A chlorine atom will happily take an electron from a sodium atom — that transfer built every salt in Unit 4. But chlorine gas is Cl₂: two IDENTICAL chlorine atoms bonded together. Identical atoms pull equally hard, so neither can take the other's electron. Something else must be holding them together.
You've already seen atoms lose or gain electrons to form ions. Particulate diagrams can show what the electrons are doing, and this lesson is the skill of reading them.
The idea
A particulate diagram draws each atom as a circle and marks its outer electrons as dots.
In some diagrams the two circles overlap, and electrons sit in the overlap region.
Electrons in the overlap region belong to both atoms at once, so the diagram shows 'electron sharing'.
Sharing: the electrons sit in the overlap region, held by both atoms. Transfer: an electron has moved across to one atom.
In other diagrams the two circles stay separate, and an electron has moved from one circle to the other.
A moved electron belongs only to the atom that received it, so the diagram shows 'electron transfer'.
To classify any diagram, find the electrons: sitting in the overlap region means sharing, moved across to one atom means transfer.
Worked examples
Worked example 1. Does the diagram in the figure show electron sharing or electron transfer?
Step 1
Find the electrons: two dots sit in the overlap region between the two H circles.
Step 2
Electrons in the overlap region belong to both atoms at once.
Step 3
The diagram shows electron sharing.
Worked example 2. Does the diagram in the figure show electron sharing or electron transfer?
Step 1
Find the electrons: one electron has moved from the Li circle to the F circle, and the circles do not overlap.
Step 2
A moved electron belongs only to the atom that received it.
Step 3
The diagram shows electron transfer.
You can now classify a particulate diagram of two bonded atoms as showing electron sharing or electron transfer.
Check your understanding
Panels A to D each show a particulate diagram of two atoms. Which panel shows electron sharing?
Acorrect
B
This option is wrong — you picked a moved electron — sharing needs electrons sitting in the overlap region, held by both atoms at once.
C
This option is wrong — you picked two atoms that are not interacting — no electrons are shared or moved between them.
D
This option is wrong — you accepted overlap alone as sharing — the shared electrons must sit in the overlap region, and this overlap region is empty.
Find the electrons first. In panel A, two electrons sit in the overlap region, held by both Br atoms at once — that is electron sharing. A moved electron shows transfer, and an empty overlap region shows nothing being shared.
Check your understanding
Diagrams 1 and 2 in the figure each show two bonded atoms. Which classification is correct?
ADiagram 1 shows sharing, and diagram 2 shows transfer.correct
BDiagram 1 shows transfer, and diagram 2 shows sharing.
This option is wrong — you swapped the two pictures — diagram 1's electrons sit in the overlap region, held by both atoms, while diagram 2's electrons have moved across to one atom.
CBoth diagrams show sharing.
This option is wrong — you read the moved electrons in diagram 2 as shared — electrons that have moved across belong only to the atom that received them.
DBoth diagrams show transfer.
This option is wrong — you read the overlap-region electrons in diagram 1 as moved — electrons sitting between overlapping circles are held by both atoms at once.
Find the electrons in each diagram. Diagram 1 keeps its two electrons in the overlap region — sharing. Diagram 2's two electrons have moved onto the sulfur — transfer. Overlap region means sharing; moved across means transfer.
Check your understanding
Panels A to D each show a particulate diagram of two atoms. Which panel shows electron transfer?
Acorrect
B
This option is wrong — you picked electrons sitting in the overlap region — those are held by both atoms, which is sharing.
C
This option is wrong — you treated two different elements as a sign of transfer — the electrons still sit in the overlap region, so the atoms are sharing.
D
This option is wrong — you picked atoms that are not interacting — transfer needs an electron that has moved from one atom to the other.
Transfer means the electrons have moved across and now sit on one atom. In panel B, two electrons have left the calcium and sit on the oxygen — that is electron transfer. Electrons in an overlap region are shared, whatever the two elements are.
Lesson 2 of 70 · CMB-002
What a covalent bond is
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You've already classified particulate diagrams as showing electron sharing or electron transfer. This lesson gives the sharing case its chemical name — and draws the boundary around it.
The idea
In Na–Cl, one electron moves from the sodium atom to the chlorine atom — the atoms do not share.
In Cl–Cl, the two chlorine atoms hold one pair of electrons in the overlap region — the atoms share.
Cl–Cl, F–Cl, and O–O share pairs in the overlap region — covalent. Na–Cl and Mg–O moved their electrons — not covalent.
In F–Cl, two different elements still hold a shared pair between them — the atoms share.
In O–O, the two oxygen atoms hold two shared pairs between them — the atoms share.
In Mg–O, two electrons move from the magnesium atom to the oxygen atom — the atoms do not share.
A bond in which two atoms share one or more pairs of electrons is called a 'covalent bond'.
Cl–Cl, F–Cl, and O–O are covalent bonds; Na–Cl and Mg–O are not, because their electrons moved instead of being shared.
Worked examples
Worked example 1. In Br₂, the two bromine atoms hold one pair of electrons in the overlap region between them. Is the Br–Br bond covalent?
Step 1
The two atoms hold a pair of electrons between them, so they share it.
Step 2
A bond in which two atoms share one or more pairs of electrons is a covalent bond.
Step 3
The Br–Br bond is covalent.
Worked example 2. In potassium fluoride, one electron moves from the potassium atom to the fluorine atom. Is the K–F bond covalent?
Step 1
The electron moves across — the atoms do not share it.
Step 2
Without a shared pair of electrons, a bond is not covalent.
Step 3
The K–F bond is not covalent.
You can now classify a bond as covalent or not covalent from whether the two atoms share a pair of electrons.
Check your understanding
Bond 1: in hydrogen iodide, the H and I atoms hold one shared pair of electrons. Bond 2: in lithium chloride, one electron moves from the lithium atom to the chlorine atom. Which classification is correct?
ABond 1 is covalent, and bond 2 is not covalent.correct
BBond 1 is not covalent, and bond 2 is covalent.
This option is wrong — you swapped the two — the shared pair makes H–I covalent, while lithium's moved electron leaves Li–Cl with nothing shared.
CBoth bonds are covalent.
This option is wrong — you counted a moved electron as shared — an electron that moves across belongs only to the atom that received it.
DNeither bond is covalent.
This option is wrong — you missed the shared pair in hydrogen iodide — one shared pair is exactly what makes a bond covalent.
A bond in which two atoms share one or more pairs of electrons is a covalent bond. H and I hold a shared pair — covalent. Li's electron moved across — not covalent. Shared means held between both atoms; moved means owned by one.
Check your understanding
Bond 1: in ICl, the iodine and chlorine atoms hold one shared pair of electrons. Bond 2: in CaBr₂, one electron moves from the calcium atom to each bromine atom. Which classification is correct?
ABond 1 is covalent, and bond 2 is not covalent.correct
BBond 1 is not covalent, and bond 2 is covalent.
This option is wrong — you may have treated two different elements as unable to share — iodine and chlorine hold the pair together, so they share it.
CBoth bonds are covalent.
This option is wrong — you counted calcium's moved electrons as shared — they sit on the bromine atoms after moving.
DNeither bond is covalent.
This option is wrong — you missed the shared pair in ICl — atoms of different elements share pairs too.
Different elements can share: the pair in ICl is held by both atoms, so the bond is covalent. In CaBr₂ the electrons moved across — nothing is shared, so those bonds are not covalent. The test is always the same: is a pair of electrons shared?
Check your understanding
Bond 1: in CS₂, the carbon atom and each sulfur atom hold two shared pairs of electrons. Bond 2: in Na₂S, one electron moves from each sodium atom to the sulfur atom. Which classification is correct?
ABond 1 is covalent, and bond 2 is not covalent.correct
BBond 1 is not covalent, and bond 2 is covalent.
This option is wrong — you swapped the two — two shared pairs still count as sharing, while sodium's moved electrons leave nothing shared.
CBoth bonds are covalent.
This option is wrong — you counted sodium's moved electrons as shared — a moved electron belongs only to the atom that received it.
DNeither bond is covalent.
This option is wrong — you capped sharing at one pair — one OR MORE shared pairs makes a bond covalent.
A covalent bond is one or more shared pairs — two shared pairs qualify. C and S hold two pairs between them — covalent. Na's electrons moved — not covalent. Count of pairs never matters; sharing does.
Lesson 3 of 70 · CMB-003
Why sharing holds atoms together
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You've already classified the Cl–Cl bond as covalent — the two atoms share a pair of electrons. Sharing says what the electrons do, but not what holds the atoms together. This lesson explains the pull.
The idea
Every atomic nucleus is positively charged, and electrons are negatively charged.
Opposite charges attract, so each nucleus attracts the shared electrons.
The shared pair sits between the two atoms, inside both circles at once.
Two covalently bonded atoms stay together because both nuclei attract the same shared electrons, which pulls the two atoms together.
Both nuclei attract the same shared electrons, which pulls the two atoms together.
It works like two people holding the same shopping bag — each grips the bag, so the two stay side by side.
Pulling the two atoms apart means pulling both nuclei away from electrons they attract, and that takes an energy supply from outside.
Worked examples
Worked example 1. The two hydrogen atoms in H₂ share one pair of electrons. Explain why the two atoms stay together.
Step 1
Each hydrogen nucleus is positive, and the shared electrons between the atoms are negative.
Step 2
Both nuclei attract the same shared electrons, which pulls the two atoms together.
Step 3
The two H atoms stay together because both nuclei attract the same shared pair.
Worked example 2. In HBr, the hydrogen and bromine atoms share one pair of electrons. Explain why the two atoms stay together.
Step 1
The shared pair sits between the hydrogen nucleus and the bromine nucleus.
Step 2
Both nuclei attract the same shared electrons, which pulls the two atoms together.
Step 3
The H and Br atoms stay together because both nuclei attract the same shared pair.
You can now explain that two covalently bonded atoms stay together because both nuclei attract the same shared electrons, which pulls the two atoms together.
Check your understanding
The two fluorine atoms in F₂ share one pair of electrons. Why do the two atoms stay together?
ABoth nuclei attract the same shared electrons, which pulls the two atoms together.correct
BEach atom wants a full outer shell, and that wanting pulls the atoms together.
This option is wrong — you used the full-shell pattern as the cause — the pattern describes the outcome, while the pull comes from both nuclei attracting the same shared electrons.
CThe two positively charged nuclei attract each other.
This option is wrong — you attracted like charges — two nuclei are both positive and repel each other; each attracts the shared electrons between them.
DOne atom has taken the other's electron, and the resulting opposite charges attract.
This option is wrong — you described a transfer bond — in F₂ nothing moves across; the electrons are shared between the atoms.
The shared pair sits between the two nuclei. Both nuclei attract the same shared electrons, which pulls the two atoms together. Wanting a full shell is a pattern, not a pull — the attraction runs between positive nuclei and the shared negative electrons.
Check your understanding
In HI, the hydrogen and iodine atoms share one pair of electrons. What attracts what, to hold the two atoms together?
AEach nucleus attracts the shared electrons that sit between the atoms.correct
BThe hydrogen nucleus attracts the iodine nucleus.
This option is wrong — you attracted the two positives — nuclei repel each other; each one attracts the shared pair instead.
CThe shared electrons attract each other.
This option is wrong — you attracted like charges — electrons repel each other; they are attracted BY the two nuclei.
This option is wrong — you gave the atoms whole charges — neither atom in HI is an ion; the attraction runs between each nucleus and the shared pair.
Only opposite charges attract: positive nuclei and negative electrons. Both nuclei attract the same shared electrons, which pulls the two atoms together. Neither atom carries a whole charge — the pull is on the shared pair between them.
Check your understanding
A student says the two iodine atoms in I₂ stay together because each iodine atom wants eight electrons in its outer shell. What is wrong with the student's explanation?
AIt names a pattern, not a pull — the atoms stay together because both nuclei attract the same shared electrons.correct
BNothing — the explanation is correct as it stands.
This option is wrong — you accepted a wish as a force — an electron count describes the outcome, while the holding force is the nuclei attracting the shared pair.
CIt is wrong only because iodine needs two more electrons, not eight in total.
This option is wrong — you fixed the number instead of the reasoning — no electron count pulls atoms together; the nuclei attracting the shared pair does.
DIt is wrong because the atoms actually stay together when their two nuclei attract each other.
This option is wrong — you attracted the two positive nuclei — they repel; each attracts the shared electrons between them.
Ask what physically pulls on what. Both nuclei attract the same shared electrons, which pulls the two atoms together. Electron-count patterns describe where bonding ends up, never the force that holds it.
Lesson 4 of 70 · CMB-004
Molecules and molecular substances
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You've already seen atoms joined by covalent bonds two at a time. Groups of atoms joined this way get their own name.
The idea
A group of atoms held together by covalent bonds is called a 'molecule'.
A water molecule is three atoms — one oxygen and two hydrogens — held together by covalent bonds.
A substance made of molecules is called a 'molecular substance'.
A molecule: a group of atoms held together by covalent bonds.
Water is a molecular substance: a sample of water is a crowd of separate water molecules.
A molecule can be as small as two atoms or hold thousands.
Worked examples
Worked example 1. What is a group of atoms held together by covalent bonds called?
Step 1
Answer: a molecule.
Worked example 2. Carbon dioxide is made of CO₂ molecules. What kind of substance is carbon dioxide?
Step 1
Answer: a molecular substance.
You can now state that a molecule is a group of atoms held together by covalent bonds, and that a substance made of molecules is called a molecular substance.
Check your understanding
An ammonia molecule is one nitrogen atom and three hydrogen atoms grouped together. What holds the atoms of the molecule together?
ACovalent bonds.correct
BIonic bonds.
This option is wrong — you reached for the transfer-based bond — nothing in a molecule transfers electrons; the atoms share pairs.
CTransferred electrons sitting on the nitrogen.
This option is wrong — you moved the electrons — the atoms of a molecule hold shared pairs, which is what a covalent bond is.
DGravity between the atoms.
This option is wrong — you picked a force far too weak to matter between atoms — the glue is covalent bonds.
A molecule is a group of atoms held together by covalent bonds. The nitrogen and each hydrogen share a pair of electrons — three covalent bonds hold the group. Transfer builds ionic compounds, not molecules.
Check your understanding
A substance made of molecules is called what?
AA molecular substance.correct
BAn ionic compound.
This option is wrong — you picked the Unit 4 category — ionic compounds are built from ions in a lattice, not from molecules.
CA lattice.
This option is wrong — you named the ionic arrangement — a substance made of molecules is a molecular substance.
DA mixture.
This option is wrong — you treated a crowd of identical molecules as a mixture — one kind of molecule is one pure substance.
A substance made of molecules is called a molecular substance. Each molecule is one covalently bonded group; the sample is a crowd of those groups.
Check your understanding
Methane is made of CH₄ molecules. Which statement about methane is correct?
AEach CH₄ molecule is a group of atoms held together by covalent bonds.correct
BEach CH₄ molecule is a single atom.
This option is wrong — you collapsed the molecule — a molecule is a GROUP of atoms, five of them here.
CThe atoms within one CH₄ molecule are held together by electron transfer.
This option is wrong — you moved the electrons — the atoms of a molecule share pairs; that sharing is the covalent bond.
DMethane is made of ions arranged in a lattice.
This option is wrong — you described an ionic compound — methane is molecular: separate CH₄ molecules.
A molecule is a group of atoms held together by covalent bonds. Each CH₄ molecule is one carbon and four hydrogens sharing pairs. Methane, made of these molecules, is a molecular substance.
Lesson 5 of 70 · CMB-005
Reading a molecular formula
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You've already read subscripts in ionic formulas like MgCl₂ as ion counts in a formula unit. Molecular substances write formulas too, and there the counts describe one molecule.
The idea
A molecular substance's formula tells you what one molecule contains.
A formula read this way is called a 'molecular formula'.
Each element's symbol appears once, and the subscript after a symbol counts that element's atoms in one molecule.
A symbol with no subscript means one atom.
CO₂ reads: one carbon atom and two oxygen atoms in one CO₂ molecule.
The counts belong to a single molecule — every molecule of the substance contains exactly these atoms.
One CO₂ molecule: one carbon atom and two oxygen atoms.
Worked examples
Worked example 1. How many atoms of each element are in one molecule of H₂O₂?
Step 1
The subscript after H is 2 — two hydrogen atoms.
Step 2
The subscript after O is 2 — two oxygen atoms.
Step 3
One H₂O₂ molecule contains two hydrogen atoms and two oxygen atoms.
Worked example 2. How many atoms of each element are in one molecule of C₃H₈?
Step 1
The subscript after C is 3 — three carbon atoms.
Step 2
The subscript after H is 8 — eight hydrogen atoms.
Step 3
One C₃H₈ molecule contains three carbon atoms and eight hydrogen atoms.
You can now identify the number of atoms of each element in one molecule from its molecular formula.
Check your understanding
How many hydrogen atoms are in one molecule of CH₄?
Answer: 4atoms
A subscript counts the atoms of the symbol directly before it. The 4 sits after H, so one CH₄ molecule contains 4 hydrogen atoms.
Check your understanding
How many oxygen atoms are in one molecule of N₂O₅?
Answer: 5atoms
Find the subscript directly after O. It is 5, so one N₂O₅ molecule contains 5 oxygen atoms.
Check your understanding
Which statement gives the atoms in one molecule of C₂H₆?
A2 carbon atoms and 6 hydrogen atoms.correct
B6 carbon atoms and 2 hydrogen atoms.
This option is wrong — you swapped the subscripts — each subscript counts the element directly before it.
C1 carbon atom and 6 hydrogen atoms.
This option is wrong — you dropped carbon's subscript — C carries the subscript 2, so there are two carbon atoms.
D8 atoms of one element.
This option is wrong — you pooled the counts — C₂H₆ holds two elements, counted separately: 2 carbon and 6 hydrogen.
Read each symbol with the subscript directly after it. C₂ is two carbon atoms; H₆ is six hydrogen atoms. One C₂H₆ molecule: 2 carbon and 6 hydrogen.
Lesson 6 of 70 · CMB-006
Prefixes for counting atoms
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Compound names you will meet shortly carry counting words. This lesson is the ten-prefix codebook those names use.
The idea
Each counting prefix stands for one number.
mono- means 1, di- means 2, tri- means 3, tetra- means 4, and penta- means 5.
The ten counting prefixes
Prefix
Number
mono-
1
di-
2
tri-
3
tetra-
4
penta-
5
hexa-
6
hepta-
7
octa-
8
nona-
9
deca-
10
Each counting prefix stands for one number.
hexa- means 6, hepta- means 7, octa- means 8, nona- means 9, and deca- means 10.
penta- always signals five, whatever name it appears in.
Two pairs are easy to mix up: hexa- is 6 but hepta- is 7, and nona- is 9 but deca- is 10.
Worked examples
Worked example 1. What number does octa- stand for?
Step 1
Answer: 8.
Worked example 2. Which prefix stands for 2?
Step 1
Answer: di-.
You can now state the number that each prefix from mono- through deca- stands for in a compound name.
Check your understanding
What number does hexa- stand for in a compound name?
Answer: 6
hexa- is 6. Its neighbor hepta- is 7 — the pair is worth double-checking every time.
Check your understanding
Which prefix stands for 9 in a compound name?
Accepted answer: nona-
nona- is 9. Its neighbor deca- is 10 — the second easy-to-mix pair.
Check your understanding
What number does the prefix deca- stand for?
A10correct
B9
This option is wrong — you slid one prefix down — nona- is 9; deca- is 10.
C8
This option is wrong — you slid two prefixes down — octa- is 8; deca- is 10.
D2
This option is wrong — you echoed the d of di- — di- is 2; deca- is 10.
deca- is 10, the top of the list. nona- sits just below it at 9.
Lesson 7 of 70 · CMB-007
Naming a binary molecular compound
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Wonder this:
One nitrogen and one oxygen make NO. One nitrogen and two oxygens make NO₂ — a completely different gas. A name like 'nitrogen oxide' cannot tell them apart. Molecular compounds need names that count.
You've already read a molecular formula's atom counts and the ten counting prefixes. Naming a molecular compound puts the two together.
The idea
A molecular compound of exactly two elements is called a 'binary molecular compound'.
To name one from its formula, name the first element with a prefix for its count — but drop mono- on the first element.
Then name the second element with a prefix for its count, and change its ending to -ide; mono- is kept on the second element.
When a prefix ending in a or o runs into oxide, drop the prefix's last letter: mono- + oxide becomes monoxide, and tetra- + oxide becomes tetroxide.
CO₂ is carbon dioxide: mono- is dropped on the one carbon, and di- counts the two oxygens.
N₂O₄ is dinitrogen tetroxide: di- counts the two nitrogens, and tetra- + oxide gives tetroxide.
N₂O₄ → dinitrogen tetroxide: each subscript becomes a prefix.
Worked examples
Worked example 1. Name the binary molecular compound PCl₅.
Step 1
First element: one phosphorus — mono- is dropped, so just phosphorus.
Step 2
Second element: five chlorines — penta- plus chloride gives pentachloride.
Step 3
PCl₅ is phosphorus pentachloride.
Worked example 2. Name the binary molecular compound CO.
Step 1
First element: one carbon — mono- is dropped, so just carbon.
Step 2
Second element: one oxygen — mono- is kept on the second element, and mono- + oxide becomes monoxide.
Step 3
CO is carbon monoxide.
You can now state the name of a binary molecular compound from its formula using prefixes, dropping mono- on the first element.
Check your understanding
Name the binary molecular compound SO₃.
Accepted answer: sulfur trioxide
One sulfur: mono- is dropped on the first element. Three oxygens: tri- + oxide gives trioxide. SO₃ is sulfur trioxide.
Check your understanding
Name the binary molecular compound SiCl₄.
Accepted answer: silicon tetrachloride
One silicon: mono- dropped. Four chlorines: tetra- + chloride. SiCl₄ is silicon tetrachloride.
Check your understanding
Which is the correct name of Cl₂O₇?
Adichlorine heptoxidecorrect
Bchlorine heptoxide
This option is wrong — you dropped di- — mono- is the only prefix dropped, and only on the first element; the two chlorines keep di-.
Cheptachlorine dioxide
This option is wrong — you swapped the counts — each prefix belongs to its own element: di- to the two chlorines, hept(a)- to the seven oxygens.
Dchlorine(VII) oxide
This option is wrong — you used a Roman numeral — those belong to ionic naming for metals with more than one ion charge; molecular compounds count atoms with prefixes.
Two chlorines: di- stays, because only mono- is ever dropped. Seven oxygens: hepta- + oxide gives heptoxide. Cl₂O₇ is dichlorine heptoxide.
Lesson 8 of 70 · CMB-008
Writing a formula from a name
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You've already turned formulas into prefix names. This lesson runs the same code the other way: from the prefix name to the formula.
The idea
Each prefix in the name becomes a subscript in the formula.
Write the element symbols in the order the name gives them.
A prefix's number becomes the subscript after that element's own symbol.
A count of one — mono-, or a first element with no prefix — gets no subscript.
Sulfur hexafluoride: S for the one sulfur, then F with subscript 6 — SF₆.
Dinitrogen trioxide: N with subscript 2, then O with subscript 3 — N₂O₃.
sulfur hexafluoride → SF₆: each prefix becomes a subscript on its own element.
Worked examples
Worked example 1. Write the formula of phosphorus pentafluoride.
Step 1
Phosphorus has no prefix — one P, no subscript.
Step 2
penta- means five — F takes the subscript 5.
Step 3
Phosphorus pentafluoride is PF₅.
Worked example 2. Write the formula of dichlorine monoxide.
Step 1
di- means two — Cl takes the subscript 2.
Step 2
mon- means one — O gets no subscript.
Step 3
Dichlorine monoxide is Cl₂O.
You can now state the chemical formula of a binary molecular compound from its prefix-based name.
Check your understanding
Write the formula of boron trifluoride.
Accepted answer: BF₃
Boron has no prefix: one B, no subscript. tri- means three: F₃. Boron trifluoride is BF₃.
Check your understanding
Write the formula of dinitrogen monoxide.
Accepted answer: N₂O
di- means two: N₂. mon- means one: O with no subscript. Dinitrogen monoxide is N₂O.
Check your understanding
Which formula matches the name carbon tetrachloride?
ACCl₄correct
BC₄Cl
This option is wrong — you attached the count to the wrong element — tetra- belongs to chloride, so the 4 follows Cl.
CCCl
This option is wrong — you dropped the count — tetra- means the formula needs a 4 after Cl.
DC₄Cl₄
This option is wrong — you gave both elements the count of four — carbon has no prefix, so it is one atom with no subscript.
Carbon has no prefix: one C. tetra- means four: Cl₄. Carbon tetrachloride is CCl₄.
Lesson 9 of 70 · CMB-009
Choosing the right naming system
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Wonder this:
A student sees CaCl₂ and writes 'calcium dichloride'. Every prefix rule was applied perfectly — and the name is still wrong. Chemistry runs two naming systems, and the first job is choosing which one a compound needs.
You've already named binary molecular compounds with prefixes, and ionic compounds from their ions. This lesson decides which system a formula calls for.
The idea
Check the first element in the formula.
A metal first means an ionic compound — use ionic naming, with no prefixes.
Ionic names need no counting, because the ion charges already fix the ratio.
Which naming system?
First element
Compound type
Naming system
Example
a metal
ionic
ionic naming — no prefixes
CaCl₂ → calcium chloride
a nonmetal (H counts)
molecular
prefix naming
SCl₂ → sulfur dichloride
Metal first: ionic naming. Nonmetals only: prefix naming.
Nonmetals only means a molecular compound — use prefix naming.
Hydrogen counts as a nonmetal here.
CaCl₂ starts with the metal calcium, so it is calcium chloride — no prefixes.
SCl₂ starts with the nonmetal sulfur, so it is sulfur dichloride — prefixes count the atoms.
Worked examples
Worked example 1. Name K₂O.
Step 1
First element: potassium, a metal — ionic naming, no prefixes.
Step 2
Potassium ion plus oxide ion give the name directly.
Step 3
K₂O is potassium oxide.
Worked example 2. Name NF₃.
Step 1
First element: nitrogen, a nonmetal, and fluorine is also a nonmetal — prefix naming.
Step 2
One nitrogen (mono- dropped), three fluorines: trifluoride.
Step 3
NF₃ is nitrogen trifluoride.
You can now judge whether a compound is named with prefixes or with ionic naming rules from the elements in its formula, and name it with the correct system.
Check your understanding
Which is the correct name of MgF₂?
Amagnesium fluoridecorrect
Bmagnesium difluoride
This option is wrong — you counted with a prefix — magnesium is a metal, so MgF₂ is ionic, and ionic names never use prefixes.
Cmonomagnesium difluoride
This option is wrong — you used the full prefix system on an ionic compound — the charges already fix the ratio, so nothing is counted.
Dmagnesium(II) fluoride
This option is wrong — you added a Roman numeral — those mark metals with more than one common ion charge, and magnesium always forms Mg²⁺.
First element: magnesium, a metal — ionic naming. Ionic names carry no prefixes; the 2 comes from the ion charges. MgF₂ is magnesium fluoride.
Check your understanding
Which is the correct name of PBr₃?
Aphosphorus tribromidecorrect
Bphosphorus bromide
This option is wrong — you used ionic-style naming — phosphorus and bromine are both nonmetals, so the name must count atoms with prefixes.
Cmonophosphorus tribromide
This option is wrong — you kept mono- on the first element — mono- is always dropped there.
Dphosphorus(III) bromide
This option is wrong — you added a Roman numeral — those belong to ionic naming for metals; molecular compounds count atoms with prefixes.
First element: phosphorus, a nonmetal, and bromine is a nonmetal too — prefix naming. One phosphorus (mono- dropped), three bromines: tribromide. PBr₃ is phosphorus tribromide.
Check your understanding
Which of these compounds is named using prefixes?
AOF₂correct
BNaF
This option is wrong — you prefixed an ionic compound — sodium is a metal, so NaF takes ionic naming.
CCaO
This option is wrong — you prefixed an ionic compound — calcium is a metal, so CaO takes ionic naming.
DK₂S
This option is wrong — you read the subscript 2 as needing di- — the 2 comes from the ion charges; potassium is a metal, so K₂S takes ionic naming.
Check the first element of each formula. Only OF₂ starts with a nonmetal and contains nonmetals only — a molecular compound, named oxygen difluoride. Na, Ca, and K are metals: their compounds are ionic and never take prefixes.
Lesson 10 of 70 · CMB-010
Reading a Lewis diagram
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Wonder this:
Overlap-circle diagrams show sharing clearly, but they crowd fast — a five-atom molecule becomes a pile of circles and dots. Chemists use a faster picture, and reading it takes about a minute to learn.
You've already drawn dot symbols for single atoms — an element symbol ringed by its valence-electron dots. The new picture joins atoms into a molecule.
The idea
A 'Lewis diagram' draws a molecule with element symbols, lines, and dots.
Each element symbol stands for one atom of that element.
A line drawn between two symbols stands for one shared pair of electrons — two electrons, held by both atoms.
Each dot stands for one valence electron that is not shared, and unshared dots are drawn in pairs.
Only valence electrons appear — inner electrons are never drawn.
In the Lewis diagram of HCl, the line stands for the shared pair, and the three dot pairs on the Cl are chlorine's six unshared valence electrons.
The Lewis diagram of HCl: symbols for atoms, a line for the shared pair, dot pairs for unshared valence electrons.
Worked examples
Worked example 1. The figure shows the Lewis diagram of F₂. What does the line between the two F symbols stand for?
Step 1
A line between two symbols stands for one shared pair of electrons.
Step 2
The line stands for one shared pair — two electrons held by both fluorine atoms.
Worked example 2. In the same Lewis diagram of F₂, each F carries six dots. What do the dots stand for?
Step 1
Each dot is one valence electron that is not shared.
Step 2
Six dots on an F are six unshared valence electrons, drawn as three pairs.
Step 3
The dots are fluorine's unshared valence electrons.
You can now identify what each line and each pair of dots stands for in a supplied Lewis diagram.
Check your understanding
The figure shows the Lewis diagram of HBr. What does the line between H and Br stand for?
AOne shared pair of electrons, held by both atoms.correct
BOne single electron.
This option is wrong — you read one line as one electron — a line is a PAIR: two electrons.
CAn electron that has moved from H to Br.
This option is wrong — you read the line as a transfer — a Lewis line means sharing, not moving.
DThe two atoms touching, with no electrons involved.
This option is wrong — you emptied the line — the line IS electrons: one shared pair.
A line between two symbols stands for one shared pair of electrons. That is two electrons, held by both the H and the Br at once.
Check your understanding
The figure shows the Lewis diagram of BrCl. What do the three dot pairs drawn on the Cl stand for?
ASix of chlorine's valence electrons that are not shared.correct
BThree shared pairs of electrons.
This option is wrong — you read dots as shared — shared pairs are drawn as lines; dots are unshared electrons.
CChlorine's six inner electrons, closest to the nucleus.
This option is wrong — you drew the inner electrons — a Lewis diagram shows only valence electrons.
DSix electrons that bromine handed to chlorine.
This option is wrong — you read a transfer — the dots are chlorine's own unshared electrons; nothing has moved.
Each dot is one valence electron that is not shared. Three dot pairs on the Cl are six unshared valence electrons. Only sharing is drawn as a line; only valence electrons appear at all.
Check your understanding
In the Lewis diagram of HI shown in the figure, how many electrons does the line between H and I stand for?
Answer: 2electrons
A line stands for one shared pair. One pair is 2 electrons.
Lesson 11 of 70 · CMB-011
Bonding pairs and lone pairs
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You've already read what a Lewis diagram's lines and dots stand for. The electron pairs come in exactly two kinds, and each kind has a name.
The idea
An electron pair drawn as a line — shared between two atoms — is called a 'bonding pair'.
An electron pair drawn as two dots on one atom — not shared — is called a 'lone pair'.
Every electron pair in a Lewis diagram is one or the other.
In the Lewis diagram of water, the two lines are two bonding pairs, and the two dot pairs on the oxygen are two lone pairs.
To classify a pair, check where it is drawn: a line between two symbols is a bonding pair, and dots sitting on one atom are a lone pair.
Water's Lewis diagram: two bonding pairs (the lines) and two lone pairs (the dot pairs on the oxygen).
Worked examples
Worked example 1. The figure shows the Lewis diagram of NH₃. Classify the electron pairs around the nitrogen.
Step 1
Three lines join N to the three H atoms — three bonding pairs.
Step 2
One dot pair sits on the nitrogen alone — one lone pair.
Step 3
The nitrogen has three bonding pairs and one lone pair.
Worked example 2. The figure shows the Lewis diagram of HF. Classify its electron pairs.
Step 1
One line joins H and F — one bonding pair.
Step 2
Three dot pairs sit on the fluorine — three lone pairs.
Step 3
HF shows one bonding pair and three lone pairs.
You can now classify each electron pair in a Lewis diagram as a bonding pair or a lone pair.
Check your understanding
In the Lewis diagram of H₂S shown in the figure, two electron pairs are marked 1 and 2. Which classification is correct?
APair 1 is a bonding pair, and pair 2 is a lone pair.correct
BPair 1 is a lone pair, and pair 2 is a bonding pair.
This option is wrong — you swapped the two kinds — pair 1 is a line between two atoms, so it is shared; pair 2 sits on the sulfur alone.
CBoth pairs are bonding pairs.
This option is wrong — you counted the dot pair as shared — dots sitting on one atom are not shared between two atoms.
DBoth pairs are lone pairs.
This option is wrong — you counted the line as unshared — a line always joins two atoms through a shared pair.
Check where each pair is drawn. Pair 1 is a line between S and H — a bonding pair. Pair 2 is two dots on the S — a lone pair. Line between symbols: bonding. Dots on one atom: lone.
Check your understanding
The figure shows the Lewis diagram of Cl₂. Which statement classifies its electron pairs correctly?
AOne bonding pair and six lone pairs.correct
BSeven bonding pairs.
This option is wrong — you called every pair bonding — only the line between the two Cl atoms is shared.
COne lone pair and six bonding pairs.
This option is wrong — you swapped the two kinds — the single line is the one shared pair; the six dot pairs sit on single atoms.
DOne bonding pair and three lone pairs.
This option is wrong — you counted only one chlorine's lone pairs — each Cl carries three, six in all.
One line joins the two Cl atoms: one bonding pair. Each Cl carries three dot pairs: 3 + 3 = six lone pairs. Cl₂ shows one bonding pair and six lone pairs.
Check your understanding
How many lone pairs does the Lewis diagram of PH₃ in the figure show?
Answer: 1lone pairs
Lone pairs are the dot pairs sitting on one atom. PH₃ shows exactly one — the dot pair on the phosphorus.
Lesson 12 of 70 · CMB-012
Single, double, and triple bonds
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Every Lewis diagram so far has shown two atoms sharing one pair. Atoms can share more.
The idea
Two atoms can share one, two, or three pairs of electrons.
One shared pair is a 'single bond', drawn as one line.
Two shared pairs are a 'double bond', drawn as two lines.
One code, three bonds
Shared pairs
Drawn as
Name
1 pair (2 electrons)
one line, as in F–F
single bond
2 pairs (4 electrons)
two lines, as in O=O
double bond
3 pairs (6 electrons)
three lines, as in N≡N
triple bond
The count of lines equals the count of shared pairs.
Three shared pairs are a 'triple bond', drawn as three lines.
The two lines in O=O show a double bond — the two oxygen atoms share two pairs.
The count of lines always equals the count of shared pairs.
Worked examples
Worked example 1. Two atoms share three pairs of electrons. What is the bond called, and how many lines show it?
Step 1
Answer: a triple bond, drawn as three lines.
Worked example 2. A bond is drawn as two lines. How many pairs of electrons do the two atoms share?
Step 1
Answer: two pairs.
You can now state that two atoms can share one, two, or three pairs of electrons, called single, double, and triple bonds and drawn as one, two, or three lines.
Check your understanding
What is a bond in which two atoms share two pairs of electrons called?
AA double bond.correct
BA single bond.
This option is wrong — you dropped a pair — one shared pair is a single bond; two shared pairs are a double bond.
CA triple bond.
This option is wrong — you added a pair — three shared pairs make a triple bond; two make a double bond.
DTwo single bonds.
This option is wrong — you split the sharing — two pairs between the SAME two atoms make one double bond.
Count the shared pairs: two. Two shared pairs are a double bond, drawn as two lines.
Check your understanding
How many pairs of electrons do two atoms share in a triple bond?
Answer: 3pairs
'Triple' counts the shared pairs. A triple bond is three shared pairs, drawn as three lines.
Check your understanding
In a Lewis diagram, how is a double bond drawn?
ATwo lines between the two symbols.correct
BOne thicker line.
This option is wrong — you thickened instead of counting — each shared pair gets its own line, so a double bond is two lines.
CTwo dots between the symbols.
This option is wrong — you drew shared pairs as dots — shared pairs are lines; dots are unshared electrons.
DFour lines between the two symbols.
This option is wrong — you counted electrons — the two lines stand for two PAIRS, which is four electrons.
One line per shared pair. A double bond is two shared pairs, so it is drawn as two lines.
Lesson 13 of 70 · CMB-013
Spotting bond types in a structure
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You've already read the line code: one, two, or three lines for one, two, or three shared pairs. Real diagrams mix bond types, and this lesson classifies each bond you meet.
The idea
Classify each bond in a diagram separately.
Count the lines between one pair of atoms: one line is a single bond, two lines a double bond, three lines a triple bond.
Dots never count toward a bond — only lines between two symbols do.
In the Lewis diagram of CO₂, two lines join the carbon to each oxygen — both carbon–oxygen bonds are double bonds.
In the Lewis diagram of N₂, three lines join the two nitrogens — one triple bond.
Count the lines between one pair of atoms: two lines — double bond; three lines — triple bond.
Worked examples
Worked example 1. The figure shows the Lewis diagram of C₂H₄. Classify each bond.
Step 1
Two lines join the two carbons — a double bond.
Step 2
One line joins each carbon to each of its hydrogens — four single bonds.
Step 3
C₂H₄ has one carbon–carbon double bond and four carbon–hydrogen single bonds.
Worked example 2. The figure shows the Lewis diagram of HCN. Classify each bond.
Step 1
One line joins H to C — a single bond.
Step 2
Three lines join C to N — a triple bond.
Step 3
HCN has one single bond and one triple bond.
You can now classify each bond in a supplied Lewis diagram as single, double, or triple.
Check your understanding
The figure shows the Lewis diagram of C₂H₂. Classify the bond between the two carbon atoms.
AA triple bond.correct
BA double bond.
This option is wrong — you dropped a line — three lines join the two carbons.
CA single bond.
This option is wrong — you counted only one of the three lines between the carbons.
DThree single bonds.
This option is wrong — you split the lines — lines between the SAME two atoms combine into one bond.
Count the lines between the two C symbols: three. Three lines are three shared pairs — one triple bond.
Check your understanding
The figure shows the Lewis diagram of CS₂. Which statement classifies the two carbon–sulfur bonds?
ABoth are double bonds.correct
BBoth are single bonds.
This option is wrong — you missed the second line on each side — two lines join the carbon to each sulfur.
COne is a single bond and one is a triple bond.
This option is wrong — you pooled the four lines unevenly — each carbon–sulfur pair shows exactly two lines.
DBoth are triple bonds.
This option is wrong — you added a line — each side shows two lines, not three.
Classify each bond separately. Left bond: two lines — double. Right bond: two lines — double. Both carbon–sulfur bonds are double bonds.
Check your understanding
The figure shows the Lewis diagram of C₂H₆. Classify the bond between the two carbon atoms.
AA single bond.correct
BA double bond.
This option is wrong — you expected carbon–carbon bonds to be double — count the lines: one.
CA triple bond.
This option is wrong — you counted the C–H lines into the carbon–carbon bond — only lines between the two carbons count.
DNo bond.
This option is wrong — you missed the line joining the two carbons — one line is one single bond.
Count only the lines between the two C symbols: one. One line is one shared pair — a single bond.
Lesson 14 of 70 · CMB-014
The octet pattern in molecules
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You've already seen the octet pattern for ions — atoms gain or lose electrons until they hold a noble-gas count of eight. Molecules show the same pattern, with a twist in the counting.
The idea
In most stable molecules, each atom is surrounded by eight electrons.
The twist: a shared pair counts for BOTH atoms it joins.
Each chlorine atom in Cl₂ is surrounded by eight electrons — six in its own lone pairs, plus the two shared electrons, counted for both atoms.
Hydrogen is the exception: a hydrogen atom in a molecule is surrounded by two electrons.
Each chlorine is surrounded by eight electrons: six of its own plus the shared pair, counted for both.
Two is hydrogen's full count, matching helium, just as eight matches the other noble gases.
A few molecules break the octet pattern — this course never tests them; the sentence is here only so an exception never surprises you.
Worked examples
Worked example 1. In a stable molecule, how many electrons surround a nitrogen atom?
Step 1
Answer: eight.
Worked example 2. In a stable molecule, how many electrons surround a hydrogen atom?
Step 1
Answer: two.
You can now state that in most stable molecules each atom is surrounded by eight electrons, counting every shared pair for both atoms, while hydrogen is surrounded by two.
Check your understanding
In most stable molecules, how many electrons surround each atom other than hydrogen?
Answer: 8electrons
The octet pattern for molecules: eight electrons around each atom. Hydrogen alone is full at two.
Check your understanding
A shared pair sits between two bonded atoms. Toward which atom's eight does the pair count?
ABoth atoms — the pair counts fully for each.correct
BOnly the atom that supplied the two electrons.
This option is wrong — you tracked ownership — once shared, the pair surrounds both atoms and counts for both.
COnly the larger of the two atoms.
This option is wrong — you ranked the atoms — sharing has no owner; both atoms count the pair.
DNeither atom — shared electrons count for no one.
This option is wrong — you excluded shared electrons — they surround both atoms at once, so both count them.
The twist in molecular counting: a shared pair counts for BOTH atoms it joins. That is how two chlorines reach eight each while sharing only one pair.
Check your understanding
In a stable molecule, how many electrons surround a hydrogen atom?
Answer: 2electrons
Hydrogen is the pattern's one exception. Its shared pair counts fully, and two matches helium — hydrogen's noble gas.
Lesson 15 of 70 · CMB-015
Counting electrons around an atom
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You've already seen that in most stable molecules each atom is surrounded by eight electrons, with hydrogen surrounded by two. That claim is checkable: a Lewis diagram lets you count the electrons around any atom directly.
The idea
To count the electrons around an atom, add its lone-pair electrons to every electron in its shared pairs.
Each lone pair on the atom contributes two electrons.
Each shared pair also contributes two electrons, and both bonded atoms count the same shared pair in full.
A double bond is two shared pairs, so it contributes four electrons, and a triple bond contributes six.
Count only the pairs touching the atom in question — lone pairs sitting on other atoms belong to those atoms.
Panel 1 of the figure shows the water Lewis diagram: the oxygen holds two lone pairs and two single bonds.
The lone pairs give 2 + 2 = 4 electrons, the two single bonds give 2 + 2 = 4 more, so the oxygen is surrounded by 8 electrons.
Counting electrons around an atom: panel 1 walks the count for the oxygen of H₂O; panels 2 and 3 are the worked-example diagrams.
Each hydrogen in the same diagram shares one pair and holds no lone pairs, so each hydrogen is surrounded by 2 electrons.
Worked examples
Worked example 1. Panel 2 of the figure shows the ammonia Lewis diagram, NH₃. How many electrons surround the nitrogen?
Step 1
The nitrogen holds one lone pair: 2 electrons.
Step 2
The nitrogen shares three pairs, one with each hydrogen: 3 × 2 = 6 electrons.
Step 3
2 + 6 = 8.
Step 4
8 electrons surround the nitrogen.
Worked example 2. Panel 3 of the figure shows the fluorine Lewis diagram, F₂. How many electrons surround the left fluorine?
Step 1
The left fluorine holds three lone pairs: 3 × 2 = 6 electrons.
Step 2
It shares one pair with the other fluorine: 2 electrons.
Step 3
6 + 2 = 8.
Step 4
8 electrons surround the left fluorine.
You can now calculate the number of electrons around an atom in a Lewis diagram by adding its lone-pair electrons and every electron in its shared pairs.
Check your understanding
The figure shows the Lewis diagram of oxygen difluoride, OF₂. How many electrons surround the oxygen atom?
Answer: 8electrons
Count the pairs touching the oxygen only. Two lone pairs on the oxygen give 4 electrons. Two shared pairs give 4 more, so 4 + 4 = 8 electrons surround the oxygen.
Check your understanding
The figure shows the Lewis diagram of methane, CH₄. How many electrons surround the top hydrogen atom?
Answer: 2electrons
The hydrogen holds no lone pairs. It shares one pair with the carbon, and a shared pair holds two electrons. So 2 electrons surround the hydrogen.
Check your understanding
The figure shows the Lewis diagram of oxygen, O₂. How many electrons surround the left oxygen atom?
Answer: 8electrons
Two lone pairs on the left oxygen give 4 electrons. The double bond is two shared pairs, giving 4 more. 4 + 4 = 8 electrons surround the left oxygen.
Lesson 16 of 70 · CMB-016
How many bonds an atom makes
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You've already seen that bonded atoms end up surrounded by eight electrons, with hydrogen full at two. That pattern sets how many covalent bonds an atom typically forms.
The equation
In a covalent bond, the partner atom supplies one of the two shared electrons.
So every bond an atom forms raises its electron count by one.
An atom therefore typically forms one bond for every electron it needs to reach eight.
typical bonds = 8 − valence electrons
Nitrogen has five valence electrons, needs three more, and typically forms three bonds.
Carbon has four valence electrons, needs four more, and typically forms four bonds.
Hydrogen's full count is two, not eight, so hydrogen needs one electron and forms one bond.
The table gives the typical bond count for hydrogen, carbon, nitrogen, oxygen, and the halogens.
Typical covalent bond counts
Element
Valence electrons
Electrons needed
Typical bonds
hydrogen
1
1 (full shell is 2)
1
carbon
4
4
4
nitrogen
5
3
3
oxygen
6
2
2
halogens (F, Cl, Br, I)
7
1
1
An atom typically forms one bond for every electron it needs to fill its outer count.
Worked examples
Worked example 1. Oxygen has six valence electrons. How many covalent bonds does oxygen typically form?
Step 1
Write down the values in the question
valence electrons = 6
Step 2
Write down the equation
typical bonds = 8 − valence electrons
Step 3
Substitute in the values, and calculate
typical bonds = 8 − 6
typical bonds = 2
Worked example 2. Bromine, a halogen, has seven valence electrons. How many covalent bonds does bromine typically form?
Step 1
Write down the values in the question
valence electrons = 7
Step 2
Write down the equation
typical bonds = 8 − valence electrons
Step 3
Substitute in the values, and calculate
typical bonds = 8 − 7
typical bonds = 1
You can now predict how many covalent bonds an atom of hydrogen, carbon, nitrogen, oxygen, or a halogen typically forms from the number of electrons it needs to complete its octet.
Check your understanding
Fluorine has seven valence electrons. How many covalent bonds does fluorine typically form?
Answer: 1bonds
Write down the values in the question: valence electrons = 7 Write down the equation: typical bonds = 8 − valence electrons Substitute in the values, and calculate: typical bonds = 8 − 7 typical bonds = 1
Check your understanding
An atom typically forms three covalent bonds. Valence electron counts: oxygen 6, nitrogen 5, carbon 4, fluorine 7. Which atom is it?
ANitrogencorrect
BOxygen
This option is wrong — you matched three bonds to six valence electrons — 8 − 6 is two bonds, and three bonds needs five valence electrons.
CCarbon
This option is wrong — you matched three bonds to four valence electrons — 8 − 4 is four bonds, and three bonds needs five valence electrons.
DFluorine
This option is wrong — you matched three bonds to seven valence electrons — 8 − 7 is one bond, and three bonds needs five valence electrons.
Run the rule in reverse: three bonds means the atom needs three electrons. 8 − valence electrons = 3, so the valence count is 5. Nitrogen has five valence electrons, so nitrogen typically forms three bonds.
Check your understanding
Chlorine has seven valence electrons. Why does chlorine typically form one covalent bond?
AChlorine needs one more electron to reach eight, and each bond brings in one shared electron from a partner atom.correct
BChlorine has seven valence electrons, so it forms seven bonds and one of them is typical.
This option is wrong — you used the valence count as the bond count — the bonds equal the electrons still needed, which is 8 − 7 = 1.
CChlorine forms one bond because each of its three lone pairs blocks one extra bond.
This option is wrong — you treated lone pairs as bond blockers — the bond count comes from the one electron chlorine still needs, not from its lone pairs.
DChlorine forms one bond because a bond delivers all eight electrons at once.
This option is wrong — you gave one bond the whole octet — each bond adds only the one electron the partner shares in.
Each bond an atom forms raises its electron count by one, because the partner supplies one of the shared electrons. Chlorine sits at seven and needs one more. 8 − 7 = 1, so chlorine typically forms one bond.
Lesson 17 of 70 · CMB-017
Total valence electrons for a molecule
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You've already read atom counts from a formula's subscripts and valence electron counts from an element's group. Put together, they give the electron supply a whole molecule has to work with.
The equation
Every atom in a molecule brings its own valence electrons.
total valence electrons = (atoms of element 1 × its valence electrons) + (atoms of element 2 × its valence electrons) + …
Read each element's atom count from the formula's subscripts.
atoms
how many atoms of the element the formula shows (none)
valence electrons
valence electrons of one atom of the element (none)
Multiply each element's atom count by the valence electrons of one atom of that element.
Add the results for every element in the formula.
Methane is CH₄: one carbon with four valence electrons, and four hydrogens with one each.
total valence electrons = (1 × 4) + (4 × 1) = 8
Worked examples
Worked example 1. Carbon is in Group 14 and oxygen is in Group 16. What is the total number of valence electrons in one CO₂ molecule?
Step 1
Write down the values in the question
valence electrons of carbon = 4
valence electrons of oxygen = 6
atoms: 1 carbon, 2 oxygens
Step 2
Write down the equation
total valence electrons = (atoms of C × 4) + (atoms of O × 6)
You can now calculate the total number of valence electrons in a molecule by adding the valence electrons of every atom in its formula.
Check your understanding
Sulfur is in Group 16 and hydrogen has one valence electron. What is the total number of valence electrons in one H₂S molecule?
Answer: 8valence electrons
Write down the values in the question: hydrogen: 2 atoms × 1 valence electron sulfur: 1 atom × 6 valence electrons Substitute in the values, and calculate: total valence electrons = (2 × 1) + (1 × 6) = 2 + 6 total valence electrons = 8
Check your understanding
Carbon is in Group 14 and fluorine is in Group 17. What is the total number of valence electrons in one CF₄ molecule?
You've read Lewis diagrams that others drew and counted the electrons in them. Now you draw one yourself, starting with the simplest case: two atoms joined by a single bond.
The idea
Count the molecule's total valence electrons first.
Draw the two element symbols side by side, joined by one line for the shared pair.
The line uses two of the total electrons.
Place every remaining electron as lone pairs around the two atoms.
Draw each lone pair as two dots side by side, pointing straight out from its atom.
Give each atom lone pairs until its count reaches eight, remembering hydrogen is already full at two.
One line joins H and Cl, using two electrons, and the remaining six form three lone pairs on the chlorine.
Finish by checking: every electron used, hydrogen at two, chlorine at eight.
The drawing target: one line for the shared pair, every remaining electron in radial lone pairs.
Worked examples
Worked example 1. Draw the Lewis diagram of fluorine, F₂. Fluorine is in Group 17.
Step 1
Total valence electrons: 7 + 7 = 14.
Step 2
Draw F–F: the line uses 2 electrons, leaving 12.
Step 3
Each fluorine needs six more electrons to reach eight, so each gets three lone pairs.
Step 4
Check: 2 + 6 + 6 = 14 electrons used, and each fluorine sits at eight.
Step 5
F–F with three lone pairs on each fluorine, every lone pair pointing straight out from its atom.
Worked example 2. Draw the Lewis diagram of chlorine monofluoride, ClF. Both elements are in Group 17.
Step 1
Total valence electrons: 7 + 7 = 14.
Step 2
Draw Cl–F: the line uses 2 electrons, leaving 12.
Step 3
Each atom needs six more electrons, so each gets three lone pairs.
Step 4
Check: 2 + 6 + 6 = 14 electrons used, and both atoms sit at eight.
Step 5
Cl–F with three lone pairs on each atom — two different elements, same construction.
You can now draw the Lewis diagram of a two-atom molecule joined by a single bond, showing the shared pair as a line and every remaining valence electron in lone pairs.
Check your understanding
Which picture shows the correct Lewis diagram of chlorine, Cl₂? Chlorine is in Group 17.
Acorrect
B
This option is wrong — you stopped placing electrons too soon — Cl₂ has 14 valence electrons, and this drawing shows only 10, leaving each chlorine short of eight.
C
This option is wrong — you drew a double bond — each chlorine needs to share only one pair to reach eight, so the bond is single.
D
This option is wrong — you piled every lone pair onto one atom — both chlorines need three lone pairs to reach eight.
Total valence electrons: 7 + 7 = 14. One line uses 2 electrons, leaving 12 — three lone pairs for each chlorine. Check each atom: one shared pair plus three lone pairs puts each chlorine at eight.
Your turn
On paper, draw the Lewis diagram of hydrogen bromide, HBr. Hydrogen has one valence electron and bromine is in Group 17. Then select Continue to compare your drawing with the model answer.
Model answer. H and Br joined by one line. The line is the shared pair, using 2 of the 8 valence electrons. The remaining 6 electrons sit as three lone pairs on the bromine, each pair pointing straight out from the atom with its two dots side by side. Hydrogen carries no dots — it is full at two.
The two symbols are joined by exactly one line.
The diagram shows 8 electrons in total: one line (2) plus three lone pairs (6).
All three lone pairs sit on the bromine, none on the hydrogen.
Each lone pair points straight out from the bromine, its two dots side by side.
Your turn
On paper, draw the Lewis diagram of iodine, I₂. Iodine is in Group 17. Then select Continue to compare your drawing with the model answer.
Model answer. I and I joined by one line. The line uses 2 of the 14 valence electrons, and the remaining 12 sit as three lone pairs on each iodine, every pair pointing straight out from its atom with the two dots side by side.
The two symbols are joined by exactly one line.
The diagram shows 14 electrons in total: one line (2) plus six lone pairs (12).
Each iodine carries three lone pairs.
Each lone pair points straight out from its atom, its two dots side by side.
Lesson 19 of 70 · CMB-019
Finding the central atom
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You've drawn molecules of two atoms. Most molecules have more, and before drawing them you need to decide which atom sits in the middle.
The idea
A molecule with three or more atoms has one atom in the middle, bonded to the others.
The middle atom is called the 'central atom'.
The central atom is the atom that can form the most bonds.
Typical bond counts decide it: carbon's four beats nitrogen's three, which beats oxygen's two, which beats a halogen's one.
Hydrogen forms only one bond, so hydrogen is never the central atom.
A shortcut: the central atom is usually the atom that appears only once in the formula.
In CF₄, carbon forms four bonds and fluorine forms one, so carbon is the central atom.
The atom that can form the most bonds takes the middle.
Worked examples
Worked example 1. Which atom is the central atom of ammonia, NH₃?
Step 1
Nitrogen typically forms three bonds; hydrogen forms one and is never central.
Step 2
Nitrogen also appears only once in the formula.
Step 3
Nitrogen is the central atom of NH₃.
Worked example 2. Which atom is the central atom of dichlorine monoxide, Cl₂O?
Step 1
Oxygen typically forms two bonds; chlorine forms one.
Step 2
Oxygen appears only once, even though the formula writes it last — position in the formula does not matter.
Step 3
Oxygen is the central atom of Cl₂O.
You can now identify the central atom of a small molecule as the atom that can form the most bonds, which is usually the atom that appears only once in the formula.
Check your understanding
Which atom is the central atom of CH₃Br?
ACarboncorrect
BHydrogen
This option is wrong — you picked the most common atom — hydrogen forms only one bond and is never the central atom.
CBromine
This option is wrong — you picked the heavier atom — bromine forms one bond, and carbon's four bonds win the middle.
DNone of the above
This option is wrong — you decided the molecule has no middle atom — carbon can form four bonds, so it sits in the middle.
Compare typical bond counts: carbon 4, bromine 1, hydrogen 1. Carbon can form the most bonds. So carbon is the central atom of CH₃Br.
Check your understanding
Which atom is the central atom of HOCl?
AOxygencorrect
BHydrogen
This option is wrong — you picked the atom written first — hydrogen forms only one bond and is never the central atom.
CChlorine
This option is wrong — you picked chlorine, which forms one bond — oxygen's two bonds let it hold both neighbors.
DNone of the above
This option is wrong — you decided the molecule has no middle atom — oxygen can form two bonds, so it joins the hydrogen to the chlorine.
Compare typical bond counts: oxygen 2, chlorine 1, hydrogen 1. Oxygen can form the most bonds. So oxygen is the central atom of HOCl.
Check your understanding
Which atom is the central atom of CHF₃?
ACarboncorrect
BFluorine
This option is wrong — you picked the most common atom — fluorine forms one bond, and the central atom is the one that can form the most bonds.
CHydrogen
This option is wrong — you picked an atom that appears only once — the shortcut usually works, but hydrogen forms one bond and is never central.
DNone of the above
This option is wrong — you decided the molecule has no middle atom — carbon's four bonds hold the hydrogen and all three fluorines.
Carbon and hydrogen each appear once, so the shortcut alone cannot decide. Compare bond counts: carbon 4, hydrogen 1, fluorine 1. Carbon can form the most bonds, so carbon is the central atom.
Lesson 20 of 70 · CMB-020
Drawing central-atom molecules
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You've drawn two-atom molecules and picked out central atoms. Combining the two lets you draw molecules with one atom in the middle.
The idea
Count the molecule's total valence electrons.
Place the central atom in the middle, with the other atoms spaced around it.
Join each outer atom to the central atom with one line.
Each line uses two electrons from the total.
Place the remaining electrons as lone pairs, giving every atom eight, with hydrogen full at two.
Draw each lone pair as two dots side by side, pointing straight out from its atom.
Ammonia, NH₃, has 5 + 3 = 8 valence electrons.
Three N–H lines use six electrons, and the remaining two form one lone pair on the nitrogen.
Finish by checking: all eight electrons drawn, each hydrogen at two, the nitrogen at eight.
The drawing target: every outer atom joined to the middle by one line, the leftover electrons as radial lone pairs.
Worked examples
Worked example 1. Draw the Lewis diagram of methane, CH₄. Carbon is in Group 14 and hydrogen has one valence electron.
Step 1
Total valence electrons: 4 + 4 × 1 = 8.
Step 2
Carbon is the central atom; draw four C–H lines.
Step 3
The four lines use all 8 electrons, so no lone pairs remain.
Step 4
Check: each hydrogen sits at two, and the carbon's four shared pairs put it at eight.
Step 5
C in the middle with four single lines to H, and no lone pairs anywhere.
Worked example 2. Draw the Lewis diagram of water, H₂O. Oxygen is in Group 16 and hydrogen has one valence electron.
Step 1
Total valence electrons: 2 × 1 + 6 = 8.
Step 2
Oxygen is the central atom; draw two O–H lines, using four electrons.
Step 3
The remaining four electrons form two lone pairs on the oxygen, each pointing straight out.
Step 4
Check: each hydrogen sits at two, and the oxygen's two lone pairs plus two shared pairs put it at eight.
Step 5
O in the middle with two lines to H and two radial lone pairs on the oxygen.
You can now draw the Lewis diagram of a molecule with one central atom and single bonds, placing shared pairs and lone pairs so every atom completes its octet, or two electrons for hydrogen.
Check your understanding
Which picture shows the correct Lewis diagram of hydrogen sulfide, H₂S? Sulfur is in Group 16 and hydrogen has one valence electron.
Acorrect
B
This option is wrong — you drew 10 electrons — H₂S has 8, and the sulfur stops at two lone pairs.
C
This option is wrong — you gave the hydrogens lone pairs — hydrogen is full at two with its shared pair alone.
D
This option is wrong — you stopped after the bonds — four of the eight electrons remain, and they sit as two lone pairs on the sulfur.
Total valence electrons: 2 × 1 + 6 = 8. Two S–H lines use 4, and the remaining 4 form two lone pairs on the sulfur. Check: each hydrogen at two, the sulfur at eight.
Your turn
On paper, draw the Lewis diagram of oxygen difluoride, OF₂. Oxygen is in Group 16 and fluorine is in Group 17. Then select Continue to compare your drawing with the model answer.
Model answer. O in the middle joined to each F by a single line. The two lines use 4 of the 20 valence electrons. The remaining 16 sit as lone pairs: two on the oxygen and three on each fluorine, every pair pointing straight out from its atom with the two dots side by side.
Oxygen sits in the middle, joined to each fluorine by exactly one line.
The diagram shows 20 electrons: two lines (4) plus eight lone pairs (16).
The oxygen carries two lone pairs and each fluorine carries three.
Every lone pair points straight out from its atom, its two dots side by side.
Your turn
On paper, draw the Lewis diagram of phosphine, PH₃. Phosphorus is in Group 15 and hydrogen has one valence electron. Then select Continue to compare your drawing with the model answer.
Model answer. P in the middle joined to each H by a single line. The three lines use 6 of the 8 valence electrons, and the remaining 2 sit as one lone pair on the phosphorus, pointing straight out with its two dots side by side. The hydrogens carry no dots.
Phosphorus sits in the middle, joined to each hydrogen by exactly one line.
The diagram shows 8 electrons: three lines (6) plus one lone pair (2).
The lone pair sits on the phosphorus, and no hydrogen carries dots.
The lone pair points straight out from the phosphorus, its two dots side by side.
Lesson 21 of 70 · CMB-021
Drawing double and triple bonds
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You've drawn molecules where single bonds and lone pairs fill every atom to eight. For some molecules, that is not enough.
The idea
Sometimes every electron is placed and an atom still sits below eight.
The fix: move a lone pair from a neighboring atom into the space between the two atoms, making it a second shared pair.
A second shared pair turns the single bond into a double bond, drawn as two lines.
A third shared pair makes a triple bond, drawn as three lines.
Each moved pair raises the short atom's count by two without changing the diagram's total.
Keep converting until every atom reaches eight.
Carbon dioxide, CO₂, has 16 valence electrons: two C–O lines and three lone pairs on each oxygen use all 16, but the carbon sits at only four.
Moving one lone pair in from each oxygen makes two double bonds, and every atom reaches eight.
Converting lone pairs into shared pairs fills the short atom without changing the total.
Worked examples
Worked example 1. Draw the Lewis diagram of oxygen, O₂. Oxygen is in Group 16.
Step 1
Total valence electrons: 6 + 6 = 12.
Step 2
One O–O line plus lone pairs uses all 12, but one oxygen sits at six.
Step 3
Move one lone pair from the other oxygen into the bond: a double bond.
Step 4
Check: two lines (4) plus two lone pairs on each oxygen (8) = 12, and each oxygen sits at eight.
Step 5
O=O with two lone pairs on each oxygen.
Worked example 2. Draw the Lewis diagram of hydrogen cyanide, HCN. Hydrogen has one valence electron; carbon is in Group 14 and nitrogen in Group 15.
Step 1
Total valence electrons: 1 + 4 + 5 = 10.
Step 2
Carbon takes the middle: H–C–N with single bonds uses 4, and the remaining 6 go to the nitrogen as three lone pairs.
Step 3
The carbon sits at four — two pairs short — so move two lone pairs from the nitrogen into the bond: a triple bond.
Step 4
Check: H–C≡N with one lone pair on the nitrogen is 2 + 6 + 2 = 10, hydrogen at two, carbon and nitrogen at eight.
Step 5
H–C≡N with one lone pair on the nitrogen.
You can now draw the Lewis diagram of a molecule that needs a double or triple bond, converting lone pairs into extra shared pairs until every atom completes its octet.
Your turn
On paper, draw the Lewis diagram of carbon disulfide, CS₂. Carbon is in Group 14 and sulfur is in Group 16. Then select Continue to compare your drawing with the model answer.
Model answer. S=C=S: the carbon in the middle joined to each sulfur by a double bond, with two lone pairs on each sulfur pointing straight out, dots side by side. Single bonds would leave the carbon at four, so one lone pair moves in from each sulfur. Total: two double bonds (8) plus four lone pairs (8) = 16 electrons.
Carbon sits in the middle, joined to each sulfur by two parallel lines.
The diagram shows 16 electrons: two double bonds (8) plus four lone pairs (8).
Each sulfur carries exactly two lone pairs, and the carbon carries none.
Every lone pair points straight out from its atom, its two dots side by side.
Your turn
On paper, draw the Lewis diagram of nitrogen, N₂. Nitrogen is in Group 15. Then select Continue to compare your drawing with the model answer.
Model answer. N≡N: the two nitrogens joined by three parallel lines, with one lone pair on each nitrogen pointing straight out, dots side by side. A single bond leaves each nitrogen well short of eight, so two lone pairs convert into shared pairs. Total: one triple bond (6) plus two lone pairs (4) = 10 electrons.
The two nitrogens are joined by three parallel lines.
The diagram shows 10 electrons: the triple bond (6) plus two lone pairs (4).
Each nitrogen carries exactly one lone pair.
Each lone pair points straight out from its atom, its two dots side by side.
Check your understanding
Which picture shows the correct Lewis diagram of ethyne, C₂H₂? Carbon is in Group 14 and hydrogen has one valence electron.
Acorrect
B
This option is wrong — you drew 12 electrons — C₂H₂ has only 10; converting both lone pairs into a third shared pair keeps the total at 10 with every atom full.
C
This option is wrong — you left the shared count too low — single bonds put each carbon at six even with the lone pairs, so pairs must move into the bond.
D
This option is wrong — you over-bonded the hydrogens — hydrogen is full at two, one single line each.
Total valence electrons: 2 × 4 + 2 × 1 = 10. Each carbon bonds one hydrogen, then the carbons share three pairs with each other. H–C≡C–H uses 2 + 6 + 2 = 10 electrons, every hydrogen at two, every carbon at eight.
Lesson 22 of 70 · CMB-022
Checking a Lewis diagram
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You can draw Lewis diagrams. A diagram can look tidy and still be wrong, so chemists run two quick checks on any diagram — their own included.
The idea
Check 1: count every electron in the diagram — each line is two — and compare with the molecule's total valence electrons.
Check 2: count the electrons around each atom — eight for most atoms, two for hydrogen.
A diagram that fails either check is wrong, and the failed check names the error.
The figure shows a student's water diagram with one lone pair on the oxygen.
Check 1: two lines (4) plus one lone pair (2) is 6 electrons, but H₂O has 8 — two electrons are missing.
A tidy-looking diagram that fails check 1: only six electrons drawn where eight belong.
Check 2 agrees: the oxygen sits at six.
The diagram is wrong; the oxygen needs a second lone pair.
Worked examples
Worked example 1. A student draws NF₃ with three N–F lines, three lone pairs on each fluorine, and two lone pairs on the nitrogen. Run the two checks. NF₃ has 26 valence electrons.
Step 1
Check 1: three lines (6) + nine fluorine lone pairs (18) + two nitrogen lone pairs (4) = 28 electrons, but the molecule has 26.
Step 2
The diagram shows two electrons too many.
Step 3
Check 2 finds the culprit: the nitrogen sits at ten.
Step 4
Wrong — the nitrogen should carry one lone pair, not two.
Worked example 2. A student draws PH₃ with three P–H lines and one lone pair on the phosphorus. Run the two checks. PH₃ has 8 valence electrons.
Step 1
Check 1: three lines (6) + one lone pair (2) = 8 electrons — matches the total.
Step 2
Check 2: each hydrogen sits at two, and the phosphorus sits at 6 + 2 = 8.
Step 3
Both checks pass — the diagram is correct.
You can now evaluate a supplied Lewis diagram by checking the total electron count and each atom's octet, and identify the error when the diagram is wrong.
Check your understanding
The figure shows a student's Lewis diagram of fluorine, F₂, which has 14 valence electrons. Run the two checks. What is the verdict?
AThe diagram is correct.correct
BThe diagram shows too many electrons.
This option is wrong — you over-counted — one line (2) plus six lone pairs (12) is exactly 14, matching the total.
CThe diagram shows too few electrons.
This option is wrong — you under-counted — remember each line is two electrons and each lone pair is two more, giving 14.
DThe total is right, but an atom is short of its eight.
This option is wrong — you miscounted an atom — each fluorine has one shared pair plus three lone pairs, which is eight.
Check 1: one line (2) + six lone pairs (12) = 14 — matches F₂'s total. Check 2: each fluorine sits at 2 + 6 = 8. Both checks pass, so the diagram is correct.
Check your understanding
The figure shows a student's Lewis diagram of hydrogen sulfide, H₂S, which has 8 valence electrons. Run the two checks. What is the verdict?
AThe diagram shows too many electrons.correct
BThe diagram is correct.
This option is wrong — you skipped check 1 — two lines (4) plus three lone pairs (6) is 10 electrons, but H₂S has only 8.
CThe diagram shows too few electrons.
This option is wrong — you flipped the direction — the drawing holds 10 electrons against a total of 8, which is two too many.
DThe total is right, but an atom is short of its eight.
This option is wrong — you passed check 1 without counting — the total is 10, not 8, so the diagram already fails the first check.
Check 1: two lines (4) + three lone pairs (6) = 10, but H₂S has 8. Two electrons too many — the diagram fails the first check. The sulfur should carry two lone pairs, not three.
Check your understanding
The figure shows a student's Lewis diagram of hydrogen bromide, HBr, which has 8 valence electrons. Run the two checks. What is the verdict?
AThe diagram shows too few electrons.correct
BThe diagram is correct.
This option is wrong — you skipped check 1 — one line (2) plus two lone pairs (4) is 6 electrons, but HBr has 8.
CThe diagram shows too many electrons.
This option is wrong — you flipped the direction — the drawing holds 6 electrons against a total of 8, which is two too few.
DThe total is right, but an atom is short of its eight.
This option is wrong — you passed check 1 without counting — the total is 6, not 8, so the first check already fails.
Check 1: one line (2) + two lone pairs (4) = 6, but HBr has 8. Two electrons are missing — the diagram fails the first check. Check 2 names the spot: the bromine sits at six and needs a third lone pair.
Lesson 23 of 70 · CMB-023
The full Lewis routine
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You've drawn two-atom molecules, central-atom molecules, and molecules with double and triple bonds, and you can check any diagram. One routine strings those skills together — and it works on molecules you have never met.
The idea
Step 1: count the molecule's total valence electrons.
Step 2: place the central atom, with the other atoms around it.
Step 3: join each outer atom to the central atom with a single line.
Step 4: place the remaining electrons as lone pairs, outer atoms first, until every atom has eight, with hydrogen full at two.
Step 5: if an atom is still short, convert a lone pair from a neighboring atom into an extra shared pair.
Finish with the two checks: the total matches, and every atom is full.
Methanal, H₂CO, runs the routine like this: total 1 + 1 + 4 + 6 = 12; carbon central; three single lines use 6; the remaining 6 make three lone pairs on the oxygen; the carbon sits at six, so one oxygen pair converts to a C=O double bond.
Both checks now pass: 12 electrons drawn, hydrogens at two, carbon and oxygen at eight.
The routine's finished product: methanal after step 5, passing both checks.
Worked examples
Worked example 1. Draw the Lewis diagram of chloromethane, CH₃Cl. Carbon is in Group 14, hydrogen has one valence electron, chlorine is in Group 17.
Step 1
Step 1: total = 4 + 3 × 1 + 7 = 14.
Step 2
Step 2: carbon forms the most bonds, so carbon is central.
Step 3
Step 3: four single lines — three to H, one to Cl — use 8 electrons.
Step 4
Step 4: the remaining 6 make three lone pairs on the chlorine.
Step 5
Step 5: no atom is short, so nothing converts; both checks pass.
Step 6
C central with three C–H lines, one C–Cl line, and three radial lone pairs on the chlorine.
Worked example 2. Draw the Lewis diagram of phosgene, COCl₂. Carbon is in Group 14, oxygen in Group 16, chlorine in Group 17.
Step 1
Step 1: total = 4 + 6 + 2 × 7 = 24.
Step 2
Step 2: carbon is central.
Step 3
Step 3: three single lines use 6 electrons.
Step 4
Step 4: the remaining 18 fill the outer atoms — three lone pairs each on both chlorines and the oxygen.
Step 5
Step 5: the carbon sits at six, so one oxygen lone pair converts to a C=O double bond; both checks pass.
Step 6
C central with C=O, two C–Cl lines, two lone pairs on the oxygen, three on each chlorine.
You can now draw the Lewis diagram of an unfamiliar small molecule by the full routine: total the valence electrons, place the central atom, connect the atoms with single bonds, complete octets with lone pairs, and convert lone pairs into extra shared pairs if needed.
Your turn
On paper, use the five-step routine to draw the Lewis diagram of dichloromethane, CH₂Cl₂. Carbon is in Group 14, hydrogen has one valence electron, chlorine is in Group 17. Then select Continue to compare your drawing with the model answer.
Model answer. Carbon in the middle with four single lines: two to hydrogens, two to chlorines. Each chlorine carries three lone pairs pointing straight out, dots side by side. Total: four lines (8) plus six lone pairs (12) = 20 electrons; step 5 is not needed because every atom is already full.
Carbon sits in the middle with four single lines — two to H, two to Cl.
The diagram shows 20 electrons: four lines (8) plus six lone pairs (12).
Each chlorine carries three lone pairs; the carbon and hydrogens carry none.
Every lone pair points straight out from its atom, its two dots side by side.
Your turn
On paper, use the five-step routine to draw the Lewis diagram of carbonyl sulfide, OCS — a real gas with a carbon central atom. Carbon is in Group 14; oxygen and sulfur are in Group 16. Then select Continue to compare your drawing with the model answer.
Model answer. O=C=S: carbon in the middle joined to the oxygen and to the sulfur by double bonds, with two lone pairs each on the oxygen and the sulfur, pointing straight out. After step 4, single bonds leave the carbon at four, so one lone pair converts in from each neighbor. Total: two double bonds (8) plus four lone pairs (8) = 16 electrons.
Carbon sits in the middle joined to the oxygen and the sulfur by two parallel lines each.
The diagram shows 16 electrons: two double bonds (8) plus four lone pairs (8).
The oxygen and the sulfur each carry two lone pairs; the carbon carries none.
Every lone pair points straight out from its atom, its two dots side by side.
Check your understanding
Which picture shows the Lewis diagram that the five-step routine produces for silicon tetrafluoride, SiF₄? Silicon is in Group 14 and fluorine is in Group 17.
Acorrect
B
This option is wrong — you converted a pair no one needed — after step 4 every atom already sits at eight, so step 5 does nothing.
C
This option is wrong — you stopped step 4 early — SiF₄ has 32 electrons, and each fluorine needs three lone pairs to reach eight.
D
This option is wrong — you overfilled the silicon — its four shared pairs already give it eight, and the total would rise to 34.
Step 1: total = 4 + 4 × 7 = 32. Steps 2–3: silicon central, four single lines (8 electrons). Step 4: the remaining 24 give each fluorine three lone pairs; step 5 is not needed.
Summary video — Covalent bonds, naming molecules, and Lewis diagrams
Tie four balloons together at their necks and let go. Nobody arranges them, yet they always spring into the same spread-out pattern. Something very similar decides the shape of every molecule.
You've seen that the electron pairs around an atom come as bonding pairs and lone pairs. A Lewis diagram is flat on the page — a real molecule is not.
The idea
A real molecule is a three-dimensional object, and its atoms sit at definite positions.
The bonding pairs and lone pairs around a central atom are called its 'electron groups'.
Electron groups are all made of negative electrons, and like charges repel.
A molecule takes its shape because electron groups repel each other, so they take up positions as far apart as possible around the central atom.
That is why the four bonding pairs of CH₄ spread out evenly in three dimensions instead of crowding onto one side.
The balloons behave the same way: squeezed together at one point, they push one another apart until they are as spread out as they can get.
Electron groups repel each other, so they take up positions as far apart as possible around the central atom.
Worked examples
Worked example 1. Why do the four bonding pairs around the carbon of CBr₄ not bunch together on one side of the atom?
Step 1
The four bonding pairs are four electron groups, all negatively charged.
Step 2
Electron groups repel each other, so they take up positions as far apart as possible around the central atom.
Step 3
The four pairs spread out evenly around the carbon — bunching would push like charges together.
Worked example 2. The nitrogen of NF₃ holds three bonding pairs and one lone pair. Why does the lone pair claim a position of its own instead of squeezing in beside a bond?
Step 1
The lone pair is an electron group just like the bonding pairs.
Step 2
Electron groups repel each other, so they take up positions as far apart as possible around the central atom.
Step 3
All four groups — three bonds and the lone pair — spread out around the nitrogen.
You can now explain why a molecule takes the shape it does, because electron groups repel each other, so they take up positions as far apart as possible around the central atom.
Check your understanding
Why do the four bonding pairs of SiCl₄ spread out evenly around the silicon?
ABecause electron groups repel each other, so they take up positions as far apart as possible around the central atom.correct
BBecause the chlorine atoms are heavy, and their weight pulls the bonds down into a balanced, evenly spaced arrangement.
This option is wrong — you used mass as the cause — the spreading comes from repulsion between the negative electron groups, not from the outer atoms' weight.
CBecause the bonding pairs attract one another and pull themselves into an evenly spaced ring around the silicon.
This option is wrong — you flipped the force — electron pairs are all negative, so they repel; attraction between them would crowd the pairs together.
DBecause the Lewis diagram of SiCl₄ is drawn with its four bonds pointing in four different directions on the page.
This option is wrong — you treated the drawing as the cause — the flat diagram records bonds, and the real spreading is driven by repulsion between the groups.
The four bonding pairs are four negative electron groups. Electron groups repel each other, so they take up positions as far apart as possible around the central atom. Even spreading is the arrangement that keeps the like charges farthest apart.
Check your understanding
What decides the positions the electron groups around a central atom take up?
ATheir mutual repulsion — the groups take positions as far apart from each other as possible.correct
BThe order in which the formula lists the atoms — earlier atoms take the closer positions.
This option is wrong — you read geometry out of writing order — a formula's letter order carries no position information; repulsion between the groups sets the positions.
CThe masses of the outer atoms — heavier atoms push the groups into place.
This option is wrong — you used mass as the cause — the groups are negative electron pairs, and their mutual repulsion, not any atom's weight, spaces them out.
DTheir mutual attraction — the groups pull each other into evenly spaced positions.
This option is wrong — you flipped the force — like charges repel, so the groups push apart rather than pull together.
Electron groups are all negatively charged. Electron groups repel each other, so they take up positions as far apart as possible around the central atom. No other property — mass, writing order, attraction — plays a part.
Check your understanding
The phosphorus of PH₃ holds three bonding pairs and one lone pair. Which statement about the lone pair is correct?
AThe lone pair repels the bonding pairs and takes up a spread-out position of its own.correct
BThe lone pair has no effect on the other pairs, because it joins the phosphorus to no atom.
This option is wrong — you tied repulsion to bonding — a lone pair is a negative electron group whether or not it joins two atoms, so it repels like any other group.
CThe lone pair attracts the three bonding pairs and gathers them onto its side of the atom.
This option is wrong — you flipped the force — all the pairs are negative, so the lone pair pushes the bonding pairs away rather than gathering them.
DThe lone pair squeezes itself between two bonding pairs without claiming any space.
This option is wrong — you let groups overlap — every electron group claims its own position, as far from the others as possible.
A lone pair is an electron group just like a bonding pair. Electron groups repel each other, so they take up positions as far apart as possible around the central atom. All four of the phosphorus's groups — three bonds and the lone pair — spread out.
Lesson 25 of 70 · CMB-025
Counting electron groups
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You've seen that electron groups spread out by repulsion. Before any shape can be worked out, the groups have to be counted — and the counting has two rules of its own.
The idea
Look only at the central atom.
Count each bond as one electron group, whether it is single, double, or triple.
A double or triple bond is one group because its shared pairs sit together in the same space between the same two atoms.
Count each lone pair on the central atom as one electron group.
Lone pairs on the outer atoms do not count — they crowd their own atom, not the central one.
In CO₂, the carbon has two double bonds and no lone pairs, so the carbon has two electron groups.
Counting electron groups at the central atom: panel 1 walks CO₂; panels 2 and 3 are the worked-example diagrams.
Worked examples
Worked example 1. The figure's worked-example panel shows the Lewis diagram of ammonia, NH₃. How many electron groups surround the nitrogen?
Step 1
Bonds at the central atom: three N–H single bonds = 3 groups.
Step 2
Lone pairs on the central atom: one = 1 group.
Step 3
3 + 1 = 4.
Step 4
The nitrogen has 4 electron groups.
Worked example 2. The figure's second worked-example panel shows the Lewis diagram of methanal, H₂CO. How many electron groups surround the carbon?
Step 1
Bonds at the central atom: two C–H single bonds and one C=O double bond = 3 groups.
Step 2
The double bond counts once, and the oxygen's lone pairs belong to the oxygen.
Step 3
3 + 0 = 3.
Step 4
The carbon has 3 electron groups.
You can now calculate the number of electron groups around the central atom of a Lewis diagram, counting each bond, whether single, double, or triple, as one group and each lone pair as one group.
Check your understanding
The figure shows the Lewis diagram of water, H₂O. How many electron groups surround the oxygen?
Answer: 4groups
Bonds at the oxygen: two O–H single bonds = 2 groups. Lone pairs on the oxygen: two = 2 groups. 2 + 2 = 4 electron groups.
Check your understanding
The figure shows the Lewis diagram of hydrogen cyanide, HCN. How many electron groups surround the carbon?
Answer: 2groups
Bonds at the carbon: one C–H single bond and one C≡N triple bond = 2 groups. The triple bond counts once; the nitrogen's lone pair belongs to the nitrogen. 2 + 0 = 2 electron groups.
Check your understanding
The figure shows the Lewis diagram of carbonyl fluoride, COF₂. How many electron groups surround the carbon?
Answer: 3groups
Bonds at the carbon: two C–F single bonds and one C=O double bond = 3 groups. The carbon has no lone pairs, and the outer atoms' pairs do not count. 3 + 0 = 3 electron groups.
Lesson 26 of 70 · CMB-026
Linear molecules
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You can count the electron groups around a central atom. Each count produces its own shape, and the shapes have names. The first: two groups.
The idea
Two electron groups sit on exactly opposite sides of the central atom, because electron groups repel each other, so they take up positions as far apart as possible around the central atom.
With the two groups opposite each other, the three atoms lie in a straight line.
A molecule whose central atom has two electron groups and no lone pairs is 'linear'.
Both conditions matter: count the groups, then check that none of them is a lone pair — in the molecules you will meet in this course, linear means exactly this pair of conditions.
In CO₂, the carbon has two electron groups — the two double bonds — and no lone pairs, so CO₂ is linear.
The figure shows the shape: O, C, and O in one straight line.
Two electron groups sit opposite each other, so the three atoms lie in a straight line.
Worked examples
Worked example 1. The carbon of hydrogen cyanide, HCN, has two electron groups — one single bond and one triple bond — and no lone pairs. Classify the molecule's shape.
Step 1
Two electron groups, and neither is a lone pair.
Step 2
Two groups and no lone pairs is the linear condition.
Step 3
HCN is linear — H, C, and N lie in a straight line.
Worked example 2. The carbon of carbon disulfide, CS₂, has two double bonds and no lone pairs. Classify the molecule's shape.
Step 1
Each double bond is one group, so the carbon has two electron groups and no lone pairs.
Step 2
Two groups and no lone pairs is the linear condition.
Step 3
CS₂ is linear — S, C, and S lie in a straight line.
You can now classify a molecule as linear when its central atom has two electron groups and no lone pairs.
Check your understanding
Each picture shows a Lewis diagram. Which molecule is linear?
Acorrect
B
This option is wrong — you counted only the bonds — the oxygen's two lone pairs are groups too, giving four groups, and linear needs exactly two with none a lone pair.
C
This option is wrong — you passed a three-group atom — linear needs exactly two electron groups at the central atom.
D
This option is wrong — you passed a four-group atom — three bonds plus a lone pair is four groups, not the two that linear requires.
Count the groups at each central atom, lone pairs included. Only the OCS carbon has exactly two groups with none a lone pair. Two groups and no lone pairs is the linear condition.
Check your understanding
In the molecules you will meet in this course, what must be true of a molecule's central atom for the molecule to be linear?
AIt has two electron groups and no lone pairs.correct
BIt has two bonding pairs and two lone pairs.
This option is wrong — you allowed lone pairs into the count — that central atom has four groups, and linear requires exactly two with none a lone pair.
CIt has three electron groups and no lone pairs.
This option is wrong — you took the three-group condition — three groups spread into a different arrangement; linear is the two-group case.
DIt is joined to exactly two other atoms, whatever else it carries.
This option is wrong — you counted attached atoms instead of groups — a central atom with two bonds can also carry lone pairs, and those extra groups change the shape.
Linear is a two-part condition. Count the electron groups: exactly two. Check the groups: neither is a lone pair.
Check your understanding
Two electron groups surround a central atom. Where do they sit?
AOn opposite sides of the atom, as far apart from each other as possible.correct
BAt right angles to each other, a quarter turn apart.
This option is wrong — you stopped the spreading early — a quarter turn still leaves room to separate, and repulsion drives the two groups to opposite sides.
CSide by side on the same side of the atom.
This option is wrong — you crowded the like charges together — electron groups repel each other, so two groups end up opposite, never adjacent.
DWherever the Lewis diagram happens to place them on the page.
This option is wrong — you treated the drawing as the geometry — the flat diagram records bonds, and repulsion sets the real positions.
Electron groups repel each other, so they take up positions as far apart as possible around the central atom. For two groups, farthest apart means exactly opposite sides. Opposite groups put the attached atoms in a straight line.
Lesson 27 of 70 · CMB-027
Trigonal planar molecules
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Did You Know?
Two electron groups gave a straight line. The next count up has its own shape and name.
The idea
Three electron groups spread toward the corners of a flat triangle, because electron groups repel each other, so they take up positions as far apart as possible around the central atom.
A molecule whose central atom has three electron groups and no lone pairs is 'trigonal planar'.
'Trigonal' means three-cornered, and 'planar' means flat — the central atom and all three attached atoms lie in one flat plane.
Both conditions matter: count three groups, then check that none of them is a lone pair.
In methanal, H₂CO, the carbon has three electron groups — two single bonds and one double bond — and no lone pairs, so H₂CO is trigonal planar.
The figure shows the shape: the carbon in the middle, the two hydrogens and the oxygen at the triangle's corners.
Three electron groups point at the corners of a flat triangle.
Worked examples
Worked example 1. The carbon of phosgene, COCl₂, has two single bonds, one double bond, and no lone pairs. Classify the molecule's shape.
Step 1
Two single bonds and one double bond is three electron groups, and none is a lone pair.
Step 2
Three groups and no lone pairs is the trigonal planar condition.
Step 3
COCl₂ is trigonal planar — the carbon sits in the middle of a flat triangle of O, Cl, and Cl.
Worked example 2. The carbon of hydrogen cyanide, HCN, has one single bond, one triple bond, and no lone pairs. Is HCN trigonal planar?
Step 1
One single bond and one triple bond is two electron groups, not three.
Step 2
Two groups and no lone pairs is the linear condition.
Step 3
No — HCN is linear, not trigonal planar.
You can now classify a molecule as trigonal planar when its central atom has three electron groups and no lone pairs.
Check your understanding
Each picture shows a Lewis diagram. Which molecule is trigonal planar?
Acorrect
B
This option is wrong — you passed a two-group atom — two double bonds is two groups, which is the linear condition, not the three of trigonal planar.
C
This option is wrong — you passed a four-group atom — trigonal planar needs exactly three electron groups.
D
This option is wrong — you counted only the bonds — the oxygen's two lone pairs bring its count to four groups, not three.
Count the groups at each central atom, lone pairs included, each bond once. Only the COF₂ carbon has exactly three groups with none a lone pair. Three groups and no lone pairs is the trigonal planar condition.
Check your understanding
What must be true of a molecule's central atom for the molecule to be trigonal planar?
AIt has three electron groups and no lone pairs.correct
BIt has three bonding pairs and one lone pair.
This option is wrong — you let a lone pair in — that atom has four groups, and trigonal planar requires exactly three with none a lone pair.
CIt has two electron groups and no lone pairs.
This option is wrong — you took the linear condition — two groups give a straight line; trigonal planar is the three-group case.
DIt has four electron groups and no lone pairs.
This option is wrong — you took the four-group count — trigonal planar is exactly three groups at the central atom.
Trigonal planar is a two-part condition. Count the electron groups: exactly three. Check the groups: none is a lone pair.
Check your understanding
The figure shows the Lewis diagram of ethene, C₂H₄. Which description fits the arrangement around each carbon in the real molecule?
AEach carbon's three groups point at the corners of a flat triangle — the trigonal planar arrangement.correct
BEach carbon's two groups sit on exactly opposite sides of the carbon, in the linear arrangement.
This option is wrong — you counted the double bond as nothing or the atom as two-group — each carbon has THREE groups: two C–H bonds plus the C=C bond counted once.
CEach carbon's four shared pairs spread as four separate groups.
This option is wrong — you counted the double bond as two groups — a bond of any multiplicity is one group, so each carbon has three.
DThe groups crowd toward the other carbon, pulled by its charge.
This option is wrong — you flipped the force — electron groups repel each other and spread as far apart as possible; nothing pulls them together.
Count at one carbon: two C–H single bonds plus the C=C double bond, counted once, is three groups. No lone pairs sit on either carbon. Three groups and no lone pairs is the trigonal planar condition, at each carbon.
Lesson 28 of 70 · CMB-028
Tetrahedral molecules
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Did You Know?
Two groups gave a line and three gave a flat triangle. Four electron groups cannot all get their distance on a flat page — they need the third dimension.
The idea
Four electron groups spread out farthest by pointing at the four corners of a 'tetrahedron' — a solid with four triangular faces, like a pyramid on a triangular base.
They do this because electron groups repel each other, so they take up positions as far apart as possible around the central atom.
In three dimensions the four corners of a tetrahedron are farther apart than any flat arrangement allows.
A molecule whose central atom has four electron groups and no lone pairs is 'tetrahedral'.
Both conditions matter: count four groups, then check that none of them is a lone pair.
In methane, CH₄, the carbon has four electron groups — the four single bonds — and no lone pairs, so CH₄ is tetrahedral.
The figure shows the shape: the carbon in the middle, the four hydrogens at the tetrahedron's corners.
Four electron groups point at the four corners of a tetrahedron — farther apart than any flat arrangement allows.
Worked examples
Worked example 1. The silicon of silicon tetrachloride, SiCl₄, has four single bonds and no lone pairs. Classify the molecule's shape.
Step 1
Four bonds is four electron groups, and none is a lone pair.
Step 2
Four groups and no lone pairs is the tetrahedral condition.
Step 3
SiCl₄ is tetrahedral — the four chlorines sit at the corners of a tetrahedron.
Worked example 2. The nitrogen of ammonia, NH₃, has three single bonds and one lone pair. Is NH₃ tetrahedral?
Step 1
Three bonds plus one lone pair is four electron groups, but one of them IS a lone pair.
Step 2
Tetrahedral requires four groups with none a lone pair.
Step 3
No — NH₃ is not tetrahedral. Its shape has its own name, coming in a later lesson.
You can now classify a molecule as tetrahedral when its central atom has four electron groups and no lone pairs.
Check your understanding
Each picture shows a Lewis diagram. Which molecule is tetrahedral?
Acorrect
B
This option is wrong — you matched the four-group count without the second check — two of the oxygen's four groups are lone pairs, and tetrahedral requires all four to be bonds.
C
This option is wrong — you passed a three-group atom — that is the trigonal planar count, and tetrahedral needs four groups.
D
This option is wrong — you passed a two-group atom — two double bonds is two groups, the linear count, not four.
Count the groups at each central atom, lone pairs included, each bond once. Only the CBr₄ carbon has exactly four groups with none a lone pair. Four groups and no lone pairs is the tetrahedral condition.
Check your understanding
What must be true of a molecule's central atom for the molecule to be tetrahedral?
AIt has four electron groups and no lone pairs.correct
BIt has four electron groups, one of them a lone pair.
This option is wrong — you let a lone pair in — tetrahedral names the shape of four BONDING groups; a lone pair among the four changes the molecule's shape.
CIt has three electron groups and no lone pairs.
This option is wrong — you took the trigonal planar condition — three groups make the flat triangle; tetrahedral is the four-group case.
DIt has two double bonds and no lone pairs.
This option is wrong — you counted a double bond as two groups — two double bonds is two groups, the linear condition.
Tetrahedral is a two-part condition. Count the electron groups: exactly four. Check the groups: none is a lone pair.
Check your understanding
The figure shows the Lewis diagram of difluoromethane, CH₂F₂. Classify the shape of the molecule.
ATetrahedralcorrect
BTrigonal planar
This option is wrong — you dropped a group — the carbon has four single bonds, and four groups with no lone pairs is tetrahedral, not the three-group flat triangle.
CLinear
This option is wrong — you gave a four-group atom the two-group shape — count the bonds: the carbon holds four.
DNone of the above
This option is wrong — you counted the fluorines' lone pairs at the carbon — outer-atom lone pairs never count, and the carbon's four bonding groups make the molecule tetrahedral.
Count at the carbon: four single bonds — two to hydrogen, two to fluorine. Four groups, none a lone pair; the fluorines' pairs belong to the fluorines. Four groups and no lone pairs is the tetrahedral condition.
Lesson 29 of 70 · CMB-029
Trigonal pyramidal molecules
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Did You Know?
In every shape you've classified so far, all of the central atom's electron groups were bonding pairs. NH₃ is the first molecule where one of the groups is not.
The idea
In the Lewis diagram of NH₃, the nitrogen holds three bonding pairs and one lone pair — four electron groups.
All four groups spread out, because electron groups repel each other, so they take up positions as far apart as possible around the central atom.
Four electron groups, one of them a lone pair: the three hydrogen atoms form a tripod under the nitrogen — trigonal pyramidal.
Only three of the four positions hold atoms — the fourth holds the lone pair.
The three hydrogen atoms sit as a low tripod with the nitrogen above them.
A molecule shaped this way is called 'trigonal pyramidal' — a pyramid with a triangle for its base and the central atom at its peak.
Classify a molecule as trigonal pyramidal when its central atom has four electron groups and exactly one of them is a lone pair.
Worked examples
Worked example 1. In the Lewis diagram of PCl₃, the phosphorus makes single bonds to three chlorine atoms and holds one lone pair. Classify the shape of PCl₃.
Step 1
Electron groups around the phosphorus: three bonding pairs plus one lone pair, so four groups.
Step 2
Lone pairs among the four groups: exactly one.
Step 3
Four groups with exactly one lone pair is trigonal pyramidal.
Step 4
PCl₃ is trigonal pyramidal.
Worked example 2. In the Lewis diagram of NF₃, the nitrogen makes single bonds to three fluorine atoms and holds one lone pair. Classify the shape of NF₃.
Step 1
Electron groups around the nitrogen: three bonding pairs plus one lone pair, so four groups.
Step 2
Lone pairs among the four groups: exactly one.
Step 3
NF₃ is trigonal pyramidal.
You can now classify a molecule as trigonal pyramidal when its central atom has four electron groups and exactly one of them is a lone pair.
Check your understanding
The figure shows the Lewis diagram of PF₃. Classify its shape.
ATrigonal pyramidalcorrect
BTetrahedral
This option is wrong — you counted the lone pair as if it held an atom — four groups, but exactly one is a lone pair, and that is the trigonal pyramidal pattern.
CTrigonal planar
This option is wrong — you ignored the lone pair — it is a fourth electron group, so the three bonds are pushed out of a flat triangle.
DLinear
This option is wrong — you gave the two-group shape — the phosphorus holds four electron groups: three bonds plus one lone pair.
Count the groups around the phosphorus: three bonds plus one lone pair is four. Count the lone pairs among them: exactly one. Four groups with exactly one lone pair is trigonal pyramidal, so PF₃ is trigonal pyramidal.
Check your understanding
The figure shows the Lewis diagram of AsH₃. Classify its shape.
ATrigonal pyramidalcorrect
BTrigonal planar
This option is wrong — you dropped the lone pair from the count — with four groups pushing apart, the three As–H bonds cannot lie in a flat triangle.
CTetrahedral
This option is wrong — you treated the lone pair as a fourth attached atom — only the three hydrogens hold positions with atoms in them.
DLinear
This option is wrong — you gave the two-group shape — the arsenic holds four electron groups: three bonds plus one lone pair.
Count the groups around the arsenic: three bonds plus one lone pair is four. Exactly one of the four groups is a lone pair. Four groups with exactly one lone pair is trigonal pyramidal, so AsH₃ is trigonal pyramidal.
Check your understanding
The figure shows the Lewis diagram of nitrogen trichloride, NCl₃. Classify its shape.
ATrigonal pyramidalcorrect
BTrigonal planar
This option is wrong — you counted only the three bonds — the lone pair on the nitrogen is a fourth group, and it pushes the bonds out of a flat triangle.
CTetrahedral
This option is wrong — you counted the chlorine atoms' lone pairs into the shape — only the CENTRAL atom's groups set the shape, and one of nitrogen's four is a lone pair.
DLinear
This option is wrong — you gave the two-group shape — the nitrogen holds four electron groups: three bonds plus one lone pair.
Only the central atom's groups count: nitrogen holds three bonds plus one lone pair, so four groups. Exactly one of the four is a lone pair. Four groups with exactly one lone pair is trigonal pyramidal, so NCl₃ is trigonal pyramidal.
Lesson 30 of 70 · CMB-030
Bent molecules
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Did You Know?
You've already seen one lone pair at work in trigonal pyramidal molecules. The central atom of a water molecule holds two.
The idea
In the Lewis diagram of H₂O, the oxygen holds two bonding pairs and two lone pairs — four electron groups.
All four groups spread out, because electron groups repel each other, so they take up positions as far apart as possible around the central atom.
Four electron groups, two of them lone pairs: the three atoms form a wide V — bent.
Only two of the four positions hold atoms — the other two hold lone pairs.
The three atoms make a wide open V.
A molecule shaped this way is called 'bent'.
Classify a molecule as bent when its central atom has four electron groups and exactly two of them are lone pairs.
Worked examples
Worked example 1. In the Lewis diagram of oxygen difluoride, OF₂, the oxygen makes single bonds to two fluorine atoms and holds two lone pairs. Classify the shape of OF₂.
Step 1
Electron groups around the oxygen: two bonding pairs plus two lone pairs, so four groups.
Step 2
Lone pairs among the four groups: exactly two.
Step 3
Four groups with exactly two lone pairs is bent.
Step 4
OF₂ is bent.
Worked example 2. In the Lewis diagram of SCl₂, the sulfur makes single bonds to two chlorine atoms and holds two lone pairs. Classify the shape of SCl₂.
Step 1
Electron groups around the sulfur: two bonding pairs plus two lone pairs, so four groups.
Step 2
Lone pairs among the four groups: exactly two.
Step 3
SCl₂ is bent.
You can now classify a molecule as bent when its central atom has four electron groups and exactly two of them are lone pairs.
Check your understanding
The figure shows the Lewis diagram of H₂Se. Classify its shape.
ABentcorrect
BLinear
This option is wrong — you put the three atoms in a straight line — the two lone pairs are electron groups too, and they push the two bonds into a V.
CTrigonal pyramidal
This option is wrong — you counted only one lone pair — the selenium holds two, and four groups with two lone pairs is bent.
DTetrahedral
This option is wrong — you counted the two lone pairs as if they held atoms — only two positions hold atoms.
Count the groups around the selenium: two bonds plus two lone pairs is four. Exactly two of the four groups are lone pairs. Four groups with exactly two lone pairs is bent, so H₂Se is bent.
Check your understanding
The figure shows the Lewis diagram of SF₂. Classify its shape.
ABentcorrect
BLinear
This option is wrong — you drew the three atoms in a row — the sulfur's two lone pairs push the two S–F bonds into a V.
CTetrahedral
This option is wrong — you treated the two lone pairs as attached atoms — only the two fluorines hold atom positions.
DTrigonal planar
This option is wrong — you counted three groups — the sulfur holds four: two bonds plus two lone pairs.
Count the groups around the sulfur: two bonds plus two lone pairs is four. Exactly two of the four groups are lone pairs. Four groups with exactly two lone pairs is bent, so SF₂ is bent.
Check your understanding
The figure shows the Lewis diagram of dichlorine monoxide, Cl₂O, whose central atom is the oxygen. Classify its shape.
ABentcorrect
BLinear
This option is wrong — you lined the three atoms up straight — the oxygen's two lone pairs are groups that push the bonds into a V.
CTrigonal pyramidal
This option is wrong — you counted one lone pair instead of two — four groups with TWO lone pairs is bent.
DTetrahedral
This option is wrong — you counted the chlorine atoms' lone pairs into the shape — only the central oxygen's four groups count, and two of them are lone pairs.
Only the central atom's groups count: the oxygen holds two bonds plus two lone pairs, so four groups. Exactly two of the four are lone pairs. Four groups with exactly two lone pairs is bent, so Cl₂O is bent.
Lesson 31 of 70 · CMB-031
How lone pairs change the shape
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Did You Know?
You've already classified CH₄ as tetrahedral and NH₃ as trigonal pyramidal. Both central atoms hold four electron groups — so why do the two molecules get different names?
The idea
CH₄ and NH₃ both hold four electron groups around the central atom, spread as far apart as possible.
In CH₄ every group holds an atom; in NH₃ one group is a lone pair.
Both molecules hold four electron groups; the name reports only where the atoms are.
A shape's name describes only the positions of the atoms.
The lone pair still occupies its own position — it is an electron group like any other — but it does not appear in the name.
So NH₃ is named for what its atoms show: three hydrogens in a tripod under the nitrogen, which is trigonal pyramidal rather than tetrahedral.
The lone pair does one more thing: it pushes the three bonding pairs slightly closer together, squeezing the pyramid narrower than CH₄'s spread.
Worked examples
Worked example 1. H₂O has four electron groups around its oxygen, two of them lone pairs. Explain why H₂O is named bent rather than tetrahedral.
Step 1
A shape's name describes only the positions of the atoms.
Step 2
Two of water's four groups are lone pairs, so atoms sit at only three positions — the oxygen and the two hydrogens.
Step 3
Three atoms in a wide V is the bent shape.
Step 4
H₂O is named bent because the name reports its three atoms' V — the two lone pairs occupy positions but are not atoms.
Worked example 2. Explain why PF₃, whose phosphorus holds four electron groups, is named trigonal pyramidal rather than tetrahedral.
Step 1
A shape's name describes only the positions of the atoms.
Step 2
One of the four groups is a lone pair, so atoms sit at only three of the positions around the phosphorus.
Step 3
Three fluorines in a tripod under the phosphorus is the trigonal pyramidal shape.
Step 4
PF₃ is named trigonal pyramidal because only its atom positions are named — the lone pair's position is not.
You can now explain why a shape's name describes only the positions of the atoms, even though lone pairs also take up a position and push the bonding pairs together.
Check your understanding
NF₃ has four electron groups around its nitrogen, yet it is named trigonal pyramidal, not tetrahedral. Why?
AShape names describe only the positions of the atoms — the fourth position holds a lone pair, not an atom.correct
BThe lone pair disappears once the three bonds have formed, leaving only three groups.
This option is wrong — you removed the lone pair — it is still there, occupying its own position and pushing on the bonding pairs; it just is not an atom, so the name skips it.
CThe fluorine atoms are too large for the molecule to form a tetrahedral arrangement.
This option is wrong — you blamed atom size — the name difference comes from what names are allowed to count, which is atom positions only.
DThe nitrogen in NF₃ holds only three electron groups, so there is no fourth position to account for.
This option is wrong — you miscounted — three bonds plus one lone pair is four groups; the name changes because one group holds no atom.
Count what the name may report: atom positions only. NF₃ has atoms at three of its four positions — the fourth holds a lone pair. Three fluorines in a tripod under the nitrogen is trigonal pyramidal.
Check your understanding
What does the lone pair on the arsenic in AsH₃ do to the three As–H bonding pairs?
AIt pushes them slightly closer together.correct
BIt spreads them slightly farther apart.
This option is wrong — you flipped the push — the lone pair repels the bonding pairs toward one another, squeezing the pyramid.
CIt does nothing to their positions, because it holds no atom.
This option is wrong — you confused the naming rule with the physics — the lone pair is skipped by the NAME, but it still occupies a position and pushes on the bonds.
DIt flattens the three bonds into a triangle around the arsenic.
This option is wrong — you removed the lone pair's own position — it occupies one of the four positions, so the three bonds stay pushed below the arsenic, not flat around it.
The lone pair is an electron group with its own position. It repels the three bonding pairs, pushing them slightly closer together. That squeeze is real even though the lone pair never appears in the shape's name.
Check your understanding
H₂S is named bent. Why does the name never mention the two lone pairs on the sulfur?
AShape names describe only the positions of the atoms, and the lone pairs are not atoms.correct
BThe two lone pairs left the sulfur when the two bonds formed.
This option is wrong — you deleted the lone pairs — they remain on the sulfur, occupying two of the four positions and pushing the bonds into a V.
CLone pairs do not count as electron groups, so there is nothing to mention.
This option is wrong — you demoted the lone pairs — each lone pair IS an electron group with its own position; the name simply reports atoms only.
DThe name skips the lone pairs because they are too small to affect the molecule.
This option is wrong — you made the naming rule a physical claim — the lone pairs strongly affect the molecule by pushing the bonds together; the name just does not report them.
A shape's name describes only the positions of the atoms. H₂S has atoms at three positions, forming a V — that is what 'bent' reports. The two lone pairs still occupy positions and push the two bonds together; the name simply leaves them out.
Lesson 32 of 70 · CMB-032
Classifying any shape
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Did You Know?
You've already met the five shapes one at a time. This lesson puts the whole decision into one routine you can run on any small molecule.
The idea
Count the electron groups around the central atom, counting each bond — single, double, or triple — as one group and each lone pair as one group.
Then count how many of those groups are lone pairs.
Two groups with no lone pair is linear.
Three groups with no lone pair is trigonal planar.
The five shapes
Electron groups
Lone pairs
Shape
2
0
linear
3
0
trigonal planar
4
0
tetrahedral
4
1
trigonal pyramidal
4
2
bent
Count the groups, count the lone pairs, read off the shape. Every bond — single, double, or triple — is one group.
Four groups with no lone pair is tetrahedral.
Four groups with one lone pair is trigonal pyramidal.
Four groups with two lone pairs is bent.
Take H₂S: the sulfur holds two bonding pairs and two lone pairs — four groups, two of them lone pairs — so H₂S is bent.
Worked examples
Worked example 1. In the Lewis diagram of carbonyl fluoride, COF₂, the carbon makes a double bond to the oxygen and single bonds to two fluorine atoms, with no lone pair on the carbon. Classify the shape.
Step 1
Electron groups around the carbon: the double bond counts as one group, plus two single bonds, so three groups.
Step 2
Lone pairs on the carbon: none.
Step 3
Three groups with no lone pair is trigonal planar.
Step 4
COF₂ is trigonal planar.
Worked example 2. In the Lewis diagram of HCN, the carbon makes a single bond to the hydrogen and a triple bond to the nitrogen, with no lone pair on the carbon. Classify the shape.
Step 1
Electron groups around the carbon: the single bond is one group and the triple bond is one group, so two groups.
Step 2
Lone pairs on the carbon: none.
Step 3
Two groups with no lone pair is linear.
Step 4
HCN is linear.
You can now classify the shape of a supplied small molecule as linear, bent, trigonal planar, trigonal pyramidal, or tetrahedral from its Lewis diagram.
Check your understanding
The figure shows the Lewis diagram of SiCl₄. Classify its shape.
ATetrahedralcorrect
BTrigonal pyramidal
This option is wrong — you imagined a lone pair on the silicon — all four of its groups are bonds.
CTrigonal planar
This option is wrong — you dropped one of the four bonds — four groups, not three.
DBent
This option is wrong — you counted two of the four bonds as lone pairs — the silicon holds no lone pair.
Count the groups around the silicon: four bonds, so four groups. Lone pairs on the silicon: none. Four groups with no lone pair is tetrahedral, so SiCl₄ is tetrahedral.
Check your understanding
The figure shows the Lewis diagram of phosphine, PH₃. Classify its shape.
ATrigonal pyramidalcorrect
BTrigonal planar
This option is wrong — you ignored the lone pair — it is a fourth group, so the three bonds are pushed out of a flat triangle.
CTetrahedral
This option is wrong — you counted the lone pair as an attached atom — atoms sit at only three of the four positions.
DBent
This option is wrong — you counted two lone pairs — the phosphorus holds exactly one.
Count the groups around the phosphorus: three bonds plus one lone pair, so four groups. Lone pairs among them: exactly one. Four groups with one lone pair is trigonal pyramidal, so PH₃ is trigonal pyramidal.
Check your understanding
The figure shows the Lewis diagram of carbon disulfide, CS₂, in which the carbon makes a double bond to each sulfur. Classify its shape.
ALinearcorrect
BTetrahedral
This option is wrong — you counted each double bond as two electron groups — a double bond is ONE group, so the carbon holds two groups, not four.
CBent
This option is wrong — you counted the lone pairs on the OUTER sulfur atoms — only the central atom's groups set the shape, and the carbon has no lone pair.
DTrigonal planar
This option is wrong — you counted three groups — the carbon holds exactly two: one double bond on each side.
Each double bond counts as one group, so the carbon holds two groups. Lone pairs on the carbon: none — the sulfurs' lone pairs do not count. Two groups with no lone pair is linear, so CS₂ is linear.
Lesson 33 of 70 · CMB-033
Drawing molecular shapes
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Did You Know?
You've already classified the five shapes from Lewis diagrams. Now you draw them yourself.
The idea
A 'shape diagram' shows where a molecule's atoms sit: draw each atom as its element symbol, join the symbols with plain lines for the bonds, and write the shape's name under the drawing.
Leave lone pairs out of a shape diagram, because a shape's name describes only the positions of the atoms.
Linear: draw the atoms in one straight line.
Bent: draw the two bonds as a wide V with the central atom at the point.
The five drawing patterns. Atoms only — lone pairs stay out of a shape diagram — and the shape name goes under each drawing.
Trigonal planar: draw the three bonds out to the corners of a flat triangle around the central atom.
Tetrahedral: draw three bonds down as a low tripod and one bond straight up.
Trigonal pyramidal: draw the central atom at the top with its three bonds going down to a low tripod — a pyramid with the central atom at the peak.
Take NH₃: its Lewis diagram shows four groups with one lone pair, so it is trigonal pyramidal — draw the N at the top, three H at the tripod's corners, and label it 'trigonal pyramidal'.
Worked examples
Worked example 1. The Lewis diagram of CH₄ shows four bonding pairs and no lone pair on the carbon. Draw the shape diagram of CH₄.
Step 1
Four groups with no lone pair is tetrahedral.
Step 2
Draw the C in the middle.
Step 3
Draw three C–H bonds going down as a low tripod and one C–H bond going straight up.
Step 4
Label every atom with its symbol and write 'tetrahedral' under the drawing.
Step 5
A tetrahedral shape diagram: C at the center, one H straight up, three H as a low tripod below, labeled 'tetrahedral'.
Worked example 2. The Lewis diagram of CO₂ shows a double bond from the carbon to each oxygen and no lone pair on the carbon. Draw the shape diagram of CO₂.
Step 1
Two groups with no lone pair is linear.
Step 2
Draw the three atoms in one straight line: O, then C, then O.
Step 3
Label every atom with its symbol and write 'linear' under the drawing.
Step 4
A linear shape diagram: O–C–O in one straight line, labeled 'linear'.
You can now draw a labeled shape diagram of a molecule from its Lewis diagram, placing the atoms to match its shape.
Your turn
The figure shows the Lewis diagram of H₂S: the sulfur makes single bonds to two hydrogens and holds two lone pairs. On paper, draw the shape diagram of H₂S, label every atom, and write the shape's name under your drawing. Then select Continue to compare your drawing with the model answer.
Model answer. A wide V with the S at the point and one H at the end of each arm, bonds drawn as plain lines, every atom labeled with its symbol, and 'bent' written under the drawing. No lone pairs appear in the shape diagram.
Four groups with two lone pairs means bent — your drawing is a wide V, not a straight line.
The S sits at the point of the V, with one H at the end of each arm.
Every atom is labeled with its element symbol.
No lone pairs are drawn — a shape diagram shows atoms only.
The name 'bent' is written under the drawing.
Your turn
The figure shows the Lewis diagram of SiH₄: the silicon makes single bonds to four hydrogens and holds no lone pair. On paper, draw the shape diagram of SiH₄, label every atom, and write the shape's name under your drawing. Then select Continue to compare your drawing with the model answer.
Model answer. The Si at the center with three Si–H bonds going down as a low tripod and one Si–H bond going straight up, every atom labeled, and 'tetrahedral' written under the drawing.
Four groups with no lone pair means tetrahedral — three bonds go down as a low tripod and one goes straight up.
The hydrogens are NOT drawn as a flat cross around the silicon.
Every atom is labeled with its element symbol.
The name 'tetrahedral' is written under the drawing.
Your turn
The figure shows the Lewis diagram of NCl₃: the nitrogen makes single bonds to three chlorines and holds one lone pair. On paper, draw the shape diagram of NCl₃, label every atom, and write the shape's name under your drawing. Then select Continue to compare your drawing with the model answer.
Model answer. The N at the top with three N–Cl bonds going down to the corners of a low tripod, every atom labeled, and 'trigonal pyramidal' written under the drawing. The lone pair is not drawn.
Four groups with one lone pair means trigonal pyramidal — the N sits at the peak with the three Cl below it.
The three chlorines are NOT drawn as a flat triangle with the nitrogen at its center.
No lone pair is drawn — a shape diagram shows atoms only.
Every atom is labeled, and 'trigonal pyramidal' is written under the drawing.
Lesson 34 of 70 · CMB-034
From formula to shape
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You've already drawn Lewis diagrams from formulas, and you've read shapes off Lewis diagrams. This lesson chains the two into one run: formula in, shape out.
The idea
Start from the formula and run the full Lewis routine: total the valence electrons, place the central atom, connect the atoms with single bonds, complete octets with lone pairs, and convert lone pairs into extra shared pairs if any octet falls short.
Then count the electron groups and the lone pairs on the central atom.
Read the shape from the counts, and draw or name it.
Take CF₄: the total is 4 + 4 × 7 = 32 valence electrons.
Carbon is the central atom, four C–F single bonds use 8 electrons, and the remaining 24 complete the fluorines' octets as lone pairs.
Formula in, shape out: total the electrons, build the Lewis diagram, count the central atom's groups and lone pairs, read off the shape.
The carbon holds four groups and no lone pair, so CF₄ is tetrahedral.
Worked examples
Worked example 1. Draw the Lewis diagram of HOCl (the oxygen is the central atom) and classify its shape.
Step 1
Total valence electrons: 1 + 6 + 7 = 14.
Step 2
Connect the atoms: H–O–Cl uses 4 electrons, leaving 10.
Step 3
Complete the octets: two lone pairs on the oxygen and three on the chlorine use all 10.
Step 4
Count the oxygen's groups: two bonds plus two lone pairs is four groups, two of them lone pairs.
Step 5
Four groups with two lone pairs is bent.
Step 6
HOCl is bent.
Worked example 2. Draw the Lewis diagram of H₂CO (the carbon is the central atom) and classify its shape.
Step 1
Total valence electrons: 2 × 1 + 4 + 6 = 12.
Step 2
Connect the atoms: two C–H bonds and one C–O bond use 6 electrons, leaving 6.
Step 3
Complete the octets: three lone pairs on the oxygen use the 6, but the carbon's octet falls short.
Step 4
Convert one oxygen lone pair into a second shared pair: a C=O double bond completes both octets.
Step 5
Count the carbon's groups: the double bond plus two single bonds is three groups, no lone pair — trigonal planar.
Step 6
H₂CO is trigonal planar.
You can now draw the Lewis diagram of a molecule from its formula and classify its shape.
Your turn
On paper, draw the Lewis diagram of SiF₄ from its formula, then classify its shape. Then select Continue to compare your work with the model answer.
Model answer. Total: 4 + 4 × 7 = 32 valence electrons. Si central with four Si–F single bonds (8 electrons); the remaining 24 electrons sit as three lone pairs on each fluorine; no lone pair on the silicon. Four groups with no lone pair — SiF₄ is tetrahedral.
The electron total is 32, and every one of the 32 appears in the diagram.
Silicon is the central atom with four single bonds.
Each fluorine carries three lone pairs, drawn radially with the two dots equidistant.
The silicon holds no lone pair.
The shape call is tetrahedral — four groups, no lone pair.
Check your understanding
Starting from its formula, work out the shape of AsF₃. Arsenic is in Group 15 and fluorine is in Group 17.
ATrigonal pyramidalcorrect
BTrigonal planar
This option is wrong — you left the arsenic's lone pair out of your Lewis diagram — 26 valence electrons only fit with one lone pair on the arsenic, making four groups.
CTetrahedral
This option is wrong — you counted the arsenic's lone pair as a bonded atom — atoms sit at only three of its four positions.
DBent
This option is wrong — you gave the arsenic two lone pairs — the electron total leaves it exactly one.
Total the valence electrons: 5 + 3 × 7 = 26. Three As–F bonds use 6 electrons; 18 complete the fluorines' octets; the last 2 sit as one lone pair on the arsenic. Four groups with one lone pair is trigonal pyramidal.
Your turn
On paper, draw the Lewis diagram of H₂Se from its formula, then classify its shape. Selenium is in Group 16 and hydrogen has one valence electron. Then select Continue to compare your work with the model answer.
Model answer. Total: 2 × 1 + 6 = 8 valence electrons. Se central with two Se–H single bonds (4 electrons); the remaining 4 electrons sit as two lone pairs on the selenium. Four groups with two lone pairs — H₂Se is bent.
The electron total is 8, and all 8 appear in the diagram.
Selenium is the central atom with two single bonds — each hydrogen holds two electrons, its full count.
The selenium carries two lone pairs, drawn radially with the two dots equidistant.
The shape call is bent — four groups, two lone pairs.
Lesson 35 of 70 · CMB-035
Equal and unequal sharing
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Wonder this:
Two equally strong tug-of-war teams hold the rope's middle perfectly still. Mismatch the teams, and the rope slides toward the stronger side. Bonded atoms play the same game — over electrons.
You've already seen that elements differ in electronegativity — how strongly an atom pulls on shared electrons.
The idea
Every covalent bond is a tug of war over the shared electrons.
When the two atoms have the same electronegativity, they pull equally, and the sharing is equal.
Two atoms of the same element always have the same electronegativity, so the sharing in Cl–Cl is equal.
Equal pulls hold the shared pair in the middle; unequal pulls drag it toward the stronger puller.
When the two atoms have different electronegativities, the stronger puller drags the shared electrons its way, and the sharing is unequal.
Chlorine is more electronegative than hydrogen, so the sharing in H–Cl is unequal.
Classify the sharing in a covalent bond as equal when the two atoms have the same electronegativity, and as unequal when their electronegativities differ.
Worked examples
Worked example 1. Classify the sharing in the F–F bond of F₂.
Step 1
The two atoms are the same element, so they have the same electronegativity.
Step 2
Same electronegativity means equal pulls.
Step 3
The sharing in F–F is equal.
Worked example 2. Oxygen is more electronegative than hydrogen. Classify the sharing in the O–H bond.
Step 1
The two atoms have different electronegativities.
Step 2
Different electronegativities mean unequal pulls.
Step 3
The sharing in O–H is unequal.
You can now classify the sharing in a covalent bond as equal or unequal from whether the two atoms have the same or different electronegativity.
Check your understanding
In which bond is the sharing of electrons equal? Where the elements differ, the more electronegative atom is named in parentheses.
ABr–Brcorrect
BH–Br (bromine more electronegative)
This option is wrong — you treated two nonmetals as automatic equal sharers — the atoms' electronegativities differ, so the pulls differ and the sharing is unequal.
CN–H (nitrogen more electronegative)
This option is wrong — you overlooked the stated difference — different electronegativities always mean unequal sharing.
DC–F (fluorine more electronegative)
This option is wrong — you matched the two atoms by both being in a molecule — equal sharing needs equal electronegativity, and carbon and fluorine differ.
Equal sharing needs equal electronegativity. Only Br–Br joins two atoms of the same element, which always have the same electronegativity. Each of the other bonds joins atoms whose pulls differ, so their sharing is unequal.
Check your understanding
Nitrogen is more electronegative than hydrogen. In which bond is the sharing of electrons unequal?
AN–Hcorrect
BF–F
This option is wrong — you assumed the most electronegative element always wins electrons — here both atoms are fluorine, so their pulls are identical and the sharing is equal.
CI–I
This option is wrong — you picked a same-element bond — two iodine atoms pull identically, so the sharing is equal.
DH–H
This option is wrong — you picked a same-element bond — two hydrogen atoms pull identically, so the sharing is equal.
Unequal sharing needs different electronegativities. Nitrogen and hydrogen differ, so N–H shares unequally. The other three bonds each join two atoms of the same element — equal pulls, equal sharing.
Check your understanding
Sulfur and oxygen have different electronegativities — oxygen pulls shared electrons more strongly. What happens to the shared electrons in an S–O bond?
AThey stay shared, but the sharing is unequal.correct
BThey stay shared, and the sharing is equal.
This option is wrong — you ignored the stated difference in pull — different electronegativities always make the sharing unequal.
CThey transfer completely to the oxygen.
This option is wrong — you jumped to electron transfer — in a covalent bond the electrons remain shared; unequal pull shifts them, it does not hand them over.
DThey split up, one electron returning to each atom.
This option is wrong — you broke the bond — the shared pair stays between the atoms; the tug of war changes where it sits, not whether it is shared.
The bond is covalent, so the electrons stay shared. Sulfur and oxygen pull with different strengths. Different electronegativities mean the sharing is unequal.
Lesson 36 of 70 · CMB-036
Nonpolar and polar covalent bonds
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Did You Know?
You've already classified sharing as equal or unequal, and you've seen that a very large electronegativity difference — a metal with a nonmetal — means the electrons transfer and the bond is ionic. The covalent range in between has two named bands.
The idea
The size of the electronegativity difference sets the kind of covalent bond.
When the difference is zero or small, the sharing stays close to equal, and the bond is a 'nonpolar covalent bond'.
Cl–Cl has zero difference, so it is nonpolar covalent.
The bond type reads off the size of the electronegativity difference — no numbers needed at this level.
Carbon and hydrogen pull with almost the same strength, so C–H is also nonpolar covalent.
When the difference is larger, the stronger puller holds the shared electrons clearly closer, and the bond is a 'polar covalent bond'.
Chlorine pulls noticeably more strongly than hydrogen, so H–Cl is polar covalent.
When the difference is very large, as between a metal and a nonmetal, the electrons transfer completely and the bond is ionic, not covalent.
Worked examples
Worked example 1. Classify the Br–Br bond as nonpolar covalent, polar covalent, or ionic.
Step 1
The two atoms are the same element, so the electronegativity difference is zero.
Step 2
Zero or small difference means nonpolar covalent.
Step 3
Br–Br is a nonpolar covalent bond.
Worked example 2. Nitrogen pulls shared electrons noticeably more strongly than hydrogen. Classify the N–H bond.
Step 1
The two atoms are nonmetals, so the electrons are shared, and the bond is covalent.
Step 2
The difference in pull is noticeable, not zero or small.
Step 3
A larger difference means polar covalent.
Step 4
N–H is a polar covalent bond.
You can now classify a covalent bond as nonpolar when the electronegativity difference between its atoms is zero or small, and as polar when the difference is larger.
Check your understanding
Phosphorus and hydrogen pull shared electrons with almost the same strength. Classify the P–H bond.
AA nonpolar covalent bondcorrect
BA polar covalent bond
This option is wrong — you treated any two different elements as polar — when the pulls are almost the same, the sharing stays close to equal and the bond is nonpolar covalent.
CAn ionic bond
This option is wrong — you jumped to electron transfer — both atoms are nonmetals with almost matching pulls, so the electrons stay shared.
DNone of the above
This option is wrong — you looked for a category beyond the three bands — an almost-zero difference lands squarely in the nonpolar covalent band.
Read the difference: almost the same strength means a small difference. Zero or small difference means nonpolar covalent. P–H is a nonpolar covalent bond.
Check your understanding
Fluorine pulls shared electrons much more strongly than hydrogen, and both elements are nonmetals. Classify the H–F bond.
AA polar covalent bondcorrect
BA nonpolar covalent bond
This option is wrong — you ignored the stated gap in pull — a clearly larger difference moves the bond out of the nonpolar band.
CAn ionic bond
This option is wrong — you read 'much more strongly' as complete transfer — the ionic band belongs to metal-with-nonmetal pairs; two nonmetals keep sharing, unequally.
DNone of the above
This option is wrong — you looked for a fourth band — a shared pair held clearly closer to one atom is exactly what polar covalent names.
Both atoms are nonmetals, so the electrons are shared and the bond is covalent. The difference in pull is clearly larger than small. A larger difference means polar covalent, so H–F is polar covalent.
Check your understanding
Classify the I–I bond in iodine, I₂.
AA nonpolar covalent bondcorrect
BA polar covalent bond
This option is wrong — you expected a big element to hog the electrons — the two atoms are the same element, so the difference is zero and the sharing stays equal.
CAn ionic bond
This option is wrong — you treated the bond as a transfer — two identical nonmetal atoms share their pair; nothing transfers.
DNone of the above
This option is wrong — you looked past the obvious band — zero difference is the clearest nonpolar covalent case there is.
Same element on both ends means zero electronegativity difference. Zero or small difference means nonpolar covalent. I–I is a nonpolar covalent bond.
Lesson 37 of 70 · CMB-037
Partial charges
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Did You Know?
You've already classified H–Cl as a polar covalent bond: chlorine holds the shared electrons closer. That lopsidedness leaves marks on the two ends — and chemists label them.
The idea
In a polar covalent bond, the shared electrons sit closer to one atom, so the bond's two ends are no longer even.
The end holding the electrons closer gets a small extra share of negative charge.
A charge like this — far smaller than the full charge of an ion — is called a 'partial charge', written with the Greek letter delta, δ.
The more electronegative atom is labeled 'δ−', read 'delta minus'.
The other atom, left slightly short of electrons, is labeled 'δ+', read 'delta plus'.
The more electronegative atom carries δ−; the other atom carries δ+.
In H–Cl, chlorine is more electronegative, so the chlorine end is δ− and the hydrogen end is δ+.
The more electronegative atom of a polar covalent bond carries δ−, and the other atom carries δ+.
Worked examples
Worked example 1. Oxygen is more electronegative than hydrogen. Label the two atoms of the O–H bond with their partial charges.
Step 1
The more electronegative atom carries δ−: that is the oxygen.
Step 2
The other atom carries δ+: that is the hydrogen.
Step 3
O is δ− and H is δ+.
Worked example 2. Fluorine is more electronegative than carbon. Label the two atoms of the C–F bond with their partial charges.
Step 1
The more electronegative atom carries δ−: that is the fluorine.
Step 2
The other atom carries δ+: that is the carbon.
Step 3
F is δ− and C is δ+.
You can now identify which atom of a polar covalent bond carries the small negative charge, written δ−, and which carries the small positive charge, written δ+.
Check your understanding
Bromine is more electronegative than hydrogen. Which labels are correct for the H–Br bond?
ABr is δ−, H is δ+correct
BBr is δ+, H is δ−
This option is wrong — you swapped the labels — the MORE electronegative atom holds the electrons closer, so bromine's end is the negative one.
CBr is −1, H is +1
This option is wrong — you gave full ion charges — in a polar covalent bond the electrons stay shared, so the charges are partial: δ− and δ+.
DBoth atoms are δ−
This option is wrong — you charged both ends negative — the electrons that crowd one end must come from the other, which goes δ+.
Find the more electronegative atom: bromine. The more electronegative atom carries δ−, so Br is δ−. The other atom carries δ+, so H is δ+.
Check your understanding
Nitrogen is more electronegative than hydrogen. Which labels are correct for the N–H bond?
AN is δ−, H is δ+correct
BN is δ+, H is δ−
This option is wrong — you swapped the labels — nitrogen pulls the shared electrons closer, so nitrogen's end goes slightly negative.
CN is −1, H is +1
This option is wrong — you gave full ion charges — the electrons never transfer in a covalent bond, so the charges stay partial.
DBoth atoms are δ+
This option is wrong — you charged both ends positive — the end holding the electrons closer is negative, and only the other end is δ+.
Find the more electronegative atom: nitrogen. The more electronegative atom carries δ−, so N is δ−. The other atom carries δ+, so H is δ+.
Check your understanding
Chlorine is more electronegative than carbon. Which labels are correct for the C–Cl bond?
ACl is δ−, C is δ+correct
BCl is δ+, C is δ−
This option is wrong — you swapped the labels — chlorine is the stronger puller, so its end holds the electrons closer and goes δ−.
CCl is −1, C is +1
This option is wrong — you gave full ion charges — the shared pair shifts toward chlorine but never leaves the bond, so the charges are partial.
DBoth atoms are δ−
This option is wrong — you charged both ends negative — the extra electron share at one end is missing from the other end, which goes δ+.
Find the more electronegative atom: chlorine. The more electronegative atom carries δ−, so Cl is δ−. The other atom carries δ+, so C is δ+.
Lesson 38 of 70 · CMB-038
Why one end goes negative
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You've already labeled bond ends δ− and δ+. This lesson is the why behind the labels.
The idea
The labels come straight from where the shared electrons spend their time.
One end of a polar covalent bond is δ− because the more electronegative atom pulls the shared electrons closer to itself, leaving its end slightly negative and the other end slightly positive.
Electrons carry negative charge, so the end where they crowd turns slightly negative.
No electron ever leaves the bond — the shift is a lean, not a transfer.
In O–H, oxygen is more electronegative, so oxygen pulls the shared electrons closer, the oxygen end goes δ−, and the hydrogen end goes δ+.
Oxygen pulls the shared electrons closer, so the oxygen end turns slightly negative and the hydrogen end slightly positive.
Worked examples
Worked example 1. Fluorine is more electronegative than hydrogen. Explain why the fluorine end of the H–F bond is δ−.
Step 1
The more electronegative atom pulls the shared electrons closer to itself, leaving its end slightly negative and the other end slightly positive.
Step 2
Fluorine is the more electronegative atom here, so the shared electrons crowd the fluorine end.
Step 3
Electrons are negative, so the fluorine end goes δ− and the hydrogen end goes δ+.
Step 4
The fluorine end is δ− because fluorine pulls the shared electrons closer to itself.
Worked example 2. Oxygen is more electronegative than carbon. Explain why the carbon end of the C–O bond is δ+.
Step 1
The more electronegative atom pulls the shared electrons closer to itself, leaving its end slightly negative and the other end slightly positive.
Step 2
Oxygen wins the pull, so the shared electrons spend more time near the oxygen.
Step 3
The carbon end is left slightly short of electron charge, so it reads δ+.
Step 4
The carbon end is δ+ because the shared electrons it half-owns are pulled toward the oxygen, leaving carbon's end slightly positive.
You can now explain why one end of a polar covalent bond is δ−, because the more electronegative atom pulls the shared electrons closer to itself, leaving its end slightly negative and the other end slightly positive.
Check your understanding
Bromine is more electronegative than hydrogen. Why is the bromine end of the H–Br bond δ−?
ABecause the more electronegative atom pulls the shared electrons closer to itself, leaving its end slightly negative and the other end slightly positive.correct
BBecause the bromine takes one electron completely away from the hydrogen, gaining a full negative charge.
This option is wrong — you turned the lean into a transfer — the shared electrons stay in the bond; they only sit closer to the bromine.
CBecause the hydrogen's proton moves across to the bromine.
This option is wrong — you moved the nucleus instead of the electrons — the atoms stay put; it is the shared ELECTRONS that shift toward the stronger puller.
DBecause bromine's own lone pairs make its end negative all by themselves, while the shared pair stays exactly centered between the two atoms.
This option is wrong — you credited the wrong electrons — the partial charges come from the SHARED pair shifting, not from lone pairs that were already there.
Ask which atom pulls the shared electrons more strongly: the bromine. The more electronegative atom pulls the shared electrons closer to itself, leaving its end slightly negative and the other end slightly positive. So the bromine end reads δ− and the hydrogen end reads δ+.
Check your understanding
Fluorine is more electronegative than chlorine. Why is the fluorine end of the Cl–F bond δ−?
ABecause the more electronegative atom pulls the shared electrons closer to itself, leaving its end slightly negative and the other end slightly positive.correct
BBecause the chlorine hands its shared electron over to the fluorine for keeps, giving the fluorine a whole extra electron of its own.
This option is wrong — you made the bond ionic — nothing is handed over; the shared pair leans toward the fluorine while staying shared.
CBecause fluorine atoms always carry a full 1− charge in every compound they form, whatever the partner atom.
This option is wrong — you gave fluorine an ion's charge — in a covalent bond fluorine gains only a partial charge, from holding the shared electrons closer.
DBecause the fluorine end is heavier, and heavier ends turn negative.
This option is wrong — you used mass — the negative end is set by pull on the shared electrons, not by weight, and here chlorine is the heavier atom anyway.
Fluorine out-pulls chlorine for the shared electrons. The more electronegative atom pulls the shared electrons closer to itself, leaving its end slightly negative and the other end slightly positive. So F reads δ− and Cl reads δ+.
Check your understanding
Chlorine is more electronegative than phosphorus. What happens to the shared electrons in a P–Cl bond, and what follows for the two ends?
AThey shift closer to the chlorine while staying shared, so the chlorine end goes slightly negative and the phosphorus end slightly positive.correct
BThey transfer to the chlorine completely, so the chlorine becomes a Cl⁻ ion.
This option is wrong — you turned unequal sharing into transfer — a full transfer is the ionic case; here the pair leans toward chlorine and stays shared.
CThey stay exactly centered, so neither end carries any charge.
This option is wrong — you erased the stated difference in pull — with chlorine pulling harder, the pair sits off-center, and the ends pick up partial charges.
DThey shift toward the phosphorus while staying shared, because the larger atom always attracts the electrons more strongly.
This option is wrong — you let size decide — the shared electrons move toward the stronger PULLER, and chlorine is the more electronegative atom.
Chlorine pulls the shared electrons more strongly than phosphorus. The more electronegative atom pulls the shared electrons closer to itself, leaving its end slightly negative and the other end slightly positive. The lean is partial: the electrons never leave the bond.
Lesson 39 of 70 · CMB-039
Polar and nonpolar molecules
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Did You Know?
Wonder this:
Rub a balloon on your hair and hold it beside a thin stream of tap water: the stream bends toward the balloon. Why would water care about a charged balloon? Because some molecules have charged ends of their own.
You've already labeled bond ends δ− and δ+. Whole molecules can have ends like that too — or fail to.
The idea
A molecule with a slightly positive end and a slightly negative end is a 'polar molecule'.
A molecule with no such ends is a 'nonpolar molecule'.
Two things together decide which a molecule is: its bond polarities and its shape.
A molecule is polar only when its bonds are polar AND its shape does not cancel their pulls.
CO₂'s two bonds are polar, but its shape cancels their pulls, so CO₂ is nonpolar.
H₂O's two bonds are polar and its bent shape does not cancel their pulls, so H₂O is polar.
Bond polarity and shape together decide: same polar bonds, different shapes, opposite verdicts.
A molecule with no polar bonds is nonpolar, whatever its shape.
Worked examples
Worked example 1. What two features of a molecule together decide whether it is polar?
Step 1
Answer: its bond polarities and its shape.
Worked example 2. A molecule contains no polar bonds. What does that alone tell you about the molecule's polarity?
Step 1
Answer: it is nonpolar, whatever its shape.
You can now state that a whole molecule is polar only when its bonds are polar and the molecular shape does not cancel their pulls, so bond polarity and shape together decide.
Check your understanding
When is a whole molecule polar?
AOnly when its bonds are polar and its shape does not cancel their pulls.correct
BWhenever it contains at least one polar bond.
This option is wrong — you used bonds alone — a molecule's shape can cancel its polar bonds' pulls, leaving the molecule nonpolar.
CWhenever its shape is bent, whatever its bonds are like.
This option is wrong — you used shape alone — with no polar bonds there are no pulls for any shape to leave uncancelled.
DWhenever it contains oxygen, nitrogen, or fluorine.
This option is wrong — you used an element checklist — polarity comes from bond polarity plus shape, not from which elements appear.
Two things decide together: bond polarities and shape. A molecule is polar only when its bonds are polar AND its shape does not cancel their pulls. Either polar bonds without cancellation-proof shape, or shape without polar bonds, is not enough on its own.
Check your understanding
Four molecules are described. Which one is polar?
AA molecule whose bonds are polar and whose shape does not cancel their pulls.correct
BA molecule whose bonds are polar and whose shape cancels their pulls exactly.
This option is wrong — you stopped at the polar bonds — when the shape cancels the pulls, no end of the molecule is charged, so it is nonpolar.
CA molecule with no polar bonds and a bent shape.
This option is wrong — you let the shape act alone — with no polar bonds there are no pulls, so even a bent molecule is nonpolar.
DA molecule with no polar bonds and a straight-line shape.
This option is wrong — you had neither ingredient — no polar bonds means nonpolar, whatever the shape.
Check both ingredients in each description. Polar needs BOTH: polar bonds AND a shape that does not cancel their pulls. Only the first description has both.
Check your understanding
A molecule has no polar bonds. Which statement about it is correct?
AIt is nonpolar, whatever its shape.correct
BIt is polar if its shape is bent.
This option is wrong — you let shape create polarity — shape can only fail to cancel pulls that exist, and this molecule's bonds supply none.
CIt is polar if it contains lone pairs.
This option is wrong — you swapped in lone pairs — the two deciding features are bond polarity and shape, and the bonds here are not polar.
DIts polarity cannot be judged until its shape is known.
This option is wrong — you waited for information you do not need — with no polar bonds there is nothing for any shape to leave uncancelled.
Start with the bonds: none is polar. A molecule with no polar bonds is nonpolar, whatever its shape. Shape only matters when there are polar-bond pulls to cancel or not cancel.
Lesson 40 of 70 · CMB-040
Why symmetric molecules cancel
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Did You Know?
You've already seen the claim: CO₂ has polar bonds yet is a nonpolar molecule. This lesson shows the cancellation doing it.
The idea
Oxygen pulls shared electrons more strongly than carbon, so each C=O bond in CO₂ has a pull toward its oxygen.
The two pulls are equally strong, and the linear shape points them in exactly opposite directions.
A symmetric molecule with identical polar bonds is nonpolar because equal pulls in opposite directions cancel, leaving no overall pull.
Two equal pulls in exactly opposite directions cancel, leaving no overall pull — so CO₂ has no charged ends.
It is the tug of war between equal teams: the rope's middle never moves.
With no overall pull, no end of CO₂ builds up charge, so the molecule is nonpolar.
Break the symmetry — bend the shape or change one of the outer atoms — and the pulls no longer cancel.
Worked examples
Worked example 1. Each C–Cl bond in CCl₄ is polar, with the pull toward the chlorine. Explain why the CCl₄ molecule is nonpolar.
Step 1
The four pulls are identical, and the tetrahedral shape spreads them evenly in all directions.
Step 2
Equal pulls in opposite directions cancel, leaving no overall pull.
Step 3
With no overall pull, no end of the molecule builds up charge.
Step 4
CCl₄ is nonpolar because its four identical pulls cancel, leaving no overall pull.
Worked example 2. Each S–H bond in bent H₂S is slightly polar, with the pull toward the sulfur. Explain why the two pulls do NOT cancel.
Step 1
Cancellation needs equal pulls in opposite directions.
Step 2
In a bent molecule the two bonds point along a V, so their pulls are angled, not opposite.
Step 3
Two angled pulls add up to one overall pull toward the sulfur side.
Step 4
The pulls do not cancel because they are not in opposite directions — H₂S keeps an overall pull and is polar.
You can now explain why a symmetric molecule with identical polar bonds is nonpolar, because equal pulls in opposite directions cancel, leaving no overall pull.
Check your understanding
Each C–F bond in tetrahedral CF₄ is polar, with the pull toward the fluorine. Why is the CF₄ molecule nonpolar?
ABecause equal pulls in opposite directions cancel, leaving no overall pull.correct
BBecause the C–F bonds are actually nonpolar.
This option is wrong — you denied the premise — each C–F bond IS polar; it is the symmetric arrangement of the four equal pulls that cancels them.
CBecause fluorine's pulls are too weak to charge the molecule's ends.
This option is wrong — you made the pulls weak — they are strong, and they still cancel because they are equal and oppositely arranged.
DBecause the lone pairs on the fluorines soak up the bond pulls.
This option is wrong — you gave the outer lone pairs a cancelling job — the cancellation is between the four bond pulls themselves.
Each of the four identical pulls points from the carbon out toward a fluorine. The tetrahedral shape arranges them evenly, and equal pulls in opposite directions cancel, leaving no overall pull. No overall pull means no charged ends: CF₄ is nonpolar.
Check your understanding
Each O–F bond in bent OF₂ is polar, and the two pulls are equally strong. Why do they fail to cancel?
ABecause they are not in opposite directions — only equal pulls in opposite directions cancel, leaving no overall pull.correct
BBecause two pulls can never cancel each other, no matter how they are arranged around the molecule.
This option is wrong — you ruled out cancellation entirely — two equal pulls DO cancel when they point in exactly opposite directions, as in a linear molecule.
CBecause the two pulls differ in strength.
This option is wrong — you blamed unequal strength — the stem says the pulls are equal; the failure is direction: a bent V never points them opposite ways.
DBecause fluorine atoms refuse to share their pull with oxygen, keeping the tug entirely on their own side.
This option is wrong — you made cancellation a property of the atoms — it is geometry: angled pulls add up instead of cancelling.
Cancellation has two requirements: equal strength AND opposite directions. The bent shape angles the two pulls along a V, so they are not opposite. Angled pulls add into one overall pull — OF₂ keeps charged ends.
Check your understanding
Each Ge–Cl bond in tetrahedral GeCl₄ is polar. A tug of war is a good model for what happens overall in this molecule. Which version of the game matches?
AEqually strong teams pulling in balanced directions — the middle never moves, and no overall pull remains.correct
BOne team stronger than the rest — the middle slides toward it.
This option is wrong — you unbalanced the teams — the four Ge–Cl pulls are identical, so no direction wins.
CAll teams pulling the same way — the middle races off in that direction, dragged by the combined pull.
This option is wrong — you pointed the pulls together — the tetrahedral shape spreads them apart evenly, not side by side.
DNo teams at all — nothing pulls in any direction.
This option is wrong — you removed the pulls — each polar bond really does pull; the pulls exist and cancel.
Four identical pulls, spread evenly by the tetrahedral shape. Equal pulls in opposite directions cancel, leaving no overall pull. Pulls that exist but cancel: that is GeCl₄, and the molecule is nonpolar.
Lesson 41 of 70 · CMB-041
Classifying molecular polarity
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Did You Know?
You've already seen both ingredients — polar bonds and shape — and why symmetric shapes cancel. Now you run the full classification on any small molecule.
The idea
First ask: does the molecule have any polar bonds?
If none of its bonds is polar, the molecule is nonpolar — stop there.
If it has polar bonds, ask next: does the shape cancel their pulls?
Identical polar bonds arranged symmetrically — a linear molecule with two identical ends, or a tetrahedral molecule with four identical outer atoms — cancel, and the molecule is nonpolar.
In a bent or trigonal pyramidal molecule the pulls are angled, so they do not cancel, and the molecule is polar.
The polarity decision
Bonds
Shape and outer atoms
Verdict
no polar bonds
any shape
nonpolar
identical polar bonds
linear with two identical ends, or tetrahedral with identical outer atoms
nonpolar — pulls cancel
polar bonds
bent or trigonal pyramidal
polar — pulls angled, not cancelled
polar bonds
outer atoms differ
polar — pulls unequal, not cancelled
Run the two questions in order: polar bonds first, then whether the shape cancels their pulls.
Polar bonds whose outer atoms differ give unequal pulls, so they do not cancel, and the molecule is polar.
Take H₂O: oxygen out-pulls hydrogen, so its bonds are polar, and the bent shape does not cancel the pulls — H₂O is a polar molecule.
Worked examples
Worked example 1. Nitrogen pulls shared electrons more strongly than hydrogen, and NH₃ is trigonal pyramidal. Classify NH₃ as polar or nonpolar.
Step 1
Polar bonds? Yes — nitrogen and hydrogen pull unequally, so each N–H bond is polar.
Step 2
Does the shape cancel the pulls? No — in a trigonal pyramidal molecule the three pulls are angled toward the nitrogen's side, not opposite.
Step 3
Polar bonds plus uncancelled pulls means polar.
Step 4
NH₃ is a polar molecule.
Worked example 2. Fluorine pulls shared electrons more strongly than silicon, and SiF₄ is tetrahedral with four identical Si–F bonds. Classify SiF₄ as polar or nonpolar.
Step 1
Polar bonds? Yes — each Si–F bond is polar.
Step 2
Does the shape cancel the pulls? Yes — four identical pulls arranged tetrahedrally cancel.
Step 3
Polar bonds whose pulls cancel means nonpolar.
Step 4
SiF₄ is a nonpolar molecule.
You can now classify a small molecule as polar or nonpolar from its shape and its bond polarities.
Check your understanding
Fluorine pulls shared electrons much more strongly than hydrogen. Which of these molecules is polar?
AHFcorrect
BF₂
This option is wrong — you expected the most electronegative element to make any molecule polar — F₂'s two identical atoms pull equally, so its bond has no pull to leave uncancelled.
CBr₂
This option is wrong — you skipped the first question — a same-element bond is nonpolar, so the molecule has no polar bond and is nonpolar.
DI₂
This option is wrong — you treated a big heavy molecule as polar — polarity needs a polar bond, and two identical iodine atoms share equally.
First question: any polar bonds? Only HF has one — its two atoms pull unequally. Second question: does the shape cancel the pull? A two-atom molecule has one pull and nothing to cancel it. HF keeps a δ+ end and a δ− end, so HF is polar.
Check your understanding
Each of these molecules contains polar bonds, except one — and that one is nonpolar for exactly that reason. Which is the nonpolar molecule? (Chlorine out-pulls hydrogen and sulfur; oxygen out-pulls hydrogen.)
ACH₄correct
BH₂S (bent)
This option is wrong — you cancelled a bent molecule's pulls — its two angled pulls add up, so H₂S is polar.
CHCl
This option is wrong — you found no partner to cancel HCl's single pull because there is none — one uncancelled polar bond makes the molecule polar.
DCl₂O (bent)
This option is wrong — you treated the two identical O–Cl pulls as cancelling — in a bent shape they are angled, not opposite, so the molecule is polar.
Run question one on each molecule: does it have polar bonds? C–H pulls are almost equal, so CH₄ has no polar bonds — nonpolar, whatever its shape. The other three all carry polar bonds with uncancelled pulls, so they are polar.
Check your understanding
Chlorine pulls shared electrons more strongly than sulfur and more strongly than silicon. Which of these molecules is polar?
ASCl₂ (bent)correct
BSiCl₄ (tetrahedral)
This option is wrong — you stopped after finding polar bonds — SiCl₄'s four identical pulls are arranged symmetrically, and equal pulls in opposite directions cancel.
CCl₂
This option is wrong — you gave a same-element molecule a polar bond — two chlorines pull equally, so Cl₂ is nonpolar.
DN₂
This option is wrong — you read the triple bond as polarity — bond multiplicity is not polarity, and two identical nitrogen atoms share equally.
SCl₂ has polar bonds — chlorine out-pulls sulfur. Its bent shape angles the two pulls, so they do not cancel. Polar bonds plus uncancelled pulls: SCl₂ is polar. The other three fail question one or cancel at question two.
Rain on a waxed car hood gathers itself into round beads. Something is pulling water molecules toward each other — and it is not the same something that holds each molecule's three atoms together.
You've already seen what holds a molecule's atoms together: covalent bonds, where both nuclei attract the same shared electrons. Liquids reveal a second attraction.
The idea
Liquid water holds together in two different ways at once.
Within each molecule, covalent bonds hold the three atoms together — the two O–H bonds.
A force acting within one molecule is an 'intramolecular force' — intra means within.
Solid lines: bonds within a molecule (intramolecular). Dashed line: attraction between molecules (intermolecular).
Between neighboring molecules there is a second, separate attraction, holding molecule to molecule.
A force acting between neighboring molecules is an 'intermolecular force' — inter means between.
To classify an attraction, ask one question: does it act within one molecule, or between two molecules?
The O–H bond inside a water molecule is intramolecular; the attraction pulling two neighboring water molecules together is intermolecular.
Worked examples
Worked example 1. Liquid bromine is made of Br₂ molecules. Classify the Br–Br bond inside one molecule as intramolecular or intermolecular.
Step 1
Ask the question: does the attraction act within one molecule, or between two?
Step 2
The Br–Br bond joins the two atoms of a single Br₂ molecule — it acts within one molecule.
Step 3
The Br–Br bond is an intramolecular force.
Worked example 2. In liquid ammonia, each NH₃ molecule is attracted to the NH₃ molecules around it. Classify that attraction.
Step 1
Ask the question: does the attraction act within one molecule, or between two?
Step 2
This attraction acts between one NH₃ molecule and its neighbors — between molecules.
Step 3
The attraction between neighboring NH₃ molecules is an intermolecular force.
You can now classify a supplied attraction as a covalent bond within a molecule, called an intramolecular force, or an attraction between neighboring molecules, called an intermolecular force.
Check your understanding
Liquid HBr contains H–Br bonds within its molecules and attractions between neighboring molecules. Which classification pairs them correctly?
AThe H–Br bond is intramolecular; the attraction between neighboring molecules is intermolecular.correct
BThe H–Br bond is intermolecular; the attraction between neighboring molecules is intramolecular.
This option is wrong — you swapped the prefixes — intra means within one molecule, inter means between molecules.
CBoth are intramolecular, because both act inside the liquid.
This option is wrong — you treated the whole liquid as one molecule — each HBr molecule is a separate unit, and the attraction linking two units acts between molecules.
DBoth are intermolecular, because both involve attraction.
This option is wrong — you classified by 'attraction' alone — the classifying question is WHERE the attraction acts: the bond acts within one molecule.
Ask the one question for each attraction: within one molecule, or between two? The H–Br bond joins the atoms of a single molecule — intramolecular. The neighbor-to-neighbor attraction acts between molecules — intermolecular.
Check your understanding
Which of these is an intermolecular force?
AThe attraction between two neighboring HF molecules.correct
BThe H–F bond within one HF molecule.
This option is wrong — you picked a covalent bond — it joins atoms inside a single molecule, which is intramolecular.
CA C–H bond within one CH₄ molecule.
This option is wrong — you picked a bond inside one molecule — any force within a single molecule is intramolecular.
DThe double bond within one O₂ molecule.
This option is wrong — you read the double bond's extra lines as something between molecules — both shared pairs sit within the one O₂ molecule.
Intermolecular means between molecules. Only the neighbor-to-neighbor HF attraction acts between two separate molecules. Every bond listed — single or double — acts within one molecule, so those are intramolecular.
Check your understanding
Solid carbon dioxide contains C=O bonds within each CO₂ molecule and attractions between neighboring CO₂ molecules. Which classification pairs them correctly?
AThe C=O bonds are intramolecular; the attractions between neighboring molecules are intermolecular.correct
BThe C=O bonds are intermolecular; the attractions between neighboring molecules are intramolecular.
This option is wrong — you swapped the prefixes — the bonds act within one molecule (intra), the neighbor attractions act between molecules (inter).
CBoth are intramolecular, because in a solid all the particles lock into one unit.
This option is wrong — you merged the solid into one molecule — solid CO₂ is still made of separate CO₂ molecules, and the attractions linking them act between molecules.
DBoth are intermolecular, because a double bond spans two atoms.
This option is wrong — you counted atoms instead of molecules — the two atoms of a C=O bond belong to the SAME molecule, so the bond is intramolecular.
The state of matter does not change the question: within one molecule, or between two? Each C=O bond joins atoms of a single CO₂ molecule — intramolecular. The attractions holding neighboring molecules in the solid act between molecules — intermolecular.
Lesson 43 of 70 · CMB-043
How strong are intermolecular forces
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You've already seen the two kinds of attraction in a molecular substance: covalent bonds within each molecule, and intermolecular forces between neighboring molecules. One fact about their strengths runs the rest of this unit.
The idea
Intermolecular forces are much weaker than covalent bonds.
Inside one water molecule, two strong covalent O–H bonds hold the three atoms together.
Between one water molecule and its neighbor acts only a weak attraction — far weaker than either O–H bond.
Two water molecules. The covalent O–H bonds within each molecule (thick solid lines) are much stronger than the attraction between the molecules (thin dashed line).
Separating two neighboring molecules therefore takes far less energy than breaking a covalent bond.
Worked examples
Worked example 1. Which is stronger: the H–Cl covalent bond inside a hydrogen chloride molecule, or the attraction between two neighboring HCl molecules?
Step 1
Answer: the H–Cl covalent bond — intermolecular forces are much weaker than covalent bonds.
Worked example 2. In liquid ammonia, compare the strength of an N–H bond within one NH₃ molecule with the attraction between two NH₃ molecules.
Step 1
Answer: the N–H bond is much stronger — the attraction between the two molecules is an intermolecular force, and intermolecular forces are much weaker than covalent bonds.
You can now state that intermolecular forces are much weaker than covalent bonds.
Check your understanding
Inside a methane molecule, covalent C–H bonds hold each hydrogen atom to the carbon. A weak attraction acts between neighboring CH₄ molecules. Which comparison of the two strengths is correct?
AThe C–H bond is much stronger than the attraction between neighboring molecules.correct
BThe C–H bond is much weaker than the attraction between neighboring molecules.
This option is wrong — you flipped the comparison — intermolecular forces are much weaker than covalent bonds, not stronger.
CThe two attractions are about equal in strength.
This option is wrong — you leveled the two forces — the difference is large: the covalent bond is much stronger.
DThe attraction between the molecules is itself a covalent bond, so no comparison can be made.
This option is wrong — you merged the two kinds of force — the attraction between molecules is an intermolecular force, a different and much weaker attraction than a covalent bond.
Two kinds of attraction: covalent C–H bonds within each CH₄ molecule, and an intermolecular force between neighboring molecules. Intermolecular forces are much weaker than covalent bonds. So the C–H bond is much stronger than the attraction between the molecules.
Check your understanding
Which takes more energy: breaking the Br–Br covalent bond inside one bromine molecule, or pulling two neighboring Br₂ molecules apart from each other?
ABreaking the Br–Br bond takes much more energy.correct
BPulling the two neighboring molecules apart takes much more energy.
This option is wrong — you flipped the comparison — the attraction between molecules is much weaker than the covalent bond, so it takes much less energy to overcome.
CThe two changes take the same energy.
This option is wrong — you leveled the two forces — separating neighboring molecules takes far less energy than breaking a covalent bond.
DThe two molecules cannot be pulled apart without also breaking their Br–Br bonds.
This option is wrong — you chained the two changes together — neighboring molecules separate while every covalent bond inside them stays intact.
The Br–Br bond is a covalent bond within a molecule; the attraction between two Br₂ molecules is an intermolecular force. Intermolecular forces are much weaker than covalent bonds. So breaking the bond takes much more energy than separating the neighbors.
Check your understanding
Which statement about any molecular substance is correct?
AThe attractions between its molecules are much weaker than the covalent bonds within them.correct
BThe attractions between its molecules are much stronger than the covalent bonds within them.
This option is wrong — you flipped the comparison — intermolecular forces are much weaker than covalent bonds.
CThe attractions between its molecules and the bonds within them are equally strong, because both involve electrons.
This option is wrong — you reasoned from a shared ingredient to equal strength — both involve electrons, but the attraction between molecules is much weaker.
DOnly the covalent bonds are real forces; nothing at all acts between separate molecules.
This option is wrong — you erased the intermolecular forces — neighboring molecules do attract each other, just much more weakly than bonded atoms do.
Every molecular substance holds both kinds of attraction. Intermolecular forces are much weaker than covalent bonds. Weaker — but real: neighboring molecules do attract one another.
Lesson 44 of 70 · CMB-044
What melting and boiling break
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Did You Know?
You've already seen that the attractions between molecules are much weaker than the covalent bonds within them. That raises a practical question: when a molecular substance melts or boils, what actually comes apart?
The idea
When a molecular substance melts or boils, its molecules separate from one another.
Each molecule stays intact — no covalent bond inside any molecule breaks.
Steam is made of complete H₂O molecules — exactly the same molecules that made up the liquid water.
A change of state rearranges whole molecules; it never takes molecules apart.
Boiling separates whole H₂O molecules from one another. Every molecule in the steam is complete — no O–H bond has broken.
Worked examples
Worked example 1. Liquid bromine boils at 59 °C. What particles make up the bromine gas?
Step 1
Answer: complete Br₂ molecules — the same molecules that made up the liquid.
Worked example 2. Solid carbon dioxide (dry ice) turns straight into a gas as it warms. What particles make up that gas?
Step 1
Answer: intact CO₂ molecules — the change of state separated the molecules without breaking any C=O bond.
You can now state that when a molecular substance melts or boils, the molecules separate from one another but each molecule stays intact.
Check your understanding
Liquid ammonia boils at −33 °C. What does the gas that forms consist of?
AComplete NH₃ molecules.correct
BSeparate nitrogen and hydrogen atoms.
This option is wrong — you broke the covalent bonds — boiling separates molecules from one another; every N–H bond survives.
CN₂ and H₂ molecules.
This option is wrong — you turned a change of state into a chemical change — boiling rearranges whole molecules; it does not regroup their atoms into new substances.
DNH₃ molecules that have each lost one hydrogen.
This option is wrong — you let boiling nibble at the molecules — each molecule stays fully intact; no bond inside any molecule breaks.
Boiling separates a molecular substance's molecules from one another. Each molecule stays intact — no covalent bond breaks. So ammonia gas is complete NH₃ molecules, the same molecules that made up the liquid.
Check your understanding
When solid methane melts, what happens to its CH₄ molecules?
AThey separate from one another, and each molecule stays intact.correct
BEach molecule breaks into one carbon atom and four hydrogen atoms.
This option is wrong — you broke the covalent bonds — melting separates molecules from one another; the C–H bonds all survive.
CThe C–H bonds break and the atoms regroup into larger molecules.
This option is wrong — you turned melting into a chemical change — a change of state rearranges whole molecules, never their atoms.
DNothing separates — the molecules simply get hotter while staying locked in place.
This option is wrong — you kept the solid's structure — melting frees the molecules from their fixed positions; they separate from one another.
Melting, like boiling, separates whole molecules from one another. Each CH₄ molecule stays intact. The same molecules that built the solid now slide past each other in the liquid.
Check your understanding
Solid iodine is made of I₂ molecules. Warmed gently, it turns straight into a purple vapor. What particles make up the vapor?
AIntact I₂ molecules.correct
BSeparate iodine atoms.
This option is wrong — you broke the I–I bonds — the change of state separates I₂ molecules from one another and leaves every bond intact.
CI₄ molecules formed as pairs of molecules stick together.
This option is wrong — you fused molecules — a change of state neither joins molecules into bigger ones nor splits them.
DA mixture of single iodine atoms and I₂ molecules.
This option is wrong — you let some bonds break — none do; every particle in the vapor is a complete I₂ molecule.
A change of state rearranges whole molecules; it never takes molecules apart. The purple vapor is intact I₂ molecules. They are the same molecules that made up the solid — just separated from one another.
Lesson 45 of 70 · CMB-045
Why molecules survive boiling
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Did You Know?
You've already seen two facts: intermolecular forces are much weaker than covalent bonds, and melting or boiling separates molecules without breaking them. Put together, the first fact explains the second.
The idea
Heating a molecular substance strains both kinds of attraction at once — the bonds within molecules and the attractions between them.
Heating separates the molecules without breaking them apart, because the attractions between molecules are much weaker than the bonds within them, so the attractions between molecules give way first.
Boiling water therefore produces H₂O molecules — not hydrogen and oxygen.
The weaker attachment always fails first, the way a sticky note peels off a page long before the page itself tears.
Worked examples
Worked example 1. Methane boils at −162 °C, and the gas is intact CH₄ molecules. Explain why boiling does not break the C–H bonds.
Step 1
Two attractions compete: the weak attractions between CH₄ molecules, and the strong C–H bonds within each molecule.
Step 2
The attractions between molecules are much weaker than the bonds within them, so the attractions between molecules give way first.
Step 3
Boiling overcomes only the attractions between CH₄ molecules — every C–H bond survives, so the gas is intact CH₄ molecules.
Worked example 2. When solid bromine melts at −7 °C, why does every Br₂ molecule stay in one piece?
Step 1
Melting must overcome one of the two attractions: the attraction between Br₂ molecules, or the Br–Br bond within each.
Step 2
The attractions between molecules are much weaker than the bonds within them, so the attractions between molecules give way first.
Step 3
The molecules break loose from one another while each Br–Br bond holds — the liquid is intact Br₂ molecules.
You can now explain why heating a molecular substance separates its molecules without breaking them apart, because the attractions between molecules are much weaker than the bonds within them, so the attractions between molecules give way first.
Check your understanding
Liquid nitrogen boils at −196 °C, producing a gas of intact N₂ molecules. Why does boiling separate the molecules without breaking the strong N≡N bonds?
ABecause the attractions between molecules are much weaker than the bonds within them, so the attractions between molecules give way first.correct
BBecause the N≡N bond becomes stronger as the liquid heats up, protecting it from breaking.
This option is wrong — you invented a heat-hardened bond — the bond's strength does not change; it survives because the far weaker attractions between molecules fail first.
CBecause the attractions between molecules are stronger than the bonds, and the stronger attraction always breaks first.
This option is wrong — you flipped both the strengths and the rule — the attractions between molecules are the WEAKER ones, and it is the weaker attachment that gives way first.
DBecause boiling adds no energy to the molecules, so nothing can break at all.
This option is wrong — you removed the energy — boiling does supply energy, and that energy overcomes the weak attractions between molecules while leaving the bonds intact.
Two attractions compete when a molecular substance is heated. The attractions between molecules are much weaker than the bonds within them, so the attractions between molecules give way first. That is why the gas is intact N₂ molecules.
Check your understanding
When solid hydrogen chloride melts, its molecules separate but every H–Cl bond survives. Which attraction gave way, and why that one?
AThe attractions between HCl molecules — they are much weaker than the bonds within the molecules, so they give way first.correct
BThe H–Cl bonds gave way — the bonds within molecules always fail before the attractions between the molecules do.
This option is wrong — you flipped the order of failure — the bonds are the much stronger attachment, so the weak attractions between molecules give way first.
CBoth gave way equally, because heat strains every attraction by the same amount.
This option is wrong — you shared the failure out evenly — heat strains both, but only the much weaker attractions between molecules actually give way.
DNeither gave way — melting rearranges molecules without overcoming any attraction.
This option is wrong — you made melting free — separating molecules from their neighbors means overcoming the attractions between them.
Melting separates molecules from one another. The attractions between molecules are much weaker than the bonds within them, so the attractions between molecules give way first. Every H–Cl bond therefore survives the melt.
Check your understanding
Ethanol boils at 78 °C. What does the vapor consist of, and why?
AIntact ethanol molecules — the weaker attractions between molecules give way before the stronger bonds within them.correct
BFragments of ethanol molecules — heat splits each molecule at its weakest bond.
This option is wrong — you sent the heat into the bonds — the attractions BETWEEN molecules are far weaker than any bond, so they fail first and the molecules stay whole.
CCarbon, hydrogen, and oxygen atoms — boiling reduces a substance to its elements.
This option is wrong — you turned boiling into decomposition — a change of state overcomes only the attractions between molecules.
DIntact ethanol molecules — but only because ethanol's covalent bonds happen to be unbreakable.
This option is wrong — you credited the right result to an unbreakable bond — the bonds can break with enough energy; they survive boiling because the weaker attractions between molecules give way first.
Boiling must overcome one of the two attractions. The attractions between molecules are much weaker than the bonds within them, so the attractions between molecules give way first. The vapor is therefore intact ethanol molecules.
Lesson 46 of 70 · CMB-046
Dispersion forces
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Did You Know?
Wonder this:
Nitrogen is nonpolar: no δ+ end, no δ− end — nothing, it seems, for a neighboring molecule to grab. Yet cool nitrogen to −196 °C and it turns into a liquid, its molecules clinging to one another. Some attraction must act even between nonpolar molecules.
That attraction is real, it is everywhere, and it has a name.
The idea
All molecules attract their neighbors through a weak attraction called the 'dispersion force'.
The dispersion force acts even between nonpolar molecules.
N₂ molecules attract one another through dispersion forces — that attraction is what holds liquid nitrogen together.
No molecule is exempt: polar or nonpolar, every molecule exerts dispersion forces on its neighbors.
Worked examples
Worked example 1. Methane, CH₄, is nonpolar. What attraction acts between CH₄ molecules?
Step 1
Answer: dispersion forces — the weak attraction that acts between all molecules.
Worked example 2. What attraction lets nonpolar Cl₂ molecules cling together as a liquid at −34 °C?
Step 1
Answer: dispersion forces.
You can now state that all molecules attract their neighbors through a weak attraction called the dispersion force, which acts even between nonpolar molecules.
Check your understanding
Carbon dioxide is a nonpolar molecular substance. What attraction acts between CO₂ molecules?
ADispersion forces.correct
BNo attraction at all.
This option is wrong — you gave nonpolar molecules nothing to attract with — all molecules attract their neighbors through dispersion forces.
CCovalent bonds between the molecules.
This option is wrong — you put covalent bonds between molecules — covalent bonds act within a molecule; between molecules acts the much weaker dispersion force.
DAttraction between permanent δ+ and δ− ends.
This option is wrong — you gave a nonpolar molecule permanent charged ends — CO₂ has none; its attraction is the dispersion force.
All molecules attract their neighbors through dispersion forces. That includes nonpolar molecules like CO₂. The attraction is weak, but it is there.
Check your understanding
Between which molecules do dispersion forces act?
AAll molecules, polar and nonpolar alike.correct
BOnly nonpolar molecules.
This option is wrong — you fenced dispersion off from polar molecules — every molecule exerts dispersion forces on its neighbors, polar ones included.
COnly polar molecules.
This option is wrong — you attached dispersion to polarity — dispersion forces act even between nonpolar molecules, and between all others too.
DOnly molecules that are touching in a solid.
This option is wrong — you restricted dispersion to solids — neighboring molecules attract in liquids and gases as well.
All molecules attract their neighbors through dispersion forces. No molecule is exempt: polar or nonpolar, every molecule exerts them. The force is weak — but universal.
Check your understanding
Hydrogen gas, H₂, can be cooled into a liquid at −253 °C. What attraction holds the H₂ molecules together in the liquid?
ADispersion forces.correct
BCovalent bonds that form between neighboring molecules.
This option is wrong — you bonded the molecules to each other — the H–H covalent bond stays inside each molecule; between molecules acts only the dispersion force.
CAttraction between the molecules' permanent δ+ and δ− ends.
This option is wrong — you gave H₂ permanent charged ends — H₂ is nonpolar, with no δ ends; the attraction is the dispersion force.
DThe pull of gravity between neighboring molecules.
This option is wrong — you reached for gravity — the gravitational pull between two molecules is far too small to hold a liquid together; dispersion forces do the holding.
H₂ is nonpolar — yet its molecules still attract one another. All molecules attract their neighbors through dispersion forces. Those weak attractions are what hold liquid hydrogen together.
Lesson 47 of 70 · CMB-047
Why dispersion forces exist
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Did You Know?
You've already seen that all molecules, even nonpolar ones, attract their neighbors through dispersion forces. But a nonpolar molecule has no permanent δ+ or δ− end. Where does the attraction come from?
The idea
A molecule's electrons are always moving.
Dispersion forces exist because a molecule's moving electrons can pile up on one side for a moment, giving it a temporary uneven charge that attracts its neighbor.
For that moment, the crowded side of the molecule is slightly negative (δ−) and the other side is slightly positive (δ+).
A molecule's moving electrons pile up on one side for a moment. The crowded side is briefly δ−, the other side δ+, and the temporary charge attracts the neighboring molecule.
An instant later the electrons have moved on, and the uneven charge appears somewhere else.
Nonpolar O₂ molecules attract one another this way: each charge is temporary, but there is always a momentary imbalance somewhere.
Worked examples
Worked example 1. Fluorine, F₂, is nonpolar. Explain why F₂ molecules still attract one another.
Step 1
Dispersion forces act, because a molecule's moving electrons can pile up on one side for a moment, giving it a temporary uneven charge that attracts its neighbor.
Step 2
For that moment one side of an F₂ molecule is δ− and the other side δ+, and the temporary charge attracts the neighboring molecule.
Step 3
F₂ molecules attract through the temporary uneven charges their moving electrons keep creating.
Worked example 2. Any single temporary charge on a CH₄ molecule vanishes almost instantly. Why do CH₄ molecules keep attracting each other anyway?
Step 1
The electrons never stop moving, so a new pile-up forms the moment an old one fades.
Step 2
There is always a momentary imbalance somewhere.
Step 3
The individual charges are fleeting, but the attraction they produce is continuous.
You can now explain why dispersion forces exist, because a molecule's moving electrons can pile up on one side for a moment, giving it a temporary uneven charge that attracts its neighbor.
Check your understanding
Iodine molecules, I₂, are nonpolar. Why do they attract one another?
ABecause a molecule's moving electrons can pile up on one side for a moment, giving it a temporary uneven charge that attracts its neighbor.correct
BBecause each I₂ molecule has a permanent δ+ end and a permanent δ− end.
This option is wrong — you gave a nonpolar molecule permanent charged ends — I₂ has none; its uneven charge is temporary, made by moving electrons.
CBecause neighboring molecules share pairs of electrons with each other, forming weak covalent bonds that hold the molecules together.
This option is wrong — you bonded the molecules together — no electrons are shared between molecules; the attraction comes from a momentary charge imbalance.
DBecause iodine molecules are heavy, and heavy objects press against each other.
This option is wrong — you used weight instead of charge — the attraction is electrical, created by a temporary pile-up of moving electrons.
I₂ has no permanent δ ends. Dispersion forces exist because a molecule's moving electrons can pile up on one side for a moment, giving it a temporary uneven charge that attracts its neighbor. Fleeting charges, steady attraction — a new pile-up always replaces the last.
Check your understanding
What creates the temporary uneven charge behind a dispersion force?
AThe molecule's moving electrons pile up on one side for a moment.correct
BElectrons permanently transfer from one molecule to its neighbor.
This option is wrong — you moved electrons between molecules — the pile-up happens inside one molecule, and no electron leaves it.
CThe protons in the molecule's nuclei drift to one side.
This option is wrong — you moved the protons — nuclei stay put; it is the fast-moving electrons that crowd to one side.
DOne molecule permanently pulls the shared electrons of its neighbor toward itself.
This option is wrong — you made the imbalance permanent and between molecules — the pile-up is momentary and happens within a single molecule.
A molecule's electrons are always moving. For a moment they can pile up on one side, making that side δ− and the other δ+. That temporary uneven charge attracts the neighboring molecule.
Check your understanding
A snapshot of a Cl₂ molecule catches its electrons piled toward the left end. What are the molecule's charges at that instant?
AThe left end is momentarily δ− and the right end momentarily δ+.correct
BThe left end is momentarily δ+ and the right end momentarily δ−.
This option is wrong — you put the signs on the wrong ends — electrons are negative, so the crowded end is the δ− end.
CThe whole molecule is momentarily negative.
This option is wrong — you changed the molecule's total charge — the electrons only moved within the molecule, so one end is δ− and the other δ+ while the total stays neutral.
DThe molecule has split into Cl⁻ and Cl⁺ ions.
This option is wrong — you turned partial charges into full ions — the pile-up makes only small δ charges, and the molecule stays bonded and whole.
Electrons carry negative charge, so the side they crowd is δ−. The side they left behind is δ+. The imbalance is momentary — the next snapshot would look different.
Lesson 48 of 70 · CMB-048
Bigger molecules, stronger dispersion
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You've already seen why dispersion forces exist. Their strength is not the same for every substance — molecular size sets it.
The idea
Between two similar substances, the one with larger molecules has the stronger dispersion forces.
That is because larger molecules have more electrons, so the momentary charge imbalances are larger and the attractions stronger.
A Br₂ molecule (70 electrons) is larger than a Cl₂ molecule (34 electrons), so bromine has stronger dispersion forces than chlorine.
The trend is for like-with-like comparisons: between substances that are not so similar, other details — such as the molecules' shapes — also play a part.
Bigger molecules, stronger dispersion
Substance
Electrons per molecule
Dispersion forces
Cl₂
34
weaker
Br₂
70
stronger
Br₂ molecules are larger, with more electrons, so their momentary charge imbalances are larger and their dispersion forces stronger.
Worked examples
Worked example 1. Fluorine, F₂ (18 electrons per molecule), and iodine, I₂ (106 electrons per molecule), are similar substances. Which has the stronger dispersion forces?
Step 1
I₂ molecules are larger, with far more electrons.
Step 2
Larger molecules have more electrons, so the momentary charge imbalances are larger and the attractions stronger.
Step 3
Iodine has the stronger dispersion forces.
Worked example 2. Methane, CH₄ (10 electrons per molecule), and propane, C₃H₈ (26 electrons per molecule), are similar substances. Which has the stronger dispersion forces?
Step 1
C₃H₈ molecules are larger, with more electrons.
Step 2
Larger molecules have more electrons, so the momentary charge imbalances are larger and the attractions stronger.
Step 3
Propane has the stronger dispersion forces.
You can now predict which of two similar substances has the stronger dispersion forces from molecular size, because larger molecules have more electrons, so the momentary charge imbalances are larger and the attractions stronger.
Check your understanding
Ethane, C₂H₆ (18 electrons per molecule), and pentane, C₅H₁₂ (42 electrons per molecule), are similar substances. Which has the stronger dispersion forces?
APentanecorrect
BEthane
This option is wrong — you gave the smaller molecule the stronger forces — larger molecules have more electrons, so the momentary charge imbalances are larger and the attractions stronger.
CBoth have identical dispersion forces
This option is wrong — you made dispersion one-size-fits-all — its strength grows with molecular size, and pentane's molecules are the larger ones.
DNeither — nonpolar molecules have no dispersion forces
This option is wrong — you removed dispersion from nonpolar molecules — dispersion forces act between all molecules; the question is only how strong.
Compare the sizes: C₅H₁₂ (42 electrons) is larger than C₂H₆ (18 electrons). Larger molecules have more electrons, so the momentary charge imbalances are larger and the attractions stronger. So pentane has the stronger dispersion forces.
Check your understanding
Butane, C₄H₁₀ (34 electrons per molecule), fuels lighters; octane, C₈H₁₈ (66 electrons per molecule), is a gasoline component. The two are similar substances. Which has the stronger dispersion forces?
AOctanecorrect
BButane
This option is wrong — you gave the smaller molecule the stronger forces — octane's larger molecules have more electrons, so their momentary charge imbalances are larger.
CBoth have identical dispersion forces
This option is wrong — you ignored molecular size — dispersion strength grows with it, and octane's molecules are far larger.
DNeither — dispersion forces act only between small molecules
This option is wrong — you capped dispersion at small molecules — all molecules exert dispersion forces, and larger ones exert stronger ones.
Octane's molecules are larger: 66 electrons against butane's 34. Larger molecules have more electrons, so the momentary charge imbalances are larger and the attractions stronger. So octane has the stronger dispersion forces.
Check your understanding
Two similar nonpolar substances are compared, and substance B turns out to have stronger dispersion forces than substance A. Which difference between their molecules best explains this?
AB's molecules are larger, with more electrons.correct
BA's molecules are larger, with more electrons.
This option is wrong — you attached the stronger forces to the smaller molecule — the substance with stronger dispersion forces is the one with larger molecules.
CB's molecules move faster than A's.
This option is wrong — you used speed instead of size — dispersion strength comes from electron count, not from how fast the molecules travel.
DB's molecules have stronger covalent bonds inside them.
This option is wrong — you reached inside the molecule — the bonds within a molecule do not set the dispersion force between molecules; electron count does.
Run the trend backwards: between similar substances, stronger dispersion points to larger molecules. Larger molecules have more electrons, so the momentary charge imbalances are larger and the attractions stronger. So B's molecules are the larger ones.
Lesson 49 of 70 · CMB-049
Dipole-dipole attractions
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You've already seen that some molecules are polar: their bond pulls do not cancel, leaving a permanent δ+ end and a permanent δ− end. Those permanent ends give polar molecules a second attraction, on top of the dispersion forces every molecule has.
The idea
A polar molecule, with its two oppositely charged ends, is called a 'dipole'.
Polar molecules attract their neighbors through 'dipole-dipole attractions' — the attraction between the oppositely charged ends of polar molecules.
A polar molecule such as HCl is a dipole: a permanent δ+ end and a permanent δ− end on one molecule.
HCl is polar, so HCl molecules attract one another through dipole-dipole attractions.
These attractions ADD to the dispersion forces that all molecules already exert.
Chemists sometimes group dispersion forces and dipole-dipole attractions under the umbrella name 'van der Waals forces' — a label you may meet, not a new force.
Worked examples
Worked example 1. Hydrogen bromide, HBr, is a polar molecule. What attraction do its molecules' permanent δ+ and δ− ends give rise to?
Step 1
Answer: dipole-dipole attractions.
Worked example 2. What is a dipole?
Step 1
Answer: a polar molecule, with its two oppositely charged ends.
You can now state that polar molecules attract their neighbors through dipole-dipole attractions, the attraction between the oppositely charged ends of polar molecules.
Check your understanding
Iodine monochloride, ICl, is a polar molecule. Its δ+ and δ− ends attract the oppositely charged ends of neighboring ICl molecules. What is this attraction called?
AA dipole-dipole attractioncorrect
BA dispersion force
This option is wrong — you named the temporary-charge force — this attraction runs on the molecules' PERMANENT δ ends, which makes it a dipole-dipole attraction.
CA covalent bond
This option is wrong — you called an attraction between molecules a bond — covalent bonds act within a molecule; this is an intermolecular attraction.
DAn ionic bond
This option is wrong — you promoted partial charges to full ionic charges — δ+ and δ− are small partial charges on neutral molecules, not ions.
ICl is polar: a permanent δ+ end and a permanent δ− end. Polar molecules attract their neighbors through dipole-dipole attractions — the attraction between the oppositely charged ends of polar molecules. Permanent ends, permanent name: dipole-dipole.
Check your understanding
Which molecules attract their neighbors through dipole-dipole attractions?
APolar moleculescorrect
BAll molecules
This option is wrong — you gave every molecule permanent charged ends — only polar molecules have them; the force ALL molecules share is dispersion.
CNonpolar molecules
This option is wrong — you picked the molecules with no δ ends — dipole-dipole attraction needs the permanent oppositely charged ends of polar molecules.
DOnly molecules that contain hydrogen
This option is wrong — you made hydrogen the requirement — the requirement is polarity: permanent δ+ and δ− ends, with or without hydrogen.
Dipole-dipole attraction is the attraction between the oppositely charged ends of polar molecules. Only polar molecules have those permanent ends. Nonpolar molecules attract their neighbors through dispersion forces alone.
Check your understanding
Chloromethane, CH₃Cl, is polar. A classmate says only dispersion forces act between its molecules. What attraction is the classmate missing?
ADipole-dipole attraction — the attraction between the oppositely charged ends of polar molecules.correct
BNothing — polar molecules exert only dispersion forces.
This option is wrong — you left the permanent δ ends idle — polar molecules attract their neighbors through dipole-dipole attractions as well.
CA covalent bond that forms between neighboring molecules and links them together in pairs.
This option is wrong — you bonded the molecules together — no covalent bond forms between molecules; the missing attraction is dipole-dipole.
DAn ionic bond between the molecules' δ+ and δ− ends.
This option is wrong — you treated partial charges as full ionic charges — δ ends attract each other, but the attraction is dipole-dipole, not ionic bonding.
CH₃Cl is polar, so it has permanent δ+ and δ− ends. Polar molecules attract their neighbors through dipole-dipole attractions. Those attractions ADD to the dispersion forces the classmate already counted.
Lesson 50 of 70 · CMB-050
Why polar molecules stick together
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You've already seen that polar molecules attract their neighbors through dipole-dipole attractions. Here is how those attractions actually form — and how they arrange the molecules.
The idea
Dipole-dipole attractions form because the slightly positive end of one polar molecule attracts the slightly negative end of the next.
In liquid HCl, the δ+ hydrogen end of one molecule points toward the δ− chlorine end of its neighbor.
Neighboring polar molecules settle into arrangements where opposite ends face each other.
The δ+ hydrogen end of one HCl molecule points toward the δ− chlorine end of its neighbor. The dashed line is the dipole-dipole attraction; the solid lines are covalent bonds.
The attraction is weak because the charges involved are small partial charges (δ), not full charges.
Worked examples
Worked example 1. Liquid hydrogen bromide contains polar HBr molecules with δ+ hydrogen ends and δ− bromine ends. Explain why one HBr molecule attracts its neighbor, and how the two arrange themselves.
Step 1
The attraction forms because the slightly positive end of one polar molecule attracts the slightly negative end of the next.
Step 2
So the δ+ hydrogen end of one HBr molecule turns toward the δ− bromine end of the next.
Step 3
The molecules attract through their opposite ends and settle with δ+ facing δ−.
Worked example 2. In solid iodine monochloride, each ICl molecule has a δ+ iodine end and a δ− chlorine end. Which end of one molecule faces the chlorine end of its neighbor?
Step 1
The slightly positive end of one polar molecule attracts the slightly negative end of the next.
Step 2
The chlorine end is the δ− end, so the neighboring molecule's δ+ end faces it.
Step 3
The δ+ iodine end of one molecule faces the δ− chlorine end of its neighbor.
You can now explain why dipole-dipole attractions form, because the slightly positive end of one polar molecule attracts the slightly negative end of the next.
Check your understanding
Chloromethane molecules, CH₃Cl, are polar, each with a δ+ end and a δ− chlorine end. Why do CH₃Cl molecules attract one another through dipole-dipole attractions?
ABecause the slightly positive end of one polar molecule attracts the slightly negative end of the next.correct
BBecause their moving electrons pile up on one side for a moment.
This option is wrong — you gave the dispersion mechanism — dipole-dipole attraction runs on the molecules' PERMANENT δ ends, not on momentary pile-ups.
CBecause the molecules pass electrons back and forth between each other as they collide.
This option is wrong — you traded electrons between molecules — no electrons move between them; the permanent opposite ends simply attract.
DBecause the δ+ end of one molecule attracts the δ+ end of the next.
This option is wrong — you attracted like charges — like charges repel; it is the OPPOSITE ends that attract.
Each CH₃Cl molecule is a dipole with permanent δ+ and δ− ends. Dipole-dipole attractions form because the slightly positive end of one polar molecule attracts the slightly negative end of the next. Opposite ends face each other; like ends do not.
Check your understanding
Hydrogen iodide molecules are polar: a δ+ hydrogen end and a δ− iodine end. In liquid HI, which arrangement do neighboring molecules favor?
AThe δ+ hydrogen end of one molecule beside the δ− iodine end of its neighbor.correct
BThe δ+ hydrogen end of one molecule beside the δ+ hydrogen end of its neighbor.
This option is wrong — you paired like charges — like charges repel; the molecules settle with opposite ends together.
CThe molecules keep as far from one another as possible, avoiding contact.
This option is wrong — you turned an attraction into avoidance — polar molecules pull toward each other, opposite ends first.
DNo favored arrangement — the ends pair up completely at random.
This option is wrong — you removed the ordering — the attraction between opposite ends steers neighbors into δ+-to-δ− arrangements.
The slightly positive end of one polar molecule attracts the slightly negative end of the next. So δ+ hydrogen ends turn toward δ− iodine ends. That opposite-ends-together arrangement is the favored one.
Check your understanding
In a polar liquid, the δ− end of one molecule is approached by two ends of nearby molecules: a δ+ end and a δ− end. Which end does it attract?
AThe δ+ end — opposite partial charges attract.correct
BThe δ− end — matching charges pull together.
This option is wrong — you attracted like charges — two δ− ends repel; the attraction is between opposite ends.
CBoth ends equally.
This option is wrong — you made the attraction charge-blind — the δ− end attracts the opposite (δ+) end and repels the like (δ−) end.
DNeither — partial charges are too small to attract anything.
This option is wrong — you dismissed partial charges — δ charges are small, so the attraction is weak, but it is real and it orders the whole liquid.
Dipole-dipole attractions form because the slightly positive end of one polar molecule attracts the slightly negative end of the next. A δ− end therefore attracts a δ+ end and repels another δ− end. Small charges, weak attraction — but a definite preference.
Lesson 51 of 70 · CMB-051
Hydrogen bonding
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Did You Know?
You've already seen dipole-dipole attractions between polar molecules. One special case is so much stronger than the rest that it gets its own name.
The idea
When a hydrogen atom is covalently bonded to nitrogen, oxygen, or fluorine, that hydrogen is attracted to an N, O, or F atom of a neighboring molecule.
This especially strong intermolecular attraction is called 'hydrogen bonding'.
A hydrogen bond is NOT a covalent bond — it is an attraction between molecules, not a bond within one.
Water molecules attract one another through hydrogen bonding: each O–H hydrogen is attracted to the oxygen of a neighboring molecule.
Only nitrogen, oxygen, and fluorine qualify — hydrogen bonded to any other element does not hydrogen-bond.
Hydrogen bonding between two water molecules: the O–H hydrogen of one molecule is attracted to the oxygen of its neighbor. Dashed line = hydrogen bond; solid lines = covalent bonds.
Worked examples
Worked example 1. In liquid ammonia, each NH₃ hydrogen is bonded to nitrogen. Do NH₃ molecules attract one another through hydrogen bonding?
Step 1
Answer: yes — hydrogen bonded to nitrogen qualifies, so each N–H hydrogen is attracted to the nitrogen of a neighboring molecule.
Worked example 2. Hydrogen fluoride molecules attract one another through hydrogen bonding. Is that attraction a covalent bond?
Step 1
Answer: no — a hydrogen bond is an attraction between molecules, not a covalent bond.
You can now state that an especially strong intermolecular attraction called hydrogen bonding forms when a hydrogen atom bonded to nitrogen, oxygen, or fluorine is attracted to an N, O, or F atom of a neighboring molecule, and that a hydrogen bond is not a covalent bond.
Check your understanding
Methanol, CH₃OH, is polar, and one of its hydrogens is bonded to oxygen. Which attraction acts between methanol molecules in addition to dispersion forces and dipole-dipole attractions?
AHydrogen bondingcorrect
BNo further attraction
This option is wrong — you overlooked the O–H hydrogen — hydrogen bonded to oxygen is attracted to the oxygen of a neighboring molecule, and that attraction is hydrogen bonding.
CCovalent bonding between the molecules
This option is wrong — you bonded the molecules together — covalent bonds stay within each molecule; the extra attraction between them is hydrogen bonding.
DIonic bonding between the molecules
This option is wrong — you turned neutral molecules into ions — no full charges exist here; the extra attraction is hydrogen bonding.
Check the condition: is a hydrogen bonded to N, O, or F? Yes — methanol has an O–H hydrogen. So methanol molecules also attract through hydrogen bonding.
Check your understanding
In hydrogen chloride, HCl, the hydrogen is bonded to chlorine. Which statement about hydrogen bonding between HCl molecules is correct?
AHCl molecules do not hydrogen-bond, because chlorine is not nitrogen, oxygen, or fluorine.correct
BHCl molecules hydrogen-bond, because the molecule contains hydrogen.
This option is wrong — you counted any hydrogen — hydrogen bonding needs a hydrogen bonded to N, O, or F, and HCl's hydrogen is bonded to chlorine.
CHCl molecules hydrogen-bond, because chlorine is highly electronegative.
This option is wrong — you extended the rule to any electronegative atom — only nitrogen, oxygen, and fluorine qualify.
DHCl molecules cannot hydrogen-bond, because HCl is nonpolar.
This option is wrong — you got the right answer from a wrong fact — HCl IS polar; it fails the hydrogen-bonding test because chlorine is not N, O, or F.
The condition: a hydrogen covalently bonded to nitrogen, oxygen, or fluorine. HCl's hydrogen is bonded to chlorine — not one of the three. So HCl molecules attract through dispersion and dipole-dipole attractions, but not hydrogen bonding.
Check your understanding
In which liquid do the molecules attract one another through hydrogen bonding?
AEthanol, C₂H₅OH — one hydrogen is bonded to oxygen.correct
BMethane, CH₄ — every hydrogen is bonded to carbon.
This option is wrong — you counted hydrogens bonded to carbon — carbon is not N, O, or F, so CH₄ cannot hydrogen-bond.
CHydrogen bromide, HBr — the hydrogen is bonded to bromine.
This option is wrong — you let bromine qualify — only nitrogen, oxygen, and fluorine qualify, and bromine is none of them.
DNitrogen, N₂ — the molecule contains nitrogen.
This option is wrong — you matched on nitrogen alone — N₂ contains no hydrogen at all, so there is nothing to hydrogen-bond with.
Apply the condition to each molecule: a hydrogen bonded to N, O, or F. Only ethanol has one — its O–H hydrogen. That hydrogen is attracted to the oxygen of a neighboring ethanol molecule.
Lesson 52 of 70 · CMB-052
Why hydrogen bonding is so strong
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You've already seen what hydrogen bonding is and where it forms. Here is why it beats ordinary dipole-dipole attraction.
The idea
Hydrogen bonding is stronger than ordinary dipole-dipole attraction because nitrogen, oxygen, and fluorine pull shared electrons so strongly that the attached hydrogen becomes strongly positive and gets very close to a lone pair on the neighboring molecule.
Fluorine and oxygen are the two strongest electron-pullers in the periodic table, and nitrogen is close behind — and all three are small atoms. That is why only they qualify.
The hydrogen they strip of electron share ends up more strongly positive than the δ+ end of an ordinary polar molecule.
And because a hydrogen atom is tiny, it can approach the neighboring molecule's lone pair very closely.
Because opposite charges attract, and the attraction is stronger when the charges are larger or closer together, the bigger charge at closer range makes hydrogen bonding the standout attraction.
The attraction between water molecules is therefore stronger than the attraction between HCl molecules, even though both substances are polar.
Worked examples
Worked example 1. Explain why the hydrogen bonding between NH₃ molecules is stronger than the dipole-dipole attraction between PH₃ molecules.
Step 1
Nitrogen is one of the strongest electron-pullers; phosphorus's pull is much weaker.
Step 2
Hydrogen bonding is stronger because nitrogen, oxygen, and fluorine pull shared electrons so strongly that the attached hydrogen becomes strongly positive and gets very close to a lone pair on the neighboring molecule.
Step 3
PH₃'s hydrogens stay only mildly δ+, so PH₃ manages only ordinary dipole-dipole attraction.
Step 4
NH₃'s strongly positive N–H hydrogens, held very close to neighboring lone pairs, out-attract PH₃'s ordinary dipole-dipole ends.
Worked example 2. HF molecules attract one another far more strongly than HBr molecules do, though both are polar. Why?
Step 1
In HF the hydrogen is bonded to fluorine — the strongest electron-puller of all — so the hydrogen becomes strongly positive and gets very close to a lone pair on the neighboring molecule: hydrogen bonding.
Step 2
In HBr the bromine's weaker pull leaves an ordinary δ+ hydrogen, so only dipole-dipole attraction forms.
Step 3
HF hydrogen-bonds; HBr does not — so HF molecules hold one another far more strongly.
You can now explain why hydrogen bonding is stronger than ordinary dipole-dipole attraction, because nitrogen, oxygen, and fluorine pull shared electrons so strongly that the attached hydrogen becomes strongly positive and gets very close to a lone pair on the neighboring molecule.
Check your understanding
Why is the hydrogen bonding between CH₃OH molecules stronger than the dipole-dipole attraction between CH₃Cl molecules of similar size?
ABecause nitrogen, oxygen, and fluorine pull shared electrons so strongly that the attached hydrogen becomes strongly positive and gets very close to a lone pair on the neighboring molecule.correct
BBecause oxygen shares its electrons equally with hydrogen, so the O–H bond itself is stronger, and molecules with stronger bonds inside them attract their neighbors more strongly.
This option is wrong — you made the sharing equal — oxygen pulls the shared electrons strongly toward itself, and that unequal pull is what leaves the hydrogen strongly positive.
CBecause CH₃OH molecules are much larger, so their momentary charge imbalances are bigger.
This option is wrong — you reached for the dispersion size trend — the molecules are similar in size; the extra strength comes from the strongly positive O–H hydrogen.
DBecause a hydrogen bond is a covalent bond, and covalent bonds are strong.
This option is wrong — you promoted the hydrogen bond to a covalent bond — it is an attraction between molecules, strong for its kind but not a bond.
CH₃OH has an O–H hydrogen; CH₃Cl does not. Hydrogen bonding is stronger because nitrogen, oxygen, and fluorine pull shared electrons so strongly that the attached hydrogen becomes strongly positive and gets very close to a lone pair on the neighboring molecule. Bigger charge, closer approach — stronger attraction.
Check your understanding
What does the strong electron pull of nitrogen, oxygen, or fluorine do to a hydrogen atom bonded to it?
AIt leaves the hydrogen strongly positive.correct
BIt leaves the hydrogen strongly negative.
This option is wrong — you sent the charge the wrong way — the electron share is pulled AWAY from the hydrogen, leaving it positive.
CIt pulls the hydrogen off the molecule as a free H⁺ ion.
This option is wrong — you broke the covalent bond — the hydrogen stays bonded; it is only stripped of its share of the electrons, not removed.
DIt has no effect on the hydrogen's charge.
This option is wrong — you ignored the pull — losing most of its electron share is exactly what makes the hydrogen strongly positive.
N, O, and F pull shared electrons strongly toward themselves. The bonded hydrogen keeps little of the electron share, so it becomes strongly positive. That strongly positive hydrogen is what reaches for the neighboring molecule's lone pair.
Check your understanding
Two features of the hydrogen in an O–H group make its attraction to a neighboring molecule's lone pair especially strong. Which pair of features is it?
AIts strong positive charge and its ability to get very close to the lone pair.correct
BIts large size and heavy mass.
This option is wrong — you sized the hydrogen up — hydrogen is the tiniest atom, and that tininess is exactly what lets it approach the lone pair so closely.
CIts strong negative charge and its extra electrons.
This option is wrong — you flipped the charge — the oxygen pulls the electron share away, leaving the hydrogen strongly POSITIVE.
DIts full 1+ charge and the covalent bond it forms to the lone pair.
This option is wrong — you overshot on both counts — the charge is a strong partial charge, not a full 1+, and the attraction to the lone pair is not a covalent bond.
Feature one: the hydrogen is strongly positive, stripped of its electron share by the oxygen. Feature two: the hydrogen is tiny, so it gets very close to the neighboring lone pair. Because opposite charges attract, and the attraction is stronger when the charges are larger or closer together, the two features multiply the attraction.
Lesson 53 of 70 · CMB-053
Which forces a substance has
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You've now met all three intermolecular forces. Given any molecular substance, three questions tell you exactly which forces act between its molecules.
The idea
Question 1 — is it made of molecules? Then dispersion forces act: all molecules attract their neighbors through dispersion.
Question 2 — are the molecules polar? Then dipole-dipole attractions act as well.
Which forces act between the molecules?
Question
If yes
1. Is it made of molecules?
dispersion forces act
2. Are the molecules polar?
add dipole-dipole attractions
3. Is a hydrogen bonded to N, O, or F?
add hydrogen bonding
Run the three questions in order. Each 'yes' adds a force; no 'yes' ever removes one.
Question 3 — is a hydrogen bonded to N, O, or F? Then hydrogen bonding acts too.
Each 'yes' ADDS a force — a hydrogen-bonding substance keeps its dispersion forces and its dipole-dipole attractions.
NH₃ is molecular, polar, and has hydrogens bonded to nitrogen — so ammonia has dispersion forces, dipole-dipole attractions, AND hydrogen bonding.
Worked examples
Worked example 1. Which intermolecular forces act between HBr molecules? (HBr is polar; its hydrogen is bonded to bromine.)
Question 3: the hydrogen is bonded to bromine, not N, O, or F — no hydrogen bonding.
Step 4
HBr: dispersion forces and dipole-dipole attractions.
Worked example 2. Which intermolecular forces act between CO₂ molecules? (CO₂ is nonpolar.)
Step 1
Question 1: molecular — dispersion forces act.
Step 2
Question 2: nonpolar — no dipole-dipole attractions.
Step 3
Question 3: no hydrogen in the molecule — no hydrogen bonding.
Step 4
CO₂: dispersion forces only.
You can now classify which intermolecular forces, dispersion, dipole-dipole, or hydrogen bonding, act between the molecules of a substance from its molecular polarity and its formula.
Check your understanding
Methane, CH₄, is nonpolar. Which intermolecular forces act between CH₄ molecules?
ADispersion forces onlycorrect
BDispersion forces and dipole-dipole attractions
This option is wrong — you treated CH₄ as polar — a nonpolar molecule has no permanent δ ends, so no dipole-dipole attraction forms.
CDispersion forces, dipole-dipole attractions, and hydrogen bonding
This option is wrong — you counted the C–H hydrogens as hydrogen-bonders — hydrogen bonding needs a hydrogen bonded to N, O, or F, not to carbon.
DNo intermolecular forces at all
This option is wrong — you left a molecular substance with nothing — all molecules attract their neighbors through dispersion forces.
Question 1: molecular — dispersion forces act. Question 2: nonpolar — no dipole-dipole. Question 3: hydrogens on carbon only — no hydrogen bonding. CH₄: dispersion only.
Check your understanding
Hydrogen sulfide, H₂S, is polar; its hydrogens are bonded to sulfur. Which intermolecular forces act between H₂S molecules?
ADispersion forces and dipole-dipole attractionscorrect
BDispersion forces, dipole-dipole attractions, and hydrogen bonding
This option is wrong — you let sulfur qualify for hydrogen bonding — only hydrogen bonded to N, O, or F counts, and sulfur is none of them.
CDispersion forces only
This option is wrong — you skipped the polarity question — H₂S is polar, so dipole-dipole attractions act as well.
DDipole-dipole attractions only
This option is wrong — you dropped dispersion — every molecular substance keeps its dispersion forces; each yes ADDS a force.
Question 1: molecular — dispersion. Question 2: polar — add dipole-dipole. Question 3: hydrogens on sulfur, not N/O/F — no hydrogen bonding. H₂S: dispersion + dipole-dipole.
Check your understanding
Hydrogen fluoride, HF, is polar. Which intermolecular forces act between HF molecules?
ADispersion forces, dipole-dipole attractions, and hydrogen bondingcorrect
BDispersion forces and dipole-dipole attractions
This option is wrong — you stopped before question 3 — HF's hydrogen is bonded to fluorine, so hydrogen bonding acts too.
CHydrogen bonding only
This option is wrong — you let the strongest force replace the others — each yes ADDS a force; HF keeps its dispersion forces and dipole-dipole attractions.
DDipole-dipole attractions and hydrogen bonding
This option is wrong — you dropped dispersion — all molecules attract through dispersion forces, HF included.
Question 1: molecular — dispersion. Question 2: polar — add dipole-dipole. Question 3: hydrogen bonded to fluorine — add hydrogen bonding. HF has all three.
Lesson 54 of 70 · CMB-054
Ranking the three forces
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Did You Know?
You've already worked out which forces a substance has. When two substances have molecules of similar size, the three forces also line up in strength.
The idea
For molecules of similar size, the three intermolecular forces rank from weakest to strongest: dispersion, then dipole-dipole, then hydrogen bonding.
A hydrogen-bonding substance therefore clings together more strongly than a similar-size substance with only dipole-dipole attractions, which in turn beats a similar-size substance with dispersion alone.
for molecules of SIMILAR SIZE only
For molecules of similar size, the three intermolecular forces rank from weakest to strongest: dispersion, dipole-dipole, hydrogen bonding.
The attraction between H₂O molecules (hydrogen bonding) is stronger than the attraction between similar-size H₂S molecules (dipole-dipole).
The order holds ONLY when the molecules compared are of similar size.
Between molecules of very different sizes, a large molecule's dispersion forces can outweigh a small molecule's dipole-dipole attractions — so check sizes before you rank.
Worked examples
Worked example 1. HCl and F₂ have molecules of similar size. HCl is polar; F₂ is nonpolar. Which substance's molecules attract one another more strongly?
Step 1
F₂: dispersion forces only. HCl: dispersion plus dipole-dipole attractions.
Step 2
For similar-size molecules, dipole-dipole attractions rank above dispersion alone.
Step 3
HCl's molecules attract more strongly.
Worked example 2. CH₃OH and CH₃F have molecules of similar size. Both are polar; only CH₃OH has a hydrogen bonded to oxygen. Which substance's molecules attract one another more strongly?
Step 1
CH₃F: dispersion plus dipole-dipole. CH₃OH: those two plus hydrogen bonding.
Step 2
For similar-size molecules, hydrogen bonding is the strongest of the three forces.
Step 3
CH₃OH's molecules attract more strongly.
You can now rank dispersion, dipole-dipole, and hydrogen bonding from weakest to strongest for molecules of similar size, and state that the order holds only when the molecules compared are of similar size.
Check your understanding
For molecules of similar size, rank the three intermolecular forces from weakest to strongest.
ADispersion, then dipole-dipole, then hydrogen bondingcorrect
BHydrogen bonding, then dipole-dipole, then dispersion
This option is wrong — you ran the ladder top-down — the question asks weakest FIRST, and dispersion is the weakest.
CDipole-dipole, then dispersion, then hydrogen bonding
This option is wrong — you swapped the bottom two rungs — dispersion sits below dipole-dipole for similar-size molecules.
DDispersion, then hydrogen bonding, then dipole-dipole
This option is wrong — you swapped the top two rungs — hydrogen bonding out-pulls dipole-dipole, so it sits at the top.
Weakest: dispersion. Then dipole-dipole attractions. Strongest: hydrogen bonding — and the whole order holds only for molecules of similar size.
Check your understanding
NH₃ molecules hydrogen-bond; CH₄ molecules, of similar size, are nonpolar. Which substance's molecules attract one another more strongly?
ANH₃correct
BCH₄
This option is wrong — you put dispersion above hydrogen bonding — at similar size, hydrogen bonding is the strongest of the three forces.
CBoth attract equally
This option is wrong — you flattened the ranking — a hydrogen-bonding substance out-grips a similar-size dispersion-only substance.
DNeither attracts at all
This option is wrong — you removed the forces — both substances' molecules attract; the question is which attraction is stronger.
Sizes are similar, so the ranking applies. NH₃ brings hydrogen bonding; CH₄ has dispersion only. Hydrogen bonding sits at the top of the ladder, so NH₃'s molecules attract more strongly.
Check your understanding
The weakest-to-strongest ranking of the three intermolecular forces comes with one condition. When does the ranking reliably hold?
AWhen the molecules compared are of similar sizecorrect
BAlways, for any two molecular substances
This option is wrong — you dropped the caveat — between very different sizes, a big molecule's dispersion forces can outweigh a small molecule's dipole-dipole attractions.
COnly when both substances are liquids
This option is wrong — you tied the ranking to a state of matter — the forces act in solids, liquids, and gases; the condition is similar molecular size.
DOnly when both molecules are polar
This option is wrong — you required polarity — the ranking compares all three forces, including dispersion in nonpolar substances; the condition is similar size.
The order holds only when the molecules compared are of similar size. Size feeds dispersion: a much larger molecule can out-attract through dispersion alone. So check sizes before you rank.
Lesson 55 of 70 · CMB-055
Boiling points follow force strength
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Wonder this:
Chlorine and bromine sit next to each other in Group 17, and both form nonpolar two-atom molecules. Yet at room temperature chlorine is a gas while bromine is a liquid — bromine's molecules refuse to let go of one another. Whatever decides how easily molecules part company decides which substances are gases, liquids, or solids on your bench.
You can already compare the strength of two substances' intermolecular forces. That comparison buys you a prediction about a measurable property.
The idea
The stronger a molecular substance's intermolecular forces, the higher its boiling point.
To predict which of two substances boils at the higher temperature, compare the forces between their molecules.
H₂O molecules hydrogen-bond, while similar-size H₂S molecules manage only dipole-dipole attraction — so water boils at the higher temperature.
The prediction runs on force strength alone: work out whose grip is stronger, and you have named the higher boiler.
Worked examples
Worked example 1. NH₃ molecules hydrogen-bond; CH₄ molecules, of similar size, are nonpolar with dispersion forces only. Which substance has the higher boiling point?
Step 1
Compare the forces: hydrogen bonding (NH₃) beats dispersion alone (CH₄) at similar size.
Step 2
Stronger intermolecular forces mean a higher boiling point.
Step 3
NH₃ boils at the higher temperature — in fact at −33 °C, against −162 °C for CH₄.
Worked example 2. Pentane, C₅H₁₂, and methane, CH₄, are similar nonpolar substances, and pentane's larger molecules give it stronger dispersion forces. Which boils at the higher temperature?
Step 1
Compare the forces: pentane's dispersion forces are the stronger ones.
Step 2
Stronger intermolecular forces mean a higher boiling point.
Step 3
Pentane boils at the higher temperature — 36 °C, against −162 °C for methane.
You can now predict which of two molecular substances has the higher boiling point from the strength of their intermolecular forces.
Check your understanding
CH₃OH molecules hydrogen-bond; CH₃F molecules, of similar size, have dipole-dipole attractions but no hydrogen bonding. Which substance has the higher boiling point?
ACH₃OHcorrect
BCH₃F
This option is wrong — you gave the higher boiling point to the weaker grip — hydrogen bonding out-pulls dipole-dipole at similar size, and stronger forces mean a higher boiling point.
CBoth boil at the same temperature
This option is wrong — you cut the link between forces and boiling point — different force strengths mean different boiling points.
DIt cannot be predicted from their forces
This option is wrong — you gave up on the rule — the stronger a substance's intermolecular forces, the higher its boiling point, and these two differ clearly.
Compare the forces first: hydrogen bonding (CH₃OH) beats dipole-dipole (CH₃F) at similar size. The stronger the intermolecular forces, the higher the boiling point. CH₃OH is the higher boiler — 65 °C, against −78 °C for CH₃F.
Check your understanding
HCl is polar; F₂, of similar molecular size, is nonpolar. Which substance boils at the higher temperature?
AHClcorrect
BF₂
This option is wrong — you gave the higher boiling point to dispersion alone — HCl's added dipole-dipole attractions make its forces stronger, and stronger forces mean a higher boiling point.
CBoth boil at the same temperature
This option is wrong — you leveled two different force strengths — HCl's molecules grip more strongly, so HCl boils higher.
DNeither substance can be boiled
This option is wrong — you removed boiling altogether — every molecular substance boils once its intermolecular forces are overcome.
HCl: dispersion plus dipole-dipole. F₂: dispersion only. Stronger forces, higher boiling point. HCl boils higher — −85 °C, against −188 °C for F₂.
Check your understanding
Butane, C₄H₁₀, and octane, C₈H₁₈, are similar nonpolar substances, and octane's larger molecules give it the stronger dispersion forces. Which boils at the higher temperature?
AOctanecorrect
BButane
This option is wrong — you attached the higher boiling point to the weaker forces — octane's stronger dispersion forces mean the higher boiling point.
CBoth boil at the same temperature, because both are nonpolar
This option is wrong — you treated all dispersion forces as equal — octane's are stronger, so its boiling point is higher.
DNeither — boiling point does not depend on intermolecular forces
This option is wrong — you cut the force-property link — boiling point follows force strength directly.
The force comparison is given: octane's dispersion forces are stronger. The stronger the intermolecular forces, the higher the boiling point. Octane boils higher — 126 °C, against −1 °C for butane.
Lesson 56 of 70 · CMB-056
Why stronger forces raise the boiling point
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Did You Know?
You've already seen the pattern: stronger intermolecular forces, higher boiling point. And you've seen what boiling does — it separates molecules without breaking them. Put together, the second fact explains the first.
The idea
A substance with stronger intermolecular forces boils at a higher temperature because boiling has to pull molecules away from each other, so stronger attractions need more energy to overcome.
Higher temperature is how that extra energy arrives: the liquid must get hotter before its molecules can escape their neighbors.
HF molecules hydrogen-bond while F₂ molecules have only dispersion forces, so HF needs far more energy per escape — HF boils at 20 °C, F₂ at −188 °C.
Worked example 1. The hydrogen bonding between NH₃ molecules is stronger than the dispersion forces between similar-size CH₄ molecules. Explain why NH₃ boils at the higher temperature.
Step 1
Boiling has to pull molecules away from each other, so stronger attractions need more energy to overcome.
Step 2
NH₃'s hydrogen bonds are the stronger attractions, so separating NH₃ molecules costs more energy.
Step 3
NH₃ must be heated further before its molecules can escape — it boils at −33 °C, while CH₄ boils at −162 °C.
Worked example 2. Butane's C₄H₁₀ molecules have stronger dispersion forces than propane's C₃H₈ molecules. Explain why butane boils at −1 °C while propane boils at −42 °C.
Step 1
Boiling has to pull molecules away from each other, so stronger attractions need more energy to overcome.
Step 2
Butane's stronger dispersion forces make each escape cost more energy, so butane needs the higher temperature.
Step 3
Butane's stronger grip explains its higher boiling point of −1 °C.
You can now explain why a substance with stronger intermolecular forces boils at a higher temperature, because boiling has to pull molecules away from each other, so stronger attractions need more energy to overcome.
Check your understanding
Why does a substance with stronger intermolecular forces boil at a higher temperature?
ABecause boiling has to pull molecules away from each other, so stronger attractions need more energy to overcome.correct
BBecause stronger attractions make the molecules heavier, and heavy molecules cannot leave the liquid.
This option is wrong — you turned attraction into mass — the molecules' masses do not change; stronger attractions simply cost more energy to overcome.
CBecause boiling must break the covalent bonds inside each molecule, and stronger substances have stronger bonds.
This option is wrong — you sent the boil into the bonds — boiling separates whole molecules; the energy overcomes the attractions BETWEEN them.
DBecause stronger attractions speed the molecules up, and fast molecules stay in the liquid.
This option is wrong — you rewired heat and speed — attractions do not speed molecules up; they hold them together until enough energy arrives to pull them apart.
Boiling is a separation job: molecules must be pulled away from their neighbors. Boiling has to pull molecules away from each other, so stronger attractions need more energy to overcome. More energy needed means a hotter liquid — a higher boiling point.
Check your understanding
Boiling pulls a liquid's molecules away from each other. What does a stronger attraction between the molecules change about this process?
AEach separation needs more energy, so the boiling temperature is higher.correct
BEach separation needs less energy, so the boiling temperature is lower.
This option is wrong — you inverted the cost — a stronger grip takes MORE energy to break, which pushes the boiling temperature up.
CNothing changes — boiling temperature depends only on the size of the molecules.
This option is wrong — you swapped in size as the only factor — size matters only through the forces; it is the attraction's strength that sets the energy cost.
DThe molecules break into atoms instead of separating.
This option is wrong — you broke the molecules — boiling never breaks covalent bonds; it only pulls whole molecules apart.
Stronger attraction, higher energy cost per escape. Boiling has to pull molecules away from each other, so stronger attractions need more energy to overcome. The liquid must therefore get hotter before boiling — a higher boiling point.
Check your understanding
The dipole-dipole attractions between ICl molecules are stronger than the dispersion forces between similar-size Br₂ molecules. Which substance boils at the higher temperature, and why?
AICl — its stronger attractions need more energy to overcome, so its molecules separate only at a higher temperature.correct
BBr₂ — dispersion forces always take the most energy to overcome.
This option is wrong — you crowned dispersion — the stem states ICl's attractions are stronger, and stronger attractions cost more energy to overcome.
CBoth boil at the same temperature, because molecules of the same size always need the same energy to separate.
This option is wrong — you let size overrule force strength — equal size only makes the comparison fair; the stronger attraction still sets the higher boiling point.
DICl boils lower, because polar molecules slip out of liquids more easily.
This option is wrong — you gave polarity an escape bonus — polarity ADDS attraction, so polar ICl's molecules are harder to pull away, not easier.
Boiling has to pull molecules away from each other, so stronger attractions need more energy to overcome. ICl's dipole-dipole attractions are the stronger grip here. So ICl needs the higher temperature — it boils at 97 °C, against 59 °C for Br₂.
Lesson 57 of 70 · CMB-057
Reading force strength from data
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Have You Ever Wondered?
Wonder this:
No microscope can show you the attraction between two molecules. Yet chemists confidently say methanol's molecules grip each other far more strongly than methane's. How can anyone know that without seeing it?
You've already seen why a substance with stronger intermolecular forces boils at a higher temperature: boiling has to pull molecules away from each other, so stronger attractions need more energy to overcome. That link runs in both directions — and the reverse direction turns a boiling-point table into a force detector.
The idea
A boiling point is something you can measure; the forces between molecules are not.
Boiling has to pull molecules away from each other, so stronger attractions need more energy to overcome.
So a HIGHER boiling point is evidence of STRONGER intermolecular forces.
To compare two substances, read both boiling points from the data and pick the higher one.
The substance with the higher boiling point has the stronger intermolecular forces.
Methanol, CH₃OH, boils at 65 °C; methane, CH₄, boils at −162 °C.
Methanol's boiling point is far higher, so methanol's molecules attract each other far more strongly than methane's do.
Boiling points measured at standard pressure
Substance
Boiling point
methanol, CH₃OH
65 °C
methane, CH₄
−162 °C
Methanol boils far higher than methane — evidence that methanol's molecules attract each other far more strongly.
Worked examples
Worked example 1. Acetone boils at 56 °C. Propane boils at −42 °C. Which substance has the stronger intermolecular forces?
Step 1
Read the data: 56 °C for acetone, −42 °C for propane.
Step 2
Acetone's boiling point is higher.
Step 3
A higher boiling point is evidence of stronger intermolecular forces.
Step 4
Acetone has the stronger intermolecular forces.
Worked example 2. Ammonia, NH₃, boils at −33 °C. Nitrogen, N₂, boils at −196 °C. Which substance has the stronger intermolecular forces?
Step 1
Read the data: −33 °C for ammonia, −196 °C for nitrogen.
Step 2
Both are below zero, but −33 °C is the higher temperature.
Step 3
A higher boiling point is evidence of stronger intermolecular forces.
Step 4
Ammonia has the stronger intermolecular forces.
You can now judge which of two substances has the stronger intermolecular forces from supplied boiling-point data.
Check your understanding
The table shows the measured boiling points of ethanol and ethane. Which substance has the stronger intermolecular forces?
Boiling points
Substance
Boiling point
ethanol
78 °C
ethane
−89 °C
AEthanol, because its boiling point is higher.correct
BEthane, because its boiling point is lower.
This option is wrong — you flipped the link — a LOW boiling point means the molecules separate easily, which is the mark of WEAK attractions.
CEthane, because a negative boiling point means stronger forces.
This option is wrong — you read the minus sign as strength — a negative boiling point is just a low temperature, and low boiling means weak attractions.
DNeither, because boiling points say nothing about the forces between molecules.
This option is wrong — you cut the link the data gives you — boiling has to pull molecules away from each other, so the boiling point directly reflects how strongly they attract.
Read the table: ethanol boils at 78 °C, ethane at −89 °C. Boiling has to pull molecules away from each other, so stronger attractions need more energy to overcome. Ethanol's higher boiling point is evidence of stronger intermolecular forces.
Check your understanding
The table shows the measured boiling points of hydrogen fluoride and fluorine. Which substance has the stronger intermolecular forces?
Boiling points
Substance
Boiling point
hydrogen fluoride, HF
20 °C
fluorine, F₂
−188 °C
AHydrogen fluoride, because its boiling point is higher.correct
BFluorine, because its boiling point is lower.
This option is wrong — you flipped the link — fluorine's molecules separate at a much lower temperature, so their attractions are the weaker ones.
CHydrogen fluoride, because its molecules contain stronger covalent bonds.
This option is wrong — you compared the wrong forces — boiling separates whole molecules from each other, so the data reports the attractions BETWEEN molecules, not the bonds within them.
DFluorine, because F₂ contains two atoms of the same element.
This option is wrong — you judged from the formula instead of the data — the boiling points are the evidence, and 20 °C is far higher than −188 °C.
Read the table: hydrogen fluoride boils at 20 °C, fluorine at −188 °C. The higher boiling point marks the stronger attractions between molecules. Hydrogen fluoride has the stronger intermolecular forces.
Check your understanding
The table shows the measured boiling points of bromine and chlorine. What do the data show about the attractions between the molecules of each substance?
Boiling points
Substance
Boiling point
bromine, Br₂
59 °C
chlorine, Cl₂
−34 °C
ABr₂ molecules attract each other more strongly than Cl₂ molecules do.correct
BCl₂ molecules attract each other more strongly than Br₂ molecules do.
This option is wrong — you flipped the link — chlorine boils at the lower temperature, so its molecules are the easier ones to pull apart.
CThe two attractions are equally strong, because both substances are made of two-atom molecules.
This option is wrong — you judged from the formulas instead of the data — a 93-degree gap in boiling point is direct evidence the attractions differ.
DThe Br–Br bond is stronger than the Cl–Cl bond.
This option is wrong — you compared bonds within molecules — boiling pulls whole molecules away from each other, so the data reports intermolecular attractions, not bond strengths.
Read the table: bromine boils at 59 °C, chlorine at −34 °C. Boiling has to pull molecules away from each other, so stronger attractions need more energy to overcome. Bromine's higher boiling point shows its molecules attract each other more strongly.
Lesson 58 of 70 · CMB-058
Water's unusual boiling point
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Did You Know?
You've already used boiling points as evidence of force strength. One everyday substance stands out from every molecule of its size: water.
The idea
Small molecules normally boil far below room temperature.
Methane, CH₄, is about the same size as a water molecule, and it boils at −162 °C.
Water boils at 100 °C — more than 250 degrees higher than methane.
Boiling points of similar-sized molecules
Substance
Boiling point
water, H₂O
100 °C
methane, CH₄
−162 °C
Two molecules of similar size, more than 250 degrees apart — water's hydrogen bonding makes the difference.
The reason is the kind of attraction between water molecules: hydrogen bonding.
Water's hydrogen bonding is much stronger than the dispersion or dipole-dipole attractions between other molecules of similar size.
Boiling has to pull molecules away from each other, so stronger attractions need more energy to overcome.
That is why liquid water survives on a warm planet while other small molecules exist only as gases.
Worked examples
Worked example 1. Nitrogen, N₂, is a small molecule like water, yet it boils at −196 °C while water boils at 100 °C. What accounts for the huge gap?
Step 1
Answer: water's hydrogen bonding is much stronger than the dispersion forces between N₂ molecules.
Worked example 2. Which intermolecular attraction gives water its unusually high boiling point?
Step 1
Answer: hydrogen bonding.
You can now explain why water boils at a far higher temperature than molecules of similar size, because its hydrogen bonding is much stronger than their dispersion or dipole-dipole attractions.
Check your understanding
Oxygen, O₂, is a molecule of similar size to water, yet O₂ boils at −183 °C while water boils at 100 °C. Why does water boil so much higher?
AWater's hydrogen bonding is much stronger than the dispersion forces between O₂ molecules.correct
BWater's O–H covalent bonds are stronger than the O=O bond in oxygen.
This option is wrong — you compared the bonds inside the molecules — boiling pulls whole molecules apart from each other, so only the attractions BETWEEN molecules set the boiling point.
CWater molecules are much heavier than O₂ molecules, and heavier molecules always boil higher.
This option is wrong — you reached for size — the two molecules are similar in size, which is exactly why the force difference must explain the gap.
DLiquid water contains dissolved minerals that hold its molecules together.
This option is wrong — you credited impurities — pure water itself boils at 100 °C, because its own molecules hydrogen-bond to each other.
Boiling has to pull molecules away from each other, so stronger attractions need more energy to overcome. Between water molecules the attraction is hydrogen bonding; between O₂ molecules it is only dispersion. Water's much stronger hydrogen bonding is why it boils 283 degrees higher.
Check your understanding
Which attraction is responsible for water's unusually high boiling point?
AHydrogen bonding between water molecules.correct
BDispersion forces between water molecules.
This option is wrong — you picked the weakest attraction — dispersion acts between all molecules, but it is water's much stronger hydrogen bonding that lifts its boiling point.
CThe covalent bonds within each water molecule.
This option is wrong — you looked inside the molecule — the O–H bonds stay intact during boiling; the boiling point is set by attractions between molecules.
DAttractions between water molecules and the container walls.
This option is wrong — you brought in the container — boiling is molecules escaping each OTHER, and it happens the same way in any container.
Water molecules attract one another through hydrogen bonding. That hydrogen bonding is much stronger than the attractions between other similar-size molecules. Stronger attractions need more energy to overcome, so water boils unusually high.
Check your understanding
At 100 °C, boiling finally separates liquid water's molecules from one another. What is true of each escaping H₂O molecule?
AIt leaves intact — the energy overcame hydrogen bonds between molecules, not covalent bonds within them.correct
BIt splits into hydrogen and oxygen atoms as it escapes.
This option is wrong — you broke the molecule — the attractions between molecules give way first, because they are much weaker than the bonds within them.
CIt escapes only after its O–H covalent bonds absorb enough energy to break.
This option is wrong — you sent the energy to the wrong target — boiling water produces whole H₂O molecules, so the covalent bonds never break.
DIt drags a cluster of neighboring molecules along with it, with all of their hydrogen bonds still intact.
This option is wrong — you kept the attractions attached — escaping IS breaking free of the hydrogen bonds to the neighbors.
Boiling has to pull molecules away from each other. In water, that means overcoming hydrogen bonds between molecules — the strongest attractions a small molecule can have. Each H₂O molecule leaves whole; only the attractions between molecules are overcome.
Lesson 59 of 70 · CMB-059
Molecular vs ionic properties
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Have You Ever Wondered?
Wonder this:
An ice cube melts in your hand. A grain of table salt shrugs off a 500 °C flame and needs 801 °C before it melts. Both are small, hard, colorless crystals — why is one so easy to melt and the other so stubborn?
You've already seen the two kinds of attraction involved. Intermolecular forces are much weaker than covalent bonds, and in an ionic solid the ions are held in a repeating lattice by attraction between opposite charges acting in every direction. Melting puts those two arrangements to the test.
The idea
Melting a solid means giving its particles enough energy to break out of their fixed positions.
What melting must overcome depends on what holds the particles in place.
In a molecular solid like ice, the molecules are held to each other only by intermolecular forces.
Intermolecular forces are much weaker than covalent bonds, so a little energy frees the molecules — ice melts at 0 °C.
Melting ice breaks only weak attractions between intact molecules; melting sodium chloride must overcome attractions running through the whole lattice.
In an ionic solid like sodium chloride, the ions are held in a repeating lattice by attraction between opposite charges acting in every direction.
Freeing ions from that lattice takes far more energy — sodium chloride melts at 801 °C.
So molecular substances typically melt low, and ionic substances typically melt high, because melting overcomes weak attractions between molecules in one case and strong lattice-wide attractions in the other.
Worked examples
Worked example 1. Naphthalene, the molecular solid in mothballs, melts at 80 °C. Magnesium oxide, an ionic solid, melts at 2852 °C. Explain the difference.
Step 1
Ask what melting must overcome in each solid.
Step 2
Naphthalene is molecular: melting only has to overcome the weak intermolecular forces between its molecules.
Step 3
Magnesium oxide is ionic: melting has to free ions held in a repeating lattice by attraction between opposite charges acting in every direction.
Step 4
The lattice-wide attractions need far more energy to overcome than the weak attractions between molecules.
Step 5
Naphthalene melts at 80 °C because only weak intermolecular forces must be overcome; magnesium oxide needs 2852 °C because strong lattice-wide attractions must be overcome.
Worked example 2. Methane, a molecular substance, melts at −182 °C. Lithium fluoride, an ionic substance, melts at 845 °C. Why is the gap more than 1000 degrees?
Step 1
Ask what melting must overcome in each solid.
Step 2
Methane's molecules are held to each other only by weak dispersion forces, so barely any energy frees them.
Step 3
Lithium fluoride's ions are held in a repeating lattice by attraction between opposite charges acting in every direction.
Step 4
Overcoming attractions throughout a lattice takes far more energy than overcoming weak attractions between molecules.
Step 5
The gap exists because melting methane overcomes weak attractions between molecules, while melting lithium fluoride overcomes strong attractions running through the whole lattice.
You can now explain the difference in melting points between molecular and ionic substances in terms of the forces that must be overcome, weak attractions between molecules versus strong attractions throughout an ionic lattice.
Check your understanding
Iodine, I₂, a molecular solid, melts at 114 °C. Potassium fluoride, an ionic solid, melts at 858 °C. Why does potassium fluoride need so much more energy to melt?
AIts ions are held by charge attractions acting in every direction; iodine's molecules are held only by weak attractions.correct
BMelting potassium fluoride must break the strong covalent bonds that hold the atoms together inside each of its molecules.
This option is wrong — you gave an ionic solid molecules — potassium fluoride has no molecules; it is a lattice of ions held by charge attraction in every direction.
CMelting iodine breaks the I–I covalent bond, which is unusually weak.
This option is wrong — you melted through the bond — the I₂ molecules leave intact; melting only overcomes the attractions BETWEEN the molecules.
DPotassium fluoride's particles are heavier, and heavier particles always melt higher.
This option is wrong — you used mass — an I₂ molecule is actually heavier than a K⁺ or F⁻ ion; the difference is the strength and reach of the attractions being overcome.
Ask what melting must overcome in each solid. Iodine is molecular: only weak intermolecular forces hold its molecules together, so 114 °C frees them. Potassium fluoride's ions are held in a repeating lattice by attraction between opposite charges acting in every direction — freeing them needs 858 °C.
Check your understanding
A white crystalline solid melts at −101 °C. Based on its melting point, which description of the solid fits best?
AA molecular solid — melting it overcomes only weak attractions between molecules.correct
BAn ionic solid — melting it overcomes lattice attractions acting in every direction.
This option is wrong — you matched a lattice to a tiny melting energy — attractions acting in every direction through a lattice are never overcome at −101 °C.
CAn ionic solid whose ions carry unusually small charges.
This option is wrong — you kept the lattice and shrank the charges — even the smallest ionic charges produce melting points hundreds of degrees higher than this.
DA molecular solid whose covalent bonds are unusually weak.
This option is wrong — you melted through the bonds — a molecular solid's covalent bonds do not break on melting; the low melting point reflects its weak intermolecular forces.
A melting point of −101 °C means very little energy frees the particles. Only weak attractions between molecules give way that easily. The solid is molecular. (It is in fact solid chlorine, Cl₂.)
Check your understanding
Camphor, a molecular solid used in balms, melts at 175 °C. Potassium chloride, an ionic solid, melts at 770 °C. Which statement explains the two melting points?
ACamphor's molecules are held only by weak attractions; potassium chloride's ions are held by lattice-wide charge attractions.correct
BCamphor's covalent bonds are much weaker than the covalent bonds that hold the particles of potassium chloride together in its crystal.
This option is wrong — you compared covalent bonds — melting camphor leaves every molecule intact, and potassium chloride is ionic, with no covalent bonds to compare.
CPotassium chloride melts higher because its crystals are larger than camphor crystals.
This option is wrong — you used crystal size — melting point comes from the strength of the attractions being overcome, not from how big the crystal grew.
DCamphor melts low because its molecules repel each other once the temperature rises.
This option is wrong — you invented a repulsion — camphor's molecules keep attracting each other; 175 °C is simply enough energy to overcome those weak attractions.
Ask what melting must overcome in each solid. Camphor is molecular: weak attractions between intact molecules give way at 175 °C. Potassium chloride is ionic: its ions are held in a repeating lattice by attraction between opposite charges acting in every direction, so it holds firm to 770 °C.
Lesson 60 of 70 · CMB-060
Structure decides what materials do
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Did You Know?
Wonder this:
Rain hits a freshly waxed car and rolls off in tight, round beads. On the unwaxed hood next to it, the same rain flattens out and clings. The wax has no moving parts and no power source — whatever it is doing, it is doing it molecule by molecule.
You've already seen how polarity decides which intermolecular forces a substance's molecules can form. Materials designers use that link in reverse: pick molecules whose attractions produce the property you want.
The idea
A designed material works because of what its molecules are like.
To explain a material's property, connect three things: the molecular structure, the attractions it allows, and the job the material does.
Wax molecules are nonpolar, so the only attraction they can offer a water molecule is weak dispersion.
Water molecules attract each other strongly through hydrogen bonding.
On a waxed surface, water molecules hold on to each other far more strongly than the wax holds on to them.
So the water pulls itself into beads and rolls off — the wax coating sheds water.
Water beads on wax because it attracts itself far more strongly than the nonpolar wax attracts it.
Strong attractions do the opposite job: molecules built to attract their neighbors strongly make materials that hold on — to water, to other surfaces, or to each other.
Worked examples
Worked example 1. A nonstick pan is coated with a fluoropolymer whose molecules are nonpolar. Explain why watery sauces slide off the coating instead of sticking.
Step 1
Structure: the coating's molecules are nonpolar.
Step 2
Attractions: nonpolar molecules offer the sauce's water only weak dispersion forces.
Step 3
The water molecules attract each other through hydrogen bonding, far more strongly than the coating attracts them.
Step 4
Job: the sauce holds itself together, pulls away from the surface, and slides off.
Step 5
The nonpolar coating attracts the watery sauce only weakly, so the sauce clings to itself instead of the pan and slides off.
Worked example 2. Kevlar's long chain molecules carry N–H groups that hydrogen-bond to the O atoms of neighboring chains. Explain why Kevlar fibers are strong enough for protective vests.
Step 1
Structure: each chain carries hydrogen atoms bonded to nitrogen, close to oxygen atoms on the neighboring chains.
Step 2
Attractions: the chains grip each other through many hydrogen bonds along their whole length.
Step 3
Pulling the fibers apart means overcoming all of those attractions at once.
Step 4
Job: the fiber resists being pulled apart, so the vest stops what hits it.
Step 5
Kevlar is strong because hydrogen bonds all along the neighboring chains must be overcome together before the fibers separate.
You can now explain how the molecular-level structure of a designed material produces a property the material is used for, in terms of its polarity or its intermolecular forces.
Check your understanding
A windshield treatment coats the glass with nonpolar molecules, and rain then flies off in beads as the car moves. Why does the coating shed water?
AThe nonpolar coating offers water only weak dispersion attractions, so the water molecules hold on to each other and pull into beads.correct
BThe nonpolar coating repels the water molecules, pushing the drops away.
This option is wrong — you turned weak attraction into repulsion — the coating still attracts water, just far more weakly than water attracts itself.
CThe coating's molecules hydrogen-bond to each raindrop and then fling the drops off as the moving glass vibrates beneath them at speed.
This option is wrong — you gave a nonpolar molecule hydrogen bonding — hydrogen bonding needs hydrogen bonded to N, O, or F, which a nonpolar coating does not offer.
DThe coating dissolves the outer layer of each raindrop, letting the rest slide.
This option is wrong — you brought in dissolving — nothing dissolves here; the beading comes from water gripping itself more strongly than the coating grips it.
Structure: the coating's molecules are nonpolar. Attractions: water gets only weak dispersion from the coating, while its own molecules hydrogen-bond strongly. Job: the water pulls itself into beads and leaves the glass.
Check your understanding
Glycerin, an ingredient in skin moisturizers, is a small molecule carrying three O–H groups. Why does a glycerin film keep skin moist?
AEach O–H group hydrogen-bonds to water molecules, so the film holds water against the skin instead of letting it escape.correct
BGlycerin is a nonpolar molecule, so it seals water out of the skin the same way a coat of wax seals water away from a car.
This option is wrong — you classified glycerin from its job, not its structure — a molecule with three O–H groups is strongly polar and works by holding water, not by shedding it.
CGlycerin's covalent bonds break open and capture passing water molecules.
This option is wrong — you broke covalent bonds — holding water takes only intermolecular attraction; the hydrogen bonds form between intact molecules.
DGlycerin molecules are too large for water molecules to move past.
This option is wrong — you built a physical wall — glycerin is a small molecule; it keeps water by attracting it, not by blocking it.
Structure: three O–H groups on each glycerin molecule. Attractions: hydrogen bonds form between those O–H groups and water molecules. Job: the film grips water molecules, keeping the skin moist.
Check your understanding
A designer must pick a tent-fabric coating that makes rain bead up and roll off. Which coating molecule should the designer choose?
AA nonpolar molecule, so the fabric offers rain only weak dispersion attractions.correct
BA molecule carrying many O–H groups, so the fabric hydrogen-bonds to the rain.
This option is wrong — you chose the water-gripping structure — hydrogen bonding would hold the rain against the fabric, the opposite of shedding it.
CA strongly polar molecule, so the fabric's charged ends pull the raindrops flat.
This option is wrong — you chose strong attraction for a shedding job — a polar surface attracts water strongly and makes it spread, not bead.
DAny molecule at all, because beading depends on the weave of the fabric, not the coating.
This option is wrong — you ignored the molecular level — beading happens when water attracts itself more strongly than the surface attracts it, and that is set by the coating's polarity.
The job is shedding water, so the fabric must attract water only weakly. A nonpolar coating offers water nothing stronger than dispersion. The rain then grips itself, beads up, and rolls off.
Every living thing on Earth — and the fuel in a camp stove, and the plastic of your pen — is built around the same element: carbon. One bonding habit explains its starring role.
You've already predicted how many bonds an atom typically forms from its octet. For carbon, the answer is worth knowing on sight.
The idea
A carbon atom forms four covalent bonds.
In methane, CH₄, the carbon forms four single bonds, one to each hydrogen.
Count the lines at a carbon atom in any correct structure and you will count four.
Methane: the carbon atom forms four covalent bonds.
A double bond counts as two of the four, and a triple bond counts as three.
Four bonds, every time — that fact anchors everything else about carbon compounds.
Worked examples
Worked example 1. How many covalent bonds does the carbon atom in CF₄ form?
Step 1
Answer: four — one single bond to each fluorine.
Worked example 2. In H₂CO, the carbon has single bonds to two hydrogens and a double bond to oxygen. How many bonds is the carbon forming in total?
Step 1
Answer: four — the double bond counts as two.
You can now state that a carbon atom forms four covalent bonds.
Check your understanding
How many covalent bonds does the carbon atom in CHCl₃ form?
Answer: 4bonds
A carbon atom forms four covalent bonds. In CHCl₃ that is one bond to hydrogen and three bonds to chlorine. 1 + 3 = 4 bonds.
Check your understanding
In carbon dioxide, O=C=O, how many covalent bonds does the carbon atom form in total?
AFour — each double bond counts as two.correct
BTwo — one bond to each oxygen atom.
This option is wrong — you counted attached atoms instead of bonds — each O=C link is a DOUBLE bond, worth two of carbon's four.
CEight — the octet number.
This option is wrong — you counted the electrons around carbon — eight electrons, yes, but they sit in four shared pairs, so the bond count is four.
DSix — counting three for each double bond.
This option is wrong — you counted a double bond as three — a double bond is two shared pairs, so it counts as two bonds.
A carbon atom forms four covalent bonds. Each double bond in O=C=O counts as two. 2 + 2 = 4 bonds.
Check your understanding
Which statement about carbon's bonding is correct?
AA carbon atom forms four covalent bonds.correct
BA carbon atom forms two covalent bonds.
This option is wrong — you gave carbon oxygen's typical count — carbon's count is four.
CA carbon atom forms eight covalent bonds.
This option is wrong — you turned the octet's eight electrons into eight bonds — the eight electrons sit in four shared pairs, so the count is four.
DA carbon atom's bond count changes from molecule to molecule.
This option is wrong — you let the count float — the mix of single, double, and triple bonds changes, but the total is four in every stable molecule.
The fact to keep: a carbon atom forms four covalent bonds. Singles, doubles, and triples can combine in different ways. The total at each carbon is always four.
Lesson 62 of 70 · CMB-062
Why carbon makes four bonds
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Did You Know?
You've already seen the fact: a carbon atom forms four covalent bonds. The octet arithmetic you used for other atoms explains why the number is four and not three or five.
The idea
Carbon sits in Group 14, so a carbon atom has four valence electrons.
A complete octet is eight electrons.
Carbon therefore needs four more electrons: 8 − 4 = 4.
Every shared pair counts fully for both atoms, so each bond carbon forms adds one more electron to its count.
Carbon forms four bonds because it has four valence electrons and needs four more to complete its octet, so it shares four pairs.
In methane, CH₄, carbon's four own electrons plus one from each of four hydrogens put eight electrons around the carbon.
Fewer than four bonds would leave the octet short; more than four would overfill it.
Carbon's four electrons plus one from each hydrogen complete the octet: 4 + 4 = 8.
Worked examples
Worked example 1. In CF₄, show that the carbon atom's four bonds complete its octet.
Step 1
Carbon brings four valence electrons of its own.
Step 2
Each of the four C–F bonds is a shared pair contributing one fluorine electron to carbon's count.
Step 3
Count around the carbon: 4 + 4 = 8 electrons.
Step 4
Four bonds give carbon a complete octet of eight electrons.
Worked example 2. In CO₂ the carbon forms two double bonds. Explain why that still fits carbon's octet arithmetic.
Step 1
Two double bonds are four shared pairs in total.
Step 2
Each shared pair adds one oxygen electron to carbon's count.
Step 3
Count around the carbon: 4 own + 4 shared-in = 8 electrons.
Step 4
Two double bonds are still four shared pairs, so carbon's octet is complete.
You can now explain why carbon forms four bonds, because it has four valence electrons and needs four more to complete its octet, so it shares four pairs.
Check your understanding
A carbon atom has four valence electrons. How many more electrons does it need to complete its octet?
Answer: 4electrons
A complete octet is eight electrons. Carbon brings four of its own. 8 − 4 = 4 more electrons needed — which is why carbon shares four pairs.
Check your understanding
Why does a carbon atom form exactly four covalent bonds?
ABecause it has four valence electrons and needs four more to complete its octet, so it shares four pairs.correct
BBecause it has four valence electrons and gives all four of them away, leaving four empty spaces to fill.
This option is wrong — you turned sharing into losing — carbon keeps its four electrons and adds four more by sharing, one per bond.
CBecause it needs eight more electrons, and each bond supplies two of them.
This option is wrong — you forgot carbon's own four — it needs only 8 − 4 = 4 more, and each shared pair adds one partner electron to its count.
DBecause four is the number of atoms that physically fit around a carbon atom.
This option is wrong — you made it about space — the count comes from octet arithmetic, not room; the same carbon can reach four with only two neighbors, as in CO₂.
Carbon has four valence electrons; a complete octet is eight. 8 − 4 = 4 more electrons needed. Each shared pair adds one, so carbon shares four pairs — four bonds.
Check your understanding
In CCl₄, count the electrons around the carbon atom to check its octet. Which count is correct?
A4 of carbon's own + 4 shared in from the chlorines = 8.correct
B4 of carbon's own + 8 shared in from the chlorines = 12.
This option is wrong — you counted both electrons of each shared pair as incoming — one electron of each pair is already carbon's own, so only one per bond is new.
C0 of carbon's own + 8 shared in from the chlorines = 8.
This option is wrong — you took carbon's own electrons away — carbon keeps its four; the chlorines supply only one electron per shared pair.
D4 of carbon's own + 4 shared in = 8, minus 4 given to the chlorines = 4.
This option is wrong — you made carbon pay for sharing — a shared pair counts fully for BOTH atoms, so nothing is subtracted.
Carbon brings four valence electrons. Each of the four C–Cl shared pairs adds one chlorine electron to carbon's count. 4 + 4 = 8 — a complete octet.
Lesson 63 of 70 · CMB-063
Carbon chains and rings
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Did You Know?
You've already seen that every carbon atom forms four covalent bonds. Carbon's special trick is what it does with them: it spends them on other carbon atoms.
The idea
Carbon atoms bond to one another.
Carbon after carbon can link into a 'chain' — in propane, three carbons form a three-carbon chain.
A chain can fork where a carbon bonds to three or four other carbons, making a 'branched chain'.
Three carbon skeletons: a chain, a branched chain, and a ring. Hydrogens are omitted so the skeletons stand out.
A chain can also close into a loop, making a 'ring'.
Whatever the carbon skeleton — chain, branched chain, or ring — other atoms attach along the way, filling each carbon's four bonds.
These skeletons are the frames on which every carbon compound is built.
Worked examples
Worked example 1. Pentane's five carbon atoms are bonded one after another, none bonded to more than two other carbons. What kind of skeleton is that?
Step 1
Answer: a straight chain.
Worked example 2. Cyclopentane's five carbon atoms are bonded in a closed loop. What kind of skeleton is that?
Step 1
Answer: a ring.
You can now state that carbon atoms bond to one another to form chains, branched chains, and rings, with other atoms attached along the way.
Check your understanding
The figure shows the carbon skeleton of a molecule. What kind of skeleton is it?
Hydrogens omitted for clarity.
AA straight chaincorrect
BA branched chain
This option is wrong — you saw a fork that is not there — every carbon here bonds to at most two other carbons, so the row never branches.
CA ring
This option is wrong — you closed the loop yourself — the two end carbons are not bonded to each other, so the skeleton stays open.
DNone of the above
This option is wrong — you passed on a clean case — an unbranched open row of carbons is exactly what 'straight chain' names.
Trace the carbons: they run one after another with no fork. The two ends are not joined, so the skeleton is open. An open, unbranched row is a straight chain.
Check your understanding
The figure shows the carbon skeleton of a molecule. What kind of skeleton is it?
Hydrogens omitted for clarity.
AA ringcorrect
BA straight chain
This option is wrong — you missed the closing bond — the last carbon bonds back to the first, so the skeleton is a loop, not an open row.
CA branched chain
This option is wrong — you read the corner as a fork — no carbon here carries a side group; the three carbons simply close into a loop.
DNone of the above
This option is wrong — you passed on a clean case — carbons joined in a closed loop are exactly what 'ring' names.
Trace the carbons: each one bonds to the next, and the last bonds back to the first. A closed loop of carbons is a ring. Rings can be any size — this one has three carbons.
Check your understanding
The figure shows the carbon skeleton of a molecule. What kind of skeleton is it?
Hydrogens omitted for clarity.
AA branched chaincorrect
BA straight chain
This option is wrong — you overlooked the fork — the second carbon bonds to THREE other carbons, which makes the skeleton branch.
CA ring
This option is wrong — you closed a loop that is not there — no bond joins the ends back together; the skeleton is open but forked.
DNone of the above
This option is wrong — you passed on a clean case — an open skeleton with a fork is exactly what 'branched chain' names.
Trace the carbons: four run in a row, and a fifth hangs off the second one. A carbon bonded to three other carbons makes a fork. An open skeleton with a fork is a branched chain.
Lesson 64 of 70 · CMB-064
Why carbon compounds are so diverse
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Have You Ever Wondered?
Wonder this:
Chemists have catalogued tens of millions of different compounds, and most of them are built on carbon. Silicon, carbon's neighbor, manages only a tiny fraction of that. What is carbon doing that almost no other element can?
You've already seen the two ingredients: carbon forms four strong covalent bonds, and carbon atoms bond to one another in chains, branched chains, and rings. Put the two together and the numbers explode.
The idea
Four bonds per carbon, spendable on other carbons, means skeletons of any size and shape: long chains, forks, and rings.
The same set of atoms can usually be assembled onto more than one skeleton.
Every different arrangement of the same atoms is a different compound.
Different arrangements have different properties — a different shape means different attractions and different behavior.
The formula C₅H₁₂ can be built three ways: a five-carbon chain, a branched four-carbon chain, and a doubly branched three-carbon chain.
Those three arrangements are three different compounds, with three different boiling points.
One formula, three skeletons — three different compounds. Hydrogens omitted for clarity.
Skeleton choices multiply with every carbon added — which is why carbon compounds number in the tens of millions.
Worked examples
Worked example 1. The formula C₄H₁₀ can be assembled two ways: four carbons in a chain, or three carbons in a chain with the fourth branching off the middle. How many different compounds is that, and why?
Step 1
Compare the arrangements: one skeleton is a straight chain, the other is branched.
Step 2
Every different arrangement of the same atoms is a different compound.
Step 3
The two skeletons are different arrangements.
Step 4
Two different compounds — same atoms, two arrangements.
Worked example 2. Hydrogen atoms form only one bond each. Explain why hydrogen cannot build a family of compounds the way carbon does.
Step 1
Building a skeleton needs atoms that can bond to two or more neighbors at once.
Step 2
A hydrogen atom's single bond is used up on its first neighbor.
Step 3
So hydrogen can only cap the end of a structure, never extend one.
Step 4
With one bond each, hydrogen atoms cannot link into chains, branches, or rings — no skeletons, so no compound family.
You can now explain why carbon's four strong bonds and its ability to bond to itself make an enormous number of different carbon compounds possible, because every different arrangement of the same atoms is a different compound.
Check your understanding
The formula C₆H₁₄ can be assembled onto five different carbon skeletons. How many different compounds share that formula?
AFive — every different arrangement of the same atoms is a different compound.correct
BOne — the formula is the compound, however the atoms are arranged.
This option is wrong — you let the formula stand for the compound — the arrangement matters, and five arrangements are five compounds.
CFive, but they are really just five samples of one single compound caught in different poses.
This option is wrong — you treated the skeletons as poses — a branched skeleton cannot be straightened without breaking bonds, so each skeleton is a genuinely different compound.
DCannot say — the number of compounds depends on temperature.
This option is wrong — you made identity depend on conditions — the count of arrangements is fixed by the bonding, not by temperature.
Every different arrangement of the same atoms is a different compound. C₆H₁₄ has five possible skeletons. Five arrangements — five different compounds.
Check your understanding
Which two facts about carbon, taken together, explain why carbon compounds number in the tens of millions?
ACarbon forms four strong bonds, and carbon atoms bond to one another into chains, branches, and rings.correct
BCarbon is the most abundant element on Earth, and it forms four bonds.
This option is wrong — you leaned on abundance — carbon is not Earth's most abundant element, and abundance alone builds no variety; the skeleton-building does.
CCarbon atoms bond to one another, and carbon compounds are all gases.
This option is wrong — you added a false property — carbon compounds span solids, liquids, and gases; the diversity comes from four bonds plus self-bonding.
DCarbon forms four strong bonds, and every carbon compound has exactly one possible arrangement of its atoms.
This option is wrong — you removed the multiplier — it is because the SAME atoms allow MANY arrangements that the compound count explodes.
Ingredient 1: four strong bonds at every carbon. Ingredient 2: carbon atoms bond to one another into chains, branches, and rings. Many skeletons per formula, and every different arrangement is a different compound.
Check your understanding
Oxygen atoms form two bonds each. Why can oxygen not build huge families of skeleton-based compounds the way carbon does?
AWith only two bonds, an oxygen atom can never fork, so almost no different arrangements are possible.correct
BOxygen atoms are too small to bond to one another at all.
This option is wrong — you banned the O–O bond — oxygen atoms can bond to each other; the shortage is bonds per atom, which kills branching.
COxygen's two bonds are so strong that its atoms can never be rearranged into differently shaped skeletons.
This option is wrong — you blamed bond strength — strong bonds are what carbon uses; the limit is that two bonds allow no forks.
DOxygen cannot form compounds with hydrogen, so its families never start.
This option is wrong — you erased water — H₂O itself is an oxygen-hydrogen compound; the missing ingredient is a four-bond atom to build skeletons from.
Variety comes from skeletons: chains that fork, loop, and carry attached groups. A two-bond atom in a chain has both bonds spent on its neighbors — nothing left to branch with. Carbon's four bonds leave two spare at every chain position, and that is where the variety comes from.
Lesson 65 of 70 · CMB-065
Reading structural formulas
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Did You Know?
You've already read Lewis diagrams, where every line is one shared pair. Carbon compounds are usually drawn in a close cousin called a structural formula — same lines, bigger molecules, and usually no lone pairs shown.
The idea
A 'structural formula' shows every atom by its symbol and every bond as a line.
Each line stands for one shared pair of electrons, exactly as in a Lewis diagram.
Two lines between atoms are a double bond; three lines are a triple bond.
To read a structural formula: count the atoms of each element, then trace the bonds between them.
Ethane's structural formula shows two carbon atoms joined by a single C–C bond, each carbon also bonded to three hydrogens.
Check any carbon in a correct structural formula and its lines total four.
Ethane's structural formula: every atom shown, every bond a line, four lines at each carbon.
Worked examples
Worked example 1. Read the structural formula of propane (shown): three carbons in a row, each end carbon bonded to three hydrogens, the middle carbon bonded to two. How many atoms of each element does the molecule contain, and how many C–C bonds?
Step 1
Count the carbons: 3.
Step 2
Count the hydrogens: 3 + 2 + 3 = 8.
Step 3
Trace the carbon–carbon bonds: two lines join the three carbons.
Step 4
Propane is C₃H₈, with two C–C single bonds.
Worked example 2. Read the structural formula of ethene (shown): two carbons joined by two lines, each carbon also bonded to two hydrogens. What do the two lines between the carbons stand for?
Step 1
Each line is one shared pair.
Step 2
Two lines are two shared pairs — a double bond.
Step 3
The two lines are a C=C double bond: two shared pairs of electrons.
You can now identify the atoms and the bonds in a structural formula of a simple carbon compound, where each line stands for one shared pair.
Check your understanding
The figure shows the structural formula of butane. Reading the structure, write the molecular formula of butane.
Accepted answer: C₄H₁₀
Count the carbons: four in the row. Count the hydrogens: 3 + 2 + 2 + 3 = 10. The molecular formula is C₄H₁₀.
Check your understanding
The figure shows the structural formula of chloromethane. Which reading of the structure is correct?
AOne carbon bonded to three hydrogens and one chlorine, all by single bonds.correct
BOne carbon bonded to three hydrogens and one chlorine, with the C–Cl line showing a double bond.
This option is wrong — you promoted a single line — one line is one shared pair; a double bond would be drawn as two lines.
CThree separate CH molecules attached to one chlorine.
This option is wrong — you broke the molecule apart — all five atoms are bonded into ONE molecule around the central carbon.
DOne carbon bonded to four hydrogens, one of them drawn as Cl by mistake.
This option is wrong — you overruled the symbols — the symbols are the atoms: Cl is chlorine, and the structure means what it shows.
Read the symbols: one C, three H, one Cl. Trace the lines: four single lines leave the carbon, one to each atom. Four lines at the carbon — the count checks out.
Check your understanding
The figure shows the structural formula of ethyne. What do the three lines between the two carbons stand for?
AThree shared pairs of electrons — a triple bond.correct
BThree separate single bonds joining three pairs of carbon atoms.
This option is wrong — you multiplied the atoms — there are only two carbons; the three lines all run between the same two atoms.
COne shared pair drawn three times for emphasis.
This option is wrong — you read the lines as decoration — every line is its own shared pair, so three lines are three pairs.
DSix shared pairs of electrons.
This option is wrong — you counted each line as a pair of pairs — one line is ONE shared pair, so three lines are three pairs, six electrons.
Each line stands for one shared pair. Three lines between the carbons are three shared pairs. Three shared pairs are a triple bond — and with one C–H line each, every carbon's count is 3 + 1 = 4.
Lesson 66 of 70 · CMB-066
Functional groups
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Did You Know?
Wonder this:
Ethane is a stove fuel you must keep away from your face. Bolt one oxygen and one hydrogen onto it and you get ethanol — the liquid in hand sanitizer. Almost the whole molecule is unchanged, yet nearly everything about how it behaves is different.
You've already read structural formulas of carbon compounds. The behavior of those compounds usually traces back to one small piece of the structure.
The idea
In a carbon compound, a small group of atoms often controls how the whole compound behaves.
Such a property-giving cluster is called a 'functional group'.
In ethanol, the –OH pair of atoms is the functional group; the two-carbon frame around it behaves much like plain ethane.
The same functional group brings similar behavior to whatever carbon frame carries it.
Read a carbon compound in two parts: the carbon frame, and the functional group that controls its behavior.
So chemists read a carbon compound in two parts: the carbon skeleton, and the functional groups attached to it.
Spot the group, and you can predict the behavior — that shortcut is the next three lessons.
Worked examples
Worked example 1. Methanol's structure is a one-carbon frame carrying the same –OH cluster as ethanol. What is the –OH cluster called?
Step 1
Answer: a functional group.
Worked example 2. Two compounds carry the same functional group on different carbon frames. What should you expect about their behavior?
Step 1
Answer: similar characteristic behavior — the group, not the frame, controls it.
You can now state that a functional group is a small group of atoms in a carbon compound that gives the compound its characteristic properties.
Check your understanding
In a carbon compound, what is a functional group?
AA small group of atoms that gives the compound its characteristic properties.correct
BThe longest continuous chain of carbon atoms that can be traced through the compound.
This option is wrong — you named the frame — the skeleton holds the molecule together, but the small attached group is what controls the behavior.
CAny pair of atoms joined by a double bond.
This option is wrong — you made it about multiplicity — a functional group is defined by what it DOES (giving characteristic properties), not by containing a double bond.
DA group of molecules that function together in a mixture.
This option is wrong — you moved up a level — a functional group is a cluster of ATOMS inside one molecule, not a team of molecules.
A functional group is a small group of atoms in a carbon compound. It gives the compound its characteristic properties. The carbon frame carries it; the group does the behaving.
Check your understanding
Butanol is a four-carbon frame carrying an –OH cluster, and that cluster gives butanol its characteristic behavior. In butanol, the –OH cluster is best described as what?
AA functional group.correct
BA carbon skeleton.
This option is wrong — you swapped the two parts — the skeleton is the four-carbon frame; the small property-giving cluster attached to it is the functional group.
CA separate molecule attached to butanol.
This option is wrong — you detached the group — the –OH is covalently bonded into the butanol molecule, not a molecule of its own.
DAn ion carrying a negative charge.
This option is wrong — you charged the group — the –OH here is a neutral, covalently bonded cluster of atoms, not the hydroxide ion.
A property-giving cluster of atoms in a carbon compound is a functional group. The –OH in butanol is exactly that. The four-carbon frame is the skeleton; the –OH is the functional group.
Check your understanding
Two carbon compounds carry the same functional group — one on a three-carbon frame, one on a seven-carbon frame. What should you expect when comparing their characteristic behavior?
ASimilar characteristic behavior, because the shared group controls it.correct
BCompletely unrelated behavior, because the frames are different sizes.
This option is wrong — you handed control to the frame — the functional group gives the compound its characteristic properties, so a shared group means shared behavior.
CIdentical behavior in every measurable property.
This option is wrong — you erased the frame entirely — the frame still nudges properties like boiling point; the group makes behavior SIMILAR, not identical.
DNo prediction is possible without testing both compounds.
This option is wrong — you gave up the shortcut — the whole point of spotting functional groups is that the group lets you predict characteristic behavior.
The functional group gives a compound its characteristic properties. A shared group means the two compounds behave in the same characteristic way. The frame size still tunes details, so 'similar', not 'identical'.
Lesson 67 of 70 · CMB-067
The hydroxyl group
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Did You Know?
You've already seen that a functional group gives a carbon compound its characteristic properties. Here is the first named group — the one in ethanol.
The idea
An oxygen bonded to a hydrogen, attached to a carbon frame, is written –OH.
This group is called the 'hydroxyl group'.
In ethanol's structure, the hydroxyl group is the O–H on the second carbon.
To spot a hydroxyl group, look for an O bonded to exactly one H and one carbon of the frame.
The hydroxyl group: an O–H on the carbon frame. It hydrogen-bonds to water, so hydroxyl compounds mix well with water.
The hydroxyl group's hydrogen is bonded to oxygen, so hydroxyl compounds can form hydrogen bonds.
Hydrogen bonding to water molecules is why hydroxyl compounds mix well with water.
One glance at –OH therefore predicts a behavior: the compound is a good mixer with water.
Worked examples
Worked example 1. Propanol's structure (shown) is a three-carbon chain whose end carbon is bonded to an O, which is bonded to an H. Identify the functional group and the behavior it predicts.
Step 1
Look for an O bonded to one H and one frame carbon: the end O–H fits.
Step 2
That group is the hydroxyl group, –OH.
Step 3
The hydroxyl group lets the molecule hydrogen-bond to water.
Step 4
Propanol carries a hydroxyl group, so it should mix well with water — and it does.
Worked example 2. Glycerin's structure (shown) is a three-carbon chain in which EACH carbon is bonded to an O–H. How many hydroxyl groups does glycerin carry?
Step 1
Check each O: every one is bonded to one H and one frame carbon.
Step 2
Each O–H on the frame is one hydroxyl group.
Step 3
Count them: one per carbon, three carbons.
Step 4
Glycerin carries three hydroxyl groups — which is why it grips water so well.
You can now identify the hydroxyl group, –OH, in a structural formula and state that it lets the molecule form hydrogen bonds, so hydroxyl compounds mix well with water.
Check your understanding
The figure shows the structural formula of butanol with four bonds labeled A to D. Which label marks the hydroxyl group?
ACcorrect
BA
This option is wrong — you picked a C–H bond — the hydroxyl group is an OXYGEN bonded to a hydrogen, not a carbon bonded to one.
CB
This option is wrong — you picked the C–C frame — the skeleton holds the molecule together, but the hydroxyl group is the O–H cluster.
DD
This option is wrong — you stopped at the C–O bond — that bond attaches the group to the frame; the group itself is the O with its H.
Look for an O bonded to one H and one frame carbon. Label C sits on exactly that O–H cluster. That is the hydroxyl group, –OH.
Check your understanding
Write the two-atom cluster of a hydroxyl group as it is written in structural formulas.
Accepted answer: –OH
The hydroxyl group is one oxygen bonded to one hydrogen, attached to a carbon frame. It is written –OH, with the dash marking the bond to the frame. No charge — it is not the hydroxide ion.
Check your understanding
Rubbing alcohol's active molecule carries a hydroxyl group. Why does it mix well with the water it is sold diluted in?
AThe hydroxyl group's O–H hydrogen-bonds to water molecules.correct
BThe hydroxyl group makes the molecule nonpolar, and water is nonpolar too.
This option is wrong — you flipped both polarities — the O–H is a polar cluster, water is polar, and the mixing comes from hydrogen bonding between them.
CThe hydroxyl group breaks apart in water, releasing its H atom into the mixture.
This option is wrong — you broke a covalent bond — the –OH stays bonded to its frame; mixing needs only intermolecular attraction.
DThe carbon frame attracts the water while the hydroxyl group does nothing.
This option is wrong — you handed the job to the frame — the frame offers water only weak dispersion; the O–H is what hydrogen-bonds to water.
The hydroxyl group's hydrogen is bonded to oxygen. H bonded to O can hydrogen-bond — including to the O of a water molecule. Those hydrogen bonds are why hydroxyl compounds mix well with water.
Lesson 68 of 70 · CMB-068
The carboxyl group
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Did You Know?
You've already spotted the hydroxyl group. The second named group looks like a hydroxyl with a partner — and it announces itself to your tongue.
The idea
A carbon bonded to two oxygens — one by a double bond, one carrying a hydrogen — is written –COOH.
This cluster is called the 'carboxyl group'.
The carboxyl group makes a compound acidic — sharp and sour, in the everyday sense.
Vinegar's sourness is the carboxyl group of acetic acid at work.
To spot a carboxyl group, find a frame carbon that carries BOTH a double-bonded O and an O–H together.
The carboxyl group: a carbon carrying a double-bonded O and an O–H together. It makes the compound acidic — this one is the acid in vinegar.
An O–H alone on the frame is a hydroxyl group; the same O–H sitting on a double-bonded-O carbon is part of a carboxyl group.
One glance at –COOH therefore predicts a behavior: the compound is acidic.
Worked examples
Worked example 1. Formic acid, the sting in some ant bites, has the structure shown: a single carbon bonded to an H, a double-bonded O, and an O–H. Identify the functional group and the behavior it predicts.
Step 1
Find a carbon carrying both a double-bonded O and an O–H: the only carbon qualifies.
Step 2
That cluster is the carboxyl group, –COOH.
Step 3
The carboxyl group makes a compound acidic.
Step 4
Formic acid carries a carboxyl group, so it is acidic — hence the sting.
Worked example 2. Pentanoic acid's structure (shown) is a five-carbon chain whose end carbon carries a double-bonded O and an O–H. Which part of the structure makes the compound acidic?
Step 1
Check the end carbon: it carries both a double-bonded O and an O–H.
Step 2
That is a carboxyl group.
Step 3
The carboxyl group is the acid-making part.
Step 4
The –COOH on the end carbon makes pentanoic acid acidic; the four-carbon frame behind it does not.
You can now identify the carboxyl group, –COOH, in a structural formula and state that it makes the compound acidic, like the acetic acid in vinegar.
Check your understanding
The figure shows the structural formula of butanoic acid with four parts labeled A to D. Which label marks the carboxyl group?
ADcorrect
BA
This option is wrong — you picked the plain CH₃ end — the carboxyl group is the carbon carrying a double-bonded O and an O–H, at the other end.
CB
This option is wrong — you picked the frame's C–C bond — the skeleton is not a functional group; look for the two-oxygen cluster.
DC
This option is wrong — you picked a C–H bond — a carboxyl group needs oxygens: a double-bonded O and an O–H on the same carbon.
Find the carbon that carries BOTH a double-bonded O and an O–H. Label D boxes exactly that cluster. That is the carboxyl group, –COOH — the part that makes the compound acidic.
Check your understanding
Write the atom cluster of a carboxyl group as it is written in structural formulas.
Accepted answer: –COOH
The carboxyl group is one carbon, two oxygens, and one hydrogen. The carbon holds a double-bonded O and an O–H together. It is written –COOH.
Check your understanding
Swiss cheese owes part of its flavor to propanoic acid, whose structure ends in a carbon carrying a double-bonded O and an O–H. What behavior does that end cluster predict for the compound?
AIt is acidic — sharp and sour in the everyday sense.correct
BIt is basic — the chemical opposite of acidic.
This option is wrong — you flipped the property — the carboxyl group is the ACID-making group; basicity belongs to a different group.
CIt sheds water the way a nonpolar wax does.
This option is wrong — you read the cluster as nonpolar — a carboxyl group is a polar, oxygen-rich cluster, and its signature behavior is acidity.
DIt has no particular behavior, because clusters this small do not affect a compound.
This option is wrong — you shrugged off a functional group — small clusters control characteristic properties; this one makes the compound acidic.
A carbon carrying a double-bonded O and an O–H is a carboxyl group. The carboxyl group makes a compound acidic. That everyday sourness is exactly what propanoic acid contributes to the cheese.
Lesson 69 of 70 · CMB-069
The amino group
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Did You Know?
You've already met the group that makes compounds acidic. The third named group does the opposite job — and your nose knows it from old fish.
The idea
A nitrogen bonded to two hydrogens, attached to a carbon frame, is written –NH₂.
This cluster is called the 'amino group'.
The amino group makes a compound basic — the chemical opposite of acidic.
Methylamine, a one-carbon frame carrying –NH₂, is the sharp fishy smell of aging seafood.
To spot an amino group, find an N bonded to two hydrogens and one carbon of the frame.
The amino group: a nitrogen with two hydrogens on the carbon frame. It makes the compound basic — the chemical opposite of acidic.
Do not confuse it with a hydroxyl or carboxyl: the amino group is built on NITROGEN, and it carries no oxygen at all.
Worked examples
Worked example 1. Ethylamine's structure (shown) is a two-carbon chain whose end carbon is bonded to an N, which is bonded to two hydrogens. Identify the functional group and the behavior it predicts.
Step 1
Find an N bonded to two hydrogens and one frame carbon: the end N–H₂ fits.
Step 2
That cluster is the amino group, –NH₂.
Step 3
The amino group makes a compound basic.
Step 4
Ethylamine carries an amino group, so it is basic — the chemical opposite of acidic.
Worked example 2. Putrescine, a compound released by decaying fish, is a four-carbon chain with an N bonded to two hydrogens at EACH end. How many amino groups does putrescine carry?
Step 1
Check each N: both are bonded to two hydrogens and one frame carbon.
Step 2
Each qualifying N–H₂ is one amino group.
Step 3
Count them: one at each end.
Step 4
Putrescine carries two amino groups — a double dose of the fishy, basic behavior.
You can now identify the amino group, –NH₂, in a structural formula and state that it makes the compound basic, the chemical opposite of acidic.
Check your understanding
The figure shows the structural formula of butylamine with four parts labeled A to D. Which label marks the amino group?
ACcorrect
BA
This option is wrong — you picked the plain CH₃ end — the amino group is the NITROGEN with its two hydrogens, at the other end.
CB
This option is wrong — you picked the frame's C–C bond — the skeleton is not a functional group; look for the N–H₂ cluster.
DD
This option is wrong — you stopped at the C–N bond — that bond attaches the group to the frame; the group itself is the N with its two hydrogens.
Look for an N bonded to two hydrogens and one frame carbon. Label C sits on exactly that cluster. That is the amino group, –NH₂.
Check your understanding
Write the atom cluster of an amino group as it is written in structural formulas.
Accepted answer: –NH₂
The amino group is one nitrogen bonded to two hydrogens. Its third bond attaches it to the carbon frame. It is written –NH₂.
Check your understanding
Propylamine's structure is a three-carbon chain ending in an N bonded to two hydrogens. What behavior does that end cluster predict for the compound?
AIt is basic — the chemical opposite of acidic.correct
BIt is acidic — sharp and sour like vinegar.
This option is wrong — you gave the amino group the carboxyl's job — the amino group is the base-maker, the chemical opposite.
CIt sheds water the way a nonpolar coating does.
This option is wrong — you read N–H as nonpolar — the amino group is a polar cluster, and its signature behavior is basicity.
DIt behaves exactly like a hydroxyl compound, because H atoms hang off both groups.
This option is wrong — you matched groups by their hydrogens — the amino group is built on NITROGEN, and its characteristic behavior is basic, not hydroxyl-like.
An N bonded to two hydrogens on a carbon frame is an amino group. The amino group makes a compound basic. Basic is the chemical opposite of acidic.
Lesson 70 of 70 · CMB-070
Reading a molecule's groups
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Did You Know?
Wonder this:
Glycine is the smallest building block of every protein in your body — and it is sour-capable and base-capable at the same time. One tiny molecule, two personalities. The structure explains how.
You've already learned to spot the hydroxyl, carboxyl, and amino groups one at a time. Real molecules often carry more than one, and reading them means finding every group.
The idea
A carbon compound can carry several functional groups at once.
To read one, scan the whole structure and test every attached cluster against the patterns you know.
An O–H alone on the frame is a hydroxyl group.
A carbon carrying a double-bonded O and an O–H together is a carboxyl group.
An N bonded to two hydrogens is an amino group.
Count carefully: the O–H inside a carboxyl group belongs to the carboxyl — it is not a separate hydroxyl group.
Glycine's structure carries an amino group on one carbon and a carboxyl group on the other: two groups, two behaviors, one molecule.
Glycine carries two functional groups at once: an amino group and a carboxyl group.
Worked examples
Worked example 1. Lactic acid, made in hard-working muscles, has the structure shown: a three-carbon chain whose middle carbon carries an O–H, and whose end carbon carries a double-bonded O and an O–H together. Identify every functional group.
Step 1
Scan cluster by cluster.
Step 2
The middle carbon's O–H stands alone — a hydroxyl group.
Step 3
The end carbon carries a double-bonded O and an O–H together — a carboxyl group.
Step 4
The carboxyl's O–H is already counted inside the carboxyl, not as an extra hydroxyl.
Step 5
Lactic acid carries one hydroxyl group and one carboxyl group.
Worked example 2. Ethanolamine, used in gas-scrubbing towers, has the structure shown: a two-carbon chain with an O–H on one end carbon and an N bonded to two hydrogens on the other. Identify every functional group.
Step 1
Scan cluster by cluster.
Step 2
One end carbon carries an O–H alone — a hydroxyl group.
Step 3
The other end carries an N with two hydrogens — an amino group.
Step 4
Ethanolamine carries one hydroxyl group and one amino group.
You can now identify every functional group present in a supplied structural formula of a carbon compound that carries more than one group.
Check your understanding
The figure shows the structural formula of alanine, a protein building block. Which functional groups does the molecule carry?
AOne amino group, one carboxyl group, and no hydroxyl groupcorrect
BOne hydroxyl group, one carboxyl group, and no amino group
This option is wrong — you counted the carboxyl's O–H twice — that O–H belongs to the carboxyl group, and the nitrogen cluster you passed over is the amino group.
COne amino group, no carboxyl group, and no hydroxyl group
This option is wrong — you stopped scanning after the first find — the end carbon's double-bonded O plus O–H is a carboxyl group.
DOne amino group, one carboxyl group, and one hydroxyl group
This option is wrong — you added a third group by re-counting the carboxyl's O–H — it is part of the carboxyl, not a separate hydroxyl.
Scan every attached cluster. The N with two hydrogens is an amino group; the carbon with a double-bonded O and an O–H is a carboxyl group. The carboxyl's O–H is already counted — no separate hydroxyl.
Check your understanding
The figure shows the structural formula of glycolic acid, used in skin-care peels. Which functional groups does the molecule carry?
AOne hydroxyl group, one carboxyl group, and no amino groupcorrect
BTwo hydroxyl groups, no carboxyl group, and no amino group
This option is wrong — you read the carboxyl as a hydroxyl — the second O–H sits on a carbon with a double-bonded O, making that whole cluster a carboxyl group.
CTwo carboxyl groups, no hydroxyl group, and no amino group
This option is wrong — you promoted the lone O–H — the first carbon has no double-bonded O, so its O–H is a hydroxyl, not a carboxyl.
DOne carboxyl group, no hydroxyl group, and no amino group
This option is wrong — you skipped the first carbon's O–H — an O–H alone on the frame is a hydroxyl group and must be counted.
Test each O–H's carbon for a double-bonded O. First carbon: no double-bonded O, so its O–H is a hydroxyl group. Second carbon: double-bonded O plus O–H — a carboxyl group. One of each.
Check your understanding
The figure shows the structural formula of lysine, a protein building block. Which functional groups does the molecule carry?
ATwo amino groups, one carboxyl group, and no hydroxyl groupcorrect
BOne amino group, one carboxyl group, and no hydroxyl group
This option is wrong — you stopped after one nitrogen — scan the WHOLE chain: the fifth carbon carries a second N with two hydrogens.
CTwo amino groups, one hydroxyl group, and no carboxyl group
This option is wrong — you read the carboxyl as a hydroxyl — its O–H sits on a carbon with a double-bonded O, so the cluster is a carboxyl group.
DTwo amino groups, one carboxyl group, and one hydroxyl group
This option is wrong — you double-counted the carboxyl's O–H — it belongs to the carboxyl, not to a separate hydroxyl.
Scan carbon by carbon and test every cluster. Two separate N-with-two-hydrogens clusters: two amino groups. One double-bonded-O-plus-O–H cluster: one carboxyl group — its O–H is not an extra hydroxyl.