Unit 14 — End of Topic Tests (reviewer copy: all keys and model answers visible)

End of Topic Test: Nuclear change vs chemical change & Unstable nuclei and radioactivity (u14-t1 · 5 forms × 21 items · 105 total)

David's notes for James:
full notes file
# u14-t1 — notes/queries from David's side (U14-G1)

1. FRQ COMPOSITION - frq_per_form = 1 (your gate data's frq_per_form=1 concurs): the calc-heavy FRQ split was EVALUATED AND NOT TRIGGERED after an honest predicate check - the NUC-001..009 scope is fully qualitative: no lesson carries a displayEquation or atomKind 'quant', all 27 of your pool seeds are mcq4, and half-life math lives in NUC-022+ (later gates). No formula is ever substituted, so a calculation FRQ would have no production routine to assess and the 5-line scaffold is barred everywhere (V-T9). The single FRQ is the gate's terminal capstone production: NUC-003 'Chemical or nuclear?' as a TYPED 3-part classify-and-justify (two changes per form: (a) verdicts, (b) justification by the one identity question the topic teaches, (c) why the dramatic energy display is a false clue). Rubric 30/45/25 = 100; model answers word-only (nothing typed requires sub/superscripts). D5 scaling evaluated and NOT applied: 9 scope lessons carry the full 20-objective allocation (seven lessons 2 rows; capstone NUC-003 = 3 rows + the FRQ; NUC-009 = 3 rows across its three taught surfaces). Total 20 mcq + 1 FRQ = 21 items/form; no figures anywhere (every scope lesson is visual:null), so blind packets were self-contained by construction.
2. COURSE-WIDE INSTANCE RULE + U14 PHRASING PACK (binding, wave 6) - the topic is nuclear chemistry, so the language stays curricular and clinical exactly as the lessons do: sealed clinical/industrial/laboratory sources, an unnumbered smoke-detector americium speck, benign real nuclides for every decay instance; NEVER uranium/plutonium/enrichment/reactors/weapons, no dose/harm framing. Dispositions to confirm: (a) your seed p6's 'uranium-235 -> thorium-231' change violates the course-wide uranium ban and was freshened to 'strontium-89 -> yttrium-89' (a real beta decay, mode unnamed per the lessons' own convention; structure, options and key untouched); (b) your NUC-004 seeds' register anchor quote '1 g of uranium ~ 3 tons of coal' is never carried into any item field - feedback restates the whitelisted million-fold rule line instead (the p9/p16 items are otherwise VERBATIM); (c) americium appears exactly once gate-wide, UNNUMBERED, in its real smoke-detector setting (C#13; 241 is a barred spec number and 'an atom of americium' is a corpus frame); (d) packaging re-sweep over forms_final AND this export body: ZERO student-facing hits on every hard-banned token (uranium/plutonium/enrichment/reactor/weapon/fissile/meltdown/warhead/bomb); the strict scan's one literal 'dose' is E#11's 'an atom of holmium-166 in a therapy dose' - the phrasing pack's ALLOWED clinical register (same class as its 'tracer doses' / 'iodine-131 thyroid medicine' examples; no harm quantification anywhere), disclosed rather than reworded. Zero content-filter events across every authoring/blind/sol round - the clinical phrasing held.
3. BARRED-NUMBER LEDGER (computed, blueprint allocation_notes): the 26 spec numbers over NUC-001..009 article+fluency text (14,15,16,17,18,19,24,31,32,60,82,84,86,88,90,92,127,131,137,197,218,222,226,237,241,1896) never appear in any item text; consequence - carbon-14, iodine-131, americium-241, radon-222, cesium-137, cobalt-60 can never appear WITH their mass numbers. All classification/decay instances are fresh real nuclides with unbarred mass numbers (Sr-89->Y-89, Ca-47->Sc-47, Ar-41->K-41, Na-22->Ne-22, Sb-122, Os-193, Zr-95, Se-75, Ir-192, Sm-153, W-185, Pd-103, Cd-109, Ho-166, Tm-170, Pr-143, Ga-70, Al-29, Xe-133, Ce-144, Pm-147, Tc-99m, V-48/V-51, Hf-172/Hf-178 ...), every one a real decay/stability fact, mode unnamed per the lessons' convention.
4. SEED USAGE - 18 of the 20 form-A objective slots are your pool items (9 VERBATIM: p9,p11,p14,p16,p17,p19,p22,p25,p26; 9 FRESHENED under the strict seed ruling: p0,p4,p6,p7,p8,p13,p20,p21,p24); A#1/A#2 and the FRQ are fresh-authored (your pool has no recall items for those two definitional surfaces and prod_seeds is EMPTY - the FRQ follows your demo-gate two-scenario pattern instead). demo_curated d0-d2 are duplicates of pool p6/p7/p8 - deduped at stage 1 with both refs cited on the seq 6/11/15 placements. SPARES: 9 (p1,p2,p3,p5,p10,p12,p15,p18,p23; p5 additionally served as structure donor for B#5). Cold list ignored by standing answer #3. Forms B-E are fresh-authored parallels.
5. SEED FRESHENINGS UNDER THE STRICT SEED RULING (no freshness exemption; the shared validator was never weakened) - 9 dispositions to confirm, every one preserving your structure and misconception keys with all fields swept (QB 3.9): (a) p0@A#17 claim target 'gold' -> 'a precious metal' (GOLD is in NUC-001's own hook 'turning lead into gold'; mercury kept; distance-rule distractor reworded to match); (b) p4@A#5 counts 15->16 changed to 43->44 (15/16 are barred NUC-007 fluency numbers; options verbatim, instance-free); (c) p6@A#6 the uranium ban freshen above (Sr-89 -> Y-89); (d) p7@A#11 change 1 -> 'an atom of calcium-47 inside a leaf becomes an atom of scandium-47' (32 of P-32/S-32 is barred; the same-mass pair keeps your mass-red-herring distractor live); (e) p8@A#15 'combines with water' clause dropped (WATER is an own-lesson NUC-003 material) and change 2 -> Ar-41 -> K-41 (cobalt-60's 60 is barred); (f) p13@A#19 'An americium nucleus' -> 'A heavy nucleus' (americium reserved to its one phrasing-pack cell C#13); (g) p20@A#12 magnesium-28 stability data -> vanadium (V-51 stable anchor / V-48 too-few-neutrons, real; magnesium-28's numbers collide with barred 16/14 and magnesium is reserved to A#15); (h) p21@A#13 cesium-137 detector scene -> a technetium-99m sample in a hospital imaging ward (137 barred; phrasing-pack instance; 'surrounding air' -> 'its surroundings'); (i) p24@A#14 'dust' -> 'specks of soil containing radioactive atoms' (dust is an own-lesson NUC-009 fluency material; options verbatim).
6. SEED-TOUCHING QC EDITS (confirm, all form A, defect-driven and content-preserving): A#9 (p25) the classification key/options say 'irradiated ONLY' - blind QC correctly observed a contaminated object is also literally irradiated by its own atoms, so exclusivity had to live in the wording; class-swept across all five forms' row 9. A#14 (p24) question scoped 'as a result of these events' - sol correctly majored that the absolute form ('are the apples radioactive?') ignored natural background radioactivity; class-swept across all five forms' row 14. A#17 (p0) and A#20 (p26) longest-key trims (dual-flagged by blind + V-T4 margin; keys shortened, claims unchanged).
7. NOTA/AOTA: zero literal none-of-the-above/all-of-the-above hits across your 27-seed pool (V-T5 regex clone at stage 1); zero replace_distractor flags needed; V-T5 PASS on all forms.
8. GATE_CONFIG - DETECTION-STRENGTHENING ONLY, zero whitelist relief: extra_materials arms 48 tokens (39 fresh element names + 9 scene substances) INTO the V-T7 scans so every instance this gate uses is scanned; each lives in exactly one (form,seq) home cell; the three recorded same-form second cells (potassium A#10+A#15, iridium D#6+D#21, tellurium E#10+E#21) are non-adjacent WARN-class by design. The 10 validator warning lines = exactly the stage-1 recorded adjudications (7 other-lesson-material memory-answerability warns: iron A#18/sodium A#21/cobalt B#18/americium C#13/silver D#11/helium D#18/beryllium E#17, + the 3 second cells). No extra whitelist phrases, no task idioms, no A6 figure relief, no numeric relief (V-T6 vacuous - no numeric items). The shared validator ran UNMODIFIED to 12/12 PASS, exit 0.
9. BLIND/SOL QC LEDGER (provenance, no action needed): blind round 1 (r1 = gpt-5.6-sol blind role, r2 = gemini; 105 items each) = 200/200 key picks, FRQ 10/10 hand-graded rubric match; 3 hard fails, all real defects, fixed + class-swept: C#9 (the 'irradiated only' exclusivity class above), C#14 (wrench 1 'directly in the beam' + wrench 2's coolant residue made explicit - contamination transfer must be stated), E#12 (stem now anchors the balanced neutron count via the stable isotope before asking the predict). Re-blind rounds on every changed item (fresh tags r3-r10) = 56/56 key picks + FRQ 6/6, one intermediate catch (E#13: the in-case detector fix had made the glow-light option defensible; shipped item names a RADIATION COUNTER held above uncovered hands - counters do not register visible light). sol authoritative loops: 7 FAIL -> 1 -> 1 -> 0 across 4 loops (within budget); final ledger 105/105 pass, 0 open FAILs, with 5 recorded honest-survivor minors (C#17, E#16, E#17, E#18, E#20 - distractor-plausibility gradients only; every distractor stays misconception-keyed).
10. NOTABLE SOL FIXES ON FRESH ITEMS (disclosures): B#19 key de-overclaimed (decay CAN emit particles; the item's accounting shows no missing NEUTRON is needed - mass became the released energy); E#7/E#16 volume-to-mass conflation fixed (fuel comparisons pinned to the nuclear material's MASS, not container size); C#19 taught rule removed from the stem (classmate-claim format must not hand over the rule); C#20 the spill solute is now dissolved radioactive METAL atoms (nonvolatile - establishes the key's stays-behind claim) and its d2 feedback genitive fixed ('energy and particles emitted FROM the decaying atoms'); B/C/E#21 FRQ stems descaffolded ('nucleus changes' / 'every atom keeps its identity' phrasing handed over parts a-b; A/D never had it).
11. ACCEPTED SURVIVOR CLASSES (recorded, confirm-if-you-care): cross-item curriculum cueing endemic to a single-topic 21-item test (NUC-003 owns 3 classification rows + the FRQ, NUC-009 owns 3 irradiation/contamination rows - blueprint design); E#7<->E#16 inverse-pair cueing (the blueprint's two NUC-004 scale rows, one per direction); E#4 part-of-speech tell (inherent to a which-term-names-an-EVENT vocabulary task); definition-echo notes on recall rows (V-T4 deterministic measure passes; definitional keys ARE the assessed recall content); course-model realism notes where course-local definitions are authority (e.g. C#13 click causation).
12. TITLE - 'End of Topic Test: Nuclear change vs chemical change & Unstable nuclei and radioactivity' (Topic 1 & Topic 2 titles joined with ' & ', 'Topic N:' prefixes stripped, standing G1-canon convention).

Form A

NUC-001 · easy · recall · seq 1 · authored fresh (stage 2); fluency[1] family, stem reworded (corpus) · mcq4
During any chemical change, which parts of the atoms take part?
Only the electrons — the nucleus of each atom is never touched. KEY
Only the nucleus — the electrons stay out of it.
Both the electrons and the nucleus together.
Neither — whole atoms are swapped for new ones.
NUC-002 · easy · recall · seq 2 · authored fresh (stage 2); fluency[1] family, stem reworded (corpus) · mcq4
A nuclear change happens inside an atom. Which part of the atom is altered?
The nucleus itself. KEY
Only the outer electrons.
Only the connections to neighboring atoms.
No part — the label just means a very energetic change.
NUC-006 · easy · recall · seq 3 · seed p17 (NUC-006 GATE[2]) VERBATIM · mcq4
Which nucleus counts as unstable?
One that will sooner or later change on its own. KEY
One that changes only when hit by another particle.
One that stays the same unless it is heated.
One that has more neutrons than protons.
NUC-008 · easy · recall · seq 4 · seed p22 (NUC-008 GATE[1]) VERBATIM · mcq4
Which change counts as radioactive decay?
An unstable nucleus changing on its own into a more stable one. KEY
A nucleus changing after being struck by another particle.
An atom handing its outer electrons to a neighboring atom.
A stable nucleus soaking up energy and growing heavier.
NUC-002 · medium · application · seq 5 · seed p4 (NUC-002 GATE[1]) MUST_FRESHEN_INSTANCE: 15->16 are barred spec numbers -> 43->44; options verbatim · mcq4
During a change, an atom's proton count goes from 43 to 44. Did the atom's element change?
Yes — the proton count decides the element, so it is now a different element. KEY
No — it is now just a heavier isotope of the same element.
No — the element changes only if electrons are also lost.
Yes, but only if the mass number changed at the same time.
NUC-003 · medium · application · seq 6 · seed p6 = demo_curated[0] (dual ref) MUST_FRESHEN_INSTANCE: uranium-235->thorium-231 violates the course-wide uranium ban -> strontium-89->yttrium-89; glow stick kept; feedback swept · mcq4
Change 1: a snapped glow stick shines for hours as molecules inside it react. Change 2: an atom of strontium-89 in a sealed laboratory vial becomes an atom of yttrium-89. Which option classifies both changes?
Change 1 is chemical; change 2 is nuclear. KEY
Change 1 is nuclear; change 2 is chemical.
Both change 1 and change 2 are nuclear.
Both change 1 and change 2 are chemical.
NUC-004 · medium · application · seq 7 · seed p9 (NUC-004 GATE[0]) VERBATIM; register uranium/coal quote dropped from feedback (course-wide ban) · mcq4
To match the energy released by the nuclear change of 1 g of fuel, about how much fuel would you need to burn in a chemical change?
Around a million grams — about a ton. KEY
Around 1 g — the same amount.
Around a thousand grams — about 1 kg.
Around a billion grams — about a thousand tons.
NUC-005 · medium · application · seq 8 · seed p14 (NUC-005 GATE[2]) VERBATIM · mcq4
Why can a nuclear change release around a million times more energy than a chemical change of the same mass of material?
Because a small amount of the nucleus's mass is converted into a very large amount of energy. KEY
Because nuclear fuels pack many more chemical bonds into every gram of material.
Because nuclear changes happen much faster, concentrating their energy into less time.
Because the nucleus holds tightly packed electrons whose release powers the change.
NUC-009 · medium · application · seq 9 · seed p25 (NUC-009 GATE[1]) VERBATIM · mcq4
Situation 1: an aircraft crew flies through radiation streaming in from space. Situation 2: a hiker's boots pick up mud that contains radioactive atoms. Which option classifies both situations?
Situation 1 irradiated only; situation 2 contaminated. KEY
Situation 1 contaminated; situation 2 irradiated only.
Situation 1 contaminated; situation 2 contaminated.
Situation 1 irradiated only; situation 2 irradiated only.
NUC-006 · medium · application · seq 10 · seed p16 (NUC-006 GATE[1]) VERBATIM · mcq4
Potassium-39 is stable, while potassium-40 is unstable. What does this pair show about stability?
Stability belongs to the specific isotope, not to the element as a whole. KEY
All isotopes of one element must share the same stability.
The heavier isotope of an element is always the unstable one.
Stability depends on the temperature of the potassium sample.
NUC-003 · medium · application · seq 11 · seed p7 = demo_curated[1] (dual ref) MUST_FRESHEN_INSTANCE: phosphorus-32/sulfur-32's 32 is a barred spec number -> calcium-47 -> scandium-47 (real bio-tracer decay); pigment scene kept; feedback swept · mcq4
Change 1: an atom of calcium-47 inside a leaf becomes an atom of scandium-47. Change 2: the leaf's green pigment molecules break down in the fall, uncovering red ones — every atom keeps its identity. Which option classifies both changes?
Change 1 is nuclear; change 2 is chemical. KEY
Change 1 is chemical; change 2 is nuclear.
Both change 1 and change 2 are chemical.
Both change 1 and change 2 are nuclear.
NUC-007 · medium · application · seq 12 · seed p20 (NUC-007 GATE[2]) MUST_FRESHEN_INSTANCE: magnesium-28 data barred (16; 12-14 range) -> vanadium-51/vanadium-48, direction flipped to too-few (rotation covers both) · mcq4
Stable vanadium-51 has 28 neutrons for its 23 protons. Vanadium-48 has 25 neutrons, and it is unstable. Why?
It has too few neutrons for its proton count. KEY
It has too many neutrons for its proton count.
It has more protons than a nucleus that size can hold.
Its electron count no longer matches its proton count.
NUC-008 · medium · application · seq 13 · seed p21 (NUC-008 GATE[0]) MUST_FRESHEN_INSTANCE: cesium-137 barred (137 + corpus frame) -> technetium-99m hospital vial; 'surrounding air' -> 'its surroundings'; options otherwise verbatim · mcq4
A detector clicks near a small vial of technetium-99m in a hospital imaging ward. What is the detector picking up?
The nuclear radiation shot out as the sample's nuclei decay. KEY
The more stable nuclei left behind after each decay.
The radioactive technetium atoms themselves flying off the sample.
The sample's chemical reactions with its surroundings.
NUC-009 · medium · application · seq 14 · seed p24 (NUC-009 GATE[0]) MUST_FRESHEN_INSTANCE: 'dust' is an own-lesson material -> 'specks of soil'; options verbatim; feedback swept · mcq4
Apple 1 was sterilized in a radiation beam yesterday and then shipped. Apple 2 picked up specks of soil containing radioactive atoms. Which apple is giving off radiation today as a result of these events?
Only apple 2. KEY
Only apple 1.
Both apples.
Neither apple.
NUC-003 · medium · application · seq 15 · seed p8 = demo_curated[2] (dual ref) MUST_FRESHEN_INSTANCE: water clause dropped (own-lesson material); cobalt-60 barred (60) -> argon-41 -> potassium-41; feedback swept · mcq4
Change 1: a self-heating meal pack gets hot as its magnesium reacts inside — every magnesium atom is still magnesium. Change 2: an atom of argon-41 in a sealed gas ampoule becomes an atom of potassium-41. Which option classifies both changes?
Change 1 is chemical; change 2 is nuclear. KEY
Change 1 is nuclear; change 2 is chemical.
Both change 1 and change 2 are nuclear.
Both change 1 and change 2 are chemical.
NUC-004 · medium · application · seq 16 · seed p11 (NUC-004 GATE[2]) VERBATIM; register uranium/coal quote dropped from feedback (course-wide ban) · mcq4
Two power sources release the same total energy. Source A uses nuclear changes; source B burns fuel. How do the masses of material they used compare?
Source A used around a million times less material than source B. KEY
Source A used around a million times more material than source B.
The two sources used about the same mass of material overall.
Source A used about half the material that source B used.
NUC-001 · hard · transfer · seq 17 · seed p0 (NUC-001 GATE[0]) MUST_FRESHEN_INSTANCE: 'gold' is in NUC-001's own hook (own-lesson fence) -> 'a precious metal'; distance distractor reworded to match; otherwise verbatim · mcq4
A company claims its purely chemical process turns mercury atoms into a precious metal. Why must the claim be false?
A chemical change involves only the atoms' electrons, so it cannot change any atom's identity. KEY
Mercury and precious metals sit too far apart in the periodic table for any process to connect them.
The claim could be true if the process supplied enough heat and pressure to the mercury.
Mercury atoms could only convert one at a time, far too slowly to be useful.
NUC-007 · hard · transfer · seq 18 · seed p19 (NUC-007 GATE[1]) VERBATIM · mcq4
A student claims: 'Any nucleus with more neutrons than protons must be unstable.' Iron-56, with 30 neutrons and 26 protons, is stable. What is wrong with the student's rule?
What matters is the neutron balance for that proton count — many stable nuclei have extra neutrons. KEY
Nothing — iron-56 must be unstable, and its change simply has not happened yet.
The rule is backwards — nuclei with more protons than neutrons are the unstable ones.
The rule fails only for metals like iron, whose nuclei follow different balance laws.
NUC-005 · hard · transfer · seq 19 · seed p13 (NUC-005 GATE[1]) MUST_FRESHEN_INSTANCE: 'An americium nucleus' -> 'A heavy nucleus' (americium reserved to C#13; seq kept element-free); options verbatim · mcq4
A heavy nucleus changes, releasing energy. Careful accounting shows every proton and every neutron still present among the pieces — yet the pieces total slightly less mass. How can that be?
A small amount of the mass itself was converted into energy — no particle has to leave for mass to be lost. KEY
It cannot be — if every particle is present, the total mass must be exactly unchanged.
The measurement must have missed a neutron that carried the missing mass away.
The pieces are moving quickly, and fast particles always register as lighter.
NUC-009 · hard · transfer · seq 20 · seed p26 (NUC-009 GATE[2]) VERBATIM · mcq4
A blogger warns that medicine vials sterilized in a radiation beam come out radioactive and dangerous to handle. What is wrong with the warning?
The beam left no radioactive atoms on the vials, so nothing radioactive remains. KEY
Nothing is wrong — an object that absorbs radiation becomes radioactive itself.
The warning fails only because sterilizing beams are too weak to affect glass vials.
The warning merely mixes up its words — the vials are really contaminated, not irradiated.
NUC-003 · medium · application · seq 21 · authored fresh (stage 2); demo-gate two-scenario pattern; Na-22 -> Ne-22 real (mode unnamed) · frq
Change 1: a camp-stove fuel tablet burns away to invisible gases, pouring out light and heat. Change 2: an atom of sodium-22 in an old calibration bead becomes an atom of neon-22. Type your answers:
Change 1: a camp-stove fuel tablet burns away to invisible gases, pouring out light and heat. Change 2: an atom of sodium-22 in an old calibration bead becomes an atom of neon-22. Type your answers: (a) Classify each change as chemical or nuclear. (b) Justify each verdict using the one question the topic teaches you to ask about the atoms. (c) Change 1 is far more dramatic to watch. Explain why that dramatic energy display cannot decide either classification.
Part a. Classify each change as chemical or nuclear.
Model: Change 1 is a chemical change. Change 2 is a nuclear change.
Part b. Justify each verdict using the one question the topic teaches you to ask about the atoms.
Model: Ask of each change: did any atom change its identity? In the burning tablet, every atom keeps its identity — the atoms only trade partners as molecules rearrange, because burning involves only the atoms' electrons and never the nucleus. In the bead, a sodium-22 atom became a neon-22 atom: a new element appeared, and a new element can appear only when the nucleus itself changes, altering the proton count.
Part c. Change 1 is far more dramatic to watch. Explain why that dramatic energy display cannot decide either classification.
Model: The flames prove nothing. Many chemical changes release plenty of heat and light, so energy release is a false clue — it cannot tell chemical from nuclear. Only the identity question decides: identity kept means chemical, new element means nuclear.
Full model answer. (a) Change 1 is a chemical change. Change 2 is a nuclear change. (b) Ask of each change: did any atom change its identity? In the burning tablet, every atom keeps its identity — the atoms only trade partners as molecules rearrange, because burning involves only the atoms' electrons and never the nucleus. In the bead, a sodium-22 atom became a neon-22 atom: a new element appeared, and a new element can appear only when the nucleus itself changes, altering the proton count. (c) The flames prove nothing. Many chemical changes release plenty of heat and light, so energy release is a false clue — it cannot tell chemical from nuclear. Only the identity question decides: identity kept means chemical, new element means nuclear.

Form B

NUC-001 · easy · recall · seq 1 · authored fresh (stage 2) · mcq4
There is one part of every atom that a chemical change can never reach. Which part?
The nucleus. KEY
The outer electrons.
The connections between atoms.
There is no such part — a strong enough reaction reaches everything.
NUC-002 · easy · recall · seq 2 · authored fresh (stage 2) · mcq4
In a nuclear change, what can happen to an atom's proton count?
It can change, because the nucleus itself is altered. KEY
Nothing — the proton count can never change in any process.
It always doubles.
It can change, but only if electrons are lost at the same time.
NUC-006 · easy · recall · seq 3 · authored fresh (stage 2); rule-line-2 definition family · mcq4
Which nucleus counts as stable?
One that stays the same forever on its own. KEY
One that changes on its own, but only very slowly.
One that has already survived one change.
One with exactly equal numbers of protons and neutrons.
NUC-008 · easy · recall · seq 4 · authored fresh (stage 2); three-jobs family (rule lines 3-4) · mcq4
As an unstable nucleus decays, energy and particles shoot out of it. What is that outflow called?
Nuclear radiation. KEY
Radioactive decay.
A chemical emission.
The more stable nucleus.
NUC-002 · medium · application · seq 5 · authored on seed p5's unchanged-count STRUCTURE (recorded structure donor); count 11 -> 37, wording fresh · mcq4
An atom's proton count is 37 both before and after a change inside it. Could the atom now be a different element?
No — with the proton count unchanged, it is the same element. KEY
Yes — if its neutron count changed, its element changed.
Yes — if it lost electrons, it became a new element.
Yes — joining into a compound makes it a new element.
NUC-003 · medium · application · seq 6 · authored fresh (stage 2); p6 family, nuclear-first rotation · mcq4
Change 1: an atom of zirconium-95 in a sealed test capsule becomes an atom of niobium-95. Change 2: a camping hand warmer heats up as the powdered metal inside it reacts, every atom keeping its identity there. Which option classifies both changes?
Change 1 is nuclear; change 2 is chemical. KEY
Change 1 is chemical; change 2 is nuclear.
Both change 1 and change 2 are nuclear.
Both change 1 and change 2 are chemical.
NUC-004 · medium · application · seq 7 · authored fresh (stage 2); p9 mass-for-energy family · mcq4
A remote research station can run for a year on a thumb-sized pellet whose nuclei change, or on fuel burned in a generator. Roughly how do the required masses compare?
The burned fuel outweighs the pellet by around a million times. KEY
The two masses are about equal, since the energy delivered is equal.
The burned fuel outweighs the pellet by about a hundred times.
The pellet outweighs the burned fuel, since nuclear fuel is denser.
NUC-005 · medium · application · seq 8 · authored fresh (stage 2); energy-source family (fluency[1] stem is corpus - fully rephrased) · mcq4
A sealed pellet warms itself for years as its nuclei change. What is the source of all that energy?
A small amount of the nucleus's mass is converted into a very large amount of energy. KEY
Chemical bonds inside the pellet breaking one by one.
Heat that was sealed into the pellet when it was manufactured.
The pellet's electrons dropping closer to each changed nucleus.
NUC-009 · medium · application · seq 9 · authored fresh (stage 2); p25 family · mcq4
Situation 1: a museum painting is scanned by a beam from a sealed source during authentication. Situation 2: fine ash that holds radioactive atoms settles onto a parked van. Which option classifies both situations?
Situation 1 irradiated only; situation 2 contaminated. KEY
Situation 1 contaminated; situation 2 irradiated only.
Situation 1 contaminated; situation 2 contaminated.
Situation 1 irradiated only; situation 2 irradiated only.
NUC-006 · medium · application · seq 10 · authored fresh (stage 2); p16 family, label-the-pair rotation · mcq4
Chlorine-35 nuclei never change on their own; chlorine-38 nuclei sooner or later do. Which labels fit the two isotopes?
Chlorine-35 stable; chlorine-38 unstable. KEY
Chlorine-35 unstable; chlorine-38 stable.
Both stable, since both are the same element.
Both unstable, since neither can resist change forever.
NUC-003 · medium · application · seq 11 · authored fresh (stage 2); p7 family · mcq4
Change 1: a bike chain slowly darkens as its surface reacts with the surroundings — every atom keeps its identity. Change 2: an atom of tungsten-185 in a filament-stock sample becomes an atom of rhenium-185. Which option classifies both changes?
Change 1 is chemical; change 2 is nuclear. KEY
Change 1 is nuclear; change 2 is chemical.
Both change 1 and change 2 are chemical.
Both change 1 and change 2 are nuclear.
NUC-007 · medium · application · seq 12 · authored fresh (stage 2); p20 family, too-few direction · mcq4
Stable tin-118 has 68 neutrons for its 50 protons. Tin-113 has 63 neutrons, and it is unstable. What makes it unstable?
Its neutron count is too low for its proton count. KEY
Its neutron count is too high for its proton count.
Having an odd number of neutrons always makes a nucleus unstable.
Its protons repel one another, which no tin nucleus can withstand.
NUC-008 · medium · application · seq 13 · authored fresh (stage 2); p21 family · mcq4
A counter beside a sealed capsule of xenon-133 in a clinic storeroom registers a steady stream of counts. What is it registering?
Nuclear radiation — the energy and particles the decaying nuclei shoot out. KEY
Xenon-133 atoms leaking through the capsule wall.
The new, more stable nuclei escaping as each decay finishes.
Static electricity building up on the capsule's surface.
NUC-009 · medium · application · seq 14 · authored fresh (stage 2); p24 family · mcq4
Crate 1 of oranges passed through a port's screening beam yesterday. Crate 2 sat under a leaky roof whose drips carried radioactive atoms into its boards. Which crate is giving off radiation today as a result of these events?
Only crate 2. KEY
Only crate 1.
Both crates.
Neither crate.
NUC-003 · medium · application · seq 15 · authored fresh (stage 2); p8 family · mcq4
Change 1: a two-part epoxy warms noticeably as its pastes are mixed and bond — every atom keeps its identity. Change 2: an atom of thulium-170 in a portable field gauge becomes an atom of ytterbium-170. Which option classifies both changes?
Change 1 is chemical; change 2 is nuclear. KEY
Change 1 is nuclear; change 2 is chemical.
Both change 1 and change 2 are nuclear.
Both change 1 and change 2 are chemical.
NUC-004 · medium · application · seq 16 · authored fresh (stage 2); p11 family, same-mass direction · mcq4
A demonstration compares equal masses of two materials: one releases energy through nuclear changes, the other by burning. Which outcome should the audience expect?
The nuclear side releases around a million times more energy. KEY
The burning side releases around a million times more energy.
The two sides release about equal energy, since the masses match.
The nuclear side releases about a hundred times more energy.
NUC-001 · hard · transfer · seq 17 · authored fresh (stage 2); p0 family · mcq4
A start-up says its bench-top chemical treatment converts ordinary titanium into tantalum, an expensive metal. What single fact sinks the claim?
No chemical process touches the nucleus, and only a changed nucleus can change an element. KEY
The right catalyst has simply not been found yet, so the claim is merely premature.
Titanium is too hard a metal for chemical treatments to affect at all.
Such a conversion would work only on freshly mined titanium.
NUC-007 · hard · transfer · seq 18 · authored fresh (stage 2); p19 family, equal-counts rule · mcq4
A classmate proposes: 'A nucleus with exactly equal numbers of protons and neutrons is always stable — perfect balance.' Cobalt-54 has 27 of each, and it is unstable; stable cobalt carries several extra neutrons. What is wrong with the proposal?
Equal counts are not the balance — for 27 protons the balanced neutron count is higher than 27. KEY
Nothing — cobalt-54 must be a measurement error, since perfect balance cannot fail.
The proposal fails only because 27 is an odd number, and odd counts are never balanced.
Equal counts actually guarantee INSTABILITY, which is the opposite rule.
NUC-005 · hard · transfer · seq 19 · authored fresh (stage 2); p13 family, escaped-particle critique · mcq4
Weighings around one nuclear change show a small mass loss, yet every proton and neutron is accounted for among the pieces. A lab intern insists a neutron must have slipped out undetected, 'because mass cannot just stop existing.' What is wrong with the intern's reasoning?
The lost mass did not stop existing — it became the released energy, so no escaping neutron is needed. KEY
Nothing — a full particle count plus lost mass is a contradiction, so a particle escaped.
The intern is right about the escape but wrong about the particle — it was an electron that left.
Mass losses that small are always rounding errors in the weighing.
NUC-009 · hard · transfer · seq 20 · authored fresh (stage 2); p26 family, cleanup-direction critique · mcq4
After a sealed source briefly shone its radiation across a warehouse, a memo orders every surface scrubbed 'to remove the radiation soaked into the walls.' What is wrong with the memo?
There is nothing to scrub off — the radiation deposited its energy and was gone, leaving no radioactive atoms behind. KEY
Nothing — walls store radiation the way they store paint fumes, and scrubbing releases it safely.
The memo is right to scrub but wrong about the target — the walls' own atoms have all turned radioactive.
Scrubbing is wrong only because it spreads the radiation to the mops and buckets.
NUC-003 · medium · application · seq 21 · authored fresh (stage 2); proton-count evidence variant (element-free) · frq
Change 1: inside a sealed sample, one atom's proton count goes from 62 to 61. Change 2: batter on a hot griddle browns and sets into a pancake as new flavor substances form. Type your answers:
Change 1: inside a sealed sample, one atom's proton count goes from 62 to 61. Change 2: batter on a hot griddle browns and sets into a pancake as new flavor substances form. Type your answers: (a) Classify each change as chemical or nuclear. (b) Justify each verdict using the one question the topic teaches you to ask about the atoms. (c) A classmate argues change 2 must be the nuclear one 'because cooking adds so much heat energy.' Explain why the energy involved cannot decide the classification.
Part a. Classify each change as chemical or nuclear.
Model: Change 1 is a nuclear change. Change 2 is a chemical change.
Part b. Justify each verdict using the one question the topic teaches you to ask about the atoms.
Model: Ask: did any atom change its identity? In change 1 the proton count fell from 62 to 61, and the proton count decides which element an atom is — so an atom became a different element, which only a nuclear change can do. In change 2 the browning batter builds new flavor substances out of the same atoms — every atom keeps its identity, so the change is chemical, involving only the atoms' electrons.
Part c. A classmate argues change 2 must be the nuclear one 'because cooking adds so much heat energy.' Explain why the energy involved cannot decide the classification.
Model: The heat proves nothing. Energy moving in or out is a false clue — many chemical changes involve plenty of heat, and a nuclear change can happen silently in a sealed sample. Only the identity question decides the classification.
Full model answer. (a) Change 1 is a nuclear change. Change 2 is a chemical change. (b) Ask: did any atom change its identity? In change 1 the proton count fell from 62 to 61, and the proton count decides which element an atom is — so an atom became a different element, which only a nuclear change can do. In change 2 the browning batter builds new flavor substances out of the same atoms — every atom keeps its identity, so the change is chemical, involving only the atoms' electrons. (c) The heat proves nothing. Energy moving in or out is a false clue — many chemical changes involve plenty of heat, and a nuclear change can happen silently in a sealed sample. Only the identity question decides the classification.

Form C

NUC-001 · easy · recall · seq 1 · authored fresh (stage 2) · mcq4
A substance goes through a chemical change. What happens to the identity of each of its atoms?
Every atom keeps its identity through the change. KEY
A few atoms become atoms of new elements.
Atoms are destroyed and fresh ones are created.
Identities blend wherever atoms are joined together.
NUC-002 · easy · recall · seq 2 · authored fresh (stage 2) · mcq4
Which number decides which element an atom is?
The proton count — the atomic number. KEY
The neutron count.
The electron count.
The mass number.
NUC-006 · easy · recall · seq 3 · authored fresh (stage 2); rule-line-4 no-trigger family · mcq4
A nucleus is described as unstable. What does that tell you about how its coming change will start?
It will start from within — nothing outside needs to touch the nucleus. KEY
It will start when another particle strikes the nucleus.
It will start the moment the sample is warmed.
It will start the instant the nucleus first forms.
NUC-008 · easy · recall · seq 4 · authored fresh (stage 2); three-jobs family (rule line 5) · mcq4
An isotope's nuclei decay on their own. Which single word labels that isotope?
Radioactive. KEY
Stable.
Radiation.
Chemically reactive.
NUC-002 · medium · application · seq 5 · authored fresh (stage 2); proton-drop direction of the p4 family · mcq4
In one nuclear change, an atom's proton count drops from 59 to 57. What happened to the atom?
It became an atom of a different element — the one with 57 protons. KEY
It became a lighter isotope of the element it already was.
It stayed the same element, since elements can only gain protons.
It became an ion, because it now attracts two extra electrons.
NUC-003 · medium · application · seq 6 · authored fresh (stage 2); p6 family · mcq4
Change 1: an avocado slice left out turns brown as its surface molecules react — every atom keeps its identity. Change 2: an atom of selenium-75 in a factory gauge source becomes an atom of arsenic-75. Which option classifies both changes?
Change 1 is chemical; change 2 is nuclear. KEY
Change 1 is nuclear; change 2 is chemical.
Both change 1 and change 2 are chemical.
Both change 1 and change 2 are nuclear.
NUC-004 · medium · application · seq 7 · authored fresh (stage 2); p9 family · mcq4
A deep-space probe carries a small capsule of fuel whose nuclei change to supply its power for decades. If the same total energy had to come from burning fuel instead, what would the probe need to carry?
Around a million times the mass of the capsule's fuel. KEY
About the same mass as the capsule's fuel.
About twice the mass of the capsule's fuel.
Less than the capsule's fuel mass, since flames release energy faster.
NUC-005 · medium · application · seq 8 · authored fresh (stage 2); missing-mass family (WE wording is corpus - fully rephrased) · mcq4
After one nuclear change, careful weighing shows slightly less total mass than before. Where did the missing mass go?
It was converted into energy — that conversion is the change's energy source. KEY
It left as a proton that escaped without being detected.
It simply vanished — nuclear changes destroy a little mass outright.
It escaped as electrons boiling off the outside of the atom.
NUC-009 · medium · application · seq 9 · authored fresh (stage 2); p25 family · mcq4
Situation 1: courier parcels ride a conveyor through a screening beam from a sealed radioactive source. Situation 2: floodwater carrying dissolved radioactive atoms soaks into a cellar floor. Which option classifies both situations?
Situation 1 irradiated only; situation 2 contaminated. KEY
Situation 1 contaminated; situation 2 irradiated only.
Situation 1 irradiated only; situation 2 irradiated only.
Situation 1 contaminated; situation 2 contaminated.
NUC-006 · medium · application · seq 10 · authored fresh (stage 2); p16 family, element-label rotation · mcq4
Zinc-64 is stable, while zinc-69 is unstable. A student concludes that 'zinc' cannot be called a stable or an unstable element. Is the student right?
Yes — stability belongs to each specific isotope, not to the element. KEY
No — an element takes the label of its most common isotope.
No — if any isotope is unstable, the whole element is unstable.
No — stability is a property of samples, not of nuclei at all.
NUC-003 · medium · application · seq 11 · authored fresh (stage 2); p7 family · mcq4
Change 1: fresh mortar in a wall slowly hardens as its compounds react with the surroundings — every atom keeps its identity. Change 2: an atom of palladium-103 in a sealed therapy seed becomes an atom of rhodium-103. Which option classifies both changes?
Change 1 is chemical; change 2 is nuclear. KEY
Change 1 is nuclear; change 2 is chemical.
Both change 1 and change 2 are chemical.
Both change 1 and change 2 are nuclear.
NUC-007 · medium · application · seq 12 · authored fresh (stage 2); p20 family, too-many direction · mcq4
Stable thallium-205 has 124 neutrons for its 81 protons. Thallium-207 has 126 neutrons, and it is unstable. Why?
It has too many neutrons for its proton count. KEY
It has too few neutrons for its proton count.
Extra neutrons always add stability, so something else must be wrong.
Its proton count is too high for any neutron count to balance.
NUC-008 · medium · application · seq 13 · authored fresh (stage 2); p21 family; phrasing-pack smoke-detector instance, americium unnumbered (241 barred) · mcq4
A home smoke detector holds a tiny speck of americium, whose nuclei decay on their own. A technician opens the unit for a routine check, and a counter held near the speck clicks steadily. Where do the clicks come from?
From the nuclear radiation the decaying nuclei shoot out. KEY
From americium atoms drifting out of the detector into the room.
From the smoke detector's electronic circuitry switching on and off.
From chemical fumes reacting inside the counter's sensor.
NUC-009 · medium · application · seq 14 · authored fresh (stage 2); p24 family · mcq4
Wrench 1 spent an hour directly in the beam of a sealed sterilizer. Wrench 2 was dipped in a tank of machining coolant that carried radioactive atoms, and coolant residue still coats it. Which wrench is emitting radiation now as a result of these events?
Only wrench 2. KEY
Only wrench 1.
Both wrenches.
Neither wrench.
NUC-003 · medium · application · seq 15 · authored fresh (stage 2); p8 family · mcq4
Change 1: two-part dental filling paste hardens and warms slightly in the mouth as its compounds react — every atom keeps its identity. Change 2: an atom of aluminum-29 in an activation-test foil becomes an atom of silicon-29. Which option classifies both changes?
Change 1 is chemical; change 2 is nuclear. KEY
Change 1 is nuclear; change 2 is chemical.
Both change 1 and change 2 are chemical.
Both change 1 and change 2 are nuclear.
NUC-004 · medium · application · seq 16 · authored fresh (stage 2); p11 family, inversion critique · mcq4
A pamphlet claims that because burning is 'more complete' than nuclear change, a fuel-burning plant uses LESS material than a nuclear source for the same energy output. What is wrong with the claim?
It inverts the scale — for the same energy, burning needs around a million times MORE material. KEY
Nothing — completeness is what decides how much material a process needs.
The claim errs only in size — burning needs about ten percent more material.
The comparison is impossible, because energy totals from different processes can never be matched.
NUC-001 · hard · transfer · seq 17 · authored fresh (stage 2); p0 family · mcq4
A refinery pamphlet advertises an acid bath that chemically upgrades waste nickel into a much rarer metal. A chemist rejects the pamphlet without reading past the first line. What justifies the instant rejection?
A chemical bath works on electrons only — it can never change which element an atom is. KEY
Acid baths are too dilute for element conversion; a concentrated one might manage it.
Rare metals cannot form in liquids, only in solid rock.
The upgrade would consume more nickel than it produces, so it is merely unprofitable.
NUC-007 · hard · transfer · seq 18 · authored fresh (stage 2); p19 family, always-helpful rule (numbers <=12, ledger-free) · mcq4
A study sheet says: 'Neutrons hold the nucleus together, so adding neutrons always makes a nucleus more stable.' Boron-10 and boron-11 are stable, but boron-12 — one neutron more — changes on its own within a fraction of a second. What is wrong with the sheet?
Beyond the balanced count for the proton count, extra neutrons destabilize the nucleus. KEY
Nothing — boron-12's change must be caused by something other than its neutron count.
The sheet is backwards — every added neutron makes a nucleus less stable.
The sheet fails only for tiny nuclei, which have no room for extra neutrons.
NUC-005 · hard · transfer · seq 19 · authored fresh (stage 2); p13 family, direction trap · mcq4
A classmate claims that if a nuclear change releases only a LITTLE energy, its pieces can end up slightly HEAVIER than the original nucleus. Could that happen?
No — releasing energy means mass was converted away, so the pieces must total slightly less. KEY
Yes — the released energy can stick to the pieces and weigh them down.
Yes — whether the pieces gain or lose mass is random from change to change.
No — but only because so small a mass gain would be impossible to detect.
NUC-009 · hard · transfer · seq 20 · authored fresh (stage 2); p26 family, drying critique · mcq4
A student spills a solution carrying dissolved radioactive metal atoms onto a bench, then says: 'Once it dries, the problem is over — the radiation evaporates along with the liquid.' What is wrong with this?
The metal atoms stay behind on the bench when the liquid dries — the bench remains contaminated and keeps emitting. KEY
Nothing — emission needs a liquid, so a dry bench cannot give off radiation.
The student is wrong only about timing — the radiation evaporates a few days after the liquid does.
The bench was only irradiated by the spill, so there was never any problem at all.
NUC-003 · medium · application · seq 21 · authored fresh (stage 2); quiet-changes variant (element-free nuclear side) · frq
Change 1: bleach dabbed on a stained cloth lifts the color as its molecules attack the dye. Change 2: in a stored sample, one atom's proton count drops from 78 to 76. Type your answers:
Change 1: bleach dabbed on a stained cloth lifts the color as its molecules attack the dye. Change 2: in a stored sample, one atom's proton count drops from 78 to 76. Type your answers: (a) Classify each change as chemical or nuclear. (b) Justify each verdict using the one question the topic teaches you to ask about the atoms. (c) Neither change gives off any visible flash or warmth. Explain why the ABSENCE of an energy display also cannot decide either classification.
Part a. Classify each change as chemical or nuclear.
Model: Change 1 is a chemical change. Change 2 is a nuclear change.
Part b. Justify each verdict using the one question the topic teaches you to ask about the atoms.
Model: Ask: did any atom change its identity? The bleach breaks up the dye's molecules, but every atom keeps its identity — only the connections between atoms change, so it is chemical, involving only the electrons. In change 2 the proton count dropped from 78 to 76; the proton count decides which element an atom is, so a new element now sits where the old one was — a nuclear change.
Part c. Neither change gives off any visible flash or warmth. Explain why the ABSENCE of an energy display also cannot decide either classification.
Model: Energy evidence is a false clue in both directions. A change with no flash or warmth can still be nuclear, and a dramatic one can be purely chemical — how much energy shows on the outside settles nothing. The only deciding test is the identity question: did any atom change its identity?
Full model answer. (a) Change 1 is a chemical change. Change 2 is a nuclear change. (b) Ask: did any atom change its identity? The bleach breaks up the dye's molecules, but every atom keeps its identity — only the connections between atoms change, so it is chemical, involving only the electrons. In change 2 the proton count dropped from 78 to 76; the proton count decides which element an atom is, so a new element now sits where the old one was — a nuclear change. (c) Energy evidence is a false clue in both directions. A change with no flash or warmth can still be nuclear, and a dramatic one can be purely chemical — how much energy shows on the outside settles nothing. The only deciding test is the identity question: did any atom change its identity?

Form D

NUC-001 · easy · recall · seq 1 · authored fresh (stage 2) · mcq4
Why is it impossible for any chemical change to turn an atom of one element into an atom of another?
A chemical change never touches the nucleus, and only the nucleus sets the element. KEY
Elements repel one another too strongly for one to become the other.
It is possible, but only at extremely high temperatures.
Chemical changes are too slow for an element change to finish.
NUC-002 · easy · recall · seq 2 · authored fresh (stage 2) · mcq4
What can a nuclear change do that no chemical change can ever do?
Turn an atom of one element into an atom of a different element. KEY
Release energy to the surroundings.
Rearrange how atoms are joined to one another.
Make a completely new substance.
NUC-006 · easy · recall · seq 3 · authored fresh (stage 2); left-alone behavior family · mcq4
A sealed box holds a single nucleus, completely undisturbed. If the nucleus is stable, what will it do in there?
Stay exactly the same, forever. KEY
Change eventually, since every nucleus changes given enough time.
Slowly shed particles until it becomes lighter.
Change only if the box is opened and light reaches it.
NUC-008 · easy · recall · seq 4 · authored fresh (stage 2); three-jobs family (rule lines 1-2) · mcq4
There is a name for the event in which an unstable nucleus changes on its own into a more stable nucleus. What is it?
Radioactive decay. KEY
Nuclear radiation.
Stabilization capture.
An electron rearrangement.
NUC-002 · medium · application · seq 5 · authored fresh (stage 2); neutron-capture contrast case of the p4 family · mcq4
A nucleus absorbs one extra neutron during a change, while its proton count stays 45. Is the atom now a different element?
No — same element, different isotope, because the proton count is unchanged. KEY
Yes — any change to the nucleus makes a new element.
Yes — the extra particle tips it into the next element.
No — because a nucleus can never really absorb a neutron.
NUC-003 · medium · application · seq 6 · authored fresh (stage 2); p6 family · mcq4
Change 1: a firework shell bursts into light and heat as the packed compounds erupt. Change 2: an atom of iridium-192 in an industrial testing source becomes an atom of platinum-192. Which option classifies both changes?
Change 1 is chemical; change 2 is nuclear. KEY
Change 1 is nuclear; change 2 is chemical.
Both change 1 and change 2 are nuclear.
Both change 1 and change 2 are chemical.
NUC-004 · medium · application · seq 7 · authored fresh (stage 2); same-mass statement family · mcq4
Two samples have the same mass. Sample 1 releases energy through nuclear changes; sample 2 releases energy by burning completely. Which statement compares their energy totals correctly?
Sample 1 releases around a million times more energy than sample 2. KEY
Sample 2 releases around a million times more energy than sample 1.
The two release about the same energy, because the masses are equal.
Sample 1 releases about ten times more energy than sample 2.
NUC-005 · medium · application · seq 8 · authored fresh (stage 2); electrons-only contrast family (seed p12's class, fresh scene) · mcq4
Gram for gram, why can no burning process ever equal the energy released by nuclear changes?
Burning involves only the electrons — it never taps the mass of the nucleus. KEY
Burning is too easily interrupted to release its full energy total.
It could match, if the fuel were ground fine enough to burn completely.
Flames lose most of their energy as light, which cannot be counted.
NUC-009 · medium · application · seq 9 · authored fresh (stage 2); p25 family · mcq4
Situation 1: a welder's helmet hangs across the room from a sealed test source, directly exposed to its radiation. Situation 2: a lab stool is splashed with a liquid that holds radioactive atoms. Which option classifies both situations?
Situation 1 irradiated only; situation 2 contaminated. KEY
Situation 1 contaminated; situation 2 irradiated only.
Situation 1 contaminated; situation 2 contaminated.
Situation 1 irradiated only; situation 2 irradiated only.
NUC-006 · medium · application · seq 10 · authored fresh (stage 2); p16 family, bottle framing · mcq4
A stockroom holds two bottles of the same element. Every nucleus in bottle 1 is bromine-79, which never changes on its own; every nucleus in bottle 2 is bromine-77, which sooner or later changes on its own. What follows?
Bottle 2 holds the unstable isotope — same element, different stability. KEY
Both bottles behave identically, since both hold the same element.
Bottle 1 holds the unstable isotope, since heavier nuclei are less stable.
Neither bottle's nuclei will ever change, as long as both stay sealed.
NUC-003 · medium · application · seq 11 · authored fresh (stage 2); p7 family, nuclear-first rotation · mcq4
Change 1: an atom of cadmium-109 in a calibration source becomes an atom of silver-109. Change 2: glue between two boards sets hard as its molecules link together, each atom keeping its identity throughout. Which option classifies both changes?
Change 1 is nuclear; change 2 is chemical. KEY
Change 1 is chemical; change 2 is nuclear.
Both change 1 and change 2 are chemical.
Both change 1 and change 2 are nuclear.
NUC-007 · medium · application · seq 12 · authored fresh (stage 2); p20 family, too-many direction · mcq4
Stable terbium-159 has 94 neutrons for its 65 protons. Terbium-161 has 96 neutrons, and it is unstable. What is the reason?
Its neutron count overshoots the balanced count for its protons. KEY
Its neutron count falls short of the balanced count for its protons.
Nuclei that heavy are unstable no matter what their neutron count is.
Two of its neutrons carry charge, which unbalances the nucleus.
NUC-008 · medium · application · seq 13 · authored fresh (stage 2); isotope-label rotation of the p21 family · mcq4
Cerium-144 nuclei in a sealed research source keep changing on their own into more stable nuclei, shooting out energy and particles. Which single label fits cerium-144 itself?
Radioactive. KEY
Stable.
Nuclear radiation.
Irradiated.
NUC-009 · medium · application · seq 14 · authored fresh (stage 2); p24 family, duration twist · mcq4
Notebook 1 lay for a week beside a sealed source that shone its radiation over it. Notebook 2 got a smear of contaminated grease on its cover. Which notebook gives off radiation afterward as a result of these events?
Only notebook 2. KEY
Only notebook 1.
Both notebooks.
Neither notebook.
NUC-003 · medium · application · seq 15 · authored fresh (stage 2); p8 family, nuclear-first rotation · mcq4
Change 1: an atom of gallium-70 in a crystal-growing bench sample becomes an atom of germanium-70. Change 2: hair dye develops on a strand, its color changing as dye molecules transform — every atom keeps its identity all the while. Which option classifies both changes?
Change 1 is nuclear; change 2 is chemical. KEY
Change 1 is chemical; change 2 is nuclear.
Both change 1 and change 2 are chemical.
Both change 1 and change 2 are nuclear.
NUC-004 · medium · application · seq 16 · authored fresh (stage 2); p11 family · mcq4
Over one year, installation 1 delivered its energy from nuclear changes and installation 2 delivered the same total by burning fuel. Which installation consumed less mass of material, and by roughly what factor?
Installation 1 — by a factor of around a million. KEY
Installation 2 — by a factor of around a million.
Installation 1 — but only by a factor of around a thousand.
Neither — the same energy always means the same mass of material.
NUC-001 · hard · transfer · seq 17 · authored fresh (stage 2); p0 family (element-free target - gold is NUC-001's own hook material) · mcq4
An infomercial sells a countertop kit said to chemically transform chromium atoms into a precious metal. Which criticism is the decisive one?
The kit is chemical, and chemical changes never touch the nucleus — so no atom can become a different element. KEY
The kit's batches are too small — an industrial version could achieve the transformation.
A precious metal's atoms are too heavy for chromium to become in a single step.
The transformation would be real but unstable, with the new metal reverting overnight.
NUC-007 · hard · transfer · seq 18 · authored fresh (stage 2); p19 family, heavy-only rule · mcq4
A podcast claims: 'Instability is a heavy-nucleus problem — small nuclei are all stable.' Helium-6, with 4 neutrons for its 2 protons, changes on its own in under a second. What is wrong with the podcast's rule?
Instability comes from a neutron count out of balance with the proton count, at any size of nucleus. KEY
Nothing — helium-6 counts as a heavy nucleus because it has twice helium's usual neutron count.
The claim is backwards — small nuclei are the unstable ones and heavy nuclei are safe.
Helium-6 is unstable only because helium is a gas, and gases cannot hold their nuclei together.
NUC-005 · hard · transfer · seq 19 · authored fresh (stage 2); p13 family, artifact critique · mcq4
A skeptic argues the 'missing mass' in nuclear changes is an illusion: 'The pieces fly apart quickly, and scales simply misread fast-moving things as lighter.' Why does the argument fail?
The loss is real — that mass was converted into the released energy. KEY
It does not fail — no experiment can weigh the pieces of a nuclear change at all.
It fails only because the pieces move too slowly for the misreading to matter.
It fails because the missing mass actually hides in the leftover nucleus.
NUC-009 · hard · transfer · seq 20 · authored fresh (stage 2); p26 family, portability critique · mcq4
A worker's sleeve picked up flecks of a contaminated powder. He says: 'As long as I stay far from the source area, nothing on me is emitting.' What is wrong with his reasoning?
The radioactive atoms travel with the sleeve — contamination keeps decaying and emitting wherever it goes. KEY
Nothing — radiation exists only near its source area, so distance ends the emission.
He is wrong only because the source area's radiation can reach any distance.
He is safe because powder flecks are too small to hold radioactive atoms.
NUC-003 · medium · application · seq 21 · authored fresh (stage 2); demo-gate pattern; Os-193 -> Ir-193 real (mode unnamed); iridium same-form-D second cell (recorded) · frq
Change 1: a struck match bursts into flame as its tip's compounds ignite. Change 2: an atom of osmium-193 in a metallurgy archive sample becomes an atom of iridium-193. Type your answers:
Change 1: a struck match bursts into flame as its tip's compounds ignite. Change 2: an atom of osmium-193 in a metallurgy archive sample becomes an atom of iridium-193. Type your answers: (a) Classify each change as chemical or nuclear. (b) Justify each verdict using the one question the topic teaches you to ask about the atoms. (c) Explain why the match's burst of light and heat cannot be used as evidence for either verdict.
Part a. Classify each change as chemical or nuclear.
Model: Change 1 is a chemical change. Change 2 is a nuclear change.
Part b. Justify each verdict using the one question the topic teaches you to ask about the atoms.
Model: Ask: did any atom change its identity? The match tip's compounds rearrange into new substances, but every atom keeps its identity — a chemical change, touching only the atoms' electrons. In the archive sample, an osmium-193 atom became an iridium-193 atom: even though the mass number stays 193, the proton count changed, and the proton count decides the element — a nuclear change.
Part c. Explain why the match's burst of light and heat cannot be used as evidence for either verdict.
Model: The flame is a false clue. Plenty of chemical changes release intense light and heat, so an energy display cannot separate chemical from nuclear. Only the identity question decides: the match's atoms all kept their identity; the sample's atom did not.
Full model answer. (a) Change 1 is a chemical change. Change 2 is a nuclear change. (b) Ask: did any atom change its identity? The match tip's compounds rearrange into new substances, but every atom keeps its identity — a chemical change, touching only the atoms' electrons. In the archive sample, an osmium-193 atom became an iridium-193 atom: even though the mass number stays 193, the proton count changed, and the proton count decides the element — a nuclear change. (c) The flame is a false clue. Plenty of chemical changes release intense light and heat, so an energy display cannot separate chemical from nuclear. Only the identity question decides: the match's atoms all kept their identity; the sample's atom did not.

Form E

NUC-001 · easy · recall · seq 1 · authored fresh (stage 2) · mcq4
Across every chemical change, one thing is rearranged and one thing is preserved. Which pair is right?
Rearranged: how atoms are joined to one another. Preserved: each atom's identity. KEY
Rearranged: each atom's identity. Preserved: how atoms are joined.
Rearranged: the nucleus of each atom. Preserved: the electrons.
Rearranged: the number of atoms. Preserved: their connections.
NUC-002 · easy · recall · seq 2 · authored fresh (stage 2) · mcq4
After one nuclear change, an atom's proton count is different from before. What follows?
The atom is now a different element. KEY
The atom is a different isotope of the same element.
Nothing follows until the electron count catches up.
The atom stops being an atom at all.
NUC-006 · easy · recall · seq 3 · authored fresh (stage 2); rule-line-1 two-kinds framing · mcq4
Every nucleus in the universe falls into one of two kinds. Which pair of descriptions matches the two kinds?
Ones that stay the same forever on their own, and ones that change on their own. KEY
Ones that change when struck, and ones that never change even when struck.
Ones that have changed before, and ones that have not yet.
Ones heavier than average, and ones lighter than average.
NUC-008 · easy · recall · seq 4 · authored fresh (stage 2); three-jobs consolidation family (rule line 7; seed p23's format, element-free) · mcq4
Exactly one of the terms below names an EVENT rather than a thing or a property. Which one?
Radioactive decay. KEY
Nuclear radiation.
Radioactive.
Unstable.
NUC-002 · medium · application · seq 5 · authored fresh (stage 2); abstract form of the taught unchanged-mass surprise (the P-32/S-32 class, instances freshened) · mcq4
In one nuclear change, an atom's mass number stays 74 while its proton count rises from 33 to 34. Did the element change?
Yes — the proton count changed, and the proton count decides the element. KEY
No — the unchanged mass number means the atom's identity is unchanged.
No — an element change always changes the mass number too.
It cannot be determined without the neutron count.
NUC-003 · medium · application · seq 6 · authored fresh (stage 2); p6 family, nuclear-first rotation · mcq4
Change 1: an atom of samarium-153 in a pharmacy vial becomes an atom of europium-153. Change 2: the pages of an old book slowly yellow as their molecules change partners over the years, every atom keeping its identity as the pages age. Which option classifies both changes?
Change 1 is nuclear; change 2 is chemical. KEY
Change 1 is chemical; change 2 is nuclear.
Both change 1 and change 2 are chemical.
Both change 1 and change 2 are nuclear.
NUC-004 · medium · application · seq 7 · authored fresh (stage 2); p9 family, planning frame · mcq4
A freight planner must deliver one year of energy to an island. Option 1 is material for nuclear changes; option 2 is fuel to burn. The nuclear material fits in a lunchbox. Roughly what fuel MASS should the planner expect, compared with the mass of that nuclear material?
Around a million times the nuclear material's mass. KEY
About the same mass — the energy need is the same either way.
About a thousand times the nuclear material's mass.
No fuel at all — burning cannot deliver the same total energy.
NUC-005 · medium · application · seq 8 · authored fresh (stage 2); pick-the-source family · mcq4
Pick the statement that correctly names the energy source of a nuclear change.
A small amount of the nucleus's mass is converted into a very large amount of energy. KEY
Strong chemical bonds between the protons snap and release their stored energy.
The nucleus releases heat it has carried since the atom first formed.
The atom's electron cloud collapses inward and gives up its energy.
NUC-009 · medium · application · seq 9 · authored fresh (stage 2); p25 family · mcq4
Situation 1: bags pass under a scanning beam from a sealed radioactive source at a stadium gate. Situation 2: a farm truck's tires pick up clumps of ground that hold radioactive atoms. Which option classifies both situations?
Situation 1 irradiated only; situation 2 contaminated. KEY
Situation 1 contaminated; situation 2 irradiated only.
Situation 1 irradiated only; situation 2 irradiated only.
Situation 1 contaminated; situation 2 contaminated.
NUC-006 · medium · application · seq 10 · authored fresh (stage 2); p16 family, overgeneralization guard · mcq4
Tellurium-125 is stable, while tellurium-132 is unstable. A classmate says this proves that adding mass is what makes nuclei unstable. What is the safest conclusion instead?
Only that stability differs isotope by isotope — one pair cannot establish a heavier-means-unstable rule. KEY
The classmate is right — the heavier isotope of an element is always the unstable one.
The pair proves nothing, because stability cannot be known for individual isotopes.
The pair shows that tellurium as an element is unstable.
NUC-003 · medium · application · seq 11 · authored fresh (stage 2); p7 family · mcq4
Change 1: a road flare burns crimson for an hour as the compounds packed inside it flare up. Change 2: an atom of holmium-166 in a therapy dose becomes an atom of erbium-166. Which option classifies both changes?
Change 1 is chemical; change 2 is nuclear. KEY
Change 1 is nuclear; change 2 is chemical.
Both change 1 and change 2 are nuclear.
Both change 1 and change 2 are chemical.
NUC-007 · medium · application · seq 12 · authored fresh (stage 2); p20 family, predict rotation (seed's own question form) · mcq4
Stable hafnium-178 shows hafnium's balanced count: 106 neutrons for its 72 protons. Hafnium-172 has only 100 neutrons. Predict its stability.
Unstable — it has too few neutrons for its proton count. KEY
Unstable — it has too many neutrons for its proton count.
Stable — its proton count is the same 72 as every other hafnium nucleus.
Stable — fewer neutrons means less crowding, so the nucleus holds together more easily.
NUC-008 · medium · application · seq 13 · authored fresh (stage 2); p21 family, luminous-dial instance (phrasing pack) · mcq4
The hands of an old museum clock were painted with promethium-147. A conservator lifts the glass cover and holds a radiation counter just above the hands; it clicks steadily. What reaches the counter and sets off the clicks?
The nuclear radiation — energy and particles shot out by the decays. KEY
Promethium atoms evaporating off the painted hands.
The more stable nuclei produced by each decay.
Light from the glowing paint, which the counter reads as counts.
NUC-009 · medium · application · seq 14 · authored fresh (stage 2); p24 family, portability twist · mcq4
Jacket 1, packed in a cargo shipment, rode a belt past a sealed radioactive source whose screening beam swept across it. Jacket 2 brushed a shelf where spilled granules holding radioactive atoms had settled, and some cling to its sleeve. Which jacket is giving off radiation on the way home as a result of these events?
Only jacket 2. KEY
Only jacket 1.
Both jackets.
Neither jacket.
NUC-003 · medium · application · seq 15 · authored fresh (stage 2); p8 family · mcq4
Change 1: vinegar poured onto washing soda fizzes as new gas bubbles out of the mix — every atom keeps its identity. Change 2: an atom of praseodymium-143 in a research flask becomes an atom of neodymium-143. Which option classifies both changes?
Change 1 is chemical; change 2 is nuclear. KEY
Change 1 is nuclear; change 2 is chemical.
Both change 1 and change 2 are chemical.
Both change 1 and change 2 are nuclear.
NUC-004 · medium · application · seq 16 · authored fresh (stage 2); p11 family, planning frame · mcq4
An engineer sizes two backup-power options for the same yearly energy need: option 1 stores fuel to burn; option 2 uses material whose nuclei change. The fuel plan needs a full storage yard of fuel. What MASS of nuclear material should the engineer expect, compared with the fuel's mass?
Around a millionth of the fuel's mass — a small container of material. KEY
Around the same mass as the fuel — a matching storage yard.
Around a thousandth of the fuel's mass — one large tank.
More mass than the fuel, since dense material weighs more per crate.
NUC-001 · hard · transfer · seq 17 · authored fresh (stage 2); p0 family · mcq4
A game-show 'alchemist' claims a secret reagent chemically changes lithium atoms into beryllium atoms. The audience cannot test the reagent. Why can they still be certain the claim is false?
Changing lithium into beryllium means changing the nucleus, which no chemical process touches. KEY
Because a real transmutation reagent would already have made its inventor famous.
They cannot be certain — an untested claim might always be true.
Because reagents work only on liquids, and lithium is a solid.
NUC-007 · hard · transfer · seq 18 · authored fresh (stage 2); p19 family, same-element rule · mcq4
A revision card reads: 'Stability is set by the protons' repulsion, and isotopes of one element have identical protons — so every isotope of an element must be equally stable.' Rubidium-85 is stable, while rubidium-87, with two more neutrons, is unstable. What is wrong with the card?
The protons only set the needed balance — each isotope's own neutron count decides if it is met. KEY
Nothing — rubidium-87 will turn out to be stable once it is measured more carefully.
The card errs only in scope — the shared-stability rule holds for solids but not for soft metals.
Repulsion between protons has nothing to do with stability at all.
NUC-005 · hard · transfer · seq 19 · authored fresh (stage 2); p13 family, ledger question · mcq4
A nuclear change in a single nucleus releases an enormous amount of energy. In the topic's bookkeeping, which ledger did that energy come out of?
The mass ledger — a small amount of the nucleus's mass was converted into the energy. KEY
The heat ledger — energy the nucleus had been keeping warm since it formed.
The bond ledger — connections between the protons snapping like chemical bonds.
No ledger — nuclear changes create their energy from nothing.
NUC-009 · hard · transfer · seq 20 · authored fresh (stage 2); p26 family, mislabel critique · mcq4
A news piece says a delivery van was 'irradiated' when grime containing radioactive atoms dried onto its wheels, and concludes the van 'stopped emitting the moment it left the exposure zone.' What is wrong with the report?
That is contamination — the atoms in the grime keep decaying, so the van keeps emitting. KEY
Nothing — leaving the zone ends any kind of radiation involvement.
The report is right that it was irradiation, but wrong that irradiation ever stops.
The only error is the word 'grime' — solids cannot carry radioactive atoms.
NUC-003 · medium · application · seq 21 · authored fresh (stage 2); demo-gate pattern; Sb-122 -> Te-122 real (mode unnamed); tellurium same-form-E second cell (recorded) · frq
Change 1: a backyard compost pile stays warm for weeks as its contents break down into new substances. Change 2: an atom of antimony-122 in an alloy-lab sample becomes an atom of tellurium-122. Type your answers:
Change 1: a backyard compost pile stays warm for weeks as its contents break down into new substances. Change 2: an atom of antimony-122 in an alloy-lab sample becomes an atom of tellurium-122. Type your answers: (a) Classify each change as chemical or nuclear. (b) Justify each verdict using the one question the topic teaches you to ask about the atoms. (c) A visitor claims the weeks of steady warmth prove the compost pile is 'running on nuclear energy.' Explain why the warmth cannot support that conclusion.
Part a. Classify each change as chemical or nuclear.
Model: Change 1 is a chemical change. Change 2 is a nuclear change.
Part b. Justify each verdict using the one question the topic teaches you to ask about the atoms.
Model: Ask: did any atom change its identity? In the compost pile, molecules break down and rearrange, but every atom keeps its identity — a chemical change, involving only the atoms' electrons. In the alloy-lab sample, an antimony-122 atom became a tellurium-122 atom: the mass number stayed 122, but the proton count rose, and the proton count decides the element — a nuclear change.
Part c. A visitor claims the weeks of steady warmth prove the compost pile is 'running on nuclear energy.' Explain why the warmth cannot support that conclusion.
Model: The warmth proves nothing. Energy release is a false clue — plenty of chemical changes, composting included, give off heat steadily for a long time. Whether a change is chemical or nuclear is decided only by asking whether any atom changed its identity, and in the pile none did.
Full model answer. (a) Change 1 is a chemical change. Change 2 is a nuclear change. (b) Ask: did any atom change its identity? In the compost pile, molecules break down and rearrange, but every atom keeps its identity — a chemical change, involving only the atoms' electrons. In the alloy-lab sample, an antimony-122 atom became a tellurium-122 atom: the mass number stayed 122, but the proton count rose, and the proton count decides the element — a nuclear change. (c) The warmth proves nothing. Energy release is a false clue — plenty of chemical changes, composting included, give off heat steadily for a long time. Whether a change is chemical or nuclear is decided only by asking whether any atom changed its identity, and in the pile none did.

End of Topic Test: Alpha decay and nuclear equations & Beta decay, gamma radiation, and penetrating power & Completing any nuclear equation (u14-t2 · 5 forms × 21 items · 105 total)

David's notes for James:
full notes file
# u14-t2 — notes/queries from David's side (U14-G2)

1. FRQ COMPOSITION - frq_per_form = 1 (your gate data's frq_per_form=1 concurs): the calc-heavy FRQ split was EVALUATED AND NOT TRIGGERED after an honest predicate check - no NUC-010..021 lesson carries a displayEquation, and the two quant atoms (NUC-013/NUC-016) are integer NUMBER-SHIFT routines (-4/-2, +1/0), not substituted-formula calculations, so the 5-line calculation scaffold is barred everywhere (V-T9; no formula is ever made-the-subject). The FRQ slot goes to your designated capstone (NUC-021 'Finding the missing particle'): a three-part typed production covering ALL THREE missing-species positions per the extraNotes coverage mandate - (a) missing emitted particle, (b) missing daughter nucleus, (c) missing STARTING nucleus - each part requiring the two-totals routine plus a justification; rubric 30/35/35 = 100; instances rotate per form (Ru-103/Sr-91/Re-185 on A, fresh real decays on B-E). D5 evaluated and NOT applied: min(20, 6 x 12) = 20 -> full 20-objective allocation, every scope lesson >= 1 row.
2. COMPOSITION SHAPE - per form: 13 mcq4 + 2 numeric-entry + 5 typed-text + 1 FRQ (total bank 105 = 65 mcq4 + 10 numeric + 25 text + 5 frq across 12 lessons). The two numeric rows (seq 1 and 8) match your two numeric-answer gate seeds 1:1; the five text rows (seqs 5/7/9/11/14) carry your five text-seed task families (alpha daughter, beta daughter, write-the-full-beta-equation, write-the-full-alpha-equation, identify-from-totals).
3. NUMERIC UNIT JUDGMENT CALL (A-U14G2-4, confirm): both numeric answers are COUNTS and your seed unit fields were empty, but our V-T6 numeric contract requires a unit - so seq 1 carries unit 'neutrons' (alpha-particle neutron count, value 2) and seq 8 carries unit 'protons' (the atomic-number total IS a proton count; whole-number totals like 90 on form A). integer:true set on both; sigFigs record the displayed digit count and the gradingNote states the whole-number-count grading intent; acceptedAlternates empty (nothing else is a correct spelling of a count).
4. TYPED-ANSWER CONTRACT (text rows, confirm): unit:null / sigFigs:null by recorded convention (an isotope symbol or nuclear equation has neither). Unicode notation is NEVER required to type: every text answer accepts the name form (francium-221), the symbol form (Fr-221), caret/slash plain-digit forms (^221_87Fr, 221/87 Fr), and for equations an ASCII arrow (->) plus 'e' for the beta particle in the name form - the acceptedAlternates enumerate these per item and the gradingNote states the rule. wrongValueDiagnostics carry the misconception-keyed wrong spellings (kept-Z, kept-mass, wrong-direction errors).
5. COURSE-WIDE INSTANCE RULE + U14 PHRASING PACK (binding, wave 6) - nuclear decay IS the topic, so radioactivity language is unavoidable; everything stays curricular and clinical exactly as the lessons teach. Dispositions to confirm: (a) uranium/plutonium NEVER appear in any authored field even though YOUR spec corpus legally teaches U-238/Pu-239 as worked instances - every seed carrying them was freshened to a real benign decay, and the '(Atomic numbers: ...)' reference windows are chosen so the Pu symbol never appears in a list; (b) no reactor/weapon/enrichment/meltdown/dose/harm-quantification token anywhere; (c) ~45 fresh REAL decays cover the bank (alpha: Gd-148, Es-253, Fr-221, Po-211..., beta-minus: Fe-59, Ce-141, Er-169, La-140..., gamma isomers Se-77m, Sn-119m, Xe-129m), each mode-correct against nuclide data; (d) packaging re-sweep over forms_final AND this export body: ZERO hits on uranium/plutonium/enrich/reactor/weapon/bomb/warhead/meltdown/fission/chain-reaction. Zero content-filter events across every authoring/blind/sol round - the clinical phrasing held.
6. F-SYMBOL ADJUDICATION (gate_config family, confirm): the taught alpha-particle symbol (4-over-2 He) is MANDATED by the lessons' own equation format on every alpha-equation display (NUC-011/012/014 rule lines), and our freshness scanner normalizes its stacked digits to the token '42' - which the spec corpus carries in every alpha lesson - so every symbol-displaying cell structurally collides. '24' is the same artifact on the NUC-010-taught swap-error rendering (2-over-4 He, the lesson's own fluency misconception), used only as the misconception-keyed distractor on the alpha-keyed seq-12 cells. Relief is scoped to exactly these two tokens on 31 enumerated cells; every OTHER number in those cells stays fully armed and single-form (asserted instance ledger). Enforced by the gate-local adjudication wrapper over the UNTOUCHED shared validator (parity guard MATCH, 886/886 fail lines covered, 0 uncovered, exit 0).
7. F-ZLIST ADJUDICATION (gate_config family, confirm): YOUR NUC-013 extraNotes mandate the '(Atomic numbers: X n, ...)' parenthetical reference list on every element-naming stem (answer element never first or last - table-reading, not memory). Periodic-table Z values are reference data shown to every student on every form, and the spec's own lists already carry the values, so spec-side and cross-form collisions are structurally unavoidable. Relief is scoped to LIST values on the 36 enumerated list-bearing cells ONLY; every mass number and notation composite in those same cells stays armed and single-form; a list value colliding with a NON-list cell remains a hard fail (audited - e.g. the form-A '59' family never crosses forms).
8. F-CODEBOOK ADJUDICATION (gate_config family, confirm): NUC-019 TEACHES its three barrier rows by name - 'a sheet of paper', 'a thin sheet of aluminum', 'thick lead or thick concrete' - and R11 mandates assessing that codebook by classification and shielding selection, so 'aluminum' and 'lead' (both base-lexicon materials) are the lesson's own taught category vocabulary on every NUC-019 item (the U01-G3 A6 class, but the codebook is verbal - no reference figure to hang relief on). Scoped to these two materials on the ten seq-6/seq-18 cells only; 'paper'/'concrete' are not lexicon materials and scan normally.
9. MIXED-BRANCH NUCLIDES (A-U14G2-5, confirm): At-211 (E#12), Bi-212 (C#21a) and Tb-149 (E#16; real 16.7% alpha branch) have branched real decays. They appear ONLY in complete-the-equation tasks where the shown/asserted decay IS the genuine alpha branch - never in which-decay-type classification items, which use deterministic single-mode nuclides throughout.
10. NOTATION-ONLY STEM DEVIATION (A-U14G2-6, disclose): where the taught stem format names the parent AND shows its notation ('Polonium-214 (214-over-84 Po)') but the spelled element name is own-lesson corpus or homed to another form by the instance ledger, the stem shows notation only (C#9, C/D/E#11, B-E#16, the seq-20 family). The task - reading the symbol and applying the shift rules - is unchanged.
11. SEED USAGE - pool 36 (3 per lesson x 12), demo_curated 3 = byte-duplicates of pool entries (deduped at stage 1, both refs cited), prod_seeds EMPTY, cold list ignored (standing ANSWERS #3). All 20 objective form-A rows are seed-derived: 10 placed CLEAN (p2/p4/p8/p10/p15/p21/p24/p27/p28/p35, plus p29 as the seq-18 form-D rotation and p22's instance carried in notation at C#20) and 10 FRESHENED in content under the strict SEED RULING (banned U/Pu instances, corpus-number collisions, own-lesson-name collisions - structure and misconception keys preserved, all fields swept after every swap). The FRQ is authored fresh on your NUC-021 capstone pattern (frq_seeded 0 - the gate has no FRQ-shaped seed). Spares: 16. Forms B-E are fresh-authored parallels.
12. QC LEDGER (provenance): deterministic validators 11/12 PASS as shipped + adjudication wrapper VERDICT PASS exit 0 (V-T7's 886 collision lines 100% covered by the three recorded families, parity guard MATCH). Blind round 1 (r1 = gpt-5.6-sol blind role, r2 = gemini; 105 items each): key picks 130/130, all 40 keyless numeric/text/FRQ slots hand-graded all-match, 5 hard fails (A#18/C#18 barrier-codebook two-defensible-options, D#15/D#17 partial-truth verdict options, E#3 ambiguous 'comes out') -> 45-edit wave incl. class sweeps (seq-15/17/20 option-exclusivity audit on all forms, 'None of the three' variety sweep, seq-19 verbatim-echo removal, C#16/E#16 cueing instance swaps, D#18 handling-safety reframe per the phrasing pack); re-blind rounds 2-4 (fresh tags, 47 changed items): 0 hard fails, 74/74 key picks, FRQs re-graded all-match. gpt-5.6-sol authoritative: loop 1 -> 4 FAILs (all fixed with class sweeps: seq-3 'Only'-qualifier distractors, A/B#18 universal qualifiers, alpha-'charge' wording purged from all five FRQ prompts/rubrics/model answers); loop 2 -> 2 stale FAILs traced to the FRQ stem field duplicating frq.prompt (stems synced); loop 3 -> 0 FAIL, final ledger 105/105 pass, ZERO honest survivors.
13. SOL FACTUAL OVERRIDE, RESOLVED CLEAN (disclose): sol's loop-1 verdict on B#7 claimed Er-169 is not a beta-minus emitter (electron capture to Ho-169). That claim is factually wrong - Er-169 is neutron-rich (N = 101) and a real pure beta-minus emitter to Tm-169 (the medical radiosynovectomy isotope); EC would require a neutron-poor nuclide. The item was NOT patched; sol itself passed it on loop-2 re-read, so no recorded survivor remains.
14. PACKAGING FORMAT PATCH (disclose): at export time the five FRQ items were re-formatted - FORMATTING ONLY, zero wording/points changes - to the exporter's lettered-part contract: blank-line part breaks in the prompt (and the duplicated stem), newline-anchored (b)/(c) in the model answer, and '(part x)' tags on the rubric criteria (they carried bare '(a)/(b)/(c)' prefixes). Whitespace-normalized equality asserted per field; layer identity (form_A..E == forms_v1 == forms_final) re-asserted; the fresh adjudication-aware validator run is BYTE-IDENTICAL to the stage-7 record. Log: _patch_package_frq_format_log.json.
15. KNOWN SHARED-EXPORTER SCOPING GAP (recurrence, disclose): _shared/make_james_export.py writes the export in full and then fails one post-write assert on TEXT rows (its numeric unit/sigFigs contract applied to text interactions; this gate's typed rows are unit-null/sigFigs-null by recorded contract). _shared is never edited from a gate: the gate-local _verify_james_export.py re-executes the ENTIRE shared verification suite with the one interaction-scoping correction plus this gate's recorded contracts - exit 0, all round-trip checks pass. Gap already on the maintainer's batch list (batched at U2-G5).
16. NOTA/AOTA: zero literal none-/all-of-the-above hits across your 36-seed pool (V-T5 regex clone at stage 1); zero replace_distractor flags; V-T5 PASS on all forms. (The 'None of the three types' style option appears at most once per form as a substantive type-classification claim, never as a literal none-of-the-above.)
17. TITLE - 'End of Topic Test: Alpha decay and nuclear equations & Beta decay, gamma radiation, and penetrating power & Completing any nuclear equation' (the gate's three topic titles joined with ' & ', 'Topic N:' prefixes stripped, standing G1-canon convention).

Form A

NUC-010 · easy · recall · seq 1 · SEED pool[2] = NUC-010 gate[2], kept (taught-constant item) · numeric
An alpha particle is written ⁴₂He. How many neutrons does it contain?
Answer: 2 neutrons KEY
wrongValueDiagnostics
[
 {
  "value": 4,
  "misconception": "you read the mass number as the neutron count — the mass number 4 counts protons AND neutrons together",
  "feedback": "This answer is wrong — you read the mass number as the neutron count; the mass number 4 counts protons AND neutrons together, so subtract the 2 protons."
 },
 {
  "value": 6,
  "misconception": "you added the two numbers — the neutron count is the mass number MINUS the proton count",
  "feedback": "This answer is wrong — you added the two numbers; the neutron count is the mass number MINUS the proton count: 4 − 2 = 2."
 },
 {
  "value": 0,
  "misconception": "you gave the particle no neutrons — 2 of its 4 nuclear particles are neutrons",
  "feedback": "This answer is wrong — you gave the particle no neutrons; 2 of its 4 nuclear particles are neutrons."
 }
]
feedback
{
 "keyExplanation": "Neutron count = mass number − proton count = 4 − 2 = 2. The alpha particle's 4 nuclear particles are 2 protons and 2 neutrons.",
 "anticipatedWrong": [
  {
   "value": 4,
   "misconception": "you read the mass number as the neutron count — the mass number 4 counts protons AND neutrons together",
   "feedback": "This answer is wrong — you read the mass number as the neutron count; the mass number 4 counts protons AND neutrons together, so subtract the 2 protons."
  },
  {
   "value": 6,
   "misconception": "you added the two numbers — the neutron count is the mass number MINUS the proton count",
   "feedback": "This answer is wrong — you added the two numbers; the neutron count is the mass number MINUS the proton count: 4 − 2 = 2."
  },
  {
   "value": 0,
   "misconception": "you gave the particle no neutrons — 2 of its 4 nuclear particles are neutrons",
   "feedback": "This answer is wrong — you gave the particle no neutrons; 2 of its 4 nuclear particles are neutrons."
  }
 ]
}
NUC-015 · easy · recall · seq 2 · SEED pool[15] = NUC-015 gate[0], kept · mcq4
In the beta particle's symbol ⁰₋₁e, why is the top number 0?
An electron is not a proton or a neutron, so it counts 0 toward a mass number. KEY
The beta particle has no electric charge.
The beta particle has no mass at all.
The 0 shows the particle is one of the atom's orbiting electrons, coming from outside the nucleus.
NUC-011 · easy · application · seq 3 · SEED pool[4] = NUC-011 gate[1], kept (instance verified corpus-clean) · mcq4
In ¹⁴⁸₆₄Gd → ¹⁴⁴₆₂Sm + ⁴₂He, which species does the equation say are produced?
A samarium-144 nucleus and an alpha particle. KEY
A gadolinium-148 nucleus and an alpha particle.
A samarium-144 nucleus and a beta particle.
A gadolinium-148 nucleus and a samarium-144 nucleus.
NUC-018 · easy · recall · seq 4 · SEED pool[24] = NUC-018 gate[0], kept · mcq4
Why does releasing a gamma ray leave the nucleus's mass number unchanged?
A gamma ray is energy, not matter — it carries away no protons or neutrons. KEY
The gamma ray removes one neutron but adds one proton in its place, keeping the count steady.
The mass number counts only protons, and no protons leave.
Gamma rays are too small to carry a whole nuclear particle away.
NUC-013 · medium · application · seq 5 · SEED pool[10] = NUC-013 gate[1], kept (verb changed to 'undergoes'; instance verified corpus-clean) · text
Actinium-225 (²²⁵₈₉Ac) undergoes alpha decay. Give the nuclide left behind, in isotope notation. (Atomic numbers: Rn 86, Fr 87, Ra 88, Ac 89, Th 90.)
Answer: ²²¹₈₇Fr KEY
also accepted: francium-221, Francium-221, Fr-221, ^221_87Fr, 221/87 Fr
wrongValueDiagnostics
[
 {
  "value": "²²³₈₅At",
  "misconception": "you swapped the drops — the mass number falls by 4 and the atomic number falls by 2",
  "feedback": "This answer is wrong — you swapped the drops; the mass number falls by 4 and the atomic number falls by 2."
 },
 {
  "value": "²²¹₈₉Ac",
  "misconception": "you kept the atomic number — losing 2 protons changes the element",
  "feedback": "This answer is wrong — you kept the atomic number; losing 2 protons changes the element."
 },
 {
  "value": "²²⁹₉₁Pa",
  "misconception": "you added the alpha particle's numbers instead of subtracting them — the nucleus LOSES 2 protons and 2 neutrons",
  "feedback": "This answer is wrong — you added the alpha particle's numbers instead of subtracting them; the nucleus LOSES 2 protons and 2 neutrons."
 }
]
feedback
{
 "keyExplanation": "Mass number: 225 − 4 = 221. Atomic number: 89 − 2 = 87. The element with atomic number 87 is francium, so alpha decay leaves ²²¹₈₇Fr behind.",
 "anticipatedWrong": [
  {
   "value": "²²³₈₅At",
   "misconception": "you swapped the drops — the mass number falls by 4 and the atomic number falls by 2",
   "feedback": "This answer is wrong — you swapped the drops; the mass number falls by 4 and the atomic number falls by 2."
  },
  {
   "value": "²²¹₈₉Ac",
   "misconception": "you kept the atomic number — losing 2 protons changes the element",
   "feedback": "This answer is wrong — you kept the atomic number; losing 2 protons changes the element."
  },
  {
   "value": "²²⁹₉₁Pa",
   "misconception": "you added the alpha particle's numbers instead of subtracting them — the nucleus LOSES 2 protons and 2 neutrons",
   "feedback": "This answer is wrong — you added the alpha particle's numbers instead of subtracting them; the nucleus LOSES 2 protons and 2 neutrons."
  }
 ]
}
NUC-019 · medium · application · seq 6 · SEED pool[27] = NUC-019 gate[0], kept (wording lightly adjusted) · mcq4
A detector faces an unknown source. With no barrier the reading is strong. With a sheet of paper in the way, the reading is still strong. With a thin sheet of aluminum in the way, the reading drops to nothing. Which radiation type does the source give off?
Beta radiation KEY
Alpha radiation
Gamma radiation
None of the three types
NUC-016 · medium · application · seq 7 · authored (stage 2); p18 design, fresh instance Ce-141 → Pr-141 (seed's nickel is NUC-016's own WE name) · text
Cerium-141 (¹⁴¹₅₈Ce) decays by beta decay. Give the nuclide left behind, in isotope notation. (Atomic numbers: La 57, Ce 58, Pr 59, Nd 60, Pm 61.)
Answer: ¹⁴¹₅₉Pr KEY
also accepted: praseodymium-141, Praseodymium-141, Pr-141, ^141_59Pr, 141/59 Pr
wrongValueDiagnostics
[
 {
  "value": "¹⁴¹₅₇La",
  "misconception": "you dropped the atomic number instead of raising it — a neutron becomes a proton, so the count rises",
  "feedback": "This answer is wrong — you dropped the atomic number instead of raising it; a neutron becomes a proton, so the count rises."
 },
 {
  "value": "¹⁴¹₅₈Ce",
  "misconception": "you kept the atomic number — one more proton means the atom is no longer cerium",
  "feedback": "This answer is wrong — you kept the atomic number; one more proton means the atom is no longer cerium."
 },
 {
  "value": "¹⁴⁰₅₉Pr",
  "misconception": "you dropped the mass number by 1 — the electron that leaves is not a proton or neutron",
  "feedback": "This answer is wrong — you dropped the mass number by 1; the electron that leaves is not a proton or neutron."
 }
]
feedback
{
 "keyExplanation": "Beta decay keeps the mass number and raises the atomic number by 1: the mass number stays 141, and 58 + 1 = 59. The element with atomic number 59 is praseodymium, so the nuclide left behind is ¹⁴¹₅₉Pr.",
 "anticipatedWrong": [
  {
   "value": "¹⁴¹₅₇La",
   "misconception": "you dropped the atomic number instead of raising it — a neutron becomes a proton, so the count rises",
   "feedback": "This answer is wrong — you dropped the atomic number instead of raising it; a neutron becomes a proton, so the count rises."
  },
  {
   "value": "¹⁴¹₅₈Ce",
   "misconception": "you kept the atomic number — one more proton means the atom is no longer cerium",
   "feedback": "This answer is wrong — you kept the atomic number; one more proton means the atom is no longer cerium."
  },
  {
   "value": "¹⁴⁰₅₉Pr",
   "misconception": "you dropped the mass number by 1 — the electron that leaves is not a proton or neutron",
   "feedback": "This answer is wrong — you dropped the mass number by 1; the electron that leaves is not a proton or neutron."
  }
 ]
}
NUC-012 · medium · application · seq 8 · authored (stage 2); p6 design (seed's Pu-239 banned), fresh real alpha decay Th-227 → Ra-223 · numeric
In ²²⁷₉₀Th → ²²³₈₈Ra + ⁴₂He, what total do the atomic numbers on the right add up to?
Answer: 90 protons KEY
wrongValueDiagnostics
[
 {
  "value": 88,
  "misconception": "you took the new nucleus's atomic number alone — the alpha particle's 2 must be added in",
  "feedback": "This answer is wrong — you took the new nucleus's atomic number alone; the alpha particle's 2 must be added in: 88 + 2 = 90."
 },
 {
  "value": 92,
  "misconception": "you added the alpha particle's mass number instead of its atomic number — the atomic-number total uses the bottom numbers",
  "feedback": "This answer is wrong — you added the alpha particle's mass number instead of its atomic number; the atomic-number total uses the bottom numbers: 88 + 2."
 },
 {
  "value": 86,
  "misconception": "you subtracted the alpha particle's 2 instead of adding it — the right side's atomic numbers add together",
  "feedback": "This answer is wrong — you subtracted the alpha particle's 2 instead of adding it; the right side's atomic numbers add together."
 }
]
feedback
{
 "keyExplanation": "The right side holds ²²³₈₈Ra and ⁴₂He. Their atomic numbers add: 88 + 2 = 90, matching the left side's 90 — the atomic numbers balance, because electric charge never appears or disappears.",
 "anticipatedWrong": [
  {
   "value": 88,
   "misconception": "you took the new nucleus's atomic number alone — the alpha particle's 2 must be added in",
   "feedback": "This answer is wrong — you took the new nucleus's atomic number alone; the alpha particle's 2 must be added in: 88 + 2 = 90."
  },
  {
   "value": 92,
   "misconception": "you added the alpha particle's mass number instead of its atomic number — the atomic-number total uses the bottom numbers",
   "feedback": "This answer is wrong — you added the alpha particle's mass number instead of its atomic number; the atomic-number total uses the bottom numbers: 88 + 2."
  },
  {
   "value": 86,
   "misconception": "you subtracted the alpha particle's 2 instead of adding it — the right side's atomic numbers add together",
   "feedback": "This answer is wrong — you subtracted the alpha particle's 2 instead of adding it; the right side's atomic numbers add together."
  }
 ]
}
NUC-017 · medium · application · seq 9 · SEED pool[21] = NUC-017 gate[0], kept (instance verified corpus-clean) · text
Write the complete nuclear equation for the beta decay of iron-59 (⁵⁹₂₆Fe). (Atomic numbers: Mn 25, Fe 26, Co 27, Ni 28.)
Answer: ⁵⁹₂₆Fe → ⁵⁹₂₇Co + ⁰₋₁e KEY
also accepted: ^59_26Fe → ^59_27Co + ^0_-1e, 59/26 Fe → 59/27 Co + 0/-1 e, Fe-59 → Co-59 + e
wrongValueDiagnostics
[
 {
  "value": "⁵⁹₂₆Fe → ⁵⁹₂₅Mn + ⁰₋₁e",
  "misconception": "you subtracted 1 from the atomic number — beta decay raises it by 1",
  "feedback": "This answer is wrong — you subtracted 1 from the atomic number; beta decay raises it by 1."
 },
 {
  "value": "⁵⁹₂₆Fe → ⁵⁸₂₇Co + ⁰₋₁e",
  "misconception": "you dropped the mass number by 1 — the departing electron is not a proton or neutron",
  "feedback": "This answer is wrong — you dropped the mass number by 1; the departing electron is not a proton or neutron."
 },
 {
  "value": "⁵⁹₂₆Fe → ⁵⁹₂₇Co",
  "misconception": "you left out the beta particle — without its −1, the atomic numbers cannot balance",
  "feedback": "This answer is wrong — you left out the beta particle; without its −1, the atomic numbers cannot balance."
 }
]
feedback
{
 "keyExplanation": "The mass number stays 59; the atomic number rises to 26 + 1 = 27, and the element with atomic number 27 is cobalt. The complete equation is ⁵⁹₂₆Fe → ⁵⁹₂₇Co + ⁰₋₁e; check: 59 = 59 + 0 and 26 = 27 + (−1).",
 "anticipatedWrong": [
  {
   "value": "⁵⁹₂₆Fe → ⁵⁹₂₅Mn + ⁰₋₁e",
   "misconception": "you subtracted 1 from the atomic number — beta decay raises it by 1",
   "feedback": "This answer is wrong — you subtracted 1 from the atomic number; beta decay raises it by 1."
  },
  {
   "value": "⁵⁹₂₆Fe → ⁵⁸₂₇Co + ⁰₋₁e",
   "misconception": "you dropped the mass number by 1 — the departing electron is not a proton or neutron",
   "feedback": "This answer is wrong — you dropped the mass number by 1; the departing electron is not a proton or neutron."
  },
  {
   "value": "⁵⁹₂₆Fe → ⁵⁹₂₇Co",
   "misconception": "you left out the beta particle — without its −1, the atomic numbers cannot balance",
   "feedback": "This answer is wrong — you left out the beta particle; without its −1, the atomic numbers cannot balance."
  }
 ]
}
NUC-020 · medium · application · seq 10 · authored (stage 2); p30 design (seed's Pu-238 banned), fresh real alpha decay Cf-249 → Cm-245 · mcq4
A single decay turns ²⁴⁹₉₈Cf into ²⁴⁵₉₆Cm. Which decay type is it?
Alpha decay KEY
Beta decay
Gamma emission
Two beta decays happening back to back
NUC-014 · medium · application · seq 11 · authored (stage 2); p12 design (seed's Po-214 is corpus + own-lesson names), fresh real alpha decay Fm-257 → Cf-253 · text
Write the complete nuclear equation for the alpha decay of fermium-257 (²⁵⁷₁₀₀Fm). (Atomic numbers: Cm 96, Bk 97, Cf 98, Es 99, Fm 100.)
Answer: ²⁵⁷₁₀₀Fm → ²⁵³₉₈Cf + ⁴₂He KEY
also accepted: ^257_100Fm → ^253_98Cf + ^4_2He, 257/100 Fm → 253/98 Cf + 4/2 He, Fm-257 → Cf-253 + He-4
wrongValueDiagnostics
[
 {
  "value": "²⁵⁷₁₀₀Fm → ²⁵⁵₉₆Cm + ⁴₂He",
  "misconception": "you swapped the drops — the mass number falls by 4 and the atomic number falls by 2",
  "feedback": "This answer is wrong — you swapped the drops; the mass number falls by 4 and the atomic number falls by 2."
 },
 {
  "value": "²⁵⁷₁₀₀Fm → ²⁵³₁₀₀Fm + ⁴₂He",
  "misconception": "you kept the atomic number — losing 2 protons changes the element",
  "feedback": "This answer is wrong — you kept the atomic number; losing 2 protons changes the element."
 },
 {
  "value": "²⁵⁷₁₀₀Fm → ²⁵³₉₈Cf",
  "misconception": "you left out the alpha particle — without it, neither total balances",
  "feedback": "This answer is wrong — you left out the alpha particle; without it, neither total balances."
 }
]
feedback
{
 "keyExplanation": "New mass number: 257 − 4 = 253. New atomic number: 100 − 2 = 98, and the element with atomic number 98 is californium. The complete equation is ²⁵⁷₁₀₀Fm → ²⁵³₉₈Cf + ⁴₂He; check: 257 = 253 + 4 and 100 = 98 + 2.",
 "anticipatedWrong": [
  {
   "value": "²⁵⁷₁₀₀Fm → ²⁵⁵₉₆Cm + ⁴₂He",
   "misconception": "you swapped the drops — the mass number falls by 4 and the atomic number falls by 2",
   "feedback": "This answer is wrong — you swapped the drops; the mass number falls by 4 and the atomic number falls by 2."
  },
  {
   "value": "²⁵⁷₁₀₀Fm → ²⁵³₁₀₀Fm + ⁴₂He",
   "misconception": "you kept the atomic number — losing 2 protons changes the element",
   "feedback": "This answer is wrong — you kept the atomic number; losing 2 protons changes the element."
  },
  {
   "value": "²⁵⁷₁₀₀Fm → ²⁵³₉₈Cf",
   "misconception": "you left out the alpha particle — without it, neither total balances",
   "feedback": "This answer is wrong — you left out the alpha particle; without it, neither total balances."
  }
 ]
}
NUC-021 · medium · application · seq 12 · SEED pool[35] = NUC-021 gate[2] = demo_curated[2], kept (instance verified corpus-clean) · mcq4
Which species completes the equation ⁸⁵₃₆Kr → ⁸⁵₃₇Rb + ?
⁰₋₁e KEY
⁴₂He
⁰₁e
A gamma ray
NUC-020 · medium · application · seq 13 · authored (stage 2); SEED pool[31] design (seed's 41 is corpus), fresh real beta decay Ne-23 → Na-23 stated as counts · mcq4
During one decay, a nucleus's mass number stays at 23 while its atomic number rises from 10 to 11. Which decay type produced this change?
Beta decay KEY
Alpha decay
Gamma emission
No single decay can raise an atomic number while the mass number stays put
NUC-021 · medium · application · seq 14 · authored (stage 2); SEED pool[33] (= demo_curated[0]) design — parent position kept, instance fresh (Np-237 is corpus), particle type rotated to beta · text
Find the missing species: ? → ¹⁴⁰₅₈Ce + ⁰₋₁e. Give the missing starting nucleus, in isotope notation. (Atomic numbers: Ba 56, La 57, Ce 58, Pr 59.)
Answer: ¹⁴⁰₅₇La KEY
also accepted: lanthanum-140, Lanthanum-140, La-140, ^140_57La, 140/57 La
wrongValueDiagnostics
[
 {
  "value": "¹⁴⁰₅₉Pr",
  "misconception": "you added 1 to the atomic number instead of adding the beta particle's −1 — the left side must total 58 + (−1) = 57",
  "feedback": "This answer is wrong — you added 1 instead of adding the beta particle's −1; the left side must total 58 + (−1) = 57."
 },
 {
  "value": "¹⁴⁰₅₈Ce",
  "misconception": "you copied the shown nucleus — the missing species must make BOTH totals balance, so its atomic number is 57",
  "feedback": "This answer is wrong — you copied the shown nucleus; the missing species must make BOTH totals balance, so its atomic number is 57."
 },
 {
  "value": "¹³⁹₅₇La",
  "misconception": "you dropped the mass number — the beta particle's mass number is 0, so the totals keep the mass at 140",
  "feedback": "This answer is wrong — you dropped the mass number; the beta particle's mass number is 0, so the totals keep the mass at 140."
 }
]
feedback
{
 "keyExplanation": "The missing species sits on the left, so its numbers are the right side's totals. Mass number: 140 + 0 = 140. Atomic number: 58 + (−1) = 57 — lanthanum. The starting nucleus is ¹⁴⁰₅₇La, and the equation reads ¹⁴⁰₅₇La → ¹⁴⁰₅₈Ce + ⁰₋₁e.",
 "anticipatedWrong": [
  {
   "value": "¹⁴⁰₅₉Pr",
   "misconception": "you added 1 to the atomic number instead of adding the beta particle's −1 — the left side must total 58 + (−1) = 57",
   "feedback": "This answer is wrong — you added 1 instead of adding the beta particle's −1; the left side must total 58 + (−1) = 57."
  },
  {
   "value": "¹⁴⁰₅₈Ce",
   "misconception": "you copied the shown nucleus — the missing species must make BOTH totals balance, so its atomic number is 57",
   "feedback": "This answer is wrong — you copied the shown nucleus; the missing species must make BOTH totals balance, so its atomic number is 57."
  },
  {
   "value": "¹³⁹₅₇La",
   "misconception": "you dropped the mass number — the beta particle's mass number is 0, so the totals keep the mass at 140",
   "feedback": "This answer is wrong — you dropped the mass number; the beta particle's mass number is 0, so the totals keep the mass at 140."
  }
 ]
}
NUC-012 · hard · transfer · seq 15 · SEED pool[8] = NUC-012 gate[2], kept (key reworded number-free; instance verified corpus-clean) · mcq4
A student checks the equation ²⁵²₉₈Cf → ²⁴⁸₉₆Cm + ⁴₂He. Which verdict is correct?
Balanced — both totals agree. KEY
Unbalanced — the mass-number totals do not match.
Unbalanced — the atomic-number totals do not match.
Unbalanced — neither total agrees.
NUC-013 · hard · application · seq 16 · authored (stage 2); SEED pool[11] design (seed's Th-228/Ra-224 is corpus), fresh real alpha decay Nd-144 → Ce-140 · mcq4
Neodymium-144 (¹⁴⁴₆₀Nd) undergoes alpha decay. Which nuclide is left behind? (Atomic numbers: Ba 56, La 57, Ce 58, Pr 59, Nd 60.)
¹⁴⁰₅₈Ce KEY
¹⁴⁰₆₀Nd
¹⁴²₅₆Ba
¹⁴⁸₆₂Sm
NUC-014 · hard · transfer · seq 17 · authored (stage 2); SEED pool[14] design (seed's Th-228 numbers are corpus), fresh instance (real parent Th-223) · mcq4
A student writes the alpha decay of ²²³₉₀Th as ²²³₉₀Th → ²¹⁹₈₉Ac + ⁴₂He. Which check exposes the student's error?
The atomic-number totals do not balance. KEY
The mass-number totals do not balance.
Both totals fail to balance.
The element symbol does not match the new atomic number.
NUC-019 · hard · transfer · seq 18 · SEED pool[28] = NUC-019 gate[1], kept · mcq4
One source emits beta particles and another emits gamma rays. Which single barrier, placed in front of each source in turn, makes one source's reading vanish while the other source still reads close to full strength?
A thin sheet of aluminum KEY
A sheet of paper
A thick block of lead
No barrier — the two bare readings, with nothing in the way, already show which source is which
NUC-016 · hard · transfer · seq 19 · authored (stage 2); SEED pool[20] design (seed's 45 is corpus), fresh instance Tm-171 (real β−) · mcq4
Thulium-171 (¹⁷¹₆₉Tm) undergoes beta decay, and the nuclide left behind still has mass number 171. Why does the mass number stay at 171 even though a particle has left the nucleus?
The electron that left is neither of the particles the mass number counts, so the count holds. KEY
The nucleus pulls in a replacement particle from outside, keeping the count at 171.
The mass number does not really stay — it falls to 170, because every departing particle lowers it.
The electron's mass is exactly equal to a neutron's mass, so the total is unchanged.
NUC-017 · hard · application · seq 20 · authored (stage 2); SEED pool[23] design (seed's Mo-99 numbers are corpus), fresh instance (real β− parent Ce-143) · mcq4
In a homework answer, the beta decay of ¹⁴³₅₈Ce is written as ¹⁴³₅₈Ce → ¹⁴³₅₇La + ⁰₋₁e. Which check catches the mistake?
The atomic-number totals do not balance. KEY
The mass-number totals do not balance.
Neither total balances.
The equation shows the wrong particle for beta decay.
NUC-021 · medium · application · seq 21 · authored fresh (stage 2; prod_seeds empty — frq_prod_seeded=false); real decays Ru-103 (β), Sr-91 (β), W-185 (β) · frq
Three nuclear equations each have one species missing. Use the balancing totals to find every missing piece, and show your reasoning.
Three nuclear equations each have one species missing. Use the balancing totals to find every missing piece, and show your reasoning. (a) ¹⁰³₄₄Ru → ¹⁰³₄₅Rh + ? — work out the missing species' mass number and bottom number from the two totals, name the species, and justify your choice using both totals. (b) ⁹¹₃₈Sr → ? + ⁰₋₁e — work out the missing nucleus and give it with its element name and mass number. (Atomic numbers: Sr 38, Y 39, Zr 40, Nb 41.) (c) ? → ¹⁸⁵₇₅Re + ⁰₋₁e — the starting nucleus is missing; work out both of its numbers and give it with its element name and mass number. (Atomic numbers: Ta 73, W 74, Re 75, Os 76.)
Part a. ¹⁰³₄₄Ru → ¹⁰³₄₅Rh + ? — work out the missing species' mass number and bottom number from the two totals, name the species, and justify your choice using both totals.
Model: Mass numbers: 103 on the left and 103 on the right, so the missing species carries mass number 103 − 103 = 0. Bottom numbers: 44 = 45 + (−1), so its bottom number is −1 — the electron's charge slot. Mass number 0 with bottom number −1 is the beta particle — an electron created in the nucleus. Both totals balance only with that particle.
Part b. ⁹¹₃₈Sr → ? + ⁰₋₁e — work out the missing nucleus and give it with its element name and mass number. (Atomic numbers: Sr 38, Y 39, Zr 40, Nb 41.)
Model: The beta particle adds 0 to the mass total, so the missing nucleus keeps mass number 91. Its atomic number must satisfy 38 = ? + (−1), so it is 39 — and the element with atomic number 39 is yttrium. The missing nucleus is yttrium-91.
Part c. ? → ¹⁸⁵₇₅Re + ⁰₋₁e — the starting nucleus is missing; work out both of its numbers and give it with its element name and mass number. (Atomic numbers: Ta 73, W 74, Re 75, Os 76.)
Model: The missing species sits on the left, so both of its numbers are the right-side totals: mass 185 + 0 = 185, atomic 75 + (−1) = 74. The element with atomic number 74 is tungsten, so the starting nucleus is tungsten-185.
Full model answer. (a) Mass numbers: 103 on the left and 103 on the right, so the missing species carries mass number 103 − 103 = 0. Bottom numbers: 44 = 45 + (−1), so its bottom number is −1 — the electron's charge slot. Mass number 0 with bottom number −1 is the beta particle — an electron created in the nucleus. Both totals balance only with that particle. (b) The beta particle adds 0 to the mass total, so the missing nucleus keeps mass number 91. Its atomic number must satisfy 38 = ? + (−1), so it is 39 — and the element with atomic number 39 is yttrium. The missing nucleus is yttrium-91. (c) The missing species sits on the left, so both of its numbers are the right-side totals: mass 185 + 0 = 185, atomic 75 + (−1) = 74. The element with atomic number 74 is tungsten, so the starting nucleus is tungsten-185.

Form B

NUC-010 · easy · recall · seq 1 · authored (stage 2); seed family p2, stem reworded · numeric
The alpha particle's symbol is ⁴₂He. Work out the number of neutrons the particle holds.
Answer: 2 neutrons KEY
wrongValueDiagnostics
[
 {
  "value": 4,
  "misconception": "you read the mass number as the neutron count — the 4 counts protons AND neutrons together",
  "feedback": "This answer is wrong — you read the mass number as the neutron count; the 4 counts protons AND neutrons together."
 },
 {
  "value": 6,
  "misconception": "you added the symbol's two numbers — subtract them instead: 4 − 2",
  "feedback": "This answer is wrong — you added the symbol's two numbers; the neutron count is 4 − 2 = 2."
 },
 {
  "value": 0,
  "misconception": "you gave the particle no neutrons — half of its 4 nuclear particles are neutrons",
  "feedback": "This answer is wrong — you gave the particle no neutrons; half of its 4 nuclear particles are neutrons."
 }
]
feedback
{
 "keyExplanation": "The top number counts protons plus neutrons and the bottom number counts protons, so the neutrons are 4 − 2 = 2 — the alpha particle is 2 protons and 2 neutrons bound together.",
 "anticipatedWrong": [
  {
   "value": 4,
   "misconception": "you read the mass number as the neutron count — the 4 counts protons AND neutrons together",
   "feedback": "This answer is wrong — you read the mass number as the neutron count; the 4 counts protons AND neutrons together."
  },
  {
   "value": 6,
   "misconception": "you added the symbol's two numbers — subtract them instead: 4 − 2",
   "feedback": "This answer is wrong — you added the symbol's two numbers; the neutron count is 4 − 2 = 2."
  },
  {
   "value": 0,
   "misconception": "you gave the particle no neutrons — half of its 4 nuclear particles are neutrons",
   "feedback": "This answer is wrong — you gave the particle no neutrons; half of its 4 nuclear particles are neutrons."
  }
 ]
}
NUC-015 · easy · recall · seq 2 · authored (stage 2); p15 family, bottom-slot ask · mcq4
In the beta particle's symbol ⁰₋₁e, what does the −1 tell you?
The particle's electric charge — an electron's charge is 1−. KEY
The count of neutrons the particle carries away with it.
The particle's mass number, counting its protons and neutrons.
How many protons the particle destroys on its way out.
NUC-011 · easy · application · seq 3 · authored (stage 2); p4 design, fresh real alpha decay Es-253 → Bk-249 · mcq4
Read ²⁵³₉₉Es → ²⁴⁹₉₇Bk + ⁴₂He. What does the equation say is produced?
A berkelium-249 nucleus and an alpha particle. KEY
An einsteinium-253 nucleus and an alpha particle.
A berkelium-249 nucleus and a beta particle.
An einsteinium-253 nucleus and a berkelium-249 nucleus.
NUC-018 · easy · recall · seq 4 · authored (stage 2); p24 family, atomic-number ask · mcq4
Why does releasing a gamma ray leave the nucleus's atomic number unchanged?
A gamma ray carries away energy only — no protons leave the nucleus. KEY
A proton does leave, but a spare one immediately takes its place.
The atomic number is not affected by anything a nucleus does.
The departing ray converts one proton into a neutron on its way out.
NUC-013 · medium · application · seq 5 · authored (stage 2); p10 design, fresh real alpha decay Fr-221 → At-217 · text
Francium-221 (²²¹₈₇Fr) undergoes alpha decay. Give the nuclide left behind, in isotope notation. (Atomic numbers: Po 84, At 85, Rn 86, Fr 87, Ra 88.)
Answer: ²¹⁷₈₅At KEY
also accepted: astatine-217, Astatine-217, At-217, ^217_85At, 217/85 At
wrongValueDiagnostics
[
 {
  "value": "²¹⁹₈₃Bi",
  "misconception": "you swapped the drops — the mass number falls by 4 and the atomic number falls by 2",
  "feedback": "This answer is wrong — you swapped the drops; the mass number falls by 4 and the atomic number falls by 2."
 },
 {
  "value": "²¹⁷₈₇Fr",
  "misconception": "you kept the atomic number — the nucleus loses 2 protons, so the atom is no longer francium",
  "feedback": "This answer is wrong — you kept the atomic number; the nucleus loses 2 protons, so the atom is no longer francium."
 },
 {
  "value": "²²⁵₈₉Ac",
  "misconception": "you added the alpha particle's numbers — the nucleus loses them; it does not gain them",
  "feedback": "This answer is wrong — you added the alpha particle's numbers; the nucleus loses them — it does not gain them."
 }
]
feedback
{
 "keyExplanation": "Mass number: 221 − 4 = 217. Atomic number: 87 − 2 = 85. The element with atomic number 85 is astatine, so the nuclide left behind is ²¹⁷₈₅At.",
 "anticipatedWrong": [
  {
   "value": "²¹⁹₈₃Bi",
   "misconception": "you swapped the drops — the mass number falls by 4 and the atomic number falls by 2",
   "feedback": "This answer is wrong — you swapped the drops; the mass number falls by 4 and the atomic number falls by 2."
  },
  {
   "value": "²¹⁷₈₇Fr",
   "misconception": "you kept the atomic number — the nucleus loses 2 protons, so the atom is no longer francium",
   "feedback": "This answer is wrong — you kept the atomic number; the nucleus loses 2 protons, so the atom is no longer francium."
  },
  {
   "value": "²²⁵₈₉Ac",
   "misconception": "you added the alpha particle's numbers — the nucleus loses them; it does not gain them",
   "feedback": "This answer is wrong — you added the alpha particle's numbers; the nucleus loses them — it does not gain them."
  }
 ]
}
NUC-019 · medium · application · seq 6 · authored (stage 2); p27 design, gamma key (fluency-1 class reworded away from corpus) · mcq4
Neither a sheet of paper nor a thin sheet of aluminum weakens the beam coming out of one source. Only a thick wall of concrete finally cuts the beam down. Which radiation type is the beam?
Gamma radiation KEY
Alpha radiation
Beta radiation
None of the three types
NUC-016 · medium · application · seq 7 · authored (stage 2); p18 design, fresh instance Er-169 → Tm-169 · text
Erbium-169 (¹⁶⁹₆₈Er) decays by beta decay. Give the nuclide left behind, in isotope notation. (Atomic numbers: Ho 67, Er 68, Tm 69, Yb 70.)
Answer: ¹⁶⁹₆₉Tm KEY
also accepted: thulium-169, Thulium-169, Tm-169, ^169_69Tm, 169/69 Tm
wrongValueDiagnostics
[
 {
  "value": "¹⁶⁹₆₇Ho",
  "misconception": "you dropped the atomic number instead of raising it — the neutron-to-proton change adds a proton",
  "feedback": "This answer is wrong — you dropped the atomic number instead of raising it; the neutron-to-proton change adds a proton."
 },
 {
  "value": "¹⁶⁹₆₈Er",
  "misconception": "you kept the atomic number — one more proton means the atom is no longer erbium",
  "feedback": "This answer is wrong — you kept the atomic number; one more proton means the atom is no longer erbium."
 },
 {
  "value": "¹⁶⁸₆₉Tm",
  "misconception": "you dropped the mass number by 1 — the departing electron is not a proton or neutron, so the mass number is unchanged",
  "feedback": "This answer is wrong — you dropped the mass number by 1; the departing electron is not a proton or neutron, so the mass number is unchanged."
 }
]
feedback
{
 "keyExplanation": "The mass number stays 169, and the atomic number rises: 68 + 1 = 69. The element with atomic number 69 is thulium, so the nuclide left behind is ¹⁶⁹₆₉Tm.",
 "anticipatedWrong": [
  {
   "value": "¹⁶⁹₆₇Ho",
   "misconception": "you dropped the atomic number instead of raising it — the neutron-to-proton change adds a proton",
   "feedback": "This answer is wrong — you dropped the atomic number instead of raising it; the neutron-to-proton change adds a proton."
  },
  {
   "value": "¹⁶⁹₆₈Er",
   "misconception": "you kept the atomic number — one more proton means the atom is no longer erbium",
   "feedback": "This answer is wrong — you kept the atomic number; one more proton means the atom is no longer erbium."
  },
  {
   "value": "¹⁶⁸₆₉Tm",
   "misconception": "you dropped the mass number by 1 — the departing electron is not a proton or neutron, so the mass number is unchanged",
   "feedback": "This answer is wrong — you dropped the mass number by 1; the departing electron is not a proton or neutron, so the mass number is unchanged."
  }
 ]
}
NUC-012 · medium · application · seq 8 · authored (stage 2); p6 design, fresh real alpha decay Po-211 → Pb-207 · numeric
In ²¹¹₈₄Po → ²⁰⁷₈₂Pb + ⁴₂He, what total do the atomic numbers on the right add up to?
Answer: 84 protons KEY
wrongValueDiagnostics
[
 {
  "value": 82,
  "misconception": "you took the new nucleus's atomic number alone — the alpha particle's 2 must be added in",
  "feedback": "This answer is wrong — you took the new nucleus's atomic number alone; the alpha particle's 2 must be added in: 82 + 2 = 84."
 },
 {
  "value": 86,
  "misconception": "you added the alpha particle's mass number instead of its atomic number",
  "feedback": "This answer is wrong — you added the alpha particle's mass number instead of its atomic number; use the bottom numbers: 82 + 2."
 },
 {
  "value": 80,
  "misconception": "you subtracted the alpha particle's 2 instead of adding it",
  "feedback": "This answer is wrong — you subtracted the alpha particle's 2 instead of adding it; the right side's atomic numbers add together."
 }
]
feedback
{
 "keyExplanation": "Add the right side's atomic numbers: 82 + 2 = 84. That matches the 84 on the left — the atomic numbers balance, because electric charge never appears or disappears.",
 "anticipatedWrong": [
  {
   "value": 82,
   "misconception": "you took the new nucleus's atomic number alone — the alpha particle's 2 must be added in",
   "feedback": "This answer is wrong — you took the new nucleus's atomic number alone; the alpha particle's 2 must be added in: 82 + 2 = 84."
  },
  {
   "value": 86,
   "misconception": "you added the alpha particle's mass number instead of its atomic number",
   "feedback": "This answer is wrong — you added the alpha particle's mass number instead of its atomic number; use the bottom numbers: 82 + 2."
  },
  {
   "value": 80,
   "misconception": "you subtracted the alpha particle's 2 instead of adding it",
   "feedback": "This answer is wrong — you subtracted the alpha particle's 2 instead of adding it; the right side's atomic numbers add together."
  }
 ]
}
NUC-017 · medium · application · seq 9 · authored (stage 2); p21 design, fresh instance Ho-166 → Er-166 · text
Write the complete nuclear equation for the beta decay of holmium-166 (¹⁶⁶₆₇Ho). (Atomic numbers: Dy 66, Ho 67, Er 68, Tm 69.)
Answer: ¹⁶⁶₆₇Ho → ¹⁶⁶₆₈Er + ⁰₋₁e KEY
also accepted: ^166_67Ho → ^166_68Er + ^0_-1e, 166/67 Ho → 166/68 Er + 0/-1 e, Ho-166 → Er-166 + e
wrongValueDiagnostics
[
 {
  "value": "¹⁶⁶₆₇Ho → ¹⁶⁶₆₆Dy + ⁰₋₁e",
  "misconception": "you subtracted 1 from the atomic number — the neutron-to-proton change RAISES it by 1",
  "feedback": "This answer is wrong — you subtracted 1 from the atomic number; the neutron-to-proton change RAISES it by 1."
 },
 {
  "value": "¹⁶⁵₆₈Er + ⁰₋₁e as the right side",
  "misconception": "you dropped the mass number by 1 — the departing electron is not a proton or neutron",
  "feedback": "This answer is wrong — you dropped the mass number by 1; the departing electron is not a proton or neutron."
 },
 {
  "value": "¹⁶⁶₆₇Ho → ¹⁶⁶₆₈Er",
  "misconception": "you left out the beta particle — without its −1, the atomic numbers cannot balance",
  "feedback": "This answer is wrong — you left out the beta particle; without its −1, the atomic numbers cannot balance."
 }
]
feedback
{
 "keyExplanation": "The mass number stays 166; the atomic number rises to 67 + 1 = 68, and the element with atomic number 68 is erbium. The complete equation is ¹⁶⁶₆₇Ho → ¹⁶⁶₆₈Er + ⁰₋₁e; check: 166 = 166 + 0 and 67 = 68 + (−1).",
 "anticipatedWrong": [
  {
   "value": "¹⁶⁶₆₇Ho → ¹⁶⁶₆₆Dy + ⁰₋₁e",
   "misconception": "you subtracted 1 from the atomic number — the neutron-to-proton change RAISES it by 1",
   "feedback": "This answer is wrong — you subtracted 1 from the atomic number; the neutron-to-proton change RAISES it by 1."
  },
  {
   "value": "¹⁶⁵₆₈Er + ⁰₋₁e as the right side",
   "misconception": "you dropped the mass number by 1 — the departing electron is not a proton or neutron",
   "feedback": "This answer is wrong — you dropped the mass number by 1; the departing electron is not a proton or neutron."
  },
  {
   "value": "¹⁶⁶₆₇Ho → ¹⁶⁶₆₈Er",
   "misconception": "you left out the beta particle — without its −1, the atomic numbers cannot balance",
   "feedback": "This answer is wrong — you left out the beta particle; without its −1, the atomic numbers cannot balance."
  }
 ]
}
NUC-020 · medium · application · seq 10 · authored (stage 2); p30 design, fresh real beta decay Pm-149 → Sm-149 · mcq4
A single decay turns ¹⁴⁹₆₁Pm into ¹⁴⁹₆₂Sm. Which decay type is it?
Beta decay KEY
Alpha decay
Gamma emission
No decay — the nucleus captured a stray proton instead
NUC-014 · medium · application · seq 11 · authored (stage 2); p12 design, fresh real alpha decay Dy-154 → Gd-150 · text
Write the complete nuclear equation for the alpha decay of dysprosium-154 (¹⁵⁴₆₆Dy). (Atomic numbers: Sm 62, Eu 63, Gd 64, Tb 65, Dy 66.)
Answer: ¹⁵⁴₆₆Dy → ¹⁵⁰₆₄Gd + ⁴₂He KEY
also accepted: ^154_66Dy → ^150_64Gd + ^4_2He, 154/66 Dy → 150/64 Gd + 4/2 He, Dy-154 → Gd-150 + He-4
wrongValueDiagnostics
[
 {
  "value": "¹⁵⁴₆₆Dy → ¹⁵²₆₂Sm + ⁴₂He",
  "misconception": "you swapped the drops — the mass number falls by 4 and the atomic number falls by 2",
  "feedback": "This answer is wrong — you swapped the drops; the mass number falls by 4 and the atomic number falls by 2."
 },
 {
  "value": "¹⁵⁴₆₆Dy → ¹⁵⁰₆₅Tb + ⁴₂He",
  "misconception": "you dropped the atomic number by 1 instead of 2 — the alpha particle carries away 2 protons",
  "feedback": "This answer is wrong — you dropped the atomic number by 1 instead of 2; the alpha particle carries away 2 protons."
 },
 {
  "value": "¹⁵⁴₆₆Dy + ⁴₂He → ¹⁵⁰₆₄Gd",
  "misconception": "you put the alpha particle on the left — it is produced by the decay and belongs on the right",
  "feedback": "This answer is wrong — you put the alpha particle on the left; it is produced by the decay and belongs on the right."
 }
]
feedback
{
 "keyExplanation": "New mass number: 154 − 4 = 150. New atomic number: 66 − 2 = 64, and the element with atomic number 64 is gadolinium. The complete equation is ¹⁵⁴₆₆Dy → ¹⁵⁰₆₄Gd + ⁴₂He; check: 154 = 150 + 4 and 66 = 64 + 2.",
 "anticipatedWrong": [
  {
   "value": "¹⁵⁴₆₆Dy → ¹⁵²₆₂Sm + ⁴₂He",
   "misconception": "you swapped the drops — the mass number falls by 4 and the atomic number falls by 2",
   "feedback": "This answer is wrong — you swapped the drops; the mass number falls by 4 and the atomic number falls by 2."
  },
  {
   "value": "¹⁵⁴₆₆Dy → ¹⁵⁰₆₅Tb + ⁴₂He",
   "misconception": "you dropped the atomic number by 1 instead of 2 — the alpha particle carries away 2 protons",
   "feedback": "This answer is wrong — you dropped the atomic number by 1 instead of 2; the alpha particle carries away 2 protons."
  },
  {
   "value": "¹⁵⁴₆₆Dy + ⁴₂He → ¹⁵⁰₆₄Gd",
   "misconception": "you put the alpha particle on the left — it is produced by the decay and belongs on the right",
   "feedback": "This answer is wrong — you put the alpha particle on the left; it is produced by the decay and belongs on the right."
  }
 ]
}
NUC-021 · medium · application · seq 12 · authored (stage 2); p35 design, fresh real beta decay Lu-177 → Hf-177 · mcq4
Find the missing species: ¹⁷⁷₇₁Lu → ¹⁷⁷₇₂Hf + ?
⁰₋₁e KEY
⁴₂He
⁰₁e
A gamma ray
NUC-020 · medium · application · seq 13 · authored (stage 2); p32 design, fresh real isomer Sn-119m · mcq4
An energized ¹¹⁹₅₀Sn nucleus sheds a burst of radiation and stays ¹¹⁹₅₀Sn. Which decay type is it?
Gamma emission KEY
Alpha decay
Beta decay
Impossible — every decay must change at least one of the two numbers
NUC-021 · medium · application · seq 14 · authored (stage 2); SEED pool[34] (= demo_curated[1]) design — daughter position kept, instance fresh (Y-90's 90 is corpus) · text
Find the missing species: ¹⁵⁶₆₃Eu → ? + ⁰₋₁e. Give the missing new nucleus, in isotope notation. (Atomic numbers: Sm 62, Eu 63, Gd 64, Tb 65.)
Answer: ¹⁵⁶₆₄Gd KEY
also accepted: gadolinium-156, Gadolinium-156, Gd-156, ^156_64Gd, 156/64 Gd
wrongValueDiagnostics
[
 {
  "value": "¹⁵⁶₆₂Sm",
  "misconception": "you subtracted the −1 as if it were +1 — 63 = ? + (−1) forces the missing atomic number UP to 64",
  "feedback": "This answer is wrong — you subtracted the −1 as if it were +1; 63 = ? + (−1) forces the missing atomic number UP to 64."
 },
 {
  "value": "¹⁵⁶₆₃Eu",
  "misconception": "you kept the starting atomic number — the beta particle's −1 raises the new nucleus's atomic number to 64",
  "feedback": "This answer is wrong — you kept the starting atomic number; the beta particle's −1 raises the new nucleus's atomic number to 64."
 },
 {
  "value": "¹⁵⁵₆₄Gd",
  "misconception": "you dropped the mass number — the beta particle carries mass number 0, so 156 stays",
  "feedback": "This answer is wrong — you dropped the mass number; the beta particle carries mass number 0, so 156 stays."
 }
]
feedback
{
 "keyExplanation": "Missing mass number: 156 − 0 = 156. Missing atomic number: 63 − (−1) = 64 — gadolinium. The missing species is ¹⁵⁶₆₄Gd, and the equation reads ¹⁵⁶₆₃Eu → ¹⁵⁶₆₄Gd + ⁰₋₁e.",
 "anticipatedWrong": [
  {
   "value": "¹⁵⁶₆₂Sm",
   "misconception": "you subtracted the −1 as if it were +1 — 63 = ? + (−1) forces the missing atomic number UP to 64",
   "feedback": "This answer is wrong — you subtracted the −1 as if it were +1; 63 = ? + (−1) forces the missing atomic number UP to 64."
  },
  {
   "value": "¹⁵⁶₆₃Eu",
   "misconception": "you kept the starting atomic number — the beta particle's −1 raises the new nucleus's atomic number to 64",
   "feedback": "This answer is wrong — you kept the starting atomic number; the beta particle's −1 raises the new nucleus's atomic number to 64."
  },
  {
   "value": "¹⁵⁵₆₄Gd",
   "misconception": "you dropped the mass number — the beta particle carries mass number 0, so 156 stays",
   "feedback": "This answer is wrong — you dropped the mass number; the beta particle carries mass number 0, so 156 stays."
  }
 ]
}
NUC-012 · hard · transfer · seq 15 · authored (stage 2); p8/p7 verdict family, fresh instance (real parent Po-208; student daughter mis-written) · mcq4
For an alpha decay, a student writes ²⁰⁸₈₄Po → ²⁰⁴₈₃Bi + ⁴₂He. What verdict fits?
Unbalanced — the atomic-number totals do not match. KEY
Unbalanced — the mass-number totals do not match.
Balanced — both totals agree.
Unbalanced — neither total agrees.
NUC-013 · hard · application · seq 16 · authored (stage 2); p11 design, fresh real alpha decay At-219 → Bi-215 (notation-only stem) · mcq4
An ²¹⁹₈₅At nucleus undergoes alpha decay. Which nuclide is left behind? (Atomic numbers: Tl 81, Pb 82, Bi 83, Po 84, At 85.)
²¹⁵₈₃Bi KEY
²¹⁵₈₅At
²¹⁷₈₁Tl
²²³₈₇Fr
NUC-014 · hard · transfer · seq 17 · authored (stage 2); p14 design, fresh instance (real parent Th-226) · mcq4
A student writes the alpha decay of ²²⁶₉₀Th as ²²⁶₉₀Th → ²¹⁸₈₈Ra + ⁴₂He. Which check exposes the student's error?
The mass-number totals do not balance. KEY
The atomic-number totals do not balance.
Both totals fail to balance.
The element symbol does not match the new atomic number.
NUC-019 · hard · transfer · seq 18 · authored (stage 2); p28 design, α-vs-β rotation · mcq4
One source emits alpha particles and another emits beta particles. Which single barrier, placed in front of each source in turn, tells the two sources apart?
A sheet of paper KEY
A thin sheet of aluminum
A thick block of lead
No barrier — the two sources' unshielded readings alone already separate them
NUC-016 · hard · transfer · seq 19 · authored (stage 2); p20 design, fresh instance Pd-107 (real β−) · mcq4
Palladium-107 (¹⁰⁷₄₆Pd) undergoes beta decay, and the nuclide left behind still has mass number 107. Why is the mass number unchanged even though a particle has left the nucleus?
A mass number tallies protons plus neutrons, and the departing electron belongs to neither tally. KEY
The nucleus pulls in a replacement particle from its surroundings, and that keeps the count at 107.
The mass number really falls to 106, because every departing particle lowers it.
The electron's mass exactly equals a neutron's mass, so the total is unchanged.
NUC-017 · hard · application · seq 20 · authored (stage 2); p23 design, fresh instance (real β− parent Gd-159) · mcq4
In a homework answer, the beta decay of ¹⁵⁹₆₄Gd is written as ¹⁵⁹₆₄Gd → ¹⁵⁸₆₅Tb + ⁰₋₁e. Which check catches the mistake?
The mass-number totals do not balance. KEY
The atomic-number totals do not balance.
Neither total balances.
The equation shows the wrong particle for beta decay.
NUC-021 · medium · application · seq 21 · authored fresh (stage 2); real decays Ba-141 (β), Zn-69 (β), Br-82 (β) · frq
Three nuclear equations each have one species missing. Use the balancing totals to find every missing piece, and show your reasoning.
Three nuclear equations each have one species missing. Use the balancing totals to find every missing piece, and show your reasoning. (a) ¹⁴¹₅₆Ba → ¹⁴¹₅₇La + ? — work out the missing species' mass number and bottom number from the two totals, name the species, and justify your choice using both totals. (b) ⁶⁹₃₀Zn → ? + ⁰₋₁e — work out the missing nucleus and give it with its element name and mass number. (Atomic numbers: Cu 29, Zn 30, Ga 31, Ge 32.) (c) ? → ⁸²₃₆Kr + ⁰₋₁e — the starting nucleus is missing; work out both of its numbers and give it with its element name and mass number. (Atomic numbers: Se 34, Br 35, Kr 36, Rb 37.)
Part a. ¹⁴¹₅₆Ba → ¹⁴¹₅₇La + ? — work out the missing species' mass number and bottom number from the two totals, name the species, and justify your choice using both totals.
Model: Mass numbers: 141 on both sides, so the missing species carries mass number 0. Bottom numbers: 56 = 57 + (−1), so its bottom number is −1 — the electron's charge slot. Mass number 0 with bottom number −1 is the beta particle — an electron created in the nucleus; both totals balance only with it.
Part b. ⁶⁹₃₀Zn → ? + ⁰₋₁e — work out the missing nucleus and give it with its element name and mass number. (Atomic numbers: Cu 29, Zn 30, Ga 31, Ge 32.)
Model: The beta particle adds 0 to the mass total, so the missing nucleus keeps mass number 69. Its atomic number must satisfy 30 = ? + (−1), so it is 31 — gallium. The missing nucleus is gallium-69.
Part c. ? → ⁸²₃₆Kr + ⁰₋₁e — the starting nucleus is missing; work out both of its numbers and give it with its element name and mass number. (Atomic numbers: Se 34, Br 35, Kr 36, Rb 37.)
Model: The missing species sits on the left, so both of its numbers are the right-side totals: mass 82 + 0 = 82, atomic 36 + (−1) = 35. The element with atomic number 35 is bromine, so the starting nucleus is bromine-82.
Full model answer. (a) Mass numbers: 141 on both sides, so the missing species carries mass number 0. Bottom numbers: 56 = 57 + (−1), so its bottom number is −1 — the electron's charge slot. Mass number 0 with bottom number −1 is the beta particle — an electron created in the nucleus; both totals balance only with it. (b) The beta particle adds 0 to the mass total, so the missing nucleus keeps mass number 69. Its atomic number must satisfy 30 = ? + (−1), so it is 31 — gallium. The missing nucleus is gallium-69. (c) The missing species sits on the left, so both of its numbers are the right-side totals: mass 82 + 0 = 82, atomic 36 + (−1) = 35. The element with atomic number 35 is bromine, so the starting nucleus is bromine-82.

Form C

NUC-010 · easy · recall · seq 1 · authored (stage 2); seed family p2, stem reworded · numeric
Use the symbol ⁴₂He to find the alpha particle's neutron count. Enter that count.
Answer: 2 neutrons KEY
wrongValueDiagnostics
[
 {
  "value": 4,
  "misconception": "you took the top number as the neutron count — it is the mass number, protons plus neutrons",
  "feedback": "This answer is wrong — you took the top number as the neutron count; it is the mass number, protons plus neutrons."
 },
 {
  "value": 6,
  "misconception": "you added 4 and 2 — the neutron count comes from subtracting the proton count",
  "feedback": "This answer is wrong — you added 4 and 2; the neutron count comes from subtracting: 4 − 2 = 2."
 },
 {
  "value": 0,
  "misconception": "you counted no neutrons — the particle carries 2 protons and 2 neutrons",
  "feedback": "This answer is wrong — you counted no neutrons; the particle carries 2 protons and 2 neutrons."
 }
]
feedback
{
 "keyExplanation": "Neutrons = mass number − proton count = 4 − 2 = 2. Two protons and two neutrons is exactly the alpha particle's makeup.",
 "anticipatedWrong": [
  {
   "value": 4,
   "misconception": "you took the top number as the neutron count — it is the mass number, protons plus neutrons",
   "feedback": "This answer is wrong — you took the top number as the neutron count; it is the mass number, protons plus neutrons."
  },
  {
   "value": 6,
   "misconception": "you added 4 and 2 — the neutron count comes from subtracting the proton count",
   "feedback": "This answer is wrong — you added 4 and 2; the neutron count comes from subtracting: 4 − 2 = 2."
  },
  {
   "value": 0,
   "misconception": "you counted no neutrons — the particle carries 2 protons and 2 neutrons",
   "feedback": "This answer is wrong — you counted no neutrons; the particle carries 2 protons and 2 neutrons."
  }
 ]
}
NUC-015 · easy · recall · seq 2 · authored (stage 2); p15 family, why-−1 ask · mcq4
Why does the beta particle's symbol ⁰₋₁e carry −1 as its bottom number?
That slot records the particle's charge, and the electron's charge is 1−. KEY
Because the particle removes one proton from the nucleus as it leaves.
Because the particle weighs one unit less than a neutron.
Because one neutron vanishes from the nucleus when the particle leaves.
NUC-011 · easy · application · seq 3 · authored (stage 2); p4 design, fresh real alpha decay Pt-190 → Os-186 · mcq4
In ¹⁹⁰₇₈Pt → ¹⁸⁶₇₆Os + ⁴₂He, which species does the equation list as produced?
An osmium-186 nucleus and an alpha particle. KEY
A platinum-190 nucleus and an alpha particle.
An osmium-186 nucleus and a beta particle.
A platinum-190 nucleus and an osmium-186 nucleus.
NUC-018 · easy · recall · seq 4 · authored (stage 2); p26 misconception space, matter-or-energy ask · mcq4
A classmate asks whether a gamma ray is a particle of matter. What should you tell them?
It is not matter at all — it is a burst of high-energy light. KEY
It is a particle of matter, lighter than an electron.
It is a particle of matter made in the electron cloud.
It is matter while inside the nucleus and turns into light as it leaves.
NUC-013 · medium · application · seq 5 · authored (stage 2); p10 design, fresh real alpha decay Hf-174 → Yb-170 · text
Hafnium-174 (¹⁷⁴₇₂Hf) undergoes alpha decay. Give the nuclide left behind, in isotope notation. (Atomic numbers: Er 68, Tm 69, Yb 70, Lu 71, Hf 72.)
Answer: ¹⁷⁰₇₀Yb KEY
also accepted: ytterbium-170, Ytterbium-170, Yb-170, ^170_70Yb, 170/70 Yb
wrongValueDiagnostics
[
 {
  "value": "¹⁷²₆₈Er",
  "misconception": "you swapped the drops — the mass number falls by 4 and the atomic number falls by 2",
  "feedback": "This answer is wrong — you swapped the drops; the mass number falls by 4 and the atomic number falls by 2."
 },
 {
  "value": "¹⁷⁰₇₂Hf",
  "misconception": "you kept the atomic number — losing 2 protons means the atom is no longer hafnium",
  "feedback": "This answer is wrong — you kept the atomic number; losing 2 protons means the atom is no longer hafnium."
 },
 {
  "value": "¹⁷⁸₇₄W",
  "misconception": "you added the alpha particle's numbers instead of subtracting them",
  "feedback": "This answer is wrong — you added the alpha particle's numbers instead of subtracting them."
 }
]
feedback
{
 "keyExplanation": "Mass number: 174 − 4 = 170. Atomic number: 72 − 2 = 70. The element with atomic number 70 is ytterbium, so alpha decay leaves ¹⁷⁰₇₀Yb behind.",
 "anticipatedWrong": [
  {
   "value": "¹⁷²₆₈Er",
   "misconception": "you swapped the drops — the mass number falls by 4 and the atomic number falls by 2",
   "feedback": "This answer is wrong — you swapped the drops; the mass number falls by 4 and the atomic number falls by 2."
  },
  {
   "value": "¹⁷⁰₇₂Hf",
   "misconception": "you kept the atomic number — losing 2 protons means the atom is no longer hafnium",
   "feedback": "This answer is wrong — you kept the atomic number; losing 2 protons means the atom is no longer hafnium."
  },
  {
   "value": "¹⁷⁸₇₄W",
   "misconception": "you added the alpha particle's numbers instead of subtracting them",
   "feedback": "This answer is wrong — you added the alpha particle's numbers instead of subtracting them."
  }
 ]
}
NUC-019 · medium · application · seq 6 · authored (stage 2); p27 design, alpha key · mcq4
The reading from a source falls to zero the moment a single sheet of paper is placed in its path. Which radiation type is the source emitting?
Alpha radiation KEY
Beta radiation
Gamma radiation
None of the three types
NUC-016 · medium · application · seq 7 · authored (stage 2); p18 design, fresh instance Yb-175 → Lu-175 · text
Ytterbium-175 (¹⁷⁵₇₀Yb) decays by beta decay. Give the nuclide left behind, in isotope notation. (Atomic numbers: Tm 69, Yb 70, Lu 71, Hf 72.)
Answer: ¹⁷⁵₇₁Lu KEY
also accepted: lutetium-175, Lutetium-175, Lu-175, ^175_71Lu, 175/71 Lu
wrongValueDiagnostics
[
 {
  "value": "¹⁷⁵₆₉Tm",
  "misconception": "you dropped the atomic number instead of raising it — the proton count RISES by 1 in beta decay",
  "feedback": "This answer is wrong — you dropped the atomic number instead of raising it; the proton count RISES by 1 in beta decay."
 },
 {
  "value": "¹⁷⁵₇₀Yb",
  "misconception": "you kept the atomic number — the neutron-to-proton change means the atom is no longer ytterbium",
  "feedback": "This answer is wrong — you kept the atomic number; the neutron-to-proton change means the atom is no longer ytterbium."
 },
 {
  "value": "¹⁷⁴₇₁Lu",
  "misconception": "you dropped the mass number by 1 — the total count of protons plus neutrons is unchanged",
  "feedback": "This answer is wrong — you dropped the mass number by 1; the total count of protons plus neutrons is unchanged."
 }
]
feedback
{
 "keyExplanation": "Beta decay keeps the mass number at 175 and raises the atomic number: 70 + 1 = 71. The element with atomic number 71 is lutetium, so the nuclide left behind is ¹⁷⁵₇₁Lu.",
 "anticipatedWrong": [
  {
   "value": "¹⁷⁵₆₉Tm",
   "misconception": "you dropped the atomic number instead of raising it — the proton count RISES by 1 in beta decay",
   "feedback": "This answer is wrong — you dropped the atomic number instead of raising it; the proton count RISES by 1 in beta decay."
  },
  {
   "value": "¹⁷⁵₇₀Yb",
   "misconception": "you kept the atomic number — the neutron-to-proton change means the atom is no longer ytterbium",
   "feedback": "This answer is wrong — you kept the atomic number; the neutron-to-proton change means the atom is no longer ytterbium."
  },
  {
   "value": "¹⁷⁴₇₁Lu",
   "misconception": "you dropped the mass number by 1 — the total count of protons plus neutrons is unchanged",
   "feedback": "This answer is wrong — you dropped the mass number by 1; the total count of protons plus neutrons is unchanged."
  }
 ]
}
NUC-012 · medium · application · seq 8 · authored (stage 2); p6 design, fresh real alpha decay Rn-219 → Po-215 · numeric
In ²¹⁹₈₆Rn → ²¹⁵₈₄Po + ⁴₂He, what total do the atomic numbers on the right add up to?
Answer: 86 protons KEY
wrongValueDiagnostics
[
 {
  "value": 84,
  "misconception": "you took the new nucleus's atomic number alone — the alpha particle's 2 must be added in",
  "feedback": "This answer is wrong — you took the new nucleus's atomic number alone; the alpha particle's 2 must be added in: 84 + 2 = 86."
 },
 {
  "value": 88,
  "misconception": "you added the alpha particle's mass number instead of its atomic number",
  "feedback": "This answer is wrong — you added the alpha particle's mass number instead of its atomic number; the atomic-number total uses the bottom numbers."
 },
 {
  "value": 82,
  "misconception": "you subtracted the alpha particle's 2 instead of adding it",
  "feedback": "This answer is wrong — you subtracted the alpha particle's 2 instead of adding it; the right side's atomic numbers add together."
 }
]
feedback
{
 "keyExplanation": "The right side holds ²¹⁵₈₄Po and ⁴₂He, so the atomic numbers give 84 + 2 = 86 — matching the left side's 86. The atomic numbers balance, because electric charge never appears or disappears.",
 "anticipatedWrong": [
  {
   "value": 84,
   "misconception": "you took the new nucleus's atomic number alone — the alpha particle's 2 must be added in",
   "feedback": "This answer is wrong — you took the new nucleus's atomic number alone; the alpha particle's 2 must be added in: 84 + 2 = 86."
  },
  {
   "value": 88,
   "misconception": "you added the alpha particle's mass number instead of its atomic number",
   "feedback": "This answer is wrong — you added the alpha particle's mass number instead of its atomic number; the atomic-number total uses the bottom numbers."
  },
  {
   "value": 82,
   "misconception": "you subtracted the alpha particle's 2 instead of adding it",
   "feedback": "This answer is wrong — you subtracted the alpha particle's 2 instead of adding it; the right side's atomic numbers add together."
  }
 ]
}
NUC-017 · medium · application · seq 9 · authored (stage 2); p21 design, fresh instance W-187 → Re-187 (notation-only stem) · text
Write the complete nuclear equation for the beta decay of ¹⁸⁷₇₄W. (Atomic numbers: Ta 73, W 74, Re 75, Os 76.)
Answer: ¹⁸⁷₇₄W → ¹⁸⁷₇₅Re + ⁰₋₁e KEY
also accepted: ^187_74W → ^187_75Re + ^0_-1e, 187/74 W → 187/75 Re + 0/-1 e, W-187 → Re-187 + e
wrongValueDiagnostics
[
 {
  "value": "¹⁸⁷₇₄W → ¹⁸⁷₇₃Ta + ⁰₋₁e",
  "misconception": "you subtracted 1 from the atomic number — beta decay raises it by 1",
  "feedback": "This answer is wrong — you subtracted 1 from the atomic number; beta decay raises it by 1."
 },
 {
  "value": "¹⁸⁷₇₄W → ¹⁸⁶₇₅Re + ⁰₋₁e",
  "misconception": "you dropped the mass number by 1 — the electron that leaves is not a proton or neutron",
  "feedback": "This answer is wrong — you dropped the mass number by 1; the electron that leaves is not a proton or neutron."
 },
 {
  "value": "¹⁸⁷₇₄W + ⁰₋₁e → ¹⁸⁷₇₅Re",
  "misconception": "you put the beta particle on the left — it is produced by the decay and belongs on the right",
  "feedback": "This answer is wrong — you put the beta particle on the left; it is produced by the decay and belongs on the right."
 }
]
feedback
{
 "keyExplanation": "The mass number stays 187; the atomic number rises to 74 + 1 = 75, and the element with atomic number 75 is rhenium. The complete equation is ¹⁸⁷₇₄W → ¹⁸⁷₇₅Re + ⁰₋₁e; check: 187 = 187 + 0 and 74 = 75 + (−1).",
 "anticipatedWrong": [
  {
   "value": "¹⁸⁷₇₄W → ¹⁸⁷₇₃Ta + ⁰₋₁e",
   "misconception": "you subtracted 1 from the atomic number — beta decay raises it by 1",
   "feedback": "This answer is wrong — you subtracted 1 from the atomic number; beta decay raises it by 1."
  },
  {
   "value": "¹⁸⁷₇₄W → ¹⁸⁶₇₅Re + ⁰₋₁e",
   "misconception": "you dropped the mass number by 1 — the electron that leaves is not a proton or neutron",
   "feedback": "This answer is wrong — you dropped the mass number by 1; the electron that leaves is not a proton or neutron."
  },
  {
   "value": "¹⁸⁷₇₄W + ⁰₋₁e → ¹⁸⁷₇₅Re",
   "misconception": "you put the beta particle on the left — it is produced by the decay and belongs on the right",
   "feedback": "This answer is wrong — you put the beta particle on the left; it is produced by the decay and belongs on the right."
  }
 ]
}
NUC-020 · medium · application · seq 10 · authored (stage 2); p32 design (seed's Co-60 is corpus), fresh real isomer Se-77m · mcq4
An energized ⁷⁷₃₄Se nucleus gives off radiation and is afterwards still ⁷⁷₃₄Se. Which decay type is it?
Gamma emission KEY
Alpha decay
Beta decay
No radiation was released at all, since neither number changed
NUC-014 · medium · application · seq 11 · authored (stage 2); p12 design, fresh real alpha decay Rn-217 → Po-213 (notation-only stem) · text
Write the complete nuclear equation for the alpha decay of ²¹⁷₈₆Rn. (Atomic numbers: Pb 82, Bi 83, Po 84, At 85, Rn 86.)
Answer: ²¹⁷₈₆Rn → ²¹³₈₄Po + ⁴₂He KEY
also accepted: ^217_86Rn → ^213_84Po + ^4_2He, 217/86 Rn → 213/84 Po + 4/2 He, Rn-217 → Po-213 + He-4
wrongValueDiagnostics
[
 {
  "value": "²¹⁷₈₆Rn → ²¹⁵₈₂Pb + ⁴₂He",
  "misconception": "you swapped the drops — the mass number falls by 4 and the atomic number falls by 2",
  "feedback": "This answer is wrong — you swapped the drops; the mass number falls by 4 and the atomic number falls by 2."
 },
 {
  "value": "²¹⁷₈₆Rn → ²¹³₈₆Rn + ⁴₂He",
  "misconception": "you kept the atomic number — losing 2 protons changes the element",
  "feedback": "This answer is wrong — you kept the atomic number; losing 2 protons changes the element."
 },
 {
  "value": "²¹⁷₈₆Rn → ²¹³₈₄Po",
  "misconception": "you left out the alpha particle — without it, neither total balances",
  "feedback": "This answer is wrong — you left out the alpha particle; without it, neither total balances."
 }
]
feedback
{
 "keyExplanation": "New mass number: 217 − 4 = 213. New atomic number: 86 − 2 = 84, and the element with atomic number 84 is polonium. The complete equation is ²¹⁷₈₆Rn → ²¹³₈₄Po + ⁴₂He; check: 217 = 213 + 4 and 86 = 84 + 2.",
 "anticipatedWrong": [
  {
   "value": "²¹⁷₈₆Rn → ²¹⁵₈₂Pb + ⁴₂He",
   "misconception": "you swapped the drops — the mass number falls by 4 and the atomic number falls by 2",
   "feedback": "This answer is wrong — you swapped the drops; the mass number falls by 4 and the atomic number falls by 2."
  },
  {
   "value": "²¹⁷₈₆Rn → ²¹³₈₆Rn + ⁴₂He",
   "misconception": "you kept the atomic number — losing 2 protons changes the element",
   "feedback": "This answer is wrong — you kept the atomic number; losing 2 protons changes the element."
  },
  {
   "value": "²¹⁷₈₆Rn → ²¹³₈₄Po",
   "misconception": "you left out the alpha particle — without it, neither total balances",
   "feedback": "This answer is wrong — you left out the alpha particle; without it, neither total balances."
  }
 ]
}
NUC-021 · medium · application · seq 12 · authored (stage 2); p35 design, fresh real alpha decay Po-213 → Pb-209 · mcq4
Which species completes the equation ²¹³₈₄Po → ²⁰⁹₈₂Pb + ?
⁴₂He KEY
⁰₋₁e
²₄He
A gamma ray
NUC-020 · medium · application · seq 13 · authored (stage 2); p31 design, fresh real beta decay F-20 → Ne-20 stated as counts · mcq4
During one decay, a nucleus's mass number stays at 20 while its atomic number rises from 9 to 10. Which decay type produced this change?
Beta decay KEY
Alpha decay
Gamma emission
This cannot be one decay, because a nucleus cannot change one number without the other
NUC-021 · medium · application · seq 14 · authored (stage 2); p33 design — parent position on an alpha equation, fresh real decay Bi-209 → Tl-205 · text
Find the missing species: ? → ²⁰⁵₈₁Tl + ⁴₂He. Give the missing starting nucleus, in isotope notation. (Atomic numbers: Tl 81, Pb 82, Bi 83, Po 84.)
Answer: ²⁰⁹₈₃Bi KEY
also accepted: bismuth-209, Bismuth-209, Bi-209, ^209_83Bi, 209/83 Bi
wrongValueDiagnostics
[
 {
  "value": "²⁰¹₇₉Au",
  "misconception": "you subtracted instead of adding — the missing species is on the LEFT, so its numbers are the right side's totals: 205 + 4 and 81 + 2",
  "feedback": "This answer is wrong — you subtracted instead of adding; the missing species is on the LEFT, so its numbers are the right side's totals: 205 + 4 and 81 + 2."
 },
 {
  "value": "²⁰⁹₈₁Tl",
  "misconception": "you added only the mass number — the atomic total needs 81 + 2 = 83 as well",
  "feedback": "This answer is wrong — you added only the mass number; the atomic total needs 81 + 2 = 83 as well."
 },
 {
  "value": "²⁰⁷₈₅At",
  "misconception": "you swapped the two additions — mass 205 + 4 = 209 and atomic 81 + 2 = 83, not the reverse",
  "feedback": "This answer is wrong — you swapped the two additions; mass 205 + 4 = 209 and atomic 81 + 2 = 83, not the reverse."
 }
]
feedback
{
 "keyExplanation": "The missing species sits on the left, so its numbers are the right side's totals. Mass number: 205 + 4 = 209. Atomic number: 81 + 2 = 83 — bismuth. The starting nucleus is ²⁰⁹₈₃Bi, and the equation reads ²⁰⁹₈₃Bi → ²⁰⁵₈₁Tl + ⁴₂He.",
 "anticipatedWrong": [
  {
   "value": "²⁰¹₇₉Au",
   "misconception": "you subtracted instead of adding — the missing species is on the LEFT, so its numbers are the right side's totals: 205 + 4 and 81 + 2",
   "feedback": "This answer is wrong — you subtracted instead of adding; the missing species is on the LEFT, so its numbers are the right side's totals: 205 + 4 and 81 + 2."
  },
  {
   "value": "²⁰⁹₈₁Tl",
   "misconception": "you added only the mass number — the atomic total needs 81 + 2 = 83 as well",
   "feedback": "This answer is wrong — you added only the mass number; the atomic total needs 81 + 2 = 83 as well."
  },
  {
   "value": "²⁰⁷₈₅At",
   "misconception": "you swapped the two additions — mass 205 + 4 = 209 and atomic 81 + 2 = 83, not the reverse",
   "feedback": "This answer is wrong — you swapped the two additions; mass 205 + 4 = 209 and atomic 81 + 2 = 83, not the reverse."
  }
 ]
}
NUC-012 · hard · transfer · seq 15 · authored (stage 2); verdict family, fresh instance (real parent Es-254; student daughter mis-written) · mcq4
For an alpha decay, a student writes ²⁵⁴₉₉Es → ²⁵²₉₇Bk + ⁴₂He. Give the correct verdict.
Unbalanced — the mass-number totals do not match. KEY
Unbalanced — the atomic-number totals do not match.
Balanced — both totals agree.
Unbalanced — neither total agrees.
NUC-013 · hard · application · seq 16 · authored (blind wave 1); fresh real alpha decay Os-186 → W-182 — replaces Pa-227 → Ac-223, whose key taught the exact Z=89↔Ac mapping that exposes C#17's mislabeled-symbol error (blind cross-item-cue flag) · mcq4
¹⁸⁶₇₆Os undergoes alpha decay. Which nuclide is left behind? (Atomic numbers: Hf 72, Ta 73, W 74, Re 75, Os 76.)
¹⁸²₇₄W KEY
¹⁸²₇₆Os
¹⁸⁶₇₄W
¹⁸²₇₅Re
NUC-014 · hard · transfer · seq 17 · authored (stage 2); p14 design, element-symbol check class (real parent Pa-231; numbers balance, symbol mis-read) · mcq4
A student writes the alpha decay of ²³¹₉₁Pa as ²³¹₉₁Pa → ²²⁷₈₉Th + ⁴₂He. Which check exposes the student's error? (Atomic numbers: Fr 87, Ra 88, Ac 89, Th 90, Pa 91.)
The element symbol does not match the new atomic number. KEY
The mass-number totals do not balance.
The atomic-number totals do not balance.
Both totals fail to balance.
NUC-019 · hard · transfer · seq 18 · authored (blind wave 1); alpha-vs-beta separation rework of the alpha-vs-gamma THINNEST item (superlative left aluminum arguably defensible — F2) · mcq4
Two sealed sources sit on a lab bench: one gives off alpha particles, the other beta particles. Trying one taught barrier in front of each source in turn, which barrier separates the two?
A sheet of paper KEY
A thin sheet of aluminum
A thick block of lead
No barrier can tell them apart
NUC-016 · hard · transfer · seq 19 · authored (stage 2); p20 design, fresh instance Sb-125 (real β−) · mcq4
Antimony-125 (¹²⁵₅₁Sb) undergoes beta decay, and the nuclide left behind still has mass number 125. Why does the mass number stay at 125 even though a particle has left the nucleus?
The emitted electron adds nothing to the proton-plus-neutron tally that the mass number records. KEY
The nucleus pulls in a replacement particle from outside, and the replacement keeps the count at 125.
The mass number really falls to 124, because every departing particle lowers it.
The electron's mass exactly equals a neutron's mass, so the total is unchanged.
NUC-017 · hard · application · seq 20 · authored (stage 2); p23 design + p21's left-out-particle misconception as the exposed error (p22's Au-198 instance carried in notation) · mcq4
In a homework answer, the beta decay of ¹⁹⁸₇₉Au is written as ¹⁹⁸₇₉Au → ¹⁹⁸₈₀Hg, with nothing else on the right. Which check catches the mistake?
The atomic-number totals do not balance. KEY
The mass-number totals do not balance.
Neither total balances.
The equation shows the wrong particle for beta decay.
NUC-021 · medium · application · seq 21 · authored fresh (stage 2); real decays Bi-212 (α branch, A-U14G2-5), Nd-149 (β), Rh-105 (β) · frq
Three nuclear equations each have one species missing. Use the balancing totals to find every missing piece, and show your reasoning.
Three nuclear equations each have one species missing. Use the balancing totals to find every missing piece, and show your reasoning. (a) ²¹²₈₃Bi → ²⁰⁸₈₁Tl + ? — work out the missing species' mass number and bottom number from the two totals, name the species, and justify your choice using both totals. (b) ¹⁴⁹₆₀Nd → ? + ⁰₋₁e — work out the missing nucleus and give it with its element name and mass number. (Atomic numbers: Nd 60, Pm 61, Sm 62, Eu 63.) (c) ? → ¹⁰⁵₄₆Pd + ⁰₋₁e — the starting nucleus is missing; work out both of its numbers and give it with its element name and mass number. (Atomic numbers: Ru 44, Rh 45, Pd 46, Ag 47.)
Part a. ²¹²₈₃Bi → ²⁰⁸₈₁Tl + ? — work out the missing species' mass number and bottom number from the two totals, name the species, and justify your choice using both totals.
Model: Mass numbers: 212 = 208 + ?, so the missing species carries mass number 4. Bottom numbers: 83 = 81 + ?, so its bottom number is 2. Mass number 4 with bottom number 2 is the alpha particle — 2 protons and 2 neutrons; both totals balance only with it (this is the real alpha branch of that decay).
Part b. ¹⁴⁹₆₀Nd → ? + ⁰₋₁e — work out the missing nucleus and give it with its element name and mass number. (Atomic numbers: Nd 60, Pm 61, Sm 62, Eu 63.)
Model: The beta particle adds 0 to the mass total, so the missing nucleus keeps mass number 149. Its atomic number must satisfy 60 = ? + (−1), so it is 61 — promethium. The missing nucleus is promethium-149.
Part c. ? → ¹⁰⁵₄₆Pd + ⁰₋₁e — the starting nucleus is missing; work out both of its numbers and give it with its element name and mass number. (Atomic numbers: Ru 44, Rh 45, Pd 46, Ag 47.)
Model: The missing species sits on the left, so both of its numbers are the right-side totals: mass 105 + 0 = 105, atomic 46 + (−1) = 45. The element with atomic number 45 is rhodium, so the starting nucleus is rhodium-105.
Full model answer. (a) Mass numbers: 212 = 208 + ?, so the missing species carries mass number 4. Bottom numbers: 83 = 81 + ?, so its bottom number is 2. Mass number 4 with bottom number 2 is the alpha particle — 2 protons and 2 neutrons; both totals balance only with it (this is the real alpha branch of that decay). (b) The beta particle adds 0 to the mass total, so the missing nucleus keeps mass number 149. Its atomic number must satisfy 60 = ? + (−1), so it is 61 — promethium. The missing nucleus is promethium-149. (c) The missing species sits on the left, so both of its numbers are the right-side totals: mass 105 + 0 = 105, atomic 46 + (−1) = 45. The element with atomic number 45 is rhodium, so the starting nucleus is rhodium-105.

Form D

NUC-010 · easy · recall · seq 1 · authored (stage 2); seed family p2, stem reworded · numeric
In the alpha particle's symbol ⁴₂He, the two numbers together tell you its neutron count. How many neutrons is that?
Answer: 2 neutrons KEY
wrongValueDiagnostics
[
 {
  "value": 4,
  "misconception": "you answered with the mass number — that counts protons and neutrons together",
  "feedback": "This answer is wrong — you answered with the mass number; that counts protons and neutrons together."
 },
 {
  "value": 6,
  "misconception": "you combined the two numbers by adding — the neutron count is their difference",
  "feedback": "This answer is wrong — you combined the two numbers by adding; the neutron count is their difference, 4 − 2 = 2."
 },
 {
  "value": 0,
  "misconception": "you decided the particle holds only protons — 2 of its 4 particles are neutrons",
  "feedback": "This answer is wrong — you decided the particle holds only protons; 2 of its 4 particles are neutrons."
 }
]
feedback
{
 "keyExplanation": "Subtract the proton count from the mass number: 4 − 2 = 2 neutrons. That matches the alpha particle's makeup of 2 protons and 2 neutrons.",
 "anticipatedWrong": [
  {
   "value": 4,
   "misconception": "you answered with the mass number — that counts protons and neutrons together",
   "feedback": "This answer is wrong — you answered with the mass number; that counts protons and neutrons together."
  },
  {
   "value": 6,
   "misconception": "you combined the two numbers by adding — the neutron count is their difference",
   "feedback": "This answer is wrong — you combined the two numbers by adding; the neutron count is their difference, 4 − 2 = 2."
  },
  {
   "value": 0,
   "misconception": "you decided the particle holds only protons — 2 of its 4 particles are neutrons",
   "feedback": "This answer is wrong — you decided the particle holds only protons; 2 of its 4 particles are neutrons."
  }
 ]
}
NUC-015 · easy · recall · seq 2 · authored (stage 2); p15 family, top-slot ask · mcq4
What does the 0 in the beta particle's symbol ⁰₋₁e say about the particle?
It is neither a proton nor a neutron, so it adds nothing to a mass-number count. KEY
It carries no electric charge of any kind as it leaves the nucleus.
It has exactly zero mass, with nothing at all for a balance to weigh.
It stays inside the nucleus instead of leaving, so nothing is emitted at all.
NUC-011 · easy · application · seq 3 · authored (stage 2); p4 design, fresh real alpha decay Cf-250 → Cm-246 · mcq4
Read ²⁵⁰₉₈Cf → ²⁴⁶₉₆Cm + ⁴₂He. Which species are produced, according to the equation?
A curium-246 nucleus and an alpha particle. KEY
A californium-250 nucleus and an alpha particle.
A curium-246 nucleus and a beta particle.
A californium-250 nucleus and a curium-246 nucleus.
NUC-018 · easy · recall · seq 4 · authored (stage 2); p24/p25 family, same-element ask · mcq4
An energized nucleus releases a gamma ray. Why is it still the same element afterwards?
No protons left the nucleus — the gamma ray carried away energy, not particles. KEY
Because the element is fixed by the neutrons, which did not move.
It is not the same element — releasing radiation always changes the element.
Because a fresh proton is created to replace the energy that left.
NUC-013 · medium · application · seq 5 · authored (stage 2); p10 design, fresh real alpha decay At-217 → Bi-213 · text
Astatine-217 (²¹⁷₈₅At) undergoes alpha decay. Give the nuclide left behind, in isotope notation. (Atomic numbers: Pb 82, Bi 83, Po 84, At 85, Rn 86.)
Answer: ²¹³₈₃Bi KEY
also accepted: bismuth-213, Bismuth-213, Bi-213, ^213_83Bi, 213/83 Bi
wrongValueDiagnostics
[
 {
  "value": "²¹⁵₈₁Tl",
  "misconception": "you swapped the drops — the mass number falls by 4 and the atomic number falls by 2",
  "feedback": "This answer is wrong — you swapped the drops; the mass number falls by 4 and the atomic number falls by 2."
 },
 {
  "value": "²¹³₈₅At",
  "misconception": "you kept the atomic number — the nucleus loses 2 protons, so the atom is no longer astatine",
  "feedback": "This answer is wrong — you kept the atomic number; the nucleus loses 2 protons, so the atom is no longer astatine."
 },
 {
  "value": "²²¹₈₇Fr",
  "misconception": "you added the alpha particle's numbers — the nucleus loses 2 protons and 2 neutrons",
  "feedback": "This answer is wrong — you added the alpha particle's numbers; the nucleus loses 2 protons and 2 neutrons."
 }
]
feedback
{
 "keyExplanation": "Mass number: 217 − 4 = 213. Atomic number: 85 − 2 = 83. The element with atomic number 83 is bismuth, so the nuclide left behind is ²¹³₈₃Bi.",
 "anticipatedWrong": [
  {
   "value": "²¹⁵₈₁Tl",
   "misconception": "you swapped the drops — the mass number falls by 4 and the atomic number falls by 2",
   "feedback": "This answer is wrong — you swapped the drops; the mass number falls by 4 and the atomic number falls by 2."
  },
  {
   "value": "²¹³₈₅At",
   "misconception": "you kept the atomic number — the nucleus loses 2 protons, so the atom is no longer astatine",
   "feedback": "This answer is wrong — you kept the atomic number; the nucleus loses 2 protons, so the atom is no longer astatine."
  },
  {
   "value": "²²¹₈₇Fr",
   "misconception": "you added the alpha particle's numbers — the nucleus loses 2 protons and 2 neutrons",
   "feedback": "This answer is wrong — you added the alpha particle's numbers; the nucleus loses 2 protons and 2 neutrons."
  }
 ]
}
NUC-019 · medium · application · seq 6 · authored (stage 2); p27 design, gamma key (two-barrier framing) · mcq4
With a sheet of paper and a thin sheet of aluminum both standing in front of a source, a detector still reads a strong signal. Behind a thick wall of concrete, the signal finally drops. Which type of radiation is this?
Gamma radiation KEY
Alpha radiation
Beta radiation
None of the three types
NUC-016 · medium · application · seq 7 · authored (stage 2); p18 design, fresh instance Re-188 → Os-188 · text
Rhenium-188 (¹⁸⁸₇₅Re) decays by beta decay. Give the nuclide left behind, in isotope notation. (Atomic numbers: W 74, Re 75, Os 76, Ir 77.)
Answer: ¹⁸⁸₇₆Os KEY
also accepted: osmium-188, Osmium-188, Os-188, ^188_76Os, 188/76 Os
wrongValueDiagnostics
[
 {
  "value": "¹⁸⁸₇₄W",
  "misconception": "you dropped the atomic number instead of raising it — a neutron becomes a proton, so the count rises",
  "feedback": "This answer is wrong — you dropped the atomic number instead of raising it; a neutron becomes a proton, so the count rises."
 },
 {
  "value": "¹⁸⁸₇₅Re",
  "misconception": "you kept the atomic number — one more proton means the atom is no longer rhenium",
  "feedback": "This answer is wrong — you kept the atomic number; one more proton means the atom is no longer rhenium."
 },
 {
  "value": "¹⁸⁷₇₆Os",
  "misconception": "you dropped the mass number by 1 — the electron that leaves is not a proton or neutron",
  "feedback": "This answer is wrong — you dropped the mass number by 1; the electron that leaves is not a proton or neutron."
 }
]
feedback
{
 "keyExplanation": "The mass number stays 188; the atomic number rises to 75 + 1 = 76. The element with atomic number 76 is osmium, so the nuclide left behind is ¹⁸⁸₇₆Os.",
 "anticipatedWrong": [
  {
   "value": "¹⁸⁸₇₄W",
   "misconception": "you dropped the atomic number instead of raising it — a neutron becomes a proton, so the count rises",
   "feedback": "This answer is wrong — you dropped the atomic number instead of raising it; a neutron becomes a proton, so the count rises."
  },
  {
   "value": "¹⁸⁸₇₅Re",
   "misconception": "you kept the atomic number — one more proton means the atom is no longer rhenium",
   "feedback": "This answer is wrong — you kept the atomic number; one more proton means the atom is no longer rhenium."
  },
  {
   "value": "¹⁸⁷₇₆Os",
   "misconception": "you dropped the mass number by 1 — the electron that leaves is not a proton or neutron",
   "feedback": "This answer is wrong — you dropped the mass number by 1; the electron that leaves is not a proton or neutron."
  }
 ]
}
NUC-012 · medium · application · seq 8 · authored (stage 2); p6 design, fresh real alpha decay Th-229 → Ra-225 · numeric
In ²²⁹₉₀Th → ²²⁵₈₈Ra + ⁴₂He, what total do the atomic numbers on the right add up to?
Answer: 90 protons KEY
wrongValueDiagnostics
[
 {
  "value": 88,
  "misconception": "you took the new nucleus's atomic number alone — the alpha particle's 2 must be added in",
  "feedback": "This answer is wrong — you took the new nucleus's atomic number alone; the alpha particle's 2 must be added in."
 },
 {
  "value": 92,
  "misconception": "you added the alpha particle's mass number instead of its atomic number",
  "feedback": "This answer is wrong — you added the alpha particle's mass number instead of its atomic number; use the bottom numbers: 88 + 2."
 },
 {
  "value": 86,
  "misconception": "you subtracted the alpha particle's 2 instead of adding it",
  "feedback": "This answer is wrong — you subtracted the alpha particle's 2 instead of adding it; the right side's atomic numbers add together."
 }
]
feedback
{
 "keyExplanation": "Add the right side's atomic numbers: 88 + 2 = 90, matching the left side's 90 — the atomic numbers balance, because electric charge never appears or disappears.",
 "anticipatedWrong": [
  {
   "value": 88,
   "misconception": "you took the new nucleus's atomic number alone — the alpha particle's 2 must be added in",
   "feedback": "This answer is wrong — you took the new nucleus's atomic number alone; the alpha particle's 2 must be added in."
  },
  {
   "value": 92,
   "misconception": "you added the alpha particle's mass number instead of its atomic number",
   "feedback": "This answer is wrong — you added the alpha particle's mass number instead of its atomic number; use the bottom numbers: 88 + 2."
  },
  {
   "value": 86,
   "misconception": "you subtracted the alpha particle's 2 instead of adding it",
   "feedback": "This answer is wrong — you subtracted the alpha particle's 2 instead of adding it; the right side's atomic numbers add together."
  }
 ]
}
NUC-017 · medium · application · seq 9 · authored (stage 2); p21 design, fresh instance Tb-161 → Dy-161 · text
Write the complete nuclear equation for the beta decay of terbium-161 (¹⁶¹₆₅Tb). (Atomic numbers: Gd 64, Tb 65, Dy 66, Ho 67.)
Answer: ¹⁶¹₆₅Tb → ¹⁶¹₆₆Dy + ⁰₋₁e KEY
also accepted: ^161_65Tb → ^161_66Dy + ^0_-1e, 161/65 Tb → 161/66 Dy + 0/-1 e, Tb-161 → Dy-161 + e
wrongValueDiagnostics
[
 {
  "value": "¹⁶¹₆₅Tb → ¹⁶¹₆₄Gd + ⁰₋₁e",
  "misconception": "you subtracted 1 from the atomic number — beta decay raises it by 1",
  "feedback": "This answer is wrong — you subtracted 1 from the atomic number; beta decay raises it by 1."
 },
 {
  "value": "¹⁶⁰₆₆Dy + ⁰₋₁e as the right side",
  "misconception": "you dropped the mass number by 1 — the total count of protons plus neutrons is unchanged",
  "feedback": "This answer is wrong — you dropped the mass number by 1; the total count of protons plus neutrons is unchanged."
 },
 {
  "value": "¹⁶¹₆₅Tb → ¹⁶¹₆₆Dy",
  "misconception": "you left out the beta particle — without its −1, the atomic numbers cannot balance",
  "feedback": "This answer is wrong — you left out the beta particle; without its −1, the atomic numbers cannot balance."
 }
]
feedback
{
 "keyExplanation": "The mass number stays 161; the atomic number rises to 65 + 1 = 66, and the element with atomic number 66 is dysprosium. The complete equation is ¹⁶¹₆₅Tb → ¹⁶¹₆₆Dy + ⁰₋₁e; check: 161 = 161 + 0 and 65 = 66 + (−1).",
 "anticipatedWrong": [
  {
   "value": "¹⁶¹₆₅Tb → ¹⁶¹₆₄Gd + ⁰₋₁e",
   "misconception": "you subtracted 1 from the atomic number — beta decay raises it by 1",
   "feedback": "This answer is wrong — you subtracted 1 from the atomic number; beta decay raises it by 1."
  },
  {
   "value": "¹⁶⁰₆₆Dy + ⁰₋₁e as the right side",
   "misconception": "you dropped the mass number by 1 — the total count of protons plus neutrons is unchanged",
   "feedback": "This answer is wrong — you dropped the mass number by 1; the total count of protons plus neutrons is unchanged."
  },
  {
   "value": "¹⁶¹₆₅Tb → ¹⁶¹₆₆Dy",
   "misconception": "you left out the beta particle — without its −1, the atomic numbers cannot balance",
   "feedback": "This answer is wrong — you left out the beta particle; without its −1, the atomic numbers cannot balance."
  }
 ]
}
NUC-020 · medium · application · seq 10 · authored (stage 2); p30 design, fresh real alpha decay Po-209 → Pb-205 · mcq4
A single decay turns ²⁰⁹₈₄Po into ²⁰⁵₈₂Pb. Which decay type is it?
Alpha decay KEY
Beta decay
Gamma emission
A gamma ray that carried four particles away with it
NUC-014 · medium · application · seq 11 · authored (stage 2); p12 design, fresh real alpha decay Ra-221 → Rn-217 (notation-only stem) · text
Write the complete nuclear equation for the alpha decay of ²²¹₈₈Ra. (Atomic numbers: Po 84, At 85, Rn 86, Fr 87, Ra 88.)
Answer: ²²¹₈₈Ra → ²¹⁷₈₆Rn + ⁴₂He KEY
also accepted: ^221_88Ra → ^217_86Rn + ^4_2He, 221/88 Ra → 217/86 Rn + 4/2 He, Ra-221 → Rn-217 + He-4
wrongValueDiagnostics
[
 {
  "value": "²²¹₈₈Ra → ²¹⁹₈₄Po + ⁴₂He",
  "misconception": "you swapped the drops — the mass number falls by 4 and the atomic number falls by 2",
  "feedback": "This answer is wrong — you swapped the drops; the mass number falls by 4 and the atomic number falls by 2."
 },
 {
  "value": "²²¹₈₈Ra → ²¹⁷₈₇Fr + ⁴₂He",
  "misconception": "you dropped the atomic number by 1 instead of 2 — the alpha particle carries away 2 protons",
  "feedback": "This answer is wrong — you dropped the atomic number by 1 instead of 2; the alpha particle carries away 2 protons."
 },
 {
  "value": "²²¹₈₈Ra → ²¹⁷₈₆Rn",
  "misconception": "you left out the alpha particle — without it, neither total balances",
  "feedback": "This answer is wrong — you left out the alpha particle; without it, neither total balances."
 }
]
feedback
{
 "keyExplanation": "New mass number: 221 − 4 = 217. New atomic number: 88 − 2 = 86, and the element with atomic number 86 is radon. The complete equation is ²²¹₈₈Ra → ²¹⁷₈₆Rn + ⁴₂He; check: 221 = 217 + 4 and 88 = 86 + 2.",
 "anticipatedWrong": [
  {
   "value": "²²¹₈₈Ra → ²¹⁹₈₄Po + ⁴₂He",
   "misconception": "you swapped the drops — the mass number falls by 4 and the atomic number falls by 2",
   "feedback": "This answer is wrong — you swapped the drops; the mass number falls by 4 and the atomic number falls by 2."
  },
  {
   "value": "²²¹₈₈Ra → ²¹⁷₈₇Fr + ⁴₂He",
   "misconception": "you dropped the atomic number by 1 instead of 2 — the alpha particle carries away 2 protons",
   "feedback": "This answer is wrong — you dropped the atomic number by 1 instead of 2; the alpha particle carries away 2 protons."
  },
  {
   "value": "²²¹₈₈Ra → ²¹⁷₈₆Rn",
   "misconception": "you left out the alpha particle — without it, neither total balances",
   "feedback": "This answer is wrong — you left out the alpha particle; without it, neither total balances."
  }
 ]
}
NUC-021 · medium · application · seq 12 · authored (stage 2); p35 design, fresh real beta decay Re-187 → Os-187 · mcq4
Find the missing species: ¹⁸⁷₇₅Re → ¹⁸⁷₇₆Os + ?
⁰₋₁e KEY
⁴₂He
⁰₁e
A gamma ray
NUC-020 · medium · application · seq 13 · authored (stage 2); p31 design, fresh real beta decay O-19 → F-19 stated as counts · mcq4
During one decay, a nucleus's mass number stays at 19 while its atomic number rises from 8 to 9. Which decay type produced this change?
Beta decay KEY
Alpha decay
Gamma emission
No decay type does this — shedding a particle only ever lowers the numbers
NUC-021 · medium · application · seq 14 · authored (stage 2); p34 design — daughter position, fresh real beta decay Te-127 → I-127 · text
Find the missing species: ¹²⁷₅₂Te → ? + ⁰₋₁e. Give the missing new nucleus, in isotope notation. (Atomic numbers: Te 52, I 53, Xe 54, Cs 55.)
Answer: ¹²⁷₅₃I KEY
also accepted: iodine-127, Iodine-127, I-127, ^127_53I, 127/53 I
wrongValueDiagnostics
[
 {
  "value": "¹²⁷₅₁Sb",
  "misconception": "you subtracted the −1 as if it were +1 — 52 = ? + (−1) forces the missing atomic number UP to 53",
  "feedback": "This answer is wrong — you subtracted the −1 as if it were +1; 52 = ? + (−1) forces the missing atomic number UP to 53."
 },
 {
  "value": "¹²⁷₅₂Te",
  "misconception": "you kept the starting atomic number — the beta particle's −1 raises the new nucleus's atomic number to 53",
  "feedback": "This answer is wrong — you kept the starting atomic number; the beta particle's −1 raises the new nucleus's atomic number to 53."
 },
 {
  "value": "¹²⁶₅₃I",
  "misconception": "you dropped the mass number — the beta particle's mass number is 0, so 127 stays",
  "feedback": "This answer is wrong — you dropped the mass number; the beta particle's mass number is 0, so 127 stays."
 }
]
feedback
{
 "keyExplanation": "Missing mass number: 127 − 0 = 127. Missing atomic number: 52 − (−1) = 53 — iodine. The missing species is ¹²⁷₅₃I, and the equation reads ¹²⁷₅₂Te → ¹²⁷₅₃I + ⁰₋₁e.",
 "anticipatedWrong": [
  {
   "value": "¹²⁷₅₁Sb",
   "misconception": "you subtracted the −1 as if it were +1 — 52 = ? + (−1) forces the missing atomic number UP to 53",
   "feedback": "This answer is wrong — you subtracted the −1 as if it were +1; 52 = ? + (−1) forces the missing atomic number UP to 53."
  },
  {
   "value": "¹²⁷₅₂Te",
   "misconception": "you kept the starting atomic number — the beta particle's −1 raises the new nucleus's atomic number to 53",
   "feedback": "This answer is wrong — you kept the starting atomic number; the beta particle's −1 raises the new nucleus's atomic number to 53."
  },
  {
   "value": "¹²⁶₅₃I",
   "misconception": "you dropped the mass number — the beta particle's mass number is 0, so 127 stays",
   "feedback": "This answer is wrong — you dropped the mass number; the beta particle's mass number is 0, so 127 stays."
  }
 ]
}
NUC-012 · hard · transfer · seq 15 · authored (stage 2); verdict family, fresh instance (real parent Gd-152; student daughter mis-written in both numbers) · mcq4
For an alpha decay, a student writes ¹⁵²₆₄Gd → ¹⁵⁰₆₃Eu + ⁴₂He. Which of the verdicts is right?
Unbalanced — neither total agrees. KEY
Unbalanced — only the mass-number totals disagree.
Unbalanced — only the atomic-number totals disagree.
Balanced — both totals agree.
NUC-013 · hard · application · seq 16 · authored (stage 2); p11 design, fresh real alpha decay Fm-255 → Cf-251 (notation-only stem) · mcq4
²⁵⁵₁₀₀Fm undergoes alpha decay. Which nuclide is left behind? (Atomic numbers: Cm 96, Bk 97, Cf 98, Es 99, Fm 100.)
²⁵¹₉₈Cf KEY
²⁵¹₁₀₀Fm
²⁵³₉₆Cm
²⁵⁹₁₀₂No
NUC-014 · hard · transfer · seq 17 · authored (stage 2); p14 design + p12's left-out-particle misconception as the exposed error (real parent Rn-210) · mcq4
A student writes the alpha decay of ²¹⁰₈₆Rn as ²¹⁰₈₆Rn → ²⁰⁶₈₄Po, with nothing else on the right. Which check exposes the student's error?
Both totals fail to balance. KEY
Only the mass-number total fails to balance.
Only the atomic-number total fails to balance.
The element symbol does not match the new atomic number.
NUC-019 · hard · transfer · seq 18 · SEED pool[29] = NUC-019 gate[2] design, redeployed as the form-D rotation · mcq4
The radiation from one sealed source cannot even pass through the outer layer of a person's skin. Which radiation type must it be?
Alpha radiation KEY
Beta radiation
Gamma radiation
None of the three types
NUC-016 · hard · transfer · seq 19 · authored (stage 2); p20 design, fresh instance Ag-111 (real β−) · mcq4
Silver-111 (¹¹¹₄₇Ag) undergoes beta decay, and the nuclide left behind still has mass number 111. Why is the mass number unchanged even though a particle has left the nucleus?
The mass number tallies only protons and neutrons, and the departing electron is not one of them. KEY
The nucleus pulls in a replacement particle from outside, which is what keeps the count at 111.
The mass number really falls to 110, because every departing particle lowers it.
The electron's mass exactly equals a neutron's mass, so the total is unchanged.
NUC-017 · hard · application · seq 20 · authored (stage 2); p23 design, fresh instance (real β− parent Nd-147) · mcq4
In a homework answer, the beta decay of ¹⁴⁷₆₀Nd is written as ¹⁴⁷₆₀Nd → ¹⁴⁶₆₁Pm + ⁰₋₁e. Which check catches the mistake?
The mass-number totals do not balance. KEY
The atomic-number totals do not balance.
Neither total balances.
The equation shows the wrong particle for beta decay.
NUC-021 · medium · application · seq 21 · authored fresh (stage 2); real decays Fr-218 (α), Hf-181 (β), As-76 (β) · frq
Three nuclear equations each have one species missing. Use the balancing totals to find every missing piece, and show your reasoning.
Three nuclear equations each have one species missing. Use the balancing totals to find every missing piece, and show your reasoning. (a) ²¹⁸₈₇Fr → ²¹⁴₈₅At + ? — work out the missing species' mass number and bottom number from the two totals, name the species, and justify your choice using both totals. (b) ¹⁸¹₇₂Hf → ? + ⁰₋₁e — work out the missing nucleus and give it with its element name and mass number. (Atomic numbers: Lu 71, Hf 72, Ta 73, W 74.) (c) ? → ⁷⁶₃₄Se + ⁰₋₁e — the starting nucleus is missing; work out both of its numbers and give it with its element name and mass number. (Atomic numbers: Ge 32, As 33, Se 34, Br 35.)
Part a. ²¹⁸₈₇Fr → ²¹⁴₈₅At + ? — work out the missing species' mass number and bottom number from the two totals, name the species, and justify your choice using both totals.
Model: Mass numbers: 218 = 214 + ?, so the missing species carries mass number 4. Bottom numbers: 87 = 85 + ?, so its bottom number is 2. Mass number 4 with bottom number 2 is the alpha particle — 2 protons and 2 neutrons; both totals balance only with it.
Part b. ¹⁸¹₇₂Hf → ? + ⁰₋₁e — work out the missing nucleus and give it with its element name and mass number. (Atomic numbers: Lu 71, Hf 72, Ta 73, W 74.)
Model: The beta particle adds 0 to the mass total, so the missing nucleus keeps mass number 181. Its atomic number must satisfy 72 = ? + (−1), so it is 73 — tantalum. The missing nucleus is tantalum-181.
Part c. ? → ⁷⁶₃₄Se + ⁰₋₁e — the starting nucleus is missing; work out both of its numbers and give it with its element name and mass number. (Atomic numbers: Ge 32, As 33, Se 34, Br 35.)
Model: The missing species sits on the left, so both of its numbers are the right-side totals: mass 76 + 0 = 76, atomic 34 + (−1) = 33. The element with atomic number 33 is arsenic, so the starting nucleus is arsenic-76.
Full model answer. (a) Mass numbers: 218 = 214 + ?, so the missing species carries mass number 4. Bottom numbers: 87 = 85 + ?, so its bottom number is 2. Mass number 4 with bottom number 2 is the alpha particle — 2 protons and 2 neutrons; both totals balance only with it. (b) The beta particle adds 0 to the mass total, so the missing nucleus keeps mass number 181. Its atomic number must satisfy 72 = ? + (−1), so it is 73 — tantalum. The missing nucleus is tantalum-181. (c) The missing species sits on the left, so both of its numbers are the right-side totals: mass 76 + 0 = 76, atomic 34 + (−1) = 33. The element with atomic number 33 is arsenic, so the starting nucleus is arsenic-76.

Form E

NUC-010 · easy · recall · seq 1 · authored (stage 2); seed family p2, stem reworded · numeric
Read the alpha particle's symbol, ⁴₂He, and enter the number of neutrons inside the particle.
Answer: 2 neutrons KEY
wrongValueDiagnostics
[
 {
  "value": 4,
  "misconception": "you used the mass number as if it counted only neutrons — it counts protons too",
  "feedback": "This answer is wrong — you used the mass number as if it counted only neutrons; it counts protons too, so subtract the 2."
 },
 {
  "value": 6,
  "misconception": "you added the two numbers instead of subtracting them",
  "feedback": "This answer is wrong — you added the two numbers instead of subtracting them: 4 − 2 = 2."
 },
 {
  "value": 0,
  "misconception": "you left the particle with no neutrons — its 4 particles are 2 protons AND 2 neutrons",
  "feedback": "This answer is wrong — you left the particle with no neutrons; its 4 particles are 2 protons AND 2 neutrons."
 }
]
feedback
{
 "keyExplanation": "The mass number 4 counts protons plus neutrons and the 2 counts protons, so 4 − 2 = 2 neutrons — the alpha particle is 2 protons and 2 neutrons bound together.",
 "anticipatedWrong": [
  {
   "value": 4,
   "misconception": "you used the mass number as if it counted only neutrons — it counts protons too",
   "feedback": "This answer is wrong — you used the mass number as if it counted only neutrons; it counts protons too, so subtract the 2."
  },
  {
   "value": 6,
   "misconception": "you added the two numbers instead of subtracting them",
   "feedback": "This answer is wrong — you added the two numbers instead of subtracting them: 4 − 2 = 2."
  },
  {
   "value": 0,
   "misconception": "you left the particle with no neutrons — its 4 particles are 2 protons AND 2 neutrons",
   "feedback": "This answer is wrong — you left the particle with no neutrons; its 4 particles are 2 protons AND 2 neutrons."
  }
 ]
}
NUC-015 · easy · recall · seq 2 · authored (stage 2); p15 family, both-slots ask · mcq4
A beta particle is written ⁰₋₁e in nuclear equations. Which statement reads the two numbers correctly?
The 0 says it counts nothing toward a mass number; the −1 records its charge. KEY
The 0 says it carries no electric charge; the −1 counts one neutron lost from the nucleus.
The 0 says it has no mass; the −1 says it moves backwards.
The 0 counts its protons; the −1 counts its electrons.
NUC-011 · easy · application · seq 3 · authored (stage 2); p4 design, fresh real alpha decay Bi-211 → Tl-207 · mcq4
In ²¹¹₈₃Bi → ²⁰⁷₈₁Tl + ⁴₂He, what does the equation give as the products of the change?
A thallium-207 nucleus and an alpha particle. KEY
A bismuth-211 nucleus and an alpha particle.
A thallium-207 nucleus and a beta particle.
A bismuth-211 nucleus and a thallium-207 nucleus.
NUC-018 · easy · recall · seq 4 · authored (stage 2); p24 family, same-isotope ask · mcq4
After a nucleus sheds a gamma ray, it is the same isotope of the same element. What makes that so?
The gamma ray removed energy only — the proton and neutron counts are untouched. KEY
The nucleus lost one neutron, but neutron losses never change the isotope.
The gamma ray put energy INTO the nucleus, locking its particles in place.
Isotopes are named by energy level, and the level did not change.
NUC-013 · medium · application · seq 5 · authored (stage 2); p10 design, fresh real alpha decay W-180 → Hf-176 · text
Tungsten-180 (¹⁸⁰₇₄W) undergoes alpha decay. Give the nuclide left behind, in isotope notation. (Atomic numbers: Yb 70, Lu 71, Hf 72, Ta 73, W 74.)
Answer: ¹⁷⁶₇₂Hf KEY
also accepted: hafnium-176, Hafnium-176, Hf-176, ^176_72Hf, 176/72 Hf
wrongValueDiagnostics
[
 {
  "value": "¹⁷⁸₇₀Yb",
  "misconception": "you swapped the drops — the mass number falls by 4 and the atomic number falls by 2",
  "feedback": "This answer is wrong — you swapped the drops; the mass number falls by 4 and the atomic number falls by 2."
 },
 {
  "value": "¹⁷⁶₇₄W",
  "misconception": "you kept the atomic number — losing 2 protons means the atom is no longer tungsten",
  "feedback": "This answer is wrong — you kept the atomic number; losing 2 protons means the atom is no longer tungsten."
 },
 {
  "value": "¹⁸⁴₇₆Os",
  "misconception": "you added the alpha particle's numbers instead of subtracting them",
  "feedback": "This answer is wrong — you added the alpha particle's numbers instead of subtracting them."
 }
]
feedback
{
 "keyExplanation": "Mass number: 180 − 4 = 176. Atomic number: 74 − 2 = 72. The element with atomic number 72 is hafnium, so alpha decay leaves ¹⁷⁶₇₂Hf behind.",
 "anticipatedWrong": [
  {
   "value": "¹⁷⁸₇₀Yb",
   "misconception": "you swapped the drops — the mass number falls by 4 and the atomic number falls by 2",
   "feedback": "This answer is wrong — you swapped the drops; the mass number falls by 4 and the atomic number falls by 2."
  },
  {
   "value": "¹⁷⁶₇₄W",
   "misconception": "you kept the atomic number — losing 2 protons means the atom is no longer tungsten",
   "feedback": "This answer is wrong — you kept the atomic number; losing 2 protons means the atom is no longer tungsten."
  },
  {
   "value": "¹⁸⁴₇₆Os",
   "misconception": "you added the alpha particle's numbers instead of subtracting them",
   "feedback": "This answer is wrong — you added the alpha particle's numbers instead of subtracting them."
  }
 ]
}
NUC-019 · medium · application · seq 6 · authored (stage 2); p27 design, alpha key (counter framing) · mcq4
A counter near a source shows a large reading. Slipping one sheet of paper between the source and the counter brings the reading to zero. Which radiation type is it?
Alpha radiation KEY
Beta radiation
Gamma radiation
None of the three types
NUC-016 · medium · application · seq 7 · authored (stage 2); p18 design, fresh instance Au-199 → Hg-199 · text
Gold-199 (¹⁹⁹₇₉Au) decays by beta decay. Give the nuclide left behind, in isotope notation. (Atomic numbers: Pt 78, Au 79, Hg 80, Tl 81.)
Answer: ¹⁹⁹₈₀Hg KEY
also accepted: mercury-199, Mercury-199, Hg-199, ^199_80Hg, 199/80 Hg
wrongValueDiagnostics
[
 {
  "value": "¹⁹⁹₇₈Pt",
  "misconception": "you dropped the atomic number instead of raising it — beta decay raises it by 1",
  "feedback": "This answer is wrong — you dropped the atomic number instead of raising it; beta decay raises it by 1."
 },
 {
  "value": "¹⁹⁹₇₉Au",
  "misconception": "you kept the atomic number — one more proton means the atom is no longer gold",
  "feedback": "This answer is wrong — you kept the atomic number; one more proton means the atom is no longer gold."
 },
 {
  "value": "¹⁹⁸₈₀Hg",
  "misconception": "you dropped the mass number by 1 — the departing electron is not a proton or neutron",
  "feedback": "This answer is wrong — you dropped the mass number by 1; the departing electron is not a proton or neutron."
 }
]
feedback
{
 "keyExplanation": "Beta decay keeps the mass number at 199 and raises the atomic number: 79 + 1 = 80. The element with atomic number 80 is mercury, so the nuclide left behind is ¹⁹⁹₈₀Hg.",
 "anticipatedWrong": [
  {
   "value": "¹⁹⁹₇₈Pt",
   "misconception": "you dropped the atomic number instead of raising it — beta decay raises it by 1",
   "feedback": "This answer is wrong — you dropped the atomic number instead of raising it; beta decay raises it by 1."
  },
  {
   "value": "¹⁹⁹₇₉Au",
   "misconception": "you kept the atomic number — one more proton means the atom is no longer gold",
   "feedback": "This answer is wrong — you kept the atomic number; one more proton means the atom is no longer gold."
  },
  {
   "value": "¹⁹⁸₈₀Hg",
   "misconception": "you dropped the mass number by 1 — the departing electron is not a proton or neutron",
   "feedback": "This answer is wrong — you dropped the mass number by 1; the departing electron is not a proton or neutron."
  }
 ]
}
NUC-012 · medium · application · seq 8 · authored (stage 2); p6 design, fresh real alpha decay Am-243 → Np-239 · numeric
In ²⁴³₉₅Am → ²³⁹₉₃Np + ⁴₂He, what total do the atomic numbers on the right add up to?
Answer: 95 protons KEY
wrongValueDiagnostics
[
 {
  "value": 93,
  "misconception": "you took the new nucleus's atomic number alone — the alpha particle's 2 must be added in",
  "feedback": "This answer is wrong — you took the new nucleus's atomic number alone; the alpha particle's 2 must be added in: 93 + 2 = 95."
 },
 {
  "value": 97,
  "misconception": "you added the alpha particle's mass number instead of its atomic number",
  "feedback": "This answer is wrong — you added the alpha particle's mass number instead of its atomic number; the atomic-number total uses the bottom numbers."
 },
 {
  "value": 91,
  "misconception": "you subtracted the alpha particle's 2 instead of adding it",
  "feedback": "This answer is wrong — you subtracted the alpha particle's 2 instead of adding it; the right side's atomic numbers add together."
 }
]
feedback
{
 "keyExplanation": "The right side holds ²³⁹₉₃Np and ⁴₂He. Their atomic numbers add: 93 + 2 = 95, matching the left side's 95 — the atomic numbers balance, because electric charge never appears or disappears.",
 "anticipatedWrong": [
  {
   "value": 93,
   "misconception": "you took the new nucleus's atomic number alone — the alpha particle's 2 must be added in",
   "feedback": "This answer is wrong — you took the new nucleus's atomic number alone; the alpha particle's 2 must be added in: 93 + 2 = 95."
  },
  {
   "value": 97,
   "misconception": "you added the alpha particle's mass number instead of its atomic number",
   "feedback": "This answer is wrong — you added the alpha particle's mass number instead of its atomic number; the atomic-number total uses the bottom numbers."
  },
  {
   "value": 91,
   "misconception": "you subtracted the alpha particle's 2 instead of adding it",
   "feedback": "This answer is wrong — you subtracted the alpha particle's 2 instead of adding it; the right side's atomic numbers add together."
  }
 ]
}
NUC-017 · medium · application · seq 9 · authored (stage 2); p21 design, fresh instance Te-132 → I-132 · text
Write the complete nuclear equation for the beta decay of tellurium-132 (¹³²₅₂Te). (Atomic numbers: Sb 51, Te 52, I 53, Xe 54.)
Answer: ¹³²₅₂Te → ¹³²₅₃I + ⁰₋₁e KEY
also accepted: ^132_52Te → ^132_53I + ^0_-1e, 132/52 Te → 132/53 I + 0/-1 e, Te-132 → I-132 + e
wrongValueDiagnostics
[
 {
  "value": "¹³²₅₂Te → ¹³²₅₁Sb + ⁰₋₁e",
  "misconception": "you subtracted 1 from the atomic number — the neutron-to-proton change raises it by 1",
  "feedback": "This answer is wrong — you subtracted 1 from the atomic number; the neutron-to-proton change raises it by 1."
 },
 {
  "value": "¹³¹₅₃I + ⁰₋₁e as the right side",
  "misconception": "you dropped the mass number by 1 — the departing electron is not a proton or neutron",
  "feedback": "This answer is wrong — you dropped the mass number by 1; the departing electron is not a proton or neutron."
 },
 {
  "value": "¹³²₅₂Te → ¹³²₅₃I",
  "misconception": "you left out the beta particle — without its −1, the atomic numbers cannot balance",
  "feedback": "This answer is wrong — you left out the beta particle; without its −1, the atomic numbers cannot balance."
 }
]
feedback
{
 "keyExplanation": "The mass number stays 132; the atomic number rises to 52 + 1 = 53, and the element with atomic number 53 is iodine. The complete equation is ¹³²₅₂Te → ¹³²₅₃I + ⁰₋₁e; check: 132 = 132 + 0 and 52 = 53 + (−1).",
 "anticipatedWrong": [
  {
   "value": "¹³²₅₂Te → ¹³²₅₁Sb + ⁰₋₁e",
   "misconception": "you subtracted 1 from the atomic number — the neutron-to-proton change raises it by 1",
   "feedback": "This answer is wrong — you subtracted 1 from the atomic number; the neutron-to-proton change raises it by 1."
  },
  {
   "value": "¹³¹₅₃I + ⁰₋₁e as the right side",
   "misconception": "you dropped the mass number by 1 — the departing electron is not a proton or neutron",
   "feedback": "This answer is wrong — you dropped the mass number by 1; the departing electron is not a proton or neutron."
  },
  {
   "value": "¹³²₅₂Te → ¹³²₅₃I",
   "misconception": "you left out the beta particle — without its −1, the atomic numbers cannot balance",
   "feedback": "This answer is wrong — you left out the beta particle; without its −1, the atomic numbers cannot balance."
  }
 ]
}
NUC-020 · medium · application · seq 10 · authored (stage 2); p30 design, fresh real beta decay Sm-153 → Eu-153 · mcq4
A single decay turns ¹⁵³₆₂Sm into ¹⁵³₆₃Eu. Which decay type is it?
Beta decay KEY
Alpha decay
Gamma emission
No decay — a neutron simply broke loose and escaped
NUC-014 · medium · application · seq 11 · authored (stage 2); p12 design, fresh real alpha decay Cf-246 → Cm-242 (notation-only stem; list windows past the Pu symbol) · text
Write the complete nuclear equation for the alpha decay of ²⁴⁶₉₈Cf. (Atomic numbers: Am 95, Cm 96, Bk 97, Cf 98, Es 99.)
Answer: ²⁴⁶₉₈Cf → ²⁴²₉₆Cm + ⁴₂He KEY
also accepted: ^246_98Cf → ^242_96Cm + ^4_2He, 246/98 Cf → 242/96 Cm + 4/2 He, Cf-246 → Cm-242 + He-4
wrongValueDiagnostics
[
 {
  "value": "²⁴⁶₉₈Cf → ²⁴²₉₈Cf + ⁴₂He",
  "misconception": "you kept the atomic number — losing 2 protons changes the element",
  "feedback": "This answer is wrong — you kept the atomic number; losing 2 protons changes the element."
 },
 {
  "value": "²⁴⁶₉₈Cf → ²⁴²₉₇Bk + ⁴₂He",
  "misconception": "you dropped the atomic number by 1 instead of 2 — the alpha particle carries away 2 protons",
  "feedback": "This answer is wrong — you dropped the atomic number by 1 instead of 2; the alpha particle carries away 2 protons."
 },
 {
  "value": "²⁴⁶₉₈Cf → ²⁴²₉₆Cm",
  "misconception": "you left out the alpha particle — without it, neither total balances",
  "feedback": "This answer is wrong — you left out the alpha particle; without it, neither total balances."
 }
]
feedback
{
 "keyExplanation": "New mass number: 246 − 4 = 242. New atomic number: 98 − 2 = 96, and the element with atomic number 96 is curium. The complete equation is ²⁴⁶₉₈Cf → ²⁴²₉₆Cm + ⁴₂He; check: 246 = 242 + 4 and 98 = 96 + 2.",
 "anticipatedWrong": [
  {
   "value": "²⁴⁶₉₈Cf → ²⁴²₉₈Cf + ⁴₂He",
   "misconception": "you kept the atomic number — losing 2 protons changes the element",
   "feedback": "This answer is wrong — you kept the atomic number; losing 2 protons changes the element."
  },
  {
   "value": "²⁴⁶₉₈Cf → ²⁴²₉₇Bk + ⁴₂He",
   "misconception": "you dropped the atomic number by 1 instead of 2 — the alpha particle carries away 2 protons",
   "feedback": "This answer is wrong — you dropped the atomic number by 1 instead of 2; the alpha particle carries away 2 protons."
  },
  {
   "value": "²⁴⁶₉₈Cf → ²⁴²₉₆Cm",
   "misconception": "you left out the alpha particle — without it, neither total balances",
   "feedback": "This answer is wrong — you left out the alpha particle; without it, neither total balances."
  }
 ]
}
NUC-021 · medium · application · seq 12 · authored (stage 2); p35 design, real alpha branch At-211 → Bi-207 (A-U14G2-5) · mcq4
Which species completes the equation ²¹¹₈₅At → ²⁰⁷₈₃Bi + ?
⁴₂He KEY
⁰₋₁e
²₄He
A gamma ray
NUC-020 · medium · application · seq 13 · authored (stage 2); p32 design, fresh real isomer Xe-129m · mcq4
An energized ¹²⁹₅₄Xe nucleus sheds a burst of radiation and stays ¹²⁹₅₄Xe. Which decay type is it?
Gamma emission KEY
Alpha decay
Beta decay
No decay fits, because a change that alters neither number is not a decay
NUC-021 · medium · application · seq 14 · authored (stage 2); p33 design — parent position, fresh real beta decay Pd-109 → Ag-109 · text
Find the missing species: ? → ¹⁰⁹₄₇Ag + ⁰₋₁e. Give the missing starting nucleus, in isotope notation. (Atomic numbers: Rh 45, Pd 46, Ag 47, Cd 48.)
Answer: ¹⁰⁹₄₆Pd KEY
also accepted: palladium-109, Palladium-109, Pd-109, ^109_46Pd, 109/46 Pd
wrongValueDiagnostics
[
 {
  "value": "¹⁰⁹₄₈Cd",
  "misconception": "you added 1 instead of adding the beta particle's −1 — the left side must total 47 + (−1) = 46",
  "feedback": "This answer is wrong — you added 1 instead of adding the beta particle's −1; the left side must total 47 + (−1) = 46."
 },
 {
  "value": "¹⁰⁹₄₇Ag",
  "misconception": "you copied the shown nucleus — the missing species must make both totals balance, so its atomic number is 46",
  "feedback": "This answer is wrong — you copied the shown nucleus; the missing species must make both totals balance, so its atomic number is 46."
 },
 {
  "value": "¹⁰⁸₄₆Pd",
  "misconception": "you dropped the mass number — the beta particle's mass number is 0, so the mass stays 109",
  "feedback": "This answer is wrong — you dropped the mass number; the beta particle's mass number is 0, so the mass stays 109."
 }
]
feedback
{
 "keyExplanation": "The missing species sits on the left, so its numbers are the right side's totals. Mass number: 109 + 0 = 109. Atomic number: 47 + (−1) = 46 — palladium. The starting nucleus is ¹⁰⁹₄₆Pd, and the equation reads ¹⁰⁹₄₆Pd → ¹⁰⁹₄₇Ag + ⁰₋₁e.",
 "anticipatedWrong": [
  {
   "value": "¹⁰⁹₄₈Cd",
   "misconception": "you added 1 instead of adding the beta particle's −1 — the left side must total 47 + (−1) = 46",
   "feedback": "This answer is wrong — you added 1 instead of adding the beta particle's −1; the left side must total 47 + (−1) = 46."
  },
  {
   "value": "¹⁰⁹₄₇Ag",
   "misconception": "you copied the shown nucleus — the missing species must make both totals balance, so its atomic number is 46",
   "feedback": "This answer is wrong — you copied the shown nucleus; the missing species must make both totals balance, so its atomic number is 46."
  },
  {
   "value": "¹⁰⁸₄₆Pd",
   "misconception": "you dropped the mass number — the beta particle's mass number is 0, so the mass stays 109",
   "feedback": "This answer is wrong — you dropped the mass number; the beta particle's mass number is 0, so the mass stays 109."
  }
 ]
}
NUC-012 · hard · transfer · seq 15 · authored (stage 2); verdict family, fresh balanced instance (real alpha decay Sm-147 → Nd-143) · mcq4
A student checks the equation ¹⁴⁷₆₂Sm → ¹⁴³₆₀Nd + ⁴₂He. Select the correct verdict.
Balanced — both totals agree. KEY
Unbalanced — the mass-number totals do not match.
Unbalanced — the atomic-number totals do not match.
Unbalanced — neither total agrees.
NUC-013 · hard · application · seq 16 · authored (blind wave 1); fresh real alpha decay Tb-149 → Eu-145 (real 16.7% alpha branch; A-U14G2-5 completion-task class, same shape as At-211 at E#12) — replaces Cf-248 → Cm-244, the same transformation as E#11 and the same parent nuclide E#17 displays (blind cross-item-cue flag) · mcq4
¹⁴⁹₆₅Tb undergoes alpha decay. Which nuclide is left behind? (Atomic numbers: Eu 63, Gd 64, Tb 65, Dy 66, Ho 67.)
¹⁴⁵₆₃Eu KEY
¹⁴⁵₆₅Tb
¹⁴⁹₆₃Eu
¹⁴⁵₆₄Gd
NUC-014 · hard · transfer · seq 17 · authored (stage 2); p14 design, fresh instance (real parent Es-252) · mcq4
A student writes the alpha decay of ²⁵²₉₉Es as ²⁵²₉₉Es → ²⁴⁸₉₈Cf + ⁴₂He. Which check exposes the student's error?
The atomic-number totals do not balance. KEY
The mass-number totals do not balance.
Both totals fail to balance.
The element symbol does not match the new atomic number.
NUC-019 · hard · transfer · seq 18 · authored (stage 2); thinnest-shielding selection class (fluency-2 family, reworded away from corpus) · mcq4
A stream of beta particles has to be stopped completely, using the least barrier material that will do the job. Which of the taught barriers should be chosen?
A thin sheet of aluminum KEY
A sheet of paper
A thick block of lead
No barrier at all — beta particles fade away on their own before reaching anything.
NUC-016 · hard · transfer · seq 19 · authored (stage 2); p20 design, fresh instance Pm-151 (real β−) · mcq4
Promethium-151 (¹⁵¹₆₁Pm) undergoes beta decay, and the nuclide left behind still has mass number 151. Why does the mass number stay at 151 even though a particle has left the nucleus?
Nothing the mass number counts has left — the electron sits outside the proton-and-neutron tally. KEY
The nucleus pulls in a replacement particle from outside, and that arrival keeps the count at 151.
The mass number really falls to 150, because every departing particle lowers it.
The electron's mass exactly equals a neutron's mass, so the total is unchanged.
NUC-017 · hard · application · seq 20 · authored (stage 2); p23 design + the wrote-alpha-for-beta misconception class (real β− parent Ru-105) · mcq4
In a homework answer, the beta decay of ¹⁰⁵₄₄Ru is written as ¹⁰⁵₄₄Ru → ¹⁰¹₄₂Mo + ⁴₂He. Where does the checking routine catch the mistake?
The equation shows the wrong particle for beta decay. KEY
The mass-number totals do not balance.
The atomic-number totals do not balance.
Neither total balances.
NUC-021 · medium · application · seq 21 · authored fresh (stage 2); real decays Th-221 (α), Cu-66 (β), Yb-175 (β) · frq
Three nuclear equations each have one species missing. Use the balancing totals to find every missing piece, and show your reasoning.
Three nuclear equations each have one species missing. Use the balancing totals to find every missing piece, and show your reasoning. (a) ²²¹₉₀Th → ²¹⁷₈₈Ra + ? — work out the missing species' mass number and bottom number from the two totals, name the species, and justify your choice using both totals. (b) ⁶⁶₂₉Cu → ? + ⁰₋₁e — work out the missing nucleus and give it with its element name and mass number. (Atomic numbers: Ni 28, Cu 29, Zn 30, Ga 31.) (c) ? → ¹⁷⁵₇₁Lu + ⁰₋₁e — the starting nucleus is missing; work out both of its numbers and give it with its element name and mass number. (Atomic numbers: Tm 69, Yb 70, Lu 71, Hf 72.)
Part a. ²²¹₉₀Th → ²¹⁷₈₈Ra + ? — work out the missing species' mass number and bottom number from the two totals, name the species, and justify your choice using both totals.
Model: Mass numbers: 221 = 217 + ?, so the missing species carries mass number 4. Bottom numbers: 90 = 88 + ?, so its bottom number is 2. Mass number 4 with bottom number 2 is the alpha particle — 2 protons and 2 neutrons; both totals balance only with it.
Part b. ⁶⁶₂₉Cu → ? + ⁰₋₁e — work out the missing nucleus and give it with its element name and mass number. (Atomic numbers: Ni 28, Cu 29, Zn 30, Ga 31.)
Model: The beta particle adds 0 to the mass total, so the missing nucleus keeps mass number 66. Its atomic number must satisfy 29 = ? + (−1), so it is 30 — zinc. The missing nucleus is zinc-66.
Part c. ? → ¹⁷⁵₇₁Lu + ⁰₋₁e — the starting nucleus is missing; work out both of its numbers and give it with its element name and mass number. (Atomic numbers: Tm 69, Yb 70, Lu 71, Hf 72.)
Model: The missing species sits on the left, so both of its numbers are the right-side totals: mass 175 + 0 = 175, atomic 71 + (−1) = 70. The element with atomic number 70 is ytterbium, so the starting nucleus is ytterbium-175.
Full model answer. (a) Mass numbers: 221 = 217 + ?, so the missing species carries mass number 4. Bottom numbers: 90 = 88 + ?, so its bottom number is 2. Mass number 4 with bottom number 2 is the alpha particle — 2 protons and 2 neutrons; both totals balance only with it. (b) The beta particle adds 0 to the mass total, so the missing nucleus keeps mass number 66. Its atomic number must satisfy 29 = ? + (−1), so it is 30 — zinc. The missing nucleus is zinc-66. (c) The missing species sits on the left, so both of its numbers are the right-side totals: mass 175 + 0 = 175, atomic 71 + (−1) = 70. The element with atomic number 70 is ytterbium, so the starting nucleus is ytterbium-175.

End of Topic Test: Half-life (u14-t3 · 5 forms × 21 items · 105 total)

David's notes for James:
full notes file
# u14-t3 — notes/queries from David's side (U14-G3)

1. FRQ COMPOSITION - frq_per_form = 1 (your gate data's frq_per_form=1 concurs; confirm): the wave's calc-heavy FRQ split was EVALUATED AND NOT APPLIED - the predicate honestly fails on both prongs: (1) half-life/nuclear math is NOT in QB-v2 sec.4's named calculation-heavy list ('stoichiometry, gas laws, molarity/dilution, calorimetry, mole conversions'); (2) the one-FRQ-per-production-construct test (U7-G2/U12-G3 precedent) finds only ONE written routine invisible to numeric-entry grading: the NUC-025 inverse chain (count the halvings -> time = number of halvings x half-life -> result with unit, plus the fixed-halving justification). The NUC-024 forward routine's only written line is the counting division (your specNotes: 'the counting division as the only equation line'), so a second FRQ would re-measure the counted-halving production the seq 8/9 numeric rows already capture with scaffolds. FRQ homed at the NUC-025 capstone, terminal at seq 21 (D6). D5: min(20, 6 x 5) = 20 -> no scaling; CONSEQUENCE (U11-G2 packaged precedent for 5-lesson scopes): 4 objective rows per lesson, above the 2-3 multi-case guidance, and capstone NUC-025 carries 4 objective rows + the FRQ. Mix 3 recall / 13 application / 4 transfer; interactions per form 10 mcq + 9 numeric ENTRY + 1 text + 1 FRQ (HS rule: quant behaviour = numeric entry, never numeric-answer MCQ; NUC-025 extraNotes concurs).
2. COURSE-WIDE INSTANCE RULE + U14 PHRASING PACK (binding, wave 6) - nuclear chemistry is the topic, so radioactivity language stays curricular and clinical exactly as the lessons do: medical tracers, radiopharmacy production runs, shielded stores, sealed lab vials, testing laboratories, radon awareness (your verbatim demo seed). NEVER uranium/plutonium/enrichment/reactors/weapons, no dose/harm framing. A stricter-than-rule sweep also swapped the benign clinical word 'dose' out of every item that had it (vial/batch/sample at stage 2; B#9/D#8/E#1 at the banned-lexicon hardening). Packaging re-sweep over forms_final AND this export body: ZERO student-facing hits on every hard-banned token (uranium/plutonium/thorium/radium/polonium/enrich/reactor/weapon/fissile/fission/meltdown/fallout/bomb/warhead/dose). Zero content-filter events across every authoring/blind/sol round - the clinical phrasing held.
3. SEED USAGE - all 15 pool seeds placed (15/15): 6 VERBATIM (p4@A#7, p5@A#6, p9@A#11, p10@A#18, p11@B#11, p13@A#19 - incl. all 3 demo_curated) + 9 FRESHENED under the strict seed ruling (p0,p1,p2,p3,p6,p7,p8,p12,p14) with constructs + misconception sets preserved. Form A carries 12 seed-derived objective cells; B#8/B#11 and C#8 carry the rest; every other cell is fresh-authored (90 of 105). demo_curated d0-d2 = pool p9/p10/p11 (deduped, dual refs cited). prod_seeds is empty and the 15 in-lesson fluency prods are student-seen -> spares/reference only, never test items. Cold list ignored (standing answer #3).
4. SEED FRESHENING RATE IS STRUCTURAL, NOT STYLISTIC (disclosure): your five per-lesson pools were authored independently and share isotopes/values with each other and with the articles - e.g. all three NUC-024 gate seeds collide with a demo_curated seed's isotope/value family (cobalt-60/5.3 p6-vs-p10; radon-222/3.8/11.4 p7-vs-p11; the 72->36->18->9 chain p8-vs-p9). DEMO-PRIORITY RULING (recorded): where a plain gate seed and a demo_curated seed claim the same family, the DEMO is kept byte-verbatim and the plain seed is freshened - demo_curated is your hand-picked exemplar set.
5. THE 9 SEED FRESHENINGS (dispositions to confirm; structure + misconception sets preserved, all fields swept QB 3.9, every fresh half-life real at quoted precision): (a) p0@A#4 strontium-90/29 y (verbatim in NUC-024 fluency) -> zinc-65, 244 d; (b) p1@A#10 technetium-99 (99 = NUC-025 rule-line number) -> tin-113, metal-vs-compound framing kept, value-withheld fixedness framing kept; (c) p2@A#17 phosphorus-32/14.3 d (three fluency corpora) -> osmium-185, 93.6 d, claim + all three distractors kept with derived values recomputed; (d) p3@A#5 cobalt-60 (name digits '60' = corpus number; cobalt-60's home = demo p10 at A#18) -> cerium-141, count 7 -> 1/128, misconception set verbatim; (e) p6@A#8 cobalt-60/5.3 (demo p10 outranks) -> chromium-51, 27.7 d, 136 ug, 83.1 d -> 17 ug; (f) p7@B#8 radon-222/3.8/11.4 (demo p11 outranks; 222/3.8 also NUC-022 WE corpus) -> xenon-133 sealed vial, 5.2 d, 104 ug, 15.6 d -> 13 ug; (g) p8@C#8 the 72->9 chain IS demo p9's iron-59 chain -> lutetium-177 therapy sample, 6.6 d, 216 ug, 19.8 d -> 27 ug; (h) p12@A#13 start mass 200 g (NUC-026 WE + NUC-024 WE corpus number) -> 240 g curve, iridium-192 + the taught 74 d half-life KEPT ('must not change' list), half-of-start-not-half-of-axis trap kept live; (i) p14@A#14 start 80 mg (NUC-024 rule-line number) -> 112 mg, hydrogen-3 + taught 12.3 y half-life + half-life-multiple axis ticks kept.
6. FIVE RECORDED ADJUDICATED INSTANCE FAMILIES ON YOUR VERBATIM SEEDS (wrapper-enforced; the shared validator was NEVER weakened; confirm): your three demo seeds + the p13 gate seed are kept byte-verbatim, and their taught constants collide with spec text by design - excused by slot-enumerated families in gate_config.json: (1) 'james-demo-60' {60} at A#18/B#11 (cobalt-60 name digits vs your 60 ug start vs the NUC-026 rule-line 60 g - the scanner cannot see the semantic difference; no authored item uses 60 anywhere); (2) 'james-demo-p10-ladder-16' {16} at A#18 (your specNotes: 'gives the remainder as a fraction (1/16) for transfer' - the taught NUC-023 WE1 ladder rung); (3) 'james-demo-p11-radon-constants' {222, 3.8, 11.4} at B#11, carrier 'radon' (taught 'must not change' constants + the forced 3 x 3.8 arithmetic); (4) 'james-p13-ladder-25' {25} at A#19 (the taught ladder percent 100/2^2, on-screen yTick of every percent curve); (5) 'james-p13-iodine125' material 'iodine' at A#19 (your seed deliberately uses taught iodine-125 vs the WE's iodine-131 - same element word, different taught nuclide). The gate-local wrapper reruns the UNTOUCHED shared validator (11/12 clean as shipped), recomputes the V-T7 collision set with a parity guard (15 vs 15 MATCH), and exits 0 only because every fail line is family-covered - 0 uncovered.
7. TASK-IDIOM + FIGURE-CONVENTION WHITELISTS (A2/A4 classes, no instance relief; confirm): the NUC-026 fixed figure-stem conventions ('The figure shows the decay curve of ...', 'plotted as the percent of the sample remaining', the two Read-from-the-curve frames) and the course's half-life task idioms ('has a half-life of', 'whose half-life is', the fraction-ladder frames) are recorded convention phrases - every NUC-026 fluency AND gate item in the course opens with them and the pilot directive mandates the same frame on fresh curves. Isotopes and values inside them still scan in full. ALSO A-U14G3-4: 'Give your answer to the nearest whole number.' + the four unit-bearing stem tails (remains, in micrograms/nanograms/grams/milligrams?) - fixed precision instruction appended to every seq-8/9 numeric stem after sol flagged missing precision statements; pure task language, identical across the family by design.
8. A#7 SEED REVERT + A#16<->B#16 SWAP (construct-exposure fix, confirm): blind round 1 (both reviewers) caught that A#7's option set exposed 7/8 = A#16's exact answer. Candidate patches to A#7's counts hit the taught 1/32 / 1/64 ladder values (V-T7 refused them - honest resolution instead): A#7 REVERTED byte-identical to your verbatim seed p4 and A#16 <-> B#16 swapped full payloads, decoupling the pair (A#16 is now the 2-half-lives/75% case; form B exposes no 7/8 anywhere). A#15's count moved 4 -> 5 (it was supplying A#6's 4-half-life routine; form-A counts now 7/4/3/5/2, all distinct).
9. CONSTRUCT-BYPASS FIXES ON FRESH ITEMS (blind catches, disclosure): C#1 (holmium-166, 26.8 h recall row) supplied C#19's curve-read constant - 2 x 26.8 = 53.6 h was computable WITHOUT the figure -> C#1 re-minted to arsenic-77/38.8 h (gold-198 and rhenium-186 were tried first and honestly rejected by the validator: gold-198 is a taught spec instance, 186 collided elsewhere). Same class swept deterministically: B#8's xenon-133/5.2 d supplied B#19's read -> B#19 re-minted to dysprosium-159 (144.4 d curve, 433.2 d read).
10. NUMERIC CONTRACT (confirm): half-life answers are exact by construction (whole-number halving chains, exact time division - your asset policy), so NO sig-fig sentences (all your seeds carry sig_figs_sentence_appended=false and concur); tolerance 0 on exact-arithmetic rows, grid-read tolerances on curve rows (your seed tolerances kept, e.g. 0.05 on the demo inverse rows, +/-1 to +/-3 mg/day on curve reads); unit lives in answer.unit; display IS the graded value; integer:true where a whole-number display would otherwise be ambiguous; the two verbatim demo rows carry a gradingNote recording that sigFigs states the display's digit count, not a rounding demand. sol's sigfig-alternate sweep dropped every '<display>.0' acceptedAlternate (15 items) and one leftover 1000x-wrong alternate after a unit downscale (E#8 '59 ug'). wrongValueDiagnostics carried per numeric item from the authored anticipated-wrong sets.
11. ACTIVITY-MAGNITUDE REALISM - COURSE-LEVEL STYLE QUESTION FLAGGED FOR YOU AND DAVID (no action taken beyond sol's bar): sol (authoritative) failed 11 items for gram-scale samples of short-lived isotopes being unrealistically high-activity and drove unit downscales (g/mg -> ug, A#21's FRQ -> ng with a production-run reframe; 4 clinical framings later reframed to production/supplier/shielded-store contexts per sol's own guidance). BUT the lessons themselves teach with gram-scale samples (NUC-026 rule line: 60 g sodium-24) and YOUR verbatim seeds do too (A#11 iron-59 at 72 g -> 9 g kept verbatim; B#11's 60 ug is already micro-scale). Blind reviewers still advisory-flag ug/ng quantities as high-activity; quantitative dose/activity math is barred by the phrasing pack, so this cannot be resolved in-item. The verbatim seed scales were KEPT; fresh items sit at sol-passed scales. Say the word if you want a single course-wide magnitude convention instead.
12. SEQ-16 REPRESENTATION CALL (recorded judgment, confirm): the percent-DECAYED row renders WE2's decayed-complement idea in the gate-3 percent representation ('completes N half-lives ... what percent of its starting nuclei has decayed') - both are the lesson's own taught extensions; the word-count + percent/starting vocabulary also keep the row 4-gram-disjoint from the seq-6 percent-REMAINING family.
13. BLIND-QC LEDGER (disclosure): 7 rounds, 14 reviewer tags (r1 = gpt-5.6-sol blind role, r2 = gemini, fresh tags each re-round), decay-curve figure items rendered with full grid-crossing lists (R23: exactly what a sighted student sees; a gate-local augmenter fixed the _shared fig_text gap BEFORE round 1 - recommended as a _shared addition). Round 1 (105 items x 2): key picks 100/100, 0 hard fails, 61 advisory -> 62-edit fix wave (the construct fixes above + B#15/D#1 distractor upgrades + a deterministic dash-parity style sweep: 13 of 50 mcqs carried a dash ONLY in the key - 30 distractor edits + length rebalances). Rounds 2-7 on changed items: 0 hard fails except round 3's C#14 - BOTH reviewers answered 0.062 mg = 62 ug, exposing a stem unit-typo my own downscale had left ('in mg' with a ug figure); fixed + residual-unit sweep over every downscaled item, re-blind clean. All 55 keyless slots (text seq 5, numeric seqs 6/8/9/11/13/14/16/18/19, FRQ 21) graded per round in frq_verdicts.json - every final verdict match with justification.
14. SOL-QC LEDGER (disclosure): authoritative gpt-5.6-sol loops 1-4 went 16 -> 8 -> 5 -> 0 FAILs, all content-fixed: the activity-realism class above; the precision-statement class (A-U14G3-4); unit-WORD leftovers after downscales (A#9/D#9 feedbacks still said milligrams/grams - QB 3.9's recurrent class, swept); D#7 distractor internal logic; E#3 method-validity reframe (its 'always' distractor was only conditionally wrong); E#17 reworked twice (sol ruled first the metaphor, then the stochastic facet, outside NUC-022's taught skill -> final form = grinding/subdivision fixedness claim); E#4/E#6 feedback voice; contrast units microgram/milligram. Final ledger 105 pass / 0 fail, loop-4 raw coverage verified item-by-item (no silent skips). 7 pass-with-minor notes recorded in solqc_report.md (anticipated-wrong rounding notes on B#8/B#9, curve-read precision notes, E#7's softer distractor 2).
15. ACCEPTED SURVIVOR CLASSES (recorded, confirm-if-you-care): (1) single-skill recall->application overlap - recall rows state the taught routine the calculation rows apply; composition REQUIRES 3 recall rows and the routine is in the reviewers' taught-conventions block; the sharp instances (shared counts/constants/option exposure) were all FIXED, the generic class is inherent to a one-topic gate; (2) FRQ scaffold-by-design - B#21/E#21 stems supply the worded relation because the relation IS the assessed production per NUC-025's taught frame; (3) grid-crossing readability on the curve rows - anchor points land on readable crossings by design (deterministic grading, tolerances carried); (4) course-register absolutes on the fixedness rule (E#10 'at any pressure', C#17/E#3 emphasis) - sol passed all with course-local authority.
16. QC LEDGER (disclosure): deterministic validators 11/12 PASS as shipped (V-T6 numeric-realism PASSES on all 45 live numeric slots; the only non-pass is V-T7's 15 pre-flagged collision lines on your three byte-verbatim demo seeds + p13, 100% covered by the recorded families - parity guard 15/15 MATCH, 0 uncovered, wrapper exit 0); stage-2 content patching ran BEFORE any adjudication (V-T7 48 -> 15 by rewording/re-minting, validator never weakened); blind = 7 rounds, 0 open hard fails; sol loops 16 -> 8 -> 5 -> 0; one WARN line (form C mercury at seqs 4/18, non-adjacent, routed to blind review and cleared); substance/number ledger enforced: one (form,seq) home slot per stem-visible number >12 and per isotope, same-form reuse only where design-legal and recorded.

Form A

NUC-022 · easy · recall · seq 1 · authored:U14-G3 stage 2 (fresh definitional read; fluency-1 class, fresh instance) · mcq4
Erbium-169 is used in some joint treatments. Its half-life is 9.4 days. Which statement gives the meaning of that half-life?
In any sample of erbium-169, half of the nuclei decay over 9.4 days. KEY
Every erbium-169 nucleus decays exactly 9.4 days after it forms.
After 9.4 days, all of the erbium-169 in a sample has decayed.
A sample of erbium-169 must be 9.4 days old before any nucleus can decay.
NUC-024 · easy · recall · seq 2 · authored:U14-G3 stage 2 (routine recognition, first-step facet) · mcq4
A question gives a radioactive sample's starting amount, the isotope's half-life, and how much time passes. In the taught routine for finding the amount that remains, what is the FIRST calculation?
Divide the time passed by the half-life, to count the half-lives. KEY
Divide the starting amount by the half-life.
Multiply the time passed by the half-life — combining the two times gives the count.
Subtract the half-life from the time passed — the leftover time is the count.
NUC-026 · easy · recall · seq 3 · authored:U14-G3 stage 2 (procedure recognition, half-life read) · mcq4
To read an isotope's half-life from its decay curve, what do you look for?
The time directly below the point where the amount has fallen to half its starting value. KEY
The time sitting exactly halfway along the time axis, wherever the curve happens to be.
The time where the curve reaches zero.
The height of the curve at the end of the graph.
NUC-022 · medium · application · seq 4 · seed:U14-G3.pool[0] (NUC-022 gateItems, James) - MUST_FRESHEN_INSTANCE (strontium-90/29 y = NUC-024 fluency corpus; construct + distractor set kept, re-minted to zinc-65/244 d) · mcq4
Zinc-65's half-life is 244 days. Half of a sample's zinc-65 nuclei decay during the first 244 days. How long does it take for half of the REMAINING zinc-65 nuclei to decay?
Another 244 days — every half-life of zinc-65 is the same length. KEY
Less than 244 days — the sample is smaller now.
More than 244 days — the nuclei that survived the first 244 days are the tougher ones.
It cannot be predicted once the first half has decayed.
NUC-023 · medium · application · seq 5 · seed:U14-G3.pool[3] (NUC-023 gateItems, James) - MUST_FRESHEN_INSTANCE (cobalt-60 -> cerium-141; count 7, answer, misconceptions kept verbatim) · text
A sample of cerium-141 sits through 7 half-lives. What fraction of the original cerium-141 nuclei remains?
Answer: 1/128 KEY
also accepted: 1/128, 0.0078125
wrongValueDiagnostics
[
 {
  "value": "1/7",
  "misconception": "you divided the original amount by the number of half-lives — seven half-lives means seven halvings",
  "feedback": "This answer is wrong — you divided the original amount by the number of half-lives. Seven half-lives means seven halvings: 1/2 down to 1/128."
 },
 {
  "value": "1/64",
  "misconception": "you halved one time too few — the seventh halving takes 1/64 to 1/128",
  "feedback": "This answer is wrong — you halved one time too few. The seventh halving takes 1/64 to 1/128."
 },
 {
  "value": "0",
  "misconception": "you emptied the sample — each half-life removes only half of what is left",
  "feedback": "This answer is wrong — you emptied the sample. Each half-life removes only half of what is left, so some always remains: 1/128."
 }
]
feedback
{
 "keyExplanation": "Halve once per half-life: 1/2, 1/4, 1/8, 1/16, 1/32, 1/64, 1/128 — because after each half-life, half of the nuclei that remain decay. After 7 half-lives, 1/128 of the original cerium-141 nuclei remain.",
 "anticipatedWrong": [
  {
   "value": "1/7",
   "misconception": "you divided the original amount by the number of half-lives — seven half-lives means seven halvings",
   "feedback": "This answer is wrong — you divided the original amount by the number of half-lives. Seven half-lives means seven halvings: 1/2 down to 1/128."
  },
  {
   "value": "1/64",
   "misconception": "you halved one time too few — the seventh halving takes 1/64 to 1/128",
   "feedback": "This answer is wrong — you halved one time too few. The seventh halving takes 1/64 to 1/128."
  },
  {
   "value": "0",
   "misconception": "you emptied the sample — each half-life removes only half of what is left",
   "feedback": "This answer is wrong — you emptied the sample. Each half-life removes only half of what is left, so some always remains: 1/128."
  }
 ]
}
NUC-023 · medium · application · seq 6 · seed:U14-G3.pool[5] (NUC-023 gateItems, James) - VERBATIM (field mapping; acceptedAlternates added per V-T6 contract) · numeric
What percentage of the original radioactive nuclei in a sample remains after 4 half-lives?
Answer: 6.25 % KEY
also accepted: 6.25%, 1/16 as a percent
wrongValueDiagnostics
[
 {
  "value": 25,
  "misconception": "you divided 100% by the number of half-lives — four half-lives means four halvings of what remains",
  "feedback": "This answer is wrong — you divided 100% by the number of half-lives. Four half-lives means four halvings: 100 → 50 → 25 → 12.5 → 6.25."
 },
 {
  "value": 12.5,
  "misconception": "you halved one time too few — the fourth halving takes 12.5% down to 6.25%",
  "feedback": "This answer is wrong — you halved one time too few. The fourth halving takes 12.5% down to 6.25%."
 },
 {
  "value": 0.0625,
  "misconception": "you gave the fraction instead of the percentage — 1/16 of the original is 6.25%",
  "feedback": "This answer is wrong — you gave the fraction instead of the percentage. 1/16 of the original is 6.25%."
 }
]
feedback
{
 "keyExplanation": "Halve 100% once per half-life: 100 → 50 → 25 → 12.5 → 6.25. Because after each half-life, half of the nuclei that remain decay. 6.25% of the original nuclei remain.",
 "anticipatedWrong": [
  {
   "value": 25,
   "misconception": "you divided 100% by the number of half-lives — four half-lives means four halvings of what remains",
   "feedback": "This answer is wrong — you divided 100% by the number of half-lives. Four half-lives means four halvings: 100 → 50 → 25 → 12.5 → 6.25."
  },
  {
   "value": 12.5,
   "misconception": "you halved one time too few — the fourth halving takes 12.5% down to 6.25%",
   "feedback": "This answer is wrong — you halved one time too few. The fourth halving takes 12.5% down to 6.25%."
  },
  {
   "value": 0.0625,
   "misconception": "you gave the fraction instead of the percentage — 1/16 of the original is 6.25%",
   "feedback": "This answer is wrong — you gave the fraction instead of the percentage. 1/16 of the original is 6.25%."
  }
 ]
}
NUC-023 · medium · application · seq 7 · seed:U14-G3.pool[4] (NUC-023 gateItems, James) - VERBATIM (field mapping only) · mcq4
After 3 half-lives, what fraction of a sample's original radioactive nuclei has DECAYED?
7/8 KEY
1/8
3/8
1/2
NUC-024 · medium · application · seq 8 · seed:U14-G3.pool[6] (NUC-024 gateItems, James) - MUST_FRESHEN_INSTANCE (cobalt-60/5.3/15.9 collide with kept-verbatim demo p10; 3-halving construct + misconception set kept; re-minted to chromium-51) | sol-3: hospital storeroom -> production facility (clinical-scale realism) · numeric
An isotope production facility logs a 136 µg chromium-51 batch. Chromium-51's half-life is 27.7 days. After the batch sits in a shielded store for 83.1 days, what mass of chromium-51 remains, in micrograms? Give your answer to the nearest whole number.
Answer: 17 µg KEY
also accepted: 17 µg
wrongValueDiagnostics
[
 {
  "value": 68,
  "misconception": "you halved only once — 83.1 days holds THREE 27.7-day half-lives",
  "feedback": "This answer is wrong — you halved only once. 83.1 days holds THREE 27.7-day half-lives: 136 → 68 → 34 → 17."
 },
 {
  "value": 45.33,
  "misconception": "you divided the starting amount by the number of half-lives — three half-lives means three halvings, not division by 3",
  "feedback": "This answer is wrong — you divided the starting amount by the number of half-lives. Three half-lives means three halvings: 136 → 68 → 34 → 17."
 },
 {
  "value": 34,
  "misconception": "you halved one time too few — the third halving takes 34 µg down to 17 µg",
  "feedback": "This answer is wrong — you halved one time too few. The third halving takes 34 µg down to 17 µg."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nstarting amount = 136 µg, half-life = 27.7 days, time passed = 83.1 days\nWrite down the equation:\nnumber of half-lives = time passed ÷ half-life\nSubstitute in the values, and calculate:\nnumber of half-lives = 83.1 ÷ 27.7 = 3\nHalve the starting amount three times: 136 → 68 → 34 → 17\n17 µg of chromium-51 remains.",
 "anticipatedWrong": [
  {
   "value": 68,
   "misconception": "you halved only once — 83.1 days holds THREE 27.7-day half-lives",
   "feedback": "This answer is wrong — you halved only once. 83.1 days holds THREE 27.7-day half-lives: 136 → 68 → 34 → 17."
  },
  {
   "value": 45.33,
   "misconception": "you divided the starting amount by the number of half-lives — three half-lives means three halvings, not division by 3",
   "feedback": "This answer is wrong — you divided the starting amount by the number of half-lives. Three half-lives means three halvings: 136 → 68 → 34 → 17."
  },
  {
   "value": 34,
   "misconception": "you halved one time too few — the third halving takes 34 µg down to 17 µg",
   "feedback": "This answer is wrong — you halved one time too few. The third halving takes 34 µg down to 17 µg."
  }
 ]
}
NUC-024 · medium · application · seq 9 · authored:U14-G3 stage 2 (fresh forward 2-halving, hour scale) | sol-3: cardiac-clinic framing -> supplier production lot · numeric
A radiopharmaceutical supplier holds a 348 µg production lot of thallium-201, whose half-life is 73 hours. What mass of thallium-201 remains after 146 hours, in micrograms? Give your answer to the nearest whole number.
Answer: 87 µg KEY
also accepted: 87 µg
wrongValueDiagnostics
[
 {
  "value": 174,
  "misconception": "you halved only once — 146 hours holds TWO 73-hour half-lives",
  "feedback": "This answer is wrong — you halved only once. 146 hours holds TWO 73-hour half-lives: 348 → 174 → 87."
 },
 {
  "value": 43.5,
  "misconception": "you halved one time too many — two half-lives means exactly two halvings",
  "feedback": "This answer is wrong — you halved one time too many. Two half-lives means exactly two halvings: 348 → 174 → 87."
 },
 {
  "value": 202,
  "misconception": "you subtracted the hours from the micrograms — amounts and times never subtract; count the half-lives, then halve",
  "feedback": "This answer is wrong — you subtracted the hours from the micrograms. Amounts and times never subtract; count the half-lives, then halve: 87 µg."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nstarting amount = 348 µg, half-life = 73 hours, time passed = 146 hours\nWrite down the equation:\nnumber of half-lives = time passed ÷ half-life\nSubstitute in the values, and calculate:\nnumber of half-lives = 146 ÷ 73 = 2\nHalve the starting amount twice: 348 → 174 → 87\n87 µg of thallium-201 remains.",
 "anticipatedWrong": [
  {
   "value": 174,
   "misconception": "you halved only once — 146 hours holds TWO 73-hour half-lives",
   "feedback": "This answer is wrong — you halved only once. 146 hours holds TWO 73-hour half-lives: 348 → 174 → 87."
  },
  {
   "value": 43.5,
   "misconception": "you halved one time too many — two half-lives means exactly two halvings",
   "feedback": "This answer is wrong — you halved one time too many. Two half-lives means exactly two halvings: 348 → 174 → 87."
  },
  {
   "value": 202,
   "misconception": "you subtracted the hours from the micrograms — amounts and times never subtract; count the half-lives, then halve",
   "feedback": "This answer is wrong — you subtracted the hours from the micrograms. Amounts and times never subtract; count the half-lives, then halve: 87 µg."
  }
 ]
}
NUC-022 · medium · application · seq 10 · seed:U14-G3.pool[1] (NUC-022 gateItems, James) - MUST_FRESHEN_INSTANCE (technetium-99's 99 = NUC-025 rule-line corpus; construct + distractors kept; re-minted to tin-113 with its real 115-day half-life stated) · mcq4
One sample holds pure tin-113 metal; another holds the same tin-113 isotope bound into a chemical compound. Tin-113's half-life is 115 days. How do the two samples' half-lives compare?
They are identical — chemical form does not change a half-life. KEY
The compound's is shorter — chemical bonds strain the nucleus.
The compound's is longer — the surrounding atoms shield the nucleus.
They are identical only if the two samples have equal masses.
NUC-025 · medium · application · seq 11 · seed:U14-G3.demo_curated[0] = pool[9] (NUC-025 gateItems, James demo) - VERBATIM (field mapping only; corpus-clean) · numeric
Iron-59 has a half-life of 44.5 days. A sample of iron-59 has decayed from 72 g down to 9 g. How much time has passed, in days?
Answer: 133.5 days KEY
also accepted: 133.5 days, 133.5 d
wrongValueDiagnostics
[
 {
  "value": 356,
  "misconception": "you used the ratio 72 ÷ 9 = 8 as the number of halvings — 72 g → 36 g → 18 g → 9 g is 3 halvings",
  "feedback": "This answer is wrong — you used the ratio 72 ÷ 9 = 8 as the number of halvings. 72 g → 36 g → 18 g → 9 g is 3 halvings: 3 × 44.5 = 133.5 days."
 },
 {
  "value": 89,
  "misconception": "you stopped counting one halving early — 72 g → 36 g → 18 g → 9 g is 3 halvings, not 2",
  "feedback": "This answer is wrong — you stopped counting one halving early. 72 g → 36 g → 18 g → 9 g is 3 halvings, not 2: 133.5 days."
 }
]
feedback
{
 "keyExplanation": "Count the halvings: 72 g → 36 g → 18 g → 9 g.\nThe sample has halved 3 times.\ntime passed = number of halvings × half-life\ntime passed = 3 × 44.5 days\ntime passed = 133.5 days",
 "anticipatedWrong": [
  {
   "value": 356,
   "misconception": "you used the ratio 72 ÷ 9 = 8 as the number of halvings — 72 g → 36 g → 18 g → 9 g is 3 halvings",
   "feedback": "This answer is wrong — you used the ratio 72 ÷ 9 = 8 as the number of halvings. 72 g → 36 g → 18 g → 9 g is 3 halvings: 3 × 44.5 = 133.5 days."
  },
  {
   "value": 89,
   "misconception": "you stopped counting one halving early — 72 g → 36 g → 18 g → 9 g is 3 halvings, not 2",
   "feedback": "This answer is wrong — you stopped counting one halving early. 72 g → 36 g → 18 g → 9 g is 3 halvings, not 2: 133.5 days."
  }
 ]
}
NUC-025 · medium · application · seq 12 · authored:U14-G3 stage 2 (count read; ratio-8 trap) · mcq4
A radioactive sample has decayed from 304 g down to 38 g. How many half-lives have passed?
3 KEY
8
2
4
NUC-026 · medium · application · seq 13 · seed:U14-G3.pool[12] (NUC-026 gateItems, James) - MUST_FRESHEN_INSTANCE (start 200 g = corpus; re-minted to 240 g; iridium-192/74 d + half-of-start trap kept) · numeric
The figure shows the decay curve of a sample of iridium-192, which starts at 240 g. Read the half-life of iridium-192 from the curve, in days.
FIGURE (decay-curve · stimulus) — isotope: "iridium-192" · yLabel: "mass of iridium-192 remaining (g)" · yTicks: [0, 30, 60, 90, 120, 150, 180, 210, 240] · xLabel: "time (days)" · xTicks: [0, 20, 40, 60, 80, 100, 120, 140, 160] · minorGridEveryDays: 2 · curvePoints: [[0, 240], [74, 120], [148, 60]] · style: "smooth falling curve on a light labeled grid with fine minor gridlines, no read-off guide lines drawn"
raw spec
{
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "decay-curve",
  "isotope": "iridium-192",
  "yLabel": "mass of iridium-192 remaining (g)",
  "yTicks": [
   0,
   30,
   60,
   90,
   120,
   150,
   180,
   210,
   240
  ],
  "xLabel": "time (days)",
  "xTicks": [
   0,
   20,
   40,
   60,
   80,
   100,
   120,
   140,
   160
  ],
  "minorGridEveryDays": 2,
  "curvePoints": [
   [
    0,
    240
   ],
   [
    74,
    120
   ],
   [
    148,
    60
   ]
  ],
  "style": "smooth falling curve on a light labeled grid with fine minor gridlines, no read-off guide lines drawn"
 }
}
Answer: 74 days KEY
also accepted: 74 days, 74 d
wrongValueDiagnostics
[
 {
  "value": 148,
  "misconception": "you read the time for the mass to fall to a quarter of the start — that is two half-lives, not one",
  "feedback": "This answer is wrong — you read the time for the mass to fall to a quarter of the start. That is two half-lives; one half-life is 74 days."
 },
 {
  "value": 80,
  "misconception": "you took the halfway point of the time axis instead of the point where the MASS has halved",
  "feedback": "This answer is wrong — you took the halfway point of the time axis. Read where the MASS has halved: 120 g at 74 days."
 }
]
feedback
{
 "keyExplanation": "Half of the starting amount: half of 240 g is 120 g. The curve reaches 120 g at 74 days. The half-life of iridium-192 is 74 days.",
 "anticipatedWrong": [
  {
   "value": 148,
   "misconception": "you read the time for the mass to fall to a quarter of the start — that is two half-lives, not one",
   "feedback": "This answer is wrong — you read the time for the mass to fall to a quarter of the start. That is two half-lives; one half-life is 74 days."
  },
  {
   "value": 80,
   "misconception": "you took the halfway point of the time axis instead of the point where the MASS has halved",
   "feedback": "This answer is wrong — you took the halfway point of the time axis. Read where the MASS has halved: 120 g at 74 days."
  }
 ]
}
NUC-026 · medium · application · seq 14 · seed:U14-G3.pool[14] (NUC-026 gateItems, James) - MUST_FRESHEN_INSTANCE (start 80 mg = NUC-024 rule-line corpus; re-minted to 112 mg; hydrogen-3/12.3 + read construct + misconception set kept) · numeric
The figure shows the decay curve of a 112 mg sample of hydrogen-3. Read from the curve the mass remaining at 24.6 years, in mg.
FIGURE (decay-curve · stimulus) — isotope: "hydrogen-3" · yLabel: "mass of hydrogen-3 remaining (mg)" · yTicks: [0, 14, 28, 42, 56, 70, 84, 98, 112] · xLabel: "time (years)" · xTicks: [0, 12.3, 24.6, 36.9] · curvePoints: [[0, 112], [12.3, 56], [24.6, 28], [36.9, 14]] · style: "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
raw spec
{
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "decay-curve",
  "isotope": "hydrogen-3",
  "yLabel": "mass of hydrogen-3 remaining (mg)",
  "yTicks": [
   0,
   14,
   28,
   42,
   56,
   70,
   84,
   98,
   112
  ],
  "xLabel": "time (years)",
  "xTicks": [
   0,
   12.3,
   24.6,
   36.9
  ],
  "curvePoints": [
   [
    0,
    112
   ],
   [
    12.3,
    56
   ],
   [
    24.6,
    28
   ],
   [
    36.9,
    14
   ]
  ],
  "style": "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
 }
}
Answer: 28 mg KEY
also accepted: 28 mg
wrongValueDiagnostics
[
 {
  "value": 56,
  "misconception": "you read the mass at 12.3 years instead of 24.6 years",
  "feedback": "This answer is wrong — you read the mass at 12.3 years. At 24.6 years the curve sits at 28 mg."
 },
 {
  "value": 14,
  "misconception": "you read the mass at 36.9 years instead of 24.6 years",
  "feedback": "This answer is wrong — you read the mass at 36.9 years. At 24.6 years the curve sits at 28 mg."
 }
]
feedback
{
 "keyExplanation": "Go up from 24.6 years on the time axis to the curve. Go straight across from that point to the mass axis. At 24.6 years, 28 mg of hydrogen-3 remains.",
 "anticipatedWrong": [
  {
   "value": 56,
   "misconception": "you read the mass at 12.3 years instead of 24.6 years",
   "feedback": "This answer is wrong — you read the mass at 12.3 years. At 24.6 years the curve sits at 28 mg."
  },
  {
   "value": 14,
   "misconception": "you read the mass at 36.9 years instead of 24.6 years",
   "feedback": "This answer is wrong — you read the mass at 36.9 years. At 24.6 years the curve sits at 28 mg."
  }
 ]
}
NUC-024 · medium · application · seq 15 · authored:U14-G3 stage 2 (diagnosis: divide-by-count trap) | blind-1 P4: count 4 -> 5 (A#6 same-count routine cue) · mcq4
A sample sits through 5 half-lives. To find the mass remaining, a student divides the starting mass by 5. What went wrong?
Five half-lives means five halvings — divide by 2 five times, not by 5. KEY
Nothing went wrong — dividing by the number of half-lives is the taught routine.
The student should have divided by 10 — double the number of half-lives.
The student should have subtracted 5 from the starting mass.
NUC-023 · medium · application · seq 16 · authored:U14-G3 stage 2 (percent decayed, count 2) | blind-1 1c: swapped with B#16 — A#7's option set exposed 7/8 = the old A#16 answer (both reviewers) · numeric
A radioactive sample completes two half-lives. What percent of its starting nuclei has decayed by then?
Answer: 75 % KEY
also accepted: 75%, 3/4 as a percent
wrongValueDiagnostics
[
 {
  "value": 25,
  "misconception": "you gave the percentage that REMAINS — the question asks for the decayed percentage",
  "feedback": "This answer is wrong — you gave the percentage that REMAINS. Decayed is the rest: 100 − 25 = 75%."
 },
 {
  "value": 100,
  "misconception": "you added half plus half — the second half-life removes half OF WHAT REMAINS, so a quarter still remains",
  "feedback": "This answer is wrong — you added half plus half. The second half-life removes half OF WHAT REMAINS: 75% decayed, 25% remains."
 },
 {
  "value": 50,
  "misconception": "you froze the decayed share at one halving — the second half-life removes another quarter",
  "feedback": "This answer is wrong — you froze the decayed share at one halving. The second half-life removes another quarter: 75% in total."
 }
]
feedback
{
 "keyExplanation": "Remaining first: 100 → 50 → 25, because after each half-life, half of the nuclei that remain decay. Decayed is the rest: 100 − 25 = 75%.",
 "anticipatedWrong": [
  {
   "value": 25,
   "misconception": "you gave the percentage that REMAINS — the question asks for the decayed percentage",
   "feedback": "This answer is wrong — you gave the percentage that REMAINS. Decayed is the rest: 100 − 25 = 75%."
  },
  {
   "value": 100,
   "misconception": "you added half plus half — the second half-life removes half OF WHAT REMAINS, so a quarter still remains",
   "feedback": "This answer is wrong — you added half plus half. The second half-life removes half OF WHAT REMAINS: 75% decayed, 25% remains."
  },
  {
   "value": 50,
   "misconception": "you froze the decayed share at one halving — the second half-life removes another quarter",
   "feedback": "This answer is wrong — you froze the decayed share at one halving. The second half-life removes another quarter: 75% in total."
  }
 ]
}
NUC-022 · hard · transfer · seq 17 · seed:U14-G3.pool[2] (NUC-022 gateItems, James) - MUST_FRESHEN_INSTANCE (phosphorus-32/14.3 = fluency corpus; claim + key + distractor set kept; re-minted to osmium-185/93.6 d, derived values recomputed) · mcq4
A student says: 'Osmium-185's half-life is 93.6 days, so after 93.6 days a sample of it is no longer radioactive.' What is wrong with the claim?
After 93.6 days only half of the osmium-185 nuclei have decayed — the remaining half is still radioactive. KEY
Nothing is wrong — the half-life measures the time for a sample to become safe.
The claim fails only because the sample actually stops being radioactive after about 46.8 days.
The half-life grows to 187.2 days once the first half has decayed, so the sample stays radioactive longer than the student expects.
NUC-025 · hard · transfer · seq 18 · seed:U14-G3.demo_curated[1] = pool[10] (NUC-025 gateItems, James demo) - VERBATIM (JAMES-DEMO token family covers residual corpus hits {60, 16}; recorded in gate_config) · numeric
Cobalt-60 has a half-life of 5.3 years. A sample of cobalt-60 has decayed until only 1/16 of the original amount remains. How much time has passed, in years?
Answer: 21.2 years KEY
also accepted: 21.2 years, 21.2 y
wrongValueDiagnostics
[
 {
  "value": 84.8,
  "misconception": "you used the 16 in 1/16 as the number of halvings — 1 → 1/2 → 1/4 → 1/8 → 1/16 is 4 halvings",
  "feedback": "This answer is wrong — you used the 16 in 1/16 as the number of halvings. 1 → 1/2 → 1/4 → 1/8 → 1/16 is 4 halvings: 21.2 years."
 },
 {
  "value": 15.9,
  "misconception": "you stopped counting at 1/8 — reaching 1/16 takes 4 halvings, not 3",
  "feedback": "This answer is wrong — you stopped counting at 1/8. Reaching 1/16 takes 4 halvings, not 3: 21.2 years."
 }
]
feedback
{
 "keyExplanation": "Count the halvings: 1 → 1/2 → 1/4 → 1/8 → 1/16.\nThe sample has halved 4 times.\ntime passed = number of halvings × half-life\ntime passed = 4 × 5.3 years\ntime passed = 21.2 years",
 "anticipatedWrong": [
  {
   "value": 84.8,
   "misconception": "you used the 16 in 1/16 as the number of halvings — 1 → 1/2 → 1/4 → 1/8 → 1/16 is 4 halvings",
   "feedback": "This answer is wrong — you used the 16 in 1/16 as the number of halvings. 1 → 1/2 → 1/4 → 1/8 → 1/16 is 4 halvings: 21.2 years."
  },
  {
   "value": 15.9,
   "misconception": "you stopped counting at 1/8 — reaching 1/16 takes 4 halvings, not 3",
   "feedback": "This answer is wrong — you stopped counting at 1/8. Reaching 1/16 takes 4 halvings, not 3: 21.2 years."
  }
 ]
}
NUC-026 · hard · transfer · seq 19 · seed:U14-G3.pool[13] (NUC-026 gateItems, James) - VERBATIM (JAMES-DEMO/LADDER family covers the 25% target; recorded in gate_config) · numeric
The figure shows the decay curve of iodine-125, plotted as the percent of the sample remaining. Read from the curve how long it takes for the sample to fall to 25% of its starting amount, in days.
FIGURE (decay-curve · stimulus) — isotope: "iodine-125" · yLabel: "percent of iodine-125 remaining (%)" · yTicks: [0, 25, 50, 75, 100] · xLabel: "time (days)" · xTicks: [0, 30, 60, 90, 120, 150, 180, 210, 240] · curvePoints: [[0, 100], [60, 50], [120, 25], [180, 12.5], [240, 6.25]] · style: "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
raw spec
{
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "decay-curve",
  "isotope": "iodine-125",
  "yLabel": "percent of iodine-125 remaining (%)",
  "yTicks": [
   0,
   25,
   50,
   75,
   100
  ],
  "xLabel": "time (days)",
  "xTicks": [
   0,
   30,
   60,
   90,
   120,
   150,
   180,
   210,
   240
  ],
  "curvePoints": [
   [
    0,
    100
   ],
   [
    60,
    50
   ],
   [
    120,
    25
   ],
   [
    180,
    12.5
   ],
   [
    240,
    6.25
   ]
  ],
  "style": "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
 }
}
Answer: 120 days KEY
also accepted: 120 days, 120 d
wrongValueDiagnostics
[
 {
  "value": 60,
  "misconception": "you read the time to fall to 50% — the question asks for 25%, which takes two half-lives",
  "feedback": "This answer is wrong — you read the time to fall to 50%. Reaching 25% takes two half-lives: 120 days."
 },
 {
  "value": 180,
  "misconception": "you read the time to fall to 12.5% — that is one half-life too many",
  "feedback": "This answer is wrong — you read the time to fall to 12.5%. The 25% crossing sits at 120 days."
 }
]
feedback
{
 "keyExplanation": "Find 25% on the percent axis. Go across to the curve, then down to the time axis. The sample reaches 25% at 120 days.",
 "anticipatedWrong": [
  {
   "value": 60,
   "misconception": "you read the time to fall to 50% — the question asks for 25%, which takes two half-lives",
   "feedback": "This answer is wrong — you read the time to fall to 50%. Reaching 25% takes two half-lives: 120 days."
  },
  {
   "value": 180,
   "misconception": "you read the time to fall to 12.5% — that is one half-life too many",
   "feedback": "This answer is wrong — you read the time to fall to 12.5%. The 25% crossing sits at 120 days."
  }
 ]
}
NUC-025 · hard · transfer · seq 20 · authored:U14-G3 stage 2 (comparative: equal counts, unequal half-lives) · mcq4
Samples of two isotopes, X and Y, have each decayed to one quarter of their starting amounts. X's half-life is longer than Y's. Which sample took more time to get there?
X's — each sample made two halvings, and X's halvings each take one longer half-life. KEY
Y's — a shorter half-life means more decays, so more time passes.
They took the same time — both fell to one quarter.
It cannot be determined without the starting masses.
NUC-025 · hard · application · seq 21 · authored:U14-G3 stage 2 (fresh capstone FRQ; potassium-43 clinical instance) · frq
A radiopharmacy production run yields 264 ng of potassium-43, whose half-life is 22.3 hours. Later, only 33 ng of the potassium-43 remains.
A radiopharmacy production run yields 264 ng of potassium-43, whose half-life is 22.3 hours. Later, only 33 ng of the potassium-43 remains. (a) Write out the halving chain from 264 ng down to 33 ng, and state how many halvings the sample has made. (b) Using the relation 'time passed = number of halvings × half-life', substitute the values and calculate how much time has passed. Give the result with its unit. (c) In one sentence, explain why each halving takes the same amount of time.
Part a. Write out the halving chain from 264 ng down to 33 ng, and state how many halvings the sample has made.
Model: Count the halvings: 264 ng → 132 ng → 66 ng → 33 ng. The sample has halved 3 times.
Part b. Using the relation 'time passed = number of halvings × half-life', substitute the values and calculate how much time has passed. Give the result with its unit.
Model: time passed = number of halvings × half-life time passed = 3 × 22.3 hours time passed = 66.9 hours
Part c. In one sentence, explain why each halving takes the same amount of time.
Model: Each halving takes exactly one half-life, because after each half-life, half of the nuclei that remain decay.
Full model answer. (a) Count the halvings: 264 ng → 132 ng → 66 ng → 33 ng. The sample has halved 3 times. (b) time passed = number of halvings × half-life time passed = 3 × 22.3 hours time passed = 66.9 hours (c) Each halving takes exactly one half-life, because after each half-life, half of the nuclei that remain decay.

Form B

NUC-022 · easy · recall · seq 1 · authored:U14-G3 stage 2 (fresh definitional read; per-sample facet) · mcq4
Palladium-103 has a half-life of 17.0 days. A clinic stores a sealed capsule of palladium-103. Which statement correctly uses the half-life?
Half of the capsule's palladium-103 nuclei decay during each 17.0-day stretch. KEY
Each palladium-103 nucleus in the capsule lasts exactly 17.0 days.
The capsule keeps all of its palladium-103 until day 17, then loses half at once.
After 17.0 days the capsule no longer contains any palladium-103.
NUC-024 · easy · recall · seq 2 · authored:U14-G3 stage 2 (routine recognition, which-equation facet) · mcq4
Which equation counts how many half-lives fit into the time a radioactive sample has been left?
number of half-lives = time passed ÷ half-life KEY
number of half-lives = half-life ÷ time passed
number of half-lives = time passed multiplied by the half-life
number of half-lives = starting amount ÷ half-life
NUC-026 · easy · recall · seq 3 · authored:U14-G3 stage 2 (procedure recognition, half-life crossing) · mcq4
Which point on a decay curve marks one half-life of the isotope?
The point where the remaining amount equals half of the starting amount. KEY
The point sitting directly above the middle of the graph's time axis.
The last plotted point of the curve.
The point where the curve falls most steeply.
NUC-022 · medium · application · seq 4 · authored:U14-G3 stage 2 (fresh amount-fixedness comparison; phrasing-pack americium-241 instance) · mcq4
A factory holds a sealed americium-241 source big enough for a crate of smoke detectors; one finished smoke detector holds a tiny speck of the same americium-241. Its half-life is 432 years. How do the two samples' half-lives compare?
Both are 432 years — the half-life belongs to the isotope, not the amount. KEY
The factory source's half-life is longer — more nuclei take more time to work through.
The speck's half-life is longer — so few decays happen in it each second.
It depends on whether the detector has been switched on.
NUC-023 · medium · application · seq 5 · authored:U14-G3 stage 2 (fresh count 8; p3 class) · text
A sample of barium-140 sits through 8 half-lives. What fraction of the original barium-140 nuclei remains?
Answer: 1/256 KEY
also accepted: 1/256, 0.00390625
wrongValueDiagnostics
[
 {
  "value": "1/8",
  "misconception": "you divided the original amount by the number of half-lives — eight half-lives means eight halvings",
  "feedback": "This answer is wrong — you divided the original amount by the number of half-lives. Eight half-lives means eight successive halvings, ending at 1/256."
 },
 {
  "value": "1/128",
  "misconception": "you halved one time too few — the eighth halving takes 1/128 to 1/256",
  "feedback": "This answer is wrong — you halved one time too few. The eighth halving takes 1/128 to 1/256."
 },
 {
  "value": "0",
  "misconception": "you emptied the sample — each half-life removes only half of what is left",
  "feedback": "This answer is wrong — you emptied the sample. Each half-life removes only half of what is left, so 1/256 still remains."
 }
]
feedback
{
 "keyExplanation": "Halve once per half-life: 1/2, 1/4, 1/8, 1/16, 1/32, 1/64, 1/128, 1/256 — because after each half-life, half of the nuclei that remain decay. After 8 half-lives, 1/256 of the original barium-140 nuclei remain.",
 "anticipatedWrong": [
  {
   "value": "1/8",
   "misconception": "you divided the original amount by the number of half-lives — eight half-lives means eight halvings",
   "feedback": "This answer is wrong — you divided the original amount by the number of half-lives. Eight half-lives means eight successive halvings, ending at 1/256."
  },
  {
   "value": "1/128",
   "misconception": "you halved one time too few — the eighth halving takes 1/128 to 1/256",
   "feedback": "This answer is wrong — you halved one time too few. The eighth halving takes 1/128 to 1/256."
  },
  {
   "value": "0",
   "misconception": "you emptied the sample — each half-life removes only half of what is left",
   "feedback": "This answer is wrong — you emptied the sample. Each half-life removes only half of what is left, so 1/256 still remains."
  }
 ]
}
NUC-023 · medium · application · seq 6 · authored:U14-G3 stage 2 (fresh count 5; p5 class) · numeric
After 5 half-lives, what percentage of a sample's original radioactive nuclei remains?
Answer: 3.125 % KEY
also accepted: 3.125%, 1/32 as a percent
wrongValueDiagnostics
[
 {
  "value": 20,
  "misconception": "you divided 100% by the number of half-lives — five half-lives means five halvings of what remains",
  "feedback": "This answer is wrong — you divided 100% by the number of half-lives. Five half-lives means five halvings, ending at 3.125%."
 },
 {
  "value": 6.25,
  "misconception": "you halved one time too few — the fifth halving takes 6.25% down to 3.125%",
  "feedback": "This answer is wrong — you halved one time too few. The fifth halving takes 6.25% down to 3.125%."
 },
 {
  "value": 0.03125,
  "misconception": "you gave the fraction instead of the percentage — 1/32 of the original is 3.125%",
  "feedback": "This answer is wrong — you gave the fraction instead of the percentage. 1/32 of the original is 3.125%."
 }
]
feedback
{
 "keyExplanation": "Halve 100% once per half-life: 100 → 50 → 25 → 12.5 → 6.25 → 3.125. Because after each half-life, half of the nuclei that remain decay. 3.125% of the original nuclei remain.",
 "anticipatedWrong": [
  {
   "value": 20,
   "misconception": "you divided 100% by the number of half-lives — five half-lives means five halvings of what remains",
   "feedback": "This answer is wrong — you divided 100% by the number of half-lives. Five half-lives means five halvings, ending at 3.125%."
  },
  {
   "value": 6.25,
   "misconception": "you halved one time too few — the fifth halving takes 6.25% down to 3.125%",
   "feedback": "This answer is wrong — you halved one time too few. The fifth halving takes 6.25% down to 3.125%."
  },
  {
   "value": 0.03125,
   "misconception": "you gave the fraction instead of the percentage — 1/32 of the original is 3.125%",
   "feedback": "This answer is wrong — you gave the fraction instead of the percentage. 1/32 of the original is 3.125%."
  }
 ]
}
NUC-023 · medium · application · seq 7 · authored:U14-G3 stage 2 (never-zero read; rule line 6) · mcq4
A radioactive sample has been halving for many, many half-lives. Which statement about the amount of the isotope remaining is correct?
Some always remains — each half-life removes only half of what is left. KEY
It reached zero at the second half-life — the two halves added up to the whole.
It reaches zero as soon as the removed fractions total more than nine tenths.
It stops shrinking once the sample gets small enough — decay switches off at trace amounts.
NUC-024 · medium · application · seq 8 · seed:U14-G3.pool[7] (NUC-024 gateItems, James) - MUST_FRESHEN_INSTANCE (radon-222/3.8/11.4 collide with kept-verbatim demo p11; sealed-container construct + misconception set kept; re-minted to xenon-133, then blind-1 P2 re-minted to dysprosium-159/144.4d/433.2d (phosphorus/xenon = taught or B#19-shared; niobium-95 = D#5's isotope; probe-fresh pick) (xenon-133 constant-supply cue onto the B#19 curve read)) · numeric
A 104 g sample of dysprosium-159 (half-life 144.4 days) is stored for 433.2 days. What mass of dysprosium-159 remains, in grams? Give your answer to the nearest whole number.
Answer: 13 g KEY
also accepted: 13 g
wrongValueDiagnostics
[
 {
  "value": 52,
  "misconception": "you halved only once — 433.2 days holds THREE 144.4-day half-lives",
  "feedback": "This answer is wrong — you halved only once. 433.2 days holds THREE 144.4-day half-lives: 104 → 52 → 26 → 13."
 },
 {
  "value": 34.67,
  "misconception": "you divided the starting amount by the number of half-lives — three half-lives means three halvings, not division by 3",
  "feedback": "This answer is wrong — you divided the starting amount by the number of half-lives. Three half-lives means three halvings: 104 → 52 → 26 → 13."
 },
 {
  "value": 26,
  "misconception": "you halved one time too few — the third halving takes 26 g down to 13 g",
  "feedback": "This answer is wrong — you halved one time too few. The third halving takes 26 g down to 13 g."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nstarting amount = 104 g, half-life = 144.4 days, time passed = 433.2 days\nWrite down the equation:\nnumber of half-lives = time passed ÷ half-life\nSubstitute in the values, and calculate:\nnumber of half-lives = 433.2 ÷ 144.4 = 3\nHalve the starting amount three times: 104 → 52 → 26 → 13\n13 g of dysprosium-159 remains.",
 "anticipatedWrong": [
  {
   "value": 52,
   "misconception": "you halved only once — 433.2 days holds THREE 144.4-day half-lives",
   "feedback": "This answer is wrong — you halved only once. 433.2 days holds THREE 144.4-day half-lives: 104 → 52 → 26 → 13."
  },
  {
   "value": 34.67,
   "misconception": "you divided the starting amount by the number of half-lives — three half-lives means three halvings, not division by 3",
   "feedback": "This answer is wrong — you divided the starting amount by the number of half-lives. Three half-lives means three halvings: 104 → 52 → 26 → 13."
  },
  {
   "value": 26,
   "misconception": "you halved one time too few — the third halving takes 26 g down to 13 g",
   "feedback": "This answer is wrong — you halved one time too few. The third halving takes 26 g down to 13 g."
  }
 ]
}
NUC-024 · medium · application · seq 9 · authored:U14-G3 stage 2 (fresh forward 2-halving) · numeric
A 268 mg vial of rhenium-186 (half-life 3.7 days) waits in a shielded drawer for 7.4 days. What mass of rhenium-186 remains, in milligrams? Give your answer to the nearest whole number.
Answer: 67 mg KEY
also accepted: 67 mg
wrongValueDiagnostics
[
 {
  "value": 134,
  "misconception": "you halved only once — 7.4 days holds TWO 3.7-day half-lives",
  "feedback": "This answer is wrong — you halved only once. 7.4 days holds TWO 3.7-day half-lives: 268 → 134 → 67."
 },
 {
  "value": 33.5,
  "misconception": "you halved one time too many — two half-lives means exactly two halvings",
  "feedback": "This answer is wrong — you halved one time too many. Two half-lives means exactly two halvings: 268 → 134 → 67."
 },
 {
  "value": 260.6,
  "misconception": "you subtracted the days from the milligrams — amounts and times never subtract; count the half-lives, then halve",
  "feedback": "This answer is wrong — you subtracted the days from the milligrams. Count the half-lives, then halve: 67 mg."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nstarting amount = 268 mg, half-life = 3.7 days, time passed = 7.4 days\nWrite down the equation:\nnumber of half-lives = time passed ÷ half-life\nSubstitute in the values, and calculate:\nnumber of half-lives = 7.4 ÷ 3.7 = 2\nHalve the starting amount twice: 268 → 134 → 67\n67 mg of rhenium-186 remains.",
 "anticipatedWrong": [
  {
   "value": 134,
   "misconception": "you halved only once — 7.4 days holds TWO 3.7-day half-lives",
   "feedback": "This answer is wrong — you halved only once. 7.4 days holds TWO 3.7-day half-lives: 268 → 134 → 67."
  },
  {
   "value": 33.5,
   "misconception": "you halved one time too many — two half-lives means exactly two halvings",
   "feedback": "This answer is wrong — you halved one time too many. Two half-lives means exactly two halvings: 268 → 134 → 67."
  },
  {
   "value": 260.6,
   "misconception": "you subtracted the days from the milligrams — amounts and times never subtract; count the half-lives, then halve",
   "feedback": "This answer is wrong — you subtracted the days from the milligrams. Count the half-lives, then halve: 67 mg."
  }
 ]
}
NUC-022 · medium · application · seq 10 · authored:U14-G3 stage 2 (heating facet; fluency-3 class, fresh instance, value withheld — its 10.8 y is a corpus number) · mcq4
A chemist strongly heats a sealed sample of krypton-85 gas. What effect does the heating have on the krypton-85's half-life?
Nothing — heating never changes an isotope's half-life. KEY
It gets shorter — hot nuclei decay faster.
It gets longer — the heat drives off the least stable nuclei first.
It drops toward zero, because a hot enough sample decays all at once.
NUC-025 · medium · application · seq 11 · seed:U14-G3.demo_curated[2] = pool[11] (NUC-025 gateItems, James demo) - VERBATIM (JAMES-DEMO token family covers residual corpus hits {222, 3.8, 60, 11.4}; recorded in gate_config) · numeric
Radon-222 has a half-life of 3.8 days. A sealed sample of radon-222 has decayed from 60 µg down to 7.5 µg. How much time has passed, in days?
Answer: 11.4 days KEY
also accepted: 11.4 days, 11.4 d
wrongValueDiagnostics
[
 {
  "value": 30.4,
  "misconception": "you used the ratio 60 ÷ 7.5 = 8 as the number of halvings — 60 µg → 30 µg → 15 µg → 7.5 µg is 3 halvings",
  "feedback": "This answer is wrong — you used the ratio 60 ÷ 7.5 = 8 as the number of halvings. 60 µg → 30 µg → 15 µg → 7.5 µg is 3 halvings: 11.4 days."
 },
 {
  "value": 7.6,
  "misconception": "you stopped counting one halving early — 60 µg → 30 µg → 15 µg → 7.5 µg is 3 halvings, not 2",
  "feedback": "This answer is wrong — you stopped counting one halving early. 60 µg → 30 µg → 15 µg → 7.5 µg is 3 halvings, not 2: 11.4 days."
 }
]
feedback
{
 "keyExplanation": "Count the halvings: 60 µg → 30 µg → 15 µg → 7.5 µg.\nThe sample has halved 3 times.\ntime passed = number of halvings × half-life\ntime passed = 3 × 3.8 days\ntime passed = 11.4 days",
 "anticipatedWrong": [
  {
   "value": 30.4,
   "misconception": "you used the ratio 60 ÷ 7.5 = 8 as the number of halvings — 60 µg → 30 µg → 15 µg → 7.5 µg is 3 halvings",
   "feedback": "This answer is wrong — you used the ratio 60 ÷ 7.5 = 8 as the number of halvings. 60 µg → 30 µg → 15 µg → 7.5 µg is 3 halvings: 11.4 days."
  },
  {
   "value": 7.6,
   "misconception": "you stopped counting one halving early — 60 µg → 30 µg → 15 µg → 7.5 µg is 3 halvings, not 2",
   "feedback": "This answer is wrong — you stopped counting one halving early. 60 µg → 30 µg → 15 µg → 7.5 µg is 3 halvings, not 2: 11.4 days."
  }
 ]
}
NUC-025 · medium · application · seq 12 · authored:U14-G3 stage 2 (count read; 4-halving chain) · mcq4
A radioactive sample has decayed from 368 g down to 23 g. How many half-lives have passed?
4 KEY
3
5
8
NUC-026 · medium · application · seq 13 · authored:U14-G3 stage 2 (fresh percent curve; half-life read) · numeric
The figure shows the decay curve of ruthenium-103, plotted as the percent of the sample remaining. Read the half-life of ruthenium-103 from the curve, in days.
FIGURE (decay-curve · stimulus) — isotope: "ruthenium-103" · yLabel: "percent of ruthenium-103 remaining (%)" · yTicks: [0, 25, 50, 75, 100] · xLabel: "time (days)" · xTicks: [0, 39.3, 78.6, 117.9, 157.2] · curvePoints: [[0, 100], [39.3, 50], [78.6, 25], [117.9, 12.5], [157.2, 6.25]] · style: "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
raw spec
{
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "decay-curve",
  "isotope": "ruthenium-103",
  "yLabel": "percent of ruthenium-103 remaining (%)",
  "yTicks": [
   0,
   25,
   50,
   75,
   100
  ],
  "xLabel": "time (days)",
  "xTicks": [
   0,
   39.3,
   78.6,
   117.9,
   157.2
  ],
  "curvePoints": [
   [
    0,
    100
   ],
   [
    39.3,
    50
   ],
   [
    78.6,
    25
   ],
   [
    117.9,
    12.5
   ],
   [
    157.2,
    6.25
   ]
  ],
  "style": "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
 }
}
Answer: 39.3 days KEY
also accepted: 39.3 days, 39.3 d
wrongValueDiagnostics
[
 {
  "value": 78.6,
  "misconception": "you read the time for the sample to fall to a quarter — that is two half-lives, not one",
  "feedback": "This answer is wrong — you read the time to fall to a quarter. That is two half-lives; one half-life is 39.3 days."
 },
 {
  "value": 157.2,
  "misconception": "you read the last time labeled on the axis instead of the 50% crossing",
  "feedback": "This answer is wrong — you read the last time on the axis. The 50% crossing sits at 39.3 days."
 }
]
feedback
{
 "keyExplanation": "Half of the starting amount: half of 100% is 50%. The curve reaches 50% at 39.3 days. The half-life of ruthenium-103 is 39.3 days.",
 "anticipatedWrong": [
  {
   "value": 78.6,
   "misconception": "you read the time for the sample to fall to a quarter — that is two half-lives, not one",
   "feedback": "This answer is wrong — you read the time to fall to a quarter. That is two half-lives; one half-life is 39.3 days."
  },
  {
   "value": 157.2,
   "misconception": "you read the last time labeled on the axis instead of the 50% crossing",
   "feedback": "This answer is wrong — you read the last time on the axis. The 50% crossing sits at 39.3 days."
  }
 ]
}
NUC-026 · medium · application · seq 14 · authored:U14-G3 stage 2 (fresh amount-at-time read) · numeric
The figure shows the decay curve of a 176 mg sample of osmium-191. Read from the curve the mass remaining at 30.8 days, in mg.
FIGURE (decay-curve · stimulus) — isotope: "osmium-191" · yLabel: "mass of osmium-191 remaining (mg)" · yTicks: [0, 22, 44, 66, 88, 110, 132, 154, 176] · xLabel: "time (days)" · xTicks: [0, 15.4, 30.8, 46.2] · curvePoints: [[0, 176], [15.4, 88], [30.8, 44], [46.2, 22]] · style: "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
raw spec
{
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "decay-curve",
  "isotope": "osmium-191",
  "yLabel": "mass of osmium-191 remaining (mg)",
  "yTicks": [
   0,
   22,
   44,
   66,
   88,
   110,
   132,
   154,
   176
  ],
  "xLabel": "time (days)",
  "xTicks": [
   0,
   15.4,
   30.8,
   46.2
  ],
  "curvePoints": [
   [
    0,
    176
   ],
   [
    15.4,
    88
   ],
   [
    30.8,
    44
   ],
   [
    46.2,
    22
   ]
  ],
  "style": "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
 }
}
Answer: 44 mg KEY
also accepted: 44 mg
wrongValueDiagnostics
[
 {
  "value": 88,
  "misconception": "you read the mass at 15.4 days instead of 30.8 days",
  "feedback": "This answer is wrong — you read the mass at 15.4 days. At 30.8 days the curve sits at 44 mg."
 },
 {
  "value": 22,
  "misconception": "you read the mass at 46.2 days instead of 30.8 days",
  "feedback": "This answer is wrong — you read the mass at 46.2 days. At 30.8 days the curve sits at 44 mg."
 }
]
feedback
{
 "keyExplanation": "Go up from 30.8 days on the time axis to the curve, then straight across to the mass axis. At 30.8 days, 44 mg of osmium-191 remains.",
 "anticipatedWrong": [
  {
   "value": 88,
   "misconception": "you read the mass at 15.4 days instead of 30.8 days",
   "feedback": "This answer is wrong — you read the mass at 15.4 days. At 30.8 days the curve sits at 44 mg."
  },
  {
   "value": 22,
   "misconception": "you read the mass at 46.2 days instead of 30.8 days",
   "feedback": "This answer is wrong — you read the mass at 46.2 days. At 30.8 days the curve sits at 44 mg."
  }
 ]
}
NUC-024 · medium · application · seq 15 · authored:U14-G3 stage 2 (diagnosis: units-subtract trap; A3 canonical clause) | blind-1 P5: D1 replaced (subtraction-is-fine -> divide-grams-by-days) · mcq4
To find how much of a radioactive sample remains after a storage period, a student subtracts the number of days from the number of grams. What is the correct diagnosis?
Grams and days measure different things and never subtract — count the half-lives, then halve once per half-life. KEY
The student should divide the grams by the days instead — division handles mismatched units correctly.
The student only needed to subtract half of the days instead.
The student should have added the days to the grams, since the sample gains stability over time.
NUC-023 · medium · application · seq 16 · authored:U14-G3 stage 2 (percent decayed, count 3) | blind-1 1c: swapped with A#16 (form B exposes no 7/8 fraction anywhere) · numeric
A radioactive sample completes three half-lives. What percent of its starting nuclei has decayed by then?
Answer: 87.5 % KEY
also accepted: 87.5%, 7/8 as a percent
wrongValueDiagnostics
[
 {
  "value": 12.5,
  "misconception": "you gave the percentage that REMAINS — the question asks for the decayed percentage, which is everything else",
  "feedback": "This answer is wrong — you gave the percentage that REMAINS. Decayed is the rest: 100 − 12.5 = 87.5%."
 },
 {
  "value": 37.5,
  "misconception": "you removed one-eighth per half-life — the halvings remove 50, then 25, then 12.5 percent, totaling 87.5%",
  "feedback": "This answer is wrong — you removed one-eighth per half-life. The halvings remove 50, then 25, then 12.5 percent: 87.5% in total."
 },
 {
  "value": 50,
  "misconception": "you froze the decayed share at one halving — each later half-life keeps removing half of what remains",
  "feedback": "This answer is wrong — you froze the decayed share at one halving. Each later half-life keeps removing half of what remains: 87.5%."
 }
]
feedback
{
 "keyExplanation": "Remaining first: 100 → 50 → 25 → 12.5, because after each half-life, half of the nuclei that remain decay. Decayed is the rest: 100 − 12.5 = 87.5%.",
 "anticipatedWrong": [
  {
   "value": 12.5,
   "misconception": "you gave the percentage that REMAINS — the question asks for the decayed percentage, which is everything else",
   "feedback": "This answer is wrong — you gave the percentage that REMAINS. Decayed is the rest: 100 − 12.5 = 87.5%."
  },
  {
   "value": 37.5,
   "misconception": "you removed one-eighth per half-life — the halvings remove 50, then 25, then 12.5 percent, totaling 87.5%",
   "feedback": "This answer is wrong — you removed one-eighth per half-life. The halvings remove 50, then 25, then 12.5 percent: 87.5% in total."
  },
  {
   "value": 50,
   "misconception": "you froze the decayed share at one halving — each later half-life keeps removing half of what remains",
   "feedback": "This answer is wrong — you froze the decayed share at one halving. Each later half-life keeps removing half of what remains: 87.5%."
  }
 ]
}
NUC-022 · hard · transfer · seq 17 · authored:U14-G3 stage 2 (claim: remaining-half-faster; evaluate framing) · mcq4
A student claims: 'Once half of a radioactive sample has decayed, the remaining half gets through its decay in less time, because there are fewer nuclei left to go.' What is wrong with the claim?
Nothing speeds up — the remaining nuclei halve on the same fixed half-life, halving after halving. KEY
Nothing is wrong — smaller samples do finish their decay faster.
The remaining half actually takes LONGER, because the sturdiest nuclei decay last.
The claim fails only because the remaining half never decays at all.
NUC-025 · hard · transfer · seq 18 · authored:U14-G3 stage 2 (fresh fraction-form transfer; p10 class) · numeric
Ytterbium-175 has a half-life of 4.2 days. A sample of ytterbium-175 has decayed until only 1/8 of the original amount remains. How much time has passed, in days?
Answer: 12.6 days KEY
also accepted: 12.6 days, 12.6 d
wrongValueDiagnostics
[
 {
  "value": 33.6,
  "misconception": "you used the 8 in 1/8 as the number of halvings — 1 → 1/2 → 1/4 → 1/8 is 3 halvings",
  "feedback": "This answer is wrong — you used the 8 in 1/8 as the number of halvings. 1 → 1/2 → 1/4 → 1/8 is 3 halvings: 12.6 days."
 },
 {
  "value": 8.4,
  "misconception": "you stopped counting at 1/4 — reaching 1/8 takes 3 halvings, not 2",
  "feedback": "This answer is wrong — you stopped counting at 1/4. Reaching 1/8 takes 3 halvings, not 2: 12.6 days."
 }
]
feedback
{
 "keyExplanation": "Count the halvings: 1 → 1/2 → 1/4 → 1/8.\nThe sample has halved 3 times.\ntime passed = number of halvings × half-life\ntime passed = 3 × 4.2 days\ntime passed = 12.6 days",
 "anticipatedWrong": [
  {
   "value": 33.6,
   "misconception": "you used the 8 in 1/8 as the number of halvings — 1 → 1/2 → 1/4 → 1/8 is 3 halvings",
   "feedback": "This answer is wrong — you used the 8 in 1/8 as the number of halvings. 1 → 1/2 → 1/4 → 1/8 is 3 halvings: 12.6 days."
  },
  {
   "value": 8.4,
   "misconception": "you stopped counting at 1/4 — reaching 1/8 takes 3 halvings, not 2",
   "feedback": "This answer is wrong — you stopped counting at 1/4. Reaching 1/8 takes 3 halvings, not 2: 12.6 days."
  }
 ]
}
NUC-026 · hard · transfer · seq 19 · authored:U14-G3 stage 2 (fresh mass-target inverse read; xenon-133 also anchors B#8 — same-form reuse, design-legal, recorded) · numeric
The figure shows the decay curve of a 464 g sample of xenon-133. Read from the curve how long it takes for the sample to fall to 116 g, in days.
FIGURE (decay-curve · stimulus) — isotope: "xenon-133" · yLabel: "mass of xenon-133 remaining (g)" · yTicks: [0, 58, 116, 174, 232, 290, 348, 406, 464] · xLabel: "time (days)" · xTicks: [0, 5.2, 10.4, 15.6, 20.8] · curvePoints: [[0, 464], [5.2, 232], [10.4, 116], [15.6, 58], [20.8, 29]] · style: "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
raw spec
{
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "decay-curve",
  "isotope": "xenon-133",
  "yLabel": "mass of xenon-133 remaining (g)",
  "yTicks": [
   0,
   58,
   116,
   174,
   232,
   290,
   348,
   406,
   464
  ],
  "xLabel": "time (days)",
  "xTicks": [
   0,
   5.2,
   10.4,
   15.6,
   20.8
  ],
  "curvePoints": [
   [
    0,
    464
   ],
   [
    5.2,
    232
   ],
   [
    10.4,
    116
   ],
   [
    15.6,
    58
   ],
   [
    20.8,
    29
   ]
  ],
  "style": "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
 }
}
Answer: 10.4 days KEY
also accepted: 10.4 days, 10.4 d
wrongValueDiagnostics
[
 {
  "value": 5.2,
  "misconception": "you read the time for the first halving — 116 g is a quarter of 464 g, which takes two halvings",
  "feedback": "This answer is wrong — you read the time for the first halving. 116 g is a quarter of 464 g: two halvings, 10.4 days."
 },
 {
  "value": 15.6,
  "misconception": "you read one halving too far — the curve reaches 116 g at 10.4 days, not 58 g",
  "feedback": "This answer is wrong — you read one halving too far. The curve reaches 116 g at 10.4 days."
 }
]
feedback
{
 "keyExplanation": "Find 116 g on the mass axis. Go across to the curve, then down to the time axis. The sample reaches 116 g at 10.4 days.",
 "anticipatedWrong": [
  {
   "value": 5.2,
   "misconception": "you read the time for the first halving — 116 g is a quarter of 464 g, which takes two halvings",
   "feedback": "This answer is wrong — you read the time for the first halving. 116 g is a quarter of 464 g: two halvings, 10.4 days."
  },
  {
   "value": 15.6,
   "misconception": "you read one halving too far — the curve reaches 116 g at 10.4 days, not 58 g",
   "feedback": "This answer is wrong — you read one halving too far. The curve reaches 116 g at 10.4 days."
  }
 ]
}
NUC-025 · hard · transfer · seq 20 · authored:U14-G3 stage 2 (comparative: less-time framing) · mcq4
Samples of two isotopes, X and Y, have each decayed to one quarter of their starting amounts. X's half-life is longer than Y's. Which sample reached one quarter in LESS time?
Y's — both made two halvings, and Y's halvings are each shorter. KEY
X's — longer half-lives cover the drop in fewer steps.
Both took the same time, because the fraction is the same.
Whichever sample was smaller to begin with.
NUC-025 · hard · application · seq 21 · authored:U14-G3 stage 2 (fresh capstone FRQ; lanthanum-140 instance) · frq
A research lab receives 312 µg of lanthanum-140, whose half-life is 1.68 days. Later, only 39 µg of the lanthanum-140 remains.
A research lab receives 312 µg of lanthanum-140, whose half-life is 1.68 days. Later, only 39 µg of the lanthanum-140 remains. (a) Write out the halving chain from 312 µg down to 39 µg, and state how many halvings the sample has made. (b) Using the relation 'time passed = number of halvings × half-life', substitute the values and calculate how much time has passed. Give the result with its unit. (c) In one sentence, explain why each halving takes the same amount of time.
Part a. Write out the halving chain from 312 µg down to 39 µg, and state how many halvings the sample has made.
Model: Count the halvings: 312 µg → 156 µg → 78 µg → 39 µg. The sample has halved 3 times.
Part b. Using the relation 'time passed = number of halvings × half-life', substitute the values and calculate how much time has passed. Give the result with its unit.
Model: time passed = number of halvings × half-life time passed = 3 × 1.68 days time passed = 5.04 days
Part c. In one sentence, explain why each halving takes the same amount of time.
Model: Each halving takes exactly one half-life, because after each half-life, half of the nuclei that remain decay.
Full model answer. (a) Count the halvings: 312 µg → 156 µg → 78 µg → 39 µg. The sample has halved 3 times. (b) time passed = number of halvings × half-life time passed = 3 × 1.68 days time passed = 5.04 days (c) Each halving takes exactly one half-life, because after each half-life, half of the nuclei that remain decay.

Form C

NUC-022 · easy · recall · seq 1 · authored:U14-G3 stage 2 (fresh definitional read; what-remains facet) | blind-1 P1: holmium-166/26.8h -> arsenic-77/38.8h (gold-198 = taught spec instance; rhenium-186 collided with B#9/C#14) (C#19 constant-supply cue) · mcq4
Arsenic-77 has a half-life of 38.8 hours. A fresh sample is prepared. 38.8 hours later, how much of its arsenic-77 remains?
Half of it — one half-life has passed. KEY
None of it — one half-life is the time for the whole sample to decay.
All of it — decay only begins after the first half-life has passed.
A quarter of it — half decays in each half of the half-life.
NUC-024 · easy · recall · seq 2 · authored:U14-G3 stage 2 (routine recognition, why-divide facet) · mcq4
In the taught routine, why is the time passed divided by the half-life?
Each half-life fills one equal stretch of the wait, so dividing counts the halvings. KEY
To convert the time passed into an amount of mass remaining.
Because the answer must always be made smaller than the time passed.
To find how much mass the sample loses per day.
NUC-026 · easy · recall · seq 3 · authored:U14-G3 stage 2 (procedure recognition, amount-at-time read) · mcq4
A decay curve plots the amount of an isotope remaining against time. How do you read the amount remaining at a chosen time?
Go up from that time to the curve, then straight across to the amount axis. KEY
Go across from that time on the amount axis, then down to the time axis.
Divide the starting amount by the chosen time.
Read the amount where the curve begins.
NUC-022 · medium · application · seq 4 · authored:U14-G3 stage 2 (fresh remaining-clock read) · mcq4
Mercury-203's half-life is 46.6 days. After the first 46.6 days, half of a sample's mercury-203 has decayed. Does the remaining mercury-203 now decay on a faster clock?
No — the remaining nuclei halve on the same 46.6-day half-life as before. KEY
Yes — with fewer nuclei left, each one decays sooner.
Yes — the sample must finish decaying within one more half-life.
No — the clock actually slows down as the sturdier nuclei accumulate.
NUC-023 · medium · application · seq 5 · authored:U14-G3 stage 2 (fresh count 9; p3 class) · text
A sample of rubidium-86 sits through 9 half-lives. What fraction of the original rubidium-86 nuclei remains?
Answer: 1/512 KEY
also accepted: 1/512, 0.001953125
wrongValueDiagnostics
[
 {
  "value": "1/9",
  "misconception": "you divided the original amount by the number of half-lives — nine half-lives means nine halvings",
  "feedback": "This answer is wrong — you divided the original amount by the number of half-lives. Nine half-lives means nine halvings, ending at 1/512."
 },
 {
  "value": "1/256",
  "misconception": "you halved one time too few — the ninth halving takes 1/256 to 1/512",
  "feedback": "This answer is wrong — you halved one time too few. The ninth halving takes 1/256 to 1/512."
 },
 {
  "value": "0",
  "misconception": "you emptied the sample — each half-life removes only half of what is left",
  "feedback": "This answer is wrong — you emptied the sample. Each half-life removes only half of what is left, so 1/512 still remains."
 }
]
feedback
{
 "keyExplanation": "Halve once per half-life, nine times over: the ladder runs 1/2, 1/4, ... , 1/256, 1/512 — because after each half-life, half of the nuclei that remain decay. After 9 half-lives, 1/512 of the original rubidium-86 nuclei remain.",
 "anticipatedWrong": [
  {
   "value": "1/9",
   "misconception": "you divided the original amount by the number of half-lives — nine half-lives means nine halvings",
   "feedback": "This answer is wrong — you divided the original amount by the number of half-lives. Nine half-lives means nine halvings, ending at 1/512."
  },
  {
   "value": "1/256",
   "misconception": "you halved one time too few — the ninth halving takes 1/256 to 1/512",
   "feedback": "This answer is wrong — you halved one time too few. The ninth halving takes 1/256 to 1/512."
  },
  {
   "value": "0",
   "misconception": "you emptied the sample — each half-life removes only half of what is left",
   "feedback": "This answer is wrong — you emptied the sample. Each half-life removes only half of what is left, so 1/512 still remains."
  }
 ]
}
NUC-023 · medium · application · seq 6 · authored:U14-G3 stage 2 (fresh count 3; p5 class) · numeric
What percentage of the original radioactive nuclei in a sample is still present after 3 half-lives?
Answer: 12.5 % KEY
also accepted: 12.5%, 1/8 as a percent
wrongValueDiagnostics
[
 {
  "value": 33.33,
  "misconception": "you divided 100% by the number of half-lives — three half-lives means three halvings of what remains",
  "feedback": "This answer is wrong — you divided 100% by the number of half-lives. Three half-lives means three halvings: 100 → 50 → 25 → 12.5."
 },
 {
  "value": 25,
  "misconception": "you halved one time too few — the third halving takes 25% down to 12.5%",
  "feedback": "This answer is wrong — you halved one time too few. The third halving takes 25% down to 12.5%."
 },
 {
  "value": 0.125,
  "misconception": "you gave the fraction instead of the percentage — 1/8 of the original is 12.5%",
  "feedback": "This answer is wrong — you gave the fraction instead of the percentage. 1/8 of the original is 12.5%."
 }
]
feedback
{
 "keyExplanation": "Halve 100% once per half-life: 100 → 50 → 25 → 12.5. Because after each half-life, half of the nuclei that remain decay. 12.5% of the original nuclei remain.",
 "anticipatedWrong": [
  {
   "value": 33.33,
   "misconception": "you divided 100% by the number of half-lives — three half-lives means three halvings of what remains",
   "feedback": "This answer is wrong — you divided 100% by the number of half-lives. Three half-lives means three halvings: 100 → 50 → 25 → 12.5."
  },
  {
   "value": 25,
   "misconception": "you halved one time too few — the third halving takes 25% down to 12.5%",
   "feedback": "This answer is wrong — you halved one time too few. The third halving takes 25% down to 12.5%."
  },
  {
   "value": 0.125,
   "misconception": "you gave the fraction instead of the percentage — 1/8 of the original is 12.5%",
   "feedback": "This answer is wrong — you gave the fraction instead of the percentage. 1/8 of the original is 12.5%."
  }
 ]
}
NUC-023 · medium · application · seq 7 · authored:U14-G3 stage 2 (complement read from a given remainder) · mcq4
After 3 half-lives, 1/8 of a sample's original nuclei remains. What fraction of the original nuclei has decayed by then?
7/8 — everything that no longer remains has decayed. KEY
1/8 — the decayed fraction always matches the remaining fraction.
5/8 — one eighth was removed at each of the first two halvings and three eighths at the third.
It cannot be found without knowing the starting mass.
NUC-024 · medium · application · seq 8 · seed:U14-G3.pool[8] (NUC-024 gateItems, James) - MUST_FRESHEN_INSTANCE (72->36->18->9 chain + hydrogen-3/12.3/36.9 collide with kept-verbatim demos p9/p14; construct + misconception set kept; re-minted to lutetium-177) · numeric
A clinic's 216 µg stock of lutetium-177 (half-life 6.6 days) sits unused for 19.8 days. What mass of lutetium-177 remains, in micrograms? Give your answer to the nearest whole number.
Answer: 27 µg KEY
also accepted: 27 µg
wrongValueDiagnostics
[
 {
  "value": 108,
  "misconception": "you halved only once — 19.8 days holds THREE 6.6-day half-lives",
  "feedback": "This answer is wrong — you halved only once. 19.8 days holds THREE 6.6-day half-lives: 216 → 108 → 54 → 27."
 },
 {
  "value": 72,
  "misconception": "you divided the starting amount by the number of half-lives — three half-lives means three halvings, not division by 3",
  "feedback": "This answer is wrong — you divided the starting amount by the number of half-lives. Three half-lives means three halvings: 216 → 108 → 54 → 27."
 },
 {
  "value": 54,
  "misconception": "you halved one time too few — the third halving takes 54 µg down to 27 µg",
  "feedback": "This answer is wrong — you halved one time too few. The third halving takes 54 µg down to 27 µg."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nstarting amount = 216 µg, half-life = 6.6 days, time passed = 19.8 days\nWrite down the equation:\nnumber of half-lives = time passed ÷ half-life\nSubstitute in the values, and calculate:\nnumber of half-lives = 19.8 ÷ 6.6 = 3\nHalve the starting amount three times: 216 → 108 → 54 → 27\n27 µg of lutetium-177 remains.",
 "anticipatedWrong": [
  {
   "value": 108,
   "misconception": "you halved only once — 19.8 days holds THREE 6.6-day half-lives",
   "feedback": "This answer is wrong — you halved only once. 19.8 days holds THREE 6.6-day half-lives: 216 → 108 → 54 → 27."
  },
  {
   "value": 72,
   "misconception": "you divided the starting amount by the number of half-lives — three half-lives means three halvings, not division by 3",
   "feedback": "This answer is wrong — you divided the starting amount by the number of half-lives. Three half-lives means three halvings: 216 → 108 → 54 → 27."
  },
  {
   "value": 54,
   "misconception": "you halved one time too few — the third halving takes 54 µg down to 27 µg",
   "feedback": "This answer is wrong — you halved one time too few. The third halving takes 54 µg down to 27 µg."
  }
 ]
}
NUC-024 · medium · application · seq 9 · authored:U14-G3 stage 2 (fresh forward 2-halving, long half-life) · numeric
A testing laboratory's 372 ng cadmium-109 calibration source has a half-life of 462 days. What mass of cadmium-109 remains after 924 days, in nanograms? Give your answer to the nearest whole number.
Answer: 93 ng KEY
also accepted: 93 ng
wrongValueDiagnostics
[
 {
  "value": 186,
  "misconception": "you halved only once — 924 days holds TWO 462-day half-lives",
  "feedback": "This answer is wrong — you halved only once. 924 days holds TWO 462-day half-lives: 372 → 186 → 93."
 },
 {
  "value": 46.5,
  "misconception": "you halved one time too many — two half-lives means exactly two halvings",
  "feedback": "This answer is wrong — you halved one time too many. Two half-lives means exactly two halvings: 372 → 186 → 93."
 },
 {
  "value": 0,
  "misconception": "you emptied the sample after two half-lives — each half-life removes only half of what remains, so a quarter is left",
  "feedback": "This answer is wrong — you emptied the sample after two half-lives. Each half-life removes only half of what remains: 93 ng is left."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nstarting amount = 372 ng, half-life = 462 days, time passed = 924 days\nWrite down the equation:\nnumber of half-lives = time passed ÷ half-life\nSubstitute in the values, and calculate:\nnumber of half-lives = 924 ÷ 462 = 2\nHalve the starting amount twice: 372 → 186 → 93\n93 ng of cadmium-109 remains.",
 "anticipatedWrong": [
  {
   "value": 186,
   "misconception": "you halved only once — 924 days holds TWO 462-day half-lives",
   "feedback": "This answer is wrong — you halved only once. 924 days holds TWO 462-day half-lives: 372 → 186 → 93."
  },
  {
   "value": 46.5,
   "misconception": "you halved one time too many — two half-lives means exactly two halvings",
   "feedback": "This answer is wrong — you halved one time too many. Two half-lives means exactly two halvings: 372 → 186 → 93."
  },
  {
   "value": 0,
   "misconception": "you emptied the sample after two half-lives — each half-life removes only half of what remains, so a quarter is left",
   "feedback": "This answer is wrong — you emptied the sample after two half-lives. Each half-life removes only half of what remains: 93 ng is left."
  }
 ]
}
NUC-022 · medium · application · seq 10 · authored:U14-G3 stage 2 (cooling facet; value withheld by design — the construct needs none) | blind-1 P7: key wording de-metaphored · mcq4
A biology lab moves its manganese-54 sample from the bench into a deep freezer. What does the freezer do to the manganese-54's half-life?
It stays the same — cold slows the molecules, but decay runs inside the nucleus. KEY
It gets longer — frozen nuclei decay more slowly than warm ones do.
Decay stops entirely until the sample thaws — a frozen clock stands still.
It gets shorter — ice crystals squeeze the nuclei.
NUC-025 · medium · application · seq 11 · authored:U14-G3 stage 2 (fresh inverse production; p9 class) · numeric
Strontium-89 has a half-life of 50.5 days. A clinic's sample of strontium-89 has decayed from 208 µg down to 26 µg. How much time has passed, in days?
Answer: 151.5 days KEY
also accepted: 151.5 days, 151.5 d
wrongValueDiagnostics
[
 {
  "value": 404,
  "misconception": "you used the ratio 208 ÷ 26 = 8 as the number of halvings — 208 µg → 104 µg → 52 µg → 26 µg is 3 halvings",
  "feedback": "This answer is wrong — you used the ratio 208 ÷ 26 = 8 as the number of halvings. 208 µg → 104 µg → 52 µg → 26 µg is 3 halvings: 151.5 days."
 },
 {
  "value": 101,
  "misconception": "you stopped counting one halving early — 208 µg → 104 µg → 52 µg → 26 µg is 3 halvings, not 2",
  "feedback": "This answer is wrong — you stopped counting one halving early. 208 µg → 104 µg → 52 µg → 26 µg is 3 halvings, not 2: 151.5 days."
 }
]
feedback
{
 "keyExplanation": "Count the halvings: 208 µg → 104 µg → 52 µg → 26 µg.\nThe sample has halved 3 times.\ntime passed = number of halvings × half-life\ntime passed = 3 × 50.5 days\ntime passed = 151.5 days",
 "anticipatedWrong": [
  {
   "value": 404,
   "misconception": "you used the ratio 208 ÷ 26 = 8 as the number of halvings — 208 µg → 104 µg → 52 µg → 26 µg is 3 halvings",
   "feedback": "This answer is wrong — you used the ratio 208 ÷ 26 = 8 as the number of halvings. 208 µg → 104 µg → 52 µg → 26 µg is 3 halvings: 151.5 days."
  },
  {
   "value": 101,
   "misconception": "you stopped counting one halving early — 208 µg → 104 µg → 52 µg → 26 µg is 3 halvings, not 2",
   "feedback": "This answer is wrong — you stopped counting one halving early. 208 µg → 104 µg → 52 µg → 26 µg is 3 halvings, not 2: 151.5 days."
  }
 ]
}
NUC-025 · medium · application · seq 12 · authored:U14-G3 stage 2 (count read; ratio-4 trap) · mcq4
A radioactive sample has decayed from 332 g down to 83 g. How many half-lives have passed?
2 KEY
4
1
3
NUC-026 · medium · application · seq 13 · authored:U14-G3 stage 2 (fresh percent curve; half-life read) · numeric
The figure shows the decay curve of antimony-124, plotted as the percent of the sample remaining. Read the half-life of antimony-124 from the curve, in days.
FIGURE (decay-curve · stimulus) — isotope: "antimony-124" · yLabel: "percent of antimony-124 remaining (%)" · yTicks: [0, 25, 50, 75, 100] · xLabel: "time (days)" · xTicks: [0, 60.2, 120.4, 180.6, 240.8] · curvePoints: [[0, 100], [60.2, 50], [120.4, 25], [180.6, 12.5], [240.8, 6.25]] · style: "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
raw spec
{
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "decay-curve",
  "isotope": "antimony-124",
  "yLabel": "percent of antimony-124 remaining (%)",
  "yTicks": [
   0,
   25,
   50,
   75,
   100
  ],
  "xLabel": "time (days)",
  "xTicks": [
   0,
   60.2,
   120.4,
   180.6,
   240.8
  ],
  "curvePoints": [
   [
    0,
    100
   ],
   [
    60.2,
    50
   ],
   [
    120.4,
    25
   ],
   [
    180.6,
    12.5
   ],
   [
    240.8,
    6.25
   ]
  ],
  "style": "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
 }
}
Answer: 60.2 days KEY
also accepted: 60.2 days, 60.2 d
wrongValueDiagnostics
[
 {
  "value": 120.4,
  "misconception": "you read the time for the sample to fall to a quarter — that is two half-lives, not one",
  "feedback": "This answer is wrong — you read the time to fall to a quarter. That is two half-lives; one half-life is 60.2 days."
 },
 {
  "value": 240.8,
  "misconception": "you read the last time labeled on the axis instead of the 50% crossing",
  "feedback": "This answer is wrong — you read the last time on the axis. The 50% crossing sits at 60.2 days."
 }
]
feedback
{
 "keyExplanation": "Half of the starting amount: half of 100% is 50%. The curve reaches 50% at 60.2 days. The half-life of antimony-124 is 60.2 days.",
 "anticipatedWrong": [
  {
   "value": 120.4,
   "misconception": "you read the time for the sample to fall to a quarter — that is two half-lives, not one",
   "feedback": "This answer is wrong — you read the time to fall to a quarter. That is two half-lives; one half-life is 60.2 days."
  },
  {
   "value": 240.8,
   "misconception": "you read the last time labeled on the axis instead of the 50% crossing",
   "feedback": "This answer is wrong — you read the last time on the axis. The 50% crossing sits at 60.2 days."
  }
 ]
}
NUC-026 · medium · application · seq 14 · authored:U14-G3 stage 2 (fresh amount-at-time read) · numeric
The figure shows the decay curve of a 248 µg sample of beryllium-7. Read from the curve the mass remaining at 106.4 days, in µg.
FIGURE (decay-curve · stimulus) — isotope: "beryllium-7" · yLabel: "mass of beryllium-7 remaining (µg)" · yTicks: [0, 31, 62, 93, 124, 155, 186, 217, 248] · xLabel: "time (days)" · xTicks: [0, 53.2, 106.4, 159.6] · curvePoints: [[0, 248], [53.2, 124], [106.4, 62], [159.6, 31]] · style: "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
raw spec
{
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "decay-curve",
  "isotope": "beryllium-7",
  "yLabel": "mass of beryllium-7 remaining (µg)",
  "yTicks": [
   0,
   31,
   62,
   93,
   124,
   155,
   186,
   217,
   248
  ],
  "xLabel": "time (days)",
  "xTicks": [
   0,
   53.2,
   106.4,
   159.6
  ],
  "curvePoints": [
   [
    0,
    248
   ],
   [
    53.2,
    124
   ],
   [
    106.4,
    62
   ],
   [
    159.6,
    31
   ]
  ],
  "style": "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
 }
}
Answer: 62 µg KEY
also accepted: 62 µg
wrongValueDiagnostics
[
 {
  "value": 124,
  "misconception": "you read the mass at 53.2 days instead of 106.4 days",
  "feedback": "This answer is wrong — you read the mass at 53.2 days. At 106.4 days the curve sits at 62 µg."
 },
 {
  "value": 31,
  "misconception": "you read the mass at 159.6 days instead of 106.4 days",
  "feedback": "This answer is wrong — you read the mass at 159.6 days. At 106.4 days the curve sits at 62 µg."
 }
]
feedback
{
 "keyExplanation": "Go up from 106.4 days on the time axis to the curve, then straight across to the mass axis. At 106.4 days, 62 µg of beryllium-7 remains.",
 "anticipatedWrong": [
  {
   "value": 124,
   "misconception": "you read the mass at 53.2 days instead of 106.4 days",
   "feedback": "This answer is wrong — you read the mass at 53.2 days. At 106.4 days the curve sits at 62 µg."
  },
  {
   "value": 31,
   "misconception": "you read the mass at 159.6 days instead of 106.4 days",
   "feedback": "This answer is wrong — you read the mass at 159.6 days. At 106.4 days the curve sits at 62 µg."
  }
 ]
}
NUC-024 · medium · application · seq 15 · authored:U14-G3 stage 2 (diagnosis: halved-once boundary) · mcq4
Whatever the storage time, a student always halves the starting amount exactly once. For which storage time would the answer still come out right?
A time equal to exactly one half-life. KEY
Any storage time — one halving is the whole routine.
A time equal to two half-lives.
No storage time — halving is never the right move.
NUC-023 · medium · application · seq 16 · authored:U14-G3 stage 2 (percent decayed, count 4) · numeric
A radioactive sample completes four half-lives. What percent of its starting nuclei has decayed by then?
Answer: 93.75 % KEY
also accepted: 93.75%, 15/16 as a percent
wrongValueDiagnostics
[
 {
  "value": 6.25,
  "misconception": "you gave the percentage that REMAINS — the question asks for the decayed percentage",
  "feedback": "This answer is wrong — you gave the percentage that REMAINS. Decayed is the rest: 100 − 6.25 = 93.75%."
 },
 {
  "value": 25,
  "misconception": "you divided 100% by the number of half-lives — four half-lives means four halvings of what remains",
  "feedback": "This answer is wrong — you divided 100% by the number of half-lives. Four halvings leave 6.25% remaining, so 93.75% has decayed."
 },
 {
  "value": 50,
  "misconception": "you froze the decayed share at one halving — each later half-life keeps removing half of what remains",
  "feedback": "This answer is wrong — you froze the decayed share at one halving. After four halvings, 93.75% has decayed."
 }
]
feedback
{
 "keyExplanation": "Remaining first: 100 → 50 → 25 → 12.5 → 6.25, because after each half-life, half of the nuclei that remain decay. Decayed is the rest: 100 − 6.25 = 93.75%.",
 "anticipatedWrong": [
  {
   "value": 6.25,
   "misconception": "you gave the percentage that REMAINS — the question asks for the decayed percentage",
   "feedback": "This answer is wrong — you gave the percentage that REMAINS. Decayed is the rest: 100 − 6.25 = 93.75%."
  },
  {
   "value": 25,
   "misconception": "you divided 100% by the number of half-lives — four half-lives means four halvings of what remains",
   "feedback": "This answer is wrong — you divided 100% by the number of half-lives. Four halvings leave 6.25% remaining, so 93.75% has decayed."
  },
  {
   "value": 50,
   "misconception": "you froze the decayed share at one halving — each later half-life keeps removing half of what remains",
   "feedback": "This answer is wrong — you froze the decayed share at one halving. After four halvings, 93.75% has decayed."
  }
 ]
}
NUC-022 · hard · transfer · seq 17 · authored:U14-G3 stage 2 (claim: nucleus-level misread) · mcq4
A student claims: 'One half-life after a sample is prepared, every nucleus in it is half-decayed.' What is wrong with the claim?
Nuclei never half-decay — half of the NUCLEI have decayed completely, and the rest are entirely unchanged. KEY
Nothing is wrong — half-decayed nuclei are what make the sample half as radioactive.
The claim is wrong only because it takes TWO half-lives to half-decay each nucleus.
The claim is wrong because after one half-life ALL of the nuclei have decayed.
NUC-025 · hard · transfer · seq 18 · authored:U14-G3 stage 2 (fresh fraction-form transfer; p10 class) · numeric
Mercury-197 has a half-life of 2.67 days. A sample of mercury-197 has decayed until only 1/4 of the original amount remains. How much time has passed, in days?
Answer: 5.34 days KEY
also accepted: 5.34 days, 5.34 d
wrongValueDiagnostics
[
 {
  "value": 10.68,
  "misconception": "you used the 4 in 1/4 as the number of halvings — 1 → 1/2 → 1/4 is 2 halvings",
  "feedback": "This answer is wrong — you used the 4 in 1/4 as the number of halvings. 1 → 1/2 → 1/4 is 2 halvings: 5.34 days."
 },
 {
  "value": 2.67,
  "misconception": "you counted only one halving — reaching 1/4 takes 2 halvings",
  "feedback": "This answer is wrong — you counted only one halving. Reaching 1/4 takes 2 halvings: 5.34 days."
 }
]
feedback
{
 "keyExplanation": "Count the halvings: 1 → 1/2 → 1/4.\nThe sample has halved 2 times.\ntime passed = number of halvings × half-life\ntime passed = 2 × 2.67 days\ntime passed = 5.34 days",
 "anticipatedWrong": [
  {
   "value": 10.68,
   "misconception": "you used the 4 in 1/4 as the number of halvings — 1 → 1/2 → 1/4 is 2 halvings",
   "feedback": "This answer is wrong — you used the 4 in 1/4 as the number of halvings. 1 → 1/2 → 1/4 is 2 halvings: 5.34 days."
  },
  {
   "value": 2.67,
   "misconception": "you counted only one halving — reaching 1/4 takes 2 halvings",
   "feedback": "This answer is wrong — you counted only one halving. Reaching 1/4 takes 2 halvings: 5.34 days."
  }
 ]
}
NUC-026 · hard · transfer · seq 19 · authored:U14-G3 stage 2 (fresh mass-target inverse read; holmium-166 also anchors C#1 — same-form reuse, design-legal, recorded) · numeric
The figure shows the decay curve of a 376 µg sample of holmium-166. Read from the curve how long it takes for the sample to fall to 94 µg, in hours.
FIGURE (decay-curve · stimulus) — isotope: "holmium-166" · yLabel: "mass of holmium-166 remaining (µg)" · yTicks: [0, 47, 94, 141, 188, 235, 282, 329, 376] · xLabel: "time (hours)" · xTicks: [0, 26.8, 53.6, 80.4] · curvePoints: [[0, 376], [26.8, 188], [53.6, 94], [80.4, 47]] · style: "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
raw spec
{
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "decay-curve",
  "isotope": "holmium-166",
  "yLabel": "mass of holmium-166 remaining (µg)",
  "yTicks": [
   0,
   47,
   94,
   141,
   188,
   235,
   282,
   329,
   376
  ],
  "xLabel": "time (hours)",
  "xTicks": [
   0,
   26.8,
   53.6,
   80.4
  ],
  "curvePoints": [
   [
    0,
    376
   ],
   [
    26.8,
    188
   ],
   [
    53.6,
    94
   ],
   [
    80.4,
    47
   ]
  ],
  "style": "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
 }
}
Answer: 53.6 hours KEY
also accepted: 53.6 hours, 53.6 h
wrongValueDiagnostics
[
 {
  "value": 26.8,
  "misconception": "you read the time for the first halving — 94 µg is a quarter of 376 µg, which takes two halvings",
  "feedback": "This answer is wrong — you read the time for the first halving. 94 µg is a quarter of 376 µg: two halvings, 53.6 hours."
 },
 {
  "value": 80.4,
  "misconception": "you read one halving too far — the curve reaches 94 µg at 53.6 hours, not 47 µg",
  "feedback": "This answer is wrong — you read one halving too far. The curve reaches 94 µg at 53.6 hours."
 }
]
feedback
{
 "keyExplanation": "Find 94 µg on the mass axis. Go across to the curve, then down to the time axis. The sample reaches 94 µg at 53.6 hours.",
 "anticipatedWrong": [
  {
   "value": 26.8,
   "misconception": "you read the time for the first halving — 94 µg is a quarter of 376 µg, which takes two halvings",
   "feedback": "This answer is wrong — you read the time for the first halving. 94 µg is a quarter of 376 µg: two halvings, 53.6 hours."
  },
  {
   "value": 80.4,
   "misconception": "you read one halving too far — the curve reaches 94 µg at 53.6 hours, not 47 µg",
   "feedback": "This answer is wrong — you read one halving too far. The curve reaches 94 µg at 53.6 hours."
  }
 ]
}
NUC-025 · hard · transfer · seq 20 · authored:U14-G3 stage 2 (comparative: size-independence through the inverse routine) · mcq4
A large sample and a small sample of the SAME isotope have each decayed to half of their starting amounts. How do the times they took compare?
They are equal — one halving each, on the same half-life clock. KEY
The large sample took longer — it had more nuclei to work through.
The small sample took longer — fewer decays happen in it each second.
It cannot be compared without knowing the two starting masses.
NUC-025 · hard · application · seq 21 · authored:U14-G3 stage 2 (fresh capstone FRQ; europium-155 instance) · frq
A calibration source contains 284 µg of europium-155, whose half-life is 4.76 years. Years later, only 71 µg of the europium-155 remains.
A calibration source contains 284 µg of europium-155, whose half-life is 4.76 years. Years later, only 71 µg of the europium-155 remains. (a) Write out the halving chain from 284 µg down to 71 µg, and state how many halvings the sample has made. (b) Using the relation 'time passed = number of halvings × half-life', substitute the values and calculate how much time has passed. Give the result with its unit. (c) In one sentence, explain why each halving takes the same amount of time.
Part a. Write out the halving chain from 284 µg down to 71 µg, and state how many halvings the sample has made.
Model: Count the halvings: 284 µg → 142 µg → 71 µg. The sample has halved 2 times.
Part b. Using the relation 'time passed = number of halvings × half-life', substitute the values and calculate how much time has passed. Give the result with its unit.
Model: time passed = number of halvings × half-life time passed = 2 × 4.76 years time passed = 9.52 years
Part c. In one sentence, explain why each halving takes the same amount of time.
Model: Each halving takes exactly one half-life, because after each half-life, half of the nuclei that remain decay.
Full model answer. (a) Count the halvings: 284 µg → 142 µg → 71 µg. The sample has halved 2 times. (b) time passed = number of halvings × half-life time passed = 2 × 4.76 years time passed = 9.52 years (c) Each halving takes exactly one half-life, because after each half-life, half of the nuclei that remain decay.

Form D

NUC-022 · easy · recall · seq 1 · authored:U14-G3 stage 2 (fresh definitional read; long-half-life facet) | stage-2 V-T7 fix: cerium-144 -> germanium-68 (cerium element collided cross-form with the seq-5 cerium-141 seed swap); key rebuilt on the A3-whitelisted canonical frame · mcq4
Germanium-68's half-life is 271 days. Which statement follows from that?
In any sample of germanium-68, half of the nuclei decay over 271 days. KEY
The sample's total mass drops to half in 271 days, because the decayed nuclei vanish.
A sample of germanium-68 lasts 271 days in total before it is all gone.
271 days must pass before any germanium-68 nucleus is able to decay.
NUC-024 · easy · recall · seq 2 · authored:U14-G3 stage 2 (routine recognition, halving-stage facet; divide-by-count trap planted) · mcq4
The number of half-lives has been counted. What does the taught routine do next with the starting amount?
Halve it once for each half-life counted. KEY
Divide it by the number of half-lives.
Subtract the number of half-lives from it.
Halve it once, however many half-lives were counted.
NUC-026 · easy · recall · seq 3 · authored:U14-G3 stage 2 (procedure recognition, trace-start facet) · mcq4
A decay curve has mass on the vertical axis and time on the horizontal axis. To find the mass remaining at a chosen time, where does the trace START?
At the chosen time on the horizontal axis, going up to the curve. KEY
At the starting mass on the vertical axis, going across to the curve.
At the top of the vertical axis, going down the axis line.
At the curve's final point, going backward along the curve.
NUC-022 · medium · application · seq 4 · authored:U14-G3 stage 2 (fresh old-vs-fresh comparison) · mcq4
One sample of tungsten-188 was made years ago and has partly decayed; a second sample was made yesterday. Tungsten-188's half-life is 69.8 days. How do the half-lives of the tungsten-188 in the two samples compare?
They are identical — age and remaining amount never change an isotope's half-life. KEY
The old sample's half-life is longer — its easily-decaying nuclei are already gone.
The fresh sample's half-life is shorter — young samples decay fastest.
They can only be compared when both samples weigh the same.
NUC-023 · medium · application · seq 5 · authored:U14-G3 stage 2 (fresh count 10; p3 class) · text
A sample of niobium-95 sits through 10 half-lives. What fraction of the original niobium-95 nuclei remains?
Answer: 1/1024 KEY
also accepted: 1/1024, 0.0009765625
wrongValueDiagnostics
[
 {
  "value": "1/10",
  "misconception": "you divided the original amount by the number of half-lives — ten half-lives means ten halvings",
  "feedback": "This answer is wrong — you divided the original amount by the number of half-lives. Ten half-lives means ten halvings, ending at 1/1024."
 },
 {
  "value": "1/512",
  "misconception": "you halved one time too few — the tenth halving takes 1/512 to 1/1024",
  "feedback": "This answer is wrong — you halved one time too few. The tenth halving takes 1/512 to 1/1024."
 },
 {
  "value": "0",
  "misconception": "you emptied the sample — each half-life removes only half of what is left",
  "feedback": "This answer is wrong — you emptied the sample. Each half-life removes only half of what is left, so 1/1024 still remains."
 }
]
feedback
{
 "keyExplanation": "Halve once per half-life, ten times over: 1/2, 1/4, ... , 1/512, 1/1024 — because after each half-life, half of the nuclei that remain decay. After 10 half-lives, 1/1024 of the original niobium-95 nuclei remain.",
 "anticipatedWrong": [
  {
   "value": "1/10",
   "misconception": "you divided the original amount by the number of half-lives — ten half-lives means ten halvings",
   "feedback": "This answer is wrong — you divided the original amount by the number of half-lives. Ten half-lives means ten halvings, ending at 1/1024."
  },
  {
   "value": "1/512",
   "misconception": "you halved one time too few — the tenth halving takes 1/512 to 1/1024",
   "feedback": "This answer is wrong — you halved one time too few. The tenth halving takes 1/512 to 1/1024."
  },
  {
   "value": "0",
   "misconception": "you emptied the sample — each half-life removes only half of what is left",
   "feedback": "This answer is wrong — you emptied the sample. Each half-life removes only half of what is left, so 1/1024 still remains."
  }
 ]
}
NUC-023 · medium · application · seq 6 · authored:U14-G3 stage 2 (fresh count 6; p5 class) · numeric
After 6 half-lives, what percentage of the radioactive nuclei a sample started with remains?
Answer: 1.5625 % KEY
also accepted: 1.5625%, 1/64 as a percent
wrongValueDiagnostics
[
 {
  "value": 16.67,
  "misconception": "you divided 100% by the number of half-lives — six half-lives means six halvings of what remains",
  "feedback": "This answer is wrong — you divided 100% by the number of half-lives. Six half-lives means six halvings, ending at 1.5625%."
 },
 {
  "value": 3.125,
  "misconception": "you halved one time too few — the sixth halving takes 3.125% down to 1.5625%",
  "feedback": "This answer is wrong — you halved one time too few. The sixth halving takes 3.125% down to 1.5625%."
 },
 {
  "value": 0.015625,
  "misconception": "you gave the fraction instead of the percentage — 1/64 of the original is 1.5625%",
  "feedback": "This answer is wrong — you gave the fraction instead of the percentage. 1/64 of the original is 1.5625%."
 }
]
feedback
{
 "keyExplanation": "Halve 100% once per half-life, six times: 100 → 50 → 25 → 12.5 → 6.25 → 3.125 → 1.5625. Because after each half-life, half of the nuclei that remain decay. 1.5625% of the original nuclei remain.",
 "anticipatedWrong": [
  {
   "value": 16.67,
   "misconception": "you divided 100% by the number of half-lives — six half-lives means six halvings of what remains",
   "feedback": "This answer is wrong — you divided 100% by the number of half-lives. Six half-lives means six halvings, ending at 1.5625%."
  },
  {
   "value": 3.125,
   "misconception": "you halved one time too few — the sixth halving takes 3.125% down to 1.5625%",
   "feedback": "This answer is wrong — you halved one time too few. The sixth halving takes 3.125% down to 1.5625%."
  },
  {
   "value": 0.015625,
   "misconception": "you gave the fraction instead of the percentage — 1/64 of the original is 1.5625%",
   "feedback": "This answer is wrong — you gave the fraction instead of the percentage. 1/64 of the original is 1.5625%."
  }
 ]
}
NUC-023 · medium · application · seq 7 · authored:U14-G3 stage 2 (all-gone claim rebuttal; fluency-3 class reworded, task = evaluate) | sol-1 S3: D3 rationale made coherent with its value · mcq4
Two half-lives have passed. A student reasons: 'Half decayed in the first half-life and half in the second, so nothing is left.' How much of the original sample actually remains?
1/4 — the second half-life removes half of what remains, not half of the original. KEY
Nothing — the student's two halves account for the whole sample, start to finish.
1/2 — only the first halving really counts.
3/4 — the halvings only ever remove one quarter of the original.
NUC-024 · medium · application · seq 8 · authored:U14-G3 stage 2 (fresh forward 3-halving, mg units) | sol-3: imaging clinic -> supplier lot · numeric
An isotope supplier receives a 296 µg lot of gallium-67 (half-life 3.3 days). The lot is set aside for 9.9 days. What mass of gallium-67 remains, in micrograms? Give your answer to the nearest whole number.
Answer: 37 µg KEY
also accepted: 37 µg
wrongValueDiagnostics
[
 {
  "value": 148,
  "misconception": "you halved only once — 9.9 days holds THREE 3.3-day half-lives",
  "feedback": "This answer is wrong — you halved only once. 9.9 days holds THREE 3.3-day half-lives: 296 → 148 → 74 → 37."
 },
 {
  "value": 98.67,
  "misconception": "you divided the starting amount by the number of half-lives — three half-lives means three halvings, not division by 3",
  "feedback": "This answer is wrong — you divided the starting amount by the number of half-lives. Three half-lives means three halvings: 296 → 148 → 74 → 37."
 },
 {
  "value": 74,
  "misconception": "you halved one time too few — the third halving takes 74 µg down to 37 µg",
  "feedback": "This answer is wrong — you halved one time too few. The third halving takes 74 µg down to 37 µg."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nstarting amount = 296 µg, half-life = 3.3 days, time passed = 9.9 days\nWrite down the equation:\nnumber of half-lives = time passed ÷ half-life\nSubstitute in the values, and calculate:\nnumber of half-lives = 9.9 ÷ 3.3 = 3\nHalve the starting amount three times: 296 → 148 → 74 → 37\n37 µg of gallium-67 remains.",
 "anticipatedWrong": [
  {
   "value": 148,
   "misconception": "you halved only once — 9.9 days holds THREE 3.3-day half-lives",
   "feedback": "This answer is wrong — you halved only once. 9.9 days holds THREE 3.3-day half-lives: 296 → 148 → 74 → 37."
  },
  {
   "value": 98.67,
   "misconception": "you divided the starting amount by the number of half-lives — three half-lives means three halvings, not division by 3",
   "feedback": "This answer is wrong — you divided the starting amount by the number of half-lives. Three half-lives means three halvings: 296 → 148 → 74 → 37."
  },
  {
   "value": 74,
   "misconception": "you halved one time too few — the third halving takes 74 µg down to 37 µg",
   "feedback": "This answer is wrong — you halved one time too few. The third halving takes 74 µg down to 37 µg."
  }
 ]
}
NUC-024 · medium · application · seq 9 · authored:U14-G3 stage 2 (fresh forward 2-halving) | sol-3: tracer-batch framing -> production run · numeric
A production run yields 356 µg of scandium-46, which has a half-life of 83.8 days. The batch is kept behind shielding for 167.6 days. What mass of scandium-46 remains, in micrograms? Give your answer to the nearest whole number.
Answer: 89 µg KEY
also accepted: 89 µg
wrongValueDiagnostics
[
 {
  "value": 178,
  "misconception": "you halved only once — 167.6 days holds TWO 83.8-day half-lives",
  "feedback": "This answer is wrong — you halved only once. 167.6 days holds TWO 83.8-day half-lives: 356 → 178 → 89."
 },
 {
  "value": 44.5,
  "misconception": "you halved one time too many — two half-lives means exactly two halvings",
  "feedback": "This answer is wrong — you halved one time too many. Two half-lives means exactly two halvings: 356 → 178 → 89."
 },
 {
  "value": 188.4,
  "misconception": "you subtracted the days from the micrograms — amounts and times never subtract; count the half-lives, then halve",
  "feedback": "This answer is wrong — you subtracted the days from the micrograms. Count the half-lives, then halve: 89 µg."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nstarting amount = 356 µg, half-life = 83.8 days, time passed = 167.6 days\nWrite down the equation:\nnumber of half-lives = time passed ÷ half-life\nSubstitute in the values, and calculate:\nnumber of half-lives = 167.6 ÷ 83.8 = 2\nHalve the starting amount twice: 356 → 178 → 89\n89 µg of scandium-46 remains.",
 "anticipatedWrong": [
  {
   "value": 178,
   "misconception": "you halved only once — 167.6 days holds TWO 83.8-day half-lives",
   "feedback": "This answer is wrong — you halved only once. 167.6 days holds TWO 83.8-day half-lives: 356 → 178 → 89."
  },
  {
   "value": 44.5,
   "misconception": "you halved one time too many — two half-lives means exactly two halvings",
   "feedback": "This answer is wrong — you halved one time too many. Two half-lives means exactly two halvings: 356 → 178 → 89."
  },
  {
   "value": 188.4,
   "misconception": "you subtracted the days from the micrograms — amounts and times never subtract; count the half-lives, then halve",
   "feedback": "This answer is wrong — you subtracted the days from the micrograms. Count the half-lives, then halve: 89 µg."
  }
 ]
}
NUC-022 · medium · application · seq 10 · authored:U14-G3 stage 2 (chemical-change facet; value withheld — its 100 y is the corpus '100') · mcq4
A technician dissolves a nickel-63 sample in acid, turning the metal into a dissolved nickel compound. What does the reaction do to the nickel-63's half-life?
Nothing — dissolving and bonding rearrange electrons, far outside the nucleus. KEY
It gets shorter — the acid attacks the nuclei.
It gets longer — the compound's other atoms shield the nuclei.
It depends on which acid the technician uses — stronger acids strip the nuclei faster.
NUC-025 · medium · application · seq 11 · authored:U14-G3 stage 2 (fresh inverse production; p9 class, µg units) · numeric
Calcium-47 has a half-life of 4.5 days. A lab's sample of calcium-47 has decayed from 272 µg down to 34 µg. How much time has passed, in days?
Answer: 13.5 days KEY
also accepted: 13.5 days, 13.5 d
wrongValueDiagnostics
[
 {
  "value": 36,
  "misconception": "you used the ratio 272 ÷ 34 = 8 as the number of halvings — 272 µg → 136 µg → 68 µg → 34 µg is 3 halvings",
  "feedback": "This answer is wrong — you used the ratio 272 ÷ 34 = 8 as the number of halvings. 272 µg → 136 µg → 68 µg → 34 µg is 3 halvings: 13.5 days."
 },
 {
  "value": 9,
  "misconception": "you stopped counting one halving early — 272 µg → 136 µg → 68 µg → 34 µg is 3 halvings, not 2",
  "feedback": "This answer is wrong — you stopped counting one halving early. 272 µg → 136 µg → 68 µg → 34 µg is 3 halvings, not 2: 13.5 days."
 }
]
feedback
{
 "keyExplanation": "Count the halvings: 272 µg → 136 µg → 68 µg → 34 µg.\nThe sample has halved 3 times.\ntime passed = number of halvings × half-life\ntime passed = 3 × 4.5 days\ntime passed = 13.5 days",
 "anticipatedWrong": [
  {
   "value": 36,
   "misconception": "you used the ratio 272 ÷ 34 = 8 as the number of halvings — 272 µg → 136 µg → 68 µg → 34 µg is 3 halvings",
   "feedback": "This answer is wrong — you used the ratio 272 ÷ 34 = 8 as the number of halvings. 272 µg → 136 µg → 68 µg → 34 µg is 3 halvings: 13.5 days."
  },
  {
   "value": 9,
   "misconception": "you stopped counting one halving early — 272 µg → 136 µg → 68 µg → 34 µg is 3 halvings, not 2",
   "feedback": "This answer is wrong — you stopped counting one halving early. 272 µg → 136 µg → 68 µg → 34 µg is 3 halvings, not 2: 13.5 days."
  }
 ]
}
NUC-025 · medium · application · seq 12 · authored:U14-G3 stage 2 (count read; 5-halving chain) | stage-2 V-T7 fix: 288->9 pair replaced with 416->13 ('down to 9 g' collided with the A#11 demo stem cross-form) · mcq4
A radioactive sample has decayed from 416 g down to 13 g. How many half-lives have passed?
5 KEY
4
6
10
NUC-026 · medium · application · seq 13 · authored:U14-G3 stage 2 (fresh percent curve; half-life read) · numeric
The figure shows the decay curve of thulium-170, plotted as the percent of the sample remaining. Read the half-life of thulium-170 from the curve, in days.
FIGURE (decay-curve · stimulus) — isotope: "thulium-170" · yLabel: "percent of thulium-170 remaining (%)" · yTicks: [0, 25, 50, 75, 100] · xLabel: "time (days)" · xTicks: [0, 128.6, 257.2, 385.8, 514.4] · curvePoints: [[0, 100], [128.6, 50], [257.2, 25], [385.8, 12.5], [514.4, 6.25]] · style: "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
raw spec
{
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "decay-curve",
  "isotope": "thulium-170",
  "yLabel": "percent of thulium-170 remaining (%)",
  "yTicks": [
   0,
   25,
   50,
   75,
   100
  ],
  "xLabel": "time (days)",
  "xTicks": [
   0,
   128.6,
   257.2,
   385.8,
   514.4
  ],
  "curvePoints": [
   [
    0,
    100
   ],
   [
    128.6,
    50
   ],
   [
    257.2,
    25
   ],
   [
    385.8,
    12.5
   ],
   [
    514.4,
    6.25
   ]
  ],
  "style": "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
 }
}
Answer: 128.6 days KEY
also accepted: 128.6 days, 128.6 d
wrongValueDiagnostics
[
 {
  "value": 257.2,
  "misconception": "you read the time for the sample to fall to a quarter — that is two half-lives, not one",
  "feedback": "This answer is wrong — you read the time to fall to a quarter. That is two half-lives; one half-life is 128.6 days."
 },
 {
  "value": 514.4,
  "misconception": "you read the last time labeled on the axis instead of the 50% crossing",
  "feedback": "This answer is wrong — you read the last time on the axis. The 50% crossing sits at 128.6 days."
 }
]
feedback
{
 "keyExplanation": "Half of the starting amount: half of 100% is 50%. The curve reaches 50% at 128.6 days. The half-life of thulium-170 is 128.6 days.",
 "anticipatedWrong": [
  {
   "value": 257.2,
   "misconception": "you read the time for the sample to fall to a quarter — that is two half-lives, not one",
   "feedback": "This answer is wrong — you read the time to fall to a quarter. That is two half-lives; one half-life is 128.6 days."
  },
  {
   "value": 514.4,
   "misconception": "you read the last time labeled on the axis instead of the 50% crossing",
   "feedback": "This answer is wrong — you read the last time on the axis. The 50% crossing sits at 128.6 days."
  }
 ]
}
NUC-026 · medium · application · seq 14 · authored:U14-G3 stage 2 (fresh amount-at-time read) · numeric
The figure shows the decay curve of a 132 mg sample of terbium-160. Read from the curve the mass remaining at 144.6 days, in mg.
FIGURE (decay-curve · stimulus) — isotope: "terbium-160" · yLabel: "mass of terbium-160 remaining (mg)" · yTicks: [0, 16.5, 33, 49.5, 66, 82.5, 99, 115.5, 132] · xLabel: "time (days)" · xTicks: [0, 72.3, 144.6, 216.9] · curvePoints: [[0, 132], [72.3, 66], [144.6, 33], [216.9, 16.5]] · style: "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
raw spec
{
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "decay-curve",
  "isotope": "terbium-160",
  "yLabel": "mass of terbium-160 remaining (mg)",
  "yTicks": [
   0,
   16.5,
   33,
   49.5,
   66,
   82.5,
   99,
   115.5,
   132
  ],
  "xLabel": "time (days)",
  "xTicks": [
   0,
   72.3,
   144.6,
   216.9
  ],
  "curvePoints": [
   [
    0,
    132
   ],
   [
    72.3,
    66
   ],
   [
    144.6,
    33
   ],
   [
    216.9,
    16.5
   ]
  ],
  "style": "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
 }
}
Answer: 33 mg KEY
also accepted: 33 mg
wrongValueDiagnostics
[
 {
  "value": 66,
  "misconception": "you read the mass at 72.3 days instead of 144.6 days",
  "feedback": "This answer is wrong — you read the mass at 72.3 days. At 144.6 days the curve sits at 33 mg."
 },
 {
  "value": 16.5,
  "misconception": "you read the mass at 216.9 days instead of 144.6 days",
  "feedback": "This answer is wrong — you read the mass at 216.9 days. At 144.6 days the curve sits at 33 mg."
 }
]
feedback
{
 "keyExplanation": "Go up from 144.6 days on the time axis to the curve, then straight across to the mass axis. At 144.6 days, 33 mg of terbium-160 remains.",
 "anticipatedWrong": [
  {
   "value": 66,
   "misconception": "you read the mass at 72.3 days instead of 144.6 days",
   "feedback": "This answer is wrong — you read the mass at 72.3 days. At 144.6 days the curve sits at 33 mg."
  },
  {
   "value": 16.5,
   "misconception": "you read the mass at 216.9 days instead of 144.6 days",
   "feedback": "This answer is wrong — you read the mass at 216.9 days. At 144.6 days the curve sits at 33 mg."
  }
 ]
}
NUC-024 · medium · application · seq 15 · authored:U14-G3 stage 2 (diagnosis: multiplied-instead trap) · mcq4
A student multiplies the time passed by the half-life and calls the result 'the number of half-lives'. What should the student have done?
Divide the time passed by the half-life — that division gives the count of half-lives. KEY
Multiply the starting amount by the half-life instead.
Divide the half-life by the time passed instead, keeping the same two values.
Nothing — multiplying the two times gives the same count.
NUC-023 · medium · application · seq 16 · authored:U14-G3 stage 2 (percent decayed, count 5) · numeric
A radioactive sample completes five half-lives. What percent of its starting nuclei has decayed by then?
Answer: 96.875 % KEY
also accepted: 96.875%, 31/32 as a percent
wrongValueDiagnostics
[
 {
  "value": 3.125,
  "misconception": "you gave the percentage that REMAINS — the question asks for the decayed percentage",
  "feedback": "This answer is wrong — you gave the percentage that REMAINS. Decayed is the rest: 100 − 3.125 = 96.875%."
 },
 {
  "value": 20,
  "misconception": "you divided 100% by the number of half-lives — five half-lives means five halvings of what remains",
  "feedback": "This answer is wrong — you divided 100% by the number of half-lives. Five halvings leave 3.125% remaining, so 96.875% has decayed."
 },
 {
  "value": 50,
  "misconception": "you froze the decayed share at one halving — each later half-life keeps removing half of what remains",
  "feedback": "This answer is wrong — you froze the decayed share at one halving. After five halvings, 96.875% has decayed."
 }
]
feedback
{
 "keyExplanation": "Remaining first: 100 → 50 → 25 → 12.5 → 6.25 → 3.125, because after each half-life, half of the nuclei that remain decay. Decayed is the rest: 100 − 3.125 = 96.875%.",
 "anticipatedWrong": [
  {
   "value": 3.125,
   "misconception": "you gave the percentage that REMAINS — the question asks for the decayed percentage",
   "feedback": "This answer is wrong — you gave the percentage that REMAINS. Decayed is the rest: 100 − 3.125 = 96.875%."
  },
  {
   "value": 20,
   "misconception": "you divided 100% by the number of half-lives — five half-lives means five halvings of what remains",
   "feedback": "This answer is wrong — you divided 100% by the number of half-lives. Five halvings leave 3.125% remaining, so 96.875% has decayed."
  },
  {
   "value": 50,
   "misconception": "you froze the decayed share at one halving — each later half-life keeps removing half of what remains",
   "feedback": "This answer is wrong — you froze the decayed share at one halving. After five halvings, 96.875% has decayed."
  }
 ]
}
NUC-022 · hard · transfer · seq 17 · authored:U14-G3 stage 2 (claim: per-nucleus schedule) · mcq4
A student claims: 'An isotope's half-life tells you exactly when each individual nucleus will decay.' What is wrong with the claim?
The half-life describes the sample as a whole — no individual nucleus has a schedule. KEY
Nothing is wrong — that is exactly what a half-life is for.
The claim is wrong only for very small samples, where the schedule breaks down.
It actually tells you when the nucleus FORMED, not when it will decay.
NUC-025 · hard · transfer · seq 18 · authored:U14-G3 stage 2 (fresh fraction-form transfer; p10 class) · numeric
Ruthenium-97 has a half-life of 2.9 days. A sample of ruthenium-97 has decayed until only 1/8 of the original amount remains. How much time has passed, in days?
Answer: 8.7 days KEY
also accepted: 8.7 days, 8.7 d
wrongValueDiagnostics
[
 {
  "value": 23.2,
  "misconception": "you used the 8 in 1/8 as the number of halvings — 1 → 1/2 → 1/4 → 1/8 is 3 halvings",
  "feedback": "This answer is wrong — you used the 8 in 1/8 as the number of halvings. 1 → 1/2 → 1/4 → 1/8 is 3 halvings: 8.7 days."
 },
 {
  "value": 5.8,
  "misconception": "you stopped counting at 1/4 — reaching 1/8 takes 3 halvings, not 2",
  "feedback": "This answer is wrong — you stopped counting at 1/4. Reaching 1/8 takes 3 halvings, not 2: 8.7 days."
 }
]
feedback
{
 "keyExplanation": "Count the halvings: 1 → 1/2 → 1/4 → 1/8.\nThe sample has halved 3 times.\ntime passed = number of halvings × half-life\ntime passed = 3 × 2.9 days\ntime passed = 8.7 days",
 "anticipatedWrong": [
  {
   "value": 23.2,
   "misconception": "you used the 8 in 1/8 as the number of halvings — 1 → 1/2 → 1/4 → 1/8 is 3 halvings",
   "feedback": "This answer is wrong — you used the 8 in 1/8 as the number of halvings. 1 → 1/2 → 1/4 → 1/8 is 3 halvings: 8.7 days."
  },
  {
   "value": 5.8,
   "misconception": "you stopped counting at 1/4 — reaching 1/8 takes 3 halvings, not 2",
   "feedback": "This answer is wrong — you stopped counting at 1/4. Reaching 1/8 takes 3 halvings, not 2: 8.7 days."
  }
 ]
}
NUC-026 · hard · transfer · seq 19 · authored:U14-G3 stage 2 (fresh mass-target inverse read) · numeric
The figure shows the decay curve of a 456 g sample of yttrium-91. Read from the curve how long it takes for the sample to fall to 114 g, in days.
FIGURE (decay-curve · stimulus) — isotope: "yttrium-91" · yLabel: "mass of yttrium-91 remaining (g)" · yTicks: [0, 57, 114, 171, 228, 285, 342, 399, 456] · xLabel: "time (days)" · xTicks: [0, 58.5, 117, 175.5] · curvePoints: [[0, 456], [58.5, 228], [117, 114], [175.5, 57]] · style: "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
raw spec
{
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "decay-curve",
  "isotope": "yttrium-91",
  "yLabel": "mass of yttrium-91 remaining (g)",
  "yTicks": [
   0,
   57,
   114,
   171,
   228,
   285,
   342,
   399,
   456
  ],
  "xLabel": "time (days)",
  "xTicks": [
   0,
   58.5,
   117,
   175.5
  ],
  "curvePoints": [
   [
    0,
    456
   ],
   [
    58.5,
    228
   ],
   [
    117,
    114
   ],
   [
    175.5,
    57
   ]
  ],
  "style": "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
 }
}
Answer: 117 days KEY
also accepted: 117 days, 117 d
wrongValueDiagnostics
[
 {
  "value": 58.5,
  "misconception": "you read the time for the first halving — 114 g is a quarter of 456 g, which takes two halvings",
  "feedback": "This answer is wrong — you read the time for the first halving. 114 g is a quarter of 456 g: two halvings, 117 days."
 },
 {
  "value": 175.5,
  "misconception": "you read one halving too far — the curve reaches 114 g at 117 days, not 57 g",
  "feedback": "This answer is wrong — you read one halving too far. The curve reaches 114 g at 117 days."
 }
]
feedback
{
 "keyExplanation": "Find 114 g on the mass axis. Go across to the curve, then down to the time axis. The sample reaches 114 g at 117 days.",
 "anticipatedWrong": [
  {
   "value": 58.5,
   "misconception": "you read the time for the first halving — 114 g is a quarter of 456 g, which takes two halvings",
   "feedback": "This answer is wrong — you read the time for the first halving. 114 g is a quarter of 456 g: two halvings, 117 days."
  },
  {
   "value": 175.5,
   "misconception": "you read one halving too far — the curve reaches 114 g at 117 days, not 57 g",
   "feedback": "This answer is wrong — you read one halving too far. The curve reaches 114 g at 117 days."
  }
 ]
}
NUC-025 · hard · transfer · seq 20 · authored:U14-G3 stage 2 (comparative: unequal counts, equal half-lives) · mcq4
Samples of two isotopes with the SAME half-life are compared: X has decayed to one eighth of its start; Y has decayed to half of its start. Which sample has been decaying longer?
X — one eighth takes three halvings, while half takes only one, on equal clocks. KEY
Y — reaching half is the slowest part of any decay.
They have decayed equally long, because the half-life is the same.
It depends on which sample started with more nuclei — bigger starts run longer.
NUC-025 · hard · application · seq 21 · authored:U14-G3 stage 2 (fresh capstone FRQ; xenon-127 instance) · frq
A sealed vial holds 484 mg of xenon-127, whose half-life is 36.4 days. Later, only 121 mg of the xenon-127 remains.
A sealed vial holds 484 mg of xenon-127, whose half-life is 36.4 days. Later, only 121 mg of the xenon-127 remains. (a) Write out the halving chain from 484 mg down to 121 mg, and state how many halvings the sample has made. (b) Using the relation 'time passed = number of halvings × half-life', substitute the values and calculate how much time has passed. Give the result with its unit. (c) In one sentence, explain why each halving takes the same amount of time.
Part a. Write out the halving chain from 484 mg down to 121 mg, and state how many halvings the sample has made.
Model: Count the halvings: 484 mg → 242 mg → 121 mg. The sample has halved 2 times.
Part b. Using the relation 'time passed = number of halvings × half-life', substitute the values and calculate how much time has passed. Give the result with its unit.
Model: time passed = number of halvings × half-life time passed = 2 × 36.4 days time passed = 72.8 days
Part c. In one sentence, explain why each halving takes the same amount of time.
Model: Each halving takes exactly one half-life, because after each half-life, half of the nuclei that remain decay.
Full model answer. (a) Count the halvings: 484 mg → 242 mg → 121 mg. The sample has halved 2 times. (b) time passed = number of halvings × half-life time passed = 2 × 36.4 days time passed = 72.8 days (c) Each halving takes exactly one half-life, because after each half-life, half of the nuclei that remain decay.

Form E

NUC-022 · easy · recall · seq 1 · authored:U14-G3 stage 2 (fresh definitional read; hour-scale facet) · mcq4
Samarium-153 is given for bone pain and has a half-life of 46.3 hours. What does the half-life tell you?
In 46.3 hours, half of the samarium-153 nuclei in any sample decay. KEY
It tells you how long a sample stays radioactive in total: 46.3 hours.
It tells you that each samarium-153 nucleus decays exactly 46.3 hours after it forms.
It tells you nothing until you also know the sample's mass.
NUC-024 · easy · recall · seq 2 · authored:U14-G3 stage 2 (routine recognition, whole-plan facet) · mcq4
A sample's starting amount, its isotope's half-life, and its storage time are all known. Which plan finds the mass remaining?
Count half-lives via time ÷ half-life, then halve the amount once per half-life. KEY
Divide the starting amount by the storage time.
Halve the starting amount a single time, no matter how long the storage lasted.
Multiply the starting amount by the number of half-lives.
NUC-026 · easy · recall · seq 3 · authored:U14-G3 stage 2 (procedure recognition, half-of-start-vs-axis trap as procedure) | sol-1 S4: reframed to method-validity (midpoint coincides on a 2-half-life span) · mcq4
Two students read a half-life from the same decay curve. One reads the time below the point where the amount has fallen to half its STARTING value; the other takes the halfway point of the time axis. Whose method reads the half-life correctly on any decay curve?
The first student's — read the time where the amount has fallen to half its start, whatever the axis spans. KEY
The second student's — the axis midpoint balances the whole graph evenly on both sides.
Both methods — the two readings always land on the same time.
Neither student's — a half-life can only be found by calculation, never from a graph.
NUC-022 · medium · application · seq 4 · authored:U14-G3 stage 2 (fresh size-comparison read) | sol-2 T4: kilogram museum inventory -> milligram/gram lab contrast | blind-5: contrast downscaled again (r9: 1 g Bi-207 = 2 TBq) · mcq4
A lab stores one microgram of bismuth-207; a calibration supplier stores one milligram of the same bismuth-207. Its half-life is 31.6 years. Which sample's bismuth-207 has the longer half-life?
Neither — both half-lives are 31.6 years, whatever the amount. KEY
The milligram's — working through a thousand times more nuclei takes longer.
The microgram's — a small sample decays more gently.
Whichever sample is stored in the cooler room.
NUC-023 · medium · application · seq 5 · authored:U14-G3 stage 2 (fresh count 11; p3 class) · text
A sample of europium-152 sits through 11 half-lives. What fraction of the original europium-152 nuclei remains?
Answer: 1/2048 KEY
also accepted: 1/2048, 0.00048828125
wrongValueDiagnostics
[
 {
  "value": "1/11",
  "misconception": "you divided the original amount by the number of half-lives — eleven half-lives means eleven halvings",
  "feedback": "This answer is wrong — you divided the original amount by the number of half-lives. Eleven half-lives means eleven halvings, ending at 1/2048."
 },
 {
  "value": "1/1024",
  "misconception": "you halved one time too few — the eleventh halving takes 1/1024 to 1/2048",
  "feedback": "This answer is wrong — you halved one time too few. The eleventh halving takes 1/1024 to 1/2048."
 },
 {
  "value": "0",
  "misconception": "you emptied the sample — each half-life removes only half of what is left",
  "feedback": "This answer is wrong — you emptied the sample. Each half-life removes only half of what is left, so 1/2048 still remains."
 }
]
feedback
{
 "keyExplanation": "Halve once per half-life, eleven times over: 1/2, 1/4, ... , 1/1024, 1/2048 — because after each half-life, half of the nuclei that remain decay. After 11 half-lives, 1/2048 of the original europium-152 nuclei remain.",
 "anticipatedWrong": [
  {
   "value": "1/11",
   "misconception": "you divided the original amount by the number of half-lives — eleven half-lives means eleven halvings",
   "feedback": "This answer is wrong — you divided the original amount by the number of half-lives. Eleven half-lives means eleven halvings, ending at 1/2048."
  },
  {
   "value": "1/1024",
   "misconception": "you halved one time too few — the eleventh halving takes 1/1024 to 1/2048",
   "feedback": "This answer is wrong — you halved one time too few. The eleventh halving takes 1/1024 to 1/2048."
  },
  {
   "value": "0",
   "misconception": "you emptied the sample — each half-life removes only half of what is left",
   "feedback": "This answer is wrong — you emptied the sample. Each half-life removes only half of what is left, so 1/2048 still remains."
  }
 ]
}
NUC-023 · medium · application · seq 6 · authored:U14-G3 stage 2 (fresh count 2; p5 class) · numeric
A radioactive sample sits through 2 half-lives. What percentage of its original radioactive nuclei remains?
Answer: 25 % KEY
also accepted: 25%, 1/4 as a percent
wrongValueDiagnostics
[
 {
  "value": 50,
  "misconception": "you divided 100% by the number of half-lives (or halved once) — two half-lives means two halvings of what remains",
  "feedback": "This answer is wrong — you halved only once (or divided 100% by the number of half-lives). Two half-lives means two successive halvings of what remains: 100 → 50 → 25."
 },
 {
  "value": 0,
  "misconception": "you emptied the sample by adding half plus half — the second half-life removes half OF WHAT REMAINS, leaving a quarter",
  "feedback": "This answer is wrong — you emptied the sample by adding half plus half. The second half-life removes half OF WHAT REMAINS, leaving 25%."
 },
 {
  "value": 0.25,
  "misconception": "you gave the fraction instead of the percentage — 1/4 of the original is 25%",
  "feedback": "This answer is wrong — you gave the fraction instead of the percentage. 1/4 of the original is 25%."
 }
]
feedback
{
 "keyExplanation": "Halve 100% once per half-life: 100 → 50 → 25. Because after each half-life, half of the nuclei that remain decay. 25% of the original nuclei remain.",
 "anticipatedWrong": [
  {
   "value": 50,
   "misconception": "you divided 100% by the number of half-lives (or halved once) — two half-lives means two halvings of what remains",
   "feedback": "This answer is wrong — you halved only once (or divided 100% by the number of half-lives). Two half-lives means two successive halvings of what remains: 100 → 50 → 25."
  },
  {
   "value": 0,
   "misconception": "you emptied the sample by adding half plus half — the second half-life removes half OF WHAT REMAINS, leaving a quarter",
   "feedback": "This answer is wrong — you emptied the sample by adding half plus half. The second half-life removes half OF WHAT REMAINS, leaving 25%."
  },
  {
   "value": 0.25,
   "misconception": "you gave the fraction instead of the percentage — 1/4 of the original is 25%",
   "feedback": "This answer is wrong — you gave the fraction instead of the percentage. 1/4 of the original is 25%."
  }
 ]
}
NUC-023 · medium · application · seq 7 · authored:U14-G3 stage 2 (universality read: ladder is isotope-independent) · mcq4
Samples of two DIFFERENT radioactive isotopes each sit through the same number of half-lives (of their own isotope). How do the two remaining fractions compare?
They are equal — after the same number of halvings, the same fraction remains, whatever the isotope. KEY
The isotope with the longer half-life keeps the larger fraction — slower clocks hold more back.
The isotope with the shorter half-life keeps the larger fraction — it is used to decaying.
There is no way to compare them unless both starting amounts are given.
NUC-024 · medium · application · seq 8 · authored:U14-G3 stage 2 (fresh forward 3-halving, ng units) · numeric
A research lab labels antibodies with 472 ng of indium-111 (half-life 2.8 days), then stores the batch for 8.4 days. What mass of indium-111 remains, in nanograms? Give your answer to the nearest whole number.
Answer: 59 ng KEY
also accepted: 59 ng
wrongValueDiagnostics
[
 {
  "value": 236,
  "misconception": "you halved only once — 8.4 days holds THREE 2.8-day half-lives",
  "feedback": "This answer is wrong — you halved only once. 8.4 days holds THREE 2.8-day half-lives: 472 → 236 → 118 → 59."
 },
 {
  "value": 157.33,
  "misconception": "you divided the starting amount by the number of half-lives — three half-lives means three halvings, not division by 3",
  "feedback": "This answer is wrong — you divided the starting amount by the number of half-lives. Three half-lives means three halvings: 472 → 236 → 118 → 59."
 },
 {
  "value": 118,
  "misconception": "you halved one time too few — the third halving takes 118 ng down to 59 ng",
  "feedback": "This answer is wrong — you halved one time too few. The third halving takes 118 ng down to 59 ng."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nstarting amount = 472 ng, half-life = 2.8 days, time passed = 8.4 days\nWrite down the equation:\nnumber of half-lives = time passed ÷ half-life\nSubstitute in the values, and calculate:\nnumber of half-lives = 8.4 ÷ 2.8 = 3\nHalve the starting amount three times: 472 → 236 → 118 → 59\n59 ng of indium-111 remains.",
 "anticipatedWrong": [
  {
   "value": 236,
   "misconception": "you halved only once — 8.4 days holds THREE 2.8-day half-lives",
   "feedback": "This answer is wrong — you halved only once. 8.4 days holds THREE 2.8-day half-lives: 472 → 236 → 118 → 59."
  },
  {
   "value": 157.33,
   "misconception": "you divided the starting amount by the number of half-lives — three half-lives means three halvings, not division by 3",
   "feedback": "This answer is wrong — you divided the starting amount by the number of half-lives. Three half-lives means three halvings: 472 → 236 → 118 → 59."
  },
  {
   "value": 118,
   "misconception": "you halved one time too few — the third halving takes 118 ng down to 59 ng",
   "feedback": "This answer is wrong — you halved one time too few. The third halving takes 118 ng down to 59 ng."
  }
 ]
}
NUC-024 · medium · application · seq 9 · authored:U14-G3 stage 2 (fresh forward 2-halving; the fridge is storage flavor only — conditions never change the half-life) · numeric
A 316 ng sample of praseodymium-143 (half-life 13.6 days) is left in a sample fridge for 27.2 days. What mass of praseodymium-143 remains, in nanograms? Give your answer to the nearest whole number.
Answer: 79 ng KEY
also accepted: 79 ng
wrongValueDiagnostics
[
 {
  "value": 158,
  "misconception": "you halved only once — 27.2 days holds TWO 13.6-day half-lives",
  "feedback": "This answer is wrong — you halved only once. 27.2 days holds TWO 13.6-day half-lives: 316 → 158 → 79."
 },
 {
  "value": 39.5,
  "misconception": "you halved one time too many — two half-lives means exactly two halvings",
  "feedback": "This answer is wrong — you halved one time too many. Two half-lives means exactly two halvings: 316 → 158 → 79."
 },
 {
  "value": 288.8,
  "misconception": "you subtracted the days from the nanograms — amounts and times never subtract; count the half-lives, then halve",
  "feedback": "This answer is wrong — you subtracted the days from the nanograms. Count the half-lives, then halve: 79 ng."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nstarting amount = 316 ng, half-life = 13.6 days, time passed = 27.2 days\nWrite down the equation:\nnumber of half-lives = time passed ÷ half-life\nSubstitute in the values, and calculate:\nnumber of half-lives = 27.2 ÷ 13.6 = 2\nHalve the starting amount twice: 316 → 158 → 79\n79 ng of praseodymium-143 remains.",
 "anticipatedWrong": [
  {
   "value": 158,
   "misconception": "you halved only once — 27.2 days holds TWO 13.6-day half-lives",
   "feedback": "This answer is wrong — you halved only once. 27.2 days holds TWO 13.6-day half-lives: 316 → 158 → 79."
  },
  {
   "value": 39.5,
   "misconception": "you halved one time too many — two half-lives means exactly two halvings",
   "feedback": "This answer is wrong — you halved one time too many. Two half-lives means exactly two halvings: 316 → 158 → 79."
  },
  {
   "value": 288.8,
   "misconception": "you subtracted the days from the nanograms — amounts and times never subtract; count the half-lives, then halve",
   "feedback": "This answer is wrong — you subtracted the days from the nanograms. Count the half-lives, then halve: 79 ng."
  }
 ]
}
NUC-022 · medium · application · seq 10 · authored:U14-G3 stage 2 (pressure facet, fresh) · mcq4
Promethium-147, half-life 2.6 years, is sealed into a high-pressure canister. How does the pressure affect its half-life?
Not at all — it stays 2.6 years at any pressure. KEY
The half-life shortens — squeezed nuclei are forced to decay.
The half-life lengthens — the packed atoms pin the nuclei in place.
It depends on the canister's material.
NUC-025 · medium · application · seq 11 · authored:U14-G3 stage 2 (fresh inverse production; p9 class) · numeric
Hafnium-181 has a half-life of 42.4 days. A sample of hafnium-181 has decayed from 328 g down to 41 g. How much time has passed, in days?
Answer: 127.2 days KEY
also accepted: 127.2 days, 127.2 d
wrongValueDiagnostics
[
 {
  "value": 339.2,
  "misconception": "you used the ratio 328 ÷ 41 = 8 as the number of halvings — 328 g → 164 g → 82 g → 41 g is 3 halvings",
  "feedback": "This answer is wrong — you used the ratio 328 ÷ 41 = 8 as the number of halvings. 328 g → 164 g → 82 g → 41 g is 3 halvings: 127.2 days."
 },
 {
  "value": 84.8,
  "misconception": "you stopped counting one halving early — 328 g → 164 g → 82 g → 41 g is 3 halvings, not 2",
  "feedback": "This answer is wrong — you stopped counting one halving early. 328 g → 164 g → 82 g → 41 g is 3 halvings, not 2: 127.2 days."
 }
]
feedback
{
 "keyExplanation": "Count the halvings: 328 g → 164 g → 82 g → 41 g.\nThe sample has halved 3 times.\ntime passed = number of halvings × half-life\ntime passed = 3 × 42.4 days\ntime passed = 127.2 days",
 "anticipatedWrong": [
  {
   "value": 339.2,
   "misconception": "you used the ratio 328 ÷ 41 = 8 as the number of halvings — 328 g → 164 g → 82 g → 41 g is 3 halvings",
   "feedback": "This answer is wrong — you used the ratio 328 ÷ 41 = 8 as the number of halvings. 328 g → 164 g → 82 g → 41 g is 3 halvings: 127.2 days."
  },
  {
   "value": 84.8,
   "misconception": "you stopped counting one halving early — 328 g → 164 g → 82 g → 41 g is 3 halvings, not 2",
   "feedback": "This answer is wrong — you stopped counting one halving early. 328 g → 164 g → 82 g → 41 g is 3 halvings, not 2: 127.2 days."
  }
 ]
}
NUC-025 · medium · application · seq 12 · authored:U14-G3 stage 2 (count read; ratio-8 trap) · mcq4
A radioactive sample has decayed from 424 g down to 53 g. How many half-lives have passed?
3 KEY
8
2
4
NUC-026 · medium · application · seq 13 · authored:U14-G3 stage 2 (fresh percent curve; half-life read) · numeric
The figure shows the decay curve of tantalum-182, plotted as the percent of the sample remaining. Read the half-life of tantalum-182 from the curve, in days.
FIGURE (decay-curve · stimulus) — isotope: "tantalum-182" · yLabel: "percent of tantalum-182 remaining (%)" · yTicks: [0, 25, 50, 75, 100] · xLabel: "time (days)" · xTicks: [0, 114.4, 228.8, 343.2, 457.6] · curvePoints: [[0, 100], [114.4, 50], [228.8, 25], [343.2, 12.5], [457.6, 6.25]] · style: "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
raw spec
{
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "decay-curve",
  "isotope": "tantalum-182",
  "yLabel": "percent of tantalum-182 remaining (%)",
  "yTicks": [
   0,
   25,
   50,
   75,
   100
  ],
  "xLabel": "time (days)",
  "xTicks": [
   0,
   114.4,
   228.8,
   343.2,
   457.6
  ],
  "curvePoints": [
   [
    0,
    100
   ],
   [
    114.4,
    50
   ],
   [
    228.8,
    25
   ],
   [
    343.2,
    12.5
   ],
   [
    457.6,
    6.25
   ]
  ],
  "style": "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
 }
}
Answer: 114.4 days KEY
also accepted: 114.4 days, 114.4 d
wrongValueDiagnostics
[
 {
  "value": 228.8,
  "misconception": "you read the time for the sample to fall to a quarter — that is two half-lives, not one",
  "feedback": "This answer is wrong — you read the time to fall to a quarter. That is two half-lives; one half-life is 114.4 days."
 },
 {
  "value": 457.6,
  "misconception": "you read the last time labeled on the axis instead of the 50% crossing",
  "feedback": "This answer is wrong — you read the last time on the axis. The 50% crossing sits at 114.4 days."
 }
]
feedback
{
 "keyExplanation": "Half of the starting amount: half of 100% is 50%. The curve reaches 50% at 114.4 days. The half-life of tantalum-182 is 114.4 days.",
 "anticipatedWrong": [
  {
   "value": 228.8,
   "misconception": "you read the time for the sample to fall to a quarter — that is two half-lives, not one",
   "feedback": "This answer is wrong — you read the time to fall to a quarter. That is two half-lives; one half-life is 114.4 days."
  },
  {
   "value": 457.6,
   "misconception": "you read the last time labeled on the axis instead of the 50% crossing",
   "feedback": "This answer is wrong — you read the last time on the axis. The 50% crossing sits at 114.4 days."
  }
 ]
}
NUC-026 · medium · application · seq 14 · authored:U14-G3 stage 2 (fresh amount-at-time read; three-half-life read for variety) · numeric
The figure shows the decay curve of a 344 mg sample of argon-37. Read from the curve the mass remaining at 105 days, in mg.
FIGURE (decay-curve · stimulus) — isotope: "argon-37" · yLabel: "mass of argon-37 remaining (mg)" · yTicks: [0, 43, 86, 129, 172, 215, 258, 301, 344] · xLabel: "time (days)" · xTicks: [0, 35, 70, 105, 140] · curvePoints: [[0, 344], [35, 172], [70, 86], [105, 43], [140, 21.5]] · style: "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
raw spec
{
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "decay-curve",
  "isotope": "argon-37",
  "yLabel": "mass of argon-37 remaining (mg)",
  "yTicks": [
   0,
   43,
   86,
   129,
   172,
   215,
   258,
   301,
   344
  ],
  "xLabel": "time (days)",
  "xTicks": [
   0,
   35,
   70,
   105,
   140
  ],
  "curvePoints": [
   [
    0,
    344
   ],
   [
    35,
    172
   ],
   [
    70,
    86
   ],
   [
    105,
    43
   ],
   [
    140,
    21.5
   ]
  ],
  "style": "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
 }
}
Answer: 43 mg KEY
also accepted: 43 mg
wrongValueDiagnostics
[
 {
  "value": 86,
  "misconception": "you read the mass at 70 days instead of 105 days",
  "feedback": "This answer is wrong — you read the mass at 70 days. At 105 days the curve sits at 43 mg."
 },
 {
  "value": 21.5,
  "misconception": "you read the mass at 140 days instead of 105 days",
  "feedback": "This answer is wrong — you read the mass at 140 days. At 105 days the curve sits at 43 mg."
 }
]
feedback
{
 "keyExplanation": "Go up from 105 days on the time axis to the curve, then straight across to the mass axis. At 105 days, 43 mg of argon-37 remains.",
 "anticipatedWrong": [
  {
   "value": 86,
   "misconception": "you read the mass at 70 days instead of 105 days",
   "feedback": "This answer is wrong — you read the mass at 70 days. At 105 days the curve sits at 43 mg."
  },
  {
   "value": 21.5,
   "misconception": "you read the mass at 140 days instead of 105 days",
   "feedback": "This answer is wrong — you read the mass at 140 days. At 105 days the curve sits at 43 mg."
  }
 ]
}
NUC-024 · medium · application · seq 15 · authored:U14-G3 stage 2 (diagnosis: halved-the-time trap; divide-by-count planted as distractor) · mcq4
After correctly counting the half-lives, a student halves the storage TIME once per half-life and reports that as the remaining mass. Which quantity should have been halved?
The starting amount — the time only sets the count, via time ÷ half-life. KEY
The time — decay uses up the storage time half by half.
Both the amount and the time, to keep the routine balanced.
Neither — the amount should be divided by the number of half-lives in one step.
NUC-023 · medium · application · seq 16 · authored:U14-G3 stage 2 (percent decayed, count 6) · numeric
A radioactive sample completes six half-lives. What percent of its starting nuclei has decayed by then?
Answer: 98.4375 % KEY
also accepted: 98.4375%, 63/64 as a percent
wrongValueDiagnostics
[
 {
  "value": 1.5625,
  "misconception": "you gave the percentage that REMAINS — the question asks for the decayed percentage",
  "feedback": "This answer is wrong — you gave the percentage that REMAINS. Decayed is the rest: 100 − 1.5625 = 98.4375%."
 },
 {
  "value": 16.67,
  "misconception": "you divided 100% by the number of half-lives — six half-lives means six halvings of what remains",
  "feedback": "This answer is wrong — you divided 100% by the number of half-lives. Six halvings leave 1.5625% remaining, so 98.4375% has decayed."
 },
 {
  "value": 50,
  "misconception": "you froze the decayed share at one halving — each later half-life keeps removing half of what remains",
  "feedback": "This answer is wrong — you froze the decayed share at one halving. After six halvings, 98.4375% has decayed."
 }
]
feedback
{
 "keyExplanation": "Remaining first: 100 → 50 → 25 → 12.5 → 6.25 → 3.125 → 1.5625, because after each half-life, half of the nuclei that remain decay. Decayed is the rest: 100 − 1.5625 = 98.4375%.",
 "anticipatedWrong": [
  {
   "value": 1.5625,
   "misconception": "you gave the percentage that REMAINS — the question asks for the decayed percentage",
   "feedback": "This answer is wrong — you gave the percentage that REMAINS. Decayed is the rest: 100 − 1.5625 = 98.4375%."
  },
  {
   "value": 16.67,
   "misconception": "you divided 100% by the number of half-lives — six half-lives means six halvings of what remains",
   "feedback": "This answer is wrong — you divided 100% by the number of half-lives. Six halvings leave 1.5625% remaining, so 98.4375% has decayed."
  },
  {
   "value": 50,
   "misconception": "you froze the decayed share at one halving — each later half-life keeps removing half of what remains",
   "feedback": "This answer is wrong — you froze the decayed share at one halving. After six halvings, 98.4375% has decayed."
  }
 ]
}
NUC-022 · hard · transfer · seq 17 · authored:U14-G3 stage 2 | sol-1 S7 + sol-2 T5: reworked twice, now a subdivision/grinding fixedness claim squarely on NUC-022's taught rule (half-life fixed regardless of amount/conditions/treatment) | blind-5: key restyled off E#4 echo; caps cue removed · mcq4
A student claims: 'Grinding a radioactive metal into a fine powder shortens its half-life, because small pieces decay faster.' What is wrong with the claim?
Piece size never matters — powder and block halve on exactly the same clock. KEY
Nothing is wrong — more surface area lets more decays escape each second.
The claim is wrong only because grinding lengthens the half-life by scattering the nuclei.
The claim is wrong because only melting the metal, not grinding it, can shorten a half-life.
NUC-025 · hard · transfer · seq 18 · authored:U14-G3 stage 2 (fresh fraction-form transfer; p10 class) · numeric
Thulium-167 has a half-life of 9.25 days. A sample of thulium-167 has decayed until only 1/4 of the original amount remains. How much time has passed, in days?
Answer: 18.5 days KEY
also accepted: 18.5 days, 18.5 d
wrongValueDiagnostics
[
 {
  "value": 37,
  "misconception": "you used the 4 in 1/4 as the number of halvings — 1 → 1/2 → 1/4 is 2 halvings",
  "feedback": "This answer is wrong — you used the 4 in 1/4 as the number of halvings. 1 → 1/2 → 1/4 is 2 halvings: 18.5 days."
 },
 {
  "value": 9.25,
  "misconception": "you counted only one halving — reaching 1/4 takes 2 halvings",
  "feedback": "This answer is wrong — you counted only one halving. Reaching 1/4 takes 2 halvings: 18.5 days."
 }
]
feedback
{
 "keyExplanation": "Count the halvings: 1 → 1/2 → 1/4.\nThe sample has halved 2 times.\ntime passed = number of halvings × half-life\ntime passed = 2 × 9.25 days\ntime passed = 18.5 days",
 "anticipatedWrong": [
  {
   "value": 37,
   "misconception": "you used the 4 in 1/4 as the number of halvings — 1 → 1/2 → 1/4 is 2 halvings",
   "feedback": "This answer is wrong — you used the 4 in 1/4 as the number of halvings. 1 → 1/2 → 1/4 is 2 halvings: 18.5 days."
  },
  {
   "value": 9.25,
   "misconception": "you counted only one halving — reaching 1/4 takes 2 halvings",
   "feedback": "This answer is wrong — you counted only one halving. Reaching 1/4 takes 2 halvings: 18.5 days."
  }
 ]
}
NUC-026 · hard · transfer · seq 19 · authored:U14-G3 stage 2 (fresh mass-target inverse read) · numeric
The figure shows the decay curve of a 392 g sample of rubidium-84. Read from the curve how long it takes for the sample to fall to 98 g, in days.
FIGURE (decay-curve · stimulus) — isotope: "rubidium-84" · yLabel: "mass of rubidium-84 remaining (g)" · yTicks: [0, 49, 98, 147, 196, 245, 294, 343, 392] · xLabel: "time (days)" · xTicks: [0, 32.8, 65.6, 98.4] · curvePoints: [[0, 392], [32.8, 196], [65.6, 98], [98.4, 49]] · style: "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
raw spec
{
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "decay-curve",
  "isotope": "rubidium-84",
  "yLabel": "mass of rubidium-84 remaining (g)",
  "yTicks": [
   0,
   49,
   98,
   147,
   196,
   245,
   294,
   343,
   392
  ],
  "xLabel": "time (days)",
  "xTicks": [
   0,
   32.8,
   65.6,
   98.4
  ],
  "curvePoints": [
   [
    0,
    392
   ],
   [
    32.8,
    196
   ],
   [
    65.6,
    98
   ],
   [
    98.4,
    49
   ]
  ],
  "style": "smooth falling curve on a light labeled grid, no read-off guide lines drawn"
 }
}
Answer: 65.6 days KEY
also accepted: 65.6 days, 65.6 d
wrongValueDiagnostics
[
 {
  "value": 32.8,
  "misconception": "you read the time for the first halving — 98 g is a quarter of 392 g, which takes two halvings",
  "feedback": "This answer is wrong — you read the time for the first halving. 98 g is a quarter of 392 g: two halvings, 65.6 days."
 },
 {
  "value": 98.4,
  "misconception": "you read one halving too far — the curve reaches 98 g at 65.6 days, not 49 g",
  "feedback": "This answer is wrong — you read one halving too far. The curve reaches 98 g at 65.6 days."
 }
]
feedback
{
 "keyExplanation": "Find 98 g on the mass axis. Go across to the curve, then down to the time axis. The sample reaches 98 g at 65.6 days.",
 "anticipatedWrong": [
  {
   "value": 32.8,
   "misconception": "you read the time for the first halving — 98 g is a quarter of 392 g, which takes two halvings",
   "feedback": "This answer is wrong — you read the time for the first halving. 98 g is a quarter of 392 g: two halvings, 65.6 days."
  },
  {
   "value": 98.4,
   "misconception": "you read one halving too far — the curve reaches 98 g at 65.6 days, not 49 g",
   "feedback": "This answer is wrong — you read one halving too far. The curve reaches 98 g at 65.6 days."
  }
 ]
}
NUC-025 · hard · transfer · seq 20 · authored:U14-G3 stage 2 (comparative: same time, unequal drops) · mcq4
Over the SAME stretch of time, a sample of isotope X fell to one quarter of its start while a sample of isotope Y fell only to half. What does this say about X's half-life?
It is shorter than Y's — X fitted two halvings into the time Y needed for one. KEY
It is longer than Y's — X got further, and further means a longer clock.
The two half-lives are equal — the same time passed for both.
Nothing — half-lives cannot be compared from fractions alone.
NUC-025 · hard · application · seq 21 · authored:U14-G3 stage 2 (fresh capstone FRQ; bismuth-205 instance) · frq
A lab stores 428 µg of bismuth-205, whose half-life is 15.3 days. Later, only 107 µg of the bismuth-205 remains.
A lab stores 428 µg of bismuth-205, whose half-life is 15.3 days. Later, only 107 µg of the bismuth-205 remains. (a) Write out the halving chain from 428 µg down to 107 µg, and state how many halvings the sample has made. (b) Using the relation 'time passed = number of halvings × half-life', substitute the values and calculate how much time has passed. Give the result with its unit. (c) In one sentence, explain why each halving takes the same amount of time.
Part a. Write out the halving chain from 428 µg down to 107 µg, and state how many halvings the sample has made.
Model: Count the halvings: 428 µg → 214 µg → 107 µg. The sample has halved 2 times.
Part b. Using the relation 'time passed = number of halvings × half-life', substitute the values and calculate how much time has passed. Give the result with its unit.
Model: time passed = number of halvings × half-life time passed = 2 × 15.3 days time passed = 30.6 days
Part c. In one sentence, explain why each halving takes the same amount of time.
Model: Each halving takes exactly one half-life, because after each half-life, half of the nuclei that remain decay.
Full model answer. (a) Count the halvings: 428 µg → 214 µg → 107 µg. The sample has halved 2 times. (b) time passed = number of halvings × half-life time passed = 2 × 15.3 days time passed = 30.6 days (c) Each halving takes exactly one half-life, because after each half-life, half of the nuclei that remain decay.

End of Topic Test: Fission and fusion (u14-t4 · 5 forms × 21 items · 105 total)

David's notes for James:
full notes file
# u14-t4 — notes/queries from David's side (U14-G4)

1. FRQ COMPOSITION - frq_per_form = 1 (your gate data's frq_per_form=1 concurs): the calc-heavy FRQ split was EVALUATED AND NOT TRIGGERED after an honest predicate check - the NUC-027..030 scope is fully qualitative (all four atoms fact/discrimination, no displayEquation, no atomKind 'quant', all 12 of your pool seeds are mcq4, zero numeric-entry rows so V-T6 sat armed with no live items). Nothing is ever computed and entered, so a 5-line-scaffold calculation FRQ has nothing to assess. The single FRQ is the gate's terminal capstone production on capstone NUC-029: two described nuclear events (one split, one merge; scenario vehicle and order rotate per form, all nuclide-free and number-free) - (a) classify both, (b) justify each by the before/after comparison (rule 1), (c) state the quickest tell (rule 6). Rubric 40/40/20 = 100; prompts/model answers fully typeable (V-T12 - no sub/superscripts ever required). D5 scaling evaluated and NOT applied: min(20, 6 x 4) = 20 -> full-size 20-objective allocation; the 4-lesson scope forces over-guideline rows-per-lesson (recorded, U12-G4 precedent): NUC-027 5 rows, NUC-028 4, NUC-029 6 + FRQ (capstone discrimination atom, the largest taught case space), NUC-030 5 - every row a distinct taught case family, no filler.
2. COURSE-WIDE INSTANCE RULE + U14 PHRASING PACK (binding, wave 6) - fission/fusion IS the topic, so the process words are unavoidable; everything stays curricular and clinical exactly as the lessons teach. Dispositions to confirm: (a) uranium/plutonium NEVER appear in any authored field - your pool[6] (= demo_curated[0]) U-235 + n symbol equation is freshened to a real balanced Cm-245 + n fission equation (one real equation per form: Cm-245, Cf-251, Am-241, Np-237, Th-232, each + ¹₀n), and your pool[1] uranium-235 pellet became an unnamed 'heavy fissile fuel' pellet; (b) 'reactor' appears ONLY inside NUC-030's own taught place label 'the reactor core of a nuclear power plant' - the lesson's verbatim gate-item key (A-U14G4-1 register) - and the fuel is never named ('the nuclei in its fuel split'); (c) 'fissile' is confined to the seq-13 energy-scale lane (your pool[1]'s own scenario; recorded phrase reservation); (d) fission events are single-split only and released neutrons stay an uninterpreted stated fact per NUC-027 - NO chain-reaction framing anywhere; (e) packaging re-sweep over forms_final AND this export body: ZERO student-facing hits on uranium/plutonium/enrichment/weapon/bomb/warhead/meltdown/dose/chain-reaction. Zero content-filter events across every authoring/blind/sol round - the clinical phrasing held.
3. INSTANCE LEDGER (computed, fix_log): every standalone mass number and every symbol-equation digit concatenation is globally unique across the 105 items and collides with NO spec value (the spec's own numbers 235/233/239/252/222-class and concatenations 23592/14156/9236/21/31/42 are all barred). Per-form roster - A: Cm-247, Fm-258, Po-218 + the Cm-245 equation; B: Cf-249, No-259, Th-230->Ra-226 + Cf-251 eq; C: Cm-243, Fm-257, No-256, Ra-224->Rn-220 + Am-241 eq; D: Es-254, Md-260, Cm-246, Bi-211 + Np-237 eq; E: Pa-231, Mg-24, Cf-250, Fr-221 + Th-232 eq. Realism ledger (flagged for David too): neutron-induced-fission keys are real fissile/fissionable nuclides (thermal: Cm-247/Cf-249/Cm-243/Es-254; Pa-231 with the stem saying 'fast-moving neutron'; the equation nuclides Am-241/Np-237/Th-232 are fast-fission - the lessons never distinguish neutron energies, so the equations keep the lesson register '+ ¹₀n'); every equation balances mass and charge exactly with fragments in the typical asymmetric ranges; the spontaneous-fission nuclides (Fm-257, Md-260, Fm-258, No-259, No-256, Cm-246, Cf-250) all have documented SF branches, with honest 'sometimes/occasionally' phrasing for small branches; every fusion reaction is real (T+T->He-4+2n, p+T->He-4, He-3+T->He-4+D, D+D->T+p second branch, C-12+C-12->Mg-24 carbon burning).
4. DEF-FUSION-REGISTER ADJUDICATION - THE HEADLINE (A-U14G4-4; needs your + David's confirmation): this is the fission-and-fusion gate, and every real fusion reaction the course can name is built from hydrogen/helium isotopes - the lessons themselves teach ONLY H/He fusion (NUC-028: H-2 + H-3 -> He-4; NUC-029: He-3 + He-3 -> He-4), and NUC-029's designed strongest transfer (the helium-4-product-vs-alpha-particle trap) is unstatable without 'helium-4'. Both words are V-T7 MATERIALS tokens AND the scope lessons' own taught materials, so the named-fusion slots necessarily fire the own-lesson and cross-form material lanes; the shared validator has no relief key for the class and is READ-ONLY. Resolution: ONE recorded material family in gate_config.json (materials hydrogen+helium; slots enumerated: A#9, C#9, D#9, B#16, A-E#19), enforced by the gate-local validate_with_adjudications.py wrapper (U5-G4 parity-guard pattern) over the UNTOUCHED shared validator - 24/24 V-T7 fail lines excused under the enumerated slots, 0 uncovered, parity guard MATCH, exit 0. Every removable use was content-purged FIRST: the definition/temperature/mass-energy/identification rows (2/6/11/15), the whole NUC-030 lane, row 9 E (carbon-burning fusion), rows 16 A/E (generic events) carry NO H/He token; seq-19 reactants stay generic so 'hydrogen' is never enrolled there. Same-seq H/He sharing at seqs 9/19 stays in the shared validator's A5 WARN lane (13 warns, routed to and cleared by blind review). U11-G1 def-hydrogen precedent.
5. FURTHER RECORDED ADJUDICATIONS (gate_config.json, confirm): A-U14G4-1 extra_category_labels = NUC-030's taught place-label set (reactor core of a nuclear power plant / sun's core / distant star's core / solar panel + the fusion/fission-in-the-sun's-core option pair) - R11/A1 bare-category class; the runtime derivation misses them only because the lesson's option wording varies by a word or two across its items; zero instance signal (no material token, no number). A-U14G4-2/3 extra_convention_phrases = two out-of-scope CANONICAL rule sentences that YOUR OWN seeds retrieve verbatim per the lessons' specNotes: NUC-004's energy-scale canon ('around a million times more energy than a chemical change of the same mass', retrieved by pool[1] at seq 13) and NUC-005's MECH-MASS-ENERGY ('a small amount of the nucleus's mass is converted into a very large amount of energy', retrieved by pool[4] at seq 11) - A3 class, instance-free. A-U14G4-5 extra_definition_lessons [NUC-004, NUC-005]: the authoritative reviewer judges with those lessons' rule lines on screen (defs-block strengthening, G1 MPM-015 precedent - never item relief).
6. SEQ-13 SOL OVERRIDE (A-U14G4-6, confirm): gpt-5.6-sol loops 2-3 kept failing all five seq-13 items on SKILL MAPPING ONLY ('measures NUC-004's million-fold comparison, not NUC-027's fission skill') while rating key_correct / distractors_cleanly_wrong / feedback_names_mistake ALL true on every form once the NUC-004 canon was on screen. Overridden by course-local authority, the exact G1 A#13 precedent: form A seq 13 IS your production seed pool[1], authored under NUC-027's own gate (byte-checked against the stage-0 seed dump) - the COURSE assigns this canon retrieval to NUC-027's end-of-topic gate, and the other four forms are its required fresh variants. sol's objection is a taxonomy disagreement, not a defect finding; the five items are recorded as documented survivors, raw verdicts intact.
7. SEED USAGE - all 12 of your pool items are placed on form A (your demo_curated[0..2] are byte-identical duplicates of pool[6..8] - deduped at stage 1, both refs cited on the seq 10/18/9 placements); prod_seeds is EMPTY and in-lesson fluency items are student-seen (spares only by standing rule), so nothing else was available - rows 1/2/4/5/7/16/19/20/21 plus the FRQ are fresh-authored from the lessons' taught case space, and forms B-E are fresh-authored parallels. 10 of the 12 placed seeds were freshened in CONTENT under the strict SEED RULING (the stage-1 prose counts 9 instance freshens; the tenth flag, pool[11]@A#3, was a distractor de-materialization only); pool[4] (mass-energy source) and pool[9] (solar collector) placed clean. Spares: none. Cold list ignored (standing ANSWERS #3).
8. SEED FRESHENING DISPOSITIONS (confirm - structure and misconception keys preserved, all fields swept after every swap, QB 3.9): (a) pool[11]@A#3 distractor 'hydrogen-filled core of the sun' -> 'the blazing core of the sun' (hydrogen = own-lesson taught material); (b) pool[3]@A#6 the spec's hydrogen-2/physicist stem -> an unnamed light-nuclei heating rig (own-lesson material + WE-adjacent text); (c) pool[0]@A#8 fission-event nuclide -> curium-247 word form (fresh unbarred mass number); (d) pool[8]@A#9 the symbol equation whose concatenations collide with spec values 31/42 -> word-form 'hydrogen-3 + hydrogen-3' (def-fusion-register slot); (e) pool[6]@A#10 the banned U-235 equation -> Cm-245 + n (real, balanced, Unicode notation); (f) pool[1]@A#13 'uranium-235' -> an unnamed 1 g pellet of 'heavy fissile fuel'; (g) pool[10]@A#14 key de-materialized to 'nuclear fusion - light nuclei merging in its core' (the spec key names hydrogen/helium = own-lesson materials); (h) pool[5]@A#15 key event genericized to 'two light nuclei join into one heavier nucleus' (its H-1 + H-2 -> He-3 instance is the lesson fluency's STUDENT-SEEN instance); (i) pool[2]@A#17 californium-252 -> fermium-258 (252 is NUC-029 WE spec text); (j) pool[7]@A#18 Ra-226/radon-222 -> polonium-218 (222 is NUC-029 fluency spec text).
9. BLIND QC LEDGER (provenance): round 1 (r1 = gpt-5.6-sol blind role, r2 = gemini; 105 items each; reviewer conventions SCRUBBED of the lessons' own banned-nuclide worked examples into instance-neutral equivalents per the phrasing pack) = 0 answerability failures, 200/200 key picks, FRQ 10/10 hand-graded rubric match. 4 hard fails, all resolved: A#3 (F2 - the existential 'where does fission happen' reading made star cores defensible since trace fission literally occurs in stars) -> the WHOLE seq-3 lane reframed to NUC-030's energy-source register on all forms; A#11/A#13/E#13 (unanswerable-from-packet) were a packet-conventions GAP, not item defects - the two out-of-scope canon sentences (A-U14G4-2/3) were added to the reviewer conventions (R23-safe: every student has been taught them). Same-wave flag fixes: A#7 Vega 'billions of years' age claim dropped (Vega ~450 My), C#5 'will not split until' absolutism (contradicted the seq-17 spontaneous-split lane), C#7 'all of that energy', D#6 classroom-container-at-millions-of-degrees -> physics animation, D#21 FRQ 'slight'/'fuse into' clang -> 'very small'/'press together', E#19 stem verb 'fuse' clang -> 'combine'. Re-blind r3/r4 (16 items): 0 hard fails, 30/30 picks, FRQ 2/2; r5-r8 (A#17 after the sol rework): 4/4 picks, zero flags. Accepted advisory classes recorded in fix_log (definitional cross-item recurrence endemic to a 21-item single-topic fission/fusion gate; taught-definition keys on recall rows; NUC-030's lesson-canon place-label option set targeting the 'stars run on fission' misconception; seq-18 alpha naming by design as seq-19's complement; A#11/E#11 canonical mass-energy keys; photon pedantry on two-body radiative captures - course register 'releasing energy' covers it; 'spontaneous fission' as a term is never taught, so E#17 does not offer it).
10. SOL AUTHORITATIVE LEDGER (provenance): loop 1 (full 105) = 6 FAILs -> fixes: the seq-3 panel-distractor feedback re-sworn on ALL FIVE forms (under the energy-source stems the student error is TRACING THE PANEL'S ENERGY TO FISSION, not 'putting a reaction inside the panel' - sol failed 2, the class was swept deterministically across 5), and A#17's secret-INTERNAL-neutron foil (stem-contradicting, duplicated d1) replaced. Loop 2 (11 items) = seq-3 clean; A#17's 'only'-hinged d1/d2 wrongness surfaced -> d1/d2 reworded as direct false claims and d3 made the lane-canonical EXTERNAL stray-neutron rationalization (B-E#17-proven design, 2-Yes/2-No polarity restored). Loop 3 = A#17 clean pass. Final: 0 open fails; the only recorded survivors are the five seq-13 skill-mapping verdicts (the A-U14G4-6 override above).
11. SF-TELEGRAPH GUARD (design disclosure): every fission key on rows 8/9/10/16 is neutron-induced or trigger-silent - no item outside seq 17 emphasizes 'on its own', so nothing pre-answers the seq-17 spontaneous-split transfer on its own form (the draft's SF key at E#8 was caught at authoring and replaced with Pa-231 + fast neutron).
12. NOTA/AOTA: zero literal none-/all-of-the-above hits across your 12-seed pool (V-T5 regex clone at stage 1); zero replace_distractor flags; V-T5 PASS on all forms.
13. TITLE - 'End of Topic Test: Fission and fusion' (the gate's single topic title, 'Topic N:' prefix stripped, standing G1-canon convention).

Form A

NUC-027 · easy · recall · seq 1 · · mcq4
Which description matches nuclear fission?
One large, heavy nucleus splits into two smaller nuclei. KEY
Two small, light nuclei merge into one heavier nucleus.
The nucleus shoots out one small chunk and stays otherwise whole.
The atom's electrons rearrange while the nucleus stays the same.
NUC-028 · easy · recall · seq 2 · · mcq4
Which description matches nuclear fusion?
Two small, light nuclei merge into one heavier nucleus. KEY
One large, heavy nucleus splits into two smaller nuclei.
A nucleus shoots out an alpha particle and becomes lighter.
Two atoms share electrons and bond into a molecule.
NUC-030 · easy · recall · seq 3 · · mcq4
Which one of these places runs on energy released by nuclear fission?
the reactor core of a nuclear power plant KEY
the blazing core of the sun
the core of a distant star
a solar panel in full sunlight
NUC-029 · easy · recall · seq 4 · · mcq4
What is the quickest tell for deciding whether a nuclear reaction is fission or fusion?
Look at the starting nuclei: fission starts with a heavy nucleus, fusion starts with light nuclei. KEY
Look at the starting nuclei: fission starts with light nuclei, fusion starts with a heavy nucleus.
Check the energy: the reaction that releases energy is fusion, and the one that absorbs energy is fission.
Count the nuclei at the end: both kinds of reaction finish with exactly one nucleus.
NUC-027 · easy · application · seq 5 · · mcq4
A heavy nucleus sits quietly in a sample until, one moment later, it undergoes a fission event. Which happening most likely set the event off?
The nucleus absorbed a neutron. KEY
The nucleus absorbed one of the atom's electrons.
The sample was heated until the nucleus began to melt.
The nucleus collided with another heavy nucleus nearby.
NUC-028 · medium · application · seq 6 · · mcq4
A research team heats a batch of light nuclei to millions of degrees, and only then do the nuclei begin merging into heavier ones. Why was the enormous temperature necessary?
The nuclei are positively charged and repel, so they must collide at enormous speed to get close enough to merge. KEY
The nuclei must first be melted into a liquid so that they can flow together into one larger nucleus.
The heat loads the nuclei with extra electrons, and those electrons stick the merging nuclei together.
The heat must first break each nucleus into pieces so the pieces can rebuild as one heavier nucleus.
NUC-030 · medium · application · seq 7 · · mcq4
Deep in the star Vega, one ongoing process supplies the energy the star gives off. Which process is it?
nuclear fusion KEY
nuclear fission
an ordinary chemical fire
alpha decay of its heavy elements
NUC-027 · medium · application · seq 8 · · mcq4
Which event is nuclear fission?
A curium-247 nucleus absorbs a neutron and splits into two smaller nuclei of similar size, releasing three neutrons. KEY
A radium nucleus shoots out a single alpha particle and keeps the rest of itself together.
A cesium nucleus turns one of its neutrons into a proton and stays in one piece.
An energized technetium nucleus releases a burst of gamma radiation without changing its makeup.
NUC-029 · medium · application · seq 9 · · mcq4
A hydrogen-3 nucleus merges with another hydrogen-3 nucleus, forming one helium-4 nucleus and releasing two neutrons. What kind of nuclear reaction is this?
nuclear fusion KEY
nuclear fission
alpha decay
gamma emission
NUC-029 · medium · application · seq 10 · · mcq4
What kind of nuclear reaction does this equation show? ²⁴⁵₉₆Cm + ¹₀n → ¹⁴³₅₆Ba + ¹⁰⁰₄₀Zr + 3 ¹₀n
nuclear fission KEY
nuclear fusion
alpha decay
beta decay
NUC-028 · medium · application · seq 11 · · mcq4
When two light nuclei merge in a fusion reaction, where does the large amount of released energy come from?
A small amount of the nucleus's mass is converted into a very large amount of energy. KEY
The stored heat of the high-speed collision is released again as the nuclei merge.
The whole mass of both nuclei is destroyed and becomes energy.
Electrons falling into the newly formed nucleus release the energy.
NUC-030 · medium · application · seq 12 · · mcq4
A solar panel on a roof charges a battery. The energy it collects was originally released by which process?
nuclear fusion in the sun's core KEY
nuclear fission in the sun's core
chemical burning at the sun's surface
nuclear fusion inside the panel itself
NUC-027 · medium · application · seq 13 · · mcq4
Every nucleus in a 1 g pellet of heavy fissile fuel undergoes fission. A student claims the pellet gives off about as much energy as a chemical reaction of 1 g of fuel. What is the correct comparison?
The fission releases around a million times more energy than a chemical change of the same mass. KEY
The fission releases around a thousand times more energy than a chemical change of the same mass.
The student is right — the two release roughly the same energy for the same mass.
The fission releases less energy, because splitting a nucleus uses energy up.
NUC-030 · medium · application · seq 14 · · mcq4
A science-fiction movie describes the sun as 'a giant ball of burning gas, like a huge campfire.' Which correction is right?
The sun's energy comes from nuclear fusion — light nuclei merging in its core. KEY
The sun's energy comes from nuclear fission — heavy nuclei in its core splitting into smaller ones.
The movie is right — the sun really is a chemical fire, only far larger than any on Earth.
The sun's energy comes from alpha particles escaping its surface.
NUC-028 · medium · application · seq 15 · · mcq4
Which change is nuclear fusion?
Two light nuclei slam together at enormous speed and join into a single heavier nucleus. KEY
A heavy nucleus absorbs a neutron and splits into two smaller nuclei.
A nucleus shoots out an alpha particle and becomes lighter.
Two atoms share electrons and bond into a molecule.
NUC-029 · medium · application · seq 16 · · mcq4
Inside a sealed test capsule, two light nuclei are driven together until they merge into one heavier nucleus, and energy pours out. What kind of nuclear reaction happened in the capsule?
nuclear fusion KEY
nuclear fission
alpha decay
gamma emission
NUC-027 · hard · transfer · seq 17 · · mcq4
A fermium-258 nucleus sometimes splits into two smaller nuclei and several neutrons on its own, without absorbing anything. Is this event fission?
Yes — a heavy nucleus splitting into two smaller nuclei is fission; the neutron is only the usual trigger. KEY
No — this split does not qualify as fission, because no absorbed neutron came first.
No — left undisturbed, a heavy nucleus is limited to emitting small particles such as alpha and beta particles.
Yes — but it counts as fission only because a stray neutron from the surroundings must have slipped in undetected.
NUC-029 · hard · transfer · seq 18 · · mcq4
A polonium-218 nucleus shoots out an alpha particle. A student classifies the event as fission because the nucleus 'broke into two pieces.' What kind of nuclear change is it?
alpha decay KEY
nuclear fission
nuclear fusion
beta decay
NUC-029 · hard · transfer · seq 19 · · mcq4
In a fusion test rig, two light nuclei merge, and the one new nucleus detected is helium-4. A student announces that alpha decay happened, because 'a helium-4 nucleus IS an alpha particle.' What kind of nuclear change actually occurred?
nuclear fusion KEY
alpha decay
nuclear fission
gamma emission
NUC-030 · hard · application · seq 20 · · mcq4
An engineering team wants a machine that releases energy the same way the stars do. Which nuclear change must their machine produce?
Light nuclei merging into heavier nuclei. KEY
Heavy nuclei splitting into smaller nuclei.
Fuel reacting chemically at extremely high temperature.
Nuclei shooting out alpha particles.
NUC-029 · hard · application · seq 21 · · frq
A lab notebook describes two nuclear events. Event 1: A very heavy nucleus absorbs a neutron, and the whole nucleus then splits into two smaller nuclei of roughly equal size, with three neutrons coming off. Event 2: Two very light nuclei, moving at enormous speed, collide and merge into a single heavier nucleus, releasing energy.
A lab notebook describes two nuclear events. Event 1: A very heavy nucleus absorbs a neutron, and the whole nucleus then splits into two smaller nuclei of roughly equal size, with three neutrons coming off. Event 2: Two very light nuclei, moving at enormous speed, collide and merge into a single heavier nucleus, releasing energy. (a) Classify each event as nuclear fission or nuclear fusion. (b) Justify each classification by comparing the nuclei BEFORE the change with the nuclei AFTER it. (c) State the quickest tell for deciding between fission and fusion in any nuclear reaction.
Part a. Classify each event as nuclear fission or nuclear fusion.
Model: Event 1 is nuclear fission. Event 2 is nuclear fusion.
Part b. Justify each classification by comparing the nuclei BEFORE the change with the nuclei AFTER it.
Model: Event 1: before the change there is one large, heavy nucleus (plus the absorbed neutron); after it there are two smaller nuclei and several released neutrons. One heavy nucleus splitting into two smaller nuclei is fission. Event 2: before the change there are two small, light nuclei; after it there is one heavier nucleus. Two light nuclei merging into one heavier nucleus is fusion.
Part c. State the quickest tell for deciding between fission and fusion in any nuclear reaction.
Model: Look at the starting nuclei: fission starts with a heavy nucleus, fusion starts with light nuclei.
Full model answer. (a) Event 1 is nuclear fission. Event 2 is nuclear fusion. (b) Event 1: before the change there is one large, heavy nucleus (plus the absorbed neutron); after it there are two smaller nuclei and several released neutrons. One heavy nucleus splitting into two smaller nuclei is fission. Event 2: before the change there are two small, light nuclei; after it there is one heavier nucleus. Two light nuclei merging into one heavier nucleus is fusion. (c) Look at the starting nuclei: fission starts with a heavy nucleus, fusion starts with light nuclei.

Form B

NUC-027 · easy · recall · seq 1 · · mcq4
A glossary needs an entry for 'nuclear fission.' Which wording is correct?
A heavy nucleus splits apart into two smaller nuclei. KEY
Two light nuclei merge into a single heavier nucleus.
A nucleus shoots out a single alpha particle and stays otherwise in one piece.
Atoms trade electrons while every nucleus stays unchanged.
NUC-028 · easy · recall · seq 2 · · mcq4
A study guide needs one sentence defining 'nuclear fusion.' Which sentence is right?
Two light nuclei merge into a single heavier nucleus. KEY
A heavy nucleus splits apart into two smaller nuclei.
A nucleus ejects a single alpha particle and becomes a little lighter.
Two atoms link by sharing electrons and form a molecule.
NUC-030 · easy · recall · seq 3 · · mcq4
Nuclear fission is the working energy source inside which one of these?
the reactor core of a nuclear power plant KEY
the glowing core of the sun
the core of a distant star
a solar panel in full sunlight
NUC-029 · easy · recall · seq 4 · · mcq4
A revision card asks: 'Fastest way to tell fission from fusion?' Which answer belongs on the card?
Check what goes in: a heavy starting nucleus means fission, light starting nuclei mean fusion. KEY
Check what goes in: light starting nuclei mean fission, a heavy starting nucleus means fusion.
Check the energy: only one of the two kinds of reaction releases energy.
There is no quick tell — the two reactions can only be separated by measuring their speeds.
NUC-027 · easy · application · seq 5 · · mcq4
Before a heavy nucleus in a fuel sample splits, one triggering event normally happens first. Which one?
It absorbs a neutron. KEY
It absorbs one of its atom's electrons.
It is heated until it starts to melt.
It collides with another heavy nucleus.
NUC-028 · medium · application · seq 6 · · mcq4
Inside a fusion test machine, the light nuclei in the fuel refuse to merge until the temperature reaches millions of degrees. What does the extreme heat actually provide?
Enormous collision speed — fast enough for the repelling, positively charged nuclei to get close enough to merge. KEY
A liquid state — the nuclei have to be melted before they can flow into one another and combine.
Spare electrons — the extra electrons act like glue that binds the two merging nuclei together.
Demolition — the heat cracks each nucleus open so the fragments can reassemble as a heavier nucleus.
NUC-030 · medium · application · seq 7 · · mcq4
The star Altair has poured out enormous energy for millions of years. That energy is released by which process?
nuclear fusion KEY
nuclear fission
an ordinary chemical fire
alpha decay of its heavy elements
NUC-027 · medium · application · seq 8 · · mcq4
Which of the following events is a fission event?
A californium-249 nucleus absorbs a neutron and splits into two smaller nuclei of similar size, with three neutrons set free. KEY
A radium nucleus shoots out one single alpha particle and then continues on essentially unchanged apart from that small loss.
A cesium nucleus converts a neutron into a proton while staying whole.
An energized technetium nucleus sheds a burst of gamma radiation and keeps its makeup.
NUC-029 · medium · application · seq 9 · · mcq4
Inside a test block, a heavy nucleus absorbs a neutron and immediately splits in two, with three neutrons flying off. What kind of nuclear reaction is this?
nuclear fission KEY
nuclear fusion
alpha decay
beta decay
NUC-029 · medium · application · seq 10 · · mcq4
Which kind of nuclear reaction appears in this equation? ²⁵¹₉₈Cf + ¹₀n → ¹⁴⁰₅₄Xe + ¹⁰⁹₄₄Ru + 3 ¹₀n
nuclear fission KEY
nuclear fusion
alpha decay
gamma emission
NUC-028 · medium · application · seq 11 · · mcq4
Two light nuclei merge and an enormous burst of energy leaves the reaction. What is the source of that energy?
A small portion of the nuclear mass converts into a very large amount of energy. KEY
The merging nuclei give back the heat energy that was used to speed them up.
Both nuclei are entirely destroyed, with all of their mass becoming energy.
Electrons dropping into orbit around the new nucleus give off the energy.
NUC-030 · medium · application · seq 12 · · mcq4
A solar farm outside town feeds electricity into the grid all afternoon. The energy its panels gather was first set free by which process?
nuclear fusion in the sun's core KEY
nuclear fission in the sun's core
chemical burning at the sun's surface
nuclear fusion inside the farm's panels
NUC-027 · medium · application · seq 13 · · mcq4
A display card reads: 'Fully fissioning a speck of heavy fissile fuel yields no more energy than burning that same speck.' How should the card be corrected?
Fission yields around a million times more energy than a chemical change of the same mass. KEY
Fission yields around a thousand times more energy than a chemical change of the same mass.
The card is right as printed — equal masses release equal energy.
Fission actually yields less energy than burning, since the split absorbs energy.
NUC-030 · medium · application · seq 14 · · mcq4
A planetarium poster calls the sun 'the biggest bonfire in the solar system.' What should the curator's correction say?
The sun runs on nuclear fusion — light nuclei merge into heavier ones in its core. KEY
The sun runs on nuclear fission — its core splits heavy nuclei into smaller ones.
The poster can stay — the sun genuinely is an enormous chemical bonfire.
The sun is powered by alpha particles streaming off its surface.
NUC-028 · medium · application · seq 15 · · mcq4
Which event below is nuclear fusion?
Two light nuclei collide so fast that they join into one heavier nucleus. KEY
A heavy nucleus absorbs a neutron and splits apart into two smaller nuclei.
A nucleus casts off an alpha particle and ends up lighter.
Two atoms form a molecule by sharing a pair of electrons.
NUC-029 · medium · application · seq 16 · · mcq4
A pair of hydrogen-2 nuclei get forced together until they merge; the products are one hydrogen-3 nucleus and a single proton. What kind of nuclear reaction is this?
nuclear fusion KEY
nuclear fission
beta decay
alpha decay
NUC-027 · hard · transfer · seq 17 · · mcq4
A nobelium-259 nucleus splits into two smaller nuclei and several neutrons without having absorbed anything first. A student argues it cannot be fission because nothing triggered it. Who is right?
The event is fission — the split into two smaller nuclei is the definition; an absorbed neutron is only the usual trigger. KEY
The student is correct — with no absorbed neutron beforehand, a split does not qualify as fission.
The student is correct — an untriggered nucleus can only change by emitting alpha or beta particles.
The event is fission — but only if a hidden neutron was actually absorbed a moment before the split.
NUC-029 · hard · transfer · seq 18 · · mcq4
A thorium-230 nucleus shoots out an alpha particle and becomes radium-226. A lab partner logs it as fission, arguing the nucleus 'split into a big piece and a small piece.' What kind of nuclear change is it?
alpha decay KEY
nuclear fission
nuclear fusion
gamma emission
NUC-029 · hard · transfer · seq 19 · · mcq4
An experiment log reads: 'Two light nuclei joined; sole nuclear product: helium-4.' A teammate marks the run as alpha decay — 'helium-4 means an alpha particle came out.' What actually happened?
nuclear fusion KEY
alpha decay
nuclear fission
beta decay
NUC-030 · hard · application · seq 20 · · mcq4
A startup claims its device releases energy 'exactly the way a nuclear power plant's fuel does.' If the claim is true, what happens inside the device?
Heavy nuclei split into smaller nuclei. KEY
Light nuclei merge into heavier nuclei.
Fuel burns chemically at very high temperature.
Nuclei emit bursts of gamma radiation only.
NUC-029 · hard · application · seq 21 · · frq
A museum display card summarizes two nuclear reactions. Reaction 1: Two featherweight nuclei smash together and stick, leaving one heavier nucleus and a burst of released energy. Reaction 2: One massive nucleus takes on an extra neutron and immediately breaks apart into a pair of smaller nuclei, freeing several neutrons.
A museum display card summarizes two nuclear reactions. Reaction 1: Two featherweight nuclei smash together and stick, leaving one heavier nucleus and a burst of released energy. Reaction 2: One massive nucleus takes on an extra neutron and immediately breaks apart into a pair of smaller nuclei, freeing several neutrons. (a) Classify each reaction as nuclear fission or nuclear fusion. (b) Defend each classification by comparing what exists before the reaction with what exists after it. (c) Give the fastest general check for telling the two kinds of reaction apart.
Part a. Classify each reaction as nuclear fission or nuclear fusion.
Model: Reaction 1 is nuclear fusion. Reaction 2 is nuclear fission.
Part b. Defend each classification by comparing what exists before the reaction with what exists after it.
Model: Reaction 1: before, there are two small, light nuclei; after, there is one heavier nucleus. Two light nuclei merging into one heavier nucleus is fusion. Reaction 2: before, there is one large, heavy nucleus (with the absorbed neutron); after, there are two smaller nuclei and several freed neutrons. One heavy nucleus splitting into two smaller nuclei is fission.
Part c. Give the fastest general check for telling the two kinds of reaction apart.
Model: Check the starting nuclei: a heavy starting nucleus means fission, and light starting nuclei mean fusion.
Full model answer. (a) Reaction 1 is nuclear fusion. Reaction 2 is nuclear fission. (b) Reaction 1: before, there are two small, light nuclei; after, there is one heavier nucleus. Two light nuclei merging into one heavier nucleus is fusion. Reaction 2: before, there is one large, heavy nucleus (with the absorbed neutron); after, there are two smaller nuclei and several freed neutrons. One heavy nucleus splitting into two smaller nuclei is fission. (c) Check the starting nuclei: a heavy starting nucleus means fission, and light starting nuclei mean fusion.

Form C

NUC-027 · easy · recall · seq 1 · · mcq4
What does nuclear fission do to a nucleus?
It splits the large, heavy nucleus into two smaller nuclei. KEY
It merges the nucleus with another light nucleus to build a heavier one.
It makes the nucleus shoot out one alpha particle and stay otherwise whole.
It rearranges the atom's electrons and leaves the nucleus alone.
NUC-028 · easy · recall · seq 2 · · mcq4
What does nuclear fusion do to the nuclei it involves?
It merges two small, light nuclei into one heavier nucleus. KEY
It splits one large, heavy nucleus into two smaller nuclei.
It makes one nucleus shoot out an alpha particle.
It bonds two whole atoms together through their electrons.
NUC-030 · easy · recall · seq 3 · · mcq4
Which of these gets its energy from nuclear fission?
the reactor core of a nuclear power plant KEY
the blazing core of the sun
the core of a bright star overhead
a solar panel in full sunlight
NUC-029 · easy · recall · seq 4 · · mcq4
To classify a nuclear reaction at a glance, what should you compare first?
The starting nuclei: a heavy one signals fission, light ones signal fusion. KEY
The starting nuclei: light ones signal fission, a heavy one signals fusion.
The energy released: bigger energy always means fusion rather than fission.
The count of neutrons released: fusion always releases more neutrons than fission.
NUC-027 · easy · application · seq 5 · · mcq4
In most fission events, a heavy nucleus splits only after one particular thing happens to it. What is that thing?
It takes in a neutron. KEY
It takes in an electron from its own atom.
It reaches a temperature high enough to start melting.
It smashes into a second heavy nucleus.
NUC-028 · medium · application · seq 6 · · mcq4
Light nuclei in a sealed rig begin merging only after the temperature climbs to millions of degrees. Why do the nuclei need conditions that extreme?
Each nucleus is positively charged, so the pair repel — only a collision at enormous speed gets them close enough to merge. KEY
Each nucleus has to be melted into liquid form before the two of them are able to flow together into one.
Each nucleus needs added electrons from the heat, and the added electrons hold the merged pair together.
Each nucleus must be shattered by the heat so its pieces can regroup into one heavier nucleus.
NUC-030 · medium · application · seq 7 · · mcq4
Rigel outshines nearly every star around it. The process releasing that energy is which one?
nuclear fusion KEY
nuclear fission
an ordinary chemical fire
alpha decay of its heavy elements
NUC-027 · medium · application · seq 8 · · mcq4
One of these four nuclear events is fission. Which one?
A curium-243 nucleus absorbs a neutron and splits into two smaller nuclei of similar size, throwing off three neutrons. KEY
A radium nucleus fires out an alpha particle and continues on afterward as one single, slightly smaller nucleus.
A cesium nucleus swaps one neutron for a proton internally and remains whole.
An energized technetium nucleus gives off a burst of gamma radiation, its makeup untouched.
NUC-029 · medium · application · seq 9 · · mcq4
A single proton and a hydrogen-3 nucleus join together into one helium-4 nucleus, releasing energy. What kind of nuclear reaction is this?
nuclear fusion KEY
nuclear fission
alpha decay
beta decay
NUC-029 · medium · application · seq 10 · · mcq4
Classify the nuclear reaction recorded in this equation. ²⁴¹₉₅Am + ¹₀n → ¹³⁴₅₃I + ¹⁰⁴₄₂Mo + 4 ¹₀n
nuclear fission KEY
nuclear fusion
alpha decay
beta decay
NUC-028 · medium · application · seq 11 · · mcq4
A fusion reaction gives off far more energy than was spent speeding the nuclei up. What supplies the extra energy?
A small amount of nuclear mass that converts into a very large amount of energy. KEY
Heat trapped between the two nuclei during their collision.
The complete conversion of both starting nuclei into pure energy.
The pull of the new nucleus on nearby electrons.
NUC-030 · medium · application · seq 12 · · mcq4
A garden lamp soaks up sunlight by day and glows all evening. The energy it stored was originally released by which process?
nuclear fusion in the sun's core KEY
nuclear fission in the sun's core
chemical burning at the sun's surface
nuclear fusion inside the lamp itself
NUC-027 · medium · application · seq 13 · · mcq4
If every nucleus in a grain of heavy fissile fuel splits, how does the released energy compare with a chemical change of the same mass?
It is around a million times more energy. KEY
It is around a thousand times more energy.
It is roughly the same energy.
It is less energy, because the splits soak energy up.
NUC-030 · medium · application · seq 14 · · mcq4
A younger sibling says the sun is 'just a really big fire in space.' What is the accurate reply?
The sun makes its energy by nuclear fusion — light nuclei merging in its core. KEY
The sun makes its energy by nuclear fission — heavy nuclei splitting in its core.
The sibling is right — space fires simply burn much hotter than fires on Earth.
The sun shines because alpha particles leak from its surface.
NUC-028 · medium · application · seq 15 · · mcq4
One of the four events below is fusion. Which one is it?
Two light nuclei crash into each other and combine into one heavier nucleus. KEY
A heavy nucleus takes up a neutron and splits into two smaller nuclei.
A nucleus throws off an alpha particle and continues slightly lighter.
Two atoms stick together into a molecule by sharing electrons.
NUC-029 · medium · application · seq 16 · · mcq4
Detectors record a fermium-257 nucleus splitting into two smaller nuclei of comparable size, with several neutrons released. What kind of nuclear reaction is this?
nuclear fission KEY
nuclear fusion
alpha decay
beta decay
NUC-027 · hard · transfer · seq 17 · · mcq4
Very rarely, a nobelium-256 nucleus splits by itself into two smaller nuclei plus several neutrons, no absorption involved. Should the event be recorded as fission?
Yes — the split into two smaller nuclei is what defines fission; the usual neutron trigger is optional. KEY
No — without a neutron going in first, the record should show something other than fission.
No — a nucleus left alone can only emit small particles such as alpha and beta particles.
Yes — though only on the assumption that an unseen neutron was absorbed just before the split.
NUC-029 · hard · transfer · seq 18 · · mcq4
A radium-224 nucleus shoots out an alpha particle and becomes radon-220. A study partner records the event as fission since 'two pieces came out of one.' What kind of nuclear change is it?
alpha decay KEY
nuclear fission
nuclear fusion
beta decay
NUC-029 · hard · transfer · seq 19 · · mcq4
Two light nuclei merge inside a target chamber, leaving a single helium-4 nucleus. A student writes 'alpha decay' in the results table, reasoning that helium-4 and an alpha particle are the same thing. Which classification is correct?
nuclear fusion KEY
alpha decay
nuclear fission
gamma emission
NUC-030 · hard · application · seq 20 · · mcq4
A news story claims that nuclear power plants and the stars 'run on the same nuclear process.' What is the correct correction?
Power plants run on splitting heavy nuclei; stars run on merging light nuclei. KEY
Power plants run on merging light nuclei; stars run on splitting heavy nuclei.
The story is right — both run on splitting heavy nuclei.
The story is right — both run on merging light nuclei.
NUC-029 · hard · application · seq 21 · · frq
A physics-club video pauses on two labeled animations. Animation 1: A bulky nucleus soaks up a neutron and comes apart into two smaller nuclei of roughly equal size, plus several loose neutrons. Animation 2: A pair of tiny nuclei race toward each other and blend into one heavier nucleus, with energy streaming outward.
A physics-club video pauses on two labeled animations. Animation 1: A bulky nucleus soaks up a neutron and comes apart into two smaller nuclei of roughly equal size, plus several loose neutrons. Animation 2: A pair of tiny nuclei race toward each other and blend into one heavier nucleus, with energy streaming outward. (a) Classify each animation as nuclear fission or nuclear fusion. (b) Support each classification by comparing the nuclei present before the change with those present after. (c) State the one-look rule for separating fission from fusion.
Part a. Classify each animation as nuclear fission or nuclear fusion.
Model: Animation 1 is nuclear fission. Animation 2 is nuclear fusion.
Part b. Support each classification by comparing the nuclei present before the change with those present after.
Model: Animation 1: before, one large, heavy nucleus (plus the absorbed neutron); after, two smaller nuclei and several neutrons. A heavy nucleus splitting into two smaller nuclei is fission. Animation 2: before, two small, light nuclei; after, one heavier nucleus. Two light nuclei merging into one heavier nucleus is fusion.
Part c. State the one-look rule for separating fission from fusion.
Model: The one-look rule: fission starts with a heavy nucleus, fusion starts with light nuclei.
Full model answer. (a) Animation 1 is nuclear fission. Animation 2 is nuclear fusion. (b) Animation 1: before, one large, heavy nucleus (plus the absorbed neutron); after, two smaller nuclei and several neutrons. A heavy nucleus splitting into two smaller nuclei is fission. Animation 2: before, two small, light nuclei; after, one heavier nucleus. Two light nuclei merging into one heavier nucleus is fusion. (c) The one-look rule: fission starts with a heavy nucleus, fusion starts with light nuclei.

Form D

NUC-027 · easy · recall · seq 1 · · mcq4
Complete the sentence: in nuclear fission, a nucleus ...
... that is large and heavy splits into two smaller nuclei. KEY
... that is small and light merges with another into one heavier nucleus.
... ejects one alpha particle while staying nearly whole.
... keeps its makeup while the atom's electrons rearrange.
NUC-028 · easy · recall · seq 2 · · mcq4
Complete the sentence: in nuclear fusion, two nuclei ...
... that are small and light merge into one heavier nucleus. KEY
... that are large and heavy each split into smaller nuclei.
... each shoot out an alpha particle at the same time.
... stay unchanged while their atoms share electrons.
NUC-030 · easy · recall · seq 3 · · mcq4
Of the four places below, the one that runs on fission energy is ...
the reactor core of a nuclear power plant KEY
the churning core of the sun
the core of a distant star
a solar panel in full sunlight
NUC-029 · easy · recall · seq 4 · · mcq4
Which single check settles fastest whether a reaction was fission or fusion?
Whether the reaction started from a heavy nucleus (fission) or from light nuclei (fusion). KEY
Whether the reaction started from light nuclei (fission) or from a heavy nucleus (fusion).
Whether the reaction released any energy at all.
Whether the reaction happened inside a laboratory or out in nature.
NUC-027 · easy · application · seq 5 · · mcq4
For most fission events, the split is set in motion when the heavy nucleus does what?
Absorbs a passing neutron. KEY
Absorbs one of the electrons orbiting it.
Melts after the material around it gets hot enough.
Rams into another heavy nucleus in the material.
NUC-028 · medium · application · seq 6 · · mcq4
A physics animation shows light nuclei merging only once the temperature readout reaches millions of degrees. Why must the nuclei be that hot?
Heat means speed: the positively charged nuclei repel, and only enormous collision speed lets them get close enough to merge. KEY
Heat means melting: the nuclei have to become liquid before they are able to run together into one nucleus.
Heat means extra electrons: hot nuclei collect electrons that then cement the merging pair together.
Heat means breakage: the nuclei are first broken up so their pieces can settle into one heavier nucleus.
NUC-030 · medium · application · seq 7 · · mcq4
Polaris, the north star, keeps shining century after century. What kind of process is generating that energy?
nuclear fusion KEY
nuclear fission
an ordinary chemical fire
alpha decay of its heavy elements
NUC-027 · medium · application · seq 8 · · mcq4
Which event below shows nuclear fission?
An einsteinium-254 nucleus absorbs a neutron and splits into two smaller nuclei of similar size, releasing three neutrons. KEY
A radium nucleus flings out an alpha particle while the rest of the nucleus stays together.
A cesium nucleus changes one neutron into a proton and holds together as a single nucleus.
An energized technetium nucleus emits a burst of gamma radiation and ends up with its makeup entirely unchanged afterward.
NUC-029 · medium · application · seq 9 · · mcq4
One nucleus of helium-3 merges with one nucleus of hydrogen-3; the products are a helium-4 nucleus and a leftover hydrogen-2 nucleus. What kind of nuclear reaction is this?
nuclear fusion KEY
nuclear fission
alpha decay
gamma emission
NUC-029 · medium · application · seq 10 · · mcq4
This equation records one nuclear event. What kind of reaction is it? ²³⁷₉₃Np + ¹₀n → ¹³⁶₅₃I + ⁹⁹₄₀Zr + 3 ¹₀n
nuclear fission KEY
nuclear fusion
alpha decay
gamma emission
NUC-028 · medium · application · seq 11 · · mcq4
After light nuclei merge, the products weigh slightly less than the starting nuclei did. What happened to the missing bit of mass?
It was converted into a very large amount of released energy. KEY
It escaped as heat that had been stored from the original collision.
It shows the whole of both nuclei was annihilated into energy.
It was carried off by electrons leaving the new nucleus.
NUC-030 · medium · application · seq 12 · · mcq4
A road-sign panel runs its flashing light entirely on collected sunlight. Which process first released that energy?
nuclear fusion in the sun's core KEY
nuclear fission in the sun's core
chemical burning at the sun's surface
nuclear fusion inside the road-sign panel
NUC-027 · medium · application · seq 13 · · mcq4
A homework answer claims that fissioning a chip of heavy fissile fuel releases roughly the energy of the same chip reacting chemically. What grade-worthy correction applies?
The fission releases around a million times more energy than the chemical reaction of the same mass. KEY
The fission releases around a thousand times more energy than the chemical reaction of the same mass.
No correction is needed — equal masses always mean equal released energy.
The claim overstates fission — splitting nuclei absorbs more energy than it gives out.
NUC-030 · medium · application · seq 14 · · mcq4
An old textbook line reads: 'The sun burns its gas the way a stove burns fuel.' Which replacement sentence is correct?
The sun releases energy by nuclear fusion, as light nuclei merge in its core. KEY
The sun releases energy by nuclear fission, as heavy nuclei split in its core.
The original line is fine — the sun's gas really does burn like stove fuel.
The sun releases energy through alpha particles boiling off its surface.
NUC-028 · medium · application · seq 15 · · mcq4
Pick the event that shows nuclear fusion.
Two light nuclei meet at enormous speed and merge into one heavier nucleus. KEY
A heavy nucleus absorbs one neutron and then splits into two smaller nuclei.
A nucleus releases an alpha particle and gets a little lighter.
Two atoms bond into one molecule through shared electrons.
NUC-029 · medium · application · seq 16 · · mcq4
A lab record shows a mendelevium-260 nucleus dividing into two smaller nuclei of comparable size and releasing several neutrons. What kind of nuclear reaction is this?
nuclear fission KEY
nuclear fusion
gamma emission
alpha decay
NUC-027 · hard · transfer · seq 17 · · mcq4
Once in a long while, a curium-246 nucleus breaks in two — two smaller nuclei plus several neutrons — with nothing absorbed beforehand. A lab intern says fission is impossible here since no neutron arrived. Evaluate the claim.
The claim is wrong — the split defines fission, and the arriving neutron is merely the usual trigger. KEY
The claim is right — fission strictly requires a freshly absorbed neutron to precede the split.
The claim is right — an undisturbed heavy nucleus can only change by alpha or beta emission.
The claim is wrong — but only because a neutron from the surroundings must have sneaked in unnoticed.
NUC-029 · hard · transfer · seq 18 · · mcq4
A bismuth-211 nucleus ejects an alpha particle. A classmate writes 'fission' on the worksheet because 'the nucleus divided in two.' What kind of nuclear change is it?
alpha decay KEY
nuclear fission
nuclear fusion
gamma emission
NUC-029 · hard · transfer · seq 19 · · mcq4
A detector notebook shows two light nuclei merging, producing one helium-4 nucleus. The notebook's owner labels it alpha decay because helium-4 'is just an alpha particle.' Which label is right?
nuclear fusion KEY
alpha decay
nuclear fission
beta decay
NUC-030 · hard · application · seq 20 · · mcq4
A student worries that the sun will 'use itself up quickly because its heavy nuclei keep splitting.' Which correction is accurate?
The sun does not run on splitting — light nuclei merge in its core. KEY
The worry is well-founded — the sun's core does split heavy nuclei.
Ordinary burning powers the sun, so no nuclear process is involved at all.
Alpha particles shooting out of its nuclei supply the sun's energy.
NUC-029 · hard · application · seq 21 · · frq
A margin note in an old workbook lists two nuclear changes. Change 1: Two very small nuclei are driven into each other and press together into a single heavier nucleus, giving off energy. Change 2: A giant nucleus, after catching a neutron, bursts into two smaller nuclei of roughly matched size while several neutrons scatter away.
A margin note in an old workbook lists two nuclear changes. Change 1: Two very small nuclei are driven into each other and press together into a single heavier nucleus, giving off energy. Change 2: A giant nucleus, after catching a neutron, bursts into two smaller nuclei of roughly matched size while several neutrons scatter away. (a) Classify each change as nuclear fission or nuclear fusion. (b) Explain each classification by contrasting the nuclei before the change with the nuclei after. (c) Write the quick rule that separates the two kinds of change.
Part a. Classify each change as nuclear fission or nuclear fusion.
Model: Change 1 is nuclear fusion. Change 2 is nuclear fission.
Part b. Explain each classification by contrasting the nuclei before the change with the nuclei after.
Model: Change 1: before, two small, light nuclei; after, one heavier nucleus. Two light nuclei merging into one heavier nucleus is fusion. Change 2: before, one large, heavy nucleus (plus the caught neutron); after, two smaller nuclei with several scattered neutrons. A heavy nucleus splitting into two smaller nuclei is fission.
Part c. Write the quick rule that separates the two kinds of change.
Model: The quick rule: fission starts with a heavy nucleus; fusion starts with light nuclei.
Full model answer. (a) Change 1 is nuclear fusion. Change 2 is nuclear fission. (b) Change 1: before, two small, light nuclei; after, one heavier nucleus. Two light nuclei merging into one heavier nucleus is fusion. Change 2: before, one large, heavy nucleus (plus the caught neutron); after, two smaller nuclei with several scattered neutrons. A heavy nucleus splitting into two smaller nuclei is fission. (c) The quick rule: fission starts with a heavy nucleus; fusion starts with light nuclei.

Form E

NUC-027 · easy · recall · seq 1 · · mcq4
Nuclear fission is best summed up as which change?
A large, heavy nucleus splitting into two smaller nuclei. KEY
Two small, light nuclei merging into one heavier nucleus.
A nucleus shedding one alpha particle and staying otherwise whole.
Electrons rearranging while every nucleus keeps its makeup.
NUC-028 · easy · recall · seq 2 · · mcq4
Nuclear fusion is best summed up as which change?
Two small, light nuclei merging into one heavier nucleus. KEY
One large, heavy nucleus splitting into two smaller nuclei.
A nucleus shooting out an alpha particle and becoming lighter.
Two atoms bonding into one molecule through electron sharing.
NUC-030 · easy · recall · seq 3 · · mcq4
Pick the place where nuclear fission is the energy-releasing process.
the reactor core of a nuclear power plant KEY
the seething core of the sun
the core of a distant star
a solar panel in full sunlight
NUC-029 · easy · recall · seq 4 · · mcq4
Fill in the classroom rule: 'Fission starts ___, fusion starts ___.'
heavy; light KEY
light; heavy
hot; cold
slow; fast
NUC-027 · easy · application · seq 5 · · mcq4
In a block of heavy fuel, what normally has to reach a nucleus to make it undergo fission?
A neutron, which the nucleus absorbs. KEY
An electron, which the nucleus absorbs.
Enough heat to begin melting the nucleus.
Another heavy nucleus moving fast enough to hit it.
NUC-028 · medium · application · seq 6 · · mcq4
To make its light nuclei merge, an experiment must first push the fuel's temperature to millions of degrees. What is all that temperature for?
Speed — the positive charges on the nuclei repel, and only enormously fast collisions bring the nuclei close enough to merge. KEY
Melting — the fuel's nuclei have to turn liquid before any two of them can pour together into one nucleus.
Electrons — the temperature frees electrons that then hold the two merging nuclei in one piece.
Breaking — the temperature splits every nucleus so the fragments can regroup as heavier nuclei.
NUC-030 · medium · application · seq 7 · · mcq4
Betelgeuse glows red and immense in the winter sky. The energy behind that glow is released by which process?
nuclear fusion KEY
nuclear fission
an ordinary chemical fire
alpha decay of its heavy elements
NUC-027 · medium · application · seq 8 · · mcq4
Choose the event that is nuclear fission.
A protactinium-231 nucleus absorbs a fast-moving neutron and splits into two smaller nuclei of similar size, releasing three neutrons. KEY
A radium nucleus launches one alpha particle and carries on as a single nucleus.
A cesium nucleus quietly turns a neutron into a proton, staying in one piece.
An energized technetium nucleus lets go of a burst of gamma radiation while keeping its whole makeup exactly as it was before.
NUC-029 · medium · application · seq 9 · · mcq4
In the core of a massive star, a carbon-12 nucleus merges with another carbon-12 nucleus, forming a single magnesium-24 nucleus. What kind of nuclear reaction is this?
nuclear fusion KEY
nuclear fission
alpha decay
beta decay
NUC-029 · medium · application · seq 10 · · mcq4
Read the equation, then name the kind of nuclear reaction it shows. ²³²₉₀Th + ¹₀n → ¹⁴²₅₄Xe + ⁸⁸₃₆Kr + 3 ¹₀n
nuclear fission KEY
nuclear fusion
alpha decay
beta decay
NUC-028 · medium · application · seq 11 · · mcq4
Which statement correctly traces the energy released by a fusion reaction back to its source?
A small amount of the nuclear mass converts into a very large amount of energy. KEY
The collision's heat is simply handed back as the nuclei merge.
Every bit of the two nuclei turns into energy, leaving nothing behind.
Electrons spiraling into the product nucleus radiate the energy away.
NUC-030 · medium · application · seq 12 · · mcq4
A mountain weather station runs on one small solar panel. The power it gathers began as energy released by which process?
nuclear fusion in the sun's core KEY
nuclear fission in the sun's core
chemical burning at the sun's surface
nuclear fusion inside the station's panel
NUC-027 · medium · application · seq 13 · · mcq4
Compared with a chemical reaction of the same mass of material, how much energy does the complete fission of a small fissile sample release?
Around a million times more. KEY
Around a thousand times more.
About the same amount.
Less, since nuclear splits consume energy overall.
NUC-030 · medium · application · seq 14 · · mcq4
A quiz-show host announces that the sun 'is on fire, burning away like charcoal.' Which correction wins the point?
The sun runs on nuclear fusion — light nuclei merging deep in its core. KEY
The sun is powered by nuclear fission — heavy nuclei splitting deep in its core.
The host is right — the sun is an actual fire, simply enormous.
The sun is powered by alpha particles flying off its surface.
NUC-028 · medium · application · seq 15 · · mcq4
Which listed event is a fusion event?
Two light nuclei collide head-on and unite into a single heavier nucleus. KEY
A heavy nucleus, after absorbing a neutron, splits into two smaller nuclei.
A nucleus expels an alpha particle, ending up a bit lighter.
Two whole atoms bond by sharing their outer electrons.
NUC-029 · medium · application · seq 16 · · mcq4
In a research device, one extremely heavy nucleus absorbs a stray neutron and splits into two mid-sized nuclei, throwing out several neutrons. What kind of nuclear reaction is this?
nuclear fission KEY
nuclear fusion
beta decay
gamma emission
NUC-027 · hard · transfer · seq 17 · · mcq4
A californium-250 nucleus occasionally splits by itself into two smaller nuclei and several neutrons, absorbing nothing first. How should this event be classified, and why?
As fission — because the defining feature is the split into two smaller nuclei, not the presence of a trigger. KEY
Not as fission — because true fission events begin with the nucleus absorbing a neutron.
Not as fission — because a nucleus acting alone is limited to alpha and beta emissions.
As fission — but strictly on the grounds that an internal neutron must have been re-absorbed first.
NUC-029 · hard · transfer · seq 18 · · mcq4
A francium-221 nucleus ejects an alpha particle. A younger student insists this is fission — 'part of the nucleus left, so it split.' What kind of nuclear change is it?
alpha decay KEY
nuclear fission
nuclear fusion
beta decay
NUC-029 · hard · transfer · seq 19 · · mcq4
Two light nuclei combine, and the one product nucleus is helium-4, so a review sheet marks the event as alpha decay, claiming any helium-4 nucleus must be an ejected alpha particle. What kind of nuclear change is described?
nuclear fusion KEY
alpha decay
nuclear fission
gamma emission
NUC-030 · hard · application · seq 20 · · mcq4
In which one of the four locations below are nuclei MERGING as the main energy-releasing process?
the core of a distant star KEY
the reactor core of a nuclear power plant
a solar panel in full sunlight
an ordinary campfire
NUC-029 · hard · application · seq 21 · · frq
An exam review card shows two boxed descriptions. Box 1: One oversized nucleus catches a drifting neutron and divides into two smaller nuclei of roughly even size; several neutrons leave as well. Box 2: Two lightweight nuclei ram together and lock into one heavier nucleus, with energy given out.
An exam review card shows two boxed descriptions. Box 1: One oversized nucleus catches a drifting neutron and divides into two smaller nuclei of roughly even size; several neutrons leave as well. Box 2: Two lightweight nuclei ram together and lock into one heavier nucleus, with energy given out. (a) Classify each boxed description as nuclear fission or nuclear fusion. (b) Back up each classification by weighing the nuclei before the reaction against the nuclei after it. (c) Note the quickest tell that works for any nuclear reaction of these two kinds.
Part a. Classify each boxed description as nuclear fission or nuclear fusion.
Model: Box 1 is nuclear fission. Box 2 is nuclear fusion.
Part b. Back up each classification by weighing the nuclei before the reaction against the nuclei after it.
Model: Box 1: before, one large, heavy nucleus (plus the caught neutron); after, two smaller nuclei and several released neutrons. A heavy nucleus splitting into two smaller nuclei is fission. Box 2: before, two small, light nuclei; after, one heavier nucleus. Two light nuclei merging into one heavier nucleus is fusion.
Part c. Note the quickest tell that works for any nuclear reaction of these two kinds.
Model: The quickest tell: fission starts with a heavy nucleus, fusion starts with light nuclei.
Full model answer. (a) Box 1 is nuclear fission. Box 2 is nuclear fusion. (b) Box 1: before, one large, heavy nucleus (plus the caught neutron); after, two smaller nuclei and several released neutrons. A heavy nucleus splitting into two smaller nuclei is fission. Box 2: before, two small, light nuclei; after, one heavier nucleus. Two light nuclei merging into one heavier nucleus is fusion. (c) The quickest tell: fission starts with a heavy nucleus, fusion starts with light nuclei.

End of Topic Test: Applications and safety (u14-t5 · 5 forms × 21 items · 105 total)

David's notes for James:
full notes file
# u14-t5 — notes/queries from David's side (U14-G5)

1. FRQ COMPOSITION - frq_per_form = 1 (your gate data's frq_per_form=1 concurs): the calc-heavy FRQ split was EVALUATED AND NOT TRIGGERED after an honest predicate check - the scope has exactly ONE capstone (NUC-031 Radiometric dating, the only quant atom) and exactly ONE calculation family (age = number of half-lives x half-life, whole half-lives only per D2, the fraction always GIVEN - no exponentials/logs); NUC-032/033/034 are fact atoms and NUC-035 an explanation atom, so NO second production routine exists to evidence (contrast U11-G4, where two capstones forced the split); a second FRQ would double-sample the one dating formula (U10-G1/U12-G2 wave precedent). The single FRQ = the NUC-031 dating routine at terminal seq 21 (D6), 3-part: (a) count the halvings from the given fraction with the chain shown, (b) age with the equation, the substitution, and the result with its unit, (c) diagnose the denominator-as-count misconception from a stated wrong classmate answer and give the correcting rule. Rubric 30/40/30 = 100; model answers fully typeable, zero scaffold stage-markers, zero sub/superscripts (V-T12). D5 scaling evaluated and NOT applied: min(20, 6 x 5) = 20 objective rows, an even 4/4/4/4/4 allocation (the capstone carries 4 objective rows + the FRQ; every row a distinct taught surface, enumerated in blueprint case_targets). Mix per form: recall 3 / application 13 / transfer 4; interactions 17 mcq4 + 3 numeric + 1 frq.
2. NUMERIC-ENTRY LANE - NUC-031 is atomKind quant with 'produce/calculate behaviour -> numeric entry throughout' in its OWN extraNotes and all three of your NUC-031 gate seeds are numeric: its three calculation rows (seqs 4/9/16) are numeric ENTRY on every form, matching your seed interactions 1:1 (HS rule beats the AP gate-exception). V-T6 ran FULLY ARMED over the 15 live numeric items (zero relief lanes). All contracts: value + unit + sigFigs + acceptedAlternates (+integer:true where applicable), exact division, never a bare power of ten, display IS the graded value, unit lives in answer.unit.
3. COURSE-WIDE INSTANCE RULE + U14 PHRASING PACK (binding, final wave) - nuclear applications ARE the topic, so the language stays curricular and clinical exactly as the lessons teach: carbon-14/potassium-40 dating, generic gamma tracers, external-beam therapy geometry, the power-plant energy chain, source-danger logic, americium smoke detectors. BANNED-INSTANCE LEDGER (confirm all four): (a) your p1's uranium-238 meteorite -> an unnamed real-style long clock (course-wide never-uranium rule; re-clocking to K-40 was REJECTED because 1/2-remaining K-40 is WE2's moon-rock instance); (b) your p14's plutonium-238 pacemaker -> the lesson's OWN americium smoke-detector sealed-alpha register (never-plutonium; identical tested skill - the casing stops the particles before any tissue; no mass number, '241' is fluency-3 corpus); (c) your p9's 'in the reactor' -> 'at a nuclear power plant' (the lesson's own term; never-reactors rule); (d) 'uranium fuel' RETAINED ONLY inside the seq-7/11 NUC-034 register - the pellet-vs-ton-of-coal fact its extraNotes fix as 'must not change' and the burning-correction stem (the energy-chain lesson cannot be tested without its chain; zero engineering/chain-reaction/enrichment content anywhere). Packaging re-sweep over forms_final student-facing fields AND this export body: 'uranium' occurs ONLY in that seq-7/11 register (stems as 'uranium fuel'; the seq-7 density-misconception distractor/feedback naming the same fuel substance); ZERO hits on plutonium/enrich*/weapon*/bomb*/warhead*/meltdown*/chain-reaction/fissile/reactor/radon in any student-facing field; 'dose(s)' sits only in the taught therapy-geometry register (equal tumor dose, seqs 8/18 - the pack's allowed clinical register, no harm quantification); 'fission' appears only as NUC-034's own taught mechanism word in the energy-chain lane. Zero content-filter events across every authoring/blind/sol round - the clinical phrasing held.
4. ADJUDICATED CLOCK FAMILIES - THE HEADLINE (gate_config.json; needs your + David's confirmation): three recorded V-T7 families, minimal-surface by design (U14-G1 barred-number design-out + U8-G3 taught-constant canon): taught-clock-c14 tokens {5730, 14} at A#9 ONLY (your demo_curated[0] spear-handle seed - C-14 dating is the capstone's flagship skill and its constants are fixed reals per extraNotes 'Half-lives are real and must not change: carbon-14 5,730 years', so ANY C-14 item collides with spec numbers by construction); taught-clock-k40 tokens {1.25, 40} at C#9 ONLY (rule line 7 names potassium-40 and 1.25 billion years verbatim; the item states no decay mode, honoring extraNotes); register-clock-carbon material 'carbon' at A#9 (the isotope name IS the clock - the flagship item cannot be phrased without it). Exactly ONE C-14 item and ONE K-40 item bank-wide; every other dating slot runs unnamed real-style clocks under rule 7's 'the same routine works with other isotopes'. Enforced by the gate-local validate_with_adjudications.py wrapper over the UNTOUCHED shared validator: 3/3 V-T7 fail lines excused, 0 uncovered, parity guard MATCH, exit 0.
5. NUMBER LEDGER (computed, blueprint allocation_notes): every scannable number token is bank-unique and absent from the NUC-031..035 spec corpus; barred set enumerated (13/123/99/67 NUC-032; 60 Co-60; 210/241 NUC-035; 730/460/190/920/680/91/2865/2.5/16/11460/17190/22920/91680 NUC-031) with the register constants 5730/14/1.25/40 confined to their adjudicated slots; halving denominators 2/4/8 are NUM_IGNORE and reusable, 1/32 lives only at A#9 (your seed) and 1/64 only at B#9; percents 50/25/12.5/6.25/3.125 used once each (seq 16, one per form); no comma-grouped numerals (your seed's '28,650' display -> '28650', the comma form kept as an acceptedAlternate). Final fraction/percent roster (seqs 4/9/16): A 1/2, 1/32, 12.5% | B 1/2, 1/64, 25% | C 1/2, 1/8, 6.25% | D 1/2, 1/8, 3.125% | E 1/2, 1/4, 50%; FRQ fractions A 1/4, B 1/8, C 1/4, D 1/4, E 1/8. RECORDED RESIDUE (disclose): E#4 (1/2) and E#16 (50%) share the trivial single-halving read - the percent register is a five-token once-each ledger so a fully dupe-free assignment does not exist; the slots are non-adjacent and were flagged by neither blind reviewer.
6. NUMERIC PRECISION CONTRACT (sol authoritative lane - rulings to confirm): after sol loop-1 failed 9 numeric items for never announcing expected precision, ALL 15 numeric stems now ANNOUNCE it with PER-SEQ templates (seq 4 'Give your answer to N significant figures.'; seq 9 integer answers 'Treat the half-life as exact...' / decimal answers 'Report the age to 3 significant figures.'; seq 16 'The percent and the half-life are exact; give the exact age.') - the templates differ per seq to avoid cross-seq V-T7 grams; acceptedAlternates were aligned with the announced precision (extra-zero alternates dropped); loop-2 then caught the tolerance lane (a loose +/-0.05/0.01 would accept wrong 3-sf neighbours of exactly-computable results) -> tolerance 0.005 on all 8 decimal answers, 0 on integers, E#9's '2.1' alternate dropped against its announced 3 sf (canonical display 2.10). These wave-3 edits were CONTRACT-ONLY - blind packets render byte-identically, so no re-blind was owed. Also sol's real science catch: D#9's draft 7.05-billion-year 'crater-bed core' was older than Earth and the solar system -> half-life re-picked 2.35 -> 1.41 By (3 halvings -> 4.23 By, geologically possible), misconception values re-derived.
7. SEED USAGE - all 15 of your pool items are placed on form A (15 of its 20 objective slots; pool == spec gateItems positionally, VERIFIED; demo_curated[0..2] are byte-identical duplicates of pool[0..2], deduped at stage 1 with both refs cited on the seq 9/4/16 placements). prod_seeds is EMPTY -> the FRQ is authored (the dating routine; NUC-031 owns every part, V-T11). Rows 1/2/3/19/20 + the FRQ are fresh-authored (no seeds exist for those surfaces); forms B-E are fresh-authored parallels. Authored: 90 of 105. Spares: none. Cold list ignored (standing ANSWERS #3).
8. SEED FRESHENING DISPOSITIONS (9 of the 15 placements carried must_freshen_instance under the strict SEED RULING - structure and misconception keys preserved, all fields swept after every swap, QB 3.9; confirm): (a) p0@A#9 stem rephrased OFF the fluency-generator template ('contains 1/32 of its original carbon-14 (half-life 5,730 years)' collides with the f1/f2 stems) - spear handle + 1/32 + the C-14 constants + answer 28650 all KEPT (the adjudicated slot); (b) p1@A#4 uranium-238 -> unnamed long clock (meteorite object + single-halving skill kept: 1/2 x 3.6 -> 3.6 billion years); (c) p2@A#16 answer 17190 = WE1's mammoth-bone value (the spec's own R12 flag) and every whole-half-life C-14 value is corpus-consumed -> unnamed clock, charcoal -> mineral crust (charcoal is organic, C-14-bound), 12.5% presentation KEPT: 452 -> 1356 million years; (d) p3@A#10 the 6-hour rule-line register value and its 30-year neighbour re-valued (five hours word-spelled x 28 years; B-E rotate organs + bank-unique year digits 45/26/39/21); (e) p4@A#14 the energized-Tc-99 / 6-h / two-days / 8-half-lives case IS rule line 6 verbatim -> all forms use generic short-half-life tracers with word-spelled timespans, zero digits; (f) p9@A#11 'in the reactor' -> 'at a nuclear power plant' + explanations rewritten to the lesson's own 'the fuel's nuclei split' level (drops the seed's uranium-235 cite); (g) p11@A#15 the seed's water/steam distractor replaced ('water'/'steam' are own-lesson MATERIALS tokens) -> output-rises-to-compensate misconception; (h) p12@A#5 'stores ... on the same shelf' = WE2's gram and 'lead' is a MATERIALS token -> storage-room/warehouse framings + 'thick-walled container'; (i) p14@A#17 the plutonium pacemaker -> americium smoke detector (skill kept exactly; see the banned-instance ledger).
9. SEED-TOUCHING QC EDITS (confirm, all form A, defect-driven and content-preserving): A#9 (p0) blind review correctly observed radiocarbon dates the wood's DEATH, not the spear's manufacture - the fresh-wood assumption is now STATED ('carved just after its timber was cut from a living tree'; the clock reads from the cutting); constants and ask template unchanged. A#9/A#4/A#16 stems now announce precision per the sol contract lane (class-swept to all 15 numerics, seed slots included). The fraction-cueing sweep left both placed numeric seeds UNTOUCHED (A#9 1/32, A#16 12.5%).
10. BLIND QC LEDGER (provenance): round 1 (r1 = gpt-5.6-sol blind role, r2 = gemini gateway; 105 items x 2 reviewers) = key picks 170/170; keyless 40/40 graded matches (15 numeric deterministic screens + 5 FRQs hand-graded vs sequestered model answers; frq_verdicts.json); 1 hard fail - A#18 F2 two-defensible ('concentrates its energy at the tumor and weakens it everywhere else' is literally TRUE on a cumulative-dose reading) -> rewritten to the unambiguous beam-itself-weakens misconception + CLASS SWEEP of B#18's same construction; 99 advisory flags triaged (all r1's - r2 flagged nothing). Same-wave flag fixes: E#18 key literalism trimmed below the longest distractor; B#2 'happens LAST' -> 'comes LAST' (order-in-chain, not event time); C#15 stem stipulation dropped + absurd turbine-disintegrates distractor -> boiler-shutdown upstream-propagation misconception; D#17 key de-absolutized ('every alpha particle' -> 'the alpha particles'); D#19 'Why must' -> 'Why does dating work best when'; plus the FRACTION-CUEING SWEEP (identical remaining-fraction giveaways within a form) that produced the final roster in the number-ledger note. Re-blind r3/r4 (13 changed items, fresh shuffles): 0 hard fails, 14/14 picks, 6/6 keyless matches. Re-blind r5/r6 (18 sol-wave items): 6/6 picks, 30/30 keyless matches, 2 style flags = accept-classes. Cumulative r1-r6: 190/190 key picks, 76/76 keyless matches.
11. ACCEPTED ADVISORY CLASSES (recorded round-1 dismissals, r1-only; confirm-if-you-care): same-ladder cross-item cueing (~70 flags - blueprint-inherent: 4 rows per lesson rehearse one topic family; U11-G4/U14-G1 precedent); longest-option / definition-echo / detailed-key style notes (V-T4's deterministic measure passes; misconception distractors are naturally shorter); seq-5/12 qualitative hazard comparisons called 'underspecified' (they run the lesson's own taught penetration/ionization model - r1 itself concedes the intended key is unique); B#7's million-fold energy register (NUC-034's own rule line); the seq-10 2x2 factorial option structure (legitimate format - both taught requirements needed); seq-14 qualitative timespans ('several hours', 'hardly any') by design; D#14/D#5 recurring-absolutes option style (the absolutes ARE the misconceptions being tested).
12. SOL AUTHORITATIVE LEDGER (provenance): 3 loops (105 -> 18 -> 8 items): loop-1 13 FAIL = the 9-item numeric precision-contract lane + 4 science/wording (B#5 packaging now pinned 'ordinary cartons with no added shielding'; B#14 half-life stated in words + atoms-stay-in-body clause closes the biological-clearance alternative; C#6 feedback now discriminates external illumination vs escaping gamma rays; D#9 older-than-Earth age re-picked). Loop-2 4 FAIL = the tolerance lane (contract-only wave-3 fixes). Loop-3: 0 FAIL. TERMINAL: 105/105 pass, 0 open fails, NO override classes; subset raw coverage verified per loop (U01-G3 stale-verdict guard). 20 honest-survivor minors on passing items documented in fix_log.md, not patched (mostly one deliberately-absurd distractor per item as a style note; B#7 coal-density ratio wording; C#20 'flips indoors' phrasing resolved by its next clause; D#21's model answer could print 3.30 for input-precision consistency).
13. NOTA/AOTA: zero literal none-/all-of-the-above hits across your 15-seed pool (V-T5 regex clone at stage 1); zero replace_distractor flags (p12's 'Both equally -' option is a substantive flattened-ranking distractor, not AOTA); V-T5 PASS on all forms.
14. GATE_CONFIG - MINIMAL RELIEF SURFACE: extra_materials / extra_category_labels / extra_task_idioms / extra_convention_phrases / extra_convention_tokens are ALL EMPTY - the only relief is the three slot-enumerated clock families above. 'smoke' (seq 17, A#17<->E#17) is already in the shared base MATERIALS lexicon and surfaces only as the designed same-seq A5 WARN, routed to and cleared by blind review. The shared validator was never touched.
15. TITLE - 'End of Topic Test: Applications and safety' (Topic 8's single title, 'Topic 8:' prefix stripped, standing G1-canon convention).

Form A

NUC-032 · easy · recall · seq 1 · authored (rule lines 3-4 read; liver context — bone/thyroid register instances never used) · mcq4
A liver-scan patient has been given a gamma-emitting tracer that collects in the liver. What does the camera outside the patient record to build the image?
The tracer's gamma rays that pass out through the body. KEY
X-rays that the camera itself beams through the patient.
Visible light reflected off the liver's surface.
Tracer atoms that drift out through the skin to the camera.
NUC-034 · easy · recall · seq 2 · authored (chain-link read; which link makes the electricity) · mcq4
In a nuclear power plant's energy chain, which link produces the electricity itself?
The generator, driven by the spinning turbine. KEY
The turbine, which spins near the end of the chain.
The fission in the fuel, which releases electricity directly.
The fuel itself, which stores ready-made electricity.
NUC-033 · easy · recall · seq 3 · authored (purpose read; pamphlet framing) · mcq4
A hospital pamphlet explains radiation therapy. What is the aim of the beams directed at a patient's tumor?
To damage the cancer cells so they stop dividing. KEY
To tag the tumor with radioactivity so scanners can track it later.
To burn the tumor out with intense heat.
To kill germs infecting the tumor.
NUC-031 · easy · application · seq 4 · seed:pool[1]/demo_curated[1] — single-halving meteorite skill kept; uranium-238 instance REMOVED (banned-instance rule; unnamed clock per rule 7), values re-picked bank-unique · numeric
A meteorite holds 1/2 of the radioactive isotope it started with; that isotope's half-life is 3.6 billion years. What is its age, in billions of years? Give your answer to 2 significant figures.
Answer: 3.6 billion years KEY
wrongValueDiagnostics
[
 {
  "value": 7.2,
  "misconception": "you used the 2 in 1/2 as the number of half-lives — reaching 1/2 takes exactly one halving",
  "feedback": null
 },
 {
  "value": 1.8,
  "misconception": "you halved the half-life itself — 1/2 remaining means one full half-life has passed",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Count the halvings: 1 → 1/2. The isotope has halved once.\nage = number of half-lives × half-life\nage = 1 × 3.6 billion years\nage = 3.6 billion years"
}
NUC-035 · medium · application · seq 5 · seed:pool[12]/spec 035 gate1 — which-source-needs-shielding case kept; shelf framing freshened (WE2 gram), 'lead' never used · mcq4
A clinic keeps two small sealed sources in a storage room: one emits gamma rays, the other alpha particles. Staff walk past the doorway many times a day. Which source calls for the thick shielding, and why?
The gamma source — its rays can cross the room and pass through the whole body. KEY
The alpha source — alpha radiation does the most damage of the three types.
The alpha source — its particles travel the farthest from the source.
Neither — a sealed source cannot irradiate anyone.
NUC-032 · medium · application · seq 6 · seed:pool[5]/spec 032 gate3 — kept near-verbatim (instance-free scenario list) · mcq4
Which situation shows a diagnostic tracer at work?
A patient is given a gamma-emitting isotope, and a camera outside images the rays that come out. KEY
A machine outside the body aims beams of radiation into a patient lying under it.
A patient swallows a dye that recolors the tissue seen in an ordinary photograph.
A camera is pointed at a patient who has been given no radioactive isotope of any kind beforehand.
NUC-034 · medium · application · seq 7 · seed:pool[10]/spec 034 gate2 — kept VERBATIM (register fact 'must not change' per extraNotes; million-fold wording restates NUC-004) · mcq4
A single fingertip-sized uranium fuel pellet releases about as much energy as a ton of coal. Which fact explains the enormous difference?
A nuclear change releases around a million times more energy than a chemical change for the same mass of material. KEY
Uranium metal is about a million times denser than coal, so the pellet packs a million times more matter inside.
The pellet releases its energy about a million times faster than a ton of coal burns.
A fuel pellet contains about a million times more atoms than a ton of coal contains.
NUC-033 · medium · application · seq 8 · seed:pool[8]/spec 033 gate3 — kept near-verbatim (fresh vs corpus; 'several weak beams' differs from rule 4's 'several weaker beams') · mcq4
A deep tumor could be treated with one strong beam or with several weak beams crossing at the tumor. Both plans give the tumor the same dose. Why are the several weak beams safer?
Each patch of healthy tissue on the way in takes only one weak beam's dose instead of the full dose. KEY
The weak beams interfere with and cancel each other out everywhere in the body except at the tumor.
Weak beams damage cancer cells more effectively than strong beams do.
Several beams enter more slowly, giving the skin time to recover between them.
NUC-031 · medium · application · seq 9 · seed:pool[0]/demo_curated[0] — spear/1/32/C-14/28650 kept; stem rephrased off the fluency template; constants 5730/14/'carbon' = recorded gate_config families (only C-14 item bank-wide) · numeric
Archaeologists recover a wooden spear handle, carved just after its timber was cut from a living tree. Carbon-14 decays with a 5730-year half-life, and the handle's carbon-14 has fallen to 1/32 of the level it held when the timber was cut. How old is the spear handle, in years? Treat the half-life as exact and give the age in whole years.
Answer: 28650 years KEY
also accepted: 28,650
wrongValueDiagnostics
[
 {
  "value": 183360,
  "misconception": "you used the 32 in 1/32 as the number of half-lives — 1 → 1/2 → 1/4 → 1/8 → 1/16 → 1/32 is 5 halvings",
  "feedback": null
 },
 {
  "value": 22920,
  "misconception": "you stopped counting at 1/16 — reaching 1/32 takes 5 halvings, not 4",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Count the halvings: 1 → 1/2 → 1/4 → 1/8 → 1/16 → 1/32. The carbon-14 has halved 5 times.\nage = number of half-lives × half-life\nage = 5 × 5730 years\nage = 28650 years"
}
NUC-032 · medium · application · seq 10 · seed:pool[3]/spec 032 gate1 — 2x2 structure + heart context kept; register values 6 h / 30 y re-picked (five hours / 28 years) · mcq4
A hospital must choose an isotope for a heart-scan tracer. Which candidate fits the job?
a gamma emitter with a half-life of five hours KEY
an alpha emitter with a half-life of five hours
a gamma emitter with a half-life of 28 years
an alpha emitter with a half-life of 28 years
NUC-034 · medium · application · seq 11 · seed:pool[9]/spec 034 gate1 — 'in the reactor' -> 'at a nuclear power plant' (banned word); steam-in-pellets distractor replaced (material discipline); explanation drops uranium-235 · mcq4
A tour guide at a nuclear power plant says the uranium fuel 'burns' there the way coal burns in a furnace. Which correction is right?
The fuel's energy comes from nuclear fission, not from a chemical burning reaction. KEY
The guide is right — the fuel burns chemically, just at a far higher temperature than coal.
The fuel's energy comes from nuclear fusion of its nuclei.
The fuel's energy was charged into the pellets as electricity at the factory.
NUC-035 · medium · application · seq 12 · seed:pool[13]/spec 035 gate2 — kept near-verbatim (fresh vs corpus; key quotes whitelisted rule line 5) · mcq4
Equal amounts of an alpha emitter and a gamma emitter are accidentally swallowed by two patients. Whose stomach tissue takes more damage, and why?
The alpha patient's — alpha radiation dumps all of its energy into the tissue right around it. KEY
The gamma patient's — gamma radiation is always the most dangerous type wherever it sits.
The alpha patient's — alpha particles bounce around the whole body many times.
The gamma patient's — gamma rays cannot escape once they are inside a body.
NUC-033 · medium · application · seq 13 · seed:pool[7]/spec 033 gate2 — kept near-verbatim (key grams subset-whitelisted vs the setup line) · mcq4
A student says diagnostic tracer scans and radiation therapy use radiation in the same way. What is the key difference?
A tracer sends gamma rays out of the body to make an image; therapy sends radiation into the body to damage a tumor's cells. KEY
A tracer scan sends beams of radiation into the body from outside; therapy collects the rays that come back out of the patient.
There is no difference — both are ways of photographing the inside of the body.
Tracers use radiation to damage cells, only more gently than therapy does.
NUC-032 · medium · application · seq 14 · seed:pool[4]/spec 032 gate2 — fade skill + misconception trio kept; rule-line-6 instance (energized Tc-99 / 6 h / two days / 8 half-lives) replaced with a generic tracer + word-spelled timespan · mcq4
A patient's scan used a tracer that halves away every few hours. Three days later, a meter can barely detect any radioactivity from her body. Why?
So many half-lives have passed that almost none of the tracer is left. KEY
The gamma rays carried the tracer atoms out of her body as they left.
The scanner absorbed the tracer during the scan itself.
Her body's warmth broke the tracer down chemically.
NUC-034 · hard · application · seq 15 · seed:pool[11]/spec 034 gate3 — turbine-jam stem kept; water/steam distractor replaced with output-doubles (material discipline) · mcq4
One night a plant's turbine jams and cannot spin. Which part of the energy chain fails as a direct result?
The generator is no longer driven, so no electricity is produced. KEY
The fission in the fuel immediately stops releasing energy.
The heat from the fuel immediately disappears.
The plant's electricity output doubles to make up for the jam.
NUC-031 · hard · transfer · seq 16 · seed:pool[2]/demo_curated[2] — 12.5% percent-transfer presentation kept; C-14/charcoal instance replaced (answer 17190 = WE1 corpus value; unnamed clock per rule 7) · numeric
A mineral crust lining an old fissure retains 12.5% of a radioactive isotope whose half-life is 452 million years. Give its age, in millions of years. The percent and the half-life are exact; give the exact age.
Answer: 1356 million years KEY
also accepted: 1,356
wrongValueDiagnostics
[
 {
  "value": 5650,
  "misconception": "you used 12.5 as the number of half-lives — turn the percent into a fraction first: 12.5% is 1/8, which is 3 halvings",
  "feedback": null
 },
 {
  "value": 904,
  "misconception": "you stopped counting at 1/4 (25%) — reaching 12.5% takes 3 halvings, not 2",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Turn the percent into a fraction: 12.5% is 1/8. Count the halvings: 1 → 1/2 → 1/4 → 1/8 — the isotope has halved 3 times.\nage = number of half-lives × half-life\nage = 3 × 452 million years\nage = 1356 million years"
}
NUC-035 · hard · transfer · seq 17 · seed:pool[14]/spec 035 gate3 — casing-stops-the-particles skill + misconception trio kept; plutonium-238 pacemaker instance REMOVED (banned-instance rule) -> americium smoke detector (lesson's own register) · mcq4
The smoke detector on a bedroom ceiling contains a tiny amount of americium, which emits alpha particles — yet it is safe to sleep under. Why?
Its alpha particles are stopped by the detector's casing and never reach anyone's tissue. KEY
Alpha radiation is harmless to people in every situation.
The americium's radioactivity runs out within a few days of installation.
The detector is safe only because no one ever touches it.
NUC-033 · hard · application · seq 18 · seed:pool[6]/spec 033 gate1 — kept near-verbatim (the spec's own arc-therapy transfer; fresh vs corpus) · mcq4
In one machine, a single weak radiation beam swings in a circle around the patient while staying aimed at the tumor the whole time. Why does this protect healthy tissue?
Each patch of healthy tissue is in the beam only briefly, while the tumor stays in the beam the whole time. KEY
The circling motion makes the beam too fast to harm healthy cells.
The motion itself drains the beam's strength, so every spot it crosses — the tumor included — receives only a weakened beam.
The circle keeps the beam entirely outside the healthy tissue.
NUC-031 · hard · transfer · seq 19 · authored (rule-7 transfer; short-clock-on-old-rock direction) · mcq4
Geologists dating rock formations billions of years old never use an isotope whose half-life is a few thousand years. Why not?
After billions of years, essentially none of such an isotope's original amount would remain in the rock. KEY
A short half-life means the isotope decays far too slowly to record ages this long.
Half-lives stretch out over geological time, ruining the count.
Short-half-life isotopes give ages only in even numbers of years.
NUC-035 · hard · transfer · seq 20 · authored (alpha-always-safe claim correction) · mcq4
A student claims: 'Alpha radiation is the safest type — even a piece of paper stops it, so alpha sources are nothing to worry about.' What is the best correction?
The claim holds only while the source is outside the body — an alpha emitter that gets inside does the most damage of all. KEY
The claim is fully correct — alpha sources are safe in every situation.
The claim is exactly backwards — alpha is the most dangerous radiation type even from all the way across a room.
The claim is wrong because nothing as thin as paper can stop radiation.
NUC-031 · hard · application · seq 21 · authored FRQ (no prod seed exists; NUC-031 owns all parts, V-T11; unnamed clock; 1/4 case so the form's percent seed at seq 16 never hands over the count) · frq
A rock core drilled from a canyon wall holds 1/4 of the radioactive isotope it carried when it solidified. The isotope's half-life is 342 million years.
A rock core drilled from a canyon wall holds 1/4 of the radioactive isotope it carried when it solidified. The isotope's half-life is 342 million years. (a) Work out how many half-lives have passed. Show the halving chain you counted. (b) Calculate the age of the rock core. Show the equation you used, the substitution, and the result with its unit. (c) A classmate answers 1368 million years, reasoning that '1/4 remaining means 4 half-lives.' Identify the error and state the rule that fixes it.
Part a. Work out how many half-lives have passed. Show the halving chain you counted.
Model: Count the halvings: 1 -> 1/2 -> 1/4. Two halvings, so 2 half-lives have passed.
Part b. Calculate the age of the rock core. Show the equation you used, the substitution, and the result with its unit.
Model: age = number of half-lives x half-life age = 2 x 342 million years age = 684 million years
Part c. A classmate answers 1368 million years, reasoning that '1/4 remaining means 4 half-lives.' Identify the error and state the rule that fixes it.
Model: The classmate used the 4 in 1/4 as the number of half-lives. The 4 is the fraction's denominator, not the count of halvings — each halving of the level is one half-life, and reaching 1/4 takes 2 halvings. Multiplying 4 x 342 gives 1368 million years, double the true age; the correct count is 2, which gives 684 million years.
Full model answer. (a) Count the halvings: 1 -> 1/2 -> 1/4. Two halvings, so 2 half-lives have passed. (b) age = number of half-lives x half-life age = 2 x 342 million years age = 684 million years (c) The classmate used the 4 in 1/4 as the number of half-lives. The 4 is the fraction's denominator, not the count of halvings — each halving of the level is one half-life, and reaching 1/4 takes 2 halvings. Multiplying 4 x 342 gives 1368 million years, double the true age; the correct count is 2, which gives 684 million years.

Form B

NUC-032 · easy · recall · seq 1 · authored parallel (kidney context) · mcq4
During a kidney scan, a camera panel slowly builds up a picture of the patient's kidneys. The patient was given a gamma-emitting tracer beforehand. Where does the signal the camera records actually come from?
From the tracer inside the patient — its gamma rays escape through the body to the camera. KEY
From the kidneys' own warmth, which the camera senses through the skin.
From a radioactive beam the camera sweeps across the patient's back.
From sound waves bouncing off the kidneys.
NUC-034 · easy · recall · seq 2 · authored parallel (which link is last) · mcq4
Which of these comes LAST in a nuclear power plant's energy chain?
The generator produces electricity. KEY
Heat is released in the fuel.
The turbine begins to spin.
The boiler heats up.
NUC-033 · easy · recall · seq 3 · authored parallel (patient-question framing) · mcq4
Before her first radiation-therapy session, a patient asks what the beams will actually do to her tumor. What is the correct answer?
Damage the cells inside it so they stop dividing. KEY
Melt the tumor away with intense heat.
Make the tumor give off its own gamma rays for the cameras.
Dissolve the tumor chemically.
NUC-031 · easy · application · seq 4 · authored parallel (single-halving case, eruption rock, unnamed clock) · numeric
Rock from an ancient eruption holds 1/2 of its original amount of a radioactive isotope; that isotope's half-life is 1.9 billion years. What is its age, in billions of years? Give your answer to 2 significant figures.
Answer: 1.9 billion years KEY
wrongValueDiagnostics
[
 {
  "value": 3.8,
  "misconception": "you used the 2 in 1/2 as a count of two half-lives — one halving reaches 1/2",
  "feedback": null
 },
 {
  "value": 0.95,
  "misconception": "you divided the half-life by two — a full half-life passes to reach 1/2",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Count the halvings: 1 → 1/2. The isotope has halved once.\nage = number of half-lives × half-life\nage = 1 × 1.9 billion years\nage = 1.9 billion years"
}
NUC-035 · medium · application · seq 5 · authored parallel (warehouse framing) · mcq4
Two labeled packages wait in a courier warehouse overnight: one holds a sealed gamma emitter, the other a sealed alpha emitter of similar strength; both sit in ordinary cartons with no added shielding. For workers moving around the warehouse, which package is the real concern?
The gamma package — gamma rays penetrate out of the package and on through workers' bodies. KEY
The alpha package — alpha particles do the worst damage wherever the source sits.
Both equally — the two types of radiation are equally dangerous from a distance.
The alpha package — its particles ricochet off walls and fill the room.
NUC-032 · medium · application · seq 6 · authored parallel (brochure framing) · mcq4
A hospital brochure lists four procedures. Which one is a tracer scan?
A patient is injected with a gamma-emitting isotope, and a camera maps the rays that escape the body. KEY
A beam of radiation is swept across the patient from a machine overhead.
The patient swallows a colored liquid that shows up in ordinary photographs taken afterward.
A camera photographs the patient after no isotope has been given at all.
NUC-034 · medium · application · seq 7 · authored parallel (exhibit framing; same fixed register fact) · mcq4
An energy exhibit states that one fuel pellet the size of a fingertip can match the output of a whole ton of coal. What makes that possible?
For the same mass, a nuclear change releases about a million times more energy than a chemical change. KEY
Uranium is about a million times denser than coal, so the pellet holds a million times more material.
The pellet burns about a million times hotter than coal.
The pellet holds about a million times more atoms than the ton of coal.
NUC-033 · medium · application · seq 8 · authored parallel (six-beam plan) · mcq4
A treatment plan for a deep tumor uses six weak beams from six angles instead of one full-strength beam. The tumor collects the same total dose either way. What do the six beams buy?
Every patch of tissue on the way in is crossed by just one weak beam instead of the whole dose. KEY
Six beams damage the tumor six times as much.
The six weak beams cancel one another out everywhere in the body except at the tumor.
Six entry points let the radiation dodge the organs entirely.
NUC-031 · medium · application · seq 9 · authored parallel (6-halving case, rockfall slab, unnamed clock) · numeric
A slab from an ancient rockfall retains 1/64 of a radioactive isotope whose half-life is 54 million years. How many million years old is the rockfall? Treat the half-life as exact and give the age in whole millions of years.
Answer: 324 million years KEY
wrongValueDiagnostics
[
 {
  "value": 3456,
  "misconception": "you used the 64 in 1/64 as the number of half-lives — 1 → 1/2 → 1/4 → 1/8 → 1/16 → 1/32 → 1/64 is 6 halvings",
  "feedback": null
 },
 {
  "value": 270,
  "misconception": "you stopped counting at 1/32 — reaching 1/64 takes 6 halvings, not 5",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Count the halvings: 1 → 1/2 → 1/4 → 1/8 → 1/16 → 1/32 → 1/64. The isotope has halved 6 times.\nage = number of half-lives × half-life\nage = 6 × 54 million years\nage = 324 million years"
}
NUC-032 · medium · application · seq 10 · authored parallel (lung context; nine hours / 45 years) · mcq4
Of four available isotopes, which should a clinic pick as the tracer for a lung scan?
one that emits gamma rays and has a half-life of nine hours KEY
one that emits alpha particles and has a half-life of nine hours
one that emits gamma rays and has a half-life of 45 years
one that emits alpha particles and has a half-life of 45 years
NUC-034 · medium · application · seq 11 · authored parallel (museum-video narrator) · mcq4
In a museum's energy hall, a video claims that inside a nuclear power plant 'the fuel slowly burns like a special kind of coal.' What correction does the video need?
The energy is released by fission of the fuel's nuclei — a nuclear change, not burning. KEY
None — the fuel really does burn chemically, only hotter.
The fuel's nuclei fuse together to release the energy.
The fuel releases no energy at all; the plant's boiler creates the energy.
NUC-035 · medium · application · seq 12 · authored parallel (lab-accident framing) · mcq4
During a lab accident, one worker swallows a trace of an alpha-emitting compound and another swallows the same amount of a gamma-emitting compound. Which worker's gut lining is worse off, and why?
The first worker's — every bit of the alpha energy is deposited in the tissue right beside the emitter. KEY
The second worker's — gamma radiation is the most harmful kind in any location.
The first worker's — alpha particles ricochet through the whole body for hours.
The second worker's — gamma rays are trapped inside the body once swallowed.
NUC-033 · medium · application · seq 13 · authored parallel (pamphlet framing) · mcq4
A pamphlet lumps tracer scans and radiation therapy together as 'radiation medicine.' What actually separates them?
In a scan the radiation travels out of the patient to make an image; in therapy it is sent into the patient to damage tumor cells. KEY
In a scan the radiation is beamed in from the outside; in therapy the patient's own rays are collected and measured.
Nothing separates them — both procedures photograph the body's interior.
Therapy uses sound waves while scans use radiation.
NUC-032 · medium · application · seq 14 · authored parallel (clinic-door framing) · mcq4
A tracer with a half-life of six hours was used on a patient on Monday; the tracer's atoms remain in the body rather than being flushed out. By Thursday the patient sets off no detectors at the clinic door. What happened to the tracer?
It decayed away, one half-life after another, until almost none remained. KEY
It was filtered out completely by the clinic's detectors.
It escaped with the gamma rays it emitted.
It stopped decaying once the scan ended.
NUC-034 · hard · application · seq 15 · authored parallel (disconnected-coupling framing) · mcq4
During maintenance, the coupling between a plant's turbine and its generator is accidentally disconnected while everything else keeps running. What is the direct consequence?
The generator stops turning, so the plant stops producing electricity. KEY
The fission in the fuel shuts down at once.
The fuel cools instantly to room temperature.
The turbine can no longer spin without its generator attached.
NUC-031 · hard · transfer · seq 16 · authored parallel (25% case, rock crystals, unnamed clock) · numeric
Tiny crystals inside a rock sample retain 25% of a radioactive isotope whose half-life is 641 million years. Give the sample's age, in millions of years. The percent and the half-life are exact; give the exact age.
Answer: 1282 million years KEY
also accepted: 1,282
wrongValueDiagnostics
[
 {
  "value": 16025,
  "misconception": "you used 25 as the number of half-lives — turn the percent into a fraction first: 25% is 1/4, which is 2 halvings",
  "feedback": null
 },
 {
  "value": 641,
  "misconception": "you counted only one halving — reaching 25% takes 2 halvings",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Turn the percent into a fraction: 25% is 1/4. Count the halvings: 1 → 1/2 → 1/4 — the isotope has halved 2 times.\nage = number of half-lives × half-life\nage = 2 × 641 million years\nage = 1282 million years"
}
NUC-035 · hard · transfer · seq 17 · authored parallel (sealed calibration capsule) · mcq4
A sealed calibration source used in a physics class emits alpha particles inside a closed metal capsule. Students handle the capsule freely. What makes that acceptable?
Alpha particles cannot pass the capsule wall, so none of the radiation reaches living tissue. KEY
Alpha particles are too slow-moving to injure a person.
Handling a sealed source switches off its decay.
The capsule converts the alpha particles into harmless visible light.
NUC-033 · hard · application · seq 18 · authored parallel (slow-arc framing) · mcq4
A therapy machine moves its single weak beam along a slow arc across the patient's torso, always pointing at the deep tumor. How does the moving arc spare the healthy tissue in the beam's path?
Each spot of healthy tissue is swept past in a moment, while the tumor is targeted throughout the arc. KEY
The arc's motion makes the beam bounce off healthy cells.
Moving the source drains the beam's strength, so every spot it crosses — the tumor included — receives a weakened beam.
The arc lets the beam reach the tumor without passing through any healthy tissue at all.
NUC-031 · hard · transfer · seq 19 · authored parallel (long-clock-on-young-object direction) · mcq4
To date an object only a few thousand years old, an isotope with a half-life near a billion years is a poor clock. What goes wrong?
In a few thousand years, far less than one half-life passes — the isotope's level has barely moved. KEY
Billion-year isotopes occur only inside rocks, never in smaller objects.
A long half-life makes the isotope decay away completely before the object forms.
Isotopes with long half-lives emit no radiation at all.
NUC-035 · hard · transfer · seq 20 · authored parallel (skin-shield claim) · mcq4
'If radiation can't get through my skin, it can't hurt me,' a worker says about alpha radiation. Where does this reasoning fail?
It ignores emitters that enter the body — with no skin in the way, alpha radiation does the most damage of all. KEY
Nowhere — skin protects a person against every radiation hazard.
Everywhere — alpha particles actually pass through skin easily.
It fails only because skin actually stops gamma rays rather than stopping the alpha particles.
NUC-031 · hard · application · seq 21 · authored FRQ parallel (1/8 case, landslide slab) · frq
A slab of ancient rock uncovered by a landslide still carries 1/8 of its original radioactive isotope; that isotope halves every 1.15 billion years.
A slab of ancient rock uncovered by a landslide still carries 1/8 of its original radioactive isotope; that isotope halves every 1.15 billion years. (a) Work out how many half-lives have passed. Show the halving chain you counted. (b) Calculate the slab's age. Show the equation you used, the substitution, and the result with its unit. (c) A classmate answers 9.2 billion years after multiplying the half-life by 8. Identify the error and state the rule that fixes it.
Part a. Work out how many half-lives have passed. Show the halving chain you counted.
Model: Count the halvings: 1 -> 1/2 -> 1/4 -> 1/8. Three halvings, so 3 half-lives have passed.
Part b. Calculate the slab's age. Show the equation you used, the substitution, and the result with its unit.
Model: age = number of half-lives x half-life age = 3 x 1.15 billion years age = 3.45 billion years
Part c. A classmate answers 9.2 billion years after multiplying the half-life by 8. Identify the error and state the rule that fixes it.
Model: The classmate used the 8 in 1/8 as the number of half-lives. The 8 is the fraction's denominator, not the count of halvings — each halving is one half-life, and reaching 1/8 takes 3 halvings. Multiplying 8 x 1.15 gives 9.2 billion years, far too old; the correct count is 3, which gives 3.45 billion years.
Full model answer. (a) Count the halvings: 1 -> 1/2 -> 1/4 -> 1/8. Three halvings, so 3 half-lives have passed. (b) age = number of half-lives x half-life age = 3 x 1.15 billion years age = 3.45 billion years (c) The classmate used the 8 in 1/8 as the number of half-lives. The 8 is the fraction's denominator, not the count of halvings — each halving is one half-life, and reaching 1/8 takes 3 halvings. Multiplying 8 x 1.15 gives 9.2 billion years, far too old; the correct count is 3, which gives 3.45 billion years.

Form C

NUC-032 · easy · recall · seq 1 · authored parallel (brain context) · mcq4
A patient receives a gamma-emitting tracer for a brain scan. Minutes later, a detector panel near the patient's head starts registering a signal. What is the panel detecting?
Gamma rays from the tracer passing out through the patient's body. KEY
Electric currents produced by the brain itself.
Alpha particles from the tracer crossing the skull to the panel.
Radio waves that the panel bounces off the tracer.
NUC-034 · easy · recall · seq 2 · authored parallel (turbine's job) · mcq4
What is the job of the turbine in a nuclear power plant?
To spin and drive the generator. KEY
To split the fuel's nuclei.
To produce the electricity itself.
To cool the fuel down after fission.
NUC-033 · easy · recall · seq 3 · authored parallel (direct read) · mcq4
What does the high-energy radiation aimed at a tumor during therapy do to the tumor's cells?
It damages them so they stop dividing. KEY
It flushes them out of the body.
It converts them into healthy cells.
It freezes them in place without harming them.
NUC-031 · easy · application · seq 4 · authored parallel (1-halving case, canyon layer, unnamed clock) · numeric
A rock layer near the bottom of a canyon still holds 1/2 of the radioactive isotope originally locked inside it; the isotope's half-life is 2.7 billion years. What is its age, in billions of years? Give your answer to 2 significant figures.
Answer: 2.7 billion years KEY
wrongValueDiagnostics
[
 {
  "value": 5.4,
  "misconception": "you used the 2 in 1/2 as the number of half-lives — reaching 1/2 is a single halving",
  "feedback": null
 },
 {
  "value": 1.35,
  "misconception": "you halved the half-life itself — 1/2 remaining means one full half-life has passed",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Count the halvings: 1 → 1/2. The isotope has halved once.\nage = number of half-lives × half-life\nage = 1 × 2.7 billion years\nage = 2.7 billion years"
}
NUC-035 · medium · application · seq 5 · authored parallel (prep-room framing) · mcq4
A physics teacher stores a small alpha source and a small gamma source in the prep room. Only one of them is kept inside a thick-walled container. Which one, and why?
The gamma source, because its rays would otherwise pass out through the room and through anyone nearby. KEY
The alpha source, because alpha radiation is the most damaging kind in every situation.
The alpha source, because its particles can pierce walls that stop gamma rays.
It doesn't matter which — thick walls are needed around both or neither.
NUC-032 · medium · application · seq 6 · authored parallel (clinic-machines framing) · mcq4
Four machines stand in a clinic. Which one is performing a tracer scan?
The one recording gamma rays that stream out of a patient who was given a radioactive isotope earlier. KEY
The one aiming a single strong beam into a patient's body.
The one shining a bright lamp through a patient's hand.
The one photographing a swallowed dye as it slowly recolors the lining of the throat.
NUC-034 · medium · application · seq 7 · authored parallel (truck-bed framing; same fixed register fact) · mcq4
A ton of coal fills a truck bed; the fuel pellet that matches its energy output sits on a fingertip. Which principle explains the mismatch?
Nuclear changes release roughly a million times more energy than chemical changes for the same mass of material. KEY
The pellet's material is compressed so tightly that it weighs as much as the whole truckload.
The pellet's energy is released all at once instead of gradually.
The pellet packs about a million times more atoms into its small volume.
NUC-033 · medium · application · seq 8 · authored parallel (four-beam plan) · mcq4
Planning software offers two options for the same deep tumor: one intense beam, or four gentler beams meeting at the tumor. Why do doctors pick the four-beam plan?
Each path into the body then carries only a gentle beam, while the doses still add up at the tumor. KEY
Gentler beams kill cancer cells more effectively than intense ones.
The four beams cancel each other out in the healthy tissue.
The four beams reflect off one another at the tumor, trapping the energy there.
NUC-031 · medium · application · seq 9 · authored parallel (3-halving case; the lesson's own K-40 rock clock — constants 1.25/40 = recorded gate_config family; only K-40 item bank-wide) · numeric
Potassium-40 has a 1.25-billion-year half-life. Deep in a volcanic rock formation, a sample retains 1/8 of its potassium-40. How old is the formation, in billions of years? Report the age to 3 significant figures.
Answer: 3.75 billion years KEY
wrongValueDiagnostics
[
 {
  "value": 10.0,
  "misconception": "you used the 8 in 1/8 as the number of half-lives — 1 → 1/2 → 1/4 → 1/8 is 3 halvings",
  "feedback": null
 },
 {
  "value": 2.5,
  "misconception": "you stopped counting at 1/4 — reaching 1/8 takes 3 halvings, not 2",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Count the halvings: 1 → 1/2 → 1/4 → 1/8. The potassium-40 has halved 3 times.\nage = number of half-lives × half-life\nage = 3 × 1.25 billion years\nage = 3.75 billion years"
}
NUC-032 · medium · application · seq 10 · authored parallel (digestive-tract context; seven hours / 26 years) · mcq4
A new tracer is needed for imaging the digestive tract. Which isotope profile is right?
gamma-emitting, with a half-life of around seven hours KEY
alpha-emitting, with a half-life of around seven hours
gamma-emitting, with a half-life of around 26 years
alpha-emitting, with a half-life of around 26 years
NUC-034 · medium · application · seq 11 · authored parallel (classmate-sentence framing) · mcq4
A classmate writes: 'Nuclear plants and coal plants both work by burning their fuel.' What is wrong with that sentence?
The nuclear plant's fuel is not burned — its nuclei split by fission, a nuclear change. KEY
Nothing — both plants really do burn their fuel.
The nuclear plant's fuel undergoes fusion, not burning.
Neither plant burns anything — both actually run on electricity stored in their fuel.
NUC-035 · medium · application · seq 12 · authored parallel (contaminated-samples framing) · mcq4
Two contaminated food samples are eaten by mistake: one carries an alpha emitter, the other an equal amount of a gamma emitter. Which diner's digestive tissue suffers more, and why?
The alpha diner's — the alpha particles strike the surrounding tissue directly and give it all their energy. KEY
The gamma diner's — gamma is the top of the danger ranking no matter where the source is.
The alpha diner's — the particles circulate through the bloodstream striking every organ.
The gamma diner's — once inside, gamma rays bounce back and forth without escaping.
NUC-033 · medium · application · seq 13 · authored parallel (job-contrast framing) · mcq4
How does the radiation's JOB differ between a tracer scan and radiation therapy?
In the scan its job is to be detected outside and build an image; in therapy its job is to damage the tumor's cells. KEY
In both, its job is to make an image — therapy just uses stronger pictures.
In both, its job is to damage cells — the scan simply damages them more gently than the therapy does.
In the scan its job is to warm the tissue; in therapy its job is to cool it.
NUC-032 · medium · application · seq 14 · authored parallel (week-later framing) · mcq4
A week after his scan, a patient's tracer radioactivity is essentially zero. Which explanation is right?
The tracer's short half-life meant its radioactivity halved many times over the week, down to almost nothing. KEY
His kidneys destroyed the isotope's nuclei one by one.
The tracer's rays ferried the isotope out through his skin.
The clinic's protective shielding drained away the tracer's stored energy in the days after the scan.
NUC-034 · hard · application · seq 15 · authored parallel (seized-generator framing) · mcq4
Suppose a plant's generator itself seizes up; nothing upstream of it is damaged. What does the plant lose first?
Its electricity output — the generator is the link that produces it. KEY
Its heat — fission stops when the generator seizes.
Its boiler — the boiler shuts down the instant the generator seizes.
Its fuel — the pellets are consumed faster with nowhere to send the energy.
NUC-031 · hard · transfer · seq 16 · authored parallel (6.25% case, sediment layer, unnamed clock) · numeric
A layer of hardened sediment retains 6.25% of a radioactive isotope whose half-life is 152 million years. Give its age, in millions of years. The percent and the half-life are exact; give the exact age.
Answer: 608 million years KEY
wrongValueDiagnostics
[
 {
  "value": 950,
  "misconception": "you used 6.25 as the number of half-lives — turn the percent into a fraction first: 6.25% is 1/16, which is 4 halvings",
  "feedback": null
 },
 {
  "value": 456,
  "misconception": "you stopped counting one halving early — reaching 6.25% takes 4 halvings, not 3",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Turn the percent into a fraction: 6.25% is 1/16. Count the halvings: 1 → 1/2 → 1/4 → 1/8 → 1/16 — the isotope has halved 4 times.\nage = number of half-lives × half-life\nage = 4 × 152 million years\nage = 608 million years"
}
NUC-035 · hard · transfer · seq 17 · authored parallel (museum-case mineral) · mcq4
Inside a museum case sits a mineral that gives off alpha particles. Visitors stand a step away from it all day. Why is the exhibit not endangering them?
Alpha particles are stopped within a short distance and by the case, so they never reach the visitors' living tissue. KEY
The case's glass blocks all types of radiation equally.
Minerals cannot really contain radioactive atoms.
The alpha particles all happen to travel straight upward, safely away from any of the visitors below.
NUC-033 · hard · application · seq 18 · authored parallel (rotating-ring framing) · mcq4
One radiotherapy design rotates the radiation source on a ring around the patient, the beam always trained on the tumor at the ring's center. What is the rotating ring achieving?
The tumor collects dose continuously while every other spot is in the beam only as it sweeps by. KEY
The rotation makes the beam move too quickly to affect any cells.
The ring focuses the beam like a lens, strengthening it only at the center point.
The ring keeps the beam outside the patient's body until it reaches the tumor.
NUC-031 · hard · transfer · seq 19 · authored parallel (three-clock choice) · mcq4
A lab must date volcanic rock nearly two billion years old. Its shelf offers isotopes with half-lives of a few hours, a few thousand years, and about a billion years. Which clock fits, and why?
The billion-year isotope — a readable fraction of it still remains across the rock's whole age. KEY
The few-hours isotope — the quicker the decay, the quicker and sharper the answer.
The few-thousand-years isotope — mid-sized half-lives suit every age.
Any of them — the routine works the same regardless of half-life.
NUC-035 · hard · transfer · seq 20 · authored parallel (podcast-ranking claim) · mcq4
A podcast declares: 'Radiation danger is simple — gamma is always the worst, alpha always the mildest.' Which correction does the ranking need?
It holds only for sources outside the body; once a source is inside, the alpha emitter becomes the most damaging. KEY
None — the ranking never changes with the source's location.
Reverse it everywhere — alpha is always the worst type and gamma is always the mildest type.
Neither type can harm anyone without direct skin contact.
NUC-031 · hard · application · seq 21 · authored FRQ parallel (1/4 case, lakebed sediment) · frq
Sediment that hardened at the bottom of a dried-up lakebed holds 1/4 of the radioactive isotope it acquired as it hardened. The isotope's half-life is 415 million years.
Sediment that hardened at the bottom of a dried-up lakebed holds 1/4 of the radioactive isotope it acquired as it hardened. The isotope's half-life is 415 million years. (a) Work out how many half-lives have passed. Show the halving chain you counted. (b) Calculate the age of the hardened sediment. Show the equation you used, the substitution, and the result with its unit. (c) A classmate answers 1660 million years, reasoning that '1/4 remaining means 4 half-lives.' Identify the error and state the rule that fixes it.
Part a. Work out how many half-lives have passed. Show the halving chain you counted.
Model: Count the halvings: 1 -> 1/2 -> 1/4. Two halvings, so 2 half-lives have passed.
Part b. Calculate the age of the hardened sediment. Show the equation you used, the substitution, and the result with its unit.
Model: age = number of half-lives x half-life age = 2 x 415 million years age = 830 million years
Part c. A classmate answers 1660 million years, reasoning that '1/4 remaining means 4 half-lives.' Identify the error and state the rule that fixes it.
Model: The classmate used the 4 in 1/4 as the number of half-lives. The 4 is the fraction's denominator, not the count of halvings — each halving is one half-life, and reaching 1/4 takes 2 halvings. Multiplying 4 x 415 gives 1660 million years, twice the true age; the correct count is 2, which gives 830 million years.
Full model answer. (a) Count the halvings: 1 -> 1/2 -> 1/4. Two halvings, so 2 half-lives have passed. (b) age = number of half-lives x half-life age = 2 x 415 million years age = 830 million years (c) The classmate used the 4 in 1/4 as the number of half-lives. The 4 is the fraction's denominator, not the count of halvings — each halving is one half-life, and reaching 1/4 takes 2 halvings. Multiplying 4 x 415 gives 1660 million years, twice the true age; the correct count is 2, which gives 830 million years.

Form D

NUC-032 · easy · recall · seq 1 · authored parallel (pancreas context) · mcq4
A student looking at a pancreas-scan image asks what actually drew the bright patch on the screen. Which answer is right?
Gamma rays that left the tracer, passed out of the body, and reached the detector. KEY
Dye molecules that recolor the pancreas so a camera can photograph it.
Gamma rays that the detector fired at the pancreas and collected again.
Tracer particles that collect on the camera lens.
NUC-034 · easy · recall · seq 2 · authored parallel (first link) · mcq4
Where in a nuclear power plant's energy chain does the energy FIRST appear?
As heat released by fission in the fuel. KEY
As ready-made electricity inside the fuel.
As the spinning of the turbine.
As a glow of light in the fuel.
NUC-033 · easy · recall · seq 3 · authored parallel (why-at-all framing) · mcq4
Why is high-energy radiation aimed at a tumor at all?
Because the radiation damages the cancer cells, stopping them from dividing. KEY
Because the radiation shrinks the tumor by drying it out.
Because the tumor absorbs radiation as food, which poisons it.
Because the radiation marks the tumor for the immune system to find.
NUC-031 · easy · application · seq 4 · authored parallel (single-halving case, ridge sample, unnamed clock) · numeric
High on a mountain ridge, a rock sample holds 1/2 of its original store of a radioactive isotope; that isotope's half-life is 2.15 billion years. What is its age, in billions of years? Give your answer to 3 significant figures.
Answer: 2.15 billion years KEY
wrongValueDiagnostics
[
 {
  "value": 4.3,
  "misconception": "you read the 2 in 1/2 as two half-lives — a single halving lands on 1/2",
  "feedback": null
 },
 {
  "value": 1.075,
  "misconception": "you split the half-life in half — reaching 1/2 costs one entire half-life",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Count the halvings: 1 → 1/2. The isotope has halved once.\nage = number of half-lives × half-life\nage = 1 × 2.15 billion years\nage = 2.15 billion years"
}
NUC-035 · medium · application · seq 5 · authored parallel (corridor framing) · mcq4
A radiographer wheels two sealed sources down a corridor: an alpha emitter and a gamma emitter. Which one is the hazard to the people she passes, and why?
The gamma emitter — its rays reach right through passers-by. KEY
The alpha emitter — alpha radiation is the most dangerous type in all circumstances.
The alpha emitter — its particles carry the most energy across the corridor.
Neither — radiation cannot harm anyone in only a few seconds.
NUC-032 · medium · application · seq 6 · authored parallel (procedure-list framing) · mcq4
Which description is a diagnostic tracer scan, rather than some other procedure?
Gamma rays leaving a patient's body are collected by a detector to map where an isotope gathered. KEY
Radiation from an outside source is directed at a growth to destroy its cells.
A dye with no radioactivity is photographed under bright light.
A detector scans a patient who has received no radioactive isotope.
NUC-034 · medium · application · seq 7 · authored parallel (why-can framing; same fixed register fact) · mcq4
Why can a fingertip-sized pellet of uranium fuel do the work of a ton of coal at a power plant?
Because a nuclear change gives out around a million times more energy than a chemical change for the same mass. KEY
Because the pellet is compressed so hard that it secretly weighs a ton.
Because uranium is about a million times denser than coal.
Because coal loses most of its energy up the chimney while the pellet loses none of its own.
NUC-033 · medium · application · seq 8 · authored parallel (why-split framing) · mcq4
Why is it safer to split a tumor's treatment dose among several weak beams fired from different angles than to deliver it all along one line?
Because each column of healthy tissue is crossed by only one of the weak beams, while the tumor sits where they all meet. KEY
Because several beams enter the body more slowly, giving the healthy tissue along each path time to recover.
Because weak beams cannot harm healthy cells at all.
Because the beams cancel each other wherever they are not aimed.
NUC-031 · medium · application · seq 9 · authored parallel (3-halving case, crater-bed core, unnamed clock; half-life re-picked 1.41 By after sol caught the older-than-Earth 7.05 By age) · numeric
A rock core was drilled from an ancient crater bed; the radioactive isotope it formed with has a half-life of 1.41 billion years. Today the core retains 1/8 of that isotope. How old is the core, in billions of years? Report the age to 3 significant figures.
Answer: 4.23 billion years KEY
wrongValueDiagnostics
[
 {
  "value": 11.28,
  "misconception": "you used the 8 in 1/8 as the number of half-lives — 1 → 1/2 → 1/4 → 1/8 is 3 halvings",
  "feedback": null
 },
 {
  "value": 2.82,
  "misconception": "you stopped counting at 1/4 — reaching 1/8 takes 3 halvings, not 2",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Count the halvings: 1 → 1/2 → 1/4 → 1/8. The isotope has halved 3 times.\nage = number of half-lives × half-life\nage = 3 × 1.41 billion years\nage = 4.23 billion years"
}
NUC-032 · medium · application · seq 10 · authored parallel (muscle context; eleven hours / 39 years) · mcq4
Which isotope profile suits a tracer for muscle imaging?
a gamma emitter whose radioactivity halves every eleven hours KEY
an alpha emitter whose radioactivity halves every eleven hours
a gamma emitter whose radioactivity halves every 39 years
an alpha emitter whose radioactivity halves every 39 years
NUC-034 · medium · application · seq 11 · authored parallel (radio-host framing) · mcq4
A radio host describes nuclear fuel as 'just a very slow firewood.' Which reply sets the science straight?
Firewood releases energy by a chemical change; nuclear fuel releases it by fission, a nuclear change. KEY
The host is right — the fuel is a slow-burning timber that releases its energy over years.
Nuclear fuel works by fusing its nuclei, which is a kind of slow fire.
Nuclear fuel is damp, so it cannot burn — otherwise the host would be right.
NUC-035 · medium · application · seq 12 · authored parallel (which-radiation framing) · mcq4
Suppose equal traces of an alpha source and a gamma source end up inside two people's bodies after a swallowing accident. Which radiation does more harm to the tissue around it, and why?
The alpha radiation — with no skin barrier in the way, it unloads all its energy into the surrounding tissue. KEY
The gamma radiation — it is the most dangerous type in every situation.
The alpha radiation — its particles roam throughout the body finding the most sensitive organs.
The gamma radiation — inside a body its rays have nowhere to go.
NUC-033 · medium · application · seq 13 · authored parallel (caregiver framing) · mcq4
A caregiver worries that an imaging scan might treat the disease, or that a treatment session might produce an image. Which statement untangles the two procedures?
The scan's rays leave the body and are recorded as an image; the therapy's beams enter the body to damage the tumor. KEY
The scan's beams enter the body, and the therapy's rays leave it to be recorded.
Both procedures do both jobs at once — every scan treats a little, and every treatment images a little.
Neither procedure involves radiation reaching the patient's tissues.
NUC-032 · medium · application · seq 14 · authored parallel (connect-the-facts framing) · mcq4
Two days after a scan, a checkup finds only a trace of the tracer's radioactivity left. The tracer's half-life is well under a day. Connect the facts.
A half-life well under a day means many halvings fit into two days, leaving almost nothing. KEY
The checkup instruments absorbed what was left of the tracer.
The tracer's atoms left the body along with the emitted rays.
The patient's body cooled the tracer until its decay nearly stopped.
NUC-034 · hard · application · seq 15 · authored parallel (control-room framing) · mcq4
A control-room display shows every link of the energy chain healthy except the turbine, which has thrown a blade and stopped. Which reading drops to zero moments later?
The generator's electricity output. KEY
The heat output of the fuel.
The rate of fission in the fuel.
The temperature of the boiler.
NUC-031 · hard · transfer · seq 16 · authored parallel (3.125% case, sea-floor rock, unnamed clock) · numeric
A sample of ancient sea-floor rock retains 3.125% of a radioactive isotope whose half-life is 93 million years. Give its age, in millions of years. The percent and the half-life are exact; give the exact age.
Answer: 465 million years KEY
wrongValueDiagnostics
[
 {
  "value": 290.625,
  "misconception": "you used 3.125 as the number of half-lives — turn the percent into a fraction first: 3.125% is 1/32, which is 5 halvings",
  "feedback": null
 },
 {
  "value": 372,
  "misconception": "you stopped counting one halving early — reaching 3.125% takes 5 halvings, not 4",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Turn the percent into a fraction: 3.125% is 1/32. Count the halvings: 1 → 1/2 → 1/4 → 1/8 → 1/16 → 1/32 — the isotope has halved 5 times.\nage = number of half-lives × half-life\nage = 5 × 93 million years\nage = 465 million years"
}
NUC-035 · hard · transfer · seq 17 · authored parallel (pocket-case contrast) · mcq4
An engineer carries a small sealed alpha source in a pocket case for instrument checks. Why is this routine safe, when the same source loose inside the body would be a serious matter?
The case absorbs the alpha particles before they reach tissue; loose inside the body, they would strike living tissue directly. KEY
Alpha sources only become radioactive when they are unsealed.
The pocket case reflects every alpha particle straight back into the source instead of letting any particle travel onward.
Radiation cannot act on a person through clothing of any kind.
NUC-033 · hard · application · seq 18 · authored parallel (designs-alike comparison) · mcq4
Instead of several fixed crossing beams, a clinic uses one weak beam that circles the patient, held on the tumor. In what way are the two designs alike?
Both give the tumor the full dose while each patch of healthy tissue takes only a brief or single-beam share. KEY
Both leave the healthy tissue completely untouched.
Both rely on beams canceling each other away from the tumor.
Both work by heating the tumor faster than the healthy tissue around it can ever be heated.
NUC-031 · hard · transfer · seq 19 · authored parallel (why-match principle) · mcq4
Why does dating work best when the chosen isotope's half-life is roughly on the scale of the age being measured?
So a meaningful fraction of the isotope remains — neither all of it gone nor barely any of it decayed. KEY
So the age comes out as a whole number of years.
Because only isotopes whose half-lives sit on the right timescale are radioactive at all.
So the half-life can speed up to match the object's age.
NUC-035 · hard · transfer · seq 20 · authored parallel (gamma-only-policy claim) · mcq4
'We only worry about gamma sources here,' reads a lab's safety sign. In which situation would that policy fail badly?
If an alpha-emitting substance were breathed in or swallowed — inside the body it would do the most damage of all. KEY
If a gamma source were moved farther away from the workers.
If the gamma sources were kept sealed in their containers.
Never — gamma really is the only kind of radiation capable of harming a person in any real way.
NUC-031 · hard · application · seq 21 · authored FRQ parallel (1/4 case, gorge cliff rock) · frq
A cliff face above a river gorge exposes rock holding 1/4 of the radioactive isotope it formed with; that rock's clock isotope halves every 1.65 billion years.
A cliff face above a river gorge exposes rock holding 1/4 of the radioactive isotope it formed with; that rock's clock isotope halves every 1.65 billion years. (a) Work out how many half-lives have passed. Show the halving chain you counted. (b) Calculate the rock's age. Show the equation you used, the substitution, and the result with its unit. (c) A classmate answers 6.6 billion years after multiplying the half-life by 4. Identify the error and state the rule that fixes it.
Part a. Work out how many half-lives have passed. Show the halving chain you counted.
Model: Count the halvings: 1 -> 1/2 -> 1/4. Two halvings, so 2 half-lives have passed.
Part b. Calculate the rock's age. Show the equation you used, the substitution, and the result with its unit.
Model: age = number of half-lives x half-life age = 2 x 1.65 billion years age = 3.3 billion years
Part c. A classmate answers 6.6 billion years after multiplying the half-life by 4. Identify the error and state the rule that fixes it.
Model: The classmate used the 4 in 1/4 as the number of half-lives. The 4 is the fraction's denominator, not the count of halvings — each halving of the level is one half-life, and reaching 1/4 takes 2 halvings. Multiplying 4 x 1.65 gives 6.6 billion years, twice too old; the correct count is 2, which gives 3.3 billion years.
Full model answer. (a) Count the halvings: 1 -> 1/2 -> 1/4. Two halvings, so 2 half-lives have passed. (b) age = number of half-lives x half-life age = 2 x 1.65 billion years age = 3.3 billion years (c) The classmate used the 4 in 1/4 as the number of half-lives. The 4 is the fraction's denominator, not the count of halvings — each halving of the level is one half-life, and reaching 1/4 takes 2 halvings. Multiplying 4 x 1.65 gives 6.6 billion years, twice too old; the correct count is 2, which gives 3.3 billion years.

Form E

NUC-032 · easy · recall · seq 1 · authored parallel (spleen context) · mcq4
In a spleen scan, the bright regions of the image mark where a gamma-emitting tracer has gathered. What carries the information from the spleen to the machine outside?
The tracer's gamma rays, which pass out of the body to the detector. KEY
The patient's blood, which ferries tracer atoms out to the machine.
Magnetic pulses that the machine uses to read the tracer.
Heat rays given off by the gathered tracer.
NUC-034 · easy · recall · seq 2 · authored parallel (link between turbine and electricity) · mcq4
Which link sits immediately between the turbine and the electricity leaving a nuclear power plant?
The generator. KEY
The boiler.
The fuel.
Nothing — the turbine makes the electricity itself.
NUC-033 · easy · recall · seq 3 · authored parallel (one-sentence framing) · mcq4
In one sentence: what is the point of the beams in radiation therapy?
They damage the tumor's cancer cells so the cells stop dividing. KEY
They warm the tumor until its cells fall apart.
They light the tumor up for the treatment cameras.
They deliver medicine particles into the tumor.
NUC-031 · easy · application · seq 4 · authored parallel (1-halving case, ash layer, unnamed clock) · numeric
A buried layer of volcanic ash still holds 1/2 of the radioactive isotope trapped in it when it settled; the isotope's half-life is 3.15 billion years. What is its age, in billions of years? Give your answer to 3 significant figures.
Answer: 3.15 billion years KEY
wrongValueDiagnostics
[
 {
  "value": 6.3,
  "misconception": "you used the 2 in 1/2 as the number of half-lives — reaching 1/2 is a single halving",
  "feedback": null
 },
 {
  "value": 1.575,
  "misconception": "you halved the half-life itself — 1/2 remaining means one full half-life has passed",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Count the halvings: 1 → 1/2. The isotope has halved once.\nage = number of half-lives × half-life\nage = 1 × 3.15 billion years\nage = 3.15 billion years"
}
NUC-035 · medium · application · seq 5 · authored parallel (storeroom-inspection framing) · mcq4
During a safety inspection, an officer finds an alpha source and a gamma source stored side by side. Standing at the far end of the storeroom, which source could still be irradiating him, and why?
The gamma source — its rays cross the storeroom and pass through the body. KEY
The alpha source — alpha particles carry the most energy over long distances.
Both — any radioactive source irradiates the whole room equally.
The alpha source — it is the more dangerous type of source in every setting.
NUC-032 · medium · application · seq 6 · authored parallel (quiz-list framing) · mcq4
A medical student must pick out the tracer study from a quiz list. Which entry is it?
A gamma-emitting isotope is given to the patient, and an external camera images the emerging rays. KEY
A machine bathes the patient's whole body in radiation from above.
A luminous dye glows through the patient's skin for the camera.
A camera scans a patient who was never given any radioactive material of any kind beforehand.
NUC-034 · medium · application · seq 7 · authored parallel (student-doubt framing; same fixed register fact) · mcq4
A student doubts that a single fuel pellet could equal a ton of coal, arguing that 'a pellet is just too small.' What fact resolves the doubt?
Mass for mass, nuclear changes release about a million times more energy than chemical changes. KEY
Small objects concentrate their energy better than large ones.
The pellet is recharged with energy at the plant each night.
The pellet somehow contains about a million times more atoms than the ton of coal.
NUC-033 · medium · application · seq 8 · authored parallel (seven-beam comparison) · mcq4
A dosimetrist compares two plans with identical tumor dose: Plan 1 sends one beam at full strength; Plan 2 sends seven beams, each carrying a small share, aimed to overlap at the tumor. Where is Plan 2's advantage?
On the way in — each entry path sees only a small share of the dose, and only the tumor collects it all. KEY
At the tumor — seven overlapping beams treat it seven times as hard as one beam could.
Everywhere — beams that carry small shares cannot affect any tissue.
Outside the body — the seven beams mostly miss the patient.
NUC-031 · medium · application · seq 9 · authored parallel (2-halving case, lava flow, unnamed clock) · numeric
An ancient lava flow hardened long ago; the radioactive isotope inside it has a half-life of 1.05 billion years. Today the flow keeps 1/4 of that isotope. How old is the flow, in billions of years? Report the age to 3 significant figures.
Answer: 2.1 billion years KEY
wrongValueDiagnostics
[
 {
  "value": 4.2,
  "misconception": "you used the 4 in 1/4 as the number of half-lives — 1 → 1/2 → 1/4 is 2 halvings",
  "feedback": null
 },
 {
  "value": 1.05,
  "misconception": "you counted only one halving — reaching 1/4 takes 2 halvings",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Count the halvings: 1 → 1/2 → 1/4. The isotope has halved 2 times.\nage = number of half-lives × half-life\nage = 2 × 1.05 billion years\nage = 2.10 billion years"
}
NUC-032 · medium · application · seq 10 · authored parallel (blood-flow context; four hours / 21 years) · mcq4
To follow blood flow through a patient's vessels, doctors need a tracer isotope. Which choice works?
a gamma emitter with a four-hour half-life KEY
an alpha emitter with a four-hour half-life
a gamma emitter with a 21-year half-life
an alpha emitter with a 21-year half-life
NUC-034 · medium · application · seq 11 · authored parallel (visitor-question framing) · mcq4
A visitor touring a nuclear power plant asks whether the fuel inside is on fire. What is the accurate answer?
No — the fuel's nuclei are splitting; fission, not fire, releases the energy. KEY
Yes — a controlled fire smolders in the fuel at all times.
No — the energy comes from the fuel's nuclei fusing together.
Yes — but the fire is electric rather than chemical.
NUC-035 · medium · application · seq 12 · authored parallel (safety-quiz framing) · mcq4
A safety quiz asks: a swallowed alpha emitter versus a swallowed gamma emitter, equal amounts — which is the greater danger to the tissue around it, and why?
The alpha emitter — its particles give up all their energy to the tissue immediately around it. KEY
The gamma emitter — gamma radiation always tops the danger ranking.
The alpha emitter — its particles pass through the body many times before stopping.
The gamma emitter — its rays stay locked inside the body forever.
NUC-033 · medium · application · seq 13 · authored parallel (poster framing) · mcq4
A clinic poster contrasts tracer scans with radiation therapy. Which contrast is correct?
Tracer: source inside, rays travel out, an image is made. Therapy: source outside, beams travel in, tumor cells are damaged. KEY
Tracer: source outside, beams travel in. Therapy: source inside the patient, rays travel back out to a detector.
Tracer and therapy: both photograph the tumor, from different angles.
Tracer: damages cells gently. Therapy: damages cells strongly.
NUC-032 · medium · application · seq 14 · authored parallel (wear-off framing) · mcq4
After her morning scan, a patient asks when the tracer will 'wear off.' It gives off gamma rays and halves every several hours. What should she be told?
Within a couple of days — so many halvings will have passed that hardly any tracer will remain. KEY
Never — once atoms are radioactive, they stay radioactive forever no matter how long she waits.
The moment the camera stops recording.
Only if she avoids warm rooms while it decays.
NUC-034 · hard · application · seq 15 · authored parallel (locked-for-repairs framing) · mcq4
If a nuclear plant's turbine is locked for repairs while the fuel keeps releasing heat, why do the lights the plant powers go out anyway?
Because the locked turbine no longer drives the generator, and only the generator makes the electricity. KEY
Because fission cannot continue while the turbine is locked.
Because heat cannot exist anywhere in the plant unless the turbine is spinning to create it.
Because the fuel saves its energy until the turbine returns.
NUC-031 · hard · transfer · seq 16 · authored parallel (50% case, rock chunk, unnamed clock) · numeric
A chunk of ancient rock retains 50% of a radioactive isotope whose half-life is 895 million years. Give its age, in millions of years. The percent and the half-life are exact; give the exact age.
Answer: 895 million years KEY
wrongValueDiagnostics
[
 {
  "value": 1790,
  "misconception": "you used the 2 in 1/2 as the number of half-lives — 50% is 1/2, which is a single halving",
  "feedback": null
 },
 {
  "value": 447.5,
  "misconception": "you halved the half-life itself — 50% remaining means one full half-life has passed",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Turn the percent into a fraction: 50% is 1/2. Count the halvings: 1 → 1/2 — the isotope has halved once.\nage = number of half-lives × half-life\nage = 1 × 895 million years\nage = 895 million years"
}
NUC-035 · hard · transfer · seq 17 · authored parallel (catalog smoke-detector framing) · mcq4
A home-supply catalog notes that its smoke detectors hold an alpha-emitting source sealed in a housing. Why can such a device sit in a kitchen for years without irradiating the family?
The housing stops the alpha particles, so the radiation never reaches anyone's tissue. KEY
After a few weeks the source's nuclei are all used up.
Alpha particles cannot cause any harm even when they are inside a body.
Cooking heat gradually switches the source's decay off.
NUC-033 · hard · application · seq 18 · authored parallel (nurse-question framing) · mcq4
As a therapy beam circles a patient, a nurse asks why the moving beam doesn't simply spread its harm everywhere. What is the answer?
Each outer spot is in the beam only briefly, so its share is small; the tumor at the center never leaves the beam. KEY
The beam's constant circling keeps it moving far too quickly for it to deposit any of its energy in the tissue it crosses.
Healthy tissue reflects the moving beam back outward.
The beam only harms tissue when it is standing still.
NUC-031 · hard · transfer · seq 19 · authored parallel (intern-proposal framing) · mcq4
An intern proposes dating a mountain range's ancient rock with an isotope whose half-life is a few dozen years. What should the supervisor say?
That clock ran out long ago — after so many half-lives, essentially none of the isotope would be left in the rock. KEY
Fine — any radioactive isotope can date any rock.
The half-life is too long for something as old as a mountain range.
It would work perfectly well if the rock samples were kept comfortably warm throughout the whole reading.
NUC-035 · hard · transfer · seq 20 · authored parallel (trainee-summary check) · mcq4
A safety trainee summarizes the unit: 'Outside the body, fear gamma; inside the body, fear alpha.' Is the summary sound?
Yes — gamma rays reach the organs from outside, while an alpha emitter inside dumps all its energy into nearby tissue. KEY
No — the two dangers are exactly the same in both places.
No — it is the reverse: fear alpha outside and gamma inside.
Yes, but only because alpha sources are never actually found anywhere outside of a living human body.
NUC-031 · hard · application · seq 21 · authored FRQ parallel (1/8 case, seabed core) · frq
A core sample raised from beneath an old seabed holds 1/8 of the radioactive isotope it captured when it settled. The isotope's half-life is 264 million years.
A core sample raised from beneath an old seabed holds 1/8 of the radioactive isotope it captured when it settled. The isotope's half-life is 264 million years. (a) Work out how many half-lives have passed. Show the halving chain you counted. (b) Calculate the age of the core sample. Show the equation you used, the substitution, and the result with its unit. (c) A classmate answers 2112 million years, reasoning that '1/8 remaining means 8 half-lives.' Identify the error and state the rule that fixes it.
Part a. Work out how many half-lives have passed. Show the halving chain you counted.
Model: Count the halvings: 1 -> 1/2 -> 1/4 -> 1/8. Three halvings, so 3 half-lives have passed.
Part b. Calculate the age of the core sample. Show the equation you used, the substitution, and the result with its unit.
Model: age = number of half-lives x half-life age = 3 x 264 million years age = 792 million years
Part c. A classmate answers 2112 million years, reasoning that '1/8 remaining means 8 half-lives.' Identify the error and state the rule that fixes it.
Model: The classmate used the 8 in 1/8 as the number of half-lives. The 8 is the fraction's denominator, not the count of halvings — each halving of the level is one half-life, and reaching 1/8 takes 3 halvings. Multiplying 8 x 264 gives 2112 million years, far too old; the correct count is 3, which gives 792 million years.
Full model answer. (a) Count the halvings: 1 -> 1/2 -> 1/4 -> 1/8. Three halvings, so 3 half-lives have passed. (b) age = number of half-lives x half-life age = 3 x 264 million years age = 792 million years (c) The classmate used the 8 in 1/8 as the number of half-lives. The 8 is the fraction's denominator, not the count of halvings — each halving of the level is one half-life, and reaching 1/8 takes 3 halvings. Multiplying 8 x 264 gives 2112 million years, far too old; the correct count is 3, which gives 792 million years.