Arrhenius base is the SOURCE of the OH⁻, not a sponge for it.
DIt splits the water molecules into hydrogen and oxygen.
This option is wrong — you had the base attack the water — it is the base itself that splits, releasing OH⁻.
An Arrhenius base is a substance that releases hydroxide ions (OH⁻) when it dissolves in water. NaOH → Na⁺ + OH⁻ is the model example.
Check your understanding

The base LiOH dissolves in water. Which pair of ions forms?

ALi⁺ and OH⁻correct
BLi⁻ and OH⁺
This option is wrong — you flipped both charges — the metal leaves as the 1+ ion, and the hydroxide unit carries the 1−.
CLi⁺, O²⁻, and H⁺
This option is wrong — you broke the hydroxide unit apart — OH⁻ leaves the base whole, as one two-atom ion.
DLiO⁻ and H⁺
This option is wrong — you split off the hydrogen — a base releases the OH unit whole, as OH⁻, not an H⁺.
Dissolve a base in water and it releases hydroxide ions. LiOH → Li⁺ + OH⁻. The OH⁻ leaves as one whole two-atom ion.

Lesson 9 of 45 · ABS-009

Classify by ions released in water
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Did You Know?

You have seen the two Arrhenius definitions. Classifying a substance now takes one look: which ion does it release in water?

The idea

Read the dissolving equation and find the ions released.

A substance that releases H⁺ in water is an Arrhenius acid.

Classify by the ion released

Released in waterClassification
H⁺Arrhenius acid
OH⁻Arrhenius base
neither ionneither
One look at the released ions settles the classification.

A substance that releases OH⁻ in water is an Arrhenius base.

A substance that releases neither ion is neither an Arrhenius acid nor an Arrhenius base.

HI → H⁺ + I⁻, so HI is an Arrhenius acid.

KOH → K⁺ + OH⁻, so KOH is an Arrhenius base.

CaCl₂ → Ca²⁺ + 2Cl⁻ — no H⁺ and no OH⁻ — so CaCl₂ is neither.

Watch the hydrogens: KOH contains hydrogen, but that hydrogen leaves inside the OH⁻ unit, not as H⁺.

Worked examples

Worked example 1. H₂SO₄ → 2H⁺ + SO₄²⁻. Classify H₂SO₄.

Step 1

The substance releases H⁺ in water.

Step 2

H₂SO₄ is an Arrhenius acid.

Worked example 2. NaNO₃ → Na⁺ + NO₃⁻. Classify NaNO₃.

Step 1

No H⁺ and no OH⁻ appear among the released ions.

Step 2

NaNO₃ is neither an Arrhenius acid nor an Arrhenius base.

You can now classify a substance as an Arrhenius acid, an Arrhenius base, or neither from the ions it releases in water.

Check your understanding

Sr(OH)₂ → Sr²⁺ + 2OH⁻. Classify Sr(OH)₂.

AAn Arrhenius basecorrect
BAn Arrhenius acid
This option is wrong — you classified by the hydrogen in the formula — the hydrogen leaves inside the OH⁻ unit, and released OH⁻ marks an Arrhenius base.
CBoth an Arrhenius acid and an Arrhenius base
This option is wrong — you counted the OH⁻ as also supplying H⁺ — the hydroxide leaves whole, so only the base ion is released.
DNeither an Arrhenius acid nor an Arrhenius base
This option is wrong — you missed the OH⁻ among the products — releasing hydroxide ions is exactly what marks an Arrhenius base.
Find the released ions: Sr²⁺ and OH⁻. A substance that releases OH⁻ in water is an Arrhenius base. So Sr(OH)₂ is an Arrhenius base.
Check your understanding

HBr → H⁺ + Br⁻. Classify HBr.

AAn Arrhenius acidcorrect
BAn Arrhenius base
This option is wrong — you matched the wrong ion — HBr releases H⁺, and released H⁺ marks an Arrhenius acid.
CBoth an Arrhenius acid and an Arrhenius base
This option is wrong — you stacked the categories — HBr releases H⁺ only, so it is an acid only.
DNeither an Arrhenius acid nor an Arrhenius base
This option is wrong — you missed the H⁺ among the products — releasing hydrogen ions is exactly what marks an Arrhenius acid.
Find the released ions: H⁺ and Br⁻. A substance that releases H⁺ in water is an Arrhenius acid. So HBr is an Arrhenius acid.
Check your understanding

KCl → K⁺ + Cl⁻. Classify KCl.

ANeither an Arrhenius acid nor an Arrhenius basecorrect
BAn Arrhenius acid
This option is wrong — you classified without the marker ion — no H⁺ appears among KCl's released ions.
CAn Arrhenius base
This option is wrong — you classified without the marker ion — no OH⁻ appears among KCl's released ions.
DBoth an Arrhenius acid and an Arrhenius base
This option is wrong — you stacked two classifications that each need a marker ion — KCl releases neither H⁺ nor OH⁻.
Find the released ions: K⁺ and Cl⁻. Neither H⁺ nor OH⁻ appears. So KCl is neither an Arrhenius acid nor an Arrhenius base.

Lesson 10 of 45 · ABS-010

The hydronium ion
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Wonder this:

An H⁺ ion is a hydrogen atom stripped of its only electron — almost nothing left, with a full positive charge packed onto it. Does a particle like that really drift through water untouched?

You have seen that acids release H⁺ in water, and that a water molecule's oxygen end carries a slight negative charge.

The idea

A hydrogen ion in water does not float free.

The positive H⁺ attaches to the slightly negative oxygen end of a water molecule.

The joined particle is the 'hydronium ion', H₃O⁺ — three hydrogens, one oxygen, charge 1+.

A two-panel particle diagram. In the first panel a small labeled H plus ion approaches the slightly negative oxygen end of a bent water molecule. In the second panel they have joined into one particle labeled hydronium ion, H3O plus. The equation H plus plus H2O gives H3O plus appears beneath.beforeafter
The H⁺ attaches to the water molecule's oxygen end, forming the hydronium ion, H₃O⁺.

The equation is H⁺ + H₂O → H₃O⁺.

H⁺ and H₃O⁺ are two ways of writing the same dissolved particle.

Chemists write H⁺ as the shorthand and H₃O⁺ as the honest picture — this course uses both.

The H⁺ released by HCl in water is therefore carried as H₃O⁺.

Worked examples

Worked example 1. HNO₃ releases H⁺ into water. In what form is that hydrogen ion actually carried through the solution?

Step 1

Answer: attached to a water molecule, as the hydronium ion H₃O⁺.

Worked example 2. One bottle is labeled 'contains H⁺(aq)' and another 'contains H₃O⁺(aq)'. How do the labeled particles differ?

Step 1

Answer: they do not — H⁺ and H₃O⁺ are two ways of writing the same dissolved particle.

You can now state that a hydrogen ion in water does not float free but attaches to a water molecule to form the hydronium ion (H₃O⁺), so H⁺ and H₃O⁺ are two ways of writing the same dissolved particle.

Check your understanding

Write the formula of the hydronium ion.

Accepted answer: H₃O⁺
The hydronium ion is H₃O⁺ — three hydrogens, one oxygen, charge 1+. It forms when an H⁺ attaches to a water molecule: H⁺ + H₂O → H₃O⁺.
Check your understanding

What happens to an H⁺ ion released into water?

AIt attaches to a water molecule, forming H₃O⁺.correct
BIt floats freely between the water molecules.
This option is wrong — you left the H⁺ alone — its positive charge pulls it onto a water molecule's slightly negative oxygen end.
CIt takes an electron from the water and becomes a hydrogen atom.
This option is wrong — you cancelled the ion's charge — no electron moves; the H⁺ attaches whole, keeping its charge in H₃O⁺.
DIt pairs with another H⁺ to form hydrogen gas.
This option is wrong — you built H₂ — two positive ions repel; each H⁺ attaches to a water molecule instead.
A hydrogen ion in water does not float free. It attaches to the slightly negative oxygen end of a water molecule: H⁺ + H₂O → H₃O⁺.
Check your understanding

The acid HClO₄ dissolves in water and releases hydrogen ions. Which formula shows how each released hydrogen ion travels through the solution?

AH₃O⁺correct
BA bare H⁺ with nothing attached
This option is wrong — you left the ion free — in water every released H⁺ rides attached to a water molecule, as H₃O⁺.
CH₂
This option is wrong — you turned the ions into hydrogen gas — the released particle stays an ion, carried as H₃O⁺.
DOH⁻
This option is wrong — you wrote the hydroxide ion — the released H⁺ joins a water molecule, forming H₃O⁺.
Every H⁺ released into water attaches to a water molecule. H⁺ + H₂O → H₃O⁺, so the ion travels as hydronium.

Lesson 11 of 45 · ABS-011

Brønsted-Lowry acids
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You have seen the Arrhenius picture: an acid releases H⁺ in water. The Danish chemist Johannes Brønsted and the English chemist Thomas Lowry looked at the same event and described it as a handoff.

The idea

Look again at HCl dissolving, written the honest way: HCl + H₂O → H₃O⁺ + Cl⁻.

The hydrogen ion does not simply leave the HCl — it is passed to a water molecule.

The equation HCl plus H2O gives H3O plus and Cl minus, with a curved arrow labeled H plus passed running from the hydrogen of HCl to the oxygen of the water molecule. HCl is labeled proton donor, the Bronsted-Lowry acid. The water molecule carries no role label.HCl+H₂O→H₃O⁺+Cl⁻H⁺ passedproton donor — the Brønsted-Lowry acid
HCl donates its H⁺ to a water molecule. The donor is the Brønsted-Lowry acid.

The passed particle has a one-word name: a hydrogen atom is one proton with one electron, so the H⁺ left after losing the electron is just a 'proton'.

In the Brønsted-Lowry definition, a 'Brønsted-Lowry acid' is a particle that donates a proton — an H⁺ — to another particle.

HCl acts as the proton donor when it passes H⁺ to water, so HCl is a Brønsted-Lowry acid.

Any particle caught donating an H⁺ is, in that moment, acting as a Brønsted-Lowry acid.

Worked examples

Worked example 1. In water, an HF particle passes an H⁺ to a water molecule. What role does HF play, in the Brønsted-Lowry definition?

Step 1

Answer: the proton donor — HF acts as a Brønsted-Lowry acid.

Worked example 2. Why can a hydrogen ion be called a proton?

Step 1

Answer: because a hydrogen atom is one proton plus one electron — take the electron away, and the H⁺ that remains is just a proton.

You can now state that, in the Brønsted-Lowry definition, an acid is a particle that donates a hydrogen ion (a proton) to another particle.

Check your understanding

In the Brønsted-Lowry definition, what makes a particle an acid?

AIt donates a hydrogen ion — a proton — to another particle.correct
BIt accepts a hydrogen ion that another particle donates.
This option is wrong — you reversed the handoff — a Brønsted-Lowry acid GIVES the H⁺ away.
CIt donates an electron to another particle in the solution.
This option is wrong — you passed the wrong particle — the acid hands over an H⁺, a proton, not an electron.
DIt releases bubbles of hydrogen gas into the solution.
This option is wrong — you swapped the ion for the gas — the handoff moves a single H⁺ from one particle to another.
A Brønsted-Lowry acid is a particle that donates a proton — an H⁺ — to another particle. HCl passing its H⁺ to water is the model example.
Check your understanding

A nitric acid particle, HNO₃, passes an H⁺ to a water molecule. In the Brønsted-Lowry definition, which name fits HNO₃'s role?

AThe proton donorcorrect
BThe proton acceptor
This option is wrong — you assigned the receiving role — HNO₃ GAVE the H⁺ away, and giving is donating.
CThe electron donor
This option is wrong — you passed the wrong particle — what moves in the handoff is the H⁺, a proton.
DThe hydrogen gas source
This option is wrong — you swapped the ion for the gas — a single H⁺ moved to the water molecule; no H₂ formed.
HNO₃ passed its H⁺ to another particle. The particle that donates the proton is the Brønsted-Lowry acid — the proton donor.
Check your understanding

A hydrogen ion is identical to a single subatomic particle. Write the particle's name.

Accepted answer: proton
A hydrogen atom is one proton plus one electron. Take the electron away, and the H⁺ that remains is just a proton.

Lesson 12 of 45 · ABS-012

Brønsted-Lowry bases
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Did You Know?

You have seen the Brønsted-Lowry acid: the proton donor. Every donation needs a receiver, and the receiver has its own name.

The idea

In the Brønsted-Lowry definition, a 'Brønsted-Lowry base' is a particle that accepts a hydrogen ion from another particle.

Ammonia shows the role clearly: NH₃ gains an H⁺ and becomes NH₄⁺.

The NH₃ acts as the proton acceptor, so NH₃ is a Brønsted-Lowry base.

The equation NH3 plus H plus gives NH4 plus, with a curved arrow labeled H plus accepted running from the free hydrogen ion to the nitrogen of ammonia. NH3 is labeled proton acceptor, the Bronsted-Lowry base.NH₃+H⁺→NH₄⁺H⁺ acceptedproton acceptor — the Brønsted-Lowry base
NH₃ accepts an H⁺ and becomes NH₄⁺. The acceptor is the Brønsted-Lowry base.

Notice what accepting does to a formula: it grows by one H, and its charge rises by one.

Water can play the role too: when an acid donates an H⁺, the water molecule that accepts it becomes H₃O⁺.

Whenever a water molecule accepts an H⁺, that water molecule is acting as a Brønsted-Lowry base.

Worked examples

Worked example 1. In water, an HBr particle donates an H⁺ to a water molecule, which becomes H₃O⁺. What role does the water molecule play?

Step 1

Answer: the proton acceptor — the water molecule acts as a Brønsted-Lowry base.

Worked example 2. An OH⁻ ion gains an H⁺ and becomes a water molecule, H₂O. What role did the OH⁻ play?

Step 1

Answer: the proton acceptor — the OH⁻ acted as a Brønsted-Lowry base.

You can now state that, in the Brønsted-Lowry definition, a base is a particle that accepts a hydrogen ion from another particle.

Check your understanding

In the Brønsted-Lowry definition, what makes a particle a base?

AIt accepts a hydrogen ion from another particle.correct
BIt donates a hydrogen ion to another particle.
This option is wrong — you gave the acid's role — donating marks the Brønsted-Lowry acid; the base is the acceptor.
CIt releases hydroxide ions when it dissolves in water.
This option is wrong — you recited the Arrhenius base — the Brønsted-Lowry definition asks one thing: does the particle ACCEPT an H⁺?.
DIt accepts an electron from another particle.
This option is wrong — you accepted the wrong particle — what the base takes in is an H⁺, a proton, not an electron.
A Brønsted-Lowry base is a particle that accepts a hydrogen ion from another particle. NH₃ gaining an H⁺ to become NH₄⁺ is the model example.
Check your understanding

A fluoride ion, F⁻, gains an H⁺ and becomes HF. In the Brønsted-Lowry definition, which name fits the F⁻ ion's role?

AThe proton acceptor — a Brønsted-Lowry basecorrect
BThe proton donor — a Brønsted-Lowry acid
This option is wrong — you reversed the handoff — the F⁻ GAINED the H⁺, and gaining is accepting.
CNeither role — only particles containing OH can be bases
This option is wrong — you kept the Arrhenius requirement — the Brønsted-Lowry test is accepting the H⁺, and F⁻ passed it.
DNeither role — ions cannot take part in a proton handoff
This option is wrong — you barred ions — any particle that accepts an H⁺ is acting as a base, ion or molecule alike.
The F⁻ gained an H⁺. The particle that accepts the proton is the Brønsted-Lowry base — the proton acceptor.
Check your understanding

A cyanide ion, CN⁻, accepts one H⁺. Write the formula of the particle that forms.

Accepted answer: HCN
Accepting an H⁺ grows the formula by one H and raises the charge by one. CN⁻ + H⁺ → HCN: the 1− and the 1+ cancel, leaving a neutral particle.

Lesson 13 of 45 · ABS-013

Donor and acceptor in an equation
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You have seen the two Brønsted-Lowry definitions: an acid donates a hydrogen ion, and a base accepts one. In a real equation, you can spot which particle plays which role by tracking the H⁺.

The idea

Compare each particle on the left of the equation with the particle it becomes on the right.

The particle that loses an H⁺ between the two sides is the proton donor — the Brønsted-Lowry acid.

The particle that gains an H⁺ between the two sides is the proton acceptor — the Brønsted-Lowry base.

In HCl + H₂O → H₃O⁺ + Cl⁻, HCl becomes Cl⁻ — it lost an H⁺, so HCl is the donor, the acid.

H₂O becomes H₃O⁺ — it gained an H⁺, so H₂O is the acceptor, the base.

Water does not always play the acceptor: whichever particle gains the H⁺ in that equation is the base.

Worked examples

Worked example 1. In HNO₃ + H₂O → H₃O⁺ + NO₃⁻, which particle is the Brønsted-Lowry acid and which is the base?

Step 1

HNO₃ becomes NO₃⁻ — it lost an H⁺.

Step 2

H₂O becomes H₃O⁺ — it gained an H⁺.

Step 3

HNO₃ is the donor (the acid); H₂O is the acceptor (the base).

Worked example 2. In NH₃ + H₂O ⇌ NH₄⁺ + OH⁻, which particle is the acid and which is the base?

Step 1

This equation is written with ⇌: the double arrow shows the change also runs backward, so both forms are present. Track the H⁺ across it just as before.

Step 2

NH₃ becomes NH₄⁺ — it gained an H⁺.

Step 3

H₂O becomes OH⁻ — it lost an H⁺.

Step 4

This time water is the donor.

Step 5

H₂O is the donor (the acid); NH₃ is the acceptor (the base).

You can now identify the proton donor (the acid) and the proton acceptor (the base) in a supplied acid-base equation.

Check your understanding

In the equation HBr + H₂O → H₃O⁺ + Br⁻, which particle is the proton donor (the Brønsted-Lowry acid)?

AHBrcorrect
BH₂O
This option is wrong — you picked the acceptor — H₂O gains the H⁺, becoming H₃O⁺; the donor is the particle that loses one.
CH₃O⁺
This option is wrong — you picked a product — H₃O⁺ is water after gaining the H⁺; the donor sits on the left and loses an H⁺.
DBr⁻
This option is wrong — you picked what the donor becomes — Br⁻ is HBr after losing its H⁺, not the donor itself.
Compare each particle on the left with what it becomes on the right. HBr becomes Br⁻ — it lost an H⁺. So HBr is the proton donor, the Brønsted-Lowry acid.
Check your understanding

In the equation HI + H₂O → H₃O⁺ + I⁻, which particle is the proton acceptor (the Brønsted-Lowry base)?

AH₂Ocorrect
BHI
This option is wrong — you picked the donor — HI loses its H⁺, becoming I⁻; the acceptor is the particle that gains one.
CH₃O⁺
This option is wrong — you picked a product — H₃O⁺ is what the acceptor becomes after gaining the H⁺; the acceptor sits on the left.
DI⁻
This option is wrong — you picked what the donor becomes — I⁻ is HI after losing its H⁺; the acceptor is the particle that gains one.
Compare each particle on the left with what it becomes on the right. H₂O becomes H₃O⁺ — it gained an H⁺. So H₂O is the proton acceptor, the Brønsted-Lowry base.
Check your understanding

In the equation CH₃COOH + H₂O ⇌ H₃O⁺ + CH₃COO⁻, which particle is the Brønsted-Lowry acid?

ACH₃COOHcorrect
BH₂O
This option is wrong — you gave water the donor role — here H₂O gains an H⁺ and becomes H₃O⁺, so it is the acceptor.
CH₃O⁺
This option is wrong — you picked a product — H₃O⁺ is water after gaining the H⁺; the donor sits on the left and loses an H⁺.
DCH₃COO⁻
This option is wrong — you picked what the donor becomes — CH₃COO⁻ is CH₃COOH after losing its H⁺, not the donor itself.
Compare each particle on the left with what it becomes on the right. CH₃COOH becomes CH₃COO⁻ — it lost an H⁺. So CH₃COOH is the proton donor, the Brønsted-Lowry acid.

Lesson 14 of 45 · ABS-014

Two definitions compared
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Have You Ever Wondered?
Wonder this:

Ammonia's formula, NH₃, contains no OH at all — yet household ammonia turns red litmus paper blue, exactly like a base should. One of the two definitions you have seen cannot explain that. Which one, and why?

You have seen both definitions — Arrhenius classifies by what a substance releases in water, Brønsted-Lowry by proton transfer. Putting them side by side shows why chemists keep both.

The idea

The Arrhenius definition classifies by what a substance releases in water: an acid releases H⁺, and a base releases OH⁻.

The Brønsted-Lowry definition classifies by proton transfer: an acid donates an H⁺, and a base accepts one.

Every Arrhenius acid is also a Brønsted-Lowry acid, because releasing H⁺ into water is donating H⁺ to water molecules.

Two definitions of acid and base

ArrheniusBrønsted-Lowry
acidreleases H⁺ in waterdonates an H⁺ to another particle
basereleases OH⁻ in wateraccepts an H⁺ from another particle
coverssubstances that release ions in waterall of those, plus bases containing no OH⁻
The Brønsted-Lowry definition keeps everything Arrhenius covers and adds the bases that contain no hydroxide.

The base definitions do not match up the same way, because a particle can accept H⁺ without ever containing OH⁻.

NH₃ contains no OH⁻, so the Arrhenius definition cannot call it a base.

But NH₃ accepts an H⁺ to form NH₄⁺, so the Brønsted-Lowry definition classifies it as a base.

So the Brønsted-Lowry definition extends the Arrhenius definition: it keeps everything Arrhenius covers and adds the bases that contain no hydroxide.

Worked examples

Worked example 1. HBr releases H⁺ when it dissolves in water. Which definition or definitions classify HBr as an acid?

Step 1

Arrhenius: HBr releases H⁺ in water — an Arrhenius acid.

Step 2

Brønsted-Lowry: releasing H⁺ into water is donating H⁺ to water molecules — a proton donor.

Step 3

Both definitions classify HBr as an acid.

Worked example 2. The carbonate ion, CO₃²⁻, accepts an H⁺ to form HCO₃⁻, and its formula contains no OH. Which definition classifies CO₃²⁻ as a base?

Step 1

Arrhenius: CO₃²⁻ has no OH⁻ to release, so the Arrhenius definition cannot classify it as a base.

Step 2

Brønsted-Lowry: CO₃²⁻ accepts an H⁺ — a proton acceptor.

Step 3

Only the Brønsted-Lowry definition classifies CO₃²⁻ as a base.

You can now explain how the Brønsted-Lowry definition extends the Arrhenius definition: it classifies by proton transfer rather than by what is released in water, so it also covers bases that contain no hydroxide.

Check your understanding

How does the Brønsted-Lowry definition extend the Arrhenius definition of a base?

AIt classifies by accepting H⁺, so it covers bases whose formulas contain no OH⁻.correct
BIt classifies by releasing OH⁻ in water, so it covers more of the hydroxides.
This option is wrong — you restated the Arrhenius test — the extension is the switch to proton transfer, which frees the base from needing OH⁻.
CIt replaces the Arrhenius definition, which no longer classifies anything correctly.
This option is wrong — you discarded Arrhenius — everything it classifies still qualifies; the Brønsted-Lowry definition adds cases on top.
DIt counts only the substances that contain no OH⁻ as bases.
This option is wrong — you flipped the coverage — hydroxide bases still count; the definition adds the OH-free ones, it does not swap to them.
The Brønsted-Lowry definition classifies a base by what it does: accept an H⁺. A particle can accept H⁺ without ever containing OH⁻. So the definition keeps every Arrhenius base and adds the bases that contain no hydroxide.
Check your understanding

The sulfite ion, SO₃²⁻, accepts an H⁺ to form HSO₃⁻. Its formula contains no OH. Which definition or definitions classify SO₃²⁻ as a base?

AThe Brønsted-Lowry definition onlycorrect
BThe Arrhenius definition only
This option is wrong — you classified by release — SO₃²⁻ has no OH⁻ to release in water, so the Arrhenius definition cannot cover it.
CBoth definitions
This option is wrong — you gave Arrhenius credit it cannot earn — with no OH⁻ in the formula, only the proton-transfer definition applies.
DNeither definition
This option is wrong — you required OH⁻ for every base — accepting an H⁺ is exactly what makes a Brønsted-Lowry base.
Arrhenius asks: does it release OH⁻ in water? SO₃²⁻ contains no OH⁻, so no. Brønsted-Lowry asks: does it accept an H⁺? SO₃²⁻ does, forming HSO₃⁻. So only the Brønsted-Lowry definition classifies SO₃²⁻ as a base.
Check your understanding

HI releases H⁺ when it dissolves in water. Which definition or definitions classify HI as an acid?

ABoth definitionscorrect
BThe Arrhenius definition only
This option is wrong — you stopped at release — handing H⁺ to water molecules is proton donation, so the Brønsted-Lowry definition counts HI too.
CThe Brønsted-Lowry definition only
This option is wrong — you skipped the release test — HI releases H⁺ in water, the Arrhenius acid definition exactly.
DNeither definition
This option is wrong — you rejected a clear acid — releasing H⁺ satisfies Arrhenius, and donating that H⁺ to water satisfies Brønsted-Lowry.
Arrhenius: HI releases H⁺ in water — an Arrhenius acid. Brønsted-Lowry: that released H⁺ is donated to water molecules — a proton donor. Every Arrhenius acid is also a Brønsted-Lowry acid.

Lesson 15 of 45 · ABS-015

Conjugate acid-base pairs
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You have seen how to spot the proton donor and the proton acceptor in an equation. Donating or accepting an H⁺ also links the particles into pairs with a name of their own.

The idea

When an acid donates its H⁺, the particle left behind differs from the acid by exactly one H⁺.

Two particles whose formulas differ by exactly one H⁺ form a 'conjugate acid-base pair'.

The member with the extra H⁺ is the conjugate acid; the member without it is the conjugate base.

In NH₃ + H₂O ⇌ NH₄⁺ + OH⁻, NH₃ and NH₄⁺ differ by one H⁺ — NH₄⁺ is the conjugate acid formed from the base NH₃.

H₂O and OH⁻ also differ by one H⁺ — the equation's second conjugate pair.

The equation NH3 plus H2O, double arrow, NH4 plus and OH minus, with one arc linking NH3 to NH4 plus labeled pair 1 differs by one H plus, and a second arc linking H2O to OH minus labeled pair 2 differs by one H plus.NH₃+H₂O⇌NH₄⁺+OH⁻pair 1: differs by one H⁺pair 2: differs by one H⁺
Each conjugate acid-base pair has one member on each side, and the two members differ by exactly one H⁺.

Every Brønsted-Lowry equation contains exactly two conjugate pairs, and each pair has one member on each side of the arrow.

Worked examples

Worked example 1. Identify the two conjugate acid-base pairs in HF + H₂O ⇌ H₃O⁺ + F⁻.

Step 1

HF and F⁻ differ by exactly one H⁺ — HF is the conjugate acid, F⁻ the conjugate base.

Step 2

H₂O and H₃O⁺ differ by exactly one H⁺ — H₃O⁺ is the conjugate acid, H₂O the conjugate base.

Step 3

The pairs are HF/F⁻ and H₃O⁺/H₂O.

Worked example 2. What is the conjugate base of HNO₃?

Step 1

Remove exactly one H⁺: the formula loses one H, and losing a positive charge drops the particle's charge by one.

Step 2

Neutral HNO₃ becomes the 1− ion NO₃⁻.

Step 3

NO₃⁻ is the conjugate base of HNO₃.

You can now identify the conjugate acid-base pairs in a supplied equation, where a conjugate pair is two particles whose formulas differ by exactly one H⁺.

Check your understanding

In HBr + H₂O → H₃O⁺ + Br⁻, which particle is the conjugate base of HBr?

ABr⁻correct
BH₂O
This option is wrong — you picked a member of the other pair — H₂O does not differ from HBr by one H⁺; HBr's partner is Br⁻.
CH₃O⁺
This option is wrong — you picked a conjugate acid — H₃O⁺ carries an extra H⁺; a conjugate base is the member with one H⁺ fewer.
DHBr
This option is wrong — you paired the particle with itself — a conjugate pair is two different particles differing by one H⁺.
A conjugate pair differs by exactly one H⁺. HBr minus one H⁺ is Br⁻. So Br⁻ is the conjugate base of HBr.
Check your understanding

Which particle is the conjugate acid of the nitrite ion, NO₂⁻?

AHNO₂correct
BNO₂
This option is wrong — you removed the charge without adding the H — gaining an H⁺ adds one H to the formula and raises the charge by one.
CH₂NO₂⁺
This option is wrong — you added two H⁺ — a conjugate pair differs by exactly one.
DNO₃⁻
This option is wrong — you added an oxygen — conjugate partners differ by one H⁺, never by an O.
Add exactly one H⁺ to NO₂⁻. The formula gains one H, and the charge rises from 1− to neutral. So HNO₂ is the conjugate acid of NO₂⁻.
Check your understanding

Which two particles in CH₃COOH + H₂O ⇌ H₃O⁺ + CH₃COO⁻ form a conjugate acid-base pair?

ACH₃COOH and CH₃COO⁻correct
BCH₃COOH and H₃O⁺
This option is wrong — you paired the two acids — both carry the extra H⁺; a pair is one acid with its own base partner.
CH₂O and CH₃COO⁻
This option is wrong — you paired the two bases — a conjugate pair crosses the arrow as one particle gains exactly what the other lost.
DCH₃COOH and H₂O
This option is wrong — you paired the two left-side particles — pair members sit on opposite sides of the arrow, differing by one H⁺.
A conjugate pair differs by exactly one H⁺, with one member on each side of the arrow. CH₃COOH minus one H⁺ is CH₃COO⁻. So CH₃COOH and CH₃COO⁻ form one pair; H₃O⁺ and H₂O form the other.

Lesson 16 of 45 · ABS-016

Binary acid or oxyacid
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You have seen that acid formulas are written with H first. The acids themselves sort into two families by what follows the hydrogen.

The idea

Look at what an acid's formula contains besides hydrogen.

A 'binary acid' contains hydrogen and exactly one other element.

An 'oxyacid' contains hydrogen and a polyatomic ion that contains oxygen.

HBr contains hydrogen and only bromine — a binary acid.

HNO₃ contains hydrogen and the nitrate ion, NO₃⁻ — nitrate contains oxygen, so HNO₃ is an oxyacid.

Two families of acids

FormulaBesides hydrogenContains oxygen?Family
HBrbromine onlynobinary acid
HNO₃the nitrate ion, NO₃⁻yesoxyacid
No oxygen means binary; hydrogen plus an oxygen-containing ion means oxyacid.

The quick check: no oxygen in the formula means binary; hydrogen plus an oxygen-containing ion means oxyacid.

Worked examples

Worked example 1. Classify H₂S as a binary acid or an oxyacid.

Step 1

Besides hydrogen, H₂S contains only sulfur — one other element, and no oxygen.

Step 2

H₂S is a binary acid.

Worked example 2. Classify H₂CO₃, which contains the carbonate ion, CO₃²⁻.

Step 1

Besides hydrogen, H₂CO₃ contains the carbonate ion, and carbonate contains oxygen.

Step 2

H₂CO₃ is an oxyacid.

You can now classify an acid as a binary acid (hydrogen plus one other element) or an oxyacid (hydrogen plus a polyatomic ion containing oxygen) from its formula.

Check your understanding

Classify HI.

AA binary acidcorrect
BAn oxyacid
This option is wrong — you placed HI in the oxygen family — its formula contains no oxygen, just hydrogen and iodine.
CA base
This option is wrong — you missed the leading H — a formula written with H first marks an acid, and HI contains no hydroxide.
DNeither an acid nor a base
This option is wrong — you set the formula aside — H written first marks an acid, and one other element with no oxygen makes it binary.
Besides hydrogen, HI contains only iodine. One other element and no oxygen — a binary acid.
Check your understanding

Classify H₂SO₃, which contains the sulfite ion, SO₃²⁻.

AAn oxyacidcorrect
BA binary acid
This option is wrong — you counted only the sulfur — the sulfite ion carries three oxygens, and oxygen marks an oxyacid.
CA base
This option is wrong — you looked past the leading H — H-first formulas are acids, and H₂SO₃ contains no hydroxide.
DNeither an acid nor a base
This option is wrong — you set the formula aside — H written first marks an acid, and the oxygen-bearing sulfite ion makes it an oxyacid.
Besides hydrogen, H₂SO₃ contains the sulfite ion. Sulfite contains oxygen — an oxyacid.
Check your understanding

Classify HNO₂, which contains the nitrite ion, NO₂⁻.

AAn oxyacidcorrect
BA binary acid
This option is wrong — you counted nitrogen as the only other element — the nitrite ion carries two oxygens, and oxygen marks an oxyacid.
CA base
This option is wrong — you looked past the leading H — H-first formulas are acids, and HNO₂ contains no hydroxide.
DNeither an acid nor a base
This option is wrong — you set the formula aside — H written first marks an acid, and the oxygen-bearing nitrite ion makes it an oxyacid.
Besides hydrogen, HNO₂ contains the nitrite ion. Nitrite contains oxygen — an oxyacid.

Lesson 17 of 45 · ABS-017

Naming binary acids
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You have seen how to spot a binary acid from its formula. Binary acids are named with one fixed pattern.

The idea

The name of a binary acid has three parts: hydro-, the other element's root, and -ic acid.

Start with the prefix 'hydro-'.

Add the root of the other element's name.

Finish with -ic and the word acid.

For HBr the other element is bromine, root 'brom': hydro + brom + ic acid gives hydrobromic acid.

The subscripts play no part in the name — however many hydrogens the formula carries, the pattern is the same.

The formula HBr with three name blocks beneath it: hydro dash labeled the binary-acid prefix, brom labeled root of bromine, and dash ic acid labeled the binary-acid ending, assembling into hydrobromic acid.HBrhydro-the binary-acid prefixbromroot of bromine-ic acidthe binary-acid endinghydrobromic acid
hydro- + element root + -ic acid names any binary acid.
Worked examples

Worked example 1. Name the acid HCl.

Step 1

The other element is chlorine, root 'chlor'.

Step 2

hydro + chlor + ic acid.

Step 3

HCl is hydrochloric acid.

Worked example 2. Name the acid H₂S.

Step 1

The other element is sulfur; its root keeps the full word, 'sulfur'.

Step 2

hydro + sulfur + ic acid.

Step 3

The subscript 2 plays no part in the name.

Step 4

H₂S is hydrosulfuric acid.

You can now name a binary acid from its formula using the pattern hydro- + element root + -ic acid.

Check your understanding

Name the acid HF.

Accepted answer: hydrofluoric acid
The other element is fluorine, root 'fluor'. hydro + fluor + ic acid. HF is hydrofluoric acid.
Check your understanding

Name the acid HI.

Accepted answer: hydroiodic acid
The other element is iodine, root 'iod'. hydro + iod + ic acid. HI is hydroiodic acid.
Check your understanding

Which name is correct for the acid H₂Se? (Selenium's root is 'selen'.)

AHydroselenic acidcorrect
BSelenic acid
This option is wrong — you dropped the hydro- prefix, which marks a binary acid.
CHydroselenous acid
This option is wrong — you used the -ous suffix — binary acids always take -ic.
DSelenous acid
This option is wrong — you dropped the prefix and switched the suffix — the binary pattern is hydro- + root + -ic acid.
The other element is selenium, root 'selen'. hydro + selen + ic acid — the subscript 2 plays no part. H₂Se is hydroselenic acid.

Lesson 18 of 45 · ABS-018

Binary acid formulas
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You have seen how a binary acid's name is built from its formula. Writing the formula runs the pattern in reverse: from the name back to the formula.

The idea

A name of the form hydro-…-ic acid announces a binary acid: hydrogen plus one other element.

The root between hydro- and -ic names that element.

Write hydrogen with that element's negative ion, balancing the charges the same way as for any ionic formula.

Hydrogen counts as 1+ here, so the ion's charge number tells you how many H to write.

For hydrosulfuric acid the root is sulfur, and the sulfide ion is S²⁻.

Balancing 1+ hydrogens against one 2− sulfide takes two hydrogens: H₂S.

Worked examples

Worked example 1. Write the formula of hydrofluoric acid. (The fluoride ion is F⁻.)

Step 1

The root 'fluor' names fluorine.

Step 2

Balance 1+ against 1−: one H for one F.

Step 3

HF

Worked example 2. Write the formula of hydroselenic acid. (The selenide ion is Se²⁻.)

Step 1

The root 'selen' names selenium.

Step 2

Balance 1+ hydrogens against one 2− selenide: two hydrogens.

Step 3

H₂Se

You can now write the formula of a binary acid from its name by pairing hydrogen with the nonmetal ion and balancing the charges.

Check your understanding

Write the formula of hydrochloric acid. (The chloride ion is Cl⁻.)

Accepted answer: HCl
The root 'chlor' names chlorine, and the chloride ion is Cl⁻. Balance 1+ against 1−: one H for one Cl. Hydrochloric acid is HCl.
Check your understanding

Write the formula of hydroiodic acid. (The iodide ion is I⁻.)

Accepted answer: HI
The root 'iod' names iodine, and the iodide ion is I⁻. Balance 1+ against 1−: one H for one I. Hydroiodic acid is HI.
Check your understanding

Which formula matches hydrobromic acid? (The bromide ion is Br⁻.)

AHBrcorrect
BHBrO₃
This option is wrong — you added oxygens — the hydro- prefix promises a binary acid, with no oxygen.
CH₂Br
This option is wrong — you doubled the hydrogen — bromide's 1− charge needs only one H.
DHBr₂
This option is wrong — you doubled the bromine as in elemental Br₂ — in the acid one H⁺ pairs with one Br⁻.
The root 'brom' names bromine, and the bromide ion is Br⁻. Balance 1+ against 1−: one H for one Br. Hydrobromic acid is HBr.

Lesson 19 of 45 · ABS-019

Naming oxyacids
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You have seen that an oxyacid is hydrogen joined to an oxygen-containing polyatomic ion. The acid's name comes from that ion's name, changed by one suffix rule.

The idea

Find the polyatomic ion inside the oxyacid's formula.

If the ion's name ends in -ate, the acid's name ends in -ic acid.

If the ion's name ends in -ite, the acid's name ends in -ous acid.

The oxyacid suffix rule

Ion name ends inAcid name ends inExample
-ate-ic acidsulfate → sulfuric acid
-ite-ous acidsulfite → sulfurous acid
-ate turns into -ic acid; -ite turns into -ous acid. No hydro- prefix on an oxyacid.

There is no hydro- prefix on an oxyacid's name.

H₂SO₄ contains the sulfate ion — sulfate becomes sulfuric acid.

H₂SO₃ contains the sulfite ion — sulfite becomes sulfurous acid.

The element root sometimes stretches so the name says smoothly: sulfate gives sulfURic, and phosphate gives phosphORic.

Worked examples

Worked example 1. Name HNO₃, which contains the nitrate ion, NO₃⁻.

Step 1

-ate becomes -ic acid: nitrate → nitric.

Step 2

HNO₃ is nitric acid.

Worked example 2. Name HNO₂, which contains the nitrite ion, NO₂⁻.

Step 1

-ite becomes -ous acid: nitrite → nitrous.

Step 2

HNO₂ is nitrous acid.

You can now name an oxyacid from its formula using the anion suffix rules -ate → -ic acid and -ite → -ous acid.

Check your understanding

Name H₂CO₃, which contains the carbonate ion, CO₃²⁻.

Accepted answer: carbonic acid
The ion is carbonate — its name ends in -ate. -ate becomes -ic acid: carbonate → carbonic. H₂CO₃ is carbonic acid.
Check your understanding

Name HClO₃, which contains the chlorate ion, ClO₃⁻.

Accepted answer: chloric acid
The ion is chlorate — its name ends in -ate. -ate becomes -ic acid: chlorate → chloric. HClO₃ is chloric acid.
Check your understanding

Which name is correct for H₃PO₄, which contains the phosphate ion, PO₄³⁻?

APhosphoric acidcorrect
BPhosphorous acid
This option is wrong — you used the -ite rule — phosphATE takes -ic acid.
CHydrophosphoric acid
This option is wrong — you added hydro- — that prefix marks binary acids, and H₃PO₄ contains oxygen.
DPhosphate acid
This option is wrong — you left the ion's name unchanged — the -ate ending must switch to -ic.
The ion is phosphate — its name ends in -ate. -ate becomes -ic acid, and the root stretches: phosphate → phosphoric. H₃PO₄ is phosphoric acid.

Lesson 20 of 45 · ABS-020

Oxyacid formulas
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You have seen the suffix rules that name an oxyacid from its ion. Writing the formula runs those rules backward, then balances the ion's charge with hydrogen.

The idea

Reverse the suffix first: -ic acid points back to an -ate ion, and -ous acid points back to an -ite ion.

Write down that ion's formula and charge.

Add enough H, counting 1+ each, to cancel the ion's charge.

For nitrous acid, -ous points to the nitrite ion, NO₂⁻.

One 1− charge takes one H: HNO₂.

Check the finish: the H count equals the ion's charge number, so the formula is neutral.

Worked examples

Worked example 1. Write the formula of sulfuric acid. (The sulfate ion is SO₄²⁻.)

Step 1

-ic points back to the -ate ion: sulfate, SO₄²⁻.

Step 2

A 2− charge takes two H.

Step 3

H₂SO₄

Worked example 2. Write the formula of carbonic acid. (The carbonate ion is CO₃²⁻.)

Step 1

-ic points back to the -ate ion: carbonate, CO₃²⁻.

Step 2

A 2− charge takes two H.

Step 3

H₂CO₃

You can now write the formula of an oxyacid from its name by reversing the suffix rules to find the anion and balancing its charge with hydrogen ions.

Check your understanding

Write the formula of nitric acid. (The nitrate ion is NO₃⁻.)

Accepted answer: HNO₃
-ic points back to the -ate ion: nitrate, NO₃⁻. A 1− charge takes one H. Nitric acid is HNO₃.
Check your understanding

Write the formula of sulfurous acid. (The sulfite ion is SO₃²⁻.)

Accepted answer: H₂SO₃
-ous points back to the -ite ion: sulfite, SO₃²⁻. A 2− charge takes two H. Sulfurous acid is H₂SO₃.
Check your understanding

Which formula matches phosphoric acid? (The phosphate ion is PO₄³⁻.)

AH₃PO₄correct
BHPO₄
This option is wrong — you added a single H — phosphate's 3− charge takes three.
CH₂PO₄
This option is wrong — you stopped at two H — one short of cancelling the 3− charge.
DH₃PO₃
This option is wrong — you swapped in the -ite ion — -ic acid points back to phosphATE, PO₄³⁻.
-ic points back to the -ate ion: phosphate, PO₄³⁻. A 3− charge takes three H. Phosphoric acid is H₃PO₄.

Lesson 21 of 45 · ABS-021

Naming bases
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You have seen naming routines for acids, and back in ionic bonding you learned to name ionic compounds. Bases need almost nothing new.

The idea

A metal hydroxide is an ionic compound, so its name is its ordinary ionic name.

Name the metal, then the hydroxide ion: metal name + hydroxide.

Ca(OH)₂ is calcium hydroxide — the subscript 2 appears nowhere in the name.

Base names never take hydro-, -ic, or -ous — those patterns belong to acids.

One common base breaks the pattern: NH₃ carries the special name 'ammonia'.

NH₃ contains no metal and no hydroxide, so the ionic routine cannot name it — the special name is all there is.

Worked examples

Worked example 1. Name the base KOH.

Step 1

Metal: potassium. Ion: hydroxide.

Step 2

KOH is potassium hydroxide.

Worked example 2. Name the base Sr(OH)₂.

Step 1

Metal: strontium — and the subscript 2 plays no part in the name.

Step 2

Sr(OH)₂ is strontium hydroxide.

You can now name a base from its formula using ordinary ionic-compound naming for metal hydroxides and the special name ammonia for NH₃.

Check your understanding

Name the base LiOH.

Accepted answer: lithium hydroxide
Metal: lithium. Ion: hydroxide. LiOH is lithium hydroxide.
Check your understanding

Name the base Ba(OH)₂.

Accepted answer: barium hydroxide
Metal: barium. Ion: hydroxide — the subscript 2 plays no part in the name. Ba(OH)₂ is barium hydroxide.
Check your understanding

Which name is correct for NH₃?

AAmmoniacorrect
BAmmonium
This option is wrong — you named the ion — NH₄⁺ is ammonium; the base NH₃ is ammonia.
CNitrogen hydroxide
This option is wrong — you invented a hydroxide — NH₃ contains no OH⁻, so the ionic routine cannot name it; it carries the special name ammonia.
DHydronitric acid
This option is wrong — you applied the binary-acid pattern — NH₃ is a base, and its name is simply ammonia.
NH₃ contains no metal and no hydroxide, so the ionic routine cannot name it. It carries the special name ammonia.
Summary video — Recognizing, defining, and naming acids and bases

Watch in David’s player

End of Topic Test

End of Topic Test — five interchangeable forms, delivered separately.

Intro video — Strong and weak

Watch in David’s player

Lesson 22 of 45 · ABS-022

Strong vs weak ionization
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Wonder this:

Dissolve the same amount of two different acids in two beakers of water and test each with a conductivity bulb. One bulb glows brightly; the other glows dimly. The same amount is dissolved in each beaker — so what is different inside them?

You have seen that a solution conducts only when charged particles are free to move through it. The two bulbs are reporting how many free ions each beaker holds.

The idea

When an acid or base dissolves in water, its particles can split into ions — chemists call this splitting 'ionizing'.

A 'strong' acid or base ionizes completely: every dissolved particle splits into ions.

A 'weak' acid or base ionizes only partially: most of its dissolved particles stay whole, and only a few split.

The two beakers show the contrast at the particle level: every HCl has split into H⁺ and Cl⁻, while most CH₃COOH particles are still intact.

HCl is a strong acid, and complete ionization is written with a single arrow: HCl → H⁺ + Cl⁻.

Two beaker diagrams. The hydrochloric acid beaker holds six H plus ions and six Cl minus ions, all separate, with no intact HCl. The acetic acid beaker holds five intact CH3COOH units and just one H plus with one CH3COO minus.hydrochloric acid, HClCl⁻Cl⁻H⁺Cl⁻Cl⁻H⁺H⁺H⁺Cl⁻H⁺H⁺Cl⁻acetic acid, CH₃COOHCH₃COO⁻CH₃COOHCH₃COOHCH₃COOHH⁺CH₃COOHCH₃COOH
Same amount dissolved in each beaker: every HCl has split into ions, while most CH₃COOH particles are still whole.

Acetic acid is weak, and partial ionization is written with a double arrow: CH₃COOH ⇌ CH₃COO⁻ + H⁺.

The double arrow shows the change also runs backward, so both forms are present.

More free ions carry more current — the bright bulb was the strong acid's beaker, and the dim bulb the weak acid's.

Strong and weak mean exactly the same for bases: a strong base ionizes completely, and a weak base only partially.

Worked examples

Worked example 1. Every dissolved NaOH unit in a solution has split into Na⁺ and OH⁻, with none left intact. Is NaOH strong or weak?

Step 1

Every dissolved particle has split — ionization is complete.

Step 2

NaOH is a strong base.

Worked example 2. In a solution of NH₃, most dissolved NH₃ particles are still whole; only a few have reacted with water to form NH₄⁺ and OH⁻. Is ammonia strong or weak, and which arrow belongs in its equation?

Step 1

Most particles stay whole — ionization is partial.

Step 2

Partial ionization takes the double arrow: NH₃ + H₂O ⇌ NH₄⁺ + OH⁻.

Step 3

Ammonia is a weak base, and its equation is written with ⇌.

You can now state that a strong acid or base ionizes (splits into ions) completely in water, while a weak acid or base ionizes only partially, leaving most of its particles intact.

Check your understanding

What does it mean for an acid to be strong?

AEvery one of its dissolved particles splits into ions.correct
BMost of its dissolved particles stay whole in water.
This option is wrong — you described a weak acid — strong means the splitting is complete.
CA large amount of it is dissolved in the water.
This option is wrong — you described concentration — how much is dissolved is a different quantity from how completely it splits.
DIt burns skin faster than any other acid can.
This option is wrong — you used the everyday meaning — in chemistry, strong reports complete ionization, nothing else.
Strong reports how completely the dissolved particles split. A strong acid ionizes completely: every dissolved particle splits into ions. A weak acid splits only partially, leaving most particles whole.
Check your understanding

An acid's ionization is written HNO₂ ⇌ H⁺ + NO₂⁻. What does the double arrow show?

AThe change also runs backward, so both forms are present.correct
BThe acid ionizes completely, in a single forward direction.
This option is wrong — you read ⇌ as complete — complete ionization takes the single arrow →.
CThe ionization happens twice as fast as normal.
This option is wrong — you read the two arrowheads as speed — the double arrow says nothing about how fast, only that the change also runs backward.
DThe equation has not been balanced yet.
This option is wrong — you treated the arrow as an error mark — ⇌ is deliberate notation for a change that also runs backward.
⇌ marks partial ionization. The double arrow shows the change also runs backward, so both forms are present. That is why a weak acid's solution holds mostly intact particles plus some ions.
Check your understanding

The figure shows particle diagrams of two acid solutions at the same concentration. Which beaker holds the weak acid?

particle panels — Beaker X; H⁺; Br⁻; Beaker Y; HF; F⁻Beaker XH⁺Br⁻Br⁻H⁺H⁺H⁺Br⁻Br⁻H⁺H⁺Br⁻Br⁻Beaker YHFHFHFH⁺HFF⁻HF
ABeaker Ycorrect
BBeaker X
This option is wrong — you picked the fully split acid — complete splitting marks a strong acid.
CBoth beakers
This option is wrong — you counted any ionization as weakness — Beaker X shows no intact particles at all, which is complete ionization.
DNeither beaker
This option is wrong — you expected zero splitting from a weak acid — weak means partial, and Beaker Y's few split particles fit that exactly.
Look for intact particles. Beaker Y holds mostly whole HF units with only one split — partial ionization. Partial ionization is what weak means, so Beaker Y holds the weak acid.

Lesson 23 of 45 · ABS-023

The six strong acids
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You have seen what makes an acid strong. Which real acids are strong? In this course the answer is a short list, worth committing to memory.

The idea

Six common acids are strong — each ionizes completely in water.

Three are binary acids of halogens: HCl, HBr, and HI.

The fourth halogen acid, HF, is NOT on the list.

The six strong acids

FormulaName
HClhydrochloric acid
HBrhydrobromic acid
HIhydroiodic acid
HNO₃nitric acid
H₂SO₄sulfuric acid
HClO₄perchloric acid
An acid that is not on this list can be assumed weak in this course.

Three are oxyacids: nitric acid HNO₃, sulfuric acid H₂SO₄, and HClO₄, called perchloric acid.

An acid that is not on this list can be assumed weak in this course.

So HF — and any other unlisted acid you meet here — counts as weak.

Worked examples

Worked example 1. Is HBr a strong acid or a weak acid?

Step 1

Answer: strong — HBr is one of the six.

Worked example 2. Is acetic acid, CH₃COOH, strong or weak?

Step 1

Answer: weak — it is not on the list of six.

You can now state that the six common strong acids are HCl, HBr, HI, HNO₃, H₂SO₄, and HClO₄, and that an acid not on this list can be assumed weak in this course.

Check your understanding

Which of these acids is one of the six strong acids?

AHNO₃correct
BHF
This option is wrong — you included the fourth halogen acid — HF is the one halogen acid left off the list.
CHNO₂
This option is wrong — you matched it to nitric acid — the list carries HNO₃; HNO₂ is unlisted, so assume it weak.
DH₂CO₃
This option is wrong — you added carbonic acid — it is not on the list, so in this course it is assumed weak.
The six strong acids are HCl, HBr, HI, HNO₃, H₂SO₄, and HClO₄. HNO₃ is on the list; HF, HNO₂, and H₂CO₃ are not.
Check your understanding

Which of these acids should be assumed weak in this course?

AH₂SO₃correct
BH₂SO₄
This option is wrong — you picked sulfuric acid — it IS one of the six; its near-twin H₂SO₃ is the unlisted one.
CHBr
This option is wrong — you picked a listed halogen acid — HCl, HBr, and HI are all on the list.
DHClO₄
This option is wrong — you picked perchloric acid — it is one of the six strong acids.
Check the list: HCl, HBr, HI, HNO₃, H₂SO₄, HClO₄. H₂SO₃ is not on it — an acid not on the list can be assumed weak in this course.
Check your understanding

Which set lists ONLY strong acids?

AHCl, HNO₃, HClO₄correct
BHCl, HF, HNO₃
This option is wrong — you slipped HF in — the halogen acids on the list are HCl, HBr, and HI, and HF is the one left off.
CHBr, H₂SO₄, H₂CO₃
This option is wrong — you slipped carbonic acid in — H₂CO₃ is not one of the six.
DHI, HNO₂, H₂SO₄
This option is wrong — you slipped HNO₂ in — the list carries nitric acid, HNO₃, not nitrous.
The six strong acids are HCl, HBr, HI, HNO₃, H₂SO₄, and HClO₄. HCl, HNO₃, and HClO₄ are all members; every other set hides one unlisted acid.

Lesson 24 of 45 · ABS-024

The strong bases
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Did You Know?

You have seen the six strong acids. The strong bases are just as short a list — and they sit in a clean pattern on the periodic table.

The idea

The hydroxides of the Group 1 metals lithium, sodium, and potassium are strong bases: LiOH, NaOH, and KOH.

So KOH is a strong base — every dissolved KOH splits into K⁺ and OH⁻.

The strong bases

GroupMembers
Group 1 hydroxidesLiOH, NaOH, KOH
Heavier Group 2 hydroxidesCa(OH)₂, Sr(OH)₂, Ba(OH)₂
The common weak baseNH₃ (ammonia)
Group 1 hydroxides and the heavier Group 2 hydroxides are strong; ammonia is the common weak base.

The hydroxides of the heavier Group 2 metals are also strong: Ca(OH)₂, Sr(OH)₂, and Ba(OH)₂.

The common weak base is ammonia, NH₃ — most dissolved NH₃ stays whole.

Worked examples

Worked example 1. Is Ba(OH)₂ a strong base or a weak base?

Step 1

Answer: strong — barium is one of the heavier Group 2 metals on the list.

Worked example 2. Is the ammonia in glass cleaner a strong base or a weak base?

Step 1

Answer: weak — ammonia is the common weak base.

You can now state that the common strong bases are the group 1 metal hydroxides (LiOH, NaOH, KOH) and the heavier group 2 metal hydroxides (Ca(OH)₂, Sr(OH)₂, Ba(OH)₂), and that ammonia is the common weak base.

Check your understanding

Which of these bases is the common WEAK base?

ANH₃correct
BNaOH
This option is wrong — you picked a Group 1 hydroxide — those are all strong; the common weak base is ammonia.
CCa(OH)₂
This option is wrong — you picked a heavier Group 2 hydroxide — those are strong; the common weak base is ammonia.
DLiOH
This option is wrong — you picked a Group 1 hydroxide — those are all strong; the common weak base is ammonia.
Group 1 hydroxides and the heavier Group 2 hydroxides are the strong bases. The common weak base is ammonia, NH₃ — most dissolved NH₃ stays whole.
Check your understanding

Which list contains ONLY strong bases?

ALiOH, Ca(OH)₂, Ba(OH)₂correct
BNaOH, KOH, NH₃
This option is wrong — you slipped ammonia in — NH₃ is the common weak base.
CLiOH, NaOH, Mg(OH)₂
This option is wrong — you included magnesium hydroxide — the Group 2 members on the list are the heavier three: Ca, Sr, Ba.
DKOH, Ca(OH)₂, HNO₃
This option is wrong — you included nitric acid — it is a strong ACID; the strong-base list holds metal hydroxides.
The strong bases are LiOH, NaOH, KOH and Ca(OH)₂, Sr(OH)₂, Ba(OH)₂. LiOH, Ca(OH)₂, and Ba(OH)₂ are all members; the other sets each hide a non-member.
Check your understanding

Sr(OH)₂ dissolves in water. What happens to its dissolved units?

AEvery one splits into Sr²⁺ and OH⁻ ions.correct
BMost stay whole, with only a few splitting.
This option is wrong — you treated it as weak — strontium hydroxide is one of the heavier Group 2 strong bases, so it ionizes completely.
CNone split, so the solution holds no ions.
This option is wrong — you turned a strong base into a non-electrolyte — a strong base splits completely, flooding the solution with ions.
DThey split only when an acid is added to the water.
This option is wrong — you made ionization conditional — a strong base splits completely in plain water.
Sr(OH)₂ is on the strong-base list — the heavier Group 2 hydroxides. A strong base ionizes completely: every dissolved unit splits into Sr²⁺ and OH⁻.

Lesson 25 of 45 · ABS-025

Strength is not concentration
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Have You Ever Wondered?
Wonder this:

Vinegar is about 0.8 M acetic acid, and it goes on salads. A 0.10 M hydrochloric acid solution holds far less acid per liter — yet chemists call the hydrochloric acid the strong one. If there is less of it, what makes it strong?

You have seen that a strong acid or base ionizes completely in water while a weak one ionizes only partially. 'Strong' answers one question about a solution. 'Concentrated' answers a different one.

The idea

An acid's 'strength' reports the fraction of its dissolved particles that ionize in water.

An acid's 'concentration' reports how much acid is dissolved per liter of solution — the molarity you have seen.

Strength is fixed by which acid it is; concentration is chosen by whoever mixes the solution.

Hydrochloric acid ionizes completely at 6.0 M and it ionizes completely at 0.10 M — diluting it changes the concentration, never the strength.

'Concentrated' and 'dilute' describe concentration; 'strong' and 'weak' describe strength.

So a dilute solution of hydrochloric acid is still a strong-acid solution — a small amount of acid, every particle of it ionized.

A two-by-two grid of beakers. The top row shows hydrochloric acid: a dilute beaker with four dissolved units all split into ions, and a concentrated beaker with twelve dissolved units all split into ions. The bottom row shows acetic acid: a dilute beaker with four units of which one is split, and a concentrated beaker with twelve units of which three are split.dilute (0.10 M)concentrated (6.0 M)hydrochloric acid — strongH⁺Cl⁻H⁺Cl⁻H⁺Cl⁻H⁺Cl⁻H⁺Cl⁻H⁺Cl⁻H⁺Cl⁻H⁺Cl⁻H⁺Cl⁻H⁺Cl⁻H⁺Cl⁻H⁺Cl⁻H⁺Cl⁻H⁺Cl⁻H⁺Cl⁻H⁺Cl⁻acetic acid — weakH⁺Ac⁻HAcHAcHAcH⁺Ac⁻H⁺Ac⁻H⁺Ac⁻HAcHAcHAcHAcHAcHAcHAcHAcHAc
Concentration sets how many particles are in the beaker; strength sets what fraction of them are split into ions.

And a concentrated solution of acetic acid is still a weak-acid solution — a large amount of acid, most of it staying whole.

Worked examples

Worked example 1. A bottle holds a 0.050 M solution of nitric acid, HNO₃. A student calls the solution weak because so little acid is dissolved. Is the student right?

Step 1

Ask the two questions separately.

Step 2

Concentration: 0.050 M is a small amount per liter, so the solution is dilute.

Step 3

Strength: HNO₃ is one of the six strong acids, so every dissolved particle ionizes.

Step 4

No — the solution is dilute but still strong; diluting an acid never changes its strength.

Worked example 2. A 5.0 M solution of hydrofluoric acid, HF, is prepared. Does packing in that much acid make the solution strong?

Step 1

Concentration: 5.0 M is a large amount per liter, so the solution is concentrated.

Step 2

Strength: HF is not on the list of six strong acids, so it is weak — most of its molecules stay whole in water.

Step 3

No — the solution is concentrated but still weak; adding more acid raises the concentration, never the strength.

You can now explain the difference between an acid's strength and its concentration: strength reports the fraction of dissolved particles that ionize, while concentration reports how much acid is dissolved per liter of solution.

Check your understanding

A laboratory bottle holds a 0.020 M solution of hydroiodic acid, HI. Which pair of labels describes the solution?

ADilute, and a strong acid.correct
BDilute, and a weak acid.
This option is wrong — you read the low concentration as weakness — HI is one of the six strong acids, and diluting it changes only the concentration.
CConcentrated, and a strong acid.
This option is wrong — you judged the concentration wrong — 0.020 mol per liter is a small amount of dissolved acid, so the solution is dilute.
DConcentrated, and a weak acid.
This option is wrong — you swapped both labels — 0.020 M is a small amount per liter (dilute), and HI is one of the six strong acids.
Ask the two questions separately. Concentration: 0.020 mol per liter is a small amount, so the solution is dilute. Strength: HI is one of the six strong acids — it ionizes completely at any concentration.
Check your understanding

A window-cleaner concentrate is a 5.0 M solution of ammonia, NH₃. Which pair of labels describes the solution?

AConcentrated, and a weak base.correct
BConcentrated, and a strong base.
This option is wrong — you read the high concentration as strength — ammonia is the common weak base, and packing in more of it raises only the concentration.
CDilute, and a weak base.
This option is wrong — you judged the concentration wrong — 5.0 mol per liter is a large amount of dissolved base, so the solution is concentrated.
DDilute, and a strong base.
This option is wrong — you swapped both labels — 5.0 M is a large amount per liter (concentrated), and ammonia is the common weak base.
Concentration: 5.0 mol per liter is a large amount, so the solution is concentrated. Strength: ammonia is the common weak base — most of its molecules stay whole in water, however much is dissolved. Concentrated describes the amount; weak describes the fraction that ionizes.
Check your understanding

What does an acid's strength report?

AThe fraction of its dissolved particles that ionize in water.correct
BThe number of moles of acid dissolved per liter of solution.
This option is wrong — you gave the definition of concentration — that is molarity, the quantity 'concentrated' and 'dilute' describe.
CThe total number of acid particles in the container.
This option is wrong — you counted particles instead of taking a fraction — strength is the share of the dissolved particles that split, not how many there are.
DHow much water was used to prepare the solution.
This option is wrong — you described dilution — adding water changes the concentration, and strength stays fixed because it depends only on which acid it is.
Strength reports the fraction of the dissolved particles that ionize in water. Concentration reports how much acid is dissolved per liter. The two questions have separate answers: a solution can be dilute and strong, or concentrated and weak.

Lesson 26 of 45 · ABS-026

Strong or weak from data
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You have seen what strong and weak mean, which acids and bases are on the strong lists, and that strength is not concentration. Real laboratory data lets you classify an acid or base you have never met.

The idea

Whether an acid or base is strong or weak can be read from data about its solution.

Evidence one — the fraction ionized: a strong acid or base ionizes close to 100%, while a weak one ionizes only a few percent.

A 0.10 M HCl solution is essentially 100% ionized; a 0.10 M HF solution is about 8% ionized.

Three kinds of strength evidence

EvidenceStrong acid or baseWeak acid or base
Fraction ionizedclose to 100%only a few percent
Particle diagramevery dissolved unit split into ionsmostly whole molecules, a few split
Conductivity bulb (same concentration as a known strong acid)brightdim
All three data classes answer one question: what fraction of the dissolved particles has split into ions?

Evidence two — a particle diagram: a strong acid's diagram shows every dissolved unit split into ions, while a weak acid's diagram shows mostly whole molecules with only a few split.

Evidence three — conductivity: compared with a known strong acid at the same concentration, a weak acid lights a conductivity bulb dimly, because it supplies fewer moving ions.

Whatever the data type, the question is always the same: what fraction of the dissolved particles has split into ions?

Watch the boundary you have seen: a small total number of dissolved particles means dilute, not weak — only the fraction split reports strength.

Worked examples

Worked example 1. A data table reports that a 0.10 M solution of propanoic acid is about 1% ionized. Classify propanoic acid as strong or weak.

Step 1

The fraction ionized is the strength evidence.

Step 2

1% ionized means about 99 of every 100 dissolved molecules stay whole.

Step 3

Propanoic acid is weak — only a small fraction of its dissolved particles ionizes.

Worked example 2. The figure shows a particle diagram of a hydrobromic acid solution, HBr, with six dissolved units. Classify hydrobromic acid as strong or weak.

solution particle diagram — single; H⁺; A⁻singleH⁺A⁻H⁺A⁻H⁺A⁻H⁺A⁻H⁺A⁻H⁺A⁻
Step 1

Count the fraction split: all 6 of the 6 dissolved units in the figure are drawn as separated H⁺ and Br⁻ ions.

Step 2

Every dissolved unit has ionized.

Step 3

Hydrobromic acid is strong — the diagram shows complete ionization.

You can now classify an acid or base as strong or weak from supplied ionization data, such as the fraction of particles ionized, a particle diagram of the solution, or its electrical conductivity compared with a reference strong acid at the same concentration.

Check your understanding

A 0.10 M solution of hypochlorous acid, HOCl, lights a conductivity bulb dimly. A 0.10 M solution of hydrochloric acid lights the same bulb brightly. What does the data show about hypochlorous acid?

AIt is weak — at the same concentration it supplies far fewer ions than the strong acid.correct
BIt is strong — any solution that lights the bulb at all is fully ionized.
This option is wrong — you treated any conductivity as complete ionization — a dim glow at matched concentration means only a small fraction of the HOCl has split into ions.
CIt is strong — every compound whose formula starts with H ionizes completely in water.
This option is wrong — you classified from the formula instead of the data — only the six listed acids are strong, and this solution's dim glow shows partial ionization.
DThe data shows only that the solution is dilute — dim light means little acid is dissolved.
This option is wrong — you read conductivity as concentration — both solutions are 0.10 M, so the dimness must come from a smaller fraction ionized, not from less acid.
Both solutions hold the same amount of acid per liter, so the comparison is fair. The dim bulb means fewer moving ions — only a small fraction of the HOCl has split. Hypochlorous acid is weak, because a strong acid or base splits completely into ions in water, while a weak one splits only partially.
Check your understanding

The figure shows a particle diagram of a nitrous acid solution, HNO₂. What does the diagram show about nitrous acid?

solution particle diagram — single; H⁺; A⁻singleH⁺A⁻H⁺A⁻H⁺A⁻H⁺A⁻H⁺A⁻H⁺A⁻H⁺A⁻H⁺A⁻H⁺A⁻H⁺A⁻
AOnly a small fraction of the dissolved acid has split into ions, so it is weak.correct
BEvery dissolved unit has split into ions, so the acid is strong.
This option is wrong — you miscounted the split units — 9 of the 10 dissolved units are still whole molecules; only 1 has ionized.
CVery little acid is dissolved, so the solution is dilute rather than weak.
This option is wrong — you read the whole molecules as undissolved — every particle shown is dissolved, and the small fraction SPLIT is what reports weakness.
DThe solution contains no ions at all, so the substance is not an acid.
This option is wrong — you missed the ionized pair — one H⁺ and NO₂⁻ pair is present, which is exactly the partial ionization a weak acid shows.
Count the fraction split: 1 of the 10 dissolved units is ions; 9 stay whole. A small fraction split is the weak-acid signature, because a strong acid or base splits completely into ions in water, while a weak one splits only partially.
Check your understanding

A reference book reports that a 0.10 M solution of ammonia is about 1.3% ionized. What does this figure show about ammonia?

AIt is a weak base — nearly 99% of its dissolved molecules stay whole.correct
BIt is a strong base — 1.3% counts as complete ionization for a base.
This option is wrong — you moved the strong boundary — strong means close to 100% ionized for bases exactly as for acids, and 1.3% is nowhere near it.
CIt is a dilute base — 1.3% means very little ammonia is dissolved.
This option is wrong — you read the ionized fraction as a concentration — the solution holds 0.10 mol per liter, and 1.3% is the share of those molecules that split.
DIt is not a base at all — a true base would show 0% ionization.
This option is wrong — you flipped the ionization sign for bases — bases DO ionize in water, releasing OH⁻; a weak base simply ionizes only partially.
1.3% ionized means about 99 of every 100 dissolved ammonia molecules stay whole. That small fraction split is the weak signature, because a strong acid or base splits completely into ions in water, while a weak one splits only partially.
Summary video — Strong and weak

Watch in David’s player

End of Topic Test

End of Topic Test — five interchangeable forms, delivered separately.

Intro video — The pH scale

Watch in David’s player

Lesson 27 of 45 · ABS-027

What pH reports
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Wonder this:

A liter of black coffee holds about 0.00001 mol of hydrogen ions; a liter of lemon juice holds about 0.01 mol. Comparing solutions by counting zeros is slow and easy to get wrong. Chemists compress the whole comparison into one small number.

You have seen that acids release H⁺ into water, that H⁺ travels as H₃O⁺, and that molarity measures how much is dissolved per liter.

The idea

Chemists write the hydrogen-ion concentration of a solution as '[H⁺]' — read the square brackets as 'the concentration of', measured in molarity.

'pH' is a single number, usually between 0 and 14, that reports a solution's [H⁺].

The scale runs in reverse: the lower the pH, the higher the [H⁺].

A pH 3 solution has a higher [H⁺] than a pH 10 solution.

A horizontal pH number line from 0 to 14 with two arrows beneath it: one pointing toward 0 labeled lower pH, higher hydrogen-ion concentration, and one pointing toward 14 labeled higher pH, lower hydrogen-ion concentration.0714pHlower pH — higher [H⁺]higher pH — lower [H⁺]
pH packs a solution's [H⁺] into one number — and the scale runs in reverse.

Read the other way, the higher the pH, the lower the [H⁺].

Worked examples

Worked example 1. One solution has pH 2 and another has pH 9. Which has the higher hydrogen-ion concentration?

Step 1

Lower pH means higher [H⁺].

Step 2

The pH 2 solution has the higher [H⁺].

Worked example 2. A pH meter dipped into a solution reads 6. What quantity is that number reporting?

Step 1

The solution's hydrogen-ion concentration, [H⁺].

You can now state that pH is a single number, usually between 0 and 14, that reports the hydrogen-ion concentration of a solution - written [H⁺] - with a lower pH meaning a higher [H⁺].

Check your understanding

What does a solution's pH report?

AIts hydrogen-ion concentration, [H⁺].correct
BIts total amount of dissolved substance per liter.
This option is wrong — you generalized pH to all solutes — pH tracks one specific ion, H⁺, not everything dissolved.
CIts temperature on a 0-to-14 scale.
This option is wrong — you borrowed the 0-to-14 range for the wrong quantity — the number reports [H⁺], and temperature has its own scales.
DThe volume of acid added to the solution.
This option is wrong — you made pH a bookkeeping record — pH is measured from the solution itself and reports the H⁺ concentration in it.
pH is a single number, usually between 0 and 14, that reports a solution's [H⁺]. Read [H⁺] as 'the hydrogen-ion concentration', measured in molarity.
Check your understanding

A rainwater sample has pH 5 and a tap-water sample has pH 7. Which statement is correct?

AThe rainwater has the higher [H⁺].correct
BThe tap water has the higher [H⁺].
This option is wrong — you read a bigger pH as more H⁺ — the scale runs in reverse, so the LOWER pH marks the higher [H⁺].
CThe two samples have the same [H⁺].
This option is wrong — you treated different pH values as equivalent — different pH numbers always mean different hydrogen-ion concentrations.
DThe volumes must be known before the two can be compared.
This option is wrong — you brought volume in — [H⁺] is already an amount per liter, so pH values compare directly.
Lower pH means higher [H⁺]. pH 5 is lower than pH 7, so the rainwater has the higher hydrogen-ion concentration.
Check your understanding

How should the symbol [H⁺] be read?

AThe concentration of hydrogen ions, in molarity.correct
BThe number of hydrogen ions in the sample.
This option is wrong — you read the brackets as a count — [H⁺] is an amount per liter, not a total number of ions.
CThe mass of hydrogen dissolved, in grams.
This option is wrong — you swapped concentration for mass — the brackets mean concentration, and it is measured in mol per liter.
DThe charge carried by one hydrogen ion.
This option is wrong — you read the superscript plus as the whole meaning — the plus marks the ion's charge, and the brackets around it mean its concentration.
Square brackets around a particle mean 'the concentration of' that particle. [H⁺] is the hydrogen-ion concentration, measured in molarity.

Lesson 28 of 45 · ABS-028

Acidic, neutral, or basic
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You have seen that pH reports a solution's [H⁺], with lower pH meaning higher [H⁺]. The scale also sorts every solution into three named bands.

The idea

The pH scale sorts every solution into three bands.

A solution with pH below 7 is 'acidic'.

A pH scale from 0 to 14 divided into three labeled bands: acidic below 7, neutral at exactly 7, and basic above 7, with markers for lemon juice at pH 2, pure water at pH 7, and household ammonia at pH 11.acidicneutralbasic01234567891011121314pHlemon juicepure waterhousehold ammonia
Below 7 acidic, exactly 7 neutral, above 7 basic — the boundary at 7 is sharp.

A solution with pH exactly 7 is 'neutral' — pure water sits here.

A solution with pH above 7 is 'basic'.

The boundary is sharp: pH 6 is acidic and pH 8 is basic, even though both sit close to 7.

Lemon juice at pH 2 is acidic, pure water at pH 7 is neutral, and household ammonia at pH 11 is basic.

Worked examples

Worked example 1. Black coffee has pH 5. Classify it as acidic, neutral, or basic.

Step 1

Compare the pH with 7: 5 is below 7.

Step 2

Black coffee is acidic.

Worked example 2. A baking-soda solution has pH 9. Classify it as acidic, neutral, or basic.

Step 1

Compare the pH with 7: 9 is above 7.

Step 2

The baking-soda solution is basic.

You can now classify a solution as acidic, neutral, or basic from its pH, using pH below 7 = acidic, pH 7 = neutral, and pH above 7 = basic.

Check your understanding

Tomato juice has pH 4. Classify it as acidic, neutral, or basic.

AAcidiccorrect
BBasic
This option is wrong — you read the scale backwards — a pH BELOW 7 is acidic, and 4 is below 7.
CNeutral
This option is wrong — you widened the neutral band — neutral is pH exactly 7, and 4 is well below it.
DNone of the three bands
This option is wrong — you looked for a fourth category — every pH value sorts into one of the three bands, and 4 falls in the acidic band.
Compare the pH with 7. 4 is below 7, so tomato juice is acidic.
Check your understanding

A milk-of-magnesia mixture has pH 10. Classify it as acidic, neutral, or basic.

ABasiccorrect
BAcidic
This option is wrong — you read the scale backwards — a pH ABOVE 7 is basic, and 10 is above 7.
CNeutral
This option is wrong — you widened the neutral band — neutral is pH exactly 7 only.
DNone of the three bands
This option is wrong — you looked for a fourth category — every pH value sorts into one of the three bands, and 10 falls in the basic band.
Compare the pH with 7. 10 is above 7, so the mixture is basic.
Check your understanding

A freshly made sugar solution has pH 7. Classify it as acidic, neutral, or basic.

ANeutralcorrect
BAcidic
This option is wrong — you pushed 7 into the lower band — acidic needs a pH BELOW 7, and this solution sits exactly at 7.
CBasic
This option is wrong — you pushed 7 into the upper band — basic needs a pH ABOVE 7, and this solution sits exactly at 7.
DNone of the three bands
This option is wrong — you treated 7 as a gap between bands — pH exactly 7 IS the neutral band.
Compare the pH with 7. The pH is exactly 7, so the solution is neutral — dissolved sugar releases neither H⁺ nor OH⁻.

Lesson 29 of 45 · ABS-029

Ten times per pH unit
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Did You Know?

You have seen that lower pH means higher [H⁺]. The scale also says exactly how much higher each step is.

The idea

Each change of one pH unit means a tenfold change in [H⁺].

Step down one pH unit, and the [H⁺] is ten times higher.

A vertical ladder with three rungs labeled pH 7, pH 6, and pH 5 from top to bottom. An arrow from pH 7 down to pH 6 is labeled hydrogen-ion concentration times ten, and an arrow from pH 6 down to pH 5 carries the same label.pH 7pH 6pH 5[H⁺] × 10[H⁺] × 10
Every one-unit step down the pH ladder multiplies the [H⁺] by ten.

Step up one pH unit, and the [H⁺] is ten times lower — one tenth as much.

A pH 6 solution has ten times the [H⁺] of a pH 7 solution.

Take one more step down, and a pH 5 solution has ten times the [H⁺] of the pH 6 solution.

One small step on the scale stands for a whole factor of ten in [H⁺] — that is how pH swallows all those zeros.

Worked examples

Worked example 1. One solution has pH 3 and another has pH 4. How do their hydrogen-ion concentrations compare?

Step 1

The two are one pH unit apart, and the lower pH marks the higher [H⁺].

Step 2

The pH 3 solution has ten times the [H⁺] of the pH 4 solution.

Worked example 2. A solution's pH rises from 8 to 9. What happens to its [H⁺]?

Step 1

One pH unit up means the [H⁺] is ten times lower.

Step 2

The [H⁺] falls to one tenth of what it was.

You can now state that each change of one pH unit means a tenfold change in [H⁺] of a pH 5 solution].

Check your understanding

One solution has pH 1 and another has pH 2. How do their hydrogen-ion concentrations compare?

AThe pH 1 solution has ten times the [H⁺] of the pH 2 solution.correct
BThe pH 1 solution has twice the [H⁺] of the pH 2 solution.
This option is wrong — you treated the scale as additive — one pH unit is a factor of TEN in [H⁺], not a doubling.
CThe pH 2 solution has ten times the [H⁺] of the pH 1 solution.
This option is wrong — you flipped the direction — the LOWER pH marks the higher [H⁺].
DThe two have almost the same [H⁺], because 1 and 2 are neighboring values.
This option is wrong — you read neighboring pH values as similar concentrations — each single unit hides a full factor of ten.
Each change of one pH unit means a tenfold change in [H⁺]. pH 1 is one unit below pH 2, so its [H⁺] is ten times higher.
Check your understanding

A solution's pH falls from 12 to 11. What happens to its [H⁺]?

AIt becomes ten times higher.correct
BIt becomes ten times lower.
This option is wrong — you flipped the direction — a FALLING pH means a rising [H⁺].
CIt rises by one unit.
This option is wrong — you moved the pH step onto the concentration — the pH changed by one unit, and that one unit means the [H⁺] multiplied by ten.
DIt stays the same, because both values are in the same part of the scale.
This option is wrong — you treated a pH change as cosmetic — any one-unit change means a tenfold change in [H⁺].
Step down one pH unit, and the [H⁺] is ten times higher. The pH fell from 12 to 11 — one unit down — so the [H⁺] multiplied by ten.
Check your understanding

Solution X has one tenth the hydrogen-ion concentration of solution Y. Solution Y has pH 4. What is the pH of solution X?

ApH 5correct
BpH 3
This option is wrong — you stepped the wrong way — one TENTH the [H⁺] means one pH unit HIGHER, not lower.
CpH 4.1
This option is wrong — you treated a tenfold change as a small nudge — a factor of ten is exactly one whole pH unit.
DpH 14
This option is wrong — you multiplied the pH by ten — the factor of ten belongs to the [H⁺]; the pH itself moves by just one unit.
A tenfold change in [H⁺] is exactly one pH unit. Solution X has LESS H⁺, so its pH is one unit higher: pH 5.

Lesson 30 of 45 · ABS-030

Comparing solutions by pH
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Did You Know?

You have seen that each pH unit is a factor of ten in [H⁺]. Solutions further apart on the scale just stack those factors.

The idea

To compare two solutions' [H⁺], count the pH units between them.

Each pH unit of difference multiplies the [H⁺] by ten.

So the factor between the two solutions is a ten for every unit: two units apart means 10 × 10 = 100 times.

The solution with the lower pH is the one with the greater [H⁺].

A diagram showing pH 6 stepping down to pH 5 and then to pH 4, each step labeled times ten, with a bracket spanning both steps labeled times one hundred in hydrogen-ion concentration.pH 6pH 5pH 4× 10× 10× 100 in [H⁺]
Two pH units apart: a ten for every unit, so 10 × 10 = 100 times the [H⁺].

A pH 4 solution and a pH 6 solution sit two units apart, so the pH 4 solution has 100 times the [H⁺] of the pH 6 solution.

Worked examples

Worked example 1. How many times greater is the [H⁺] of a pH 1 solution than that of a pH 4 solution?

Step 1

Count the units between the two pH values: 4 − 1 = 3 units.

Step 2

Each unit is a factor of ten: 10 × 10 × 10 = 1000.

Step 3

The pH 1 solution has the lower pH, so it is the one with the greater [H⁺].

Step 4

The pH 1 solution has 1000 times the [H⁺] of the pH 4 solution.

Worked example 2. How many times greater is the [H⁺] of a pH 3 solution than that of a pH 8 solution?

Step 1

Count the units between the two pH values: 8 − 3 = 5 units.

Step 2

Each unit is a factor of ten: 10 × 10 × 10 × 10 × 10 = 100,000.

Step 3

The pH 3 solution has 100,000 times the [H⁺] of the pH 8 solution.

You can now calculate how many times greater the [H⁺] of one solution is than that of another from their whole-number pH values, using a factor of 10 per pH unit of a pH 5 solution].

Check your understanding

How many times greater is the [H⁺] of a pH 2 solution than that of a pH 4 solution?

Answer: 100 times (tolerance ±0.5)
Count the units between the two pH values: 4 − 2 = 2 units. Each unit is a factor of ten: 10 × 10 = 100. The pH 2 solution has 100 times the [H⁺] of the pH 4 solution.
Check your understanding

How many times greater is the [H⁺] of a pH 6 solution than that of a pH 9 solution?

Answer: 1000 times (tolerance ±0.5)
Count the units between the two pH values: 9 − 6 = 3 units. Each unit is a factor of ten: 10 × 10 × 10 = 1000. The pH 6 solution has 1000 times the [H⁺] of the pH 9 solution.
Check your understanding

How many times greater is the [H⁺] of a pH 2 solution than that of a pH 6 solution?

Answer: 10,000 times (tolerance ±0.5)
Count the units between the two pH values: 6 − 2 = 4 units. Each unit is a factor of ten: 10 × 10 × 10 × 10 = 10,000. The pH 2 solution has 10,000 times the [H⁺] of the pH 6 solution.

Lesson 31 of 45 · ABS-031

H⁺ and OH⁻ move oppositely
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Did You Know?

You have seen that acids supply H⁺ and bases supply OH⁻, and that pH sorts solutions into acidic, neutral, and basic. Both ions are present in every one of those solutions.

The idea

Every water solution contains both H⁺ ions and OH⁻ ions — the acidic ones, the neutral ones, and the basic ones alike.

The two concentrations trade off: when [H⁺] rises, [OH⁻] falls, and when [H⁺] falls, [OH⁻] rises.

In an acidic solution, [H⁺] is greater than [OH⁻].

In a neutral solution, [H⁺] and [OH⁻] are equal.

Three panels labeled acidic, neutral, and basic, each with two bars for hydrogen-ion and hydroxide-ion concentration. In the acidic panel the hydrogen-ion bar is tall and the hydroxide bar short; in the neutral panel the bars are equal; in the basic panel the hydroxide bar is tall and the hydrogen-ion bar short. No bar has zero height.[H⁺][OH⁻]acidic[H⁺][OH⁻]neutral[H⁺][OH⁻]basic
Both ions are present in every solution; the taller bar tells you which band the solution is in.

In a basic solution, [OH⁻] is greater than [H⁺].

So a basic solution still contains some H⁺ — just less of it than OH⁻.

Worked examples

Worked example 1. A drain-opener solution is basic. Compare its [H⁺] and [OH⁻].

Step 1

Basic means [OH⁻] is greater than [H⁺].

Step 2

Its [OH⁻] is greater than its [H⁺] — but some H⁺ is still present.

Worked example 2. Acid is added to a neutral solution, and its [H⁺] rises. What happens to its [OH⁻]?

Step 1

The two concentrations trade off: when one rises, the other falls.

Step 2

The [OH⁻] falls.

You can now predict the relative sizes of [H⁺] and [OH⁻] in acidic, neutral, and basic solutions, using the qualitative pattern that when one rises the other falls greater than [OH⁻]].

Check your understanding

White vinegar is an acidic solution. Which statement about its ion concentrations is correct?

AIts [H⁺] is greater than its [OH⁻].correct
BIts [OH⁻] is greater than its [H⁺].
This option is wrong — you flipped the pattern — the ion in excess in an ACIDIC solution is H⁺.
CIts [H⁺] and [OH⁻] are equal.
This option is wrong — you gave the neutral pattern — equal concentrations belong to neutral solutions only.
DIt contains H⁺ ions but no OH⁻ ions at all.
This option is wrong — you removed one ion completely — every water solution contains BOTH ions; acidic just means H⁺ is the greater one.
In an acidic solution, [H⁺] is greater than [OH⁻]. Both ions are still present — the acid tipped the balance toward H⁺, it did not erase the OH⁻.
Check your understanding

In a sample of pure water, how do [H⁺] and [OH⁻] compare?

AThey are equal.correct
B[H⁺] is greater than [OH⁻].
This option is wrong — you gave the acidic pattern — pure water is neutral, and neutral means the two concentrations match.
C[OH⁻] is greater than [H⁺].
This option is wrong — you gave the basic pattern — pure water is neutral, and neutral means the two concentrations match.
DBoth are zero — pure water contains no ions.
This option is wrong — you emptied the water of ions — even pure water contains small, equal amounts of H⁺ and OH⁻.
Pure water is neutral. In a neutral solution, [H⁺] and [OH⁻] are equal — both present, in matching small amounts.
Check your understanding

A pool chemical dissolved in water makes the water's [OH⁻] rise. What happens to the water's [H⁺]?

AIt falls.correct
BIt rises by the same amount.
This option is wrong — you moved the two concentrations together — they trade off: when one rises, the other falls.
CIt stays exactly the same.
This option is wrong — you treated the two ions as independent — a rise in [OH⁻] always comes with a fall in [H⁺].
DIt falls all the way to zero.
This option is wrong — you overshot the fall — [H⁺] drops but never disappears; every solution keeps some of both ions.
The two concentrations trade off: when [OH⁻] rises, [H⁺] falls. It falls without vanishing — some H⁺ remains in even the most basic solution.

Lesson 32 of 45 · ABS-032

The pH equation
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You have seen that each pH unit means a factor of ten in [H⁺]. That tenfold pattern is no coincidence — it is built into pH's definition.

The equation

pH is defined by the equation pH = −log[H⁺].

The 'log' of a power of ten is simply its exponent: the log of 1 × 10⁻⁴ is −4.

The equation pH equals negative log of hydrogen-ion concentration, annotated: pH is a bare number with no unit, the negative log flips the sign of the exponent, and the bracketed H plus is the hydrogen-ion concentration in molarity, always one times ten to the minus n in this course. A worked strip shows that a concentration of one times ten to the minus four molar gives pH four.pH=−log[H⁺]a bare number, no unitflips the sign of the exponenthydrogen-ion concentration, in M — herealways 1 × 10⁻ⁿ
pHpH (no unit)
[H⁺]hydrogen-ion concentration (M)

The minus sign in the equation then flips that exponent's sign: pH = −(−4) = 4.

So for [H⁺] = 1 × 10⁻ⁿ M, the pH is simply n.

In this course the equation is used only when [H⁺] is a whole-number power of ten — concentrations written 1 × 10⁻ⁿ M, never values in between.

The tenfold-per-unit behavior falls straight out: each step of n is one more power of ten in [H⁺].

Worked examples

Worked example 1. What is the pH of a solution with [H⁺] = 1 × 10⁻⁹ M?

Step 1

The exponent is −9, and the equation's minus sign flips it.

Step 2

The pH is 9.

Worked example 2. Which equation defines pH?

Step 1

pH = −log[H⁺].

You can now state the definition pH = −log[H⁺], used in this course only for concentrations that are whole-number powers of ten, where [H⁺] = 1 × 10⁻ⁿ M gives pH = n = 1 × 10⁻⁶ M has pH 6].

Check your understanding

Which equation defines pH?

ApH = −log[H⁺]correct
BpH = log[H⁺]
This option is wrong — you dropped the minus sign — without it every pH would come out negative, since the exponents of [H⁺] are negative.
CpH = −log[OH⁻]
This option is wrong — you swapped in the wrong ion — pH reports the HYDROGEN-ion concentration.
D[H⁺] = −log(pH)
This option is wrong — you turned the definition inside out — the log acts on [H⁺] to give the pH, not the other way around.
pH is defined by the equation pH = −log[H⁺]. The minus sign flips the exponent's sign, so a concentration of 1 × 10⁻ⁿ M gives a positive pH of n.
Check your understanding

A solution has [H⁺] = 1 × 10⁻ⁿ M, where n is a whole number. What is its pH?

Ancorrect
B−n
This option is wrong — you forgot the equation's minus sign — it flips the exponent's −n into n.
C10⁻ⁿ
This option is wrong — you gave the concentration's power back — the pH is the exponent's number itself, not a power of ten.
D14 − n
This option is wrong — you subtracted from 14 — no such step exists in the definition; the pH is simply n.
The log of 1 × 10⁻ⁿ is −n. The equation's minus sign flips −n to n, so the pH is n.
Check your understanding

In this course, when may the equation pH = −log[H⁺] be used?

AOnly when [H⁺] is a whole-number power of ten, written 1 × 10⁻ⁿ M.correct
BOnly when the solution has already been classified as acidic.
This option is wrong — you tied the equation to one band — the definition holds at every pH; the course restriction is about the FORM of the concentration.
CFor any [H⁺] value, including ones like 3.2 × 10⁻⁴ M.
This option is wrong — you ignored the course's validity condition — in-between concentrations need calculator logarithms, which this course does not use.
DOnly when [OH⁻] is known as well.
This option is wrong — you added an ingredient the equation never uses — pH is computed from [H⁺] alone.
In this course the equation is used only when [H⁺] is a whole-number power of ten — 1 × 10⁻ⁿ M. For those concentrations the log is just the exponent, so no calculator is needed.

Lesson 33 of 45 · ABS-033

pH from concentration
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Did You Know?

You have seen the definition pH = −log[H⁺], and that a concentration of 1 × 10⁻ⁿ M gives a pH of n. This lesson runs that as a calculation routine, start to finish.

The equation

To calculate a pH, write down the value of [H⁺], write down the equation, substitute, and calculate.

In the calculate step, the log of 1 × 10⁻ⁿ is −n, and the equation's minus sign turns −n into n.

If the concentration arrives as a decimal, first rewrite it as a power of ten: 0.00001 M is 1 × 10⁻⁵ M.

pH carries no unit — the answer is a bare number.

So a solution with [H⁺] = 0.00001 M has [H⁺] = 1 × 10⁻⁵ M, and its pH is 5.

The equation pH equals negative log of hydrogen-ion concentration annotated with the article's example: a concentration of one times ten to the minus five molar has exponent minus five, the log gives minus five, the minus sign flips it to five, and the pH is the bare number five.pH=−log[H⁺]1 × 10⁻⁵ M — exponent −5log gives −5; the minus sign flips it to 5pH = 5 — a bare number
pHpH (no unit)
[H⁺]hydrogen-ion concentration (M)
Worked examples

Worked example 1. What is the pH of a solution with [H⁺] = 1 × 10⁻⁸ M?

Step 1

Write down the values in the question

[H⁺] = 1 × 10⁻⁸ M

Step 2

Write down the equation

pH = −log[H⁺]

Step 3

Substitute in the values, and calculate

pH = −log(1 × 10⁻⁸) = −(−8)

pH = 8

Worked example 2. What is the pH of a solution with [H⁺] = 0.01 M?

Step 1

Write down the values in the question

[H⁺] = 0.01 M

Rewrite as a power of ten: [H⁺] = 1 × 10⁻² M

Step 2

Write down the equation

pH = −log[H⁺]

Step 3

Substitute in the values, and calculate

pH = −log(1 × 10⁻²) = −(−2)

pH = 2

You can now calculate the pH of a solution from a hydrogen-ion concentration given as a whole-number power of ten = 1 × 10⁻³ M].

Check your understanding

What is the pH of a solution with [H⁺] = 1 × 10⁻⁶ M? Give the pH as a whole number.

Answer: 6 (tolerance ±0.05)
Write down the values in the question: [H⁺] = 1 × 10⁻⁶ M Write down the equation: pH = −log[H⁺] Substitute in the values, and calculate: pH = −log(1 × 10⁻⁶) = −(−6) pH = 6
Check your understanding

What is the pH of a solution with [H⁺] = 1 × 10⁻¹² M? Give the pH as a whole number.

Answer: 12 (tolerance ±0.05)
Write down the values in the question: [H⁺] = 1 × 10⁻¹² M Write down the equation: pH = −log[H⁺] Substitute in the values, and calculate: pH = −log(1 × 10⁻¹²) = −(−12) pH = 12
Check your understanding

What is the pH of a solution with [H⁺] = 0.0001 M? Give the pH as a whole number.

Answer: 4 (tolerance ±0.05)
Write down the values in the question: [H⁺] = 0.0001 M Rewrite as a power of ten: [H⁺] = 1 × 10⁻⁴ M Write down the equation: pH = −log[H⁺] Substitute in the values, and calculate: pH = −log(1 × 10⁻⁴) = −(−4) pH = 4

Lesson 34 of 45 · ABS-034

Concentration from pH
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You have seen how to calculate a pH from [H⁺]. Laboratory work often runs the other way: a meter hands you the pH, and you want the concentration behind it.

The equation

The pH equation also runs backwards: from a known whole-number pH, you can recover [H⁺].

Make [H⁺] the subject of pH = −log[H⁺]: the concentration is [H⁺] = 1 × 10⁻ᵖᴴ M — ten to the power of MINUS the pH.

The pH becomes the exponent's number, and the exponent's sign is minus.

The rearranged equation, hydrogen-ion concentration equals one times ten to the power of minus the pH, in molarity, annotated to show the pH entering the exponent with a minus sign. A worked strip shows pH four giving a concentration of one times ten to the minus four molar.[H⁺]=1×10⁻ᵖᴴMthe concentration recovered — unit Mthe pH goes into the exponent, with a minussign
pHpH (no unit)
[H⁺]hydrogen-ion concentration (M)

A solution with pH 4 has [H⁺] = 1 × 10⁻⁴ M.

The answer is a concentration, so it carries the unit M.

Worked examples

Worked example 1. What is the [H⁺] of a solution with pH 10?

Step 1

Write down the values in the question

pH = 10

Step 2

Write down the equation

pH = −log[H⁺]

Step 3

Make the unknown the subject

[H⁺] = 1 × 10⁻ᵖᴴ

Step 4

Substitute in the values, and calculate

[H⁺] = 1 × 10⁻¹⁰

[H⁺] = 1 × 10⁻¹⁰ M

Worked example 2. What is the [H⁺] of a solution with pH 1?

Step 1

Write down the values in the question

pH = 1

Step 2

Write down the equation

pH = −log[H⁺]

Step 3

Make the unknown the subject

[H⁺] = 1 × 10⁻ᵖᴴ

Step 4

Substitute in the values, and calculate

[H⁺] = 1 × 10⁻¹

[H⁺] = 1 × 10⁻¹ M, which is 0.1 M

You can now calculate the hydrogen-ion concentration of a solution from its whole-number pH, by writing ten to the power of minus the pH = 1 × 10⁻⁵ M for a solution with pH 5].

Check your understanding

What is the [H⁺] of a solution with pH 5? Give your answer in M.

Answer: 1 × 10⁻⁵ M (tolerance ±5e-07)
Write down the values in the question: pH = 5 Write down the equation: pH = −log[H⁺] Make [H⁺] the subject: [H⁺] = 1 × 10⁻ᵖᴴ Substitute in the values, and calculate: [H⁺] = 1 × 10⁻⁵ [H⁺] = 1 × 10⁻⁵ M
Check your understanding

What is the [H⁺] of a solution with pH 12? Give your answer in M.

Answer: 1 × 10⁻¹² M (tolerance ±5e-14)
Write down the values in the question: pH = 12 Write down the equation: pH = −log[H⁺] Make [H⁺] the subject: [H⁺] = 1 × 10⁻ᵖᴴ Substitute in the values, and calculate: [H⁺] = 1 × 10⁻¹² [H⁺] = 1 × 10⁻¹² M
Check your understanding

What is the [H⁺] of a solution with pH 2? Give your answer in M.

Answer: 1 × 10⁻² M (tolerance ±0.0005)
Write down the values in the question: pH = 2 Write down the equation: pH = −log[H⁺] Make [H⁺] the subject: [H⁺] = 1 × 10⁻ᵖᴴ Substitute in the values, and calculate: [H⁺] = 1 × 10⁻² [H⁺] = 1 × 10⁻² M, which is 0.01 M

Lesson 35 of 45 · ABS-035

Indicator colors
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Wonder this:

A beaker of drain-cleaner solution and a beaker of pure water look identical — clear, colorless, still. Chemists make the difference visible by adding a single drop of dye.

You have seen the pH bands: acidic below 7, neutral at 7, basic above 7. Two dyes report those bands by color.

The idea

An 'acid-base indicator' is a dye whose color depends on the pH of the solution it is in.

'Phenolphthalein' is an indicator with two states: colorless in acidic and in neutral solutions, and pink in basic solutions.

'Universal indicator' is a mixture of dyes that runs through a whole range of colors as pH changes.

Its color is matched against a chart to read an approximate pH.

On the chart: red near pH 0–2, orange at pH 3–4, yellow at pH 5–6, green at pH 7, blue at pH 8–11, and purple at pH 12–14.

A two-part color chart. The universal indicator strip runs red at pH 0 to 2, orange at 3 to 4, yellow at 5 to 6, green at 7, blue at 8 to 11, and purple at 12 to 14. The phenolphthalein strip shows colorless for acidic and neutral solutions and pink for basic solutions.Universal indicatorredpH 0–2orangepH 3–4yellowpH 5–6greenpH 7bluepH 8–11purplepH 12–14Phenolphthaleincolorlessacidic and neutral (pH 7 and below)pinkbasic (above pH 7)
Two indicators, one idea: the color reports the pH.
Worked examples

Worked example 1. A few drops of phenolphthalein are added to a solution with pH 12. What color appears?

Step 1

Pink — phenolphthalein is pink in basic solutions.

Worked example 2. Universal indicator is added to a solution with pH 7. What color appears?

Step 1

Green — the chart's color for pH 7.

You can now state that an acid-base indicator is a dye whose color depends on the pH of the solution it is in, and state the colors of phenolphthalein (colorless in acidic and neutral solutions, pink in basic solutions) and of universal indicator (a color range matched against a chart to read an approximate pH).

Check your understanding

A few drops of phenolphthalein are added to a solution with pH 3. What color does the mixture show?

AColorlesscorrect
BPink
This option is wrong — you gave phenolphthalein's basic color — pink appears only above pH 7, and pH 3 is acidic.
CRed
This option is wrong — you used the universal-indicator chart — phenolphthalein has only two states, colorless and pink.
DGreen
This option is wrong — you used the universal-indicator chart's neutral color — phenolphthalein is colorless or pink, nothing else.
Phenolphthalein has two states: colorless in acidic and neutral solutions, pink in basic solutions. pH 3 is acidic, so the mixture stays colorless.
Check your understanding

Universal indicator is added to a solution with pH 1. What color does the mixture show?

ARedcorrect
BPurple
This option is wrong — you read the chart from the wrong end — purple sits at pH 12–14; the pH 0–2 end is red.
CGreen
This option is wrong — you gave the neutral color — green belongs to pH 7, and pH 1 sits at the red end of the chart.
DColorless
This option is wrong — you gave phenolphthalein's acidic state — universal indicator always shows a color; at pH 1 it is red.
Match the pH against the chart: red covers pH 0–2. pH 1 falls in that range, so the mixture turns red.
Check your understanding

What is an acid-base indicator?

AA dye whose color depends on the pH of the solution it is in.correct
BA meter that displays a solution's pH as a number.
This option is wrong — you described a pH meter — an indicator is a dye, and it reports pH by color, not by a numeric readout.
CA chemical that changes a solution's pH to 7.
This option is wrong — you made the indicator act on the solution — an indicator only REPORTS the pH; the drop of dye leaves the pH essentially unchanged.
DA dye that colors every solution the same fixed color.
This option is wrong — you removed the pH dependence — the whole point of an indicator is that its color CHANGES with the pH.
An acid-base indicator is a dye whose color depends on the pH of the solution it is in. Phenolphthalein and universal indicator are the two you have seen — one with two states, one with a full color range.

Lesson 36 of 45 · ABS-036

Reading indicator results
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You have seen the color facts for litmus paper, phenolphthalein, and universal indicator. This lesson turns any indicator observation into a verdict: acidic, basic, or near-neutral.

The idea

Read an indicator result in two steps: name the indicator, then match the observed color against that indicator's facts.

Blue litmus turning red is the acid signal; red litmus turning blue is the base signal.

When neither litmus paper changes color, the solution is near-neutral.

Phenolphthalein turning pink identifies a basic solution.

Phenolphthalein staying colorless only rules out basic — acidic and neutral solutions both leave it colorless, so colorless cannot separate those two.

Universal indicator is matched against its color chart: red sits at the strongly acidic end, orange and yellow are weakly acidic, green is near-neutral, blue is weakly basic, and purple sits at the strongly basic end.

A solution that turns universal indicator red is therefore identified as acidic.

A horizontal color chart for universal indicator running from red at pH 0 through orange, yellow, green at pH 7, blue, and purple at pH 14, with each color band labeled from strongly acidic on the left to strongly basic on the right.Universal indicator color chartred0–2strongly acidicorange3–4weakly acidicyellow5–6weakly acidicgreen7near-neutralblue8–11weakly basicpurple12–14strongly basic
Universal indicator is read by matching the observed color against the chart.
Worked examples

Worked example 1. A few drops of phenolphthalein added to solution B in a lab practical turn the whole solution bright pink. Is solution B acidic, basic, or near-neutral?

Step 1

Pink is phenolphthalein's basic signal.

Step 2

Solution B is basic.

Worked example 2. Universal indicator turns a sample of rainwater yellow. Where does the chart place the sample?

Step 1

Match the color against the chart: yellow sits on the acidic side, close to green.

Step 2

The chart reads yellow as weakly acidic.

Step 3

The rainwater is acidic — mildly so.

You can now identify whether a solution is acidic, basic, or near-neutral from supplied indicator observations.

Check your understanding

A few drops of universal indicator turn a sample of fish-tank water green. Using the chart, what is the sample?

indicator color chart — red; 1–3; strongly acidic; orange; 4–5; weakly acidic; yellow; 6; green; 7; near-neutral; blue; 8–11; weakly basic; purple; 12–14; strongly basicred1–3strongly acidicorange4–5weakly acidicyellow6weakly acidicgreen7near-neutralblue8–11weakly basicpurple12–14strongly basic
ANear-neutralcorrect
BAcidic
This option is wrong — you placed green on the acid side of the chart — green sits at the chart's midpoint, pH 7.
CBasic
This option is wrong — you placed green on the basic side of the chart — green sits at the chart's midpoint, pH 7.
DIt cannot be judged from a color alone
This option is wrong — you threw the result away — the chart exists exactly to convert the color into a pH verdict, and green reads as near-neutral.
Name the indicator: universal indicator, so read the color against the chart. Green sits at the chart's midpoint, pH 7. The fish-tank water is near-neutral.
Check your understanding

A few drops of phenolphthalein turn solution T bright pink. What is solution T?

ABasiccorrect
BAcidic
This option is wrong — you attached the color change to acids — phenolphthalein stays colorless in acid; pink is its basic signal.
CNear-neutral
This option is wrong — you let pink cover the middle of the scale — phenolphthalein is colorless in near-neutral solutions and turns pink only in basic ones.
DEither acidic or near-neutral
This option is wrong — you applied the colorless rule to a pink result — colorless leaves acidic and neutral open, but pink points one way: basic.
Name the indicator: phenolphthalein. Phenolphthalein turning pink identifies a basic solution. Solution T is basic.
Check your understanding

Solution S from a water-testing kit turns blue litmus paper red, and leaves red litmus paper unchanged. What is solution S?

AAcidiccorrect
BBasic
This option is wrong — you read the litmus change backward — turning BLUE litmus red is the acid signal; a base would turn red litmus blue.
CNear-neutral
This option is wrong — you treated the unchanged red paper as the whole result — a near-neutral solution would leave BOTH papers unchanged, and the blue paper did change.
DIt cannot be judged from these results
This option is wrong — you wanted both papers to change — an acid changes only the blue paper, and that one change is a complete verdict.
Blue litmus turning red is the acid signal. Red litmus staying red fits an acid too — acids never turn red litmus blue. Solution S is acidic.
Summary video — The pH scale

Watch in David’s player

End of Topic Test

End of Topic Test — five interchangeable forms, delivered separately.

Intro video — Neutralization and titration

Watch in David’s player

Lesson 37 of 45 · ABS-037

Neutralization
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Have You Ever Wondered?
Wonder this:

Heartburn is what too much hydrochloric acid in the stomach feels like. The cure sold in every pharmacy is a tablet containing a base. Swallow one, and the burning fades. What did the base do to the acid?

You have seen the properties of acids and of bases separately. This lesson covers what happens when the two meet.

The idea

When an acid and a base react, each cancels the properties of the other — chemists call the reaction 'neutralization'.

Neutralization produces the same two kinds of product every time: water and a salt.

A 'salt' is an ionic compound made from the base's positive ion and the acid's negative ion.

Table salt is only one member of the family — every neutralization makes some salt.

Hydrochloric acid and sodium hydroxide react to form water and the salt sodium chloride: HCl + NaOH → NaCl + H₂O.

The salt NaCl took its Na⁺ from the base and its Cl⁻ from the acid.

The equation HCl plus NaOH gives NaCl plus H2O, with HCl labeled acid, NaOH labeled base, NaCl labeled salt, and H2O labeled water.HCl+NaOH→NaCl+H₂O[object Object][object Object][object Object][object Object]
Worked examples

Worked example 1. Nitric acid is mixed with just enough potassium hydroxide to react completely. What two kinds of product form?

Step 1

Every neutralization produces water and a salt — here the salt is potassium nitrate.

Step 2

Water and a salt (KNO₃).

Worked example 2. In the neutralization Ca(OH)₂ + 2HBr → CaBr₂ + 2H₂O, which product is the salt?

Step 1

The salt is the ionic compound built from the base's positive ion (Ca²⁺) and the acid's negative ion (Br⁻).

Step 2

CaBr₂ is the salt.

You can now state that in a neutralization reaction an acid and a base react to form water and a salt - an ionic compound made from the base's positive ion and the acid's negative ion.

Check your understanding

An acid solution is mixed with just enough metal hydroxide base to react completely. What two kinds of product form?

AWater and a saltcorrect
BHydrogen gas and a salt
This option is wrong — you used the acid–metal property — hydrogen gas comes from acids reacting with active metals, not from acids reacting with bases.
CWater and a gas
This option is wrong — you added fizzing that does not happen — an acid and a metal hydroxide make water and a salt, and no gas escapes.
DA weaker acid and a weaker base
This option is wrong — you treated neutralization as a tug-of-war that leaves both behind — the acid and base are used up making two new substances.
Neutralization produces the same two kinds of product every time. The acid and the base react to form water and a salt. Gas belongs to a different acid property — the reaction with active metals.
Check your understanding

In the neutralization HI + LiOH → LiI + H₂O, which substance is the salt?

ALiIcorrect
BH₂O
This option is wrong — you picked the salt's partner product — the water forms alongside the salt; the salt is the ionic compound LiI.
CHI
This option is wrong — you picked a reactant — HI is the acid going in, not a product coming out.
DLiOH
This option is wrong — you picked a reactant — LiOH is the base going in, not a product coming out.
The products sit on the right of the arrow: LiI and H₂O. A salt is an ionic compound made from the base's positive ion and the acid's negative ion. LiI — built from Li⁺ and I⁻ — is the salt.
Check your understanding

Which two ions build the salt formed in a neutralization?

AThe base's positive ion and the acid's negative ioncorrect
BThe acid's H⁺ and the base's OH⁻
This option is wrong — you named the ions that end up in the other product — the water; the salt is built from the two ions left over.
CThe base's positive ion and the base's OH⁻
This option is wrong — you rebuilt the base — its OH⁻ goes into the water, and its positive ion pairs with the acid's negative ion.
DThe acid's H⁺ and the acid's negative ion
This option is wrong — you rebuilt the acid — its H⁺ goes into the water, and its negative ion pairs with the base's positive ion.
A salt is an ionic compound made from the base's positive ion and the acid's negative ion. In HCl + NaOH → NaCl + H₂O, the salt NaCl takes Na⁺ from the base and Cl⁻ from the acid. Rebuilding the acid or the base just names a reactant again.

Lesson 38 of 45 · ABS-038

Why water and a salt form
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You have seen that an acid and a base neutralize each other to form water and a salt. Following the ions shows why those two products — and no others — appear.

The idea

In water, hydrochloric acid exists as separate H⁺ and Cl⁻ ions, and sodium hydroxide as separate Na⁺ and OH⁻ ions.

Neutralization produces water and a salt because the H⁺ ions from the acid combine with the OH⁻ ions from the base to form water, leaving the remaining ions as the salt.

Three particle boxes. The first shows separate H plus and Cl minus ions in hydrochloric acid solution. The second shows separate Na plus and OH minus ions in sodium hydroxide solution. The third, after mixing, shows H2O molecules formed from the H plus and OH minus ions, with Na plus and Cl minus ions still separate in the solution.hydrochloric acid solutionH⁺H⁺H⁺Cl⁻Cl⁻Cl⁻Cl⁻H⁺sodium hydroxide solutionNa⁺OH⁻OH⁻Na⁺Na⁺OH⁻Na⁺OH⁻after mixingNa⁺Cl⁻H₂ONa⁺Cl⁻H₂OCl⁻H₂OCl⁻Na⁺Na⁺H₂O
The H⁺ ions from the acid combine with the OH⁻ ions from the base to form water; the Na⁺ and Cl⁻ ions remain as the salt.

Each H⁺ joins one OH⁻ to form one H₂O molecule.

The Na⁺ and Cl⁻ take no part in the joining — they stay dissolved, and they are the salt's ions.

When exactly enough base has been added, every free H⁺ has been locked into water, so the acid's properties disappear.

What remains is simply the salt's ions in water — here, a solution of NaCl.

Worked examples

Worked example 1. Nitric acid solution neutralizes potassium hydroxide solution. Which ions form the water, and which ions form the salt?

Step 1

The acid's ions in water are H⁺ and NO₃⁻; the base's are K⁺ and OH⁻.

Step 2

The H⁺ ions from the acid combine with the OH⁻ ions from the base to form water.

Step 3

The remaining ions — K⁺ and NO₃⁻ — are the salt's ions.

Step 4

Water forms from H⁺ and OH⁻; the salt KNO₃ is left by K⁺ and NO₃⁻.

Worked example 2. A solution of HBr turns blue litmus paper red. After exactly enough LiOH solution is stirred in, a fresh strip of blue litmus stays blue. Why?

Step 1

The acid signal comes from the free H⁺ ions in the solution.

Step 2

The H⁺ ions from the acid combine with the OH⁻ ions from the base to form water.

Step 3

With no free H⁺ left, nothing turns the blue litmus red.

Step 4

Every free H⁺ has been locked into water, so the acid property is gone.

You can now explain why neutralization produces water and a salt: the H⁺ ions from the acid combine with the OH⁻ ions from the base to form water, leaving the remaining ions as the salt.

Check your understanding

Hydroiodic acid solution (H⁺ and I⁻ ions) neutralizes sodium hydroxide solution (Na⁺ and OH⁻ ions). Which two ions combine to form the water?

AH⁺ and OH⁻correct
BNa⁺ and I⁻
This option is wrong — you picked the leftover pair — Na⁺ and I⁻ stay dissolved as the salt's ions; the water is built from H⁺ and OH⁻.
CH⁺ and I⁻
This option is wrong — you rebuilt the acid — its two ions separate in water, and the H⁺ leaves its partner to combine with OH⁻.
DNa⁺ and OH⁻
This option is wrong — you rebuilt the base — its two ions separate in water, and the OH⁻ leaves its partner to combine with H⁺.
Neutralization produces water and a salt because the H⁺ ions from the acid combine with the OH⁻ ions from the base to form water, leaving the remaining ions as the salt. Each H⁺ joins one OH⁻ to form one H₂O molecule. Na⁺ and I⁻ are the remaining ions — the salt.
Check your understanding

Hydrobromic acid solution neutralizes potassium hydroxide solution. After the reaction, which two ions are left in the solution as the salt?

AK⁺ and Br⁻correct
BH⁺ and OH⁻
This option is wrong — you left the water-builders behind — H⁺ and OH⁻ are exactly the ions that combined into water molecules.
CK⁺ and OH⁻
This option is wrong — you kept the base intact — its OH⁻ went into the water, leaving K⁺ to pair with the acid's Br⁻.
DH⁺ and Br⁻
This option is wrong — you kept the acid intact — its H⁺ went into the water, leaving Br⁻ to pair with the base's K⁺.
The H⁺ ions from the acid combine with the OH⁻ ions from the base to form water, leaving the remaining ions as the salt. The remaining ions here are K⁺ from the base and Br⁻ from the acid. Together they are the salt KBr, dissolved in the water.
Check your understanding

Exactly enough sodium hydroxide solution has been added to a nitric acid solution. Why does the mixture no longer behave as an acid?

AIts H⁺ ions have all been combined into water molecules.correct
BIts H⁺ ions have escaped into the air as hydrogen gas.
This option is wrong — you sent the hydrogen away as a gas — each H⁺ is locked into a water molecule with an OH⁻, and nothing bubbles out.
CIts H⁺ ions have turned into OH⁻ ions.
This option is wrong — you let one ion become another — ions keep their identity; each H⁺ instead paired with an OH⁻ to form water.
DThe salt has trapped the H⁺ ions inside its crystals.
This option is wrong — you built crystals that are not there — the salt's ions stay dissolved, and the H⁺ went into water molecules.
The acid's properties come from its free H⁺ ions. The H⁺ ions from the acid combine with the OH⁻ ions from the base to form water. With no free H⁺ left, the acid behaviour is gone.

Lesson 39 of 45 · ABS-039

Predicting neutralization products
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You have seen why neutralization makes water and a salt. This lesson is the writing routine: from the acid's and the base's formulas to the formulas of the two products.

The idea

One product never needs predicting: water, H₂O, forms in every acid–metal hydroxide neutralization.

The salt takes the base's metal ion and the acid's negative ion.

Find the acid's negative ion by removing the H⁺ from its formula: HCl gives Cl⁻, HNO₃ gives NO₃⁻, and H₂SO₄ gives SO₄²⁻.

A flow diagram. HNO3 with the H plus removed gives the nitrate ion. KOH gives the potassium ion. Criss-crossing the charges of K plus and NO3 minus gives the salt KNO3, and water always forms as the other product.Predicting neutralization productsHNO₃acidremove H⁺NO₃⁻KOHbasetake the metal ionK⁺K⁺ + NO₃⁻criss-crosscharges crossKNO₃H₂Oalwayswater forms in every case
The salt takes the base's metal ion and the acid's negative ion; water always forms.

Read the base's metal ion straight from its formula: KOH gives K⁺, and Ca(OH)₂ gives Ca²⁺.

Write the salt's formula by criss-crossing the two charges, exactly as for any ionic compound.

For nitric acid reacting with potassium hydroxide: K⁺ and NO₃⁻ pair one-to-one, so the products are H₂O and the salt KNO₃.

Worked examples

Worked example 1. Predict the products when hydrochloric acid, HCl, reacts with calcium hydroxide, Ca(OH)₂.

Step 1

Water forms in every case: H₂O.

Step 2

The acid's negative ion: HCl gives Cl⁻.

Step 3

The base's metal ion: Ca(OH)₂ gives Ca²⁺.

Step 4

Criss-cross the charges: Ca²⁺ and Cl⁻ give CaCl₂.

Step 5

The products are H₂O and CaCl₂.

Worked example 2. Predict the products when sulfuric acid, H₂SO₄, reacts with sodium hydroxide, NaOH.

Step 1

Water forms in every case: H₂O.

Step 2

The acid's negative ion: H₂SO₄ gives SO₄²⁻.

Step 3

The base's metal ion: NaOH gives Na⁺.

Step 4

Criss-cross the charges: Na⁺ and SO₄²⁻ give Na₂SO₄.

Step 5

The products are H₂O and Na₂SO₄.

You can now predict the products of a reaction between an acid and a metal hydroxide base by writing the formulas of the water and the salt formed.

Check your understanding

Hydrobromic acid, HBr, reacts with lithium hydroxide, LiOH. Write the formula of the salt formed.

Accepted answer: LiBr
The acid's negative ion: HBr gives Br⁻. The base's metal ion: LiOH gives Li⁺. Criss-cross the charges: 1 and 1, so the ions pair one-to-one. The salt is LiBr — and water, H₂O, forms alongside it.
Check your understanding

Nitric acid, HNO₃, reacts with barium hydroxide, Ba(OH)₂. Write the formula of the salt formed.

Accepted answer: Ba(NO₃)₂
The acid's negative ion: HNO₃ gives NO₃⁻. The base's metal ion: Ba(OH)₂ gives Ba²⁺. Criss-cross the charges: the 2 crosses to the nitrate, which keeps its parentheses. The salt is Ba(NO₃)₂ — and water forms alongside it.
Check your understanding

Hydrochloric acid, HCl, reacts with potassium hydroxide, KOH. Which pair of products forms?

AKCl and H₂Ocorrect
BKCl and H₂
This option is wrong — you released hydrogen gas — that happens when acids meet active METALS; with a base, the hydrogen ends up in water.
CKH and ClOH
This option is wrong — you exchanged the wrong partners — the base's metal ion pairs with the acid's negative ion, and H⁺ pairs with OH⁻.
DK₂Cl and H₂O
This option is wrong — you gave potassium a subscript charge balance does not call for — K⁺ and Cl⁻ pair one-to-one.
The acid's negative ion: HCl gives Cl⁻. The base's metal ion: KOH gives K⁺. Criss-cross: equal charge numbers pair one-to-one, giving KCl. Water forms in every case, so the products are KCl and H₂O.

Lesson 40 of 45 · ABS-040

Writing neutralization equations
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Did You Know?

You have seen how to predict the two products of a neutralization. A full chemical equation must also balance — the same count of each atom on both sides.

The idea

Write the acid and the base on the left, and the predicted salt and water on the right.

Balance by adjusting coefficients one element at a time — never change a subscript.

The quick route: count the H⁺ each acid unit gives and the OH⁻ each base unit gives, and pick coefficients that make the two counts equal.

Each H⁺–OH⁻ pair becomes one H₂O, so the water's coefficient equals that shared count.

Sulfuric acid gives two H⁺ but each NaOH gives one OH⁻, so two NaOH are needed: H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O.

Check by counting atoms: 4 H, 1 S, 6 O, and 2 Na on each side.

The balanced equation H2SO4 plus 2 NaOH gives Na2SO4 plus 2 H2O, annotated to show the acid giving two H plus, the two NaOH giving two OH minus, and the two H plus OH minus pairs becoming two water molecules.H₂SO₄+2NaOH→Na₂SO₄+2H₂O[object Object][object Object][object Object]
Worked examples

Worked example 1. Write the balanced chemical equation for nitric acid, HNO₃, reacting with potassium hydroxide, KOH.

Step 1

Products: the salt KNO₃ and water.

Step 2

Count the pairs: HNO₃ gives one H⁺ and KOH gives one OH⁻ — the counts already match.

Step 3

One H⁺–OH⁻ pair means one H₂O, and no coefficients are needed.

Step 4

HNO₃ + KOH → KNO₃ + H₂O

Worked example 2. Write the balanced chemical equation for hydrochloric acid, HCl, reacting with calcium hydroxide, Ca(OH)₂.

Step 1

Products: the salt CaCl₂ and water.

Step 2

Count the pairs: each HCl gives one H⁺, but Ca(OH)₂ gives two OH⁻ — so two HCl are needed.

Step 3

Two H⁺–OH⁻ pairs mean two H₂O.

Step 4

Check the atoms: 2 H from HCl plus 2 H from Ca(OH)₂ = 4 H, matching 2H₂O; 2 Cl, 1 Ca, and 2 O on each side.

Step 5

2HCl + Ca(OH)₂ → CaCl₂ + 2H₂O

You can now write the balanced chemical equation for a neutralization reaction from the formulas of the acid and the base.

Check your understanding

Write the balanced chemical equation for hydrobromic acid, HBr, reacting with sodium hydroxide, NaOH.

Accepted answer: HBr + NaOH → NaBr + H₂O
Products: the salt NaBr and water. Count the pairs: one H⁺ from HBr, one OH⁻ from NaOH — the counts match with no coefficients. HBr + NaOH → NaBr + H₂O — check: 2 H, 1 Br, 1 Na, 1 O on each side.
Check your understanding

Write the balanced chemical equation for nitric acid, HNO₃, reacting with barium hydroxide, Ba(OH)₂.

Accepted answer: 2HNO₃ + Ba(OH)₂ → Ba(NO₃)₂ + 2H₂O
Products: the salt Ba(NO₃)₂ and water. Count the pairs: each HNO₃ gives one H⁺, but Ba(OH)₂ gives two OH⁻ — so two HNO₃, and two H₂O. 2HNO₃ + Ba(OH)₂ → Ba(NO₃)₂ + 2H₂O — check: 4 H, 2 N, 8 O, 1 Ba on each side.
Your turn

On paper, write the balanced chemical equation for sulfuric acid, H₂SO₄, reacting with potassium hydroxide, KOH — show the unbalanced product step first. Then select Continue to compare your work with the model answer.

Model answer. Products: the salt K₂SO₄ (K⁺ criss-crossed with SO₄²⁻) and water. Unbalanced: H₂SO₄ + KOH → K₂SO₄ + H₂O. Count the pairs: H₂SO₄ gives two H⁺ but each KOH gives one OH⁻, so two KOH are needed, and two H₂O form. Balanced: H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O. Check: 4 H, 1 S, 6 O, 2 K on each side.

  • The acid and the base sit on the left; the salt and water on the right.
  • The salt is K₂SO₄ — the sulfate's 2 crossed to potassium.
  • A coefficient 2 sits in front of KOH and in front of H₂O; no subscript was changed.
  • The atom check passes: 4 H, 1 S, 6 O, and 2 K on each side.

Lesson 41 of 45 · ABS-041

What titration is for
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Have You Ever Wondered?
Wonder this:

A bottle of hydrochloric acid has lost most of its label — the concentration is unreadable. The solution inside looks exactly like water; no glance, swirl, or sniff will reveal how concentrated it is. Every safe use of that acid needs the missing number. How can it be measured?

You have seen that an acid and a base react completely with each other. That reaction can be turned into a measuring tool.

The idea

Concentration leaves no visible trace — a 0.1 M and a 1.0 M hydrochloric acid solution look identical.

A 'titration' finds an unknown concentration by reacting the solution with one whose concentration is known.

A measured volume of the unknown solution is placed in a flask.

The known solution is added slowly from a thin volume-marked tube, a little at a time.

A titration setup. A thin vertical tube with volume markings holds the solution of known concentration and drips into a flask below, which holds a measured volume of the solution of unknown concentration.known solution— concentrationknown, volumeread off themarkingsmeasured volume ofthe unknownsolution
A titration: the known solution is added slowly to a measured volume of the unknown solution until the two have exactly reacted.

The additions stop at the moment the two have exactly reacted — no acid and no base left over.

The volume of known solution delivered is then read off the tube.

From the known concentration, the two measured volumes, and the balanced equation for the reaction — which supplies how many of each react together — the unknown concentration can be calculated.

Worked examples

Worked example 1. A lab has a potassium hydroxide solution of unknown concentration. A student titrates a measured sample of it with nitric acid of known concentration. What does the titration find?

Step 1

The unknown in a titration is the solution whose concentration was not known going in.

Step 2

The concentration of the potassium hydroxide solution.

Worked example 2. Why must one of the two solutions in a titration have a known concentration?

Step 1

The unknown concentration is worked out FROM the known one — it is the measurement's anchor.

Step 2

Without a known concentration on one side, there is nothing to calculate the unknown from.

You can now explain the purpose of a titration: a solution of pre-measured concentration is added slowly to a measured volume of a solution of unknown concentration until the two have exactly reacted, so the unknown concentration can be calculated.

Check your understanding

What question is a titration designed to answer?

AWhat is the concentration of a solution?correct
BIs a solution an acid or a base?
This option is wrong — you described an indicator test — one drop of indicator settles acid-or-base; a titration measures how concentrated a solution is.
CWhat products does a reaction make?
This option is wrong — you described product prediction — a titration already knows the reaction and uses it to measure a concentration.
DHow quickly do an acid and a base react?
This option is wrong — you turned the slow additions into the measurement — the adding is slow, but the target is a concentration, not a speed.
A titration finds an unknown concentration. It reacts the unknown solution with one whose concentration is known. The known concentration, the two measured volumes, and the reaction's balanced equation give the unknown concentration.
Check your understanding

During a titration, when does the student stop adding the known solution?

AWhen the two solutions have exactly reactedcorrect
BWhen equal volumes of the two solutions have been mixed
This option is wrong — you matched volumes instead of amounts — the volumes at the stopping point are usually different, and that difference is the useful data.
CWhen all of the known solution has been used up
This option is wrong — you emptied the tube — the point is to stop mid-tube at exact reaction and read how much was delivered.
DAs soon as the first drop of known solution has reacted
This option is wrong — you stopped at the start — additions continue until ALL of the unknown has reacted, with nothing left over on either side.
The additions stop at the moment the two have exactly reacted. Exactly reacted means no acid and no base left over. Then the delivered volume is read off the tube.
Check your understanding

Which set of measurements must a titration give you before the unknown concentration can be calculated?

AThe known solution's concentration and both solutions' volumescorrect
BBoth solutions' concentrations and both solutions' volumes
This option is wrong — you required the answer as an input — if both concentrations were known, there would be nothing left to find.
CThe two solutions' volumes only
This option is wrong — you dropped the anchor — without one known concentration, the volumes could only compare the two solutions, not give a value.
DThe unknown solution's volume only
This option is wrong — you kept a single measurement — the calculation needs the known concentration and BOTH volumes.
One concentration must be known going in — it is the anchor. The volume of the unknown sample is measured at the start; the delivered volume is read at the end. Known concentration plus the two volumes — with the reaction's balanced equation supplying the ratio — enough to calculate the unknown concentration.

Lesson 42 of 45 · ABS-042

The endpoint
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Wonder this:

A titration stands or falls on stopping at exactly the right drop. But a hydrochloric acid solution and a sodium hydroxide solution are both colorless — and mixed together, still colorless. How can anyone SEE the moment the reaction is exactly done?

You have seen that a titration stops when the acid and the base have exactly reacted. Seeing that moment takes one more ingredient in the flask.

The idea

A few drops of an indicator are added to the flask before the titration begins.

The 'endpoint' of a titration is the moment the indicator changes color.

The color change signals that the acid and the base have exactly reacted — or as close to it as one drop can get: a careful titration lands the endpoint within a single drop of that moment.

At the endpoint, the additions stop and the delivered volume is recorded.

With phenolphthalein in an acid-filled flask, the endpoint is the first faint pink that stays after swirling.

Two flasks under a delivery tube. Before the endpoint the flask's solution is colorless; at the endpoint the solution is faintly pink and the additions have stopped.before the endpointat the endpoint
With phenolphthalein in an acid-filled flask, the endpoint is the first faint pink that stays.
Worked examples

Worked example 1. During a titration of hydrobromic acid with sodium hydroxide, the phenolphthalein in the flask flashes pink where each drop lands, then turns colorless again as the flask is swirled — until one drop leaves the whole flask faintly pink. What has just happened?

Step 1

A lasting color change from the indicator is the endpoint — the acid and the base have exactly reacted.

Step 2

The endpoint has been reached: stop adding and record the delivered volume.

Worked example 2. A titration is run the other way around: the flask holds potassium hydroxide solution with phenolphthalein, so it starts out pink, and nitric acid is added from the tube. What marks the endpoint?

Step 1

The endpoint is still the indicator's color change — here, from pink to colorless.

Step 2

The moment the pink vanishes and stays gone is the endpoint.

You can now state that the endpoint of a titration is the moment the indicator changes color, signaling that the acid and the base have exactly reacted.

Check your understanding

What does the endpoint of a titration signal?

AThe acid and the base have exactly reactedcorrect
BThe reaction between the acid and the base has just begun
This option is wrong — you put the signal at the start — the acid and base react from the first drop; the endpoint marks the finish, with nothing left over.
CAll of the indicator has been used up by the reaction
This option is wrong — you made the indicator a reactant being consumed — the indicator is a signal dye, and its color change reports on the acid and base.
DThe flask solution has become saturated
This option is wrong — you reached for a solubility idea — nothing is crystallizing; the color change reports that the acid and base have exactly reacted.
The endpoint is the moment the indicator changes color. That color change signals that the acid and the base have exactly reacted. It is the stopping signal, not the starting one.
Check your understanding

The indicator in a titration flask has just changed color and the new color stays. What should the student do?

AStop adding and record the volume deliveredcorrect
BKeep adding until the color becomes as deep as possible
This option is wrong — you waited for a strong color — the FIRST lasting change is the endpoint, and anything added after it overshoots the measurement.
CStir until the color disappears, then continue adding
This option is wrong — you treated the signal as a nuisance — a lasting color change IS the endpoint, so the additions are finished.
DEmpty the flask and start adding the other solution
This option is wrong — you started a second titration — at the endpoint the job is reading the delivered volume, not swapping solutions.
The endpoint is the moment the indicator changes color. At the endpoint, the additions stop. The delivered volume is then recorded — that number is the titration's result.
Check your understanding

Hydroiodic acid sits in the flask with a few drops of phenolphthalein, and potassium hydroxide is added from the tube. What is observed at the endpoint?

AThe solution turns faintly pink, and the pink stayscorrect
BThe solution turns deep red
This option is wrong — you borrowed universal indicator's acid color — phenolphthalein's basic signal is pink, and the endpoint is the FIRST faint lasting pink.
CThe solution turns blue
This option is wrong — you borrowed litmus's base color — phenolphthalein turns pink, not blue.
DBubbles of gas rise through the solution
This option is wrong — you added a gas that neutralization does not make — the products are water and a salt, and the visible signal comes from the indicator.
The flask starts acidic, so the phenolphthalein starts colorless. The endpoint is the moment the indicator changes color. Here that is the first faint pink that stays after swirling.

Lesson 43 of 45 · ABS-043

Volumes reveal concentration
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Did You Know?

You have seen that a titration's endpoint means the acid and the base have exactly reacted. Even before any calculation, the two volumes on their own answer a useful question: which solution is more concentrated?

The idea

This pattern covers titrations in which the acid and the base react one-to-one.

At the endpoint, the two solutions have delivered exactly matching amounts of acid and base.

A solution that delivered its matching amount in less volume packs more into every milliliter.

So the solution that needed the smaller volume is the more concentrated one.

Equal volumes at the endpoint mean equal concentrations.

When 10.0 mL of a base neutralizes 20.0 mL of an acid, the base delivered the same amount in half the volume — the base is the more concentrated.

Two graduated cylinders. The base cylinder holds 10.0 milliliters containing six solute dots; the acid cylinder holds 20.0 milliliters containing six solute dots spread through twice the liquid, so the base's dots are more crowded.base — 10.0 mLacid — 20.0 mL
Matching amounts in different volumes: the 10.0 mL of base packs the same 6 particles into half the space, so the base is more concentrated.
Worked examples

Worked example 1. Reaching the endpoint took 12.0 mL of hydrochloric acid for a 36.0 mL sample of potassium hydroxide solution; the two react one-to-one. Which solution is more concentrated?

Step 1

At the endpoint, the two solutions delivered matching amounts.

Step 2

The acid delivered its amount in one-third of the base's volume.

Step 3

The hydrochloric acid is the more concentrated solution.

Worked example 2. A 25.0 mL sample of hydrobromic acid is neutralized by exactly 25.0 mL of sodium hydroxide solution. How do the two concentrations compare?

Step 1

Matching amounts arrived in equal volumes.

Step 2

The two solutions are equally concentrated.

You can now predict which of two solutions that react one-to-one is more concentrated from the volumes used to reach the endpoint, using the pattern that the solution needing the smaller volume is the more concentrated.

Check your understanding

Titrating a 30.0 mL sample of sodium hydroxide solution to the endpoint took 15.0 mL of nitric acid; the two react one-to-one. Which is more concentrated?

AThe nitric acidcorrect
BThe sodium hydroxide solution
This option is wrong — you gave the larger volume the higher concentration — needing MORE volume to deliver the matching amount means each milliliter carries less.
CThe two are equally concentrated
This option is wrong — you treated reaching the endpoint as proof of equality — the AMOUNTS match at the endpoint, and unequal volumes then mean unequal concentrations.
DIt cannot be judged from the volumes
This option is wrong — you threw the volumes away — in a one-to-one titration run to the endpoint, the volumes are exactly what settles the comparison.
At the endpoint, the two solutions delivered matching amounts. The acid delivered its amount in half the volume. The solution needing the smaller volume is the more concentrated — the nitric acid.
Check your understanding

A 50.0 mL sample of hydroiodic acid is neutralized at the endpoint by just 10.0 mL of lithium hydroxide solution; the two react one-to-one. Which is more concentrated?

AThe lithium hydroxide solutioncorrect
BThe hydroiodic acid
This option is wrong — you gave the larger volume the higher concentration — the acid needed five times the volume to deliver its matching amount, so it is the more dilute one.
CThe two are equally concentrated
This option is wrong — you treated reaching the endpoint as proof of equality — equal concentrations would have needed equal volumes, and these volumes differ fivefold.
DIt cannot be judged from the volumes
This option is wrong — you threw the volumes away — in a one-to-one titration run to the endpoint, the volumes are exactly what settles the comparison.
At the endpoint, the two solutions delivered matching amounts. The base delivered its amount in one-fifth of the acid's volume. The solution needing the smaller volume is the more concentrated — the lithium hydroxide.
Check your understanding

A 35.0 mL sample of hydrochloric acid reaches the endpoint after exactly 35.0 mL of lithium hydroxide solution has been added; the two react one-to-one. Which is more concentrated?

ANeither — the two are equally concentratedcorrect
BThe hydrochloric acid
This option is wrong — you picked the flask solution by habit — matching amounts in EQUAL volumes means neither packs more into a milliliter.
CThe lithium hydroxide solution
This option is wrong — you picked the added solution by habit — matching amounts in EQUAL volumes means neither packs more into a milliliter.
DIt cannot be judged from the volumes
This option is wrong — you threw the volumes away — equal volumes at the endpoint answer the question directly: equal concentrations.
At the endpoint, the two solutions delivered matching amounts. Those matching amounts arrived in equal volumes: 35.0 mL each. Equal volumes at the endpoint mean equal concentrations.

Lesson 44 of 45 · ABS-044

The titration equation
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Did You Know?

You have seen that the endpoint volumes reveal which solution is more concentrated. Turning that comparison into an exact number takes one equation — and it is built from one you have seen: n = M × V.

The equation

This equation is for titrations in which the acid and the base react one-to-one.

At the endpoint of such a titration, the moles of acid that have reacted equal the moles of base.

Each solution's delivered moles are counted by the relationship you have seen: n = M × V.

Setting the two mole counts equal gives the titration equation: M(acid) × V(acid) = M(base) × V(base).

The two volumes must be in the same unit — both in mL or both in L — and then the volume unit cancels.

The equation M of acid times V of acid equals M of base times V of base, with the left side labeled moles of acid delivered and the right side labeled moles of base delivered.M(acid)×V(acid)=M(base)×V(base)[object Object][object Object]
M(acid)molarity of the acid solution (M)
V(acid)volume of acid solution used (mL)
M(base)molarity of the base solution (M)
V(base)volume of base solution used (mL)

Know any three of the four quantities, and the fourth can be found.

Worked examples

Worked example 1. A 25.0 mL sample of nitric acid is titrated to its endpoint with potassium hydroxide solution. Write the relationship that holds between the two solutions' molarities and volumes.

Step 1

HNO₃ and KOH react one-to-one, so at the endpoint the moles of acid equal the moles of base.

Step 2

Each side's moles are M × V.

Step 3

M(HNO₃) × 25.0 = M(KOH) × V(KOH)

Worked example 2. Why do the moles of acid and base match at the endpoint of a one-to-one titration?

Step 1

The endpoint means exactly reacted — no acid and no base left over.

Step 2

One-to-one means each mole of acid consumes exactly one mole of base.

Step 3

Nothing is left over and the ratio is 1:1, so the two mole counts must be equal.

You can now state that at the endpoint of a titration in which the acid and base react one-to-one, the moles of acid equal the moles of base, so the acid's molarity times its volume equals the base's molarity times its volume.

Check your understanding

An acid and a base react one-to-one, and their titration has just reached the endpoint. Which equation relates the two solutions?

AM(acid) × V(acid) = M(base) × V(base)correct
BM(acid) × V(base) = M(base) × V(acid)
This option is wrong — you crossed the pairs — each molarity multiplies its OWN solution's volume, because M × V counts that solution's delivered moles.
CM(acid) ÷ V(acid) = M(base) ÷ V(base)
This option is wrong — you divided instead of multiplying — moles are counted by n = M × V, so the equal quantities are the two M × V products.
DM(acid) + V(acid) = M(base) + V(base)
This option is wrong — you added a molarity to a volume — the two are different kinds of quantity, and moles come from MULTIPLYING them.
At the endpoint, the moles of acid equal the moles of base. Each side's moles are that solution's own M × V. So M(acid) × V(acid) = M(base) × V(base).
Check your understanding

At the endpoint of a one-to-one titration, which two quantities are equal?

AThe moles of acid and the moles of base that reactedcorrect
BThe volumes of acid and base solution that were delivered
This option is wrong — you equated the volumes — they match only when the concentrations happen to match; it is the MOLE counts that must be equal.
CThe molarities of the two solutions
This option is wrong — you equated the concentrations — a concentrated solution simply reaches the endpoint in less volume; it is the mole counts that are equal.
DThe masses of the two solutions
This option is wrong — you reached for mass — the balance at the endpoint is counted in moles, via each solution's M × V.
The endpoint means exactly reacted, and one-to-one means a 1:1 mole ratio. So the moles of acid equal the moles of base. Volumes and molarities can each differ — only their PRODUCTS must match.
Check your understanding

The titration equation M(acid) × V(acid) = M(base) × V(base) may be used only when which condition holds?

AThe acid and the base react one-to-onecorrect
BBoth the acid and the base are strong
This option is wrong — you reached for strength — the condition is the 1:1 mole ratio; a weak acid titrated with a 1:1 partner still obeys the equation at its endpoint.
CThe two volumes are equal
This option is wrong — you demanded matching volumes — the equation exists precisely to handle UNEQUAL volumes; the condition is the one-to-one reaction.
DThe acid is the solution in the flask
This option is wrong — you tied the equation to the apparatus — either solution can sit in the flask; the condition is the one-to-one reaction.
The equation comes from setting the two mole counts equal. That equality needs a 1:1 mole ratio — the acid and base must react one-to-one. Strength, volumes, and flask position play no part in the condition.

Lesson 45 of 45 · ABS-045

Titration calculation
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You have seen the titration equation for one-to-one reactions: M(acid) × V(acid) = M(base) × V(base). A titration measures three of its four quantities — this lesson calculates the fourth.

The equation

Write down the three known values from the question.

Write down the titration equation: M(acid) × V(acid) = M(base) × V(base).

Make the unknown molarity the subject by dividing both sides by its own solution's volume.

Substitute the values and calculate — the answer is a molarity, in M.

Keep both volumes in the same unit; two mL values are fine, because the volume unit cancels.

For 50.0 mL of an acid neutralized by 25.0 mL of 0.200 M base, making M(acid) the subject gives M(acid) = 0.200 × 25.0 ÷ 50.0.

That calculates to 0.100 M — and the sanity check passes: the acid needed twice the volume, so it comes out half as concentrated.

A titration setup with the delivery tube labeled base 0.200 molar with 25.0 milliliters delivered, the flask labeled acid 50.0 milliliters with molarity unknown, and a panel showing the equation M of acid times 50.0 equals 0.200 times 25.0.base: 0.200 M,25.0 mLdeliveredacid: 50.0 mL,molarity unknownM(acid) × 50.0 =0.200 × 25.0
Three quantities measured, one unknown: M(acid) = 0.200 × 25.0 ÷ 50.0 = 0.100 M.

Always run that sanity check: the solution that needed the smaller volume must come out more concentrated.

Worked examples

Worked example 1. A 20.0 mL sample of hydrochloric acid is neutralized at the endpoint by 40.0 mL of 0.150 M sodium hydroxide solution. What is the molarity of the acid?

Step 1

Write down the values in the question

V(acid) = 20.0 mL

M(base) = 0.150 M

V(base) = 40.0 mL

Step 2

Write down the equation

M(acid) × V(acid) = M(base) × V(base)

Step 3

Make the unknown the subject

M(acid) = M(base) × V(base) ÷ V(acid)

Step 4

Substitute in the values, and calculate

M(acid) = 0.150 × 40.0 ÷ 20.0

M(acid) = 0.300 M

Worked example 2. A 30.0 mL sample of potassium hydroxide solution is neutralized at the endpoint by 10.0 mL of 0.600 M nitric acid. What is the molarity of the base?

Step 1

Write down the values in the question

V(base) = 30.0 mL

M(acid) = 0.600 M

V(acid) = 10.0 mL

Step 2

Write down the equation

M(acid) × V(acid) = M(base) × V(base)

Step 3

Make the unknown the subject

M(base) = M(acid) × V(acid) ÷ V(base)

Step 4

Substitute in the values, and calculate

M(base) = 0.600 × 10.0 ÷ 30.0

M(base) = 0.200 M

You can now calculate the unknown concentration in a one-to-one titration from the two volumes and the pre-measured concentration.

Check your understanding

A 25.0 mL sample of hydrobromic acid is neutralized at the endpoint by 50.0 mL of 0.100 M sodium hydroxide solution; the two react one-to-one. What is the molarity of the acid, in M? Give your answer to 3 significant figures.

Answer: 0.200 M (tolerance ±0.0005)
Write down the values in the question: V(acid) = 25.0 mL M(base) = 0.100 M V(base) = 50.0 mL Write down the equation: M(acid) × V(acid) = M(base) × V(base) Make M(acid) the subject: M(acid) = M(base) × V(base) ÷ V(acid) Substitute in the values, and calculate: M(acid) = 0.100 × 50.0 ÷ 25.0 M(acid) = 0.200 M
Check your understanding

A 40.0 mL sample of hydroiodic acid is neutralized at the endpoint by 20.0 mL of 0.500 M potassium hydroxide solution; the two react one-to-one. What is the molarity of the acid, in M? Give your answer to 3 significant figures.

Answer: 0.250 M (tolerance ±0.0005)
Write down the values in the question: V(acid) = 40.0 mL M(base) = 0.500 M V(base) = 20.0 mL Write down the equation: M(acid) × V(acid) = M(base) × V(base) Make M(acid) the subject: M(acid) = M(base) × V(base) ÷ V(acid) Substitute in the values, and calculate: M(acid) = 0.500 × 20.0 ÷ 40.0 M(acid) = 0.250 M
Check your understanding

A 60.0 mL sample of lithium hydroxide solution is neutralized at the endpoint by 30.0 mL of 0.400 M nitric acid; the two react one-to-one. What is the molarity of the base, in M? Give your answer to 3 significant figures.

Answer: 0.200 M (tolerance ±0.0005)
Write down the values in the question: V(base) = 60.0 mL M(acid) = 0.400 M V(acid) = 30.0 mL Write down the equation: M(acid) × V(acid) = M(base) × V(base) Make M(base) the subject: M(base) = M(acid) × V(acid) ÷ V(base) Substitute in the values, and calculate: M(base) = 0.400 × 30.0 ÷ 60.0 M(base) = 0.200 M
Summary video — Neutralization and titration

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