Unit 1 — End of Topic Tests (reviewer copy: all keys and model answers visible)

End of Topic Test: States of matter and the particle model & Classifying matter (u01-t1 · 5 forms × 21 items · 105 total)

David's notes for James:
full notes file
# u01-t1 — notes/queries from David's side (U01-G1)

1. Row 7 (MPM-006 correct-the-drawing, image options): on forms A-D the corrected key picture's particle count differs from the wrong stimulus count (your own seed pattern - pool[15]); form E was aligned 13->13 during a fix. Should corrected drawings conserve the count?
2. A#13 (MPM-015, your curated gate seed): our authoritative QC initially objected that a does-the-drawing-match-its-label MCQ maps to construction judgment; overridden by MPM-015 specNotes which sanction it. Confirm.
3. FRQ delivery: your `prod` draw-on-paper class is delivered as a typed diagram-PLAN task (state kinds/recipes/counts/spacing; rubric grades the same observables). Confirm this mapping.
4. B#19 stem word 'blend' mildly leans toward the mixture key (single-reviewer flag; passed authoritative QC) - one-word polish candidate.
5. NOTA purge (ANSWERS #2 opportunistic rule): 2 seed distractors replaced - MPM-001 gateItems[0] (A#5) and gateItems[1] (B#5) 'None of the above.' -> substantive misconception-keyed both-states distractors.

Form A

MPM-002 · easy · recall · seq 1 · seed:U01-G1.pool[3] · mcq4
The particles of a material sit in a regular repeating pattern, and each one vibrates around a single spot without ever swapping places. What state is the material in?
Solid. KEY
Liquid.
Gas.
It could be either a solid or a liquid.
MPM-007 · easy · recall · seq 2 · seed:U01-G1/pool[19] · mcq4
Which two state changes are exact opposites of each other?
Evaporation and condensation. KEY
Melting and evaporation.
Freezing and deposition.
Sublimation and condensation.
MPM-011 · easy · recall · seq 3 · seed:U01-G1.pool[29] · mcq4
Which statement gives the correct description of an element?
A pure substance made of only one kind of atom. KEY
A substance that stops being an element when its atoms join into molecules.
Anything made of atoms, whatever kinds they are.
A pure substance whose particles each contain more than one kind of atom, joined together.
MPM-016 · easy · recall · seq 4 · seed:pool[44] · mcq4
What must be true of any homogeneous mixture?
Every part of it has the same makeup and the same properties. KEY
It contains exactly one kind of particle.
Different parts of it stay visible as separate layers, pieces, or specks.
All of its components are liquids.
MPM-001 · medium · application · seq 5 · seed:U01-G1.pool[0] (= MPM-001 gateItems[0], James) · mcq4
A sealed one-liter can holds only air, and the air fills the whole can. The same air is then pumped into a half-size can, and it fills that whole can too. Is the air a solid, a liquid, or a gas?
A gas. KEY
A liquid.
A solid.
Both a liquid and a gas.
MPM-003 · medium · application · seq 6 · seed:pool[6] · mcq4
A stone statue has kept its shape for two thousand years. What does that show about its particles?
Its particles are locked in fixed positions, each only vibrating in place. KEY
They stopped moving two thousand years ago.
They slide past one another too slowly for anyone to notice the flow.
They are packed too tightly to vibrate.
MPM-006 · medium · application · seq 7 · seed:U01-G1 pool[15] (= demo_curated[0], james_curated) · mcq4
The figure shows a student's particle diagram of a gas, which is wrong. Which corrected diagram is right?
FIGURE (figure · ) — see raw spec
raw spec
{
 "option_format": "image",
 "render_contract": "R2 image-XOR-text: options render as pictures ONLY; the 'text'/'key' placeholder strings are internal ids for validation and are never rendered and never used for aria (R23 — descriptions must not exceed what a sighted student sees).",
 "stimulus": {
  "figureType": "particle-box",
  "boxes": [
   {
    "label": null,
    "glyph": "atom",
    "count": 10,
    "spacing": "touching",
    "arrangement": "jumbled",
    "fill": "bottom of box"
   }
  ],
  "style": "the student's wrong gas diagram: ten touching circles jumbled at the bottom of the box"
 },
 "optionFigureSpecs": [
  {
   "option": "key",
   "figureSpec": {
    "figureType": "particle-box",
    "boxes": [
     {
      "glyph": "atom",
      "count": 8,
      "spacing": "far apart",
      "arrangement": "scattered",
      "fill": "whole box"
     }
    ],
    "style": "correct gas: a few circles far apart, spread through the whole box"
   }
  },
  {
   "option": "distractor1",
   "figureSpec": {
    "figureType": "particle-box",
    "boxes": [
     {
      "glyph": "atom",
      "count": 10,
      "spacing": "clear gaps about half a circle wide",
      "arrangement": "jumbled",
      "fill": "bottom of box"
     }
    ],
    "style": "circles still pooled at the bottom, with small but clearly visible gaps between them"
   }
  },
  {
   "option": "distractor2",
   "figureSpec": {
    "figureType": "particle-box",
    "boxes": [
     {
      "glyph": "atom",
      "count": 10,
      "spacing": "touching",
      "arrangement": "jumbled",
      "fill": "top of box"
     }
    ],
    "style": "touching circles moved to the top of the box, bottom left empty"
   }
  },
  {
   "option": "distractor3",
   "figureSpec": {
    "figureType": "particle-box",
    "boxes": [
     {
      "glyph": "atom",
      "count": 10,
      "spacing": "touching",
      "arrangement": "regular rows",
      "fill": "bottom of box"
     }
    ],
    "style": "touching circles in neat regular rows at the bottom of the box"
   }
  }
 ]
}
Picture 1 KEY
Picture 2
Picture 3
Picture 4
MPM-007 · medium · application · seq 8 · seed:U01-G1/pool/17 · mcq4
Inside an old-style light bulb, metal vapor rises off the white-hot filament and turns straight into a thin solid metal film on the cooler glass — no liquid metal ever forms. What is the change called?
Deposition. KEY
Freezing.
Condensation.
Sublimation.
MPM-009 · medium · application · seq 9 · seed:U01-G1/pool/24 · mcq4
A student says, 'There are only three states of matter: solid, liquid, and gas.' Which example shows a fourth state?
An aurora glowing high in the night sky. KEY
A drifting cloud of deodorant mist.
Honey oozing from a squeeze bottle.
The scorching blast of gas from a hair dryer.
MPM-008 · medium · application · seq 10 · seed:pool_20 (gateItem g1; used verbatim - no NOTA/AOTA present, nothing replaced) · mcq4
In a cold-room demonstration, one single mercury particle is followed from solid frozen mercury, through the familiar liquid metal, into mercury vapor. What changes about the particle itself along the way?
Nothing — the particle itself never changes; only spacing and movement change. KEY
It grows larger at each step as it takes in heat.
It turns into a new kind of particle at each state change.
It gets lighter at each of the steps, until it is finally light enough to float away as vapor.
MPM-010 · medium · application · seq 11 · seed:U01-G1/pool[26] · mcq4
A jeweler compares two rings. In the first, all of the atoms are gold atoms. The second is 18-karat gold: gold atoms with copper atoms scattered through them. How do the two rings classify?
The first ring is a pure substance; the second ring is a mixture. KEY
Both rings are pure substances, because both are solid gold objects.
Both rings are mixtures, because every ring contains billions of atoms.
The first ring is a mixture and the second is a pure substance.
MPM-014 · medium · application · seq 12 · seed:U01-G1/pool[38] · mcq4
The figure shows a particle diagram of one boxed sample. Classify the sample.
FIGURE (particle-diagram · stimulus) — box: "four lone single circles mixed with four fused large-and-small two-atom pairs, all widely spaced through one single box" · style: "clean textbook particle diagram, single box"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "particle-diagram",
  "box": "four lone single circles mixed with four fused large-and-small two-atom pairs, all widely spaced through one single box",
  "style": "clean textbook particle diagram, single box"
 }
}
A mixture of an element and a compound. KEY
A single compound.
A mixture of two elements.
A single element.
MPM-015 · medium · application · seq 13 · seed:U01-G1.pool[43] (= MPM-015 gateItems[2], James; demo_curated[4] is a pool duplicate — both refs cited) · mcq4
A student draws the particle diagram shown in the figure and labels it 'a compound'. What does the diagram actually show?
FIGURE (particle-diagram · stimulus) — box: "three identical joined particles, each one dark circle joined to one light circle, mixed with three lone dark circles" · style: "clean textbook particle diagram, single box"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "particle-diagram",
  "box": "three identical joined particles, each one dark circle joined to one light circle, mixed with three lone dark circles",
  "style": "clean textbook particle diagram, single box"
 }
}
A mixture of a compound and an element. KEY
A compound, exactly as the student labeled it.
A single element.
A mixture of two elements.
MPM-017 · medium · application · seq 14 · seed:U01-G1.pool[47] (= MPM-017 gateItems[0], James) · mcq4
Muddy river water looks evenly brown at a glance, but under a hand lens you can see tiny solid specks drifting through the brown liquid. How does the muddy water classify?
A heterogeneous mixture. KEY
A homogeneous mixture.
A pure substance.
A compound.
MPM-018 · medium · application · seq 15 · seed:pool_50 (gateItem g1 = demo curated_5; used verbatim - no NOTA/AOTA present, nothing replaced) · mcq4
A sealed metal cylinder holds greenish-yellow chlorine gas. Every particle inside is a joined pair of two identical chlorine atoms. Classify the cylinder's contents.
An element. KEY
A compound.
A homogeneous mixture.
A heterogeneous mixture.
MPM-018 · medium · application · seq 16 · seed:pool_51 (gateItem g2; demo_curated[6]; used verbatim — no NOTA/AOTA present, nothing replaced) · mcq4
Bronze is a solid metal blend: copper atoms and tin atoms evenly mixed throughout, with the two kinds not joined to each other. Classify bronze.
A homogeneous mixture. KEY
A compound.
An element.
A heterogeneous mixture.
MPM-004 · hard · transfer · seq 17 · seed:U01-G1.pool[10] (MPM-004 gateItems[1]) · mcq4
A foam ball full of tiny sealed gas pockets squashes easily in your hand; a solid glass marble does not squash at all. Using the particles, why does the foam squash?
The trapped gas's particles are far apart, so squeezing pushes them closer together. KEY
The foam's particles are softer than the marble's particles, so each particle itself flattens when pushed.
Squeezing pushes some of the trapped gas's particles out of existence.
The foam's particles slide past one another like the particles of a liquid.
MPM-005 · hard · transfer · seq 18 · seed:U01-G1.pool[14] · mcq4
The figure shows two particle diagrams, box 1 and box 2, with ten circles in each box. Which statement about the two boxes is correct?
FIGURE (particle-box · stimulus) — boxes: [{"label": "1", "glyph": "atom", "count": 10, "spacing": "far apart", "arrangement": "scattered", "fill": "whole box"}, {"label": "2", "glyph": "atom", "coun… · style: "two side-by-side particle boxes labeled 1 and 2, ten identical circles each"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "particle-box",
  "boxes": [
   {
    "label": "1",
    "glyph": "atom",
    "count": 10,
    "spacing": "far apart",
    "arrangement": "scattered",
    "fill": "whole box"
   },
   {
    "label": "2",
    "glyph": "atom",
    "count": 10,
    "spacing": "touching",
    "arrangement": "jumbled",
    "fill": "bottom of box"
   }
  ],
  "style": "two side-by-side particle boxes labeled 1 and 2, ten identical circles each"
 }
}
Box 1 shows a gas and box 2 shows a liquid, because box 1's circles are far apart and box 2's are touching but jumbled. KEY
The two boxes show the same state, because they hold the same number of circles.
Box 1 shows a liquid and box 2 shows a gas, because box 1's circles are the ones touching and box 2's are the ones far apart.
Box 1 shows a gas and box 2 shows a solid, because box 2's circles sit touching in a regular repeating pattern.
MPM-012 · hard · transfer · seq 19 · seed:U01-G1.pool[34] (= MPM-012 gateItems[2], James; used verbatim - no NOTA/AOTA present, nothing replaced, HTML stripped only) · mcq4
A sample jar holds a fine powder blend of two kinds of particles mixed together: some particles join one tin atom to two bromine atoms, and the rest join one tin atom to four bromine atoms. How does the powder blend classify, and why?
As a mixture of two compounds — the two kinds of particles are only mixed together. KEY
As one compound — each particle joins tin atoms to bromine atoms.
As a pure substance — nothing but tin and bromine atoms is present.
As an element — tin atoms appear in each of the jar's particles.
MPM-013 · hard · transfer · seq 20 · seed:pool[37] · mcq4
A magnet easily picks up a pile of small nickel pellets. Arsenic is a dull gray, crumbly powder. Strong heating chemically joins nickel atoms to arsenic atoms, making one new solid. The magnet does not attract the new solid at all. Why?
Being pulled by a magnet was nickel's own property; the new solid is a brand-new substance, made of one new kind of particle. KEY
The nickel is still in the solid as itself; the arsenic around each nickel atom simply blocks the magnet's pull.
The strong heating destroyed the nickel atoms, so nothing magnetic is left anywhere in the solid.
The magnetism moved out of the nickel and into the arsenic when the atoms joined.
MPM-015 · medium · application · seq 21 · seed:U01-G1.pool[41] (= MPM-015 gateItems[0], James; demo_curated[2] is the same gate prod — both refs cited) · frq
In particle diagrams, circles of different sizes or shading stand for different kinds of atoms.
FIGURE (model_answer_diagram · model_answer_diagram) — see raw spec
raw spec
{
 "figureShape": "model_answer_diagram",
 "modelAnswerFigureSpecs": {
  "a": {
   "figureType": "particle-diagram",
   "box": "three large-plus-small joined particles and three two-medium-plus-small joined particles, mixed together, widely spaced, spread through the whole box",
   "style": "clean textbook particle diagram, single labeled box"
  }
 }
}
In particle diagrams, circles of different sizes or shading stand for different kinds of atoms. (a) Plan a particle diagram of a gas mixture of two different compounds. Use one kind of particle made of one large circle joined to one small circle, and a second kind made of two medium shaded circles joined to one small circle. Your plan must include exactly three particles of each kind. In your answer, state which particle kinds you would draw and what each looks like, how many of each kind, and how the particles are spaced and arranged in the box. (b) In one or two sentences, explain how someone reading your diagram can tell it shows a mixture of two compounds and not a single compound.
Part a. Plan a particle diagram of a gas mixture of two different compounds. Use one kind of particle made of one large circle joined to one small circle, and a second kind made of two medium shaded circles joined to one small circle. Your plan must include exactly three particles of each kind. In your answer, state which particle kinds you would draw and what each looks like, how many of each kind, and how the particles are spaced and arranged in the box.
Model: A box containing three joined particles of one large light circle plus one small dark circle, mixed with three joined particles of two medium shaded circles plus one small dark circle. All six particles are widely spaced and spread through the whole box, and no lone circles appear. A mixture of two compounds needs two kinds of joined particles, each kind built from different circles. A joined pair of identical circles would be an element, not a compound. Gas spacing applies to the whole mixture — every particle sits far from its neighbors.
Part b. In one or two sentences, explain how someone reading your diagram can tell it shows a mixture of two compounds and not a single compound.
Model: The box holds two different kinds of joined particles mixed together, and each kind is built from different circles joined — so each kind is a compound. A single compound would repeat only one kind of joined particle, so two mixed kinds make the sample a mixture of two compounds.
Full model answer. (a) A box containing three joined particles of one large light circle plus one small dark circle, mixed with three joined particles of two medium shaded circles plus one small dark circle. All six particles are widely spaced and spread through the whole box, and no lone circles appear. A mixture of two compounds needs two kinds of joined particles, each kind built from different circles. A joined pair of identical circles would be an element, not a compound. Gas spacing applies to the whole mixture — every particle sits far from its neighbors. (b) The box holds two different kinds of joined particles mixed together, and each kind is built from different circles joined — so each kind is a compound. A single compound would repeat only one kind of joined particle, so two mixed kinds make the sample a mixture of two compounds.

Form B

MPM-002 · easy · recall · seq 1 · authored · mcq4
In a sample of quartz, every particle is held at its own position in a neat, orderly arrangement. Each particle jiggles back and forth on the spot, and no particle ever moves past its neighbors. What state is the quartz in?
Solid. KEY
Liquid.
Gas.
It could be either a solid or a liquid.
MPM-007 · easy · recall · seq 2 · authored · mcq4
Which two state changes exactly reverse each other?
Melting and freezing. KEY
Condensation and freezing.
Melting and sublimation.
Evaporation and deposition.
MPM-011 · easy · recall · seq 3 · authored · mcq4
Finish this definition: 'An element is …'
a pure substance made of only one kind of atom. KEY
a substance whose atoms all stay separate instead of joining into groups.
any pure substance whose atoms are all listed on the periodic table.
any substance with an even, uniform look from edge to edge.
MPM-016 · easy · recall · seq 4 · authored · mcq4
What must be true of any heterogeneous mixture?
It keeps parts that remain visibly different. KEY
Every part of it has the same makeup.
It holds a single kind of particle.
No two of its particles share a kind.
MPM-001 · medium · application · seq 5 · seed:U01-G1.pool[1] (= MPM-001 gateItems[1], James) · mcq4
A student squeezes a lump of modeling clay into a new shape and says, 'Its shape changed, so clay is a liquid.' What state is the clay in?
A solid. KEY
A liquid.
A gas.
Both a solid and a liquid.
MPM-003 · medium · application · seq 6 · seed:pool[7] · mcq4
Maple syrup and a steel spoon sit in the same warm kitchen. The syrup slowly flows off the spoon; the spoon stays spoon-shaped. Which particle-level account is correct?
The syrup's particles slide past one another; the spoon's particles are locked in fixed positions. KEY
The syrup's particles are far apart and spreading; the spoon's particles are touching.
The syrup's particles change their shape as they flow; the spoon's particles cannot change their shape.
In both samples, particles slide past one another; the spoon's simply slide far more slowly.
MPM-006 · medium · application · seq 7 · authored · mcq4
The figure shows how a student drew a solid sample of one pure substance, which is wrong. Which corrected diagram is right?
FIGURE (figure · ) — see raw spec
raw spec
{
 "option_format": "image",
 "render_contract": "R2 image-XOR-text: options render as pictures ONLY; placeholder texts never rendered, never used as aria (R23).",
 "stimulus": {
  "figureType": "particle-box",
  "boxes": [
   {
    "label": null,
    "glyph": "atom",
    "count": 12,
    "spacing": "clear gaps about half a circle wide",
    "arrangement": "regular rows",
    "fill": "bottom of box"
   }
  ],
  "style": "the student's wrong solid diagram: twelve same-size circles in a regular repeating pattern two rows deep at the bottom, with clear gaps between every circle"
 },
 "optionFigureSpecs": [
  {
   "option": "key",
   "figureSpec": {
    "figureType": "particle-box",
    "boxes": [
     {
      "glyph": "atom",
      "count": 16,
      "spacing": "touching",
      "arrangement": "regular rows",
      "fill": "block"
     }
    ],
    "style": "correct solid: sixteen same-size circles touching their neighbors in a regular repeating pattern at least two rows deep, forming one block"
   }
  },
  {
   "option": "distractor1",
   "figureSpec": {
    "figureType": "particle-box",
    "boxes": [
     {
      "glyph": "atom",
      "count": 8,
      "spacing": "touching",
      "arrangement": "regular rows",
      "fill": "single row along bottom of box",
      "rowsDeep": 1
     }
    ],
    "style": "touching circles in a regular row only one row deep along the bottom of the box"
   }
  },
  {
   "option": "distractor2",
   "figureSpec": {
    "figureType": "particle-box",
    "boxes": [
     {
      "glyph": "atom",
      "count": 13,
      "spacing": "touching",
      "arrangement": "jumbled",
      "fill": "bottom of box"
     }
    ],
    "style": "touching circles in a jumble filling the bottom of the box with a roughly level top — the liquid picture"
   }
  },
  {
   "option": "distractor3",
   "figureSpec": {
    "figureType": "particle-box",
    "boxes": [
     {
      "glyph": "atom",
      "count": 16,
      "spacing": "touching",
      "arrangement": "regular rows",
      "fill": "block",
      "circleSizes": "two clearly different sizes"
     }
    ],
    "style": "touching circles in a regular repeating pattern, but drawn in two clearly different sizes"
   }
  }
 ]
}
Picture 1 KEY
Picture 2
Picture 3
Picture 4
MPM-007 · medium · application · seq 8 · seed:U01-G1/pool/18 · mcq4
In a fume hood, a small pile of dark gray iodine crystals is gently warmed in a beaker. A violet gas rises straight off the crystals, and no liquid ever appears in the beaker. What is the change called?
Sublimation. KEY
Melting.
Evaporation.
Condensation.
MPM-009 · medium · application · seq 9 · authored · mcq4
A classmate claims, 'Every kind of matter must be one of the three everyday states.' Which example shows a fourth state of matter?
The spark that snaps from a doorknob to your fingertip on a dry day. KEY
The fine mist from a perfume spray.
Cold hand lotion squeezed slowly from its tube.
The roaring blast of gas from a heat gun.
MPM-008 · medium · application · seq 10 · seed:pool_21 (gateItem g2; structure and misconception set kept, instance freshened per must_freshen_instance flag) · mcq4
In a chemistry class, rubbing-alcohol vapor rises from a gently warmed flask and meets a cold metal lid. Drops of liquid rubbing alcohol form on the lid. Which account of the drops is correct at the particle level?
Alcohol particles in the vapor slow down when they meet the cold lid and crowd back into touching, sliding contact. KEY
The cold lid creates brand-new alcohol particles on its surface as the warm vapor arrives and touches it.
Alcohol particles in the vapor lock into fixed positions on the cold lid.
Particles of the lid itself turn into liquid alcohol particles where the warm vapor touches it.
MPM-010 · medium · application · seq 11 · seed:U01-G1/pool[28] (structure+misconceptions kept; instance freshened per must_freshen_instance: sugar water -> camphor in ethanol) · mcq4
A pharmacist stirs camphor crystals into ethanol until every crystal has dissolved. The finished liquid — sold as camphor spirit — looks exactly like plain ethanol, yet the pharmacist calls it a mixture. What makes it a mixture?
It holds two kinds of particles — ethanol molecules with camphor molecules mixed in among them. KEY
Nothing does — once the camphor has dissolved, the camphor is gone and only pure ethanol remains.
It counts as a mixture only while camphor crystals are still visible in the ethanol.
The camphor changes the ethanol molecules into camphor-spirit molecules.
MPM-014 · medium · application · seq 12 · seed:U01-G1/pool[39] · mcq4
The figure shows a particle diagram of one box. Classify the matter inside.
FIGURE (particle-box · stimulus) — boxes: [{"label": null, "glyph": "diatomic-same", "count": 4, "spacing": "far apart", "arrangement": "scattered", "fill": "whole box"}, {"label": null, "glyph": "di… · style: "one box mixing four fused pairs of small circles with four fused pairs of large circles, all well separated"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "particle-box",
  "boxes": [
   {
    "label": null,
    "glyph": "diatomic-same",
    "count": 4,
    "spacing": "far apart",
    "arrangement": "scattered",
    "fill": "whole box"
   },
   {
    "label": null,
    "glyph": "diatomic-same-large",
    "count": 4,
    "spacing": "far apart",
    "arrangement": "scattered",
    "fill": "whole box"
   }
  ],
  "style": "one box mixing four fused pairs of small circles with four fused pairs of large circles, all well separated"
 }
}
A mixture of two elements. KEY
A single compound.
A mixture of two compounds.
A single element.
MPM-015 · medium · application · seq 13 · authored · mcq4
A student draws the particle diagram shown in the figure and labels it 'a compound'. What does the diagram show?
FIGURE (particle-diagram · stimulus) — box: "six identical joined particles, each one large dark circle joined to one medium shaded circle, widely spaced through the whole box, with no lone circles" · style: "clean textbook particle diagram, single box"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "particle-diagram",
  "box": "six identical joined particles, each one large dark circle joined to one medium shaded circle, widely spaced through the whole box, with no lone circles",
  "style": "clean textbook particle diagram, single box"
 }
}
A compound, exactly as the student labeled it. KEY
A mixture of two elements.
A single element.
A mixture of an element and a compound.
MPM-017 · medium · application · seq 14 · seed:U01-G1.pool[49] (= MPM-017 gateItems[2], James) · mcq4
Vegetable broth is simmered with flakes of dried herbs floating in it. A cook then filters out every flake, and the filtered broth looks uniform in every spoonful, with nothing settling over time. What is the filtered broth?
A homogeneous mixture. KEY
A heterogeneous mixture.
A pure substance.
A compound.
MPM-018 · medium · application · seq 15 · seed:pool_52 (gateItem g3 = demo curated_7; structure and misconception set kept, instance freshened per must_freshen_instance flag) · mcq4
A sealed cylinder holds ammonia gas. Every particle of the gas is the same: one nitrogen atom with three joined hydrogen atoms. Classify the cylinder's contents.
A compound. KEY
A heterogeneous mixture.
An element.
A homogeneous mixture.
MPM-018 · medium · application · seq 16 · authored · mcq4
A terrazzo floor tile holds two kinds of matter: chips of crushed stone, set in a hardened clear resin. The stone chips stay visible as distinct flecks against the resin around them. Classify the terrazzo.
A heterogeneous mixture. KEY
A compound.
An element.
A homogeneous mixture.
MPM-004 · hard · transfer · seq 17 · authored · mcq4
A marshmallow is filled with tiny bubbles of gas that were beaten into it when it was made. The marshmallow squashes easily between your fingers, but a hard candy of the same size does not squash at all. Using the particles, why does the marshmallow squash?
The gas particles in the bubbles are far apart, so squeezing pushes them closer together. KEY
The marshmallow's particles are softer than the hard candy's particles, so each particle itself flattens when pushed.
Squeezing pushes some of the gas particles in the bubbles out of existence.
The marshmallow's particles slide past one another like the particles of a liquid.
MPM-005 · hard · transfer · seq 18 · authored · mcq4
In the figure, box 1 and box 2 each contain fifteen circles. Which statement about the two boxes is correct?
FIGURE (particle-box · stimulus) — boxes: [{"label": "1", "glyph": "atom", "count": 15, "spacing": "touching", "arrangement": "regular rows", "fill": "block"}, {"label": "2", "glyph": "atom", "count"… · style: "two side-by-side particle boxes labeled 1 and 2, fifteen identical circles each"
raw spec
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Box 1 shows a solid and box 2 shows a liquid, because box 1's circles sit touching in a regular pattern while box 2's are touching but jumbled. KEY
The two boxes show the same state, because each holds fifteen circles.
Box 1 shows a liquid and box 2 shows a solid, because box 2's circles are the ones sitting in a regular repeating pattern.
Box 1 shows a solid and box 2 shows a gas, because box 2's circles are far apart with wide gaps between them.
MPM-012 · hard · transfer · seq 19 · authored · mcq4
A stoppered glass jar holds a blend of fine crystals: some particles are one titanium atom carrying three joined fluorine atoms, and others are one titanium atom carrying four joined fluorine atoms. How do the jar's crystals classify, and why?
As a mixture of two separate compounds, because the two kinds of particles are only mixed together. KEY
As one compound, because every one of its particles joins titanium atoms to fluorine atoms.
As one pure substance, because nothing except titanium and fluorine atoms is present.
As an element, because titanium atoms appear in every one of the crystals' particles.
MPM-013 · hard · transfer · seq 20 · authored · mcq4
A sealed glass tube holds a dry mix of aluminum powder and dark iodine flakes. Warmed gently, the mix gives off violet vapor, and the aluminum powder is left unchanged. Strong heating then chemically joins the aluminum and iodine atoms into one new pale solid. Warmed gently again, the tube shows no violet vapor at all. Why?
The violet vapor was iodine's own property; the pale solid is a brand-new substance, made of one new kind of particle. KEY
The iodine is still in the solid as itself; the aluminum around it simply traps the violet vapor so none can escape.
The strong heating destroyed the iodine atoms, so nothing that could give off violet vapor remains in the tube.
The pale solid still gives off violet vapor when warmed, just far too little of it for anyone to see.
MPM-015 · medium · application · seq 21 · seed:U01-G1.pool[42] (= MPM-015 gateItems[1], James; demo_curated[3] is the same gate prod — both refs cited) · frq
In particle diagrams, circles of different sizes or shading stand for different kinds of atoms.
FIGURE (model_answer_diagram · model_answer_diagram) — see raw spec
raw spec
{
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   "box": "five identical one-large-plus-two-small joined particles, touching, no fixed pattern, gathered at the bottom of the box",
   "style": "clean textbook particle diagram, single labeled box"
  }
 }
}
In particle diagrams, circles of different sizes or shading stand for different kinds of atoms. (a) Plan a particle diagram of a compound in the liquid state, where every particle contains one large circle and two small circles joined together. Your plan must include at least five particles. In your answer, state which particle kinds you would draw and what each looks like, how many of each kind, and how the particles are spaced and arranged in the box. (b) In one or two sentences, explain how someone reading your diagram can tell it shows a compound and not a mixture.
Part a. Plan a particle diagram of a compound in the liquid state, where every particle contains one large circle and two small circles joined together. Your plan must include at least five particles. In your answer, state which particle kinds you would draw and what each looks like, how many of each kind, and how the particles are spaced and arranged in the box.
Model: A box in which five identical particles — each one large light circle with two small dark circles joined to it — sit in touching contact, in no fixed pattern, gathered at the bottom of the box. No lone circles appear. A compound is one kind of particle, repeated — here, one large plus two small circles joined. Leftover lone circles would turn the drawing into a mixture. Liquid spacing means touching particles in no fixed pattern, gathered at the bottom.
Part b. In one or two sentences, explain how someone reading your diagram can tell it shows a compound and not a mixture.
Model: Every particle in the diagram is identical — the same large-plus-two-small joined group each time — with no lone circles left over. A mixture would show two or more different kinds of particles mixed together in the box, so one repeated kind of particle makes the sample a compound.
Full model answer. (a) A box in which five identical particles — each one large light circle with two small dark circles joined to it — sit in touching contact, in no fixed pattern, gathered at the bottom of the box. No lone circles appear. A compound is one kind of particle, repeated — here, one large plus two small circles joined. Leftover lone circles would turn the drawing into a mixture. Liquid spacing means touching particles in no fixed pattern, gathered at the bottom. (b) Every particle in the diagram is identical — the same large-plus-two-small joined group each time — with no lone circles left over. A mixture would show two or more different kinds of particles mixed together in the box, so one repeated kind of particle makes the sample a compound.

Form C

MPM-002 · easy · recall · seq 1 · authored · mcq4
The particles in a sample of platinum are arranged in tidy, repeating rows. Every particle stays at one place, trembling slightly there, and no particle ever slips past another. What state is the platinum in?
Solid. KEY
Liquid.
Gas.
It could be either a solid or a liquid.
MPM-007 · easy · recall · seq 2 · authored · mcq4
Which two state changes form an opposite pair?
Sublimation and deposition. KEY
Sublimation and evaporation.
Deposition and condensation.
Melting and condensation.
MPM-011 · easy · recall · seq 3 · authored · mcq4
Four classmates each write a short meaning for the word 'element'. Which meaning is correct?
One kind of atom throughout the substance, alone or in joined identical groups. KEY
Mostly one kind of atom, with small traces of other kinds still allowed.
Atoms of any kinds arranged in a tidy repeating pattern.
One single atom on its own, rather than a whole sample of matter.
MPM-016 · easy · recall · seq 4 · authored · mcq4
Which one question decides whether a mixture is called homogeneous or heterogeneous?
Is it the same throughout, or do its parts remain visibly different? KEY
Does the mixture hold more than one kind of particle?
The mixture takes which state of matter?
Which ingredient makes up the largest share of the mixture?
MPM-001 · medium · application · seq 5 · authored · mcq4
Thick wall paint is poured from its tall can into a wide, flat roller tray. The paint slowly flows until it matches the tray's shape, while its volume stays unchanged from can to tray. What is the paint?
A liquid. KEY
A solid.
A gas.
Both a liquid and a gas.
MPM-003 · medium · application · seq 6 · authored · mcq4
Warm gravy poured onto a porcelain plate slowly flows across it, yet the plate itself never changes shape. Why does the gravy flow, but not the plate?
The gravy flows because its particles can slide past one another; the plate keeps its own shape because its particles are locked in fixed positions. KEY
The gravy flows because its particles drift far apart from each other; the plate keeps its own shape because its particles stay touching.
The gravy flows because its particles bend into new shapes as they move; the plate keeps its own shape because its particles cannot bend.
Both flow at the particle level: the plate's particles also slide past one another, only far too slowly to notice.
MPM-006 · medium · application · seq 7 · authored · mcq4
The figure shows a student's particle diagram of a liquid sample of one pure substance, which is wrong. Which corrected diagram is right?
FIGURE (figure · ) — see raw spec
raw spec
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      "fill": "bottom of box"
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    "style": "correct liquid: thirteen same-size circles touching but jumbled, filling the bottom of the box with a roughly level top"
   }
  },
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  },
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      "fill": "heaped high against left wall, steeply sloped top"
     }
    ],
    "style": "touching, jumbled circles heaped up one side of the box with a steeply sloped top"
   }
  },
  {
   "option": "distractor3",
   "figureSpec": {
    "figureType": "particle-box",
    "boxes": [
     {
      "glyph": "atom",
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      "fill": "bottom of box"
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    "style": "touching circles in a regular repeating pattern at the bottom of the box — the solid picture"
   }
  }
 ]
}
Picture 1 KEY
Picture 2
Picture 3
Picture 4
MPM-007 · medium · application · seq 8 · authored · mcq4
In a chemical plant, hot methanol vapor flows into a chilled glass coil. Partway along the coil, the vapor turns into drops of liquid methanol that trickle out the far end. What is the change called?
Condensation. KEY
Evaporation.
Deposition.
Freezing.
MPM-009 · medium · application · seq 9 · seed:U01-G1/pool/25 · mcq4
The bright arc of an arc welder and the hot gas inside a pottery kiln are both extremely hot. Why is the welding arc plasma while the kiln gas is only a gas?
The welding arc's particles are electrically charged; the kiln gas's particles are not. KEY
The welding arc glows brightly, and the kiln gas does not.
The welding arc lasts a much shorter time than the kiln gas stays hot.
The welding arc's particles move far faster than the kiln gas's particles ever move.
MPM-008 · medium · application · seq 10 · authored · mcq4
In a metal workshop, molten lead fills a mold and is left to cool. The metal slowly hardens into a solid casting. What do the lead particles do as the metal hardens?
They slow down until they lock into fixed positions. KEY
They stop moving altogether the moment the casting turns solid.
Each liquid lead particle turns into a brand-new kind of solid particle.
They drift farther and farther apart as the casting cools.
MPM-010 · medium · application · seq 11 · authored · mcq4
A fuel supplier fills two gas cylinders. Inside the first cylinder, the particles are all identical propane molecules. Inside the second, propane molecules are mixed with particles of a strong-smelling safety additive. How do the contents of the two cylinders classify?
Only the first cylinder holds a pure substance; the second holds a mixture. KEY
Both cylinders hold pure substances, because each contains nothing but useful fuel gas.
Both cylinders hold mixtures, because every propane molecule is itself built from many atoms.
The first cylinder holds a mixture and the second holds a pure substance.
MPM-014 · medium · application · seq 12 · seed:U01-G1/pool[40] · mcq4
Looking at the figure, a student says, 'Two different kinds of atoms are in this box, so it must be a mixture.' What is the correct reading of the diagram?
FIGURE (particle-box · stimulus) — boxes: [{"label": null, "glyph": "diatomic-mixed", "count": 6, "spacing": "far apart", "arrangement": "scattered", "fill": "whole box"}] · style: "one box of six identical fused pairs, each one large circle fused to one small circle, well separated"
raw spec
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}
A compound — the two kinds of atoms are chemically joined into a single kind of particle. KEY
A mixture — two different kinds of atoms appear in the box.
An element — all the particles in the box are identical.
A mixture of an element and a compound — the lone circles mix together with the joined pairs.
MPM-015 · medium · application · seq 13 · authored · mcq4
On a homework sheet, a classmate labels the particle diagram shown in the figure 'a compound'. What does the diagram actually show?
FIGURE (particle-diagram · stimulus) — box: "three identical joined particles, each one medium light circle joined to two small shaded circles, mixed with three identical joined particles, each one lar… · style: "clean textbook particle diagram, single box"
raw spec
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  "style": "clean textbook particle diagram, single box"
 }
}
A mixture of two compounds. KEY
A compound, exactly as the student labeled it.
A mixture of an element and a compound.
A mixture of two elements.
MPM-017 · medium · application · seq 14 · authored · mcq4
A bag of potting soil looks evenly dark brown from arm's length. Up close, you can see pale specks of perlite and small pieces of bark scattered through the dark material. Classify the potting soil.
A heterogeneous mixture. KEY
A homogeneous mixture.
A compound.
A pure substance.
MPM-018 · medium · application · seq 15 · authored · mcq4
A rocket-fuel plant stores hydrogen gas in a sealed tank. Every particle of the gas is a joined pair of two identical hydrogen atoms, nothing more. Classify the tank's contents.
An element. KEY
A homogeneous mixture.
A compound.
A heterogeneous mixture.
MPM-018 · medium · application · seq 16 · authored · mcq4
Molasses is a thick brown liquid holding several different kinds of particles evenly mixed, with none of the kinds joined into a new kind of particle. Every spoonful poured from the jar has the same makeup as every other. Classify the molasses.
A homogeneous mixture. KEY
A compound.
An element.
A heterogeneous mixture.
MPM-004 · hard · transfer · seq 17 · authored · mcq4
A sealed plastic packing pillow from a shipping box squashes inward easily under your thumb, but a glass paperweight of the same size does not squash at all. Using the particles, why does the pillow squash?
The gas particles sealed inside the pillow are far apart, so squeezing pushes them closer together. KEY
Squeezing shrinks each particle inside the pillow, so the particles together take up less room.
Squeezing pushes some of the gas particles inside the pillow out of existence.
The pillow's particles are softer than the paperweight's particles, so each particle itself flattens when pushed.
MPM-005 · hard · transfer · seq 18 · authored · mcq4
The figure's two boxes each hold nine circles. Which statement about the two boxes is correct?
FIGURE (particle-box · stimulus) — boxes: [{"label": "1", "glyph": "atom", "count": 9, "spacing": "touching", "arrangement": "regular rows", "fill": "block"}, {"label": "2", "glyph": "atom", "count":… · style: "two side-by-side particle boxes labeled 1 and 2, nine identical circles each"
raw spec
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Box 1 shows a solid and box 2 shows a gas, because box 1's circles are touching in a regular pattern while box 2's are far apart. KEY
The two boxes show the same state, because they hold nine circles each.
Box 1 shows a gas and box 2 shows a solid, because box 2's circles are the ones packed touching in regular rows.
Box 1 shows a solid and box 2 shows a liquid, because box 2's circles are touching but jumbled, pooled at the bottom of the box.
MPM-012 · hard · transfer · seq 19 · authored · mcq4
A stoppered vial of fine powder contains some particles made of one chromium atom with two bromine atoms chemically joined to it, and others made of one chromium atom with three bromine atoms chemically joined to it. How does the vial's content classify, and why?
As a mixture of two separate compounds, because the two kinds of particles are only mixed together. KEY
As one compound, because each particle it holds contains chromium atoms joined to bromine atoms.
As one pure substance, because only chromium and bromine atoms are present.
As an element, because chromium atoms appear in every particle the vial holds.
MPM-013 · hard · transfer · seq 20 · authored · mcq4
Magnesium is a bright silvery metal that bends without snapping. Silicon is a dark gray, glassy solid. Strong heating chemically joins the magnesium and silicon atoms into one new solid made of dark blue crystals — a color neither element shows anywhere. Why is the new solid dark blue?
The dark blue is the new solid's own color; the crystals are a brand-new substance, made of one new kind of particle. KEY
Dark blue is the two elements' colors blended — silicon's dark gray deepened and tinted by the bright silvery metal.
The crystals take their color from the element they contain more of, and that element is the dark gray silicon.
The strong heating turned the atoms themselves dark blue before they joined into the new solid.
MPM-015 · medium · application · seq 21 · authored · frq
In particle diagrams, circles of different sizes or shading stand for different kinds of atoms.
FIGURE (model_answer_diagram · model_answer_diagram) — see raw spec
raw spec
{
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   "figureType": "particle-diagram",
   "box": "nine identical large dark circles, touching, in tightly packed regular rows at least two rows deep, forming a block in the lower part of the box",
   "style": "clean textbook particle diagram, single labeled box"
  }
 }
}
In particle diagrams, circles of different sizes or shading stand for different kinds of atoms. (a) Plan a particle diagram of an element in the solid state whose particles are single atoms. Your plan must include at least nine particles. In your answer, state which particle kinds you would draw and what each looks like, how many of each kind, and how the particles are spaced and arranged in the box. (b) In one or two sentences, explain how someone reading your diagram can tell it shows an element and not a compound.
Part a. Plan a particle diagram of an element in the solid state whose particles are single atoms. Your plan must include at least nine particles. In your answer, state which particle kinds you would draw and what each looks like, how many of each kind, and how the particles are spaced and arranged in the box.
Model: A box containing nine identical large dark circles, touching one another in tightly packed regular rows at least two rows deep, gathered as a block in the lower part of the box. No other kind of circle appears, and no circle is joined to a different kind. An element needs only one kind of circle. Every particle must look the same — here, single identical circles. Solid spacing packs the circles into touching, tightly packed rows — a regular repeating pattern, at least two rows deep.
Part b. In one or two sentences, explain how someone reading your diagram can tell it shows an element and not a compound.
Model: Only one kind of circle appears, and no circle is joined to a different kind of circle. A compound's particles would be built from two or more different circles joined together, so single circles of one kind make the sample an element.
Full model answer. (a) A box containing nine identical large dark circles, touching one another in tightly packed regular rows at least two rows deep, gathered as a block in the lower part of the box. No other kind of circle appears, and no circle is joined to a different kind. An element needs only one kind of circle. Every particle must look the same — here, single identical circles. Solid spacing packs the circles into touching, tightly packed rows — a regular repeating pattern, at least two rows deep. (b) Only one kind of circle appears, and no circle is joined to a different kind of circle. A compound's particles would be built from two or more different circles joined together, so single circles of one kind make the sample an element.

Form D

MPM-002 · easy · recall · seq 1 · authored · mcq4
In a sample of cobalt, the particles line up in an even, repeating arrangement. Each one wobbles gently about its own point and never trades places with a neighbor. What state is the cobalt in?
Solid. KEY
Liquid.
Gas.
It could be either a solid or a liquid.
MPM-007 · easy · recall · seq 2 · authored · mcq4
Which state change is the exact opposite of deposition?
Sublimation. KEY
Condensation.
Freezing.
Evaporation.
MPM-011 · easy · recall · seq 3 · authored · mcq4
What does it take for a pure substance to count as an element?
All of its atoms must be atoms of one kind. KEY
Its atoms must stay as separate single atoms, with no joined groups.
Being a pure substance is already enough to make it an element.
It must take the form of a gas.
MPM-016 · easy · recall · seq 4 · authored · mcq4
Two small samples are taken from two separate spots in one homogeneous mixture. How will the two samples compare?
They have the same makeup and the same properties. KEY
Each sample holds just one kind of particle.
The two samples differ visibly from each other.
The samples match in makeup with a liquid mixture but not with a solid one.
MPM-001 · medium · application · seq 5 · authored · mcq4
At a window factory, a thin stream of krypton is piped into the sealed gap between the two panes of an energy-saving window. The krypton spreads out to take both the shape and the entire volume of the gap. What is the krypton?
A gas. KEY
A liquid.
A solid.
Both a liquid and a gas.
MPM-003 · medium · application · seq 6 · authored · mcq4
A brick in an old chimney has kept exactly the same shape for a hundred years. What does that show about its particles?
They stay locked in fixed positions, each one only able to vibrate in place. KEY
They stopped moving altogether when the chimney was first built.
They creep past one another so slowly that no change can ever be seen.
They are wedged together too tightly to vibrate.
MPM-006 · medium · application · seq 7 · authored · mcq4
The figure shows a student's particle diagram of a gas sample of one pure substance. The drawing is wrong. Which corrected diagram is right?
FIGURE (figure · ) — see raw spec
raw spec
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    "style": "correct gas: a few same-size circles far apart, spread through the whole box — top and corners included"
   }
  },
  {
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   "figureSpec": {
    "figureType": "particle-box",
    "boxes": [
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      "fill": "bottom-left part of box only"
     }
    ],
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   }
  },
  {
   "option": "distractor2",
   "figureSpec": {
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     }
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    "style": "a few circles far apart through the whole box, but drawn in clearly different sizes"
   }
  },
  {
   "option": "distractor3",
   "figureSpec": {
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    ],
    "style": "touching, jumbled circles filling the bottom of the box — the liquid picture"
   }
  }
 ]
}
Picture 1 KEY
Picture 2
Picture 3
Picture 4
MPM-007 · medium · application · seq 8 · authored · mcq4
A chocolate bar left on a car's dashboard on a sunny afternoon slowly turns from a firm solid into a puddle of soft liquid. What is the change called?
Melting. KEY
Freezing.
Sublimation.
Evaporation.
MPM-009 · medium · application · seq 9 · authored · mcq4
In a running car engine, the spark that jumps across the spark plug's gap and the exhaust gas rushing out of the engine are both extremely hot. Why is the spark plasma while the exhaust gas is only a gas?
Charged particles are what make matter plasma, and the spark's particles are charged. KEY
Glowing is what makes matter plasma, and only the spark glows.
Matter that lasts just an instant counts as plasma, and the spark vanishes in an instant.
Very fast-moving particles are what make matter plasma, and the spark's particles move more quickly.
MPM-008 · medium · application · seq 10 · authored · mcq4
A cook drops a pat of solid butter into a warm pan. Warmed gently, the pat slowly melts into a liquid. What do the butter particles do as the pat melts?
They vibrate faster, break out of their fixed positions, and start sliding past one another. KEY
They fly apart from one another and spread out in all directions.
Each butter particle softens and turns runny as it warms up.
The warmth of the pan creates brand-new liquid particles between the solid butter ones.
MPM-010 · medium · application · seq 11 · authored · mcq4
Some nail-polish removers contain nothing but acetone. In one such bottle, all the particles are identical acetone molecules, and each molecule is built from three kinds of atoms joined together. A student says, 'Three kinds of atoms — that means a mixture.' How does the acetone classify, and why?
A pure substance — all its particles are molecules of one single kind. KEY
A mixture — each of its molecules contains three kinds of atoms.
A mixture — the remover is a liquid, not a solid.
A pure substance — the liquid is clear and colorless.
MPM-014 · medium · application · seq 12 · authored · mcq4
The figure shows a particle diagram of a boxed sample. Classify that sample.
FIGURE (particle-diagram · stimulus) — box: "four fused large-and-small two-atom pairs mixed with four bent three-atom particles (two small circles joined to one large circle), all widely spaced throug… · style: "clean textbook particle diagram, single box"
raw spec
{
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 "figureSpec": {
  "figureType": "particle-diagram",
  "box": "four fused large-and-small two-atom pairs mixed with four bent three-atom particles (two small circles joined to one large circle), all widely spaced through one single box, with no lone circles",
  "style": "clean textbook particle diagram, single box"
 }
}
A mixture of two compounds. KEY
A single compound.
A mixture of two elements.
A mixture of an element and a compound.
MPM-015 · medium · application · seq 13 · authored · mcq4
A student draws the particle diagram shown in the figure and labels it 'an element'. What does the diagram actually show?
FIGURE (particle-diagram · stimulus) — box: "five medium dark circles and five small light circles, all single, none joined, mixed together and widely spaced through the whole box" · style: "clean textbook particle diagram, single box"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "particle-diagram",
  "box": "five medium dark circles and five small light circles, all single, none joined, mixed together and widely spaced through the whole box",
  "style": "clean textbook particle diagram, single box"
 }
}
A mixture of two elements. KEY
An element, exactly as the student labeled it.
A single compound.
A mixture of an element and a compound.
MPM-017 · medium · application · seq 14 · authored · mcq4
A bottle of children's liquid medicine is labeled 'shake well before each use'. Freshly shaken, the medicine looks evenly white throughout. After standing overnight, a layer of fine, pale solid has settled at the bottom of the bottle, with clearer liquid above it. Classify the medicine as it stands in the bottle.
A heterogeneous mixture. KEY
A homogeneous mixture.
A compound.
A pure substance.
MPM-018 · medium · application · seq 15 · authored · mcq4
A laboratory cylinder holds hydrogen chloride gas. Each particle of the gas is a single hydrogen atom joined to a single chlorine atom, and all the particles are alike. Classify the gas.
A compound. KEY
A heterogeneous mixture.
An element.
A homogeneous mixture.
MPM-018 · medium · application · seq 16 · authored · mcq4
In a bottle of unfiltered olive oil, two kinds of matter share the bottle: clear oil above, and tiny dark specks of crushed olive that settle into a visible layer at the bottom. Classify what the bottle holds.
A heterogeneous mixture. KEY
A compound.
An element.
A homogeneous mixture.
MPM-004 · hard · transfer · seq 17 · authored · mcq4
A plastic syringe is filled with nothing but gas, and its tip is sealed with a cap. Pushing the plunger squeezes the contents easily into less room. The same syringe filled with glycerin barely budges. Using the particles, why does the gas squeeze so easily?
The gas's particles are far apart, so squeezing pushes them closer together into the empty space between them. KEY
Pushing the plunger turns part of the gas to liquid, which takes up less space.
The gas's particles are softer than the glycerin's particles, so each particle itself flattens when pushed.
Pushing the plunger squeezes some of the gas particles out of existence.
MPM-005 · hard · transfer · seq 18 · authored · mcq4
Box 1 and box 2 in the figure hold eleven circles apiece. Which statement about the two boxes is correct?
FIGURE (particle-box · stimulus) — boxes: [{"label": "1", "glyph": "atom", "count": 11, "spacing": "touching", "arrangement": "jumbled", "fill": "bottom of box"}, {"label": "2", "glyph": "atom", "cou… · style: "two side-by-side particle boxes labeled 1 and 2, eleven identical circles each"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "particle-box",
  "boxes": [
   {
    "label": "1",
    "glyph": "atom",
    "count": 11,
    "spacing": "touching",
    "arrangement": "jumbled",
    "fill": "bottom of box"
   },
   {
    "label": "2",
    "glyph": "atom",
    "count": 11,
    "spacing": "far apart",
    "arrangement": "scattered",
    "fill": "whole box"
   }
  ],
  "style": "two side-by-side particle boxes labeled 1 and 2, eleven identical circles each"
 }
}
Box 1 shows a liquid and box 2 shows a gas, because box 1's circles are touching but jumbled and box 2's are far apart. KEY
Both boxes show the same state, because they hold eleven circles apiece.
Box 1 shows a gas and box 2 shows a liquid, because box 2's circles are the ones pooled touching at the bottom.
Box 1 shows a solid and box 2 shows a gas, because box 1's circles sit touching in a regular repeating pattern.
MPM-012 · hard · transfer · seq 19 · authored · mcq4
In a research lab, a sealed dry flask of white crystals contains some particles made of one xenon atom with two fluorine atoms chemically joined to it, and others made of one xenon atom with four fluorine atoms chemically joined to it. How does the flask's content classify, and why?
As a mixture of two separate compounds, because the two kinds of particles are only mixed together. KEY
As one compound, because each particle it holds contains xenon atoms joined to fluorine atoms.
As one pure substance, because only xenon and fluorine atoms are present.
As an element, because xenon atoms appear in every particle the flask holds.
MPM-013 · hard · transfer · seq 20 · authored · mcq4
Gallium is a metal with a famous quirk: a lump of it turns to a silvery liquid in a warm hand. Arsenic is a brittle, dull gray solid. Strong heating chemically joins the gallium and arsenic atoms into one new solid. A chip of the new solid never turns liquid in a warm hand. Why?
Turning liquid in a warm hand was gallium's own property; the chip is a brand-new substance, made of one new kind of particle. KEY
The new solid is still just gallium and arsenic mixed together, and the hard arsenic keeps the soft gallium from flowing.
The strong heating destroyed the gallium atoms, so the part of the solid that could turn liquid is gone.
The new solid does still turn liquid in a warm hand — it just takes far longer than a lump of pure gallium.
MPM-015 · medium · application · seq 21 · authored · frq
In particle diagrams, circles of different sizes or shading stand for different kinds of atoms.
FIGURE (model_answer_diagram · model_answer_diagram) — see raw spec
raw spec
{
 "figureShape": "model_answer_diagram",
 "modelAnswerFigureSpecs": {
  "a": {
   "figureType": "particle-diagram",
   "box": "three single small shaded circles and three identical large-shaded-plus-medium-light joined particles, mixed together, widely spaced, spread through the whole box",
   "style": "clean textbook particle diagram, single labeled box"
  }
 }
}
In particle diagrams, circles of different sizes or shading stand for different kinds of atoms. (a) Plan a particle diagram of a gas mixture of an element and a compound. Use single small shaded circles for the element's particles, and a second particle kind made of one large shaded circle joined to one medium light circle for the compound. Your plan must include exactly three particles of each kind. In your answer, state which particle kinds you would draw and what each looks like, how many of each kind, and how the particles are spaced and arranged in the box. (b) In one or two sentences, explain how someone reading your diagram can tell it shows a mixture of an element and a compound and not a mixture of two compounds.
Part a. Plan a particle diagram of a gas mixture of an element and a compound. Use single small shaded circles for the element's particles, and a second particle kind made of one large shaded circle joined to one medium light circle for the compound. Your plan must include exactly three particles of each kind. In your answer, state which particle kinds you would draw and what each looks like, how many of each kind, and how the particles are spaced and arranged in the box.
Model: A box containing three single small shaded circles (the element) mixed with three identical joined particles, each one large shaded circle joined to one medium light circle (the compound). The two kinds are not joined to each other, and all six particles are widely spaced and spread through the whole box. A mixture needs more than one kind of particle mixed together in the same box. The element contributes one kind of lone circle; the compound contributes identical joined particles of two different circles. Gas spacing applies to the whole mixture — every particle sits far from its neighbors and the particles fill the box.
Part b. In one or two sentences, explain how someone reading your diagram can tell it shows a mixture of an element and a compound and not a mixture of two compounds.
Model: One kind of particle is a lone single circle — an element — and the other kind joins two different circles — a compound. A mixture of two compounds would show two kinds of joined particles, each built from different circles, so the lone single circles show that one ingredient is an element.
Full model answer. (a) A box containing three single small shaded circles (the element) mixed with three identical joined particles, each one large shaded circle joined to one medium light circle (the compound). The two kinds are not joined to each other, and all six particles are widely spaced and spread through the whole box. A mixture needs more than one kind of particle mixed together in the same box. The element contributes one kind of lone circle; the compound contributes identical joined particles of two different circles. Gas spacing applies to the whole mixture — every particle sits far from its neighbors and the particles fill the box. (b) One kind of particle is a lone single circle — an element — and the other kind joins two different circles — a compound. A mixture of two compounds would show two kinds of joined particles, each built from different circles, so the lone single circles show that one ingredient is an element.

Form E

MPM-002 · easy · recall · seq 1 · authored · mcq4
In a sample of tungsten, each particle keeps to one fixed spot within an orderly, repeating layout. The particles shake in place, and no particle ever changes places with another. What state is the tungsten in?
Solid. KEY
Liquid.
Gas.
It could be either a solid or a liquid.
MPM-007 · easy · recall · seq 2 · authored · mcq4
Which state change is the exact opposite of evaporation?
Condensation. KEY
Freezing.
Sublimation.
Deposition.
MPM-011 · easy · recall · seq 3 · authored · mcq4
What is an element?
A pure substance whose atoms are all of a single kind. KEY
A substance whose atoms remain single and unjoined.
A smooth, even blend of atoms of several different kinds.
A pure substance whose particles each combine two different kinds of atoms.
MPM-016 · easy · recall · seq 4 · authored · mcq4
How does a homogeneous mixture differ from a heterogeneous one?
Its makeup is the same throughout; a heterogeneous mixture keeps visibly different parts. KEY
Its parts remain visibly different, while a heterogeneous mixture stays the same throughout.
It holds just one kind of particle, but a heterogeneous mixture holds several kinds.
It is a liquid; a heterogeneous mixture is a solid.
MPM-001 · medium · application · seq 5 · authored · mcq4
Dry lentils rattle from their sack into a glass storage jar and settle to match the jar's shape. One single lentil keeps its own shape and its own volume wherever you set it down. Are the lentils a solid, a liquid, or a gas?
A solid. KEY
A liquid.
A gas.
Both a solid and a liquid.
MPM-003 · medium · application · seq 6 · authored · mcq4
Shampoo poured from a round bottle into a square bottle soon matches the new bottle's shape. Why?
Its particles slide past one another; they rearrange until the shampoo fits the new bottle. KEY
Its particles drift far apart until they fill every corner of the new bottle.
Each shampoo particle changes its own shape to fit the square bottle's corners.
Its particles lock into fixed positions as soon as the pouring stops.
MPM-006 · medium · application · seq 7 · authored · mcq4
The figure shows a student's particle diagram of a liquid sample of one pure substance. The drawing is wrong. Which corrected diagram is right?
FIGURE (figure · ) — see raw spec
raw spec
{
 "option_format": "image",
 "render_contract": "R2 image-XOR-text: options render as pictures ONLY; placeholder texts never rendered, never used as aria (R23).",
 "stimulus": {
  "figureType": "particle-box",
  "boxes": [
   {
    "label": null,
    "glyph": "atom",
    "count": 13,
    "spacing": "touching",
    "arrangement": "jumbled",
    "fill": "bottom of box",
    "circleSizes": "clearly different sizes"
   }
  ],
  "style": "the student's wrong liquid diagram: touching, jumbled circles filling the bottom of the box, but drawn in clearly different sizes"
 },
 "optionFigureSpecs": [
  {
   "option": "key",
   "figureSpec": {
    "figureType": "particle-box",
    "boxes": [
     {
      "glyph": "atom",
      "count": 13,
      "spacing": "touching",
      "arrangement": "jumbled",
      "fill": "bottom of box"
     }
    ],
    "style": "correct liquid: thirteen same-size circles touching but jumbled, filling the bottom of the box with a roughly level top"
   }
  },
  {
   "option": "distractor1",
   "figureSpec": {
    "figureType": "particle-box",
    "boxes": [
     {
      "glyph": "atom",
      "count": 6,
      "spacing": "far apart",
      "arrangement": "scattered",
      "fill": "whole box"
     }
    ],
    "style": "a few same-size circles far apart, spread through the whole box — the gas picture"
   }
  },
  {
   "option": "distractor2",
   "figureSpec": {
    "figureType": "particle-box",
    "boxes": [
     {
      "glyph": "atom",
      "count": 11,
      "spacing": "touching",
      "arrangement": "jumbled",
      "fill": "middle of box, empty above and below"
     }
    ],
    "style": "same-size touching circles in a jumble floating in the middle of the box, with empty space above and below"
   }
  },
  {
   "option": "distractor3",
   "figureSpec": {
    "figureType": "particle-box",
    "boxes": [
     {
      "glyph": "atom",
      "count": 13,
      "spacing": "touching",
      "arrangement": "jumbled",
      "fill": "bottom of box",
      "circleSizes": "most the same size, three clearly larger"
     }
    ],
    "style": "touching, jumbled circles filling the bottom of the box, most the same size but three still clearly larger"
   }
  }
 ]
}
Picture 1 KEY
Picture 2
Picture 3
Picture 4
MPM-007 · medium · application · seq 8 · authored · mcq4
In a workshop, molten pewter is poured into a toy-soldier mold. As it cools, the shiny liquid metal sets into a solid gray figurine. What is the change called?
Freezing. KEY
Melting.
Condensation.
Deposition.
MPM-009 · medium · application · seq 9 · authored · mcq4
A student writes in a lab notebook, 'Matter comes in exactly three states: solid, liquid, and gas.' Which example shows a fourth state?
The bright sparks that leap from a Tesla coil at a science museum. KEY
The cloud of tiny droplets sprayed from an insect-repellent can.
Ketchup flowing slowly from its bottle.
The orange-glowing wires inside a hot toaster.
MPM-008 · medium · application · seq 10 · authored · mcq4
While refilling a lighter, a camper spills one drop of liquid butane onto a picnic table. Within seconds the drop is gone. What do the butane particles do as the drop disappears?
They move faster still, until they fly apart from one another and spread out. KEY
They are destroyed as the drop shrinks, until every last one is gone.
They escape the drop by turning into a new sort of particle.
They slow and crowd closer together, back into touching contact.
MPM-010 · medium · application · seq 11 · authored · mcq4
At a refinery, gasoline is pumped into a tanker. The gasoline pours and swirls like a single liquid, but at the particle level it contains several kinds of molecules, all mixed with one another. How does the gasoline classify, and why?
A mixture — it holds more than one kind of particle mixed together. KEY
A pure substance — everything in the tanker is just gasoline.
A pure substance — it pours like one smooth, single liquid.
A mixture — a full tanker holds an enormous number of molecules.
MPM-014 · medium · application · seq 12 · authored · mcq4
The figure shows a particle diagram of a sealed box. Classify the matter the box holds.
FIGURE (particle-box · stimulus) — boxes: [{"label": null, "glyph": "diatomic-same-large", "count": 6, "spacing": "far apart", "arrangement": "scattered", "fill": "whole box"}] · style: "one box of six identical fused pairs of large circles, well separated"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "particle-box",
  "boxes": [
   {
    "label": null,
    "glyph": "diatomic-same-large",
    "count": 6,
    "spacing": "far apart",
    "arrangement": "scattered",
    "fill": "whole box"
   }
  ],
  "style": "one box of six identical fused pairs of large circles, well separated"
 }
}
A single element. KEY
A single compound.
A mixture of two elements.
A mixture of an element and a compound.
MPM-015 · medium · application · seq 13 · authored · mcq4
A lab partner labels the particle diagram shown in the figure 'a mixture of two elements'. What does the diagram actually show?
FIGURE (particle-diagram · stimulus) — box: "four identical joined particles, each two medium shaded circles joined to one large light circle, mixed with four lone large dark circles; all particles wid… · style: "clean textbook particle diagram, single box"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "particle-diagram",
  "box": "four identical joined particles, each two medium shaded circles joined to one large light circle, mixed with four lone large dark circles; all particles widely spaced through the whole box",
  "style": "clean textbook particle diagram, single box"
 }
}
A mixture of an element and a compound. KEY
A mixture of two elements, exactly as the student labeled it.
A single compound.
A mixture of two compounds.
MPM-017 · medium · application · seq 14 · authored · mcq4
A bottle of clear green mouthwash blends many particle kinds, all mixed together evenly, with no kind joined to another. Every capful has exactly the same makeup, and nothing ever settles out or separates into layers. Classify the mouthwash.
A homogeneous mixture. KEY
A heterogeneous mixture.
A compound.
A pure substance.
MPM-018 · medium · application · seq 15 · authored · mcq4
White phosphorus is a soft, waxy solid. Every particle of the solid is the same: four identical phosphorus atoms joined together. Classify the white phosphorus.
An element. KEY
A homogeneous mixture.
A compound.
A heterogeneous mixture.
MPM-018 · medium · application · seq 16 · authored · mcq4
A scoop of wild-bird seed holds striped sunflower seeds, round millet grains, and pieces of cracked corn, loosely poured together in one bag. Each kind stays visible and easy to tell apart from the others. Classify the bird seed.
A heterogeneous mixture. KEY
A compound.
An element.
A homogeneous mixture.
MPM-004 · hard · transfer · seq 17 · authored · mcq4
A sealed, clear plastic cup is completely full of whipped cream, which holds tiny bubbles of nitrous oxide gas. Pressing the cup's flexible lid squeezes the whole cupful into a smaller volume. An identical cup completely full of plain liquid cream cannot be pressed into a smaller volume at all. Using the particles, why can the whipped cream be pressed into a smaller volume?
The nitrous oxide particles in the bubbles are far apart, so pressing pushes them closer together. KEY
Pressing shrinks each nitrous oxide particle, so the particles together take up less room.
Pressing pushes some of the nitrous oxide particles out of existence, so the rest need less room.
Whipping makes the cream's particles softer, so each particle itself flattens when pressed.
MPM-005 · hard · transfer · seq 18 · authored · mcq4
The two boxes in the figure each contain six circles. Which statement about the two boxes is correct?
FIGURE (particle-box · stimulus) — boxes: [{"label": "1", "glyph": "atom", "count": 6, "spacing": "far apart", "arrangement": "scattered", "fill": "whole box"}, {"label": "2", "glyph": "atom", "count… · style: "two side-by-side particle boxes labeled 1 and 2, six identical circles each"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "particle-box",
  "boxes": [
   {
    "label": "1",
    "glyph": "atom",
    "count": 6,
    "spacing": "far apart",
    "arrangement": "scattered",
    "fill": "whole box"
   },
   {
    "label": "2",
    "glyph": "atom",
    "count": 6,
    "spacing": "touching",
    "arrangement": "regular rows",
    "fill": "block"
   }
  ],
  "style": "two side-by-side particle boxes labeled 1 and 2, six identical circles each"
 }
}
Box 1 shows a gas and box 2 shows a solid, because box 1's circles are far apart and box 2's are touching in a regular pattern. KEY
The two boxes show the same state, because each box holds six circles.
Box 1 shows a solid and box 2 shows a gas, because box 1's circles are the ones sitting in touching rows.
Box 1 shows a gas and box 2 shows a liquid, because box 2's circles are touching but jumbled with no repeating pattern.
MPM-012 · hard · transfer · seq 19 · authored · mcq4
A chemical supplier's sealed bottle of powder contains some particles that join two fluorine atoms to one manganese atom, and others that join three fluorine atoms to one manganese atom. How does the bottle's content classify, and why?
As a mixture of two separate compounds, because the two kinds of particles are only mixed together. KEY
As one compound, because each of its particles contains manganese atoms joined with fluorine atoms.
As one pure substance, because nothing except fluorine and manganese atoms is in the bottle.
As an element, because manganese atoms appear in every particle the bottle holds.
MPM-013 · hard · transfer · seq 20 · authored · mcq4
Zinc is a blue-gray metal, and selenium is a dull gray powder. Strong heating chemically joins the zinc and selenium atoms into one new solid, and the new solid is bright yellow — a color neither element shows anywhere. Why is the new solid yellow?
The bright yellow is the new solid's own color; it is a brand-new substance, made of one new kind of particle. KEY
Bright yellow is simply the two elements' colors blended together — the blue-gray of the metal lightened by the dull gray of the powder.
The yellow was inside the selenium all along, and joining with the metal finally brought it out to the surface.
The strong heating turned the zinc and selenium atoms into new yellow kinds of atoms.
MPM-015 · medium · application · seq 21 · authored · frq
In particle diagrams, circles of different sizes or shading stand for different kinds of atoms.
FIGURE (model_answer_diagram · model_answer_diagram) — see raw spec
raw spec
{
 "figureShape": "model_answer_diagram",
 "modelAnswerFigureSpecs": {
  "a": {
   "figureType": "particle-diagram",
   "box": "five identical one-medium-dark-plus-three-small-light joined particles, widely spaced, spread through the whole box",
   "style": "clean textbook particle diagram, single labeled box"
  }
 }
}
In particle diagrams, circles of different sizes or shading stand for different kinds of atoms. (a) Plan a particle diagram of a compound in the gas state, where every particle contains one medium dark circle and three small light circles joined together. Your plan must include at least five particles. In your answer, state which particle kinds you would draw and what each looks like, how many of each kind, and how the particles are spaced and arranged in the box. (b) In one or two sentences, explain how someone reading your diagram can tell it shows a compound and not an element.
Part a. Plan a particle diagram of a compound in the gas state, where every particle contains one medium dark circle and three small light circles joined together. Your plan must include at least five particles. In your answer, state which particle kinds you would draw and what each looks like, how many of each kind, and how the particles are spaced and arranged in the box.
Model: A box in which five identical particles — each one medium dark circle with three small light circles joined to it — are widely spaced and spread through the whole box, corners and top included. No lone circles appear. A compound is one kind of particle, repeated — here, one medium circle plus three small circles joined. Leftover lone circles would turn the drawing into a mixture. Gas spacing means widely spaced particles spread through the whole box.
Part b. In one or two sentences, explain how someone reading your diagram can tell it shows a compound and not an element.
Model: Every particle joins two different kinds of circles — one medium circle with three small circles. An element's particles could contain only one kind of circle, so joining different circles makes the sample a compound.
Full model answer. (a) A box in which five identical particles — each one medium dark circle with three small light circles joined to it — are widely spaced and spread through the whole box, corners and top included. No lone circles appear. A compound is one kind of particle, repeated — here, one medium circle plus three small circles joined. Leftover lone circles would turn the drawing into a mixture. Gas spacing means widely spaced particles spread through the whole box. (b) Every particle joins two different kinds of circles — one medium circle with three small circles. An element's particles could contain only one kind of circle, so joining different circles makes the sample a compound.

End of Topic Test: Physical and chemical properties and changes & The measurement toolkit (u01-t2 · 5 forms × 21 items · 105 total)

David's notes for James:
full notes file
# u01-t2 — notes/queries from David's side (U01-G2)

1. Numeric-ENTRY conversion of six of your mcq gate seeds (MPM-029 gateItems[0]/[1], MPM-030 gateItems[0]/[1], MPM-033 gateItems[0]/[1] -> seq 11/12/16 on forms A/B): stems kept, options dropped, your distractor misconceptions became wrong-value diagnostics with per-value feedback. Our HS rule (numeric answers are numeric ENTRY, never MCQ) wins over the AP gate-exception. Confirm the conversion.
2. sigFigs grading contract on seq 11/12 (MPM-029/030): your specNotes set sigFigs null (untaught until MPM-032), while the end-of-topic-test numeric contract (V-T6) requires the field. Resolution: sigFigs is carried as display metadata, the answer objects carry precisionAssessed:false + a gradingNote (graded on numeric value + unit only; any numerically equivalent typing accepted). The same tension recurs in the G3/G4 conversion items. Confirm the contract.
3. MPM-031 recording convention kept on seq 13: blind reviewers argued general-chemistry estimated-digit precision (C#13 should be '465' not '465.0'; D#13 '6.40' not '6.4'). Your specNotes state the one-decimal recording convention without sig-fig justification and explicitly defer estimated-digit language to MPM-032, so the keys follow the taught convention. Confirm.
4. E#13 graduated-cylinder re-scale: the draft used 10 mL graduations, which sit outside the specNotes-named transfer scales (2 mL / 0.5 mL); re-scaled to 2 mL marks (key 720.0 -> 724.0 mL). Confirm that the taught-scale boundary is the right constraint for test figures.
5. B#16 delivery requirement: the wrong-value diagnostics 6.93 and 6.930 share one float value - the delivery system must match on the student's typed STRING (not the parsed number) to attribute the right misconception. Not an item defect; flagging so grading is wired correctly.
6. FRQ seeding: U01-G2 has no gate prod seed (all 45 pool items are mcq; prod_seeds is empty), so the FRQ (seq 21) was AUTHORED on MPM-033, the heaviest procedure lesson in scope (count sig figs per measurement -> fewest -> round the computed result). Calculation pattern: model answer uses the 5-line scaffold (values -> equation -> substitute -> calculate -> result with unit); rubric = 3 observable criteria summing to 100; typed answers never need sub/superscripts (mL/s and g/mL contexts). Confirm the lesson choice and pattern.
7. Seed freshening under the strict seed ruling (your item structures/misconception sets kept; instances or values changed to clear the freshness scan): A#2 'smoke' dropped (own-lesson material); A#6 solvent water -> lemonade; A#13/B#13 cylinder liquid water -> vinegar / apple juice (B#13 reading 12.5 -> 11.5 mL); A#14/A#19/A#20 value swaps (spec-number collisions; sig-fig/ranking logic preserved); A#16 stem reframed off the lesson's own worked-example wording (values unchanged); row-11 value swaps 350 -> 483 mL and 4.5 -> 4.525 kg; B#16 factor 1.5 -> 1.1 cm with full downstream value sweep. Say the word if any edit changes your intent.
8. FRQ rubric shape: criterion 3 (40 pts, correctly rounded result with unit + precision justified) spans parts b and c; in this export it sits in part c's rubric (the part where its last observable lands) with the '(parts b and c)' tag kept in the criterion text, points counted once. Confirm your grading machinery accepts the spanning criterion.
9. NOTA/AOTA: none present in this gate's seed pool - nothing replaced (V-T5 clean; export re-scanned).

Form A

MPM-019 · easy · recall · seq 1 · seed:U01-G2.pool[0] · mcq4
Melting point and boiling point are both physical properties. What do they have in common that makes them physical?
Measuring either one leaves the same substance — only its state changes. KEY
Both turn the substance into a new substance when measured.
Both can be observed without heating the substance.
Both describe how the substance reacts with other substances.
MPM-021 · easy · recall · seq 2 · seed:U01-G2/pool[6] · mcq4
A pile of dried leaves burns down to a heap of gray ash. Why is the burning a chemical change?
The ash is a new substance — the leaves stopped being leaves. KEY
Because the pile got smaller as it burned.
Because heat was involved, and heat always means a chemical change.
Because the burning cannot be undone.
MPM-027 · easy · recall · seq 3 · seed:U01-G2.pool[24] (= MPM-027 gateItems[0], James) — VERBATIM · mcq4
A student records three measurements: the mass of a sugar sample, the volume of water in a bottle, and the temperature of the room. Which unit set matches the three, in order?
grams, milliliters, degrees Celsius KEY
milliliters, grams, degrees Celsius
grams, degrees Celsius, milliliters
degrees Celsius, milliliters, grams
MPM-028 · easy · recall · seq 4 · seed:pool[27] · mcq4
Which is the larger amount of powder — 1 milligram or 1 nanogram — and why?
1 milligram — one thousandth of a gram outweighs one billionth of a gram. KEY
1 nanogram — one billionth of a gram outweighs one thousandth of a gram.
1 nanogram — because nano- means one millionth of a gram.
They are equal — both prefixes shrink the gram to a small fraction.
MPM-020 · medium · application · seq 5 · seed:U01-G2.pool[3] (= MPM-020 gateItems[0], James) · mcq4
Four properties of magnesium metal are listed. Which one is a chemical property?
It burns to form a white ash. KEY
It conducts electricity.
It can be bent into thin ribbons.
It melts at 650 °C.
MPM-022 · medium · application · seq 6 · seed:pool[10] · mcq4
A student says: 'Dissolving vitamin C powder in lemonade must be a chemical change, because the powder disappears.' What is wrong with the claim?
The vitamin C particles are still there, unchanged, spread evenly through the lemonade. KEY
Nothing is wrong — a substance you can no longer see has become a new substance.
The student is wrong, but only because dissolving can be undone.
The claim mixes things up — it is the lemonade that changes into a new substance.
MPM-023 · medium · application · seq 7 · seed:U01-G2 pool[12] (= MPM-023 gateItems[0], James; must_freshen_instance: birthday candle -> toasting marshmallow) · mcq4
At a cookout, a marshmallow on a skewer is held over a flame until its surface catches fire. Four observations are listed. Which one is a sign of a possible chemical change?
The small flame on its surface gives off light and heat. KEY
The inside of the marshmallow turns to liquid.
Melted marshmallow runs down the skewer.
The softened marshmallow sags into a bent shape on the skewer.
MPM-024 · medium · application · seq 8 · seed:U01-G2/pool/15 · mcq4
Yellow paint and blue paint are stirred together, and the mixture looks green. Under a hand lens, the green area is still tiny specks of yellow and blue side by side. Does the color change prove a chemical change?
No — the green look comes from tiny yellow and blue specks seen together, not from a new substance. KEY
Yes — a color change is one of the five signs, so the change must be chemical.
Yes — green is a color neither paint had, so a new substance must be present.
No — because paints are already mixtures, nothing about them can ever change chemically.
MPM-025 · medium · application · seq 9 · seed:U01-G2/pool/18 (= demo_curated/0, James-curated) · mcq4
Liquid nitrogen is a single substance with a boiling point far below room temperature. An open flask of it boils steadily on a lab bench until the flask is empty, and the gas that streams off is nitrogen gas. Classify the change to the nitrogen.
Physical — the liquid left as nitrogen gas, the same substance in the gas state. KEY
Chemical — the nitrogen is gone, so it must have become something else.
Chemical — a gas formed, and a new gas is one of the five signs.
Physical — because the flask itself is unchanged.
MPM-026 · medium · application · seq 10 · seed:pool_21 (gateItem g1; used verbatim - no NOTA/AOTA present, nothing replaced; placement flags empty) · mcq4
Which entry from a lab notebook is qualitative?
The solid dissolved completely. KEY
The flask held 150 mL of liquid at the start.
The mass fell by 2.1 g during the experiment.
The fizzing lasted 52 seconds.
MPM-029 · medium · application · seq 11 · seed:pool[30] (= MPM-029 gateItems[0], James) - value swap 350 -> 483 per adjust_values_vt6; converted to numeric ENTRY per convert_to_numeric_entry; otherwise VERBATIM · numeric
A beaker holds 483 mL of water. What is that volume in liters?
Answer: 0.483 L KEY
also accepted: .483
wrongValueDiagnostics
[
 {
  "value": 483000,
  "misconception": "you treated milli- as one thousand instead of one thousandth",
  "feedback": "This answer is wrong — you treated milli- as one thousand instead of one thousandth."
 },
 {
  "value": 4.83,
  "misconception": "you moved the decimal point two places instead of three",
  "feedback": "This answer is wrong — you moved the decimal point two places instead of three."
 },
 {
  "value": 0.0483,
  "misconception": "you moved the decimal point four places instead of three",
  "feedback": "This answer is wrong — you moved the decimal point four places instead of three."
 }
]
feedback
{
 "keyExplanation": "Write down the value in the question:\nV = 483 mL\nWrite down what the prefix means:\nmilli- means one thousandth, so 1 mL = 0.001 L\nSubstitute in the meaning, and calculate:\nV = 483 × 0.001 L\nV = 0.483 L\nA milliliter is a small unit, so the same volume written in liters must be a smaller number — 0.483 L passes that check; 483,000 L does not (4.83 L is smaller too, but comes from moving the decimal two places, not three)."
}
MPM-030 · medium · application · seq 12 · seed:pool[33] (= MPM-030 gateItems[0], James) - converted mcq->numeric; value freshened · numeric
A balance reads 0.735 g. What is that mass in milligrams?
Answer: 735 mg KEY
also accepted: 735 mg, 735.0
wrongValueDiagnostics
[
 {
  "value": 0.000735,
  "misconception": "you divided by one thousand instead of multiplying — that direction turns milligrams into grams",
  "feedback": "This answer is wrong — you divided by one thousand instead of multiplying; that direction turns milligrams into grams. One gram holds 1000 mg, so the balance's 0.735 g is 0.735 × 1000 = 735 mg."
 },
 {
  "value": 73.5,
  "misconception": "you multiplied by one hundred instead of one thousand",
  "feedback": "This answer is wrong — you multiplied by one hundred instead of one thousand. milli- means one thousandth, so one gram holds 1000 mg: 0.735 × 1000 = 735 mg."
 },
 {
  "value": 7350,
  "misconception": "you multiplied by ten thousand instead of one thousand",
  "feedback": "This answer is wrong — you multiplied by ten thousand instead of one thousand. One gram holds exactly 1000 mg, so 0.735 g is 0.735 × 1000 = 735 mg."
 }
]
feedback
{
 "keyExplanation": "Write down the value in the question:\nm = 0.735 g\nWrite down what the prefix means:\nmilli- means one thousandth, so one gram holds 1000 mg\nSubstitute in the meaning, and calculate:\nm = 0.735 × 1000 mg\nm = 735 mg\nA milligram is a small unit, so the same mass written in milligrams must be a larger number than 0.735 — multiplying by 1000 gives 735 mg.",
 "anticipatedWrong": [
  {
   "value": 0.000735,
   "misconception": "you divided by one thousand instead of multiplying — that direction turns milligrams into grams",
   "feedback": "This answer is wrong — you divided by one thousand instead of multiplying; that direction turns milligrams into grams. One gram holds 1000 mg, so the balance's 0.735 g is 0.735 × 1000 = 735 mg."
  },
  {
   "value": 73.5,
   "misconception": "you multiplied by one hundred instead of one thousand",
   "feedback": "This answer is wrong — you multiplied by one hundred instead of one thousand. milli- means one thousandth, so one gram holds 1000 mg: 0.735 × 1000 = 735 mg."
  },
  {
   "value": 7350,
   "misconception": "you multiplied by ten thousand instead of one thousand",
   "feedback": "This answer is wrong — you multiplied by ten thousand instead of one thousand. One gram holds exactly 1000 mg, so 0.735 g is 0.735 × 1000 = 735 mg."
  }
 ]
}
MPM-031 · medium · application · seq 13 · seed:pool[36] · mcq4
The figure shows vinegar in a large graduated cylinder. What is the volume of the vinegar?
FIGURE (graduated-cylinder · stimulus) — scaleMin: 50 · scaleMax: 80 · unit: "mL" · markEvery: 2 · labeledMarks: [50, 60, 70, 80] · meniscusBottomAt: 74 · meniscusEdgeAt: 75 · style: "clean textbook SVG, wide cylinder, no reading printed on the figure"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "graduated-cylinder",
  "scaleMin": 50,
  "scaleMax": 80,
  "unit": "mL",
  "markEvery": 2,
  "labeledMarks": [
   50,
   60,
   70,
   80
  ],
  "meniscusBottomAt": 74,
  "meniscusEdgeAt": 75,
  "style": "clean textbook SVG, wide cylinder, no reading printed on the figure"
 }
}
74.0 mL KEY
72.0 mL
76.0 mL
75.0 mL
MPM-030 · medium · application · seq 14 · seed:U01-G2/pool/35 · mcq4
Which pair records the same measurement in two different units?
0.9 L and 900 mL KEY
0.9 L and 90 mL
2 kg and 200 g
70 cm and 7 m
MPM-032 · medium · application · seq 15 · seed:U01-G2.pool[39] · mcq4
Which measurement has exactly three significant figures?
0.0410 g KEY
0.041 g
41.00 g
104.0 g
MPM-033 · medium · application · seq 16 · seed:pool_42 (MPM-033 gateItem; scenario sentences VERBATIM; converted to numeric ENTRY per convert_to_numeric_entry - options dropped, distractor misconceptions -> wrong-value feedback, mcq clause -> the lesson's fluency numeric-entry clause; no NOTA/AOTA present, nothing replaced) · numeric
A rock sample has a mass of 9.30 g and a volume of 4.0 cm³. Dividing the mass by the volume puts 2.325 on the calculator screen. What result should be recorded, in g/cm³?
Answer: 2.3 g/cm³ KEY
wrongValueDiagnostics
[
 {
  "value": 2.325,
  "misconception": "you recorded every calculator digit — the calculator does not know which digits the measurements vouch for",
  "feedback": "This answer is wrong — you recorded every calculator digit — the calculator does not know which digits the measurements vouch for."
 },
 {
  "value": 2.33,
  "misconception": "you rounded to the more precise measurement's three significant figures instead of the fewest",
  "feedback": "This answer is wrong — you rounded to the more precise measurement's three significant figures instead of the fewest."
 },
 {
  "value": 2,
  "misconception": "you rounded past the rule — the result keeps as many significant figures as the least precise measurement, no fewer",
  "feedback": "This answer is wrong — you rounded past the rule — the result keeps as many significant figures as the least precise measurement, no fewer."
 }
]
feedback
{
 "keyExplanation": "Count the significant figures in each measurement:\n9.30 g — three significant figures\n4.0 cm³ — two significant figures\nDivide, then round to the fewest significant figures:\n9.30 ÷ 4.0 = 2.325\nrecorded result = 2.3 g/cm³\nThe least precise measurement sets the precision — two significant figures, no more and no fewer."
}
MPM-025 · hard · transfer · seq 17 · seed:U01-G2/pool/20 (= demo_curated/2, James-curated) · mcq4
A brass doorknob on a seldom-used door is kept under a snug cloth cover that keeps dust and grime off it. Even so, the knob's surface slowly darkens to a dull brown. Polishing rubs off a thin dark film, and tests on the film show it is not brass; beneath it the knob is shiny again but very slightly thinner. Classify the darkening.
Chemical — the dark film is a new substance formed from some of the knob's brass. KEY
Physical — polishing restored the shine, so nothing permanent happened.
Physical — the knob is still a brass doorknob.
Chemical — a color change is one of the five signs, so the darkening alone settles it.
MPM-033 · hard · transfer · seq 18 · seed:U01-G2.pool[44] · mcq4
A student multiplies a measured hallway length of 6.10 m by a measured width of 2.0 m and reports the floor area as 12.20 m². What is wrong with the reported result?
It keeps four significant figures — 2.0 m vouches for only two, so report 12 m². KEY
Nothing is wrong — the calculator showed 12.20, so 12.20 m² is the correct value to report.
It should be 12.2 m² — results keep three significant figures.
It should be 10 m² — always round to one significant figure.
MPM-029 · hard · transfer · seq 19 · seed:U01-G2.pool[32] (= MPM-029 gateItems[2], James; used verbatim - no NOTA/AOTA present, nothing replaced, placement unflagged) · mcq4
Four samples are weighed on different balances. Which sample has the largest mass?
A sample of 0.7 kg KEY
A sample of 60,000 mg
A sample of 450 g
A sample of 0.68 kg
MPM-032 · hard · transfer · seq 20 · seed:U01-G2/pool/41 (MPM-032 gateItems[2]) — VERBATIM · mcq4
In which pair do the two mass readings have the same number of significant figures?
0.050 g and 5.0 g KEY
0.4 g and 0.050 g
5.00 g and 5.0 g
0.006 g and 6.000 g
MPM-033 · medium · application · seq 21 · authored · frq
A lead fishing sinker has a mass of 96.9 g and a volume of 8.5 mL.
A lead fishing sinker has a mass of 96.9 g and a volume of 8.5 mL. (a) State the number of significant figures in each of the two measurements. (b) Divide the sinker's mass by its volume and report the result in g/mL, recorded with the correct number of significant figures. Show your work, including the full result the calculator shows before rounding. (c) In one or two sentences, explain how you decided how many significant figures the recorded result should keep.
Part a. State the number of significant figures in each of the two measurements.
Model: 96.9 g — three significant figures 8.5 mL — two significant figures
Part b. Divide the sinker's mass by its volume and report the result in g/mL, recorded with the correct number of significant figures. Show your work, including the full result the calculator shows before rounding.
Model: mass = 96.9 g, volume = 8.5 mL Divide the mass by the volume, then round to the fewest significant figures. 96.9 ÷ 8.5 = 11.4 The least precise measurement, 8.5 mL, has two significant figures, so round 11.4 to two significant figures. recorded result = 11 g/mL (both digits of 11 are nonzero, so 11 g/mL cleanly shows two significant figures)
Part c. In one or two sentences, explain how you decided how many significant figures the recorded result should keep.
Model: The least precise measurement sets the precision of the result: 8.5 mL has only two significant figures, so the recorded result keeps two. A result can never be more trustworthy than the shakiest measurement that went into it.
Full model answer. (a) 96.9 g — three significant figures 8.5 mL — two significant figures (b) mass = 96.9 g, volume = 8.5 mL Divide the mass by the volume, then round to the fewest significant figures. 96.9 ÷ 8.5 = 11.4 The least precise measurement, 8.5 mL, has two significant figures, so round 11.4 to two significant figures. recorded result = 11 g/mL (both digits of 11 are nonzero, so 11 g/mL cleanly shows two significant figures) (c) The least precise measurement sets the precision of the result: 8.5 mL has only two significant figures, so the recorded result keeps two. A result can never be more trustworthy than the shakiest measurement that went into it.

Form B

MPM-019 · easy · recall · seq 1 · authored · mcq4
Hardness is a physical property of a substance. What makes hardness a physical property?
Hardness can be checked while the substance stays itself — checking it forms nothing new. KEY
Hardness describes how the substance can turn into a different substance.
Checking a substance's hardness turns the sample into a new substance.
Hardness describes how strongly the substance reacts chemically with whatever scratches it.
MPM-021 · easy · recall · seq 2 · authored · mcq4
A potter rolls a lump of clay into a long, thin coil. Why is the rolling a physical change?
The coil is still clay — its shape changed, but no new substance formed. KEY
Because the coil could be squashed back into a lump at any time.
Because nothing heated the clay, and a change without heat is always physical.
Because clay is a soft material, and soft materials cannot change chemically.
MPM-027 · easy · recall · seq 3 · seed:U01-G2.pool[25] (= MPM-027 gateItems[1], James) — VERBATIM · mcq4
Why do chemists everywhere report measurements in the shared SI units?
Because a measurement then means one agreed amount to every scientist, anywhere. KEY
Because SI units make every measurement more precise than it would otherwise be.
Because SI units give smaller, easier numbers.
Because measurements in other units are less trustworthy.
MPM-028 · easy · recall · seq 4 · seed:pool[28] · mcq4
A bottle in a European pharmacy is labeled '1 cL' — one centiliter. Using the meaning of centi-, how much of a liter is that?
one hundredth of a liter KEY
one thousandth of a liter
one hundred liters
one tenth of a liter
MPM-020 · medium · application · seq 5 · seed:U01-G2.pool[4] (= MPM-020 gateItems[1], James) · mcq4
A classmate claims: 'The ability of milk to sour is a physical property, because sour milk is still milk.' Classify the property and judge the reason.
Chemical — souring forms new substances that fresh milk does not contain. KEY
Physical — the student's reason is right: sour milk is still milk.
Physical — souring happens on its own, without any heating.
Chemical — because milk is itself made of chemicals.
MPM-022 · medium · application · seq 6 · seed:pool[11] · mcq4
Coconut oil melts on a warm counter, and it can also burn in a pan fire. Which change leaves the oil's particles unchanged?
Melting only — the particles just change spacing and movement. KEY
Burning only — the flame frees the particles without changing them.
Both changes — each just loosens the particles more strongly.
Neither change — any change to the oil alters its particles.
MPM-023 · medium · application · seq 7 · seed:U01-G2 pool[13] (= MPM-023 gateItems[1], James; verbatim except SEED-RULING opening-clause freshen — see row flags) · mcq4
A student mixes two colorless liquids at room temperature. The mixture stays clear and colorless, but the beaker becomes noticeably warm. Was a sign of possible chemical change observed — and if so, which one?
Yes — a temperature change happening on its own. KEY
No — nothing visible happened in the beaker.
Yes — a color change of the mixed liquids.
Yes — a new solid forming in the mixed liquid.
MPM-024 · medium · application · seq 8 · seed:U01-G2/pool/16 · mcq4
A piece of zinc metal is dropped into a flask of clear acid. Gas puffs up a balloon fitted over the flask, and tests show the gas is a different substance from both the zinc and the acid. Judge the new-gas sign.
The sign is confirmed — a genuinely different substance formed, so a chemical change happened. KEY
The sign still proves nothing — bubbles can always be explained as boiling.
The sign fooled us — the gas must simply have been dissolved in the acid all along and then escaped.
The sign is confirmed — because fizzing always proves a chemical change.
MPM-025 · medium · application · seq 9 · seed:U01-G2/pool/19 (= demo_curated/1, James-curated) — VERBATIM · mcq4
A snapped glow stick glows for hours, and once its glow fades it never glows again, no matter how it is shaken or warmed. Tests show the spent mixture inside is no longer the same substances the fresh stick held. Classify the glowing change inside the stick.
Chemical — light is given off as the contents turn into new substances. KEY
Physical — the stick keeps its shape the whole time, and unchanged shape means unchanged substance.
Physical — nothing new can be seen inside the stick.
Chemical — because snapping plastic is itself a chemical change.
MPM-026 · medium · application · seq 10 · seed:pool_22 (gateItem g2, the number-as-label discrimination the specNotes say this gate item owns; used verbatim - no NOTA/AOTA present, nothing replaced; placement flags empty) · mcq4
A student records: 'beaker 3 fizzed steadily.' Classify the observation.
Qualitative — 'fizzed steadily' is a behavior in words. KEY
Quantitative — the record contains the number 3.
Quantitative — the fizzing shows how much gas formed.
Quantitative — because three beakers must have been counted.
MPM-029 · medium · application · seq 11 · seed:pool[31] (= MPM-029 gateItems[1], James) - value swap 4.5 -> 4.525 per adjust_values_vt6 (placement's suggested value); converted to numeric ENTRY per convert_to_numeric_entry; otherwise VERBATIM · numeric
A bag of road salt is labeled 4.525 kg. What is its mass in grams?
Answer: 4525 g KEY
also accepted: 4,525
wrongValueDiagnostics
[
 {
  "value": 0.004525,
  "misconception": "you treated kilo- as one thousandth instead of one thousand",
  "feedback": "This answer is wrong — you treated kilo- as one thousandth instead of one thousand."
 },
 {
  "value": 452.5,
  "misconception": "you multiplied by one hundred instead of one thousand",
  "feedback": "This answer is wrong — you multiplied by one hundred instead of one thousand."
 },
 {
  "value": 45250,
  "misconception": "you multiplied by ten thousand instead of one thousand",
  "feedback": "This answer is wrong — you multiplied by ten thousand instead of one thousand."
 }
]
feedback
{
 "keyExplanation": "Write down the value in the question:\nm = 4.525 kg\nWrite down what the prefix means:\nkilo- means one thousand, so 1 kg = 1000 g\nSubstitute in the meaning, and calculate:\nm = 4.525 × 1000 g\nm = 4525 g\nA kilogram is a large unit, so the same mass written in grams must be a larger number — 4525 g passes that check; 0.004525 g does not."
}
MPM-030 · medium · application · seq 12 · seed:pool[34] (= MPM-030 gateItems[1], James) - converted mcq->numeric; liquid + value freshened · numeric
A recipe for a cleaning solution calls for 2.485 L of bleach. A measuring cup is marked in milliliters. How many milliliters of bleach are needed?
Answer: 2485 mL KEY
also accepted: 2485 mL, 2,485, 2485.0
wrongValueDiagnostics
[
 {
  "value": 0.002485,
  "misconception": "you divided by one thousand instead of multiplying — that direction turns milliliters into liters",
  "feedback": "This answer is wrong — you divided by one thousand instead of multiplying; that direction turns milliliters into liters. Each liter holds 1000 mL, so 2.485 L is 2.485 × 1000 = 2485 mL."
 },
 {
  "value": 248.5,
  "misconception": "you multiplied by one hundred instead of one thousand",
  "feedback": "This answer is wrong — you multiplied by one hundred instead of one thousand. milli- means one thousandth, so one liter holds 1000 mL: 2.485 × 1000 = 2485 mL."
 },
 {
  "value": 24850,
  "misconception": "you multiplied by ten thousand instead of one thousand",
  "feedback": "This answer is wrong — you multiplied by ten thousand instead of one thousand. One liter holds exactly 1000 mL, so 2.485 L is 2485 mL."
 }
]
feedback
{
 "keyExplanation": "Write down the value in the question:\nV = 2.485 L\nWrite down what the prefix means:\nmilli- means one thousandth, so one liter holds 1000 mL\nSubstitute in the meaning, and calculate:\nV = 2.485 × 1000 mL\nV = 2485 mL\nEach liter is 1000 mL, so 2.485 L must be a little less than two and a half thousand milliliters — 2485 mL fits.",
 "anticipatedWrong": [
  {
   "value": 0.002485,
   "misconception": "you divided by one thousand instead of multiplying — that direction turns milliliters into liters",
   "feedback": "This answer is wrong — you divided by one thousand instead of multiplying; that direction turns milliliters into liters. Each liter holds 1000 mL, so 2.485 L is 2.485 × 1000 = 2485 mL."
  },
  {
   "value": 248.5,
   "misconception": "you multiplied by one hundred instead of one thousand",
   "feedback": "This answer is wrong — you multiplied by one hundred instead of one thousand. milli- means one thousandth, so one liter holds 1000 mL: 2.485 × 1000 = 2485 mL."
  },
  {
   "value": 24850,
   "misconception": "you multiplied by ten thousand instead of one thousand",
   "feedback": "This answer is wrong — you multiplied by ten thousand instead of one thousand. One liter holds exactly 1000 mL, so 2.485 L is 2485 mL."
  }
 ]
}
MPM-031 · medium · application · seq 13 · seed:pool[37] · mcq4
The figure shows apple juice in a narrow graduated cylinder. What is the volume of the juice?
FIGURE (graduated-cylinder · stimulus) — scaleMin: 5 · scaleMax: 20 · unit: "mL" · markEvery: 0.5 · labeledMarks: [5, 10, 15, 20] · meniscusBottomAt: 11.5 · meniscusEdgeAt: 12.0 · style: "clean textbook SVG, narrow cylinder, fine 0.5 mL marks, no reading printed on the figure"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "graduated-cylinder",
  "scaleMin": 5,
  "scaleMax": 20,
  "unit": "mL",
  "markEvery": 0.5,
  "labeledMarks": [
   5,
   10,
   15,
   20
  ],
  "meniscusBottomAt": 11.5,
  "meniscusEdgeAt": 12.0,
  "style": "clean textbook SVG, narrow cylinder, fine 0.5 mL marks, no reading printed on the figure"
 }
}
11.5 mL KEY
12.0 mL
11.0 mL
13.0 mL
MPM-030 · medium · application · seq 14 · authored · mcq4
A stockroom checklist states each supply's amount two ways. Which pair records the same measurement in two different units?
1800 g and 1.8 kg KEY
0.65 L and 65 mL
7 m and 7000 cm
600 mL and 6 L
MPM-032 · medium · application · seq 15 · seed:U01-G2.pool[40] · mcq4
How many significant figures does the measurement 0.0602 L have?
Three KEY
Five
Four
Two
MPM-033 · medium · application · seq 16 · seed:pool_43 (MPM-033 gateItem; converted to numeric ENTRY per convert_to_numeric_entry; factor 1.5 cm -> 1.1 cm per adjust_values_vt6 ('1.5' collides with MPM-030 spec text; interim pick 1.3 was claimed mid-authoring by row18 form E) with full downstream value sweep (9.45->6.93, 9.5->6.9, 9.450->6.930, 9->7); otherwise VERBATIM; no NOTA/AOTA present, nothing replaced) · numeric
Three measurements are multiplied: 2.0 cm × 3.15 cm × 1.1 cm. The calculator shows 6.93. What result should be recorded, in cm³?
Answer: 6.9 cm³ KEY
wrongValueDiagnostics
[
 {
  "value": 6.93,
  "misconception": "you recorded every calculator digit instead of rounding to the fewest significant figures",
  "feedback": "This answer is wrong — you recorded every calculator digit instead of rounding to the fewest significant figures."
 },
 {
  "value": 6.93,
  "misconception": "you padded the result to four digits — extra digits claim precision no measurement vouched for",
  "feedback": "This answer is wrong — you padded the result to four digits — extra digits claim precision no measurement vouched for."
 },
 {
  "value": 7,
  "misconception": "you rounded to one significant figure — the least precise measurements here have two",
  "feedback": "This answer is wrong — you rounded to one significant figure — the least precise measurements here have two."
 }
]
feedback
{
 "keyExplanation": "Count the significant figures in each measurement:\n2.0 cm — two, 3.15 cm — three, 1.1 cm — two\nMultiply, then round to the fewest significant figures:\n2.0 × 3.15 × 1.1 = 6.93\nrecorded result = 6.9 cm³\nWith three measurements the rule is unchanged — the fewest significant figures anywhere in the multiplication, two, sets the result."
}
MPM-025 · hard · transfer · seq 17 · authored · mcq4
Mothballs on a closet shelf slowly shrink week after week, yet they never melt or turn wet. The closet air fills with a strong smell, and that smell is the mothball substance itself, drifting through the air as a gas. Classify the change to the mothballs.
Physical — the balls' substance is leaving as a gas, still the same substance; nothing new is forming. KEY
Chemical — the mothballs are being used up, so their substance must be turning into new substances.
Chemical — a strong smell filling a closet that had none means new substances formed.
Physical — because slow, quiet changes are never chemical.
MPM-033 · hard · transfer · seq 18 · authored · mcq4
A student measures a pebble's mass as 4.34 g and its volume as 1.6 cm³, then divides the mass by the volume. The calculator shows 2.7125, and the student records the result as 2.70 g/cm³. What is wrong with the reported result?
It claims three significant figures — the trailing zero counts, and 1.6 cm³ vouches for only two, so report 2.7 g/cm³. KEY
Nothing is wrong — 2.70 is the same number as 2.7, so the extra zero changes nothing.
It should be 2.7125 g/cm³ — a result records every digit the calculator shows.
It should be 2.71 g/cm³ — results keep the more precise measurement's three significant figures, here set by 4.34 g.
MPM-029 · hard · transfer · seq 19 · authored · mcq4
Four samples of potting soil are weighed on different balances. Which sample has the largest mass?
A sample of 0.83 kg KEY
A sample of 49,000 mg
A sample of 780 g
A sample of 0.795 kg
MPM-032 · hard · transfer · seq 20 · authored · mcq4
In which pair do the two volume readings have the same number of significant figures?
6.07 L and 0.670 L KEY
0.067 L and 6.70 L
67.0 L and 6.7 L
0.607 L and 0.0067 L
MPM-033 · medium · application · seq 21 · authored · frq
A rectangular sticky note measures 7.48 cm along one side and 7.1 cm along the other.
A rectangular sticky note measures 7.48 cm along one side and 7.1 cm along the other. (a) State the number of significant figures in each of the two measurements. (b) Multiply the two side lengths to find the note's area and report it in square centimeters, recorded with the correct number of significant figures. Show your work, including the full result the calculator shows before rounding. (c) In one or two sentences, explain how you decided how many significant figures the recorded area should keep.
Part a. State the number of significant figures in each of the two measurements.
Model: 7.48 cm — three significant figures 7.1 cm — two significant figures
Part b. Multiply the two side lengths to find the note's area and report it in square centimeters, recorded with the correct number of significant figures. Show your work, including the full result the calculator shows before rounding.
Model: side lengths = 7.48 cm and 7.1 cm Multiply the two side lengths, then round to the fewest significant figures. 7.48 × 7.1 = 53.108 The least precise measurement, 7.1 cm, has two significant figures, so round 53.108 to two significant figures. recorded area = 53 square centimeters (both digits of 53 are nonzero, so it cleanly shows two significant figures)
Part c. In one or two sentences, explain how you decided how many significant figures the recorded area should keep.
Model: The least precise measurement sets the precision of the result: 7.1 cm has only two significant figures, so the recorded area keeps two. A result can never be more trustworthy than the shakiest measurement that went into it.
Full model answer. (a) 7.48 cm — three significant figures 7.1 cm — two significant figures (b) side lengths = 7.48 cm and 7.1 cm Multiply the two side lengths, then round to the fewest significant figures. 7.48 × 7.1 = 53.108 The least precise measurement, 7.1 cm, has two significant figures, so round 53.108 to two significant figures. recorded area = 53 square centimeters (both digits of 53 are nonzero, so it cleanly shows two significant figures) (c) The least precise measurement sets the precision of the result: 7.1 cm has only two significant figures, so the recorded area keeps two. A result can never be more trustworthy than the shakiest measurement that went into it.

Form C

MPM-019 · easy · recall · seq 1 · authored · mcq4
A substance's color is a physical property. What makes color a physical property?
Color can be observed while the substance stays itself — looking at it forms nothing new. KEY
Color describes how the substance can turn into a different substance.
Color can only be observed while the substance is melting or boiling.
Color counts as physical because it can be observed without using any instrument or tool.
MPM-021 · easy · recall · seq 2 · authored · mcq4
One question decides whether a change in a substance is physical or chemical. What is that question?
Did one or more new substances form? KEY
Did the substance change shape, size, or state?
Did the change involve heat?
Can the change be undone?
MPM-027 · easy · recall · seq 3 · seed:U01-G2.pool[26] (= MPM-027 gateItems[2], James) — value swap 250 -> 175 per adjust_values_vt6 flag; otherwise VERBATIM · mcq4
A beaker is marked '175 cm³' and a bottle is marked '175 mL'. Compare the two capacities.
They are equal — one milliliter is exactly one cubic centimeter. KEY
The beaker holds more, because a cubic centimeter is larger than a milliliter.
The bottle holds more, because a milliliter is larger than a cubic centimeter.
They cannot be compared, because cm³ measures solids and mL measures liquids.
MPM-028 · easy · recall · seq 4 · seed:pool[29] · mcq4
Which list orders the units from largest to smallest?
kilogram, gram, milligram, nanogram KEY
gram, kilogram, milligram, nanogram
kilogram, gram, nanogram, milligram
nanogram, milligram, gram, kilogram
MPM-020 · medium · application · seq 5 · seed:U01-G2.pool[5] (= MPM-020 gateItems[2], James) — instance freshened · mcq4
Turpentine, a pine-scented liquid, evaporates quickly, and it also catches fire easily. Classify the two properties.
Evaporating quickly is physical; catching fire easily is chemical. KEY
Evaporating quickly is chemical; catching fire easily is physical.
Both are physical.
Both are chemical.
MPM-022 · medium · application · seq 6 · authored · mcq4
At a craft foundry, molten tin is poured into a medallion mold and cools until it is completely solid. Why is the hardening a physical change?
Its particles lock back into fixed positions, and each one is still a tin particle. KEY
Hardening turns the liquid tin into a new solid substance made of different particles.
Each tin particle becomes hard and stiff as the hot metal cools down.
The change is physical only because the medallion could be melted down again.
MPM-023 · medium · application · seq 7 · seed:U01-G2 pool[14] (= MPM-023 gateItems[2], James; must_freshen_instance: snapped glow stick -> firefly) · mcq4
On a summer evening, the tail tip of a firefly blinks with quick pulses of pale light. The insect is not warm to the touch, and nothing is burning it. Which sign of a possible chemical change was observed?
Given-off light. KEY
A color change.
A new gas appearing.
A temperature change happening on its own.
MPM-024 · medium · application · seq 8 · seed:U01-G2/pool/17 · mcq4
A metal spoon left standing in hot tea becomes hot. A lab partner says the spoon's temperature change is a sign of a chemical change in the spoon. Judge the claim.
The claim fails — the hot tea warmed the spoon from outside. KEY
The claim holds — a temperature change is one of the five signs.
The claim holds — metals grow hot only when they change chemically.
The claim fails — because spoons are too small for chemical changes.
MPM-025 · medium · application · seq 9 · authored · mcq4
A sealed jar of honey sits in a cool pantry for months, and pale, grainy crystals slowly appear throughout the liquid. Tests show the crystals are a substance that was dissolved in the honey all along and has now come out of the liquid. Classify the change inside the jar.
Physical — a dissolved substance came out of the liquid as crystals; nothing new formed. KEY
Chemical — crystals formed, and a new solid is one of the five signs.
Chemical — the honey must have turned into a different substance to become grainy.
Physical — because the jar itself is unchanged.
MPM-026 · medium · application · seq 10 · authored · mcq4
A product tester writes in the lab notes: 'the shampoo poured slowly out of the bottle.' Classify the observation.
Qualitative — 'poured slowly' describes a behavior in words, with no measured number or count. KEY
Quantitative — the pouring could have been timed with a stopwatch to give a number of seconds.
Quantitative — 'slowly' tells how fast the shampoo was moving.
Quantitative — pouring speed is a quantity, so any observation about it is quantitative.
MPM-029 · medium · application · seq 11 · authored · numeric
A sample of citric acid has a mass of 325 mg. What is that mass in grams?
Answer: 0.325 g KEY
also accepted: .325
wrongValueDiagnostics
[
 {
  "value": 325000,
  "misconception": "you treated milli- as one thousand instead of one thousandth",
  "feedback": "This answer is wrong — you treated milli- as one thousand instead of one thousandth."
 },
 {
  "value": 3.25,
  "misconception": "you used the centi- meaning, one hundredth, instead of the milli- meaning",
  "feedback": "This answer is wrong — you used the centi- meaning, one hundredth, instead of the milli- meaning."
 },
 {
  "value": 0.0325,
  "misconception": "you moved the decimal point four places instead of three",
  "feedback": "This answer is wrong — you moved the decimal point four places instead of three."
 }
]
feedback
{
 "keyExplanation": "Write down the value in the question:\nm = 325 mg\nWrite down what the prefix means:\nmilli- means one thousandth, so 1 mg = 0.001 g\nSubstitute in the meaning, and calculate:\nm = 325 × 0.001 g\nm = 0.325 g\nA milligram is a small unit, so the same mass written in grams must be a smaller number — 0.325 g passes that check; 325,000 g does not (3.25 g is smaller too, but comes from the centi- meaning, not milli-)."
}
MPM-030 · medium · application · seq 12 · authored · numeric
A parcel at the post office weighs 6485 g. Its shipping label must list the mass in kilograms. What is the parcel's mass in kilograms?
Answer: 6.485 kg KEY
also accepted: 6.485 kg
wrongValueDiagnostics
[
 {
  "value": 6485000,
  "misconception": "you multiplied by one thousand instead of dividing — that direction turns kilograms into grams",
  "feedback": "This answer is wrong — you multiplied by one thousand instead of dividing; that direction turns kilograms into grams. Only 0.001 kg fits in one gram, so divide: 6485 ÷ 1000 = 6.485 kg."
 },
 {
  "value": 64.85,
  "misconception": "you divided by one hundred instead of one thousand",
  "feedback": "This answer is wrong — you divided by one hundred instead of one thousand. kilo- means one thousand, so 1000 g make one kilogram: 6485 ÷ 1000 = 6.485 kg."
 },
 {
  "value": 0.6485,
  "misconception": "you divided by ten thousand instead of one thousand",
  "feedback": "This answer is wrong — you divided by ten thousand instead of one thousand. 1000 g make one kilogram, so the parcel's 6485 g is 6.485 kg."
 }
]
feedback
{
 "keyExplanation": "Write down the value in the question:\nm = 6485 g\nWrite down what the prefix means:\nkilo- means one thousand, so 1000 g make one kilogram\nSubstitute in the meaning, and calculate:\nm = 6485 ÷ 1000 kg\nm = 6.485 kg\nA kilogram is a large unit — 1000 g make one kilogram — so the same mass written in kilograms must be a smaller number than 6485; dividing by 1000 gives 6.485 kg.",
 "anticipatedWrong": [
  {
   "value": 6485000,
   "misconception": "you multiplied by one thousand instead of dividing — that direction turns kilograms into grams",
   "feedback": "This answer is wrong — you multiplied by one thousand instead of dividing; that direction turns kilograms into grams. Only 0.001 kg fits in one gram, so divide: 6485 ÷ 1000 = 6.485 kg."
  },
  {
   "value": 64.85,
   "misconception": "you divided by one hundred instead of one thousand",
   "feedback": "This answer is wrong — you divided by one hundred instead of one thousand. kilo- means one thousand, so 1000 g make one kilogram: 6485 ÷ 1000 = 6.485 kg."
  },
  {
   "value": 0.6485,
   "misconception": "you divided by ten thousand instead of one thousand",
   "feedback": "This answer is wrong — you divided by ten thousand instead of one thousand. 1000 g make one kilogram, so the parcel's 6485 g is 6.485 kg."
  }
 ]
}
MPM-031 · medium · application · seq 13 · authored · mcq4
A tall graduated cylinder holds a blue solution. Using the figure, what is the volume of the solution?
FIGURE (graduated-cylinder · stimulus) — scaleMin: 400 · scaleMax: 500 · unit: "mL" · markEvery: 5 · labeledMarks: [400, 450, 500] · meniscusBottomAt: 465 · meniscusEdgeAt: 470 · style: "clean textbook SVG, tall cylinder, blue-tinted solution, no reading printed on the figure"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "graduated-cylinder",
  "scaleMin": 400,
  "scaleMax": 500,
  "unit": "mL",
  "markEvery": 5,
  "labeledMarks": [
   400,
   450,
   500
  ],
  "meniscusBottomAt": 465,
  "meniscusEdgeAt": 470,
  "style": "clean textbook SVG, tall cylinder, blue-tinted solution, no reading printed on the figure"
 }
}
465.0 mL KEY
470.0 mL
453.0 mL
485.0 mL
MPM-030 · medium · application · seq 14 · authored · mcq4
A lab data table shows each measurement written two ways. Which pair records the same measurement in two different units?
0.73 m and 73 cm KEY
2.9 kg and 290 g
0.62 L and 62 mL
80 g and 0.8 kg
MPM-032 · medium · application · seq 15 · authored · mcq4
Which measurement has exactly two significant figures?
0.079 kg KEY
0.709 kg
79.00 kg
0.7090 kg
MPM-033 · medium · application · seq 16 · authored · numeric
The mass of a seashell fragment is measured as 9.783 g and its volume as 3.6 cm³. A student divides the fragment's mass by its volume, and the calculator shows 2.7175. What result should be recorded, in g/cm³?
Answer: 2.7 g/cm³ KEY
wrongValueDiagnostics
[
 {
  "value": 2.7175,
  "misconception": "you recorded every calculator digit — the calculator does not know which digits the measurements vouch for",
  "feedback": "This answer is wrong — you recorded every calculator digit — the calculator does not know which digits the measurements vouch for."
 },
 {
  "value": 2.718,
  "misconception": "you rounded to the more precise measurement's four significant figures instead of the fewest",
  "feedback": "This answer is wrong — you rounded to the more precise measurement's four significant figures instead of the fewest."
 },
 {
  "value": 3,
  "misconception": "you rounded past the rule — the result keeps as many significant figures as the least precise measurement, no fewer",
  "feedback": "This answer is wrong — you rounded past the rule — the result keeps as many significant figures as the least precise measurement, no fewer."
 }
]
feedback
{
 "keyExplanation": "Count the significant figures in each measurement:\n9.783 g — four significant figures\n3.6 cm³ — two significant figures\nDivide, then round to the fewest significant figures:\n9.783 ÷ 3.6 = 2.7175\nrecorded result = 2.7 g/cm³\nThe least precise measurement sets the precision — two significant figures, no more and no fewer."
}
MPM-025 · hard · transfer · seq 17 · authored · mcq4
A rubber band kept for years in a closed desk drawer has turned stiff and cracked. Its surface crumbles into a dry powder, and tests on the powder show that none of it is rubber anymore. Gentle warming never makes the crumbs stretchy again. Classify the change to the band.
Chemical — the powdery surface is a new substance formed from the band's rubber. KEY
Physical — the band is still a rubber band.
Physical — the band just dried out, and drying is not a chemical change.
Chemical — because anything kept long enough turns into something new.
MPM-033 · hard · transfer · seq 18 · authored · mcq4
A student multiplies the measured length, 4.66 cm, and width, 1.7 cm, of a rectangular sticker. The calculator shows 7.922 for the sticker's area, and the student reports 7.92 cm². What is wrong with the reported result?
It keeps three significant figures — 1.7 cm vouches for only two, so report 7.9 cm². KEY
Nothing is wrong — 4.66 cm has three significant figures, so the result may keep three.
It should be 7.922 cm² — a result records every digit the calculator shows.
It should be 8 cm² — always round a calculated result to one significant figure.
MPM-029 · hard · transfer · seq 19 · authored · mcq4
Four samples of nickel pellets are weighed on different balances. Which sample has the largest mass?
A sample of 0.91 kg KEY
A sample of 56,000 mg
A sample of 875 g
A sample of 0.885 kg
MPM-032 · hard · transfer · seq 20 · authored · mcq4
In which pair do the two recorded masses have the same number of significant figures?
80.06 kg and 0.8600 kg KEY
0.086 kg and 86.0 kg
0.860 kg and 86.00 kg
0.0806 kg and 0.86 kg
MPM-033 · medium · application · seq 21 · authored · frq
A small rectangular storage box has three measured edge lengths: 4.4 cm, 2.35 cm, and 4.95 cm.
A small rectangular storage box has three measured edge lengths: 4.4 cm, 2.35 cm, and 4.95 cm. (a) State the number of significant figures in each of the three measurements. (b) Multiply the three edge lengths to find the box's volume and report it in cubic centimeters, recorded with the correct number of significant figures. Show your work, including the full result the calculator shows before rounding. (c) In one or two sentences, explain how you decided how many significant figures the recorded volume should keep.
Part a. State the number of significant figures in each of the three measurements.
Model: 4.4 cm — two significant figures 2.35 cm — three significant figures 4.95 cm — three significant figures
Part b. Multiply the three edge lengths to find the box's volume and report it in cubic centimeters, recorded with the correct number of significant figures. Show your work, including the full result the calculator shows before rounding.
Model: edge lengths = 4.4 cm, 2.35 cm, and 4.95 cm Multiply the three edge lengths, then round to the fewest significant figures. 4.4 × 2.35 × 4.95 = 51.183 The least precise measurement, 4.4 cm, has two significant figures, so round 51.183 to two significant figures. recorded volume = 51 cubic centimeters (both digits of 51 are nonzero, so it cleanly shows two significant figures)
Part c. In one or two sentences, explain how you decided how many significant figures the recorded volume should keep.
Model: With three measurements the rule is unchanged — the fewest significant figures anywhere in the multiplication set the result. 4.4 cm has only two significant figures, so the recorded volume keeps two: the least precise measurement sets the precision of the result.
Full model answer. (a) 4.4 cm — two significant figures 2.35 cm — three significant figures 4.95 cm — three significant figures (b) edge lengths = 4.4 cm, 2.35 cm, and 4.95 cm Multiply the three edge lengths, then round to the fewest significant figures. 4.4 × 2.35 × 4.95 = 51.183 The least precise measurement, 4.4 cm, has two significant figures, so round 51.183 to two significant figures. recorded volume = 51 cubic centimeters (both digits of 51 are nonzero, so it cleanly shows two significant figures) (c) With three measurements the rule is unchanged — the fewest significant figures anywhere in the multiplication set the result. 4.4 cm has only two significant figures, so the recorded volume keeps two: the least precise measurement sets the precision of the result.

Form D

MPM-019 · easy · recall · seq 1 · authored · mcq4
Whether a substance sits as a solid, a liquid, or a gas at room temperature is a physical property. What makes the state at room temperature a physical property?
The state can be observed while the substance stays itself — nothing new forms. KEY
The state at room temperature describes how the substance can turn into a different substance.
The state counts as physical because it can be seen without using any instrument or tool.
The state is physical because the state belongs to the room's temperature, not to the substance.
MPM-021 · easy · recall · seq 2 · authored · mcq4
A slice of cheese on a hot pizza melts into a gooey liquid. Why is the melting a physical change?
The melted cheese is still cheese — same substance in a new state, nothing new formed. KEY
Because the cheese will harden again as the pizza cools.
Because heat caused the melting, and heat-driven changes are the physical ones.
Because the change was quiet and slow — dramatic changes are the chemical ones.
MPM-027 · easy · recall · seq 3 · authored · mcq4
A lab data sheet has one blank left to fill: the temperature inside the lab oven. In which unit do chemists record everyday lab temperatures like this one?
Degrees Celsius — the everyday lab unit; the SI base unit is the kelvin. KEY
Kelvins — the everyday lab unit; the SI base unit is the degree Celsius.
Either one — degrees Celsius and the kelvin are two names for the same unit.
No unit can be shared — SI includes no temperature unit, so each lab picks its own.
MPM-028 · easy · recall · seq 4 · authored · mcq4
A storage tank's capacity plate reads '1 kL' — one kiloliter. Using the meaning of kilo-, how much liquid can the tank hold?
one thousand liters KEY
one hundred liters
one thousandth of a liter
one thousand grams
MPM-020 · medium · application · seq 5 · authored (no seed exists for this seq beyond forms A-C; G1 fresh-instance row rules) · mcq4
A classmate claims: 'The ability of cabbage to ferment into tangy sauerkraut is a physical property, because the shreds in the jar still look like cabbage.' Classify the property and judge the reason.
Chemical — fermenting forms new substances, and the tangy taste belongs to them. KEY
Physical — the student's reason is right: the shreds still look like cabbage.
Physical — fermenting takes weeks, and slow changes are physical.
Chemical — because sauerkraut can never turn back into fresh cabbage.
MPM-022 · medium · application · seq 6 · authored · mcq4
A drop of perfume on a student's wrist is gone within minutes, and its scent soon fills the room. The student says: 'The liquid perfume changed into a completely new substance.' What is wrong with the claim?
The perfume particles drifted away as a gas, unchanged — the scent is those particles reaching your nose. KEY
Nothing is wrong — a liquid that vanishes from sight has become a different, invisible new substance.
The claim is wrong, but only because the gas could be cooled back into liquid perfume.
The perfume's particles broke apart into much smaller scent particles.
MPM-023 · medium · application · seq 7 · authored · mcq4
A bath bomb dropped into a full bathtub fizzes vigorously, sending streams of bubbles up through the liquid, though nothing is being heated. Which sign of a possible chemical change was observed?
A new gas appearing. KEY
A new solid forming in a mixed liquid.
A temperature change happening on its own.
Given-off light.
MPM-024 · medium · application · seq 8 · authored · mcq4
A bottle of maple syrup stored in a cold cupboard slowly fills with hard, gritty grains. Tests show the grains are a substance the syrup contained all along, now in solid form. A lab partner says the grains are a sign that the syrup changed chemically. Judge the claim.
The claim fails — the grains are a substance the syrup already contained, so nothing new formed. KEY
The claim holds — a new solid appearing is one of the five signs, so the change must be chemical.
The claim holds — hard grains could not have been hiding in a smooth liquid.
The claim fails — because chemical changes need warmth, and the cupboard is cold.
MPM-025 · medium · application · seq 9 · authored · mcq4
A camper opens a disposable hand-warmer packet and shakes it. The packet grows hot by itself — nothing around it is heating it — and stays warm for hours. Once it cools, it never heats up again, no matter how it is shaken. Tests show the spent powder is no longer the substance fresh packets hold. Classify the change inside the packet.
Chemical — heat is given off as the powder turns into new substances. KEY
Physical — the packet keeps its shape the whole time, and unchanged shape means unchanged substance.
Physical — nothing new can be seen inside the packet.
Chemical — because shaking a packet is itself a chemical change.
MPM-026 · medium · application · seq 10 · authored · mcq4
During a buoyancy demonstration, a student writes: 'the plastic boat held 13 steel washers before it sank.' Classify the observation.
Quantitative — '13 steel washers' records a count. KEY
Qualitative — the washers were counted by eye, with no measuring instrument.
Qualitative — 'plastic' and 'steel' are describing words, so the entry records qualities.
Qualitative — the entry is a full written sentence, not a value in a data table.
MPM-029 · medium · application · seq 11 · authored · numeric
A lab bench is 156 cm long. What is that length in meters?
Answer: 1.56 m KEY
wrongValueDiagnostics
[
 {
  "value": 15600,
  "misconception": "you treated centi- as one hundred instead of one hundredth",
  "feedback": "This answer is wrong — you treated centi- as one hundred instead of one hundredth."
 },
 {
  "value": 0.156,
  "misconception": "you used the milli- meaning, one thousandth, instead of the centi- meaning",
  "feedback": "This answer is wrong — you used the milli- meaning, one thousandth, instead of the centi- meaning."
 },
 {
  "value": 15.6,
  "misconception": "you moved the decimal point one place instead of two",
  "feedback": "This answer is wrong — you moved the decimal point one place instead of two."
 }
]
feedback
{
 "keyExplanation": "Write down the value in the question:\nl = 156 cm\nWrite down what the prefix means:\ncenti- means one hundredth, so 1 cm = 0.01 m\nSubstitute in the meaning, and calculate:\nl = 156 × 0.01 m\nl = 1.56 m\nA centimeter is a small unit, so the same length written in meters must be a smaller number — 1.56 m passes that check; 15,600 m does not (15.6 m is smaller too, but comes from moving the decimal one place, not two)."
}
MPM-030 · medium · application · seq 12 · authored · numeric
A desk is 1.27 m long. Its assembly manual lists every length in centimeters. What is the desk's length in centimeters?
Answer: 127 cm KEY
also accepted: 127 cm, 127.0
wrongValueDiagnostics
[
 {
  "value": 0.0127,
  "misconception": "you divided by one hundred instead of multiplying — that direction turns centimeters into meters",
  "feedback": "This answer is wrong — you divided by one hundred instead of multiplying; that direction turns centimeters into meters. One meter holds 100 cm, so 1.27 m is 1.27 × 100 = 127 cm."
 },
 {
  "value": 1270,
  "misconception": "you multiplied by one thousand, the milli- meaning, instead of one hundred",
  "feedback": "This answer is wrong — you multiplied by one thousand, the milli- meaning, instead of one hundred. centi- means one hundredth, so one meter holds 100 cm: 1.27 × 100 = 127 cm."
 },
 {
  "value": 12.7,
  "misconception": "you multiplied by ten instead of one hundred",
  "feedback": "This answer is wrong — you multiplied by ten instead of one hundred. centi- means one hundredth, so one meter holds 100 cm, and 1.27 × 100 = 127 cm."
 }
]
feedback
{
 "keyExplanation": "Write down the value in the question:\nl = 1.27 m\nWrite down what the prefix means:\ncenti- means one hundredth, so one meter holds 100 cm\nSubstitute in the meaning, and calculate:\nl = 1.27 × 100 cm\nl = 127 cm\nA centimeter is a smaller unit than a meter, so the same length written in centimeters must be a larger number than 1.27 — multiplying by 100 gives 127 cm.",
 "anticipatedWrong": [
  {
   "value": 0.0127,
   "misconception": "you divided by one hundred instead of multiplying — that direction turns centimeters into meters",
   "feedback": "This answer is wrong — you divided by one hundred instead of multiplying; that direction turns centimeters into meters. One meter holds 100 cm, so 1.27 m is 1.27 × 100 = 127 cm."
  },
  {
   "value": 1270,
   "misconception": "you multiplied by one thousand, the milli- meaning, instead of one hundred",
   "feedback": "This answer is wrong — you multiplied by one thousand, the milli- meaning, instead of one hundred. centi- means one hundredth, so one meter holds 100 cm: 1.27 × 100 = 127 cm."
  },
  {
   "value": 12.7,
   "misconception": "you multiplied by ten instead of one hundred",
   "feedback": "This answer is wrong — you multiplied by ten instead of one hundred. centi- means one hundredth, so one meter holds 100 cm, and 1.27 × 100 = 127 cm."
  }
 ]
}
MPM-031 · medium · application · seq 13 · authored · mcq4
A small graduated cylinder contains a green solution. Using the figure, what volume of solution is in the cylinder?
FIGURE (graduated-cylinder · stimulus) — scaleMin: 4 · scaleMax: 8 · unit: "mL" · markEvery: 0.2 · labeledMarks: [4, 5, 6, 7, 8] · meniscusBottomAt: 6.4 · meniscusEdgeAt: 6.6 · style: "clean textbook SVG, small narrow cylinder, fine 0.2 mL marks, green-tinted solution, no reading printed on the figure"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "graduated-cylinder",
  "scaleMin": 4,
  "scaleMax": 8,
  "unit": "mL",
  "markEvery": 0.2,
  "labeledMarks": [
   4,
   5,
   6,
   7,
   8
  ],
  "meniscusBottomAt": 6.4,
  "meniscusEdgeAt": 6.6,
  "style": "clean textbook SVG, small narrow cylinder, fine 0.2 mL marks, green-tinted solution, no reading printed on the figure"
 }
}
6.4 mL KEY
6.6 mL
7.0 mL
6.0 mL
MPM-030 · medium · application · seq 14 · authored · mcq4
An equipment log lists each measurement two ways. Which pair records the same measurement in two different units?
0.48 g and 480 mg KEY
5.9 kg and 590 g
0.26 m and 260 cm
220 mL and 2.2 L
MPM-032 · medium · application · seq 15 · authored · mcq4
How many significant figures does the measurement 0.0540 g have?
Three KEY
Five
Four
Two
MPM-033 · medium · application · seq 16 · authored · numeric
A tile measures 9.4 cm along one edge and 7.31 cm along the other. Multiplying the two lengths, the calculator shows 68.714. What result should be recorded, in cm²?
Answer: 69 cm² KEY
wrongValueDiagnostics
[
 {
  "value": 68.714,
  "misconception": "you recorded every calculator digit — the calculator does not know which digits the measurements vouch for",
  "feedback": "This answer is wrong — you recorded every calculator digit — the calculator does not know which digits the measurements vouch for."
 },
 {
  "value": 68.7,
  "misconception": "you rounded to the more precise measurement's three significant figures instead of the fewest",
  "feedback": "This answer is wrong — you rounded to the more precise measurement's three significant figures instead of the fewest."
 },
 {
  "value": 1.3,
  "misconception": "you divided one edge length by the other instead of multiplying — an area multiplies the two lengths",
  "feedback": "This answer is wrong — you divided one edge length by the other instead of multiplying — an area multiplies the two lengths."
 }
]
feedback
{
 "keyExplanation": "Count the significant figures in each measurement:\n9.4 cm — two significant figures\n7.31 cm — three significant figures\nMultiply, then round to the fewest significant figures:\n9.4 × 7.31 = 68.714\nrecorded result = 69 cm²\nThe least precise measurement sets the precision — two significant figures, no more and no fewer."
}
MPM-025 · hard · transfer · seq 17 · authored · mcq4
A wool sweater that has been through many hot machine washes comes out smaller, denser, and stiffer, and no amount of stretching returns it to its old size. Under a magnifier, its fibers are the same wool hairs as before, now tangled far more tightly together. Classify the change to the sweater.
Physical — the fibers are still the same wool; only how tightly they are tangled has changed. KEY
Chemical — the shrinking can never be undone, and a change that cannot be undone must be chemical.
Chemical — becoming denser and stiffer shows the wool turned into a new substance.
Physical — because the sweater lost nothing in the wash, and a change where nothing is lost is physical.
MPM-033 · hard · transfer · seq 18 · authored · mcq4
A solid sample's mass, 21.4 g, is divided by its volume, 6.4 cm³. The calculator shows 3.34375, and the student reports 3 g/cm³. What is wrong with the reported result?
It keeps only one significant figure — 6.4 cm³ vouches for two, so report 3.3 g/cm³. KEY
Nothing is wrong — rounding to one significant figure just makes the report more cautious.
It should be 3.34375 g/cm³ — a result records every digit the calculator shows.
It should be 3.34 g/cm³ — results keep the more precise measurement's three significant figures.
MPM-029 · hard · transfer · seq 19 · authored · mcq4
Four samples of glass beads are weighed on different balances. Which sample has the largest mass?
A sample of 0.97 kg KEY
A sample of 58,000 mg
A sample of 905 g
A sample of 0.895 kg
MPM-032 · hard · transfer · seq 20 · authored · mcq4
In which pair do both mass measurements have the same number of significant figures?
0.089 g and 8.9 g KEY
0.8090 g and 8.09 g
0.0809 g and 0.89 g
0.009 g and 8.900 g
MPM-033 · medium · application · seq 21 · authored · frq
A transfer pump delivers 313 mL of liquid into a beaker in 4.0 s.
A transfer pump delivers 313 mL of liquid into a beaker in 4.0 s. (a) State the number of significant figures in each of the two measurements. (b) Divide the volume delivered by the filling time and report the pump's delivery rate in mL/s, recorded with the correct number of significant figures. Show your work, including the full result the calculator shows before rounding. (c) In one or two sentences, explain how you decided how many significant figures the recorded rate should keep.
Part a. State the number of significant figures in each of the two measurements.
Model: 313 mL — three significant figures 4.0 s — two significant figures
Part b. Divide the volume delivered by the filling time and report the pump's delivery rate in mL/s, recorded with the correct number of significant figures. Show your work, including the full result the calculator shows before rounding.
Model: volume = 313 mL, time = 4.0 s Divide the volume by the time, then round to the fewest significant figures. 313 ÷ 4.0 = 78.25 The least precise measurement, 4.0 s, has two significant figures, so round 78.25 to two significant figures. recorded result = 78 mL/s (both digits of 78 are nonzero, so it cleanly shows two significant figures)
Part c. In one or two sentences, explain how you decided how many significant figures the recorded rate should keep.
Model: The least precise measurement sets the precision of the result: 4.0 s has only two significant figures, so the recorded rate keeps two. A result can never be more trustworthy than the shakiest measurement that went into it.
Full model answer. (a) 313 mL — three significant figures 4.0 s — two significant figures (b) volume = 313 mL, time = 4.0 s Divide the volume by the time, then round to the fewest significant figures. 313 ÷ 4.0 = 78.25 The least precise measurement, 4.0 s, has two significant figures, so round 78.25 to two significant figures. recorded result = 78 mL/s (both digits of 78 are nonzero, so it cleanly shows two significant figures) (c) The least precise measurement sets the precision of the result: 4.0 s has only two significant figures, so the recorded rate keeps two. A result can never be more trustworthy than the shakiest measurement that went into it.

Form E

MPM-019 · easy · recall · seq 1 · authored · mcq4
Flammability — the ability to burn — is a chemical property. What makes flammability a chemical property?
It describes how burning turns the substance into new substances. KEY
Burning can be watched while the substance stays itself, forming nothing new.
It means the substance is made of chemicals.
It describes how quickly the substance melts when a flame is held near it.
MPM-021 · easy · recall · seq 2 · authored · mcq4
A splash of bleach turns one patch of a blue sock white, and the patch stays white through every wash that follows. Why is the bleaching a chemical change?
The bleach turned the blue dye into new, colorless substances — the dye stopped being itself. KEY
Because the sock looks completely different afterward.
Because bleach is a strong chemical, and anything a chemical touches is changed chemically.
Because the white patch can never be made blue again.
MPM-027 · easy · recall · seq 3 · authored · mcq4
A classmate's data table has an entry that reads: 'glycerin sample — 46 cm³'. Which quantity does the entry record?
Volume — cubic centimeters record how much space the glycerin takes up. KEY
Mass — cubic centimeters record how much matter the glycerin contains.
Temperature — cubic centimeters record how warm the glycerin is.
Nothing valid — cubic centimeters measure only solids, and glycerin is a liquid.
MPM-028 · easy · recall · seq 4 · authored · mcq4
The smallest tick marks on a metric ruler are one millimeter apart. Using the meaning of milli-, how much of a meter is one millimeter?
one thousandth of a meter KEY
one hundredth of a meter
one billionth of a meter
one thousand meters
MPM-020 · medium · application · seq 5 · authored (no seed exists for this seq beyond forms A-C; G1 fresh-instance row rules) · mcq4
Four properties of aluminum metal are listed. Which one is a chemical property?
It slowly grows a dull gray coating in damp weather. KEY
It melts at 660 °C.
It conducts heat quickly.
It can be rolled into thin sheets without cracking.
MPM-022 · medium · application · seq 6 · authored · mcq4
Liquid helium poured into an open container boils vigorously at room temperature until the container is empty. Why is the boiling a physical change?
The helium particles spread far apart and fly freely, but each one is still a helium particle. KEY
It is not truly physical — whenever a liquid turns into a gas, a brand-new substance has formed.
The warmth of the room breaks each helium particle into lighter gas particles.
Because the warming softens each helium particle from a liquid particle into a gas particle.
MPM-023 · medium · application · seq 7 · authored · mcq4
A student pours one clear liquid into another. A fine white solid appears throughout the mixture and slowly sinks to the bottom, while the liquid around it stays colorless. Which sign of a possible chemical change was observed?
A new solid appearing. KEY
A color change.
A new gas appearing.
Given-off light.
MPM-024 · medium · application · seq 8 · authored · mcq4
The two pastes of a two-part epoxy glue are stirred together in a plastic cup. With no heater and no sunlight anywhere near it, the mixture grows warm on its own and sets into a hard solid, and tests show the solid is not the same substance as either paste. Judge the temperature sign.
The sign is confirmed — the mixture warmed on its own while a genuinely different substance formed. KEY
The sign fooled us — something in the room must have warmed the cup from outside.
The sign proves nothing — temperature is a physical property, so a temperature change is physical evidence, not chemical evidence.
The sign fooled us — the warmth came from the stirring, since rubbing pastes together warms them.
MPM-025 · medium · application · seq 9 · authored · mcq4
Dry, light-colored sand in a playground sandbox turns dark wherever rain soaks it. Once the wet patch dries, it is light-colored again and looks just like the sand around it. Classify the darkening.
Physical — the rain soaked into the sand, and both stayed the same substances. KEY
Chemical — the sand changed color, and a color change is one of the five signs.
Chemical — the rain and the sand combined into a new, darker substance.
Physical — because rain soaking into things is too gentle to change any substance.
MPM-026 · medium · application · seq 10 · authored · mcq4
A student comparing two batches of homemade slime writes four entries about the new batch. Which entry is quantitative?
The batch's mass came to 84.6 g. KEY
The slime stretched much farther than yesterday's batch.
The slime felt perfectly smooth between the fingers.
The slime jiggled whenever the bowl was tapped.
MPM-029 · medium · application · seq 11 · authored · numeric
A railway tunnel is 2.847 km long. What is that length in meters?
Answer: 2847 m KEY
also accepted: 2,847
wrongValueDiagnostics
[
 {
  "value": 0.002847,
  "misconception": "you treated kilo- as one thousandth instead of one thousand",
  "feedback": "This answer is wrong — you treated kilo- as one thousandth instead of one thousand."
 },
 {
  "value": 284.7,
  "misconception": "you multiplied by one hundred instead of one thousand",
  "feedback": "This answer is wrong — you multiplied by one hundred instead of one thousand."
 },
 {
  "value": 28470,
  "misconception": "you multiplied by ten thousand instead of one thousand",
  "feedback": "This answer is wrong — you multiplied by ten thousand instead of one thousand."
 }
]
feedback
{
 "keyExplanation": "Write down the value in the question:\nd = 2.847 km\nWrite down what the prefix means:\nkilo- means one thousand, so 1 km = 1000 m\nSubstitute in the meaning, and calculate:\nd = 2.847 × 1000 m\nd = 2847 m\nA kilometer is a large unit, so the same length written in meters must be a larger number — 2847 m passes that check; 0.002847 m does not."
}
MPM-030 · medium · application · seq 12 · authored · numeric
A rainwater tank holds 5275 L. The supplier's invoice lists volumes in kiloliters (kL). What is the tank's volume in kiloliters?
Answer: 5.275 kL KEY
also accepted: 5.275 kL
wrongValueDiagnostics
[
 {
  "value": 5275000,
  "misconception": "you multiplied by one thousand instead of dividing — that direction turns kiloliters into liters",
  "feedback": "This answer is wrong — you multiplied by one thousand instead of dividing; that direction turns kiloliters into liters. 1000 L make one kiloliter, so divide: 5275 ÷ 1000 = 5.275 kL."
 },
 {
  "value": 52.75,
  "misconception": "you divided by one hundred instead of one thousand",
  "feedback": "This answer is wrong — you divided by one hundred instead of one thousand. kilo- means one thousand, so 1000 L make one kiloliter: 5275 ÷ 1000 = 5.275 kL."
 },
 {
  "value": 0.5275,
  "misconception": "you divided by ten thousand instead of one thousand",
  "feedback": "This answer is wrong — you divided by ten thousand instead of one thousand. 1000 L make one kiloliter, so the tank's 5275 L is 5.275 kL."
 }
]
feedback
{
 "keyExplanation": "Write down the value in the question:\nV = 5275 L\nWrite down what the prefix means:\nkilo- means one thousand, so 1000 L make one kiloliter — a prefix keeps its meaning on any unit\nSubstitute in the meaning, and calculate:\nV = 5275 ÷ 1000 kL\nV = 5.275 kL\nA kiloliter is a large unit, so the same volume written in kiloliters must be a smaller number than 5275 — dividing by 1000 gives 5.275 kL.",
 "anticipatedWrong": [
  {
   "value": 5275000,
   "misconception": "you multiplied by one thousand instead of dividing — that direction turns kiloliters into liters",
   "feedback": "This answer is wrong — you multiplied by one thousand instead of dividing; that direction turns kiloliters into liters. 1000 L make one kiloliter, so divide: 5275 ÷ 1000 = 5.275 kL."
  },
  {
   "value": 52.75,
   "misconception": "you divided by one hundred instead of one thousand",
   "feedback": "This answer is wrong — you divided by one hundred instead of one thousand. kilo- means one thousand, so 1000 L make one kiloliter: 5275 ÷ 1000 = 5.275 kL."
  },
  {
   "value": 0.5275,
   "misconception": "you divided by ten thousand instead of one thousand",
   "feedback": "This answer is wrong — you divided by ten thousand instead of one thousand. 1000 L make one kiloliter, so the tank's 5275 L is 5.275 kL."
  }
 ]
}
MPM-031 · medium · application · seq 13 · authored · mcq4
A tall graduated cylinder holds a yellow solution, shown in the figure. What is the volume of the solution?
FIGURE (graduated-cylinder · stimulus) — scaleMin: 700 · scaleMax: 730 · unit: "mL" · markEvery: 2 · labeledMarks: [700, 710, 720, 730] · meniscusBottomAt: 724 · meniscusEdgeAt: 725 · style: "clean textbook SVG, tall cylinder, yellow-tinted solution, no reading printed on the figure"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "graduated-cylinder",
  "scaleMin": 700,
  "scaleMax": 730,
  "unit": "mL",
  "markEvery": 2,
  "labeledMarks": [
   700,
   710,
   720,
   730
  ],
  "meniscusBottomAt": 724,
  "meniscusEdgeAt": 725,
  "style": "clean textbook SVG, tall cylinder, yellow-tinted solution, no reading printed on the figure"
 }
}
724.0 mL KEY
725.0 mL
722.0 mL
726.0 mL
MPM-030 · medium · application · seq 14 · authored · mcq4
On a classmate's homework, four measurements are each written two ways. Which pair records the same measurement in two different units?
5200 m and 5.2 km KEY
0.27 L and 27 mL
1.9 kg and 190 g
55 cm and 5.5 m
MPM-032 · medium · application · seq 15 · authored · mcq4
Which measurement has exactly four significant figures?
20.60 g KEY
0.0026 g
26.050 g
0.260 g
MPM-033 · medium · application · seq 16 · authored · numeric
A solid stopper has a measured mass of 7.367 g and a measured volume of 5.3 cm³. A student divides the stopper's mass by its volume, and the calculator shows 1.39. What result should be recorded, in g/cm³?
Answer: 1.4 g/cm³ KEY
wrongValueDiagnostics
[
 {
  "value": 1.39,
  "misconception": "you recorded every calculator digit — the calculator does not know which digits the measurements vouch for",
  "feedback": "This answer is wrong — you recorded every calculator digit — the calculator does not know which digits the measurements vouch for."
 },
 {
  "value": 1.39,
  "misconception": "you rounded to the more precise measurement's four significant figures instead of the fewest",
  "feedback": "This answer is wrong — you rounded to the more precise measurement's four significant figures instead of the fewest."
 },
 {
  "value": 1,
  "misconception": "you rounded past the rule — the result keeps as many significant figures as the least precise measurement, no fewer",
  "feedback": "This answer is wrong — you rounded past the rule — the result keeps as many significant figures as the least precise measurement, no fewer."
 }
]
feedback
{
 "keyExplanation": "Count the significant figures in each measurement:\n7.367 g — four significant figures\n5.3 cm³ — two significant figures\nDivide, then round to the fewest significant figures:\n7.367 ÷ 5.3 = 1.39\nrecorded result = 1.4 g/cm³\nThe least precise measurement sets the precision — two significant figures, no more and no fewer."
}
MPM-025 · hard · transfer · seq 17 · authored · mcq4
A pale limestone statue outside an old courthouse slowly grows a soft, dark gray crust — even on its sheltered underside, where nothing can settle out of the air. A conservator brushes the crust off as a fine powder, and lab checks on that powder find it is no longer limestone; beneath it the carved details are clean again but noticeably shallower. Classify the change to the statue's stone.
Chemical — the crust is a new substance formed from some of the statue's stone. KEY
Physical — the crust is only dirt from the city air settling on the statue.
Physical — the statue is still a limestone statue.
Chemical — because the crust took years to appear, and that slow creep marks a chemical change.
MPM-033 · hard · transfer · seq 18 · authored · mcq4
A student multiplies the three measured side lengths of a rectangular eraser, 1.3 cm × 1.65 cm × 3.4 cm, to find its volume. The calculator shows 7.293, and the student reports 7.293 cm³. What is wrong with the reported result?
It keeps four significant figures — 1.3 cm and 3.4 cm each vouch for only two, so report 7.3 cm³. KEY
Nothing is wrong — the calculator's 7.293 is the exact product of the three lengths, so it is the correct value to report.
It should be 7.29 cm³ — results keep the most precise measurement's three significant figures.
It should be 7 cm³ — always round a calculated result to one significant figure.
MPM-029 · hard · transfer · seq 19 · authored · mcq4
Four samples of cornstarch are weighed on different balances. Which sample has the largest mass?
A sample of 1.05 kg KEY
A sample of 87,000 mg
A sample of 815 g
A sample of 0.98 kg
MPM-032 · hard · transfer · seq 20 · authored · mcq4
In which pair do both volume measurements have the same number of significant figures?
96.0 mL and 9.06 mL KEY
0.96 mL and 90.6 mL
9.6 mL and 9.60 mL
0.960 mL and 96.00 mL
MPM-033 · medium · application · seq 21 · authored · frq
A rectangular photograph measures 8.72 cm along one side and 8.8 cm along the other.
A rectangular photograph measures 8.72 cm along one side and 8.8 cm along the other. (a) State the number of significant figures in each of the two measurements. (b) Multiply the two side lengths to find the photograph's area and report it in square centimeters, recorded with the correct number of significant figures. Show your work, including the full result the calculator shows before rounding. (c) The two side lengths are nearly the same size. In one or two sentences, explain how you decided how many significant figures the recorded area should keep.
Part a. State the number of significant figures in each of the two measurements.
Model: 8.72 cm — three significant figures 8.8 cm — two significant figures
Part b. Multiply the two side lengths to find the photograph's area and report it in square centimeters, recorded with the correct number of significant figures. Show your work, including the full result the calculator shows before rounding.
Model: side lengths = 8.72 cm and 8.8 cm Multiply the two side lengths, then round to the fewest significant figures. 8.72 × 8.8 = 76.736 The least precise measurement, 8.8 cm, has two significant figures, so round 76.736 to two significant figures. recorded area = 77 square centimeters (both digits of 77 are nonzero, so it cleanly shows two significant figures)
Part c. The two side lengths are nearly the same size. In one or two sentences, explain how you decided how many significant figures the recorded area should keep.
Model: How many digits a measurement vouches for is what counts, not how big it is: 8.8 cm has only two significant figures, so the recorded area keeps two. The least precise measurement sets the precision of the result — a result can never be more trustworthy than the shakiest measurement that went into it.
Full model answer. (a) 8.72 cm — three significant figures 8.8 cm — two significant figures (b) side lengths = 8.72 cm and 8.8 cm Multiply the two side lengths, then round to the fewest significant figures. 8.72 × 8.8 = 76.736 The least precise measurement, 8.8 cm, has two significant figures, so round 76.736 to two significant figures. recorded area = 77 square centimeters (both digits of 77 are nonzero, so it cleanly shows two significant figures) (c) How many digits a measurement vouches for is what counts, not how big it is: 8.8 cm has only two significant figures, so the recorded area keeps two. The least precise measurement sets the precision of the result — a result can never be more trustworthy than the shakiest measurement that went into it.

End of Topic Test: Density as identity evidence (u01-t3 · 5 forms × 21 items · 105 total)

David's notes for James:
full notes file
# u01-t3 — notes/queries from David's side (U01-G3)

1. Numeric-ENTRY conversion of five of your mcq gate seeds (MPM-038 gateItems[0]/[2] -> seq 8 forms A/B; MPM-039 gate item pool[15] -> seq 10 form A; MPM-040 gateItems[0]/[1] -> seq 12 forms A/B): scenarios kept, options dropped, your distractor misconceptions became wrong-value diagnostics. Same HS rule as the G2 conversions (numeric answers are numeric ENTRY, never MCQ; the AP gate-exception is overridden). On the converted seq 8/10 rows the diagnostics carry misconception text without a separate feedback string (the keyExplanation's sense check covers the flip error); the seq 12/14 rows carry full per-value feedback. Confirm the conversion.
2. Seed freshening under the strict seed ruling (your item structures + misconception sets kept; instances or values changed to clear the freshness scan - 20 of the 27 placed seeds carried must_freshen flags because this is a quant gate and numbers are instances; your pool reuses its own WE/fluency value triples heavily): A#6 values 2.0 g / 1.2 L / 11 L -> 4.0 g / 2.2 L / 23 L; A#8 silver kept, 42.0 g / 4.00 cm3 -> 31.5 g / 3.00 cm3 (answer stays silver's real 10.5); A#10 silver -> palladium 12.0 g/cm3, mass 42.0 -> 48.0 g; A#11 ethanol/water -> turpentine/glycerol, all values fresh; A#12 silver -> rhodium; A#13 aluminum 54.0 g @ 2.70 -> sulfur 24.84 g @ 2.07 and gold 38.6 g @ 19.3 -> iridium 45.12 g @ 22.56; A#19 silver @ 10.5 -> neodymium @ 7.01, every other word verbatim; A#20 7.8 -> iron pair re-picked to 18.8 -> gold, bolt -> medallion; B#6 bale mass 40 -> 65 kg; B#8 50.0 mL / 39.5 g -> 46.0 mL / 52.9 g; B#11 aluminum -> molybdenum, volume and limit re-picked; B#12 ethanol -> saturated saltwater; B#14 stone -> metal padlock, levels 25.0/33.5 -> 18.0/23.5, planted extra-info mass 22.1 -> 33.0 g; B#15 500 g -> 640 g. Say the word if any edit changes your intent.
3. Seed-distractor CONTENT edits beyond instance freshening, both on the row-19 family (MPM-042 gateItems[2]): (1) the seed-family d1 duplicated d2's size-growth misconception once the options were graded as a set - replaced with a mass-vs-density confusion d1 on all five forms including your form-A seed; (2) A#19's d3 keeps your size-blocks-comparison wrong model but drops its absolute 'never' after authoritative cross-vendor QC failed it twice; B-E#19's parallel d3s passed with their own wording, so that fix is form-A-only (asymmetry recorded). Confirm both edits.
4. Reference-figure freshness ruling (A6, new scoped validator lever - default OFF, selftest-probed, G1/G2 reruns byte-identical): on items whose OWN figure is the canonical nine-row density table (seq 16/20/21 on every form), the nine listed substance NAMES are excluded from the cross-form instance-reuse scan - the table is the MPM-043 lesson figure, displayed to every student on every form, and R11 mandates its rows as the bare identification option labels, so the names carry no instance signal there. Measured VALUES still scan in full; unlisted materials scan; non-table items get zero relief. Confirm the ruling.
5. Exact-match identification keys necessarily reproduce taught table tuples at seq 16: C copper @ 8.9, D iron @ 7.9, E silver @ 10.5 (same class as your curated zinc/ethanol targets on forms A/B). Matching a fresh measurement to the taught nine-row table IS the lesson skill, so the keyed tuple is always a taught tuple; the measured m/V data are fresh per form. Confirm this is inherent to the item class, not an instance leak.
6. FRQ seeding: U01-G3 has zero prod_seeds and zero production gate items, so the FRQ (seq 21) was AUTHORED on MPM-043, the capstone workflow lesson: (a) volume by displacement, (b) D = m/V rounded to the correct significant figures with every step shown (5-line calculation scaffold structure, no stage-marker labels), (c) density-table identification justified. Parts ask mL and g/mL so typed answers never need superscripts; part (c) bridges to the table's g/cm3 column via the taught 1 mL = 1 cm3 equivalence. Rubric = 3 observable criteria (30/40/30) summing to 100, one part tag each. Confirm the lesson choice, the g/mL unit convention, and the format.
7. Displacement-read numeric contract (seq 14, MPM-041): the stem carries NO sig-figs sentence - cylinder readings are recorded values (design ruling D2, same recording-convention class as the G2 graduated-cylinder adjudication); graded on value + unit with accepted alternates (e.g. form A's 14 cm3 also accepts '14.0'). Confirm.
8. Escape-hatch options kept as SUBSTANTIVE distractors, not NOTA (V-T5 clean - zero literal None/All-of-the-above in this gate's pool; nothing replaced; the export re-scans): 'None of the metals' on A#20 (your demo_curated exact-match-refusal misconception - a real measurement carries small error, the closest table value identifies), 'No liquid in the table matches' on C#20/D#20, and the seq-18 'nothing can be concluded' reverse-inference option (the targeted misconception). Blind reviewers never picked or rated any of them defensible. Confirm they stand.
9. Your pool[26]-family option d ('two pellets/segments/pieces/sticks/lumps of different sizes can never be compared') is kept across all five row-19 forms for class parity - your approved size-blocks-comparison wrong model, reworded without the absolute on form A only (see the seed-distractor note). Flagging the cross-form reuse of the misconception CLASS (surfaces and substances differ per form) as intended design.

Form A

MPM-034 · easy · recall · seq 1 · seed:U01-G3.pool[0] · mcq4
A jeweler says gold is one of the densest metals. What is the jeweler claiming about gold?
Each cubic centimeter of gold carries more mass than a cubic centimeter of almost any other metal. KEY
Any gold object is heavier than any object made of another metal.
Gold objects take up more space than objects made of other metals with the same mass.
Gold resists scratching better than almost any other metal.
MPM-037 · easy · recall · seq 2 · seed:U01-G3/pool[9] · mcq4
Which sentence reads the equation D = m/V correctly?
A material's density in g/cm³ is its mass in grams divided by its volume in cubic centimeters. KEY
A material's density in g/cm³ is its volume in cubic centimeters divided by its mass in grams.
A material's density in g/cm³ is its mass in grams multiplied by its volume in cubic centimeters.
A material's mass in grams is its density in g/cm³ divided by its volume in cubic centimeters.
MPM-041 · easy · recall · seq 3 · authored · mcq4
A student part-fills a graduated cylinder with liquid and records the level. She then lowers a small ceramic bead into the cylinder, where it settles completely below the surface, and the level climbs to a higher mark. Which statement about the rise in the level is correct?
The rise equals the bead's volume — the level climbed by exactly the space the bead takes up. KEY
The rise is not needed — the final level on its own gives the bead's volume.
The rise gives the bead's mass — a heavier bead of the same size pushes the level up further.
The rise gives the bead's density, because denser beads push the level up further.
MPM-042 · easy · recall · seq 4 · authored · mcq4
A jewelry workshop stores pure platinum stock in many sizes, from tiny findings to a heavy ingot. Which statement about the densities of these platinum pieces is correct?
Every piece has the same density, whatever its size. KEY
The heavy ingot has the highest density, because it contains the most mass.
The heavy ingot has the lowest density, because its mass is spread through more volume.
The densities cannot be predicted — each piece must be measured on its own.
MPM-035 · medium · application · seq 5 · seed:U01-G3.pool[3] (= MPM-035 gateItems[0], James) · mcq4
Two same-size marbles are dropped into a pond. Both have a volume of 3.0 cm³. The glass marble has a mass of 6.9 g and sinks quickly; the plastic marble has a mass of 3.3 g and sinks slowly. Which statement about density is supported?
The glass marble is denser than the plastic marble. KEY
The plastic marble is denser than the glass marble.
The marbles have equal densities.
Nothing about density can be concluded.
MPM-036 · medium · application · seq 6 · seed:U01-G3.pool[6] (must_freshen_instance applied: values 2.0 g/1.2 L/11 L -> 4.0 g/2.2 L/23 L) · mcq4
Two balloons are filled with different gases until each holds exactly 4.0 g of gas. Balloon 1 swells to 2.2 L. Balloon 2 swells to 23 L. Which gas is denser?
The gas in balloon 1 KEY
The gas in balloon 2
Neither gas
It cannot be decided from the given measurements
MPM-037 · medium · application · seq 7 · seed:U01-G3.pool[10] · mcq4
Two samples have the same volume V. Sample 1 has the greater mass m. Using D = m/V, which conclusion follows?
Sample 1 has the greater density, because a greater m over the same V gives a greater D. KEY
Sample 1 has the smaller density, because more mass weighs the ratio down.
The densities are equal, because V is the same for both.
No conclusion follows without the actual numbers.
MPM-038 · medium · application · seq 8 · seed:pool[12] (= MPM-038 gateItems[0], James) - value swap 42.0 g / 4.00 cm³ -> 31.5 g / 3.00 cm³ per must_freshen_instance (placement's suggested pair); converted to numeric ENTRY per interaction_conversion; scenario, misconception clauses, scaffold, and sense line otherwise VERBATIM · numeric
A silver bar has a mass of 31.5 g and a volume of 3.00 cm³. Calculate its density, in g/cm³, to 3 significant figures.
Answer: 10.5 g/cm³ KEY
also accepted: 10.5 g/cm³
wrongValueDiagnostics
[
 {
  "value": 0.0952,
  "misconception": "you divided the volume by the mass instead of the mass by the volume",
  "feedback": null
 },
 {
  "value": 94.5,
  "misconception": "you multiplied the mass by the volume instead of dividing",
  "feedback": null
 },
 {
  "value": 1.05,
  "misconception": "you slipped the decimal point one place",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nm = 31.5 g\nV = 3.00 cm³\nWrite down the equation:\nD = m / V\nSubstitute in the values, and calculate:\nD = 31.5 / 3.00\nD = 10.5 g/cm³\nMore than 10 g packed into each cubic centimeter fits a dense metal; 0.0952 comes from flipping the division (V/m) — a tenth of water's density, impossible for a solid metal bar, which fails the sense check."
}
MPM-038 · medium · application · seq 9 · seed:U01-G3/pool[13] · mcq4
Sample A has a mass of 35.2 g and a volume of 16.0 cm³. Sample B has a mass of 28.6 g and a volume of 11.0 cm³. Which sample has the greater density?
Sample B — 2.60 g/cm³ compared with 2.20 g/cm³. KEY
Sample A — 2.20 g/cm³ is the greater density.
Sample A — its mass, 35.2 g, is the greater.
Sample A — 0.455 g/cm³ compared with 0.385 g/cm³.
MPM-039 · medium · application · seq 10 · seed:U01-G3.pool[15] (James's MPM-039 gate item) - must_freshen_instance applied (silver -> palladium 12.0 g/cm³, 42.0 -> 48.0 g; V 4.00 cm³ kept); converted to numeric ENTRY per the HS rule; structure otherwise verbatim · numeric
A jeweler needs the mass of a 4.00 cm³ palladium casting. Palladium's density is 12.0 g/cm³. What is the casting's mass, in grams? Give your answer to 3 significant figures.
Answer: 48.0 g KEY
wrongValueDiagnostics
[
 {
  "value": 0.333,
  "misconception": "you divided the volume by the density instead of multiplying them",
  "feedback": null
 },
 {
  "value": 3.0,
  "misconception": "you divided the density by the volume instead of multiplying them",
  "feedback": null
 },
 {
  "value": 16.0,
  "misconception": "you added the density to the volume instead of multiplying them",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nD = 12.0 g/cm³\nV = 4.00 cm³\nWrite down the equation:\nD = m / V\nMake m the subject:\nm = D × V\nSubstitute in the values, and calculate:\nm = 12.0 × 4.00\nm = 48.0 g\nEach cubic centimeter of palladium carries 12.0 g, and the casting holds four of them — the mass must exceed 12.0 g, so 0.333 g and 3.00 g fail the sense check."
}
MPM-039 · medium · application · seq 11 · seed:U01-G3/pool[16] (structure+misconceptions kept; instance freshened per must_freshen_instance: ethanol/water -> turpentine/glycerol, all values fresh) · mcq4
Beaker 1 holds 200.0 cm³ of turpentine (density 0.870 g/cm³). Beaker 2 holds 120.0 cm³ of glycerol (density 1.26 g/cm³). Which liquid has the greater mass?
The turpentine — 174 g compared with 151 g. KEY
The glycerol — 151 g compared with 174 g.
The glycerol — its density, 1.26 g/cm³, beats 0.870 g/cm³.
The turpentine — 230 g compared with 151 g.
MPM-040 · medium · application · seq 12 · seed:U01-G3.pool[18] (= MPM-040 gateItems[0], James) - converted mcq->numeric per HS rule; instance freshened (silver->rhodium) · numeric
A metal refiner melts down 18.6 g of rhodium (density 12.4 g/cm³) and pours it into a mold. What volume will the cooled, solid casting occupy? Give your answer to 3 significant figures.
Answer: 1.5 cm³ KEY
also accepted: 1.50 cm³, 1.50 cm3
scaffold
[
 "Write down the values in the question:",
 "D = 12.4 g/cm³",
 "m = 18.6 g",
 "Write down the equation:",
 "D = m / V",
 "Make V the subject:",
 "V = m / D",
 "Substitute in the values, and calculate:",
 "V = 18.6 / 12.4",
 "V = 1.50 cm³"
]
wrongValueDiagnostics
[
 {
  "value": 230.64,
  "misconception": "you multiplied the mass by the density instead of dividing",
  "feedback": "This answer is wrong — you multiplied the mass by the density instead of dividing. Rhodium packs 12.4 g into each cubic centimeter, so divide the mass by the density: V = 18.6 / 12.4 = 1.50 cm³ — a 230.64 cm³ mold — over a hundred and fifty times too large — fails the sense check."
 },
 {
  "value": 0.667,
  "misconception": "you divided the density by the mass instead of the mass by the density",
  "feedback": "This answer is wrong — you divided the density by the mass instead of the mass by the density. Make V the subject of D = m/V: V = m / D = 18.6 / 12.4 = 1.50 cm³."
 },
 {
  "value": 15.0,
  "misconception": "you slipped the decimal point one place",
  "feedback": "This answer is wrong — you slipped the decimal point one place. Each cubic centimeter of rhodium already holds 12.4 g, so 18.6 g needs only 1.50 cm³, not 15.0 cm³."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nD = 12.4 g/cm³\nm = 18.6 g\nWrite down the equation:\nD = m / V\nMake V the subject:\nV = m / D\nSubstitute in the values, and calculate:\nV = 18.6 / 12.4\nV = 1.50 cm³\nRhodium packs 12.4 g into every cubic centimeter, so 18.6 g fills only one and a half of them — 230.64 cm³ would be more than a hundred and fifty times the metal's real volume, which fails the sense check.",
 "anticipatedWrong": [
  {
   "value": 230.64,
   "misconception": "you multiplied the mass by the density instead of dividing",
   "feedback": "This answer is wrong — you multiplied the mass by the density instead of dividing. Rhodium packs 12.4 g into each cubic centimeter, so divide the mass by the density: V = 18.6 / 12.4 = 1.50 cm³ — a 230.64 cm³ mold — over a hundred and fifty times too large — fails the sense check."
  },
  {
   "value": 0.667,
   "misconception": "you divided the density by the mass instead of the mass by the density",
   "feedback": "This answer is wrong — you divided the density by the mass instead of the mass by the density. Make V the subject of D = m/V: V = m / D = 18.6 / 12.4 = 1.50 cm³."
  },
  {
   "value": 15.0,
   "misconception": "you slipped the decimal point one place",
   "feedback": "This answer is wrong — you slipped the decimal point one place. Each cubic centimeter of rhodium already holds 12.4 g, so 18.6 g needs only 1.50 cm³, not 15.0 cm³."
  }
 ]
}
MPM-040 · medium · application · seq 13 · seed:U01-G3.pool[20] (= MPM-040 gateItems[2], James; must_freshen_instance + freshness_same_lesson applied: aluminum 54.0 g @2.70 -> sulfur 24.84 g @2.07, gold 38.6 g @19.3 -> iridium 45.12 g @22.56; structure + option classes kept) · mcq4
A specimen tray holds 24.84 g of sulfur (density 2.07 g/cm³) and 45.2 g of iridium (density 22.6 g/cm³). Which sample takes up more space?
The sulfur — 12.0 cm³ compared with 2.00 cm³. KEY
The iridium — 2.00 cm³ compared with 12.0 cm³.
The iridium — its density, 22.6 g/cm³, is far greater.
The iridium — 1022 cm³ compared with 51.4 cm³.
MPM-041 · medium · application · seq 14 · seed:U01-G3.pool[21] VERBATIM (MPM-041 gateItems[0]; clean seed, zero stage-1 flags; formatting-only adaptations logged in flags) · numeric
The figure shows a large graduated cylinder, marked every 2 mL, before and after a chunk of quartz is lowered in. Read both levels and calculate the quartz's volume, in cm³.
FIGURE (displacement-before-after · stimulus) — scaleMin: 50 · scaleMax: 80 · unit: "mL" · markEvery: 2 · labeledMarks: [50, 60, 70, 80] · beforeLevel: 60 · afterLevel: 74 · object: "quartz chunk" · style: "two identical wide cylinders side by side, object fully submerged in the after panel" · values: "scale window 50–80 mL, labels at 50, 60, 70, 80, one mark every 2 mL; BEFORE panel: water level exactly on the labeled 60 mL mark; AFTER panel: quartz chunk…
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "displacement-before-after",
  "scaleMin": 50,
  "scaleMax": 80,
  "unit": "mL",
  "markEvery": 2,
  "labeledMarks": [
   50,
   60,
   70,
   80
  ],
  "beforeLevel": 60,
  "afterLevel": 74,
  "object": "quartz chunk",
  "style": "two identical wide cylinders side by side, object fully submerged in the after panel",
  "values": "scale window 50–80 mL, labels at 50, 60, 70, 80, one mark every 2 mL; BEFORE panel: water level exactly on the labeled 60 mL mark; AFTER panel: quartz chunk fully submerged, water level on the mark two gradations above 70 (74 mL)"
 }
}
Answer: 14 cm³ KEY
also accepted: 14 cm³, 14 cm3, 14.0
scaffold
[
 "Check the scale first: the labels step from 50 to 60 across five marks, so each mark is 2 mL.",
 "Read the values from the figure:",
 "starting level = 60 mL",
 "final level = 74 mL",
 "Write down the equation:",
 "V = final level − starting level",
 "Substitute in the values, and calculate:",
 "V = 74 − 60",
 "V = 14 cm³"
]
wrongValueDiagnostics
[
 {
  "value": 7,
  "misconception": "you assumed the marks step by 1 mL — on this cylinder each mark is 2 mL",
  "feedback": "This answer is wrong — you assumed the marks step by 1 mL. Check the scale first: the labels step from 50 to 60 across five marks, so each mark is 2 mL, and V = 74 − 60 = 14 cm³."
 },
 {
  "value": 74,
  "misconception": "you reported the final reading instead of the rise in level",
  "feedback": "This answer is wrong — you reported the final reading instead of the rise in level. The final reading is only where the water now stands; the quartz's volume is the rise: V = 74 − 60 = 14 cm³."
 },
 {
  "value": 134,
  "misconception": "you added the two readings instead of subtracting",
  "feedback": "This answer is wrong — you added the two readings instead of subtracting. The volume is the rise in the level: V = 74 − 60 = 14 cm³."
 }
]
feedback
{
 "keyExplanation": "Check the scale first: the labels step from 50 to 60 across five marks, so each mark is 2 mL.\nRead the values from the figure:\nstarting level = 60 mL\nfinal level = 74 mL\nWrite down the equation:\nV = final level − starting level\nSubstitute in the values, and calculate:\nV = 74 − 60\nV = 14 cm³",
 "anticipatedWrong": [
  {
   "value": 7,
   "misconception": "you assumed the marks step by 1 mL — on this cylinder each mark is 2 mL",
   "feedback": "This answer is wrong — you assumed the marks step by 1 mL. Check the scale first: the labels step from 50 to 60 across five marks, so each mark is 2 mL, and V = 74 − 60 = 14 cm³."
  },
  {
   "value": 74,
   "misconception": "you reported the final reading instead of the rise in level",
   "feedback": "This answer is wrong — you reported the final reading instead of the rise in level. The final reading is only where the water now stands; the quartz's volume is the rise: V = 74 − 60 = 14 cm³."
  },
  {
   "value": 134,
   "misconception": "you added the two readings instead of subtracting",
   "feedback": "This answer is wrong — you added the two readings instead of subtracting. The volume is the rise in the level: V = 74 − 60 = 14 cm³."
  }
 ]
}
MPM-042 · medium · application · seq 15 · seed:U01-G3.pool[24] (= MPM-042 gateItems[0], James) - used VERBATIM · mcq4
Sample B of a pure liquid has twice the mass of sample A of the same liquid. A student claims sample B's density is therefore twice as large. Why is the claim wrong?
Twice the mass of the same liquid fills twice the volume, so m/V is unchanged. KEY
The claim is right — doubling the top of m/V doubles the result.
The claim is wrong because liquids have no fixed density.
The claim is wrong because density halves when the mass doubles.
MPM-043 · medium · application · seq 16 · seed:U01-G3.pool[27] (= MPM-043 gateItems[0] = demo_curated[0], James) · mcq4
An irregular chunk of metal has a mass of 21.3 g. When the chunk is placed in a graduated cylinder of water, the level rises from 31.0 mL to 34.0 mL. Use the density table to identify the metal.
FIGURE (density-reference-table · stimulus) — rows: [["ethanol", "0.79"], ["water", "1.00"], ["aluminum", "2.70"], ["zinc", "7.1"], ["iron", "7.9"], ["copper", "8.9"], ["silver", "10.5"], ["lead", "11.3"], ["g… · unitsNote: "density in g/cm³ at room temperature" · style: "same reference table as the lesson figure"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "density-reference-table",
  "rows": [
   [
    "ethanol",
    "0.79"
   ],
   [
    "water",
    "1.00"
   ],
   [
    "aluminum",
    "2.70"
   ],
   [
    "zinc",
    "7.1"
   ],
   [
    "iron",
    "7.9"
   ],
   [
    "copper",
    "8.9"
   ],
   [
    "silver",
    "10.5"
   ],
   [
    "lead",
    "11.3"
   ],
   [
    "gold",
    "19.3"
   ]
  ],
  "unitsNote": "density in g/cm³ at room temperature",
  "style": "same reference table as the lesson figure"
 }
}
Zinc KEY
Iron
Ethanol
Gold
MPM-035 · hard · transfer · seq 17 · seed:U01-G3.pool[5] (= MPM-035 gateItems[2], James) · mcq4
Two full tanks have identical volumes. Tank 1 holds a gas and has 0.6 kg more mass than when empty. Tank 2 holds a different gas and has 1.5 kg more mass than when empty. Which gas is denser inside its tank?
The gas in tank 2 KEY
The gas in tank 1
Neither gas
It cannot be decided from the given measurements
MPM-036 · hard · transfer · seq 18 · seed:U01-G3.pool[8] · mcq4
Sample P and sample Q have equal masses. Sample P has the greater density. Which statement about their volumes must be true?
Sample P occupies less volume than sample Q. KEY
Sample P occupies more volume than sample Q.
The volumes are equal, since the masses are equal.
Nothing about the volumes can be concluded.
MPM-042 · hard · transfer · seq 19 · seed:U01-G3.pool[26] (= MPM-042 gateItems[2], James) - must_freshen_instance APPLIED (silver -> neodymium, 10.5 -> 7.01 g/cm3), otherwise VERBATIM (HTML stripped) · mcq4
A quality inspector checks whether a shipment of metal pellets is pure neodymium by measuring the density of one small pellet and of one large pellet. Both measure 7.01 g/cm³. Why does testing two different sizes make the check stronger?
A single substance gives the same density at every size, so agreement across sizes is what pure neodymium predicts. KEY
It is not stronger — a fair check would compare two pellets of the same size, so using different sizes actually weakens it.
The check works because the large pellet should show a higher density if the metal is pure.
The check is flawed — the two pellets' masses and volumes are all different, so their densities cannot be compared.
MPM-043 · hard · transfer · seq 20 · seed:U01-G3.pool[29] (= MPM-043 gateItems[2] = demo_curated[2], James) - must_freshen_instance APPLIED (7.8->iron pair re-picked to 18.8->gold; bolt->medallion; all values fresh), structure and refusal misconception kept · mcq4
A medallion has a mass of 188.0 g. Lowered into a graduated cylinder, it raises the water level from 43.5 mL to 53.5 mL. Use the density table to decide which metal the medallion most likely is.
FIGURE (density-reference-table · stimulus) — rows: [["ethanol", "0.79"], ["water", "1.00"], ["aluminum", "2.70"], ["zinc", "7.1"], ["iron", "7.9"], ["copper", "8.9"], ["silver", "10.5"], ["lead", "11.3"], ["g… · unitsNote: "density in g/cm³ at room temperature" · style: "same reference table as the lesson figure" · table: "Two-column reference table, 'Densities of common substances (room temperature)' — Substance / Density (g/cm³): ethanol 0.79; water 1.00; aluminum 2.70; zinc…
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "density-reference-table",
  "rows": [
   [
    "ethanol",
    "0.79"
   ],
   [
    "water",
    "1.00"
   ],
   [
    "aluminum",
    "2.70"
   ],
   [
    "zinc",
    "7.1"
   ],
   [
    "iron",
    "7.9"
   ],
   [
    "copper",
    "8.9"
   ],
   [
    "silver",
    "10.5"
   ],
   [
    "lead",
    "11.3"
   ],
   [
    "gold",
    "19.3"
   ]
  ],
  "unitsNote": "density in g/cm³ at room temperature",
  "style": "same reference table as the lesson figure",
  "table": "Two-column reference table, 'Densities of common substances (room temperature)' — Substance / Density (g/cm³): ethanol 0.79; water 1.00; aluminum 2.70; zinc 7.1; iron 7.9; copper 8.9; silver 10.5; lead 11.3; gold 19.3"
 }
}
Gold KEY
Lead
Silver
None of the metals
MPM-043 · medium · application · seq 21 · authored (U01-G3 has zero gate prods / prod_seeds — blueprint directs an authored capstone-workflow FRQ from MPM-043) · frq
A plumber sorting a scrap bin finds an irregular metal pipe fitting and wants to know what metal it is. On the balance, the fitting's mass is 71.2 g. Lowered into a graduated cylinder of water, the fitting raises the water level from 21.5 mL to 29.5 mL.
FIGURE (density-reference-table · stimulus) — title: "Densities of common substances (room temperature)" · columns: ["Substance", "Density (g/cm³)"] · rows: [["ethanol", "0.79"], ["water", "1.00"], ["aluminum", "2.70"], ["zinc", "7.1"], ["iron", "7.9"], ["copper", "8.9"], ["silver", "10.5"], ["lead", "11.3"], ["g… · unitsNote: "density in g/cm³ at room temperature" · style: "same reference table as the lesson figure" · aria: "A two-column reference table listing nine substances and their densities in grams per cubic centimeter, from ethanol at 0.79 to gold at 19.3"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "density-reference-table",
  "title": "Densities of common substances (room temperature)",
  "columns": [
   "Substance",
   "Density (g/cm³)"
  ],
  "rows": [
   [
    "ethanol",
    "0.79"
   ],
   [
    "water",
    "1.00"
   ],
   [
    "aluminum",
    "2.70"
   ],
   [
    "zinc",
    "7.1"
   ],
   [
    "iron",
    "7.9"
   ],
   [
    "copper",
    "8.9"
   ],
   [
    "silver",
    "10.5"
   ],
   [
    "lead",
    "11.3"
   ],
   [
    "gold",
    "19.3"
   ]
  ],
  "unitsNote": "density in g/cm³ at room temperature",
  "style": "same reference table as the lesson figure",
  "aria": "A two-column reference table listing nine substances and their densities in grams per cubic centimeter, from ethanol at 0.79 to gold at 19.3"
 }
}
A plumber sorting a scrap bin finds an irregular metal pipe fitting and wants to know what metal it is. On the balance, the fitting's mass is 71.2 g. Lowered into a graduated cylinder of water, the fitting raises the water level from 21.5 mL to 29.5 mL. (a) Calculate the fitting's volume, in mL. (b) Calculate the fitting's density, in g/mL, rounded to the correct number of significant figures. Show every step of your calculation. (c) Use the density table to identify the metal, and justify your identification in one or two sentences. (1 mL = 1 cm³, so a density in g/mL matches the table's g/cm³ column directly.)
Part a. Calculate the fitting's volume, in mL.
Model: The fitting's volume is the rise in the water level, not the final reading. V = 29.5 − 21.5 V = 8.0 mL
Part b. Calculate the fitting's density, in g/mL, rounded to the correct number of significant figures. Show every step of your calculation.
Model: m = 71.2 g V = 8.0 mL (from part a) D = m / V D = 71.2 / 8.0 D = 8.9 g/mL Rounding: the least precise measurement, 8.0 mL, has 2 significant figures, so the density is reported as 8.9 g/mL.
Part c. Use the density table to identify the metal, and justify your identification in one or two sentences. (1 mL = 1 cm³, so a density in g/mL matches the table's g/cm³ column directly.)
Model: One milliliter is the same space as one cubic centimeter, so a density in g/mL reads against the table directly. The measured 8.9 g/mL matches copper's table value, 8.9. Every sample of one substance has the same density whatever the sample's size, so the fitting is copper.
Full model answer. (a) The fitting's volume is the rise in the water level, not the final reading. V = 29.5 − 21.5 V = 8.0 mL (b) m = 71.2 g V = 8.0 mL (from part a) D = m / V D = 71.2 / 8.0 D = 8.9 g/mL Rounding: the least precise measurement, 8.0 mL, has 2 significant figures, so the density is reported as 8.9 g/mL. (c) One milliliter is the same space as one cubic centimeter, so a density in g/mL reads against the table directly. The measured 8.9 g/mL matches copper's table value, 8.9. Every sample of one substance has the same density whatever the sample's size, so the fitting is copper.

Form B

MPM-034 · easy · recall · seq 1 · authored · mcq4
A chemistry teacher holds up a small sealed vial and says bromine is one of the densest liquids in the laboratory. What is the teacher claiming about bromine?
Each cubic centimeter of bromine carries more mass than a cubic centimeter of almost any other liquid. KEY
Any container of bromine has more mass than any container filled with a different liquid.
Bromine takes up more space than the same mass of almost any other liquid in the laboratory.
Bromine freezes at a lower temperature than almost any other liquid in the laboratory.
MPM-037 · easy · recall · seq 2 · authored · mcq4
In D = m/V, which quantity does the symbol V represent, and in what unit is it measured?
The volume, in cubic centimeters. KEY
The mass, in grams.
The density, in grams per cubic centimeter.
The volume, in grams.
MPM-041 · easy · recall · seq 3 · authored · mcq4
A technician pours some liquid into a graduated cylinder and notes where the level sits. He then lowers a small metal washer into the cylinder until no part of it stays above the surface, and the level moves up to a new mark. Which statement about the rise in the level is correct?
The rise equals the washer's volume — the level moved up by exactly the space the washer takes up. KEY
The rise is not needed — the final level on its own gives the washer's volume.
The rise gives the washer's mass — a heavier washer of the same size pushes the level up further.
The rise gives the washer's density, because denser washers push the level up further.
MPM-042 · easy · recall · seq 4 · authored · mcq4
A plating supplier sells pure nickel in many sizes, from thin strips to heavy anodes. Which statement about the densities of the nickel pieces is correct?
Every piece of nickel has the same density, whatever its size. KEY
The heavy anodes have the highest densities, because they hold the most mass.
The thin strips have the highest densities, because their mass sits in less space.
The supplier cannot state one density — it depends on which piece is measured.
MPM-035 · medium · application · seq 5 · seed:U01-G3.pool[4] (= MPM-035 gateItems[1], James) · mcq4
A geologist has two same-size rock samples, each 26.0 cm³. Sample 1 reads 67.5 g on the balance. Sample 2 reads 80.0 g. The geologist concludes sample 2 is made of denser rock. Why is the conclusion sound?
The volumes were held equal, so the mass difference can only reflect the rocks' packing. KEY
It is not sound — the samples would need equal masses before comparing.
It is not sound — density cannot be compared without weighing the rocks underwater.
It is sound only if the two rocks are the same kind of rock.
MPM-036 · medium · application · seq 6 · seed:U01-G3.pool[7] (must_freshen_instance applied: bale mass 40 kg -> 65 kg; aluminum kept per stage-1 adjudication) · mcq4
A recycling plant receives two bales, each with a mass of 65 kg. The crushed-aluminum bale is much smaller than the mixed-plastic bale. A worker claims the crushed-aluminum bale is denser than the mixed-plastic bale. What makes the claim sound?
The masses are equal, so the smaller bale packs that mass into less volume. KEY
Nothing — bale sizes say nothing about density.
The claim needs the two volumes to be equal before comparing.
The claim is sound only if the two bales came from the same recycling batch.
MPM-037 · medium · application · seq 7 · seed:U01-G3.pool[11] · mcq4
Two samples have the same mass m. Sample 1 has the smaller volume V. Using D = m/V, which conclusion follows?
Sample 1 has the greater density, because the same m over a smaller V gives a greater D. KEY
Sample 1 has the smaller density, because a smaller volume holds less material.
The densities are equal, because m is the same for both.
Sample 1 has the greater mass, because density and mass rise together.
MPM-038 · medium · application · seq 8 · seed:pool[14] (= MPM-038 gateItems[2], James) - value swap 50.0 mL / 39.5 g -> 46.0 mL / 52.9 g per must_freshen_instance; converted to numeric ENTRY per interaction_conversion; scenario, bridge parenthetical, misconception clauses, scaffold shape, and sense-line pattern otherwise VERBATIM · numeric
A graduated cylinder shows that a liquid sample has a volume of 46.0 mL, and the balance gives its mass as 52.9 g. Calculate the liquid's density, in g/cm³, to 3 significant figures. (1 mL = 1 cm³)
Answer: 1.15 g/cm³ KEY
also accepted: 1.15 g/cm³, 1.15 g/mL
wrongValueDiagnostics
[
 {
  "value": 0.87,
  "misconception": "you divided the volume by the mass instead of the mass by the volume",
  "feedback": null
 },
 {
  "value": 2433.4,
  "misconception": "you multiplied the mass by the volume instead of dividing",
  "feedback": null
 },
 {
  "value": 11.5,
  "misconception": "you slipped the decimal point one place",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nm = 52.9 g\nV = 46.0 mL = 46.0 cm³\nWrite down the equation:\nD = m / V\nSubstitute in the values, and calculate:\nD = 52.9 / 46.0\nD = 1.15 g/cm³\nA density slightly above 1 g/cm³ fits a pourable liquid; the mass 52.9 g and the volume 46.0 cm³ are close in size, so the density must land close to 1 g/cm³ — a value ten times larger flags a slipped decimal point."
}
MPM-038 · medium · application · seq 9 · authored · mcq4
A materials-testing bench holds two solid cubes made of different materials. Cube 1 has a mass of 41.6 g and a volume of 13.0 cm³. Cube 2 has a mass of 28.8 g and a volume of 8.0 cm³. Which cube has the greater density?
Cube 2 — 3.6 g/cm³ compared with 3.20 g/cm³. KEY
Cube 1 — 3.20 g/cm³ is the greater density.
Cube 1 — its mass, 41.6 g, is the greater.
Cube 1 — 0.313 g/cm³ compared with 0.28 g/cm³.
MPM-039 · medium · application · seq 10 · authored · numeric
A laboratory technician measures out 45.0 mL of concentrated sulfuric acid (density 1.84 g/cm³) for a dilution. (1 mL = 1 cm³) What is the mass of the acid, in grams? Give your answer to 3 significant figures.
Answer: 82.8 g KEY
wrongValueDiagnostics
[
 {
  "value": 24.5,
  "misconception": "you divided the volume by the density instead of multiplying them",
  "feedback": null
 },
 {
  "value": 0.0409,
  "misconception": "you divided the density by the volume instead of multiplying them",
  "feedback": null
 },
 {
  "value": 46.8,
  "misconception": "you added the density to the volume instead of multiplying them",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nD = 1.84 g/cm³\nV = 45.0 mL = 45.0 cm³\nWrite down the equation:\nD = m / V\nMake m the subject:\nm = D × V\nSubstitute in the values, and calculate:\nm = 1.84 × 45.0\nm = 82.8 g\nEach cubic centimeter of the acid carries 1.84 g, and the sample holds forty-five of them — the mass must exceed 1.84 g, so 0.0409 g fails the sense check."
}
MPM-039 · medium · application · seq 11 · seed:U01-G3/pool[17] (structure+misconceptions kept; instance freshened per must_freshen_instance: aluminum -> molybdenum, V and limit re-picked, furnace surface for realism) · mcq4
A molybdenum furnace part must not exceed 150.0 g. The design has a volume of 14.0 cm³, and molybdenum's density is 10.2 g/cm³. What is the part's mass, and does it meet the limit?
143 g — the part meets the 150.0 g limit. KEY
1.37 g — the part meets the limit easily.
0.729 g — the part meets the limit easily.
1428 g — the part is far over the limit.
MPM-040 · medium · application · seq 12 · seed:U01-G3.pool[19] (= MPM-040 gateItems[1], James) - converted mcq->numeric per HS rule; instance freshened (ethanol->saturated saltwater) · numeric
A lab bottle must hold 23.4 g of saturated saltwater (density 1.20 g/cm³). What is the smallest bottle volume that fits the sample? Give your answer to 3 significant figures.
Answer: 19.5 cm³ KEY
also accepted: 19.5 cm³, 19.5 cm3
scaffold
[
 "Write down the values in the question:",
 "D = 1.20 g/cm³",
 "m = 23.4 g",
 "Write down the equation:",
 "D = m / V",
 "Make V the subject:",
 "V = m / D",
 "Substitute in the values, and calculate:",
 "V = 23.4 / 1.20",
 "V = 19.5 cm³"
]
wrongValueDiagnostics
[
 {
  "value": 28.08,
  "misconception": "you multiplied the mass by the density instead of dividing",
  "feedback": "This answer is wrong — you multiplied the mass by the density instead of dividing. The saltwater packs 1.20 g into each cubic centimeter, so divide: V = 23.4 / 1.20 = 19.5 cm³ — the volume in cm³ must come out smaller than the mass in grams."
 },
 {
  "value": 0.0513,
  "misconception": "you divided the density by the mass instead of the mass by the density",
  "feedback": "This answer is wrong — you divided the density by the mass instead of the mass by the density. Make V the subject of D = m/V: V = m / D = 23.4 / 1.20 = 19.5 cm³ — a bottle of 0.0513 cm³ is nowhere near the 19.5 cm³ that 23.4 g of saltwater actually needs."
 },
 {
  "value": 195,
  "misconception": "you slipped the decimal point one place",
  "feedback": "This answer is wrong — you slipped the decimal point one place. Dividing 23.4 by 1.20 gives 19.5 cm³, not 195 cm³ — the saltwater is denser than pure water, so its volume in cm³ must be smaller than its 23.4 g mass."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nD = 1.20 g/cm³\nm = 23.4 g\nWrite down the equation:\nD = m / V\nMake V the subject:\nV = m / D\nSubstitute in the values, and calculate:\nV = 23.4 / 1.20\nV = 19.5 cm³\nSaturated saltwater packs 1.20 g into each cubic centimeter, so the volume in cm³ must come out smaller than the mass in grams — 19.5 cm³ passes that check; 28.08 cm³ does not.",
 "anticipatedWrong": [
  {
   "value": 28.08,
   "misconception": "you multiplied the mass by the density instead of dividing",
   "feedback": "This answer is wrong — you multiplied the mass by the density instead of dividing. The saltwater packs 1.20 g into each cubic centimeter, so divide: V = 23.4 / 1.20 = 19.5 cm³ — the volume in cm³ must come out smaller than the mass in grams."
  },
  {
   "value": 0.0513,
   "misconception": "you divided the density by the mass instead of the mass by the density",
   "feedback": "This answer is wrong — you divided the density by the mass instead of the mass by the density. Make V the subject of D = m/V: V = m / D = 23.4 / 1.20 = 19.5 cm³ — a bottle of 0.0513 cm³ is nowhere near the 19.5 cm³ that 23.4 g of saltwater actually needs."
  },
  {
   "value": 195,
   "misconception": "you slipped the decimal point one place",
   "feedback": "This answer is wrong — you slipped the decimal point one place. Dividing 23.4 by 1.20 gives 19.5 cm³, not 195 cm³ — the saltwater is denser than pure water, so its volume in cm³ must be smaller than its 23.4 g mass."
  }
 ]
}
MPM-040 · medium · application · seq 13 · authored · mcq4
Jug 1 holds 79.92 g of ethylene glycol (density 1.11 g/cm³). Jug 2 holds 69.0 g of olive oil (density 0.920 g/cm³). Which liquid takes up more space?
The olive oil — 75.0 cm³ compared with 72.0 cm³. KEY
The ethylene glycol — 72.0 cm³ compared with 75.0 cm³.
The ethylene glycol — its density, 1.11 g/cm³, is greater.
The ethylene glycol — 88.7 cm³ compared with 63.5 cm³.
MPM-041 · medium · application · seq 14 · seed:U01-G3.pool[22] (MPM-041 gateItems[1]) - must_freshen_instance EXECUTED: stone -> metal padlock, levels 25.0/33.5 -> 18.0/23.5, planted mass 22.1 -> 33.0 g; structure and misconception classes verbatim (see flags) · numeric
A small metal padlock with a mass of 33.0 g is lowered into the cylinder shown in the figure. Read the two levels and calculate the volume of the padlock, in cm³.
FIGURE (displacement-before-after · stimulus) — scaleMin: 15 · scaleMax: 30 · unit: "mL" · markEvery: 1 · labeledMarks: [15, 20, 25, 30] · beforeLevel: 18.0 · afterLevel: 23.5 · object: "small metal padlock" · style: "two identical cylinders side by side, object fully submerged in the after panel, no level values printed as text outside the scale" · values: "scale window 15–30 mL, labels at 15, 20, 25, 30, one mark every 1 mL; BEFORE panel: water level exactly on the mark three gradations above 15 (18.0 mL); AFT…
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "displacement-before-after",
  "scaleMin": 15,
  "scaleMax": 30,
  "unit": "mL",
  "markEvery": 1,
  "labeledMarks": [
   15,
   20,
   25,
   30
  ],
  "beforeLevel": 18.0,
  "afterLevel": 23.5,
  "object": "small metal padlock",
  "style": "two identical cylinders side by side, object fully submerged in the after panel, no level values printed as text outside the scale",
  "values": "scale window 15–30 mL, labels at 15, 20, 25, 30, one mark every 1 mL; BEFORE panel: water level exactly on the mark three gradations above 15 (18.0 mL); AFTER panel: padlock fully submerged, water level halfway between the marks three and four gradations above 20 (23.5 mL)"
 }
}
Answer: 5.5 cm³ KEY
also accepted: 5.5 cm³, 5.5 cm3
scaffold
[
 "The mass is extra information — the volume comes from the water levels alone.",
 "Read the values from the figure:",
 "starting level = 18.0 mL",
 "final level = 23.5 mL",
 "Write down the equation:",
 "V = final level − starting level",
 "Substitute in the values, and calculate:",
 "V = 23.5 − 18.0",
 "V = 5.5 cm³"
]
wrongValueDiagnostics
[
 {
  "value": 33.0,
  "misconception": "you brought the padlock's mass into the volume calculation — the volume comes from the two water levels alone",
  "feedback": "This answer is wrong — you brought the padlock's mass into the volume calculation. The mass is extra information; the volume comes from the two water levels alone: V = 23.5 − 18.0 = 5.5 cm³."
 },
 {
  "value": 23.5,
  "misconception": "you reported the final reading instead of the rise in level",
  "feedback": "This answer is wrong — you reported the final reading instead of the rise in level. The final reading is only where the water now stands; the padlock's volume is the rise: V = 23.5 − 18.0 = 5.5 cm³."
 },
 {
  "value": 41.5,
  "misconception": "you added the two readings instead of subtracting",
  "feedback": "This answer is wrong — you added the two readings instead of subtracting. The volume is the rise in the level: V = 23.5 − 18.0 = 5.5 cm³."
 }
]
feedback
{
 "keyExplanation": "The mass is extra information — the volume comes from the water levels alone.\nRead the values from the figure:\nstarting level = 18.0 mL\nfinal level = 23.5 mL\nWrite down the equation:\nV = final level − starting level\nSubstitute in the values, and calculate:\nV = 23.5 − 18.0\nV = 5.5 cm³\nThe levels are read in milliliters, and one milliliter is one cubic centimeter, so the volume comes out in cm³.",
 "anticipatedWrong": [
  {
   "value": 33.0,
   "misconception": "you brought the padlock's mass into the volume calculation — the volume comes from the two water levels alone",
   "feedback": "This answer is wrong — you brought the padlock's mass into the volume calculation. The mass is extra information; the volume comes from the two water levels alone: V = 23.5 − 18.0 = 5.5 cm³."
  },
  {
   "value": 23.5,
   "misconception": "you reported the final reading instead of the rise in level",
   "feedback": "This answer is wrong — you reported the final reading instead of the rise in level. The final reading is only where the water now stands; the padlock's volume is the rise: V = 23.5 − 18.0 = 5.5 cm³."
  },
  {
   "value": 41.5,
   "misconception": "you added the two readings instead of subtracting",
   "feedback": "This answer is wrong — you added the two readings instead of subtracting. The volume is the rise in the level: V = 23.5 − 18.0 = 5.5 cm³."
  }
 ]
}
MPM-042 · medium · application · seq 15 · seed:U01-G3.pool[25] (= MPM-042 gateItems[1], James) - must_freshen_instance APPLIED (500 g -> 640 g), otherwise VERBATIM · mcq4
Two sealed boxes each hold 640 g of material. A student says the contents must be the same substance because the masses match. What is the flaw in the reasoning?
Any substance can come as a 640 g sample — matching masses say nothing about identity; matching densities would. KEY
There is no flaw — equal masses of pure materials mean the same substance.
The flaw is that the boxes should hold equal volumes instead — equal volumes would prove identity.
The flaw is that mass cannot be measured through a sealed box.
MPM-043 · medium · application · seq 16 · seed:U01-G3.pool[28] (= MPM-043 gateItems[1] = demo_curated[1], James) · mcq4
A 12.0 mL sample of a clear, colorless liquid has a mass of 9.48 g. Use the density table to identify the liquid.
FIGURE (density-reference-table · stimulus) — rows: [["ethanol", "0.79"], ["water", "1.00"], ["aluminum", "2.70"], ["zinc", "7.1"], ["iron", "7.9"], ["copper", "8.9"], ["silver", "10.5"], ["lead", "11.3"], ["g… · unitsNote: "density in g/cm³ at room temperature" · style: "same reference table as the lesson figure"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "density-reference-table",
  "rows": [
   [
    "ethanol",
    "0.79"
   ],
   [
    "water",
    "1.00"
   ],
   [
    "aluminum",
    "2.70"
   ],
   [
    "zinc",
    "7.1"
   ],
   [
    "iron",
    "7.9"
   ],
   [
    "copper",
    "8.9"
   ],
   [
    "silver",
    "10.5"
   ],
   [
    "lead",
    "11.3"
   ],
   [
    "gold",
    "19.3"
   ]
  ],
  "unitsNote": "density in g/cm³ at room temperature",
  "style": "same reference table as the lesson figure"
 }
}
Ethanol KEY
Water
Copper
Aluminum
MPM-035 · hard · transfer · seq 17 · authored · mcq4
Two gas cylinders at a welding shop have identical internal volumes. Empty, each cylinder has a mass of 6.4 kg. After each is filled with a different gas, the scale reads 8.7 kg for cylinder 1 and 7.3 kg for cylinder 2. Which cylinder holds the denser gas?
Cylinder 1 KEY
Cylinder 2
Neither — each gas spreads out to fill its whole cylinder, so the two densities match
The cylinders cannot be compared, because each scale reading includes the cylinder's own mass
MPM-036 · hard · transfer · seq 18 · authored · mcq4
Two beakers on a lab bench each hold a sample of a different liquid, and the two samples' masses are equal. The liquid in beaker 2 has the lower density. Which statement about the two samples' volumes must be true?
The sample in beaker 2 fills a greater volume than the sample in beaker 1. KEY
The sample in beaker 2 fills a smaller volume than the sample in beaker 1.
The two samples fill equal volumes, because their masses are the same.
There is no way to tell which sample fills the greater volume without knowing what the two liquids are.
MPM-042 · hard · transfer · seq 19 · authored · mcq4
A maker of reactor control rods checks whether a batch of metal segments is pure hafnium by measuring the density of one short segment and of one long segment. Both measure 13.3 g/cm³. Why does testing two different sizes make the check stronger?
A single substance shows the same density at every size, so agreement across sizes is exactly what pure hafnium predicts. KEY
It is not stronger — measuring the two segments only confirms what was already obvious: the larger one has more mass than the smaller one.
The check works because the long segment should show a higher density if the metal is pure.
The check is flawed — two segments of different lengths can never be compared.
MPM-043 · hard · transfer · seq 20 · authored · mcq4
A tent stake has a mass of 33.6 g and a volume of 12.0 cm³. Use the density table to decide which substance the stake is most likely made of.
FIGURE (density-reference-table · stimulus) — rows: [["ethanol", "0.79"], ["water", "1.00"], ["aluminum", "2.70"], ["zinc", "7.1"], ["iron", "7.9"], ["copper", "8.9"], ["silver", "10.5"], ["lead", "11.3"], ["g… · unitsNote: "density in g/cm³ at room temperature" · style: "same reference table as the lesson figure" · table: "Two-column reference table, 'Densities of common substances (room temperature)' — Substance / Density (g/cm³): ethanol 0.79; water 1.00; aluminum 2.70; zinc…
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "density-reference-table",
  "rows": [
   [
    "ethanol",
    "0.79"
   ],
   [
    "water",
    "1.00"
   ],
   [
    "aluminum",
    "2.70"
   ],
   [
    "zinc",
    "7.1"
   ],
   [
    "iron",
    "7.9"
   ],
   [
    "copper",
    "8.9"
   ],
   [
    "silver",
    "10.5"
   ],
   [
    "lead",
    "11.3"
   ],
   [
    "gold",
    "19.3"
   ]
  ],
  "unitsNote": "density in g/cm³ at room temperature",
  "style": "same reference table as the lesson figure",
  "table": "Two-column reference table, 'Densities of common substances (room temperature)' — Substance / Density (g/cm³): ethanol 0.79; water 1.00; aluminum 2.70; zinc 7.1; iron 7.9; copper 8.9; silver 10.5; lead 11.3; gold 19.3"
 }
}
Aluminum KEY
Lead
Ethanol
None of the substances in the table
MPM-043 · medium · application · seq 21 · authored (U01-G3 has zero gate prods / prod_seeds — blueprint directs an authored capstone-workflow FRQ from MPM-043) · frq
An assay office receives a small cast bar of unmarked metal. On the balance, the bar's mass is 231.6 g. Lowered into a graduated cylinder of water, the bar raises the water level from 18.5 mL to 30.5 mL.
FIGURE (density-reference-table · stimulus) — title: "Densities of common substances (room temperature)" · columns: ["Substance", "Density (g/cm³)"] · rows: [["ethanol", "0.79"], ["water", "1.00"], ["aluminum", "2.70"], ["zinc", "7.1"], ["iron", "7.9"], ["copper", "8.9"], ["silver", "10.5"], ["lead", "11.3"], ["g… · unitsNote: "density in g/cm³ at room temperature" · style: "same reference table as the lesson figure" · aria: "A two-column reference table listing nine substances and their densities in grams per cubic centimeter, from ethanol at 0.79 to gold at 19.3"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "density-reference-table",
  "title": "Densities of common substances (room temperature)",
  "columns": [
   "Substance",
   "Density (g/cm³)"
  ],
  "rows": [
   [
    "ethanol",
    "0.79"
   ],
   [
    "water",
    "1.00"
   ],
   [
    "aluminum",
    "2.70"
   ],
   [
    "zinc",
    "7.1"
   ],
   [
    "iron",
    "7.9"
   ],
   [
    "copper",
    "8.9"
   ],
   [
    "silver",
    "10.5"
   ],
   [
    "lead",
    "11.3"
   ],
   [
    "gold",
    "19.3"
   ]
  ],
  "unitsNote": "density in g/cm³ at room temperature",
  "style": "same reference table as the lesson figure",
  "aria": "A two-column reference table listing nine substances and their densities in grams per cubic centimeter, from ethanol at 0.79 to gold at 19.3"
 }
}
An assay office receives a small cast bar of unmarked metal. On the balance, the bar's mass is 231.6 g. Lowered into a graduated cylinder of water, the bar raises the water level from 18.5 mL to 30.5 mL. (a) Calculate the bar's volume, in mL. (b) Calculate the bar's density, in g/mL, rounded to the correct number of significant figures. Show every step of your calculation. (c) Use the density table to identify the metal, and justify your identification in one or two sentences. (1 mL = 1 cm³, so a density in g/mL matches the table's g/cm³ column directly.)
Part a. Calculate the bar's volume, in mL.
Model: The bar's volume is the rise in the water level, not the final reading. V = 30.5 − 18.5 V = 12.0 mL
Part b. Calculate the bar's density, in g/mL, rounded to the correct number of significant figures. Show every step of your calculation.
Model: m = 231.6 g V = 12.0 mL (from part a) D = m / V D = 231.6 / 12.0 D = 19.3 g/mL Rounding: the least precise measurement, 12.0 mL, has 3 significant figures, so the density is reported as 19.3 g/mL.
Part c. Use the density table to identify the metal, and justify your identification in one or two sentences. (1 mL = 1 cm³, so a density in g/mL matches the table's g/cm³ column directly.)
Model: One milliliter is the same space as one cubic centimeter, so a density in g/mL reads against the table directly. The measured 19.3 g/mL matches gold's table value, 19.3. Every sample of one substance has the same density whatever the sample's size, so the bar is gold.
Full model answer. (a) The bar's volume is the rise in the water level, not the final reading. V = 30.5 − 18.5 V = 12.0 mL (b) m = 231.6 g V = 12.0 mL (from part a) D = m / V D = 231.6 / 12.0 D = 19.3 g/mL Rounding: the least precise measurement, 12.0 mL, has 3 significant figures, so the density is reported as 19.3 g/mL. (c) One milliliter is the same space as one cubic centimeter, so a density in g/mL reads against the table directly. The measured 19.3 g/mL matches gold's table value, 19.3. Every sample of one substance has the same density whatever the sample's size, so the bar is gold.

Form C

MPM-034 · easy · recall · seq 1 · authored · mcq4
A materials scientist describes aerogel as one of the least dense solids ever made. What is the scientist claiming about aerogel?
Each cubic centimeter of aerogel carries less mass than a cubic centimeter of almost any other solid. KEY
Any object made of aerogel has less mass than any object made of a different solid.
Aerogel takes up less space than the same mass of almost any other solid.
Aerogel melts at a lower temperature than almost any other solid.
MPM-037 · easy · recall · seq 2 · authored · mcq4
According to the equation D = m/V, which operation gives a material's density?
Dividing its mass by its volume. KEY
Dividing its volume by its mass.
Multiplying its mass by its volume.
Adding its mass to its volume.
MPM-041 · easy · recall · seq 3 · authored · mcq4
During a demonstration, a teacher shows the class a graduated cylinder that already holds some liquid and writes down the level. She then drops a coin into the cylinder; it sinks and comes to rest fully under the surface, and the level ends up at a higher mark. Which statement about the rise in the level is correct?
The rise equals the coin's volume — the level ended higher by exactly the space the coin takes up. KEY
The rise is not needed — the final level on its own gives the coin's volume.
The rise gives the coin's mass — a heavier coin of the same size pushes the level up further.
The rise gives the coin's density, because denser coins push the level up further.
MPM-042 · easy · recall · seq 4 · authored · mcq4
A souvenir maker pours pure tin into solid pieces of many sizes, from thumb-sized charms to large candlesticks. Which statement about the densities of the tin pieces is correct?
Every piece has the same density, whatever its size. KEY
The large candlesticks have the highest densities, because they contain the most tin.
The small charms have the highest densities, because their tin is packed into less space.
The densities differ from piece to piece and must be measured one at a time.
MPM-035 · medium · application · seq 5 · authored · mcq4
A lab technician measures out two liquid samples so that each has the same volume, 65.0 mL. The glycerin sample has a mass of 81.9 g, and the acetone sample has a mass of 50.7 g. Which liquid is denser?
The glycerin is the denser liquid. KEY
The acetone is the denser liquid.
The two liquids are equally dense.
It depends on which liquid pours more slowly.
MPM-036 · medium · application · seq 6 · authored · mcq4
A pastry chef measures out 156 g of maple syrup and 156 g of sunflower oil. The syrup fills a measuring cup to the 118 mL mark; the oil fills an identical cup to the 170 mL mark. Which liquid is denser?
The maple syrup KEY
The sunflower oil
Neither liquid — because their masses are equal, their densities must be equal.
It is impossible to tell without a density reference table.
MPM-037 · medium · application · seq 7 · authored · mcq4
Two samples have the same volume V. Sample 1 has the smaller mass m. Using D = m/V, which conclusion follows?
Sample 1 has the smaller density, because a smaller m over the same V gives a smaller D. KEY
Sample 1 has the greater density, because dividing by a smaller mass gives a greater result.
The two densities must be equal, because the samples share the same volume.
Sample 1 takes up less space, because a smaller mass needs less room.
MPM-038 · medium · application · seq 8 · authored · numeric
A small bar of indium has a mass of 14.62 g and a volume of 2.00 cm³. Calculate its density, in g/cm³, to 3 significant figures.
Answer: 7.31 g/cm³ KEY
also accepted: 7.31 g/cm³
wrongValueDiagnostics
[
 {
  "value": 0.137,
  "misconception": "you divided the volume by the mass instead of the mass by the volume",
  "feedback": null
 },
 {
  "value": 29.24,
  "misconception": "you multiplied the mass by the volume instead of dividing",
  "feedback": null
 },
 {
  "value": 0.731,
  "misconception": "you slipped the decimal point one place",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nm = 14.62 g\nV = 2.00 cm³\nWrite down the equation:\nD = m / V\nSubstitute in the values, and calculate:\nD = 14.62 / 2.00\nD = 7.31 g/cm³\nMore than 7 g packed into each cubic centimeter fits a soft, dense metal; 0.137 g/cm³ would be far too light for any solid metal, which fails the sense check."
}
MPM-038 · medium · application · seq 9 · authored · mcq4
A quality-control technician measures two solid blocks. Block P has a mass of 37.4 g and a volume of 22.0 cm³. Block Q has a mass of 32.3 g and a volume of 17.0 cm³. Which block has the greater density?
Block Q — 1.90 g/cm³ compared with 1.70 g/cm³. KEY
Block P — 1.70 g/cm³ is the greater density.
Block P — its mass, 37.4 g, is the greater.
Block P — 0.588 g/cm³ compared with 0.526 g/cm³.
MPM-039 · medium · application · seq 10 · authored · numeric
A lens maker grinds a germanium blank for an infrared camera. The finished blank has a volume of 10.0 cm³, and germanium's density is 5.32 g/cm³. What is the blank's mass, in grams? Give your answer to 3 significant figures.
Answer: 53.2 g KEY
wrongValueDiagnostics
[
 {
  "value": 1.88,
  "misconception": "you divided the volume by the density instead of multiplying them",
  "feedback": null
 },
 {
  "value": 0.532,
  "misconception": "you divided the density by the volume instead of multiplying them",
  "feedback": null
 },
 {
  "value": 15.3,
  "misconception": "you added the density to the volume instead of multiplying them",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nD = 5.32 g/cm³\nV = 10.0 cm³\nWrite down the equation:\nD = m / V\nMake m the subject:\nm = D × V\nSubstitute in the values, and calculate:\nm = 5.32 × 10.0\nm = 53.2 g\nEach cubic centimeter of germanium carries 5.32 g, and the blank holds ten of them — the mass must exceed 5.32 g, so 1.88 g and 0.532 g fail the sense check."
}
MPM-039 · medium · application · seq 11 · authored · mcq4
A metals supplier packages two solid samples: a 28.0 cm³ piece of vanadium (density 6.11 g/cm³) and a 17.5 cm³ piece of chromium (density 7.19 g/cm³). Which sample has the greater mass?
The vanadium — 171 g compared with 126 g. KEY
The chromium — 126 g compared with 171 g.
The chromium — its density, 7.19 g/cm³, beats 6.11 g/cm³.
The vanadium — 4.58 g compared with 2.43 g.
MPM-040 · medium · application · seq 12 · authored · numeric
A science-supply company seals 35.4 g of gallium into a small vial for melting demonstrations. Gallium's density is 5.90 g/cm³. What volume, in cm³, does the gallium take up? Give your answer to 3 significant figures.
Answer: 6 cm³ KEY
also accepted: 6.00 cm³, 6.00 cm3
scaffold
[
 "Write down the values in the question:",
 "D = 5.90 g/cm³",
 "m = 35.4 g",
 "Write down the equation:",
 "D = m / V",
 "Make V the subject:",
 "V = m / D",
 "Substitute in the values, and calculate:",
 "V = 35.4 / 5.90",
 "V = 6.00 cm³"
]
wrongValueDiagnostics
[
 {
  "value": 208.86,
  "misconception": "you multiplied the mass by the density instead of dividing",
  "feedback": "This answer is wrong — you multiplied the mass by the density instead of dividing. Gallium packs 5.90 g into each cubic centimeter, so divide the mass by the density: V = 35.4 / 5.90 = 6.00 cm³ — a 208.86 cm³ bucket of gallium fails the sense check."
 },
 {
  "value": 0.167,
  "misconception": "you divided the density by the mass instead of the mass by the density",
  "feedback": "This answer is wrong — you divided the density by the mass instead of the mass by the density. Make V the subject of D = m/V: V = m / D = 35.4 / 5.90 = 6.00 cm³."
 },
 {
  "value": 60.0,
  "misconception": "you slipped the decimal point one place",
  "feedback": "This answer is wrong — you slipped the decimal point one place. Each cubic centimeter of gallium already holds 5.90 g, so 35.4 g takes up only 6.00 cm³, not 60.0 cm³."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nD = 5.90 g/cm³\nm = 35.4 g\nWrite down the equation:\nD = m / V\nMake V the subject:\nV = m / D\nSubstitute in the values, and calculate:\nV = 35.4 / 5.90\nV = 6.00 cm³\nGallium packs 5.90 g into every cubic centimeter, so 35.4 g needs exactly six of them — 208.86 cm³ would be a bucket of gallium, which fails the sense check.",
 "anticipatedWrong": [
  {
   "value": 208.86,
   "misconception": "you multiplied the mass by the density instead of dividing",
   "feedback": "This answer is wrong — you multiplied the mass by the density instead of dividing. Gallium packs 5.90 g into each cubic centimeter, so divide the mass by the density: V = 35.4 / 5.90 = 6.00 cm³ — a 208.86 cm³ bucket of gallium fails the sense check."
  },
  {
   "value": 0.167,
   "misconception": "you divided the density by the mass instead of the mass by the density",
   "feedback": "This answer is wrong — you divided the density by the mass instead of the mass by the density. Make V the subject of D = m/V: V = m / D = 35.4 / 5.90 = 6.00 cm³."
  },
  {
   "value": 60.0,
   "misconception": "you slipped the decimal point one place",
   "feedback": "This answer is wrong — you slipped the decimal point one place. Each cubic centimeter of gallium already holds 5.90 g, so 35.4 g takes up only 6.00 cm³, not 60.0 cm³."
  }
 ]
}
MPM-040 · medium · application · seq 13 · authored · mcq4
A machinist has two pieces of stock: an acrylic block with a mass of 68.44 g (density 1.18 g/cm³) and a tantalum slug with a mass of 66.6 g (density 16.65 g/cm³). Which piece takes up more space?
The acrylic block — 58.0 cm³ compared with 4.00 cm³. KEY
The tantalum slug — 4.00 cm³ compared with 58.0 cm³.
The tantalum slug — its density, 16.65 g/cm³, is far greater.
The tantalum slug — 1109 cm³ compared with 80.8 cm³.
MPM-041 · medium · application · seq 14 · authored (parallel instance; both levels on unlabeled minor marks; start-reading misconception = the pool-23-licensed class re-instanced) · numeric
The figure shows a graduated cylinder before and after a metal door hinge is lowered in. Read both levels and calculate the volume of the hinge, in cm³.
FIGURE (displacement-before-after · stimulus) — scaleMin: 30 · scaleMax: 50 · unit: "mL" · markEvery: 1 · labeledMarks: [30, 35, 40, 45, 50] · beforeLevel: 34.0 · afterLevel: 43.0 · object: "metal door hinge" · style: "two identical cylinders side by side, object fully submerged in the after panel, no level values printed as text outside the scale" · values: "scale window 30–50 mL, labels at 30, 35, 40, 45, 50, one mark every 1 mL; BEFORE panel: water level exactly on the mark four gradations above 30 (34.0 mL); …
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "displacement-before-after",
  "scaleMin": 30,
  "scaleMax": 50,
  "unit": "mL",
  "markEvery": 1,
  "labeledMarks": [
   30,
   35,
   40,
   45,
   50
  ],
  "beforeLevel": 34.0,
  "afterLevel": 43.0,
  "object": "metal door hinge",
  "style": "two identical cylinders side by side, object fully submerged in the after panel, no level values printed as text outside the scale",
  "values": "scale window 30–50 mL, labels at 30, 35, 40, 45, 50, one mark every 1 mL; BEFORE panel: water level exactly on the mark four gradations above 30 (34.0 mL); AFTER panel: door hinge fully submerged, water level exactly on the mark three gradations above 40 (43.0 mL)"
 }
}
Answer: 9 cm³ KEY
also accepted: 9.0, 9 cm³, 9 cm3
scaffold
[
 "Read the values from the figure:",
 "starting level = 34.0 mL",
 "final level = 43.0 mL",
 "Write down the equation:",
 "V = final level − starting level",
 "Substitute in the values, and calculate:",
 "V = 43.0 − 34.0",
 "V = 9 cm³"
]
wrongValueDiagnostics
[
 {
  "value": 43.0,
  "misconception": "you reported the final reading instead of the rise in level",
  "feedback": "This answer is wrong — you reported the final reading instead of the rise in level. The final reading is only where the water now stands; the hinge's volume is the rise: V = 43.0 − 34.0 = 9 cm³."
 },
 {
  "value": 34.0,
  "misconception": "you reported the starting reading — that is where the water stood before the hinge went in, not the hinge's volume",
  "feedback": "This answer is wrong — you reported the starting reading; that is only where the water stood before the hinge went in. The hinge's volume is the rise: V = 43.0 − 34.0 = 9 cm³."
 },
 {
  "value": 77.0,
  "misconception": "you added the two readings instead of subtracting",
  "feedback": "This answer is wrong — you added the two readings instead of subtracting. The volume is the rise in the level: V = 43.0 − 34.0 = 9 cm³."
 }
]
feedback
{
 "keyExplanation": "Read the values from the figure:\nstarting level = 34.0 mL\nfinal level = 43.0 mL\nWrite down the equation:\nV = final level − starting level\nSubstitute in the values, and calculate:\nV = 43.0 − 34.0\nV = 9 cm³\nThe levels are read in milliliters, and one milliliter is one cubic centimeter, so the volume comes out in cm³.",
 "anticipatedWrong": [
  {
   "value": 43.0,
   "misconception": "you reported the final reading instead of the rise in level",
   "feedback": "This answer is wrong — you reported the final reading instead of the rise in level. The final reading is only where the water now stands; the hinge's volume is the rise: V = 43.0 − 34.0 = 9 cm³."
  },
  {
   "value": 34.0,
   "misconception": "you reported the starting reading — that is where the water stood before the hinge went in, not the hinge's volume",
   "feedback": "This answer is wrong — you reported the starting reading; that is only where the water stood before the hinge went in. The hinge's volume is the rise: V = 43.0 − 34.0 = 9 cm³."
  },
  {
   "value": 77.0,
   "misconception": "you added the two readings instead of subtracting",
   "feedback": "This answer is wrong — you added the two readings instead of subtracting. The volume is the rise in the level: V = 43.0 − 34.0 = 9 cm³."
  }
 ]
}
MPM-042 · medium · application · seq 15 · authored · mcq4
A solid bar of soap is sawn into two equal pieces. A student claims each piece now has only half the density of the whole bar. Why is the claim wrong?
Each piece has half the mass in half the volume, so the density comes out unchanged. KEY
The claim is right — each piece holds only half the mass, so its density is halved.
The claim is wrong because sawing the bar actually doubles each piece's density.
The claim is wrong because neither piece's density can be known until each piece is measured.
MPM-043 · medium · application · seq 16 · authored · mcq4
The specification sheet for a machined metal bushing lists a volume of 1.40 cm³. The bushing has a mass of 12.46 g. Use the density table to identify the metal.
FIGURE (density-reference-table · stimulus) — rows: [["ethanol", "0.79"], ["water", "1.00"], ["aluminum", "2.70"], ["zinc", "7.1"], ["iron", "7.9"], ["copper", "8.9"], ["silver", "10.5"], ["lead", "11.3"], ["g… · unitsNote: "density in g/cm³ at room temperature" · style: "same reference table as the lesson figure"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "density-reference-table",
  "rows": [
   [
    "ethanol",
    "0.79"
   ],
   [
    "water",
    "1.00"
   ],
   [
    "aluminum",
    "2.70"
   ],
   [
    "zinc",
    "7.1"
   ],
   [
    "iron",
    "7.9"
   ],
   [
    "copper",
    "8.9"
   ],
   [
    "silver",
    "10.5"
   ],
   [
    "lead",
    "11.3"
   ],
   [
    "gold",
    "19.3"
   ]
  ],
  "unitsNote": "density in g/cm³ at room temperature",
  "style": "same reference table as the lesson figure"
 }
}
Copper KEY
Iron
Lead
Ethanol
MPM-035 · hard · transfer · seq 17 · authored · mcq4
At an industrial gas depot, two rigid storage spheres have identical internal volumes. Filling sphere 1 with one gas raises its mass by 0.8 kg; filling sphere 2 with a different gas raises its mass by 1.6 kg. Which of the two gases is denser inside its sphere?
The gas in sphere 2 KEY
The gas in sphere 1
Neither gas — both spheres are completely filled, so both gases are packed equally
It cannot be decided which gas is denser without knowing the gases' names
MPM-036 · hard · transfer · seq 18 · authored · mcq4
A stationery factory makes vinyl erasers and rubber erasers, trimming every eraser on a balance so that each one has the same mass. The vinyl compound is denser than the rubber compound. Which statement about the erasers' volumes must be true?
A vinyl eraser is smaller in volume than a rubber eraser. KEY
A vinyl eraser is larger in volume than a rubber eraser.
A vinyl eraser and a rubber eraser have equal volumes, since every eraser has the same mass.
Measuring each eraser is the only way to learn how their volumes compare.
MPM-042 · hard · transfer · seq 19 · authored · mcq4
An alloy plant checks whether a delivery of metal pieces is pure scandium by measuring the density of one small piece and of one large piece. Both measure 2.99 g/cm³. Why does testing two different sizes make the check stronger?
A single substance shows the same density at every size, so agreement across sizes is exactly what pure scandium predicts. KEY
It is not stronger — measuring the two pieces only confirms what was already obvious: the larger one has more mass than the smaller one.
The check works because the large piece should show a higher density if the metal is pure.
The check is flawed — two pieces of different sizes can never be compared.
MPM-043 · hard · transfer · seq 20 · authored · mcq4
A laboratory storeroom has an unlabeled liquid. A 42.5 mL sample of the liquid has a mass of 44.2 g. Use the density table to decide which substance the liquid most likely is.
FIGURE (density-reference-table · stimulus) — rows: [["ethanol", "0.79"], ["water", "1.00"], ["aluminum", "2.70"], ["zinc", "7.1"], ["iron", "7.9"], ["copper", "8.9"], ["silver", "10.5"], ["lead", "11.3"], ["g… · unitsNote: "density in g/cm³ at room temperature" · style: "same reference table as the lesson figure" · table: "Two-column reference table, 'Densities of common substances (room temperature)' — Substance / Density (g/cm³): ethanol 0.79; water 1.00; aluminum 2.70; zinc…
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "density-reference-table",
  "rows": [
   [
    "ethanol",
    "0.79"
   ],
   [
    "water",
    "1.00"
   ],
   [
    "aluminum",
    "2.70"
   ],
   [
    "zinc",
    "7.1"
   ],
   [
    "iron",
    "7.9"
   ],
   [
    "copper",
    "8.9"
   ],
   [
    "silver",
    "10.5"
   ],
   [
    "lead",
    "11.3"
   ],
   [
    "gold",
    "19.3"
   ]
  ],
  "unitsNote": "density in g/cm³ at room temperature",
  "style": "same reference table as the lesson figure",
  "table": "Two-column reference table, 'Densities of common substances (room temperature)' — Substance / Density (g/cm³): ethanol 0.79; water 1.00; aluminum 2.70; zinc 7.1; iron 7.9; copper 8.9; silver 10.5; lead 11.3; gold 19.3"
 }
}
Water KEY
Ethanol
Gold
None of the substances in the table
MPM-043 · medium · application · seq 21 · authored (U01-G3 has zero gate prods / prod_seeds — blueprint directs an authored capstone-workflow FRQ from MPM-043) · frq
A hiker finds a small metal carabiner clipped to an abandoned pack and wants to know what metal it is. On the balance, the carabiner's mass is 29.7 g. Lowered into a graduated cylinder of water, the carabiner raises the water level from 25.5 mL to 36.5 mL.
FIGURE (density-reference-table · stimulus) — title: "Densities of common substances (room temperature)" · columns: ["Substance", "Density (g/cm³)"] · rows: [["ethanol", "0.79"], ["water", "1.00"], ["aluminum", "2.70"], ["zinc", "7.1"], ["iron", "7.9"], ["copper", "8.9"], ["silver", "10.5"], ["lead", "11.3"], ["g… · unitsNote: "density in g/cm³ at room temperature" · style: "same reference table as the lesson figure" · aria: "A two-column reference table listing nine substances and their densities in grams per cubic centimeter, from ethanol at 0.79 to gold at 19.3"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "density-reference-table",
  "title": "Densities of common substances (room temperature)",
  "columns": [
   "Substance",
   "Density (g/cm³)"
  ],
  "rows": [
   [
    "ethanol",
    "0.79"
   ],
   [
    "water",
    "1.00"
   ],
   [
    "aluminum",
    "2.70"
   ],
   [
    "zinc",
    "7.1"
   ],
   [
    "iron",
    "7.9"
   ],
   [
    "copper",
    "8.9"
   ],
   [
    "silver",
    "10.5"
   ],
   [
    "lead",
    "11.3"
   ],
   [
    "gold",
    "19.3"
   ]
  ],
  "unitsNote": "density in g/cm³ at room temperature",
  "style": "same reference table as the lesson figure",
  "aria": "A two-column reference table listing nine substances and their densities in grams per cubic centimeter, from ethanol at 0.79 to gold at 19.3"
 }
}
A hiker finds a small metal carabiner clipped to an abandoned pack and wants to know what metal it is. On the balance, the carabiner's mass is 29.7 g. Lowered into a graduated cylinder of water, the carabiner raises the water level from 25.5 mL to 36.5 mL. (a) Calculate the carabiner's volume, in mL. (b) Calculate the carabiner's density, in g/mL, rounded to the correct number of significant figures. Show every step of your calculation. (c) Use the density table to identify the metal, and justify your identification in one or two sentences. (1 mL = 1 cm³, so a density in g/mL matches the table's g/cm³ column directly.)
Part a. Calculate the carabiner's volume, in mL.
Model: The carabiner's volume is the rise in the water level, not the final reading. V = 36.5 − 25.5 V = 11.0 mL
Part b. Calculate the carabiner's density, in g/mL, rounded to the correct number of significant figures. Show every step of your calculation.
Model: m = 29.7 g V = 11.0 mL (from part a) D = m / V D = 29.7 / 11.0 D = 2.70 g/mL Rounding: both measurements have 3 significant figures, so the density is reported as 2.70 g/mL.
Part c. Use the density table to identify the metal, and justify your identification in one or two sentences. (1 mL = 1 cm³, so a density in g/mL matches the table's g/cm³ column directly.)
Model: One milliliter is the same space as one cubic centimeter, so a density in g/mL reads against the table directly. The measured 2.70 g/mL matches aluminum's table value, 2.70. Every sample of one substance has the same density whatever the sample's size, so the carabiner is aluminum.
Full model answer. (a) The carabiner's volume is the rise in the water level, not the final reading. V = 36.5 − 25.5 V = 11.0 mL (b) m = 29.7 g V = 11.0 mL (from part a) D = m / V D = 29.7 / 11.0 D = 2.70 g/mL Rounding: both measurements have 3 significant figures, so the density is reported as 2.70 g/mL. (c) One milliliter is the same space as one cubic centimeter, so a density in g/mL reads against the table directly. The measured 2.70 g/mL matches aluminum's table value, 2.70. Every sample of one substance has the same density whatever the sample's size, so the carabiner is aluminum.

Form D

MPM-034 · easy · recall · seq 1 · authored · mcq4
A museum guide at a metals exhibit tells visitors that osmium is denser than every other metal. What is the guide claiming about osmium?
Each cubic centimeter of osmium carries more mass than a cubic centimeter of any other metal. KEY
Any object made of osmium has more mass than any object made of a different metal.
Osmium takes up more space than the same mass of any other metal.
Osmium stays shiny longer than any other metal.
MPM-037 · easy · recall · seq 2 · authored · mcq4
A lab manual states the density equation in words: 'Density is found by dividing the ___ by the ___.' Which pair of quantities fills the blanks in order?
The mass, then the volume. KEY
The volume, then the mass.
The density, then the volume.
The mass, then the density.
MPM-041 · easy · recall · seq 3 · authored · mcq4
A hobbyist part-fills a graduated cylinder, reads the level, and then lowers a small screw into it. The screw settles fully beneath the surface, and the level now stands higher than before. Which statement about the rise in the level is correct?
The rise equals the screw's volume — the level stands higher by exactly the space the screw takes up. KEY
The rise is not needed — the final level on its own gives the screw's volume.
The rise gives the screw's mass — a heavier screw of the same size pushes the level up further.
The rise gives the screw's density, because denser screws push the level up further.
MPM-042 · easy · recall · seq 4 · authored · mcq4
A metal refinery casts pure manganese into pieces of many sizes, from small flakes to heavy ingots. Which statement about the pieces' densities is correct?
Every piece has the same density, whatever its size. KEY
The heavy ingots have the highest densities, because they have the most mass.
The heavy ingots have the lowest densities, because their mass is spread through more volume.
The pieces' densities cannot be predicted — each piece must be measured on its own.
MPM-035 · medium · application · seq 5 · authored · mcq4
At a quality-control bench, two machined blocks, K and L, have been cut to the same volume, 36.0 cm³ each. On the balance, block K reads 95.4 g and block L reads 288 g. Which block is cut from the denser material?
Block L is cut from the denser material. KEY
Block K is cut from the denser material.
The two blocks are cut from equally dense materials.
Neither can be named denser until the materials are identified.
MPM-036 · medium · application · seq 6 · authored · mcq4
A bulk-foods store sells flour and puffed rice in completely filled bags that each hold exactly 2 kg of food. The filled flour bag is far smaller than the filled puffed-rice bag. A shopper claims the flour is denser than the puffed rice. What makes the claim sound?
The masses are equal, so the smaller bag packs that mass into less volume. KEY
Nothing — bag sizes say nothing about density.
The claim needs the two bags to have equal volumes before comparing.
The claim cannot be judged without measuring both bags' volumes and computing both densities.
MPM-037 · medium · application · seq 7 · authored · mcq4
Two samples have the same mass m. Sample 1 has the greater volume V. Using D = m/V, which conclusion follows?
Sample 1 has the smaller density, because the same m over a greater V gives a smaller D. KEY
Sample 1 has the greater density, because a greater volume holds more material.
The two samples must have equal densities, since both have mass m.
Sample 1 has the greater mass, because more space means more material.
MPM-038 · medium · application · seq 8 · authored · numeric
A niobium disc made for a collector's coin has a mass of 25.71 g and a volume of 3.00 cm³. Calculate its density, in g/cm³, to 3 significant figures.
Answer: 8.57 g/cm³ KEY
also accepted: 8.57 g/cm³
wrongValueDiagnostics
[
 {
  "value": 0.117,
  "misconception": "you divided the volume by the mass instead of the mass by the volume",
  "feedback": null
 },
 {
  "value": 77.13,
  "misconception": "you multiplied the mass by the volume instead of dividing",
  "feedback": null
 },
 {
  "value": 0.857,
  "misconception": "you slipped the decimal point one place",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nm = 25.71 g\nV = 3.00 cm³\nWrite down the equation:\nD = m / V\nSubstitute in the values, and calculate:\nD = 25.71 / 3.00\nD = 8.57 g/cm³\nMore than 8 g packed into each cubic centimeter fits a dense metal; 0.117 g/cm³ would be far too light for any solid metal, which fails the sense check."
}
MPM-038 · medium · application · seq 9 · authored · mcq4
A workshop receives two small machine parts, each made of a different metal alloy. Part 1 has a mass of 36.3 g and a volume of 5.5 cm³. Part 2 has a mass of 33.3 g and a volume of 4.5 cm³. Which of the parts has the greater density?
Part 2 — 7.4 g/cm³ compared with 6.6 g/cm³. KEY
Part 1 — 6.6 g/cm³ is the greater density.
Part 1 — its mass, 36.3 g, is the greater.
Part 1 — 0.15 g/cm³ compared with 0.14 g/cm³.
MPM-039 · medium · application · seq 10 · authored · numeric
A chemist measures out 70.0 mL of dichloromethane (density 1.33 g/cm³) for an extraction. (1 mL = 1 cm³) What is the mass of the dichloromethane, in grams? Give your answer to 3 significant figures.
Answer: 93.1 g KEY
wrongValueDiagnostics
[
 {
  "value": 52.6,
  "misconception": "you divided the volume by the density instead of multiplying them",
  "feedback": null
 },
 {
  "value": 0.019,
  "misconception": "you divided the density by the volume instead of multiplying them",
  "feedback": null
 },
 {
  "value": 71.3,
  "misconception": "you added the density to the volume instead of multiplying them",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nD = 1.33 g/cm³\nV = 70.0 mL = 70.0 cm³\nWrite down the equation:\nD = m / V\nMake m the subject:\nm = D × V\nSubstitute in the values, and calculate:\nm = 1.33 × 70.0\nm = 93.1 g\nEach cubic centimeter of dichloromethane carries 1.33 g, and the sample holds seventy of them — the mass must exceed 1.33 g, so 0.019 g fails the sense check."
}
MPM-039 · medium · application · seq 11 · authored · mcq4
A beryllium component for a satellite instrument must not exceed 78.0 g. The design has a volume of 44.0 cm³, and beryllium's density is 1.85 g/cm³. What is the component's mass, and does it meet the limit?
81.4 g — the component is over the 78.0 g limit. KEY
23.8 g — the component meets the limit easily.
0.042 g — the component meets the limit easily.
814 g — the component is far over the limit.
MPM-040 · medium · application · seq 12 · authored · numeric
A machine shop cuts valve parts from solid zirconium. One blank piece has a mass of 16.3 g, and zirconium's density is 6.52 g/cm³. What volume, in cm³, does the blank piece occupy? Give your answer to 3 significant figures.
Answer: 2.5 cm³ KEY
also accepted: 2.50 cm³, 2.50 cm3
scaffold
[
 "Write down the values in the question:",
 "D = 6.52 g/cm³",
 "m = 16.3 g",
 "Write down the equation:",
 "D = m / V",
 "Make V the subject:",
 "V = m / D",
 "Substitute in the values, and calculate:",
 "V = 16.3 / 6.52",
 "V = 2.50 cm³"
]
wrongValueDiagnostics
[
 {
  "value": 106.276,
  "misconception": "you multiplied the mass by the density instead of dividing",
  "feedback": "This answer is wrong — you multiplied the mass by the density instead of dividing. Zirconium packs 6.52 g into each cubic centimeter, so divide the mass by the density: V = 16.3 / 6.52 = 2.50 cm³."
 },
 {
  "value": 0.4,
  "misconception": "you divided the density by the mass instead of the mass by the density",
  "feedback": "This answer is wrong — you divided the density by the mass instead of the mass by the density. Make V the subject of D = m/V: V = m / D = 16.3 / 6.52 = 2.50 cm³."
 },
 {
  "value": 25.0,
  "misconception": "you slipped the decimal point one place",
  "feedback": "This answer is wrong — you slipped the decimal point one place. Each cubic centimeter of zirconium already holds 6.52 g, so a 16.3 g blank occupies only 2.50 cm³, not 25.0 cm³."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nD = 6.52 g/cm³\nm = 16.3 g\nWrite down the equation:\nD = m / V\nMake V the subject:\nV = m / D\nSubstitute in the values, and calculate:\nV = 16.3 / 6.52\nV = 2.50 cm³\nZirconium packs 6.52 g into each cubic centimeter, so the blank's volume in cm³ must come out much smaller than its mass in grams — 2.50 cm³ passes that check.",
 "anticipatedWrong": [
  {
   "value": 106.276,
   "misconception": "you multiplied the mass by the density instead of dividing",
   "feedback": "This answer is wrong — you multiplied the mass by the density instead of dividing. Zirconium packs 6.52 g into each cubic centimeter, so divide the mass by the density: V = 16.3 / 6.52 = 2.50 cm³."
  },
  {
   "value": 0.4,
   "misconception": "you divided the density by the mass instead of the mass by the density",
   "feedback": "This answer is wrong — you divided the density by the mass instead of the mass by the density. Make V the subject of D = m/V: V = m / D = 16.3 / 6.52 = 2.50 cm³."
  },
  {
   "value": 25.0,
   "misconception": "you slipped the decimal point one place",
   "feedback": "This answer is wrong — you slipped the decimal point one place. Each cubic centimeter of zirconium already holds 6.52 g, so a 16.3 g blank occupies only 2.50 cm³, not 25.0 cm³."
  }
 ]
}
MPM-040 · medium · application · seq 13 · authored · mcq4
A paraffin block with a mass of 16.20 g (density 0.900 g/cm³) and a cadmium bar with a mass of 25.95 g (density 8.65 g/cm³) sit side by side. Which sample takes up more space?
The paraffin block — 18.0 cm³ compared with 3.00 cm³. KEY
The cadmium bar — 3.00 cm³ compared with 18.0 cm³.
The cadmium bar — its density, 8.65 g/cm³, is far greater.
The cadmium bar — 224.5 cm³ compared with 14.6 cm³.
MPM-041 · medium · application · seq 14 · authored (parallel instance; the seed A hazard class on a fresh scale window: 2-mL marks, labels every 10) · numeric
The figure shows a wide graduated cylinder, marked every 2 mL, before and after a spark plug is lowered in. Read both levels and calculate the volume of the spark plug, in cm³.
FIGURE (displacement-before-after · stimulus) — scaleMin: 20 · scaleMax: 50 · unit: "mL" · markEvery: 2 · labeledMarks: [20, 30, 40, 50] · beforeLevel: 28 · afterLevel: 44 · object: "spark plug" · style: "two identical wide cylinders side by side, object fully submerged in the after panel, no level values printed as text outside the scale" · values: "scale window 20–50 mL, labels at 20, 30, 40, 50, one mark every 2 mL; BEFORE panel: water level exactly on the mark one gradation below 30 (28 mL); AFTER pa…
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "displacement-before-after",
  "scaleMin": 20,
  "scaleMax": 50,
  "unit": "mL",
  "markEvery": 2,
  "labeledMarks": [
   20,
   30,
   40,
   50
  ],
  "beforeLevel": 28,
  "afterLevel": 44,
  "object": "spark plug",
  "style": "two identical wide cylinders side by side, object fully submerged in the after panel, no level values printed as text outside the scale",
  "values": "scale window 20–50 mL, labels at 20, 30, 40, 50, one mark every 2 mL; BEFORE panel: water level exactly on the mark one gradation below 30 (28 mL); AFTER panel: spark plug fully submerged, water level on the mark two gradations above 40 (44 mL)"
 }
}
Answer: 16 cm³ KEY
also accepted: 16 cm³, 16 cm3
scaffold
[
 "Check the scale first: the labels step from 20 to 30 across five marks, so each mark is 2 mL.",
 "Read the values from the figure:",
 "starting level = 28 mL",
 "final level = 44 mL",
 "Write down the equation:",
 "V = final level − starting level",
 "Substitute in the values, and calculate:",
 "V = 44 − 28",
 "V = 16 cm³"
]
wrongValueDiagnostics
[
 {
  "value": 8,
  "misconception": "you assumed the marks step by 1 mL — on this cylinder each mark is 2 mL",
  "feedback": "This answer is wrong — you assumed the marks step by 1 mL. Check the scale first: the labels step from 20 to 30 across five marks, so each mark is 2 mL, and V = 44 − 28 = 16 cm³."
 },
 {
  "value": 44,
  "misconception": "you reported the final reading instead of the rise in level",
  "feedback": "This answer is wrong — you reported the final reading instead of the rise in level. The final reading is only where the water now stands; the spark plug's volume is the rise: V = 44 − 28 = 16 cm³."
 },
 {
  "value": 72,
  "misconception": "you added the two readings instead of subtracting",
  "feedback": "This answer is wrong — you added the two readings instead of subtracting. The volume is the rise in the level: V = 44 − 28 = 16 cm³."
 }
]
feedback
{
 "keyExplanation": "Check the scale first: the labels step from 20 to 30 across five marks, so each mark is 2 mL.\nRead the values from the figure:\nstarting level = 28 mL\nfinal level = 44 mL\nWrite down the equation:\nV = final level − starting level\nSubstitute in the values, and calculate:\nV = 44 − 28\nV = 16 cm³\nThe levels are read in milliliters, and one milliliter is one cubic centimeter, so the volume comes out in cm³.",
 "anticipatedWrong": [
  {
   "value": 8,
   "misconception": "you assumed the marks step by 1 mL — on this cylinder each mark is 2 mL",
   "feedback": "This answer is wrong — you assumed the marks step by 1 mL. Check the scale first: the labels step from 20 to 30 across five marks, so each mark is 2 mL, and V = 44 − 28 = 16 cm³."
  },
  {
   "value": 44,
   "misconception": "you reported the final reading instead of the rise in level",
   "feedback": "This answer is wrong — you reported the final reading instead of the rise in level. The final reading is only where the water now stands; the spark plug's volume is the rise: V = 44 − 28 = 16 cm³."
  },
  {
   "value": 72,
   "misconception": "you added the two readings instead of subtracting",
   "feedback": "This answer is wrong — you added the two readings instead of subtracting. The volume is the rise in the level: V = 44 − 28 = 16 cm³."
  }
 ]
}
MPM-042 · medium · application · seq 15 · authored · mcq4
In a home-goods shop, two solid bookends — one dark, one pale — measure 460 cm³ each. A shopper says they must be made of the same material because they take up the same amount of space. What is the flaw in the reasoning?
Any material can be shaped into a 460 cm³ piece — equal volumes reveal nothing about identity; equal densities would. KEY
There is no flaw — two solids with equal volumes must be the same material.
The flaw is that the shopper should have compared the masses instead — equal masses would prove the bookends match.
The flaw is that a solid bookend's volume cannot actually be measured.
MPM-043 · medium · application · seq 16 · authored · mcq4
A museum's 3-D scan gives a metal spearhead's volume as 7.0 cm³. Its mass is 55.3 g. Use the density table to identify the metal.
FIGURE (density-reference-table · stimulus) — rows: [["ethanol", "0.79"], ["water", "1.00"], ["aluminum", "2.70"], ["zinc", "7.1"], ["iron", "7.9"], ["copper", "8.9"], ["silver", "10.5"], ["lead", "11.3"], ["g… · unitsNote: "density in g/cm³ at room temperature" · style: "same reference table as the lesson figure"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "density-reference-table",
  "rows": [
   [
    "ethanol",
    "0.79"
   ],
   [
    "water",
    "1.00"
   ],
   [
    "aluminum",
    "2.70"
   ],
   [
    "zinc",
    "7.1"
   ],
   [
    "iron",
    "7.9"
   ],
   [
    "copper",
    "8.9"
   ],
   [
    "silver",
    "10.5"
   ],
   [
    "lead",
    "11.3"
   ],
   [
    "gold",
    "19.3"
   ]
  ],
  "unitsNote": "density in g/cm³ at room temperature",
  "style": "same reference table as the lesson figure"
 }
}
Iron KEY
Zinc
Ethanol
The spearhead cannot be identified from mass and volume alone
MPM-035 · hard · transfer · seq 17 · authored · mcq4
A fire-safety company fills two canisters with different fire-suppressing gases. The canisters have identical internal volumes. Filling canister 1 adds 2.4 kg to its mass; filling canister 2 adds 1.8 kg. In which canister is the stored gas denser?
Canister 1 KEY
Canister 2
Neither — both canisters are full, so the gases must be equally dense
The gases cannot be compared until each gas's own volume is measured separately
MPM-036 · hard · transfer · seq 18 · authored · mcq4
Every finished paver at a landscaping yard has the same mass — the yard checks each one on a balance before sale. The pavers are cast from two different concrete mixes, and the mix 2 concrete is less dense than the mix 1 concrete. Which statement about the pavers' volumes must be true?
A mix 2 paver has a larger volume than a mix 1 paver. KEY
A mix 2 paver has a smaller volume than a mix 1 paver.
Pavers of the two mixes have identical volumes, because their masses are identical.
Until each paver's volume is measured, no volume comparison is possible.
MPM-042 · hard · transfer · seq 19 · authored · mcq4
A thermoelectric-parts factory checks whether a consignment of gray sticks is pure tellurium by measuring the density of one short stick and of one long stick. Both measure 6.24 g/cm³. Why does testing two different sizes make the check stronger?
A single substance shows the same density at every size, so agreement across sizes is exactly what pure tellurium predicts. KEY
It is not stronger — measuring the two sticks only confirms what was already obvious: the larger one has more mass than the smaller one.
The check works because the long stick should show a higher density if the material is pure.
The check is flawed — two sticks of different sizes can never be compared.
MPM-043 · hard · transfer · seq 20 · authored · mcq4
A jug found in a garage holds a small amount of a liquid. A 35.0 mL sample of the liquid has a mass of 28.7 g. Use the density table to decide which substance the liquid most likely is.
FIGURE (density-reference-table · stimulus) — rows: [["ethanol", "0.79"], ["water", "1.00"], ["aluminum", "2.70"], ["zinc", "7.1"], ["iron", "7.9"], ["copper", "8.9"], ["silver", "10.5"], ["lead", "11.3"], ["g… · unitsNote: "density in g/cm³ at room temperature" · style: "same reference table as the lesson figure" · table: "Two-column reference table, 'Densities of common substances (room temperature)' — Substance / Density (g/cm³): ethanol 0.79; water 1.00; aluminum 2.70; zinc…
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "density-reference-table",
  "rows": [
   [
    "ethanol",
    "0.79"
   ],
   [
    "water",
    "1.00"
   ],
   [
    "aluminum",
    "2.70"
   ],
   [
    "zinc",
    "7.1"
   ],
   [
    "iron",
    "7.9"
   ],
   [
    "copper",
    "8.9"
   ],
   [
    "silver",
    "10.5"
   ],
   [
    "lead",
    "11.3"
   ],
   [
    "gold",
    "19.3"
   ]
  ],
  "unitsNote": "density in g/cm³ at room temperature",
  "style": "same reference table as the lesson figure",
  "table": "Two-column reference table, 'Densities of common substances (room temperature)' — Substance / Density (g/cm³): ethanol 0.79; water 1.00; aluminum 2.70; zinc 7.1; iron 7.9; copper 8.9; silver 10.5; lead 11.3; gold 19.3"
 }
}
Ethanol KEY
Water
Zinc
None of the substances in the table
MPM-043 · medium · application · seq 21 · authored (U01-G3 has zero gate prods / prod_seeds — blueprint directs an authored capstone-workflow FRQ from MPM-043) · frq
A restorer removes a small counterweight from an antique wall clock and wants to know what metal it is. On the balance, the counterweight's mass is 135.6 g. Lowered into a graduated cylinder of water, the counterweight raises the water level from 20.5 mL to 32.5 mL.
FIGURE (density-reference-table · stimulus) — title: "Densities of common substances (room temperature)" · columns: ["Substance", "Density (g/cm³)"] · rows: [["ethanol", "0.79"], ["water", "1.00"], ["aluminum", "2.70"], ["zinc", "7.1"], ["iron", "7.9"], ["copper", "8.9"], ["silver", "10.5"], ["lead", "11.3"], ["g… · unitsNote: "density in g/cm³ at room temperature" · style: "same reference table as the lesson figure" · aria: "A two-column reference table listing nine substances and their densities in grams per cubic centimeter, from ethanol at 0.79 to gold at 19.3"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "density-reference-table",
  "title": "Densities of common substances (room temperature)",
  "columns": [
   "Substance",
   "Density (g/cm³)"
  ],
  "rows": [
   [
    "ethanol",
    "0.79"
   ],
   [
    "water",
    "1.00"
   ],
   [
    "aluminum",
    "2.70"
   ],
   [
    "zinc",
    "7.1"
   ],
   [
    "iron",
    "7.9"
   ],
   [
    "copper",
    "8.9"
   ],
   [
    "silver",
    "10.5"
   ],
   [
    "lead",
    "11.3"
   ],
   [
    "gold",
    "19.3"
   ]
  ],
  "unitsNote": "density in g/cm³ at room temperature",
  "style": "same reference table as the lesson figure",
  "aria": "A two-column reference table listing nine substances and their densities in grams per cubic centimeter, from ethanol at 0.79 to gold at 19.3"
 }
}
A restorer removes a small counterweight from an antique wall clock and wants to know what metal it is. On the balance, the counterweight's mass is 135.6 g. Lowered into a graduated cylinder of water, the counterweight raises the water level from 20.5 mL to 32.5 mL. (a) Calculate the counterweight's volume, in mL. (b) Calculate the counterweight's density, in g/mL, rounded to the correct number of significant figures. Show every step of your calculation. (c) Use the density table to identify the metal, and justify your identification in one or two sentences. (1 mL = 1 cm³, so a density in g/mL matches the table's g/cm³ column directly.)
Part a. Calculate the counterweight's volume, in mL.
Model: The counterweight's volume is the rise in the water level, not the final reading. V = 32.5 − 20.5 V = 12.0 mL
Part b. Calculate the counterweight's density, in g/mL, rounded to the correct number of significant figures. Show every step of your calculation.
Model: m = 135.6 g V = 12.0 mL (from part a) D = m / V D = 135.6 / 12.0 D = 11.3 g/mL Rounding: the least precise measurement, 12.0 mL, has 3 significant figures, so the density is reported as 11.3 g/mL.
Part c. Use the density table to identify the metal, and justify your identification in one or two sentences. (1 mL = 1 cm³, so a density in g/mL matches the table's g/cm³ column directly.)
Model: One milliliter is the same space as one cubic centimeter, so a density in g/mL reads against the table directly. The measured 11.3 g/mL matches lead's table value, 11.3. Every sample of one substance has the same density whatever the sample's size, so the counterweight is lead.
Full model answer. (a) The counterweight's volume is the rise in the water level, not the final reading. V = 32.5 − 20.5 V = 12.0 mL (b) m = 135.6 g V = 12.0 mL (from part a) D = m / V D = 135.6 / 12.0 D = 11.3 g/mL Rounding: the least precise measurement, 12.0 mL, has 3 significant figures, so the density is reported as 11.3 g/mL. (c) One milliliter is the same space as one cubic centimeter, so a density in g/mL reads against the table directly. The measured 11.3 g/mL matches lead's table value, 11.3. Every sample of one substance has the same density whatever the sample's size, so the counterweight is lead.

Form E

MPM-034 · easy · recall · seq 1 · authored · mcq4
A bicycle designer says magnesium is one of the least dense metals used for bike frames. What is the designer claiming about magnesium?
Each cubic centimeter of magnesium carries less mass than a cubic centimeter of almost any other frame metal. KEY
Any bike frame made of magnesium has less mass than any frame made of a different metal.
A magnesium part takes up less space than a part with the same mass made of a denser frame metal.
Magnesium resists corrosion better than almost any other frame metal.
MPM-037 · easy · recall · seq 2 · authored · mcq4
Which statement says what the equation D = m/V means?
A material's density equals its mass divided by its volume. KEY
A material's density equals its volume divided by its mass.
A material's density equals its mass multiplied by its volume.
A material's mass equals its density divided by its volume.
MPM-041 · easy · recall · seq 3 · authored · mcq4
Some liquid sits in a graduated cylinder, and a lab worker records the level. He then eases a small porcelain figurine into the cylinder until the whole figurine is below the surface, and the level rises to a new mark. Which statement about the rise in the level is correct?
The rise equals the figurine's volume — the level rose by exactly the space the figurine takes up. KEY
The rise is not needed — the final level on its own gives the figurine's volume.
The rise gives the figurine's mass — a heavier figurine of the same size pushes the level up further.
The rise gives the figurine's density, because denser figurines push the level up further.
MPM-042 · easy · recall · seq 4 · authored · mcq4
A science-supply store sells pure bismuth in pieces of many sizes, from small beads to large ingots. Which statement about the densities of the bismuth pieces is correct?
Every piece has the same density, whatever its size. KEY
The large ingots have the highest densities, because they carry the most mass.
The small beads have the highest densities, because their mass sits in less space.
The store cannot list one density — it depends on which piece a customer measures.
MPM-035 · medium · application · seq 5 · authored · mcq4
At a trophy shop, one award top is cast in pewter and another in titanium using the same mold, so each top has a volume of 32.0 cm³. The pewter top's mass is 234 g and the titanium top's mass is 144 g. The shop owner concludes that pewter is a denser metal than titanium. Why is this conclusion justified?
It is justified because the shared mold fixed both volumes as equal, so the mass comparison is fair. KEY
It is not justified — the tops would need equal masses before their densities could be compared.
It is not justified — the balance shows only that the pewter top is heavier, not that pewter is denser.
It is justified only if both tops were cast from the same batch of metal.
MPM-036 · medium · application · seq 6 · authored · mcq4
A craft kit contains a block of candle wax and a block of modeling clay. Each block has a mass of 84.0 g. The wax block takes up 93 cm³; the clay block takes up 47 cm³. Which block is made of the denser material?
The modeling clay KEY
The candle wax
Neither — blocks with equal masses always have equal densities.
The denser block cannot be identified without calculating both densities.
MPM-037 · medium · application · seq 7 · authored · mcq4
Two samples have the same volume V. Sample 1 has the greater density D. Using D = m/V, which conclusion follows?
Sample 1 has the greater mass, because only a greater m over the same V can give a greater D. KEY
Sample 1 has the smaller mass, because dense materials pack their matter into less space.
The masses are equal, because both samples fill the same volume.
No conclusion about the masses follows without the actual numbers.
MPM-038 · medium · application · seq 8 · authored · numeric
A chunk of solid iodine in a stoppered flask has a mass of 24.65 g and a volume of 5.00 cm³. Calculate its density, in g/cm³, to 3 significant figures.
Answer: 4.93 g/cm³ KEY
also accepted: 4.93 g/cm³
wrongValueDiagnostics
[
 {
  "value": 0.203,
  "misconception": "you divided the volume by the mass instead of the mass by the volume",
  "feedback": null
 },
 {
  "value": 123.25,
  "misconception": "you multiplied the mass by the volume instead of dividing",
  "feedback": null
 },
 {
  "value": 0.493,
  "misconception": "you slipped the decimal point one place",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nm = 24.65 g\nV = 5.00 cm³\nWrite down the equation:\nD = m / V\nSubstitute in the values, and calculate:\nD = 24.65 / 5.00\nD = 4.93 g/cm³\nAlmost 5 g packed into each cubic centimeter fits a heavy crystalline solid; 0.203 g/cm³ would be lighter than nearly any solid, which fails the sense check."
}
MPM-038 · medium · application · seq 9 · authored · mcq4
For a science-fair display, a student measures two mineral specimens. Specimen 1 has a mass of 65.1 g and a volume of 15.5 cm³. Specimen 2 has a mass of 45.6 g and a volume of 9.5 cm³. Which specimen has the greater density?
Specimen 2 — 4.8 g/cm³ compared with 4.20 g/cm³. KEY
Specimen 1 — 4.20 g/cm³ is the greater density.
Specimen 1 — its mass, 65.1 g, is the greater.
Specimen 1 — 0.238 g/cm³ compared with 0.21 g/cm³.
MPM-039 · medium · application · seq 10 · authored · numeric
A marine biologist collects a 300.0 mL sample of seawater (density 1.03 g/cm³). (1 mL = 1 cm³) What is the mass of the seawater, in grams? Give your answer to 3 significant figures.
Answer: 309 g KEY
wrongValueDiagnostics
[
 {
  "value": 291,
  "misconception": "you divided the volume by the density instead of multiplying them",
  "feedback": null
 },
 {
  "value": 0.00343,
  "misconception": "you divided the density by the volume instead of multiplying them",
  "feedback": null
 },
 {
  "value": 301,
  "misconception": "you added the density to the volume instead of multiplying them",
  "feedback": null
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nD = 1.03 g/cm³\nV = 300.0 mL = 300.0 cm³\nWrite down the equation:\nD = m / V\nMake m the subject:\nm = D × V\nSubstitute in the values, and calculate:\nm = 1.03 × 300.0\nm = 309 g\nEach cubic centimeter of seawater carries 1.03 g, and the 300.0 cm³ sample holds three hundred of them — the mass must be far above 1.03 g, so 0.00343 g fails the sense check."
}
MPM-039 · medium · application · seq 11 · authored · mcq4
Two flasks sit in a chemistry stockroom. Flask 1 holds 112 cm³ of chloroform (density 1.48 g/cm³). Flask 2 holds 185 cm³ of castor oil (density 0.960 g/cm³). Which liquid has the greater mass?
The castor oil — 178 g compared with 166 g. KEY
The chloroform — 166 g compared with 178 g.
The chloroform — its density, 1.48 g/cm³, beats 0.960 g/cm³.
The castor oil — 193 g compared with 166 g.
MPM-040 · medium · application · seq 12 · authored · numeric
A hardware store sells solid nylon mallet heads. The largest one has a mass of 108.3 g, and nylon's density is 1.14 g/cm³. What volume of nylon is that? Give your answer to 3 significant figures.
Answer: 95 cm³ KEY
also accepted: 95.0 cm³, 95.0 cm3
scaffold
[
 "Write down the values in the question:",
 "D = 1.14 g/cm³",
 "m = 108.3 g",
 "Write down the equation:",
 "D = m / V",
 "Make V the subject:",
 "V = m / D",
 "Substitute in the values, and calculate:",
 "V = 108.3 / 1.14",
 "V = 95.0 cm³"
]
wrongValueDiagnostics
[
 {
  "value": 123.462,
  "misconception": "you multiplied the mass by the density instead of dividing",
  "feedback": "This answer is wrong — you multiplied the mass by the density instead of dividing. Nylon packs 1.14 g into each cubic centimeter, so divide the mass by the density: V = 108.3 / 1.14 = 95.0 cm³ — slightly smaller than the mass in grams, since nylon is a little denser than water."
 },
 {
  "value": 0.0105,
  "misconception": "you divided the density by the mass instead of the mass by the density",
  "feedback": "This answer is wrong — you divided the density by the mass instead of the mass by the density. Make V the subject of D = m/V: V = m / D = 108.3 / 1.14 = 95.0 cm³ — a 0.0105 cm³ mallet head would be a speck."
 },
 {
  "value": 950,
  "misconception": "you slipped the decimal point one place",
  "feedback": "This answer is wrong — you slipped the decimal point one place. Dividing 108.3 by 1.14 gives 95.0 cm³, not 950 cm³ — nylon is denser than water, so the volume in cm³ must come out smaller than the 108.3 g mass."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nD = 1.14 g/cm³\nm = 108.3 g\nWrite down the equation:\nD = m / V\nMake V the subject:\nV = m / D\nSubstitute in the values, and calculate:\nV = 108.3 / 1.14\nV = 95.0 cm³\nNylon packs just over a gram into each cubic centimeter, so the mallet head's volume in cm³ comes out a little smaller than its 108.3 g mass — 95.0 cm³ passes that check.",
 "anticipatedWrong": [
  {
   "value": 123.462,
   "misconception": "you multiplied the mass by the density instead of dividing",
   "feedback": "This answer is wrong — you multiplied the mass by the density instead of dividing. Nylon packs 1.14 g into each cubic centimeter, so divide the mass by the density: V = 108.3 / 1.14 = 95.0 cm³ — slightly smaller than the mass in grams, since nylon is a little denser than water."
  },
  {
   "value": 0.0105,
   "misconception": "you divided the density by the mass instead of the mass by the density",
   "feedback": "This answer is wrong — you divided the density by the mass instead of the mass by the density. Make V the subject of D = m/V: V = m / D = 108.3 / 1.14 = 95.0 cm³ — a 0.0105 cm³ mallet head would be a speck."
  },
  {
   "value": 950,
   "misconception": "you slipped the decimal point one place",
   "feedback": "This answer is wrong — you slipped the decimal point one place. Dividing 108.3 by 1.14 gives 95.0 cm³, not 950 cm³ — nylon is denser than water, so the volume in cm³ must come out smaller than the 108.3 g mass."
  }
 ]
}
MPM-040 · medium · application · seq 13 · authored · mcq4
A parts tray holds a cobalt disk with a mass of 17.72 g (density 8.86 g/cm³) and a stack of silicon wafers with a total mass of 23.3 g (density 2.33 g/cm³). Which part takes up more space?
The silicon stack — 10.0 cm³ compared with 2.00 cm³. KEY
The cobalt disk — 2.00 cm³ compared with 10.0 cm³.
The cobalt disk — its density, 8.86 g/cm³, is far greater.
The cobalt disk — 157 cm³ compared with 54.3 cm³.
MPM-041 · medium · application · seq 14 · authored (parallel instance; whole-mark start off the labels + half-mark final read - fluency-canon reads) · numeric
The figure shows a wide graduated cylinder before and after a paperweight is lowered in. Read both levels and calculate the volume of the paperweight, in cm³.
FIGURE (displacement-before-after · stimulus) — scaleMin: 35 · scaleMax: 60 · unit: "mL" · markEvery: 1 · labeledMarks: [35, 40, 45, 50, 55, 60] · beforeLevel: 39.0 · afterLevel: 56.5 · object: "paperweight" · style: "two identical wide cylinders side by side, object fully submerged in the after panel, no level values printed as text outside the scale" · values: "scale window 35–60 mL, labels at 35, 40, 45, 50, 55, 60, one mark every 1 mL; BEFORE panel: water level exactly on the mark four gradations above 35 (39.0 m…
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "displacement-before-after",
  "scaleMin": 35,
  "scaleMax": 60,
  "unit": "mL",
  "markEvery": 1,
  "labeledMarks": [
   35,
   40,
   45,
   50,
   55,
   60
  ],
  "beforeLevel": 39.0,
  "afterLevel": 56.5,
  "object": "paperweight",
  "style": "two identical wide cylinders side by side, object fully submerged in the after panel, no level values printed as text outside the scale",
  "values": "scale window 35–60 mL, labels at 35, 40, 45, 50, 55, 60, one mark every 1 mL; BEFORE panel: water level exactly on the mark four gradations above 35 (39.0 mL); AFTER panel: paperweight fully submerged, water level halfway between the marks one and two gradations above 55 (56.5 mL)"
 }
}
Answer: 17.5 cm³ KEY
also accepted: 17.5 cm³, 17.5 cm3
scaffold
[
 "Read the values from the figure:",
 "starting level = 39.0 mL",
 "final level = 56.5 mL",
 "Write down the equation:",
 "V = final level − starting level",
 "Substitute in the values, and calculate:",
 "V = 56.5 − 39.0",
 "V = 17.5 cm³"
]
wrongValueDiagnostics
[
 {
  "value": 56.5,
  "misconception": "you reported the final reading instead of the rise in level",
  "feedback": "This answer is wrong — you reported the final reading instead of the rise in level. The final reading is only where the water now stands; the paperweight's volume is the rise: V = 56.5 − 39.0 = 17.5 cm³."
 },
 {
  "value": 39.0,
  "misconception": "you reported the starting reading — that is where the water stood before the paperweight went in, not the paperweight's volume",
  "feedback": "This answer is wrong — you reported the starting reading; that is only where the water stood before the paperweight went in. The paperweight's volume is the rise: V = 56.5 − 39.0 = 17.5 cm³."
 },
 {
  "value": 95.5,
  "misconception": "you added the two readings instead of subtracting",
  "feedback": "This answer is wrong — you added the two readings instead of subtracting. The volume is the rise in the level: V = 56.5 − 39.0 = 17.5 cm³."
 }
]
feedback
{
 "keyExplanation": "Read the values from the figure:\nstarting level = 39.0 mL\nfinal level = 56.5 mL\nWrite down the equation:\nV = final level − starting level\nSubstitute in the values, and calculate:\nV = 56.5 − 39.0\nV = 17.5 cm³\nThe levels are read in milliliters, and one milliliter is one cubic centimeter, so the volume comes out in cm³.",
 "anticipatedWrong": [
  {
   "value": 56.5,
   "misconception": "you reported the final reading instead of the rise in level",
   "feedback": "This answer is wrong — you reported the final reading instead of the rise in level. The final reading is only where the water now stands; the paperweight's volume is the rise: V = 56.5 − 39.0 = 17.5 cm³."
  },
  {
   "value": 39.0,
   "misconception": "you reported the starting reading — that is where the water stood before the paperweight went in, not the paperweight's volume",
   "feedback": "This answer is wrong — you reported the starting reading; that is only where the water stood before the paperweight went in. The paperweight's volume is the rise: V = 56.5 − 39.0 = 17.5 cm³."
  },
  {
   "value": 95.5,
   "misconception": "you added the two readings instead of subtracting",
   "feedback": "This answer is wrong — you added the two readings instead of subtracting. The volume is the rise in the level: V = 56.5 − 39.0 = 17.5 cm³."
  }
 ]
}
MPM-042 · medium · application · seq 15 · authored · mcq4
A plastics supplier sells one kind of polycarbonate as small offcuts and as whole sheets. A customer says a whole sheet must be denser than a small offcut because it is so much heavier. Why is the customer wrong?
The sheet's greater mass sits in a greater volume — mass and volume grow together, so the two densities match. KEY
The customer is right — the sheet carries far more mass, so its density is far greater.
The customer is wrong only if the sheet and the offcut are first trimmed to equal volumes.
The customer is wrong because the sheet, being larger, is actually the less dense piece.
MPM-043 · medium · application · seq 16 · authored · mcq4
A hobbyist casts a small metal weight in a 0.600 cm³ mold. The finished solid casting completely fills the mold, and its mass is 6.30 g. Use the density table to identify the metal.
FIGURE (density-reference-table · stimulus) — rows: [["ethanol", "0.79"], ["water", "1.00"], ["aluminum", "2.70"], ["zinc", "7.1"], ["iron", "7.9"], ["copper", "8.9"], ["silver", "10.5"], ["lead", "11.3"], ["g… · unitsNote: "density in g/cm³ at room temperature" · style: "same reference table as the lesson figure"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "density-reference-table",
  "rows": [
   [
    "ethanol",
    "0.79"
   ],
   [
    "water",
    "1.00"
   ],
   [
    "aluminum",
    "2.70"
   ],
   [
    "zinc",
    "7.1"
   ],
   [
    "iron",
    "7.9"
   ],
   [
    "copper",
    "8.9"
   ],
   [
    "silver",
    "10.5"
   ],
   [
    "lead",
    "11.3"
   ],
   [
    "gold",
    "19.3"
   ]
  ],
  "unitsNote": "density in g/cm³ at room temperature",
  "style": "same reference table as the lesson figure"
 }
}
Silver KEY
Zinc
Ethanol
The casting cannot be identified from mass and volume alone
MPM-035 · hard · transfer · seq 17 · authored · mcq4
Two identical glass bulbs have equal internal volumes, and each empty bulb has a mass of 412.0 g. Sealed with gas sample 1 inside, the first bulb reads 414.8 g on a laboratory balance; sealed with gas sample 2 inside, the second bulb reads 421.3 g. Which gas sample is denser inside its bulb?
Gas sample 2 KEY
Gas sample 1
Neither sample — a gas fills whatever space it is given, so the two samples are equally dense
It cannot be determined — a balance cannot detect the mass of a gas
MPM-036 · hard · transfer · seq 18 · authored · mcq4
An oak carving and a balsa carving sit on the two pans of a balance, and the balance stays level: the two carvings' masses are equal. Oak is denser than balsa. Which statement about the two carvings' volumes must be true?
The balsa carving has the greater volume. KEY
The oak carving has the greater volume.
The two carvings have equal volumes, because the balance shows their masses match.
Which carving is bigger depends on the shapes the carver chose.
MPM-042 · hard · transfer · seq 19 · authored · mcq4
A specialty-metals dealer checks whether an order of metal lumps is pure yttrium by measuring the density of one small lump and of one large lump. Both measure 4.47 g/cm³. Why does testing two different sizes make the check stronger?
A single substance shows the same density at every size, so agreement across sizes is exactly what pure yttrium predicts. KEY
It is not stronger — measuring the two lumps only confirms what was already obvious: the larger one has more mass than the smaller one.
The check works because the large lump should show a higher density if the metal is pure.
The check is flawed — two lumps of different sizes can never be compared.
MPM-043 · hard · transfer · seq 20 · authored · mcq4
A fishing sinker has a mass of 139.2 g. Lowered into a graduated cylinder, it raises the water level from 40.5 mL to 52.5 mL. Use the density table to decide which metal the sinker most likely is.
FIGURE (density-reference-table · stimulus) — rows: [["ethanol", "0.79"], ["water", "1.00"], ["aluminum", "2.70"], ["zinc", "7.1"], ["iron", "7.9"], ["copper", "8.9"], ["silver", "10.5"], ["lead", "11.3"], ["g… · unitsNote: "density in g/cm³ at room temperature" · style: "same reference table as the lesson figure" · table: "Two-column reference table, 'Densities of common substances (room temperature)' — Substance / Density (g/cm³): ethanol 0.79; water 1.00; aluminum 2.70; zinc…
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "density-reference-table",
  "rows": [
   [
    "ethanol",
    "0.79"
   ],
   [
    "water",
    "1.00"
   ],
   [
    "aluminum",
    "2.70"
   ],
   [
    "zinc",
    "7.1"
   ],
   [
    "iron",
    "7.9"
   ],
   [
    "copper",
    "8.9"
   ],
   [
    "silver",
    "10.5"
   ],
   [
    "lead",
    "11.3"
   ],
   [
    "gold",
    "19.3"
   ]
  ],
  "unitsNote": "density in g/cm³ at room temperature",
  "style": "same reference table as the lesson figure",
  "table": "Two-column reference table, 'Densities of common substances (room temperature)' — Substance / Density (g/cm³): ethanol 0.79; water 1.00; aluminum 2.70; zinc 7.1; iron 7.9; copper 8.9; silver 10.5; lead 11.3; gold 19.3"
 }
}
Lead KEY
Silver
Aluminum
None of the metals
MPM-043 · medium · application · seq 21 · authored (U01-G3 has zero gate prods / prod_seeds — blueprint directs an authored capstone-workflow FRQ from MPM-043) · frq
A blacksmith's apprentice finds an old hand-forged hinge pin and wants to know what metal it is. On the balance, the pin's mass is 47.4 g. Lowered into a graduated cylinder of water, the pin raises the water level from 22.5 mL to 28.5 mL.
FIGURE (density-reference-table · stimulus) — title: "Densities of common substances (room temperature)" · columns: ["Substance", "Density (g/cm³)"] · rows: [["ethanol", "0.79"], ["water", "1.00"], ["aluminum", "2.70"], ["zinc", "7.1"], ["iron", "7.9"], ["copper", "8.9"], ["silver", "10.5"], ["lead", "11.3"], ["g… · unitsNote: "density in g/cm³ at room temperature" · style: "same reference table as the lesson figure" · aria: "A two-column reference table listing nine substances and their densities in grams per cubic centimeter, from ethanol at 0.79 to gold at 19.3"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "density-reference-table",
  "title": "Densities of common substances (room temperature)",
  "columns": [
   "Substance",
   "Density (g/cm³)"
  ],
  "rows": [
   [
    "ethanol",
    "0.79"
   ],
   [
    "water",
    "1.00"
   ],
   [
    "aluminum",
    "2.70"
   ],
   [
    "zinc",
    "7.1"
   ],
   [
    "iron",
    "7.9"
   ],
   [
    "copper",
    "8.9"
   ],
   [
    "silver",
    "10.5"
   ],
   [
    "lead",
    "11.3"
   ],
   [
    "gold",
    "19.3"
   ]
  ],
  "unitsNote": "density in g/cm³ at room temperature",
  "style": "same reference table as the lesson figure",
  "aria": "A two-column reference table listing nine substances and their densities in grams per cubic centimeter, from ethanol at 0.79 to gold at 19.3"
 }
}
A blacksmith's apprentice finds an old hand-forged hinge pin and wants to know what metal it is. On the balance, the pin's mass is 47.4 g. Lowered into a graduated cylinder of water, the pin raises the water level from 22.5 mL to 28.5 mL. (a) Calculate the pin's volume, in mL. (b) Calculate the pin's density, in g/mL, rounded to the correct number of significant figures. Show every step of your calculation. (c) Use the density table to identify the metal, and justify your identification in one or two sentences. (1 mL = 1 cm³, so a density in g/mL matches the table's g/cm³ column directly.)
Part a. Calculate the pin's volume, in mL.
Model: The pin's volume is the rise in the water level, not the final reading. V = 28.5 − 22.5 V = 6.0 mL
Part b. Calculate the pin's density, in g/mL, rounded to the correct number of significant figures. Show every step of your calculation.
Model: m = 47.4 g V = 6.0 mL (from part a) D = m / V D = 47.4 / 6.0 D = 7.9 g/mL Rounding: the least precise measurement, 6.0 mL, has 2 significant figures, so the density is reported as 7.9 g/mL.
Part c. Use the density table to identify the metal, and justify your identification in one or two sentences. (1 mL = 1 cm³, so a density in g/mL matches the table's g/cm³ column directly.)
Model: One milliliter is the same space as one cubic centimeter, so a density in g/mL reads against the table directly. The measured 7.9 g/mL matches iron's table value, 7.9. Every sample of one substance has the same density whatever the sample's size, so the pin is iron.
Full model answer. (a) The pin's volume is the rise in the water level, not the final reading. V = 28.5 − 22.5 V = 6.0 mL (b) m = 47.4 g V = 6.0 mL (from part a) D = m / V D = 47.4 / 6.0 D = 7.9 g/mL Rounding: the least precise measurement, 6.0 mL, has 2 significant figures, so the density is reported as 7.9 g/mL. (c) One milliliter is the same space as one cubic centimeter, so a density in g/mL reads against the table directly. The measured 7.9 g/mL matches iron's table value, 7.9. Every sample of one substance has the same density whatever the sample's size, so the pin is iron.

End of Topic Test: Separating mixtures & Conservation of mass and scientific knowledge (u01-t4 · 5 forms × 21 items · 105 total)

David's notes for James:
full notes file
# u01-t4 — notes/queries from David's side (U01-G4)

1. MPM-051 numeric row (seq 7): MPM-051 is atomKind=fact (default mcq), but your numeric gate seed (pool[22], the sealed-flask total-mass ledger) licensed a numeric-ENTRY row to carry it. Confirm this row should stay numeric entry rather than mcq (ADJ-G4-2).
2. Numeric re-value on your pool[22] seed: its answer was 100.0 g (12.0 + 88.0) - a bare power of ten, which our numeric-realism gate bans as sig-fig-ambiguous. Form A keeps your stem verbatim but re-values to 15.7 + 88.9 = 104.6 g (fresh values on every form). Also, the stem carries BOTH 'to one decimal place' AND a significant-figures sentence (consistent for these values, but doubled) - your pattern, kept verbatim; say the word if you want one dropped (ADJ-G4-5).
3. SEED EDITS under the strict freshness ruling (your structure and misconceptions kept; instances/wording changed) - confirm or veto per item: pool[8] open-dish evaporation freshened off salt water (the MPM-046 article's own taught instance) on every form; pool[24] freshened off steel-wool rust (= MPM-054 WE1 and MPM-052's own article instance); A#10 salt/water -> sorbitol/liquid; A#13 baking-soda basis -> malachite; A#14 oxygen -> chlorine (aluminum kept); A#16/B#16 (pool[33]/[34]) stems now state the statement's EVIDENCE STATUS - a key-blind expert twice found 'A hypothesis' defensible without it; A#8 distractor 'Two' -> 'Six' (your 'counted only the boldest spots' diagnosis cannot produce Two on your own four-spot figure) plus a broadened wrong-count diagnosis on the other marked line; A#9 restructured to a job-pick shape with the separation goal stated.
4. Correction to the A#8 provenance string in this export: its seedRef.edits still reads 'none - verbatim' from placement; the authoritative record of the later distractor edits (D2 rewording + D3 Two -> Six) is patch_loop3_log.json and the item content in this export reflects them.
5. pool[33] on form A#16 classifies MPM-042's own density rule line - a Topic 5 (previous gate) statement inside this gate's MPM-055 classification task. Kept because you curated the item and classifying a familiar statement IS the intended task; confirm the out-of-topic statement is deliberate.
6. pool[26] (which sealed change would break the law - key 'None of them...') is held as a SPARE only: the key is None-shaped under our no-NOTA/AOTA practice. If you want it placed in a future form it needs a restructured stem/key.
7. Freshness scanning treats dye/ink/coloring as the chromatography topic's category vocabulary (your four chromatogram item-template sentences recur across your own seeds), not as instance words; the freshenable instance is the SAMPLE (navy fountain-pen ink, orange drink coloring, fabric tie-dye...). Confirm this reading (ADJ-G4-8).
8. The gate has no production seeds (prod_seeds empty), so the FRQ (seq 21) is AUTHORED from MPM-050: a TYPED multi-step separation plan (name each technique, justify by the property difference used, track every component to its end state), rubric of 3 criteria summing to 100, parallel fresh mixture per form. Related standing question below on the typed diagram-PLAN mapping applies to this typed-plan delivery too.

Form A

MPM-044 · easy · recall · seq 1 · authored · mcq4
A cook pours dried lentils and white rice into one jar and stirs until the two kinds of grain are completely mixed together. Why can the lentils and the rice still be separated from each other?
Mixing changed neither food — the lentils and the rice each keep their own properties, so a physical change can pull them apart. KEY
Stirring slowly joined the lentils and the rice into one new substance, and separating them undoes that chemical change.
Each grain loses its own properties while it sits mixed together in the jar and regains them once it is picked back out.
Taking the two kinds of grain apart is a chemical change that turns each one back into its original substance.
MPM-046 · easy · recall · seq 2 · seed:U01-G4.pool[8] (= MPM-046 gateItems[2], James; structure + misconception set kept, instance freshened per must_freshen_instance flag: article-taught salt water in an open dish -> potassium nitrate solution in an open pan) · mcq4
During the evaporation of potassium nitrate solution — a solid completely dissolved in a liquid — from an open pan, which particles leave the pan?
The liquid's particles only KEY
Particles of both the liquid and the dissolved potassium nitrate
The dissolved potassium nitrate's particles only
No particles leave the pan
MPM-051 · easy · recall · seq 3 · seed:U01-G4/pool[23] · mcq4
In the law of conservation of mass, what does 'closed container' mean?
Nothing gets in and nothing gets out. KEY
No heat can pass through the container's walls.
The container is completely full, with no air space.
The container is rigid and cannot change shape.
MPM-055 · easy · recall · seq 4 · authored · mcq4
In science, what is a law?
A well-tested statement that describes what always happens, without saying why. KEY
An explanation of why things happen, supported by extensive evidence.
A proposed explanation that is still waiting for its first test.
A theory that has collected enough evidence to be promoted.
MPM-045 · medium · application · seq 5 · seed:U01-G4/pool[3] · mcq4
A student filters a jug of fresh lemonade. Its cloudiness is insoluble fruit pulp; its sweetener is fully dissolved. Which statement describes the result?
The pulp collects on the paper; the sweetener stays dissolved in the lemonade below. KEY
The pulp and the sweetener both collect on the paper.
Everything passes through into the flask below.
The sweetener collects on the paper and the pulp passes through.
MPM-047 · medium · application · seq 6 · seed:U01-G4/pool[10] · mcq4
A deep-green plant extract — a solid leaf pigment dissolved in a colorless liquid — is distilled. Predict the result.
The colorless liquid collects in the collecting flask; the pigment stays in the heated flask. KEY
Deep-green liquid collects in the collecting flask.
The pigment collects in the collecting flask and the liquid stays behind in the heated flask.
Nothing separates.
MPM-051 · medium · application · seq 7 · seed:U01-G4/pool[22] (= MPM-051 gateItems[1], James) - values re-valued per must_freshen_values (V-T6); stem otherwise verbatim · numeric
A sealed flask holds 15.7 g of powdered chalk and 88.9 g of an acid solution. They react and fizz. What is the total mass of the sealed flask's contents after the reaction? Give your answer in grams to one decimal place. Give your answer to 4 significant figures.
Answer: 104.6 g KEY
also accepted: 104.6 g
scaffold
[
 "Write down the values in the question:",
 "mass of chalk = 15.7 g",
 "mass of acid solution = 88.9 g",
 "The flask is sealed, so the law of conservation of mass applies:",
 "total mass before = total mass after",
 "In this problem's substances:",
 "mass of chalk + mass of acid solution = total mass after",
 "Substitute in the values, and calculate:",
 "total mass after = 15.7 + 88.9",
 "total mass after = 104.6 g, gas included."
]
wrongValueDiagnostics
[
 {
  "value": 88.9,
  "misconception": "you dropped the solid's mass from the total — everything sealed inside counts",
  "feedback": "This answer is wrong — you dropped the solid's mass from the total; everything sealed inside counts, before and after. The flask holds the chalk's 15.7 g and the acid solution's 88.9 g: 15.7 + 88.9 = 104.6 g."
 },
 {
  "value": 73.2,
  "misconception": "you subtracted the chalk instead of adding it — both starting substances are inside the sealed flask",
  "feedback": "This answer is wrong — you subtracted the chalk instead of adding it; both starting substances are inside the sealed flask. Total mass before = total mass after: 15.7 + 88.9 = 104.6 g."
 },
 {
  "value": 15.7,
  "misconception": "you carried over the solid's mass alone — the total covers everything in the flask",
  "feedback": "This answer is wrong — you carried over the solid's mass alone; the total covers everything in the flask. The acid solution's 88.9 g counts too: 15.7 + 88.9 = 104.6 g."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nmass of chalk = 15.7 g\nmass of acid solution = 88.9 g\nThe flask is sealed, so the law of conservation of mass applies:\ntotal mass before = total mass after\nIn this problem's substances:\nmass of chalk + mass of acid solution = total mass after\nSubstitute in the values, and calculate:\ntotal mass after = 15.7 + 88.9\ntotal mass after = 104.6 g, gas included.",
 "anticipatedWrong": [
  {
   "value": 88.9,
   "misconception": "you dropped the solid's mass from the total — everything sealed inside counts",
   "feedback": "This answer is wrong — you dropped the solid's mass from the total; everything sealed inside counts, before and after. The flask holds the chalk's 15.7 g and the acid solution's 88.9 g: 15.7 + 88.9 = 104.6 g."
  },
  {
   "value": 73.2,
   "misconception": "you subtracted the chalk instead of adding it — both starting substances are inside the sealed flask",
   "feedback": "This answer is wrong — you subtracted the chalk instead of adding it; both starting substances are inside the sealed flask. Total mass before = total mass after: 15.7 + 88.9 = 104.6 g."
  },
  {
   "value": 15.7,
   "misconception": "you carried over the solid's mass alone — the total covers everything in the flask",
   "feedback": "This answer is wrong — you carried over the solid's mass alone; the total covers everything in the flask. The acid solution's 88.9 g counts too: 15.7 + 88.9 = 104.6 g."
  }
 ]
}
MPM-049 · medium · application · seq 8 · seed:U01-G4/pool[15] · mcq4
The figure shows the chromatogram of a food coloring. How many dyes does it contain?
FIGURE (chromatogram · stimulus) — startLineLabel: "start line (pencil)" · waterLineLabel: "highest water level" · spots: [{"color": "orange", "position": "high on the strip"}, {"color": "pink", "position": "upper middle"}, {"color": "blue, drawn faint", "position": "lower middl… · renderStyle: "single strip, one spot rendered noticeably fainter, labels in-diagram"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "chromatogram",
  "startLineLabel": "start line (pencil)",
  "waterLineLabel": "highest water level",
  "spots": [
   {
    "color": "orange",
    "position": "high on the strip"
   },
   {
    "color": "pink",
    "position": "upper middle"
   },
   {
    "color": "blue, drawn faint",
    "position": "lower middle"
   },
   {
    "color": "green",
    "position": "low on the strip"
   }
  ],
  "renderStyle": "single strip, one spot rendered noticeably fainter, labels in-diagram"
 }
}
Four KEY
Three
Five
Six
MPM-050 · medium · application · seq 9 · seed:U01-G4.pool[19] (= MPM-050 gateItems[1] = demo_curated[1], James; stem verbatim, structure + misconception classes kept, all four option instances freshened per the strict SEED RULING: dyes-in-ink -> leaf-extract pigments, dye-in-water -> colored pigment in clear liquid, salt-in-water -> boric acid, sand-in-water -> crushed brick) · mcq4
Which of these separation jobs calls for paper chromatography rather than any other technique you have seen?
Finding out which colored substances a deep-green leaf extract contains KEY
Getting a single dissolved pigment back from its liquid
Getting boric acid back as a dry solid from a beaker of clear liquid
Taking insoluble crushed brick out of a beaker of clear liquid
MPM-050 · medium · application · seq 10 · seed:U01-G4.pool[18] (= MPM-050 gateItems[0] = demo_curated[0], James) — instance FRESHENED AT GATE ASSEMBLY per the strict SEED RULING (salt/water -> sorbitol/unnamed liquid; chalk kept per the blueprint's recorded two-chalk adjudication); structure, plan logic, and all three misconception classes kept 1:1 · mcq4
A beaker holds powdered chalk (insoluble) and dissolved sorbitol, both in the same liquid. Plan a separation that recovers the chalk, the sorbitol, and the liquid.
Filter out the chalk, then distill what passes through — the liquid collects in the collecting flask and the sorbitol stays behind. KEY
Filter out the chalk, then evaporate what passes through in an open dish until dry sorbitol remains.
Distill the whole mixture first, then filter whatever remains behind in the heated flask to finish the job.
Evaporate all the liquid off first, then filter the dry chalk away from the dry sorbitol.
MPM-052 · medium · application · seq 11 · seed:U01-G4/pool[25] · mcq4
In a sealed flask, a clear liquid and a white powder react, and a yellow solid appears. Why must the total mass after the change equal the total before?
Because the atoms are only rearranged — no atoms are created or destroyed, so the total mass stays the same. KEY
Because the yellow solid that appeared weighs exactly what the white powder weighed before.
Because the atoms destroyed and the atoms created in the reaction always happen to balance out exactly.
Because mass can change only when a gas forms, and no gas formed in this reaction.
MPM-053 · medium · application · seq 12 · seed:U01-G4.pool[27] (= MPM-053 gateItems[0], James curated demo_curated[3]) - instance freshened per SEED RULING (sulfur -> chlorine gas, zinc sulfide -> zinc chloride, 6.5+3.2=9.7 -> 6.1+6.6=12.7; zinc kept); appended sig-figs sentence dropped; structure/misconceptions/scaffold otherwise VERBATIM · numeric
In a sealed flask, 6.1 g of zinc reacts completely with 6.6 g of chlorine gas to form zinc chloride, the only new substance. What mass of zinc chloride forms in the flask? Give your answer in grams to one decimal place.
Answer: 12.7 g KEY
also accepted: 12.7 g
wrongValueDiagnostics
[
 {
  "value": 0.5,
  "misconception": "you subtracted the masses — both starting substances end up inside the new substance, so add them",
  "feedback": "This answer is wrong — you subtracted the masses — both starting substances end up inside the new substance, so add them"
 },
 {
  "value": 6.1,
  "misconception": "you carried over the zinc's mass alone — the chlorine's atoms are in the zinc chloride too",
  "feedback": "This answer is wrong — you carried over the zinc's mass alone — the chlorine's atoms are in the zinc chloride too"
 },
 {
  "value": 6.6,
  "misconception": "you carried over the chlorine's mass alone — the zinc's atoms are in the zinc chloride too",
  "feedback": "This answer is wrong — you carried over the chlorine's mass alone — the zinc's atoms are in the zinc chloride too"
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nmass of zinc = 6.1 g\nmass of chlorine = 6.6 g\nWrite down the equation:\ntotal mass before = total mass after\nIn this problem's substances:\nmass of zinc before + mass of chlorine before = mass of zinc chloride after\nMake the mass of zinc chloride the subject:\nmass of zinc chloride = mass of zinc + mass of chlorine\nSubstitute in the values, and calculate:\nmass of zinc chloride = 6.1 + 6.6\nmass of zinc chloride = 12.7 g\nSanity check: the answer must exceed each starting mass, and 12.7 g does.",
 "anticipatedWrong": [
  {
   "value": 0.5,
   "misconception": "you subtracted the masses — both starting substances end up inside the new substance, so add them",
   "check": {
    "expr": "6.6-6.1",
    "expected": 0.5
   },
   "feedback": "This answer is wrong — you subtracted the masses — both starting substances end up inside the new substance, so add them"
  },
  {
   "value": 6.1,
   "misconception": "you carried over the zinc's mass alone — the chlorine's atoms are in the zinc chloride too",
   "check": {
    "expr": "6.1",
    "expected": 6.1
   },
   "feedback": "This answer is wrong — you carried over the zinc's mass alone — the chlorine's atoms are in the zinc chloride too"
  },
  {
   "value": 6.6,
   "misconception": "you carried over the chlorine's mass alone — the zinc's atoms are in the zinc chloride too",
   "check": {
    "expr": "6.6",
    "expected": 6.6
   },
   "feedback": "This answer is wrong — you carried over the chlorine's mass alone — the zinc's atoms are in the zinc chloride too"
  }
 ]
}
MPM-053 · medium · application · seq 13 · seed:pool[28] (= MPM-053 gateItems[1] = demo_curated[4], James) — instance FRESHENED AT GATE ASSEMBLY per the strict SEED RULING (baking soda/white solid/water/carbon dioxide -> malachite/black solid/condensed liquid/unnamed final gas; values re-keyed 8.4/5.3/0.9 -> 11.1/8.0/0.9, answer 2.2 kept); doubled precision sentence kept; misconception classes and 5-step scaffold structure verbatim-in-structure · numeric
Heated strongly in a closed vessel, 11.1 g of powdered green malachite breaks down into 8.0 g of a black solid, a vapor that condenses into 0.9 g of liquid, and one final gas. What mass of that final gas is in the vessel at the end? Give your answer in grams to one decimal place. Give your answer to 2 significant figures.
Answer: 2.2 g KEY
wrongValueDiagnostics
[
 {
  "value": 3.1,
  "misconception": "you subtracted only the solid — subtract every known substance formed, the condensed liquid included",
  "feedback": "This answer is wrong — you subtracted only the solid — subtract every known substance formed, the condensed liquid included"
 },
 {
  "value": 8.9,
  "misconception": "you added the known masses formed and stopped — subtract that sum from the starting mass",
  "feedback": "This answer is wrong — you added the known masses formed and stopped — subtract that sum from the starting mass"
 },
 {
  "value": 20.0,
  "misconception": "you added everything together — the substances formed must total the starting mass, not exceed it",
  "feedback": "This answer is wrong — you added everything together — the substances formed must total the starting mass, not exceed it"
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nmass of malachite = 11.1 g\nmass of black solid = 8.0 g\nmass of condensed liquid = 0.9 g\nWrite down the equation:\ntotal mass before = total mass after\nIn this problem's substances:\nmass of malachite before = mass of black solid after + mass of condensed liquid after + mass of final gas after\nMake the mass of the final gas the subject:\nmass of final gas = mass of malachite − (mass of black solid + mass of condensed liquid)\nSubstitute in the values, and calculate:\nmass of final gas = 11.1 − (8.0 + 0.9)\nmass of final gas = 11.1 − 8.9\nmass of final gas = 2.2 g",
 "anticipatedWrong": [
  {
   "value": 3.1,
   "misconception": "you subtracted only the solid — subtract every known substance formed, the condensed liquid included",
   "check": {
    "expr": "11.1-8.0",
    "expected": 3.1
   },
   "feedback": "This answer is wrong — you subtracted only the solid — subtract every known substance formed, the condensed liquid included"
  },
  {
   "value": 8.9,
   "misconception": "you added the known masses formed and stopped — subtract that sum from the starting mass",
   "check": {
    "expr": "8.0+0.9",
    "expected": 8.9
   },
   "feedback": "This answer is wrong — you added the known masses formed and stopped — subtract that sum from the starting mass"
  },
  {
   "value": 20.0,
   "misconception": "you added everything together — the substances formed must total the starting mass, not exceed it",
   "check": {
    "expr": "11.1+8.0+0.9",
    "expected": 20.0
   },
   "feedback": "This answer is wrong — you added everything together — the substances formed must total the starting mass, not exceed it"
  }
 ]
}
MPM-053 · medium · application · seq 14 · seed:U01-G4/pool[29] (= MPM-053 gateItems[2] = demo_curated[5], James) — instance FRESHENED AT GATE ASSEMBLY per the strict SEED RULING (oxygen/aluminum oxide -> chlorine/aluminum chloride; aluminum KEPT — it appears in no scope lesson's corpus, preserving the seed's identity, the row12 zinc precedent); find-the-reactant structure, doubled precision sentence, scaffold, and misconception classes verbatim-in-structure · numeric
Aluminum burns in chlorine gas inside a sealed container, forming 34.1 g of aluminum chloride, the only new substance, from 6.9 g of aluminum. What mass of chlorine reacted? Give your answer in grams to one decimal place. Give your answer to 3 significant figures.
Answer: 27.2 g KEY
also accepted: 27.2 g
scaffold
[
 "Write down the values in the question:",
 "mass of aluminum chloride = 34.1 g",
 "mass of aluminum = 6.9 g",
 "Write down the equation:",
 "total mass before = total mass after",
 "In this problem's substances:",
 "mass of aluminum before + mass of chlorine before = mass of aluminum chloride after",
 "Make the mass of chlorine the subject:",
 "mass of chlorine = mass of aluminum chloride − mass of aluminum",
 "Substitute in the values, and calculate:",
 "mass of chlorine = 34.1 − 6.9",
 "mass of chlorine = 27.2 g"
]
wrongValueDiagnostics
[
 {
  "value": 41.0,
  "misconception": "you added instead of subtracting — the 34.1 g of aluminum chloride is the total after, so the chlorine is that total minus the aluminum",
  "feedback": "This answer is wrong — you added instead of subtracting; the 34.1 g of aluminum chloride is the total after, so the chlorine is that total minus the aluminum. 34.1 − 6.9 = 27.2 g."
 },
 {
  "value": 34.1,
  "misconception": "you gave the mass of the new substance as the answer — the chlorine is only part of it",
  "feedback": "This answer is wrong — you gave the mass of the new substance as the answer; the chlorine is only part of it. The aluminum's 6.9 g is in there too: 34.1 − 6.9 = 27.2 g."
 },
 {
  "value": 6.9,
  "misconception": "you repeated the aluminum's mass — the chlorine's mass is what remains of the total",
  "feedback": "This answer is wrong — you repeated the aluminum's mass; the chlorine's mass is what remains of the total. 34.1 − 6.9 = 27.2 g."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nmass of aluminum chloride = 34.1 g\nmass of aluminum = 6.9 g\nWrite down the equation:\ntotal mass before = total mass after\nIn this problem's substances:\nmass of aluminum before + mass of chlorine before = mass of aluminum chloride after\nMake the mass of chlorine the subject:\nmass of chlorine = mass of aluminum chloride − mass of aluminum\nSubstitute in the values, and calculate:\nmass of chlorine = 34.1 − 6.9\nmass of chlorine = 27.2 g",
 "anticipatedWrong": [
  {
   "value": 41.0,
   "misconception": "you added instead of subtracting — the 34.1 g of aluminum chloride is the total after, so the chlorine is that total minus the aluminum",
   "feedback": "This answer is wrong — you added instead of subtracting; the 34.1 g of aluminum chloride is the total after, so the chlorine is that total minus the aluminum. 34.1 − 6.9 = 27.2 g."
  },
  {
   "value": 34.1,
   "misconception": "you gave the mass of the new substance as the answer — the chlorine is only part of it",
   "feedback": "This answer is wrong — you gave the mass of the new substance as the answer; the chlorine is only part of it. The aluminum's 6.9 g is in there too: 34.1 − 6.9 = 27.2 g."
  },
  {
   "value": 6.9,
   "misconception": "you repeated the aluminum's mass — the chlorine's mass is what remains of the total",
   "feedback": "This answer is wrong — you repeated the aluminum's mass; the chlorine's mass is what remains of the total. 34.1 − 6.9 = 27.2 g."
  }
 ]
}
MPM-054 · medium · application · seq 15 · seed:U01-G4/pool[32] (= MPM-054 gateItems[2], James) - verbatim except one word deleted from the key (see SEED EDIT flag) · mcq4
Bread dough loses mass while it bakes in an open oven. A baker claims baking destroys matter. What actually happens?
Vapor and gases escape from the dough, carrying their mass — nothing is destroyed. KEY
The oven's heat converts the missing mass into the energy that browns the crust.
The claim is right — high oven temperatures really do destroy a little matter.
Baking makes the bread lighter for its size, and less dense always means less mass.
MPM-055 · medium · application · seq 16 · seed:U01-G4/pool[33] (= MPM-055 gateItems[0], James curated demo_curated[6]) · mcq4
Classify the statement, which sums up generations of measurements: 'Every sample of a pure substance has the same density, whatever the sample's size.'
A law KEY
A theory
A hypothesis
An untestable opinion
MPM-044 · hard · transfer · seq 17 · seed:U01-G4/pool[2] · mcq4
Brass is a solid mixture of copper atoms and zinc atoms mixed throughout. Which statement must be true?
The copper and zinc each keep their own properties, and a physical change could in principle separate them. KEY
The copper and zinc atoms are chemically joined, so brass is a new substance with no copper or zinc left in it.
Separating brass into copper and zinc would be a chemical change, because the mixture is a solid.
Melting brass would chemically join the copper and zinc into a compound.
MPM-048 · hard · transfer · seq 18 · seed:U01-G4/pool[13] · mcq4
A student runs the same ink twice — once for five minutes and once for twenty. In the longer run every spot sits higher, but the order of the spots is unchanged. Why is the order fixed?
Each dye keeps its own strength of hold on the paper, and that strength sets the order — more time moves every spot, but cannot swap them. KEY
The dyes all stopped moving after the first five minutes, so the extra time changed nothing.
A longer run usually gives the dyes enough time to trade places on the strip, and these particular dyes simply did not get that far.
Extra time changes which dye holds to the paper most strongly, so the order is a matter of luck.
MPM-052 · hard · transfer · seq 19 · authored - FRESHENED from seed pool[24] (= MPM-052 gateItems[0], James; blueprint + must_freshen_instance direct an instance swap on EVERY form incl. A): stem skeleton, key structure, and all three misconception classes kept; instance = recorded antimony + chlorine · mcq4
A lump of a brittle silvery-gray metal is sealed in a flask of pale yellow-green gas. Slowly the gas's color fades while a white crust grows over the lump. The flask's total mass stays constant, yet the lump itself gets heavier. Explain.
Atoms from the flask's own gas joined the lump, moving mass from the gas to the solid. KEY
The white crust created brand-new atoms as it spread across the lump's surface.
Heat released by the slow change soaked into the lump and added its mass to it.
Moisture from the room seeped in through the glass and soaked into the growing crust.
MPM-054 · hard · transfer · seq 20 · authored (fresh combined two-flow instance; no MPM-054 hard seed exists) · mcq4
A crushed, dark shiny ore is roasted in an open pan over a burner. During the roasting, a gas from the surroundings combines with the solid, while a different, sharp-smelling gas forms and drifts off. The dull yellowish solid left in the pan weighs slightly less than the crushed ore did. Which statement correctly accounts for the mass change?
Nothing was destroyed — the gas that escaped carried away more mass than the arriving gas added to the solid, so the pan's contents ended slightly lighter. KEY
The strong heating destroyed part of the ore's matter, and that destroyed mass no longer exists in any form.
The law of conservation of mass stops holding when a change happens in an open pan instead of a sealed container.
Since a gas was combining with the solid throughout the roasting, the solid should have ended heavier, so the final weighing must be wrong.
MPM-050 · medium · application · seq 21 · authored (ADJ-G4-3: U01-G4 has no production seeds; blueprint-pinned rotation - recover all three components) · frq
On a compounding lab's bench, a beaker holds a three-component mixture: fine kaolin powder, a solid that never dissolves; mannitol, a sweet-tasting solid that has dissolved completely; and the liquid both solids are in. All three components must be recovered - the kaolin, the mannitol, and the pure liquid - each on its own. A solid caught on the filter paper counts as recovered once it has dried there.
On a compounding lab's bench, a beaker holds a three-component mixture: fine kaolin powder, a solid that never dissolves; mannitol, a sweet-tasting solid that has dissolved completely; and the liquid both solids are in. All three components must be recovered - the kaolin, the mannitol, and the pure liquid - each on its own. A solid caught on the filter paper counts as recovered once it has dried there. (a) Plan the separation. Name the technique for each step of your plan, in the order you would carry them out. (b) Justify each step of your plan. For each technique you named, state the property difference between the components that makes it work here. (c) Track every component. State where each of the three components - the kaolin, the mannitol, and the liquid - ends up when your plan is finished, including any component that is not kept.
Part a. Plan the separation. Name the technique for each step of your plan, in the order you would carry them out.
Model: Step 1 - filtration: pour the whole mixture through filter paper. Step 2 - distillation: distill the liquid that passed through the paper.
Part b. Justify each step of your plan. For each technique you named, state the property difference between the components that makes it work here.
Model: Filtration works because the kaolin never dissolves - its particles are too large to pass through the filter paper's holes, while the liquid, still carrying the dissolved mannitol, passes through. Distillation is chosen for the second step because the liquid must be kept: the liquid boils away, its gas is cooled back into a liquid and collected, while the mannitol stays far below its own boiling point and stays behind in the heated flask. An open dish would lose the liquid to the air.
Part c. Track every component. State where each of the three components - the kaolin, the mannitol, and the liquid - ends up when your plan is finished, including any component that is not kept.
Model: Kaolin - collected on the filter paper and left to dry there. Mannitol - stays behind in the heated flask when the liquid boils away. The liquid - leaves as a gas, is cooled back into a liquid, and is collected in the collecting flask.
Full model answer. (a) Step 1 - filtration: pour the whole mixture through filter paper. Step 2 - distillation: distill the liquid that passed through the paper. (b) Filtration works because the kaolin never dissolves - its particles are too large to pass through the filter paper's holes, while the liquid, still carrying the dissolved mannitol, passes through. Distillation is chosen for the second step because the liquid must be kept: the liquid boils away, its gas is cooled back into a liquid and collected, while the mannitol stays far below its own boiling point and stays behind in the heated flask. An open dish would lose the liquid to the air. (c) Kaolin - collected on the filter paper and left to dry there. Mannitol - stays behind in the heated flask when the liquid boils away. The liquid - leaves as a gas, is cooled back into a liquid, and is collected in the collecting flask.

Form B

MPM-044 · easy · recall · seq 1 · authored · mcq4
A baker stirs chocolate chips through a bowl of shredded coconut until the two foods are evenly mixed. Why can the chips and the coconut still be separated from each other?
Mixing changed neither food — the chips and the coconut each keep their own properties, so a physical change can pull them apart. KEY
Stirring joined the chocolate and the coconut into one new substance, and pulling them apart means undoing that change.
The chips and the coconut each lose their own properties in the bowl and get them back once they are parted.
Picking the chips back out of the coconut is a chemical change that turns each food back into its original substance.
MPM-046 · easy · recall · seq 2 · authored (fresh instance, parallel to the seed's structure and misconception classes) · mcq4
An uncovered beaker of glucose solution — a white solid fully dissolved in a liquid — slowly evaporates on a shelf in a warm lab over several days. Which particles leave the beaker?
The liquid's particles only KEY
Particles of both the liquid and the dissolved glucose
The dissolved glucose's particles only
No particles leave the beaker
MPM-051 · easy · recall · seq 3 · authored · mcq4
Finish this statement of the law of conservation of mass: 'In a closed container, the total mass …'
stays the same during any physical or chemical change. KEY
stays the same during physical changes, but rises or falls during chemical changes.
stays the same only when the change produces no gas.
falls a little during every change, because changing uses up some matter.
MPM-055 · easy · recall · seq 4 · authored · mcq4
In science, what is a theory?
An explanation of why things happen, supported by extensive evidence. KEY
A well-tested statement that describes what always happens.
A proposed explanation that has not yet been put to the test.
A hypothesis that has been proven true beyond any need for evidence.
MPM-045 · medium · application · seq 5 · seed:U01-G4/pool[4] · mcq4
Brewed espresso contains dissolved caffeine. Why can filtration not produce caffeine-free espresso?
The dissolved caffeine's particles are as small as the liquid's particles, so they pass through the filter's holes with the liquid. KEY
The caffeine in espresso is chemically joined to the liquid, so no physical change can remove it.
Filtration works only on mixtures of two solids, and espresso is a solid dissolved in a liquid.
It can — passing the espresso through the same filter paper several times removes a little more of the caffeine on each pass.
MPM-047 · medium · application · seq 6 · seed:U01-G4/pool[11] · mcq4
A biodiesel workshop is left with a mixture of two liquids: methanol, which boils at 65 °C, and thick glycerin, which boils at 290 °C. The mixture is distilled slowly. What collects first?
Mostly methanol. KEY
Mostly glycerin.
Both components together, in the mixture's original proportions.
Nothing.
MPM-051 · medium · application · seq 7 · authored · numeric
A sealed glass bottle holds 46.2 g of cooking oil and 39.1 g of lemon juice. The bottle is shaken hard until the two liquids mix into a cloudy dressing. What is the total mass of the sealed bottle's contents after the shaking? Give your answer in grams to one decimal place.
Answer: 85.3 g KEY
also accepted: 85.3 g
scaffold
[
 "Write down the values in the question:",
 "mass of oil = 46.2 g",
 "mass of lemon juice = 39.1 g",
 "The bottle is sealed, so the law of conservation of mass applies:",
 "total mass before = total mass after",
 "In this problem's substances:",
 "mass of oil + mass of lemon juice = total mass after",
 "Substitute in the values, and calculate:",
 "total mass after = 46.2 + 39.1",
 "total mass after = 85.3 g"
]
wrongValueDiagnostics
[
 {
  "value": 39.1,
  "misconception": "you dropped the oil's mass from the total — everything sealed inside counts",
  "feedback": "This answer is wrong — you dropped the oil's mass from the total; everything sealed inside counts, before and after. The bottle holds the oil's 46.2 g and the lemon juice's 39.1 g: 46.2 + 39.1 = 85.3 g."
 },
 {
  "value": 7.1,
  "misconception": "you subtracted the lemon juice instead of adding it — both liquids are inside the sealed bottle",
  "feedback": "This answer is wrong — you subtracted the lemon juice instead of adding it; both liquids are inside the sealed bottle. Total mass before = total mass after: 46.2 + 39.1 = 85.3 g."
 },
 {
  "value": 46.2,
  "misconception": "you carried over the oil's mass alone — the total covers everything in the bottle",
  "feedback": "This answer is wrong — you carried over the oil's mass alone; the total covers everything in the bottle. The lemon juice's 39.1 g counts too: 46.2 + 39.1 = 85.3 g."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nmass of oil = 46.2 g\nmass of lemon juice = 39.1 g\nThe bottle is sealed, so the law of conservation of mass applies:\ntotal mass before = total mass after\nIn this problem's substances:\nmass of oil + mass of lemon juice = total mass after\nSubstitute in the values, and calculate:\ntotal mass after = 46.2 + 39.1\ntotal mass after = 85.3 g\nShaking the liquids together is a physical change, and the law covers any physical or chemical change — sealed in, the total cannot change.",
 "anticipatedWrong": [
  {
   "value": 39.1,
   "misconception": "you dropped the oil's mass from the total — everything sealed inside counts",
   "feedback": "This answer is wrong — you dropped the oil's mass from the total; everything sealed inside counts, before and after. The bottle holds the oil's 46.2 g and the lemon juice's 39.1 g: 46.2 + 39.1 = 85.3 g."
  },
  {
   "value": 7.1,
   "misconception": "you subtracted the lemon juice instead of adding it — both liquids are inside the sealed bottle",
   "feedback": "This answer is wrong — you subtracted the lemon juice instead of adding it; both liquids are inside the sealed bottle. Total mass before = total mass after: 46.2 + 39.1 = 85.3 g."
  },
  {
   "value": 46.2,
   "misconception": "you carried over the oil's mass alone — the total covers everything in the bottle",
   "feedback": "This answer is wrong — you carried over the oil's mass alone; the total covers everything in the bottle. The lemon juice's 39.1 g counts too: 46.2 + 39.1 = 85.3 g."
  }
 ]
}
MPM-049 · medium · application · seq 8 · seed:U01-G4/pool[16] (instance+count freshened per must_freshen_instance) · mcq4
The figure shows the chromatogram of a navy fountain-pen ink. How many dyes does the ink contain?
FIGURE (chromatogram · stimulus) — startLineLabel: "start line (pencil)" · waterLineLabel: "highest water level" · spots: [{"color": "violet", "position": "high on the strip"}, {"color": "blue", "position": "upper middle"}, {"color": "turquoise", "position": "lower middle"}, {"c… · renderStyle: "single strip, well-separated round spots, labels in-diagram"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "chromatogram",
  "startLineLabel": "start line (pencil)",
  "waterLineLabel": "highest water level",
  "spots": [
   {
    "color": "violet",
    "position": "high on the strip"
   },
   {
    "color": "blue",
    "position": "upper middle"
   },
   {
    "color": "turquoise",
    "position": "lower middle"
   },
   {
    "color": "magenta",
    "position": "low on the strip, above the start line"
   },
   {
    "color": "dark gray",
    "position": "on the start line"
   }
  ],
  "renderStyle": "single strip, well-separated round spots, labels in-diagram"
 }
}
Five KEY
Four
Six
One
MPM-050 · medium · application · seq 9 · authored (inverse job-pick, instance-free; target technique = filtration) · mcq4
Which separation job calls for filtration rather than any other technique you have seen?
Getting an insoluble powder back from the liquid it is stirred through KEY
Getting a dissolved solid back from the clear solution it is dissolved in
Getting the pure liquid back from a solution of a solid dissolved in it
Finding out whether the color of a liquid comes from one dissolved substance or several
MPM-050 · medium · application · seq 10 · seed:U01-G4.pool[20] (= MPM-050 gateItems[2] = demo_curated[2], James; structure + misconception set kept, instance freshened per must_freshen_instance flag: salty muddy water -> ascorbic acid solution contaminated with talcum powder) · mcq4
A beaker holds a solution of lactose, a white powder used as a tablet filler — the lactose fully dissolved, none of it solid. Fine talcum powder, which never dissolves, is then spilled into the beaker. The technician still wants clean, dry lactose back. Which plan recovers it?
Filter the talcum powder out first, then gently warm the liquid that passed through in a shallow dish until only dry lactose is left. KEY
Warm the beaker gently just as it is — as the liquid escapes, the lactose and the talcum powder settle out cleanly apart in the dish.
Filter the talcum powder out, then pour the liquid through a second, finer paper to catch the lactose as dry crystals.
Distill the beaker's contents and collect the lactose where the drips gather at the tube's cooled end.
MPM-052 · medium · application · seq 11 · authored (fresh abstract instance, parallel to the seed's structure and misconception classes) · mcq4
In a sealed bottle, a pale blue solution is mixed with a colorless solution. A white solid settles to the bottom, and the liquid above it stays blue. Why must the total mass after the change equal the total before?
Because the atoms are only rearranged — no atoms are created or destroyed, so the total mass stays the same. KEY
Because the white solid that settled out weighs exactly what the colorless solution weighed before.
Because the atoms destroyed when the two solutions reacted are exactly replaced by new atoms created in the solid.
Because mass can change only when a gas is produced, and this reaction produced no gas.
MPM-053 · medium · application · seq 12 · authored (fresh instance, parallel to the seed's structure and misconception classes) · numeric
In a sealed container, 7.8 g of magnesium reacts completely with 3.0 g of nitrogen gas to form magnesium nitride, the only new substance. What mass of magnesium nitride forms in the container? Give your answer in grams to one decimal place.
Answer: 10.8 g KEY
also accepted: 10.8 g
wrongValueDiagnostics
[
 {
  "value": 4.8,
  "misconception": "you subtracted the masses — both starting substances end up inside the new substance, so add them",
  "feedback": "This answer is wrong — you subtracted the masses — both starting substances end up inside the new substance, so add them"
 },
 {
  "value": 7.8,
  "misconception": "you carried over the magnesium's mass alone — the nitrogen's atoms are in the magnesium nitride too",
  "feedback": "This answer is wrong — you carried over the magnesium's mass alone — the nitrogen's atoms are in the magnesium nitride too"
 },
 {
  "value": 3.0,
  "misconception": "you carried over the nitrogen's mass alone — the magnesium's atoms are in the magnesium nitride too",
  "feedback": "This answer is wrong — you carried over the nitrogen's mass alone — the magnesium's atoms are in the magnesium nitride too"
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nmass of magnesium = 7.8 g\nmass of nitrogen = 3.0 g\nWrite down the equation:\ntotal mass before = total mass after\nIn this problem's substances:\nmass of magnesium before + mass of nitrogen before = mass of magnesium nitride after\nMake the mass of magnesium nitride the subject:\nmass of magnesium nitride = mass of magnesium + mass of nitrogen\nSubstitute in the values, and calculate:\nmass of magnesium nitride = 7.8 + 3.0\nmass of magnesium nitride = 10.8 g\nSanity check: the answer must exceed each starting mass, and 10.8 g does.",
 "anticipatedWrong": [
  {
   "value": 4.8,
   "misconception": "you subtracted the masses — both starting substances end up inside the new substance, so add them",
   "check": {
    "expr": "7.8-3.0",
    "expected": 4.8
   },
   "feedback": "This answer is wrong — you subtracted the masses — both starting substances end up inside the new substance, so add them"
  },
  {
   "value": 7.8,
   "misconception": "you carried over the magnesium's mass alone — the nitrogen's atoms are in the magnesium nitride too",
   "check": {
    "expr": "7.8",
    "expected": 7.8
   },
   "feedback": "This answer is wrong — you carried over the magnesium's mass alone — the nitrogen's atoms are in the magnesium nitride too"
  },
  {
   "value": 3.0,
   "misconception": "you carried over the nitrogen's mass alone — the magnesium's atoms are in the magnesium nitride too",
   "check": {
    "expr": "3.0",
    "expected": 3.0
   },
   "feedback": "This answer is wrong — you carried over the nitrogen's mass alone — the magnesium's atoms are in the magnesium nitride too"
  }
 ]
}
MPM-053 · medium · application · seq 13 · authored · numeric
Warmed gently in a closed flask, 23.7 g of ammonium bicarbonate — a raising agent used in some cookie recipes — breaks down entirely into ammonia and two other gases. As the flask cools, one of those gases condenses into 5.4 g of liquid; the other, 13.2 g of it, stays a gas. What mass of ammonia is in the flask at the end? Give your answer in grams to one decimal place.
Answer: 5.1 g KEY
wrongValueDiagnostics
[
 {
  "value": 10.5,
  "misconception": "you subtracted only the gas that stayed a gas — subtract every known substance formed, the condensed one included",
  "feedback": "This answer is wrong — you subtracted only the gas that stayed a gas — subtract every known substance formed, the condensed one included"
 },
 {
  "value": 18.6,
  "misconception": "you added the known masses formed and stopped — subtract that sum from the starting mass",
  "feedback": "This answer is wrong — you added the known masses formed and stopped — subtract that sum from the starting mass"
 },
 {
  "value": 42.3,
  "misconception": "you added everything together — the substances formed must total the starting mass, not exceed it",
  "feedback": "This answer is wrong — you added everything together — the substances formed must total the starting mass, not exceed it"
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nmass of ammonium bicarbonate = 23.7 g\nmass of condensed gas = 5.4 g\nmass of uncondensed gas = 13.2 g\nWrite down the equation:\ntotal mass before = total mass after\nIn this problem's substances:\nmass of ammonium bicarbonate before = mass of ammonia after + mass of condensed gas after + mass of uncondensed gas after\nMake the mass of ammonia the subject:\nmass of ammonia = mass of ammonium bicarbonate − (mass of condensed gas + mass of uncondensed gas)\nSubstitute in the values, and calculate:\nmass of ammonia = 23.7 − (5.4 + 13.2)\nmass of ammonia = 23.7 − 18.6\nmass of ammonia = 5.1 g",
 "anticipatedWrong": [
  {
   "value": 10.5,
   "misconception": "you subtracted only the gas that stayed a gas — subtract every known substance formed, the condensed one included",
   "check": {
    "expr": "23.7-13.2",
    "expected": 10.5
   },
   "feedback": "This answer is wrong — you subtracted only the gas that stayed a gas — subtract every known substance formed, the condensed one included"
  },
  {
   "value": 18.6,
   "misconception": "you added the known masses formed and stopped — subtract that sum from the starting mass",
   "check": {
    "expr": "5.4+13.2",
    "expected": 18.6
   },
   "feedback": "This answer is wrong — you added the known masses formed and stopped — subtract that sum from the starting mass"
  },
  {
   "value": 42.3,
   "misconception": "you added everything together — the substances formed must total the starting mass, not exceed it",
   "check": {
    "expr": "23.7+5.4+13.2",
    "expected": 42.3
   },
   "feedback": "This answer is wrong — you added everything together — the substances formed must total the starting mass, not exceed it"
  }
 ]
}
MPM-053 · medium · application · seq 14 · authored (unnamed substances; real basis titanium + nitrogen -> titanium nitride, ratio-true at one decimal) · numeric
A gray metal powder burns in a colorless gas inside a sealed container, forming 18.6 g of a single golden solid, the only new substance, from 14.4 g of the metal. What mass of the gas reacted? Give your answer in grams to one decimal place.
Answer: 4.2 g KEY
also accepted: 4.2 g
scaffold
[
 "Write down the values in the question:",
 "mass of golden solid = 18.6 g",
 "mass of metal = 14.4 g",
 "Write down the equation:",
 "total mass before = total mass after",
 "In this problem's substances:",
 "mass of metal before + mass of gas before = mass of golden solid after",
 "Make the mass of gas the subject:",
 "mass of gas = mass of golden solid − mass of metal",
 "Substitute in the values, and calculate:",
 "mass of gas = 18.6 − 14.4",
 "mass of gas = 4.2 g"
]
wrongValueDiagnostics
[
 {
  "value": 33.0,
  "misconception": "you added instead of subtracting — the 18.6 g of golden solid is the total after, so the gas is that total minus the metal",
  "feedback": "This answer is wrong — you added instead of subtracting; the 18.6 g of golden solid is the total after, so the gas is that total minus the metal. 18.6 − 14.4 = 4.2 g."
 },
 {
  "value": 18.6,
  "misconception": "you gave the mass of the new substance as the answer — the gas is only part of it",
  "feedback": "This answer is wrong — you gave the mass of the new substance as the answer; the gas is only part of it. The metal's 14.4 g is in there too: 18.6 − 14.4 = 4.2 g."
 },
 {
  "value": 14.4,
  "misconception": "you repeated the metal's mass — the gas's mass is what remains of the total",
  "feedback": "This answer is wrong — you repeated the metal's mass; the gas's mass is what remains of the total. 18.6 − 14.4 = 4.2 g."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nmass of golden solid = 18.6 g\nmass of metal = 14.4 g\nWrite down the equation:\ntotal mass before = total mass after\nIn this problem's substances:\nmass of metal before + mass of gas before = mass of golden solid after\nMake the mass of gas the subject:\nmass of gas = mass of golden solid − mass of metal\nSubstitute in the values, and calculate:\nmass of gas = 18.6 − 14.4\nmass of gas = 4.2 g",
 "anticipatedWrong": [
  {
   "value": 33.0,
   "misconception": "you added instead of subtracting — the 18.6 g of golden solid is the total after, so the gas is that total minus the metal",
   "feedback": "This answer is wrong — you added instead of subtracting; the 18.6 g of golden solid is the total after, so the gas is that total minus the metal. 18.6 − 14.4 = 4.2 g."
  },
  {
   "value": 18.6,
   "misconception": "you gave the mass of the new substance as the answer — the gas is only part of it",
   "feedback": "This answer is wrong — you gave the mass of the new substance as the answer; the gas is only part of it. The metal's 14.4 g is in there too: 18.6 − 14.4 = 4.2 g."
  },
  {
   "value": 14.4,
   "misconception": "you repeated the metal's mass — the gas's mass is what remains of the total",
   "feedback": "This answer is wrong — you repeated the metal's mass; the gas's mass is what remains of the total. 18.6 − 14.4 = 4.2 g."
  }
 ]
}
MPM-054 · medium · application · seq 15 · seed:U01-G4/pool[31] (= MPM-054 gateItems[1], James) - instance freshened per must_freshen_instance; distractor 2 reworded to clear own-lesson 'air' (see flags); key, distractors 1/3, misconceptions, and explanation verbatim · mcq4
To check the law of conservation of mass, a student drops crushed eggshell into a beaker of dilute acid, where it fizzes. Why must the container be sealed?
The fizzing makes a gas, and in an open container the gas escapes, taking its mass with it. KEY
The gas made by the fizzing weighs nothing at all, so sealing the container makes no difference.
An open container lets the pressure of the room press down on the contents and disturb the balance reading.
A sealed container is needed only when the change being checked is a physical one.
MPM-055 · medium · application · seq 16 · seed:U01-G4/pool[34] (= MPM-055 gateItems[1], James curated demo_curated[7]) · mcq4
Classify the statement, which chemists have confirmed in countless experiments: 'A compound's properties differ from its elements' properties because chemically joining atoms makes a new substance.'
A theory KEY
A law
A hypothesis
An opinion
MPM-044 · hard · transfer · seq 17 · authored (fresh alloy instance, parallel to the seed's structure and misconception classes) · mcq4
The heating wire inside a toaster is made of nichrome, a solid mixture of nickel atoms and chromium atoms mixed throughout. Which statement must be true?
The nickel and chromium each keep their own properties, and a physical change could in principle separate them. KEY
Separating the wire into nickel and chromium would be a chemical change, because the mixture is a solid.
Melting the nichrome would chemically join the nickel and chromium into a compound.
The nickel and chromium atoms are chemically joined, so nichrome is a new substance with no nickel or chromium left in it.
MPM-048 · hard · transfer · seq 18 · authored (fresh sample + run-time instance, parallel to the seed's structure and misconception classes) · mcq4
A student runs the same fabric dye, sold for tie-dyeing clothes, on a paper strip twice — once for six minutes and once for eighteen. In the longer run every spot sits higher, but the order of the spots is unchanged. Why is the order fixed?
Each dye keeps its own strength of hold on the paper, and that strength sets the order — more time moves every spot, but cannot swap them. KEY
A longer run usually gives the dyes enough time to trade places on the strip, and these particular dyes simply did not get that far.
Extra time changes which dye holds to the paper most strongly, so the order is a matter of luck.
The dyes all stopped moving after the first six minutes, so the extra time changed nothing.
MPM-052 · hard · transfer · seq 19 · authored (fresh instance, parallel to pool[24]'s structure and misconception classes) · mcq4
A freshly cut piece of soft silvery metal is sealed in a jar of colorless gas. Over several days a dark reddish-brown crust creeps across the metal. The jar's total mass stays constant, yet the metal itself gets heavier. Explain.
Atoms from the jar's own gas joined the metal, moving mass from the gas to the solid. KEY
The dark crust created brand-new atoms as it crept across the metal's surface.
Warmth released by the slow change sank into the metal and added its mass to it.
Gas from outside slowly leaked in through the glass and joined the growing crust.
MPM-054 · hard · transfer · seq 20 · authored (fresh combined two-flow instance; no MPM-054 hard seed exists) · mcq4
A pale pink powder is heated strongly in an open crucible. As the powder darkens, a gas from the surroundings combines with the solid while a different, odorless gas escapes. Weighed again after cooling, the crucible and its contents come out slightly lighter than at the start. Which statement correctly accounts for the result?
Nothing was destroyed — the escaping gas took away more mass than the arriving gas added to the solid, so the crucible and its contents ended slightly lighter. KEY
The fierce heating in the crucible destroyed a small amount of the powder's matter, removing it from existence.
The law of conservation of mass does not apply to a change carried out in an open crucible.
Because a gas was joining the solid the whole time it darkened, the crucible should have come out heavier — the balance must have drifted.
MPM-050 · medium · application · seq 21 · authored (ADJ-G4-3; blueprint-pinned rotation - recover the two solids only) · frq
In a furniture-restoration workshop, a tub holds a three-component mixture: slate dust, a solid that cannot dissolve; oxalic acid, a wood-bleaching powder that has dissolved completely; and the liquid both solids are in. Both solids must be recovered, each on its own - the slate dust and the oxalic acid. The liquid itself is not needed and should not be kept. A solid caught on the filter paper counts as recovered once it has dried there.
In a furniture-restoration workshop, a tub holds a three-component mixture: slate dust, a solid that cannot dissolve; oxalic acid, a wood-bleaching powder that has dissolved completely; and the liquid both solids are in. Both solids must be recovered, each on its own - the slate dust and the oxalic acid. The liquid itself is not needed and should not be kept. A solid caught on the filter paper counts as recovered once it has dried there. (a) Plan the separation. Name the technique for each step of your plan, in the order you would carry them out. (b) Justify each step of your plan. For each technique you named, state the property difference between the components that makes it work here. (c) Track every component. State where each of the three components - the slate dust, the oxalic acid, and the liquid - ends up when your plan is finished, including any component that is not kept.
Part a. Plan the separation. Name the technique for each step of your plan, in the order you would carry them out.
Model: Step 1 - filtration: pour the whole mixture through filter paper. Step 2 - evaporation: gently heat the liquid that passed through the paper in an open dish until only dry oxalic acid is left.
Part b. Justify each step of your plan. For each technique you named, state the property difference between the components that makes it work here.
Model: Filtration works because the slate dust cannot dissolve - its particles are too large to pass through the filter paper's holes, while the liquid, still carrying the dissolved oxalic acid, passes through. Evaporation is chosen for the second step because the dissolved oxalic acid must be kept and the liquid is not needed: the liquid's particles escape into the air as a gas while the oxalic acid's particles stay behind in the dish.
Part c. Track every component. State where each of the three components - the slate dust, the oxalic acid, and the liquid - ends up when your plan is finished, including any component that is not kept.
Model: Slate dust - collected on the filter paper and left to dry there. Oxalic acid - left as a dry solid in the dish when the last of the liquid has gone. The liquid - lost to the air as a gas, which the goal allows.
Full model answer. (a) Step 1 - filtration: pour the whole mixture through filter paper. Step 2 - evaporation: gently heat the liquid that passed through the paper in an open dish until only dry oxalic acid is left. (b) Filtration works because the slate dust cannot dissolve - its particles are too large to pass through the filter paper's holes, while the liquid, still carrying the dissolved oxalic acid, passes through. Evaporation is chosen for the second step because the dissolved oxalic acid must be kept and the liquid is not needed: the liquid's particles escape into the air as a gas while the oxalic acid's particles stay behind in the dish. (c) Slate dust - collected on the filter paper and left to dry there. Oxalic acid - left as a dry solid in the dish when the last of the liquid has gone. The liquid - lost to the air as a gas, which the goal allows.

Form C

MPM-044 · easy · recall · seq 1 · authored · mcq4
Poppy seeds are stirred through a bag of white flour until the tiny black seeds are spread evenly through the powder. Why can the seeds and the flour still be separated from each other?
Mixing changed neither one — the seeds and the flour each keep their own properties, so a physical change can pull them apart. KEY
Stirring joined the seeds and the flour into one new substance, and separating them would mean undoing that change.
The seeds and the flour each lose their own properties while mixed together in the bag and regain them once they are apart.
Sorting the seeds back out of the flour is a chemical change that turns each one back into its original substance.
MPM-046 · easy · recall · seq 2 · authored (fresh instance, parallel to the seed's structure and misconception classes) · mcq4
A saucer of borax solution — a powdery solid dissolved in a liquid — is left open in a warm classroom and slowly evaporates. Which particles leave the saucer?
The liquid's particles only KEY
Particles of both the liquid and the dissolved borax
The dissolved borax's particles only
No particles leave the saucer
MPM-051 · easy · recall · seq 3 · authored · mcq4
Four students each write down, from memory, what the law of conservation of mass says. Which version is correct?
In a closed container, the total mass stays the same during any physical or chemical change. KEY
In a closed container, the total mass stays the same during a physical change, but burning inside it destroys a small amount of mass.
In a closed container, the total mass stays the same because nothing at all can happen inside a sealed container.
In a closed container, the total mass of the solids and liquids stays the same; any gas inside is left out of the total.
MPM-055 · easy · recall · seq 4 · authored · mcq4
In science, what is a hypothesis?
A testable proposed explanation that has not yet been tested. KEY
An explanation of why things happen, supported by extensive evidence.
A well-tested statement that describes what always happens.
Any guess about nature, even one that no test could ever check.
MPM-045 · medium · application · seq 5 · authored · mcq4
A pot of chicken broth is flecked with crumbled dried herbs, which do not dissolve in it. The warm broth is passed through a paper filter into an empty jar. What happens?
The herbs collect on the paper, and the broth drips through into the jar below. KEY
The paper soaks up the broth and holds it, so the herbs and the broth both stay on the paper.
Everything ends up in the jar — pouring presses the herbs through the paper along with the broth.
The broth stays behind on the paper, and the herbs wash through into the jar below.
MPM-047 · medium · application · seq 6 · authored · mcq4
A stockroom bottle holds a mixture of equal masses of two liquids: hexane, which boils at 69 °C, and toluene, which boils at 111 °C. The mixture is distilled slowly until about half of it has boiled away. Which liquid makes up most of what now remains in the heated flask?
Mostly toluene, because the hexane boiled away first and was collected. KEY
Mostly hexane, because the liquid with the higher boiling point escapes the flask first.
Half hexane and half toluene, because slow boiling removes both liquids at a single shared rate.
Impossible to say, because it depends on which liquid the bottle holds more of.
MPM-051 · medium · application · seq 7 · authored · numeric
A sealed glow stick holds 13.6 g of one liquid, and 4.9 g of a second liquid kept apart in a thin inner tube. When the stick is snapped, the two liquids mix, react, and give off light. What is the total mass of the sealed glow stick's contents after the reaction? Give your answer in grams to one decimal place.
Answer: 18.5 g KEY
also accepted: 18.5 g
scaffold
[
 "Write down the values in the question:",
 "mass of first liquid = 13.6 g",
 "mass of second liquid = 4.9 g",
 "The glow stick is sealed, so the law of conservation of mass applies:",
 "total mass before = total mass after",
 "In this problem's substances:",
 "mass of first liquid + mass of second liquid = total mass after",
 "Substitute in the values, and calculate:",
 "total mass after = 13.6 + 4.9",
 "total mass after = 18.5 g"
]
wrongValueDiagnostics
[
 {
  "value": 4.9,
  "misconception": "you dropped the first liquid's mass from the total — everything sealed inside counts",
  "feedback": "This answer is wrong — you dropped the first liquid's mass from the total; everything sealed inside counts, before and after. The stick holds 13.6 g of one liquid and 4.9 g of the other: 13.6 + 4.9 = 18.5 g."
 },
 {
  "value": 8.7,
  "misconception": "you subtracted the second liquid instead of adding it — both liquids are inside the sealed stick",
  "feedback": "This answer is wrong — you subtracted the second liquid instead of adding it; both liquids are inside the sealed stick. Total mass before = total mass after: 13.6 + 4.9 = 18.5 g."
 },
 {
  "value": 13.6,
  "misconception": "you carried over the first liquid's mass alone — the total covers everything in the stick",
  "feedback": "This answer is wrong — you carried over the first liquid's mass alone; the total covers everything in the stick. The second liquid's 4.9 g counts too: 13.6 + 4.9 = 18.5 g."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nmass of first liquid = 13.6 g\nmass of second liquid = 4.9 g\nThe glow stick is sealed, so the law of conservation of mass applies:\ntotal mass before = total mass after\nIn this problem's substances:\nmass of first liquid + mass of second liquid = total mass after\nSubstitute in the values, and calculate:\ntotal mass after = 13.6 + 4.9\ntotal mass after = 18.5 g\nThe stick gives off light, but light is not matter — the law is about matter, and no matter gets in or out of the sealed stick.",
 "anticipatedWrong": [
  {
   "value": 4.9,
   "misconception": "you dropped the first liquid's mass from the total — everything sealed inside counts",
   "feedback": "This answer is wrong — you dropped the first liquid's mass from the total; everything sealed inside counts, before and after. The stick holds 13.6 g of one liquid and 4.9 g of the other: 13.6 + 4.9 = 18.5 g."
  },
  {
   "value": 8.7,
   "misconception": "you subtracted the second liquid instead of adding it — both liquids are inside the sealed stick",
   "feedback": "This answer is wrong — you subtracted the second liquid instead of adding it; both liquids are inside the sealed stick. Total mass before = total mass after: 13.6 + 4.9 = 18.5 g."
  },
  {
   "value": 13.6,
   "misconception": "you carried over the first liquid's mass alone — the total covers everything in the stick",
   "feedback": "This answer is wrong — you carried over the first liquid's mass alone; the total covers everything in the stick. The second liquid's 4.9 g counts too: 13.6 + 4.9 = 18.5 g."
  }
 ]
}
MPM-049 · medium · application · seq 8 · seed:U01-G4/pool[17] (instance freshened per must_freshen_instance) · mcq4
The figure shows the chromatogram of an orange-flavor drink's coloring. What does the chromatogram show about the coloring?
FIGURE (chromatogram · stimulus) — startLineLabel: "start line (pencil)" · waterLineLabel: "highest water level" · spots: [{"color": "orange", "position": "middle of the strip"}] · renderStyle: "single strip, one round spot, labels in-diagram"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "chromatogram",
  "startLineLabel": "start line (pencil)",
  "waterLineLabel": "highest water level",
  "spots": [
   {
    "color": "orange",
    "position": "middle of the strip"
   }
  ],
  "renderStyle": "single strip, one round spot, labels in-diagram"
 }
}
It contains a single dye. KEY
It contains two dyes.
It contains no dye.
The run failed and must be repeated.
MPM-050 · medium · application · seq 9 · authored (forward technique-pick; target technique = evaporation; option set follows James's fluency[0] pattern — no distillation shadow) · mcq4
A scoop of laundry brightening powder is dissolved in a tub of warm, clear liquid. The worker wants the brightening powder back as a dry solid, and the liquid itself can be lost. Which technique should the worker choose?
Evaporation KEY
Filtration
Paper chromatography
Letting the mixture stand until the solid settles out
MPM-050 · medium · application · seq 10 · authored · mcq4
A jeweler's cleaning bath is a liquid with cream of tartar dissolved in it. After weeks of use, fine polishing grit — a solid that never dissolves — is also stirred through the bath. The jeweler wants only the pure liquid back for reuse. Which plan recovers it?
Distill the bath — boil the liquid off, cool its gas back into a liquid, and collect it; the tartar and the grit are left behind in the heated flask. KEY
Pour the bath through filter paper so the grit is caught on the paper; the liquid dripping through below is already pure enough to reuse.
Evaporate the bath from a wide open dish — the solids settle out, and the pure liquid is left waiting in the dish to pour off.
Distill the bath, but keep what stays liquid in the heated flask — the escaping gas carries the tartar and the grit away with it.
MPM-052 · medium · application · seq 11 · authored (fresh abstract instance, parallel to the seed's structure and misconception classes) · mcq4
A dark gray powder is stirred into a green solution in a sealed jar. As they react, the green color fades and a black solid collects on the bottom. Why must the total mass after the change equal the total before?
Because the atoms are only rearranged — no atoms are created or destroyed, so the total mass stays the same. KEY
Because the black solid that collected weighs exactly what the dark gray powder weighed before.
Because the reaction destroys old atoms and creates new ones at exactly matching rates.
Because only a change that gives off a gas can alter the mass, and this change gave off no gas.
MPM-053 · medium · application · seq 12 · authored (fresh instance, parallel to the seed's structure and misconception classes) · numeric
In a sealed flask, 2.3 g of sodium reacts completely with 8.0 g of liquid bromine to form sodium bromide, the only new substance. What mass of sodium bromide forms in the flask? Give your answer in grams to one decimal place.
Answer: 10.3 g KEY
also accepted: 10.3 g
wrongValueDiagnostics
[
 {
  "value": 5.7,
  "misconception": "you subtracted the masses — both starting substances end up inside the new substance, so add them",
  "feedback": "This answer is wrong — you subtracted the masses — both starting substances end up inside the new substance, so add them"
 },
 {
  "value": 2.3,
  "misconception": "you carried over the sodium's mass alone — the bromine's atoms are in the sodium bromide too",
  "feedback": "This answer is wrong — you carried over the sodium's mass alone — the bromine's atoms are in the sodium bromide too"
 },
 {
  "value": 8.0,
  "misconception": "you carried over the bromine's mass alone — the sodium's atoms are in the sodium bromide too",
  "feedback": "This answer is wrong — you carried over the bromine's mass alone — the sodium's atoms are in the sodium bromide too"
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nmass of sodium = 2.3 g\nmass of bromine = 8.0 g\nWrite down the equation:\ntotal mass before = total mass after\nIn this problem's substances:\nmass of sodium before + mass of bromine before = mass of sodium bromide after\nMake the mass of sodium bromide the subject:\nmass of sodium bromide = mass of sodium + mass of bromine\nSubstitute in the values, and calculate:\nmass of sodium bromide = 2.3 + 8.0\nmass of sodium bromide = 10.3 g\nSanity check: the answer must exceed each starting mass, and 10.3 g does.",
 "anticipatedWrong": [
  {
   "value": 5.7,
   "misconception": "you subtracted the masses — both starting substances end up inside the new substance, so add them",
   "check": {
    "expr": "8.0-2.3",
    "expected": 5.7
   },
   "feedback": "This answer is wrong — you subtracted the masses — both starting substances end up inside the new substance, so add them"
  },
  {
   "value": 2.3,
   "misconception": "you carried over the sodium's mass alone — the bromine's atoms are in the sodium bromide too",
   "check": {
    "expr": "2.3",
    "expected": 2.3
   },
   "feedback": "This answer is wrong — you carried over the sodium's mass alone — the bromine's atoms are in the sodium bromide too"
  },
  {
   "value": 8.0,
   "misconception": "you carried over the bromine's mass alone — the sodium's atoms are in the sodium bromide too",
   "check": {
    "expr": "8.0",
    "expected": 8.0
   },
   "feedback": "This answer is wrong — you carried over the bromine's mass alone — the sodium's atoms are in the sodium bromide too"
  }
 ]
}
MPM-053 · medium · application · seq 13 · authored · numeric
Heated in a sealed glass tube, 6.3 g of orange ammonium dichromate crystals break down into 3.8 g of a dark-green solid, a vapor that condenses into 1.8 g of liquid on the cool upper glass, and one last gas. What mass of that last gas is in the tube at the end? Give your answer in grams to one decimal place.
Answer: 0.7 g KEY
also accepted: .7
wrongValueDiagnostics
[
 {
  "value": 2.5,
  "misconception": "you subtracted only the solid — subtract every known substance formed, the condensed liquid included",
  "feedback": "This answer is wrong — you subtracted only the solid — subtract every known substance formed, the condensed liquid included"
 },
 {
  "value": 5.6,
  "misconception": "you added the known masses formed and stopped — subtract that sum from the starting mass",
  "feedback": "This answer is wrong — you added the known masses formed and stopped — subtract that sum from the starting mass"
 },
 {
  "value": 11.9,
  "misconception": "you added everything together — the substances formed must total the starting mass, not exceed it",
  "feedback": "This answer is wrong — you added everything together — the substances formed must total the starting mass, not exceed it"
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nmass of ammonium dichromate = 6.3 g\nmass of dark-green solid = 3.8 g\nmass of condensed liquid = 1.8 g\nWrite down the equation:\ntotal mass before = total mass after\nIn this problem's substances:\nmass of ammonium dichromate before = mass of dark-green solid after + mass of condensed liquid after + mass of last gas after\nMake the mass of the last gas the subject:\nmass of last gas = mass of ammonium dichromate − (mass of dark-green solid + mass of condensed liquid)\nSubstitute in the values, and calculate:\nmass of last gas = 6.3 − (3.8 + 1.8)\nmass of last gas = 6.3 − 5.6\nmass of last gas = 0.7 g",
 "anticipatedWrong": [
  {
   "value": 2.5,
   "misconception": "you subtracted only the solid — subtract every known substance formed, the condensed liquid included",
   "check": {
    "expr": "6.3-3.8",
    "expected": 2.5
   },
   "feedback": "This answer is wrong — you subtracted only the solid — subtract every known substance formed, the condensed liquid included"
  },
  {
   "value": 5.6,
   "misconception": "you added the known masses formed and stopped — subtract that sum from the starting mass",
   "check": {
    "expr": "3.8+1.8",
    "expected": 5.6
   },
   "feedback": "This answer is wrong — you added the known masses formed and stopped — subtract that sum from the starting mass"
  },
  {
   "value": 11.9,
   "misconception": "you added everything together — the substances formed must total the starting mass, not exceed it",
   "check": {
    "expr": "6.3+3.8+1.8",
    "expected": 11.9
   },
   "feedback": "This answer is wrong — you added everything together — the substances formed must total the starting mass, not exceed it"
  }
 ]
}
MPM-053 · medium · application · seq 14 · authored (unnamed substances; real basis mercury + oxygen -> mercury oxide, the classic sealed-retort red calx, ratio-true at one decimal) · numeric
Heated inside a sealed flask, a silvery liquid metal reacts completely with a colorless gas, forming 21.7 g of a bright red powder, the only new substance, from 1.6 g of the gas. What mass of the metal reacted? Give your answer in grams to one decimal place.
Answer: 20.1 g KEY
also accepted: 20.1 g
scaffold
[
 "Write down the values in the question:",
 "mass of red powder = 21.7 g",
 "mass of gas = 1.6 g",
 "Write down the equation:",
 "total mass before = total mass after",
 "In this problem's substances:",
 "mass of metal before + mass of gas before = mass of red powder after",
 "Make the mass of metal the subject:",
 "mass of metal = mass of red powder − mass of gas",
 "Substitute in the values, and calculate:",
 "mass of metal = 21.7 − 1.6",
 "mass of metal = 20.1 g"
]
wrongValueDiagnostics
[
 {
  "value": 23.3,
  "misconception": "you added instead of subtracting — the 21.7 g of red powder is the total after, so the metal is that total minus the gas",
  "feedback": "This answer is wrong — you added instead of subtracting; the 21.7 g of red powder is the total after, so the metal is that total minus the gas. 21.7 − 1.6 = 20.1 g."
 },
 {
  "value": 21.7,
  "misconception": "you gave the mass of the new substance as the answer — the metal is only part of it",
  "feedback": "This answer is wrong — you gave the mass of the new substance as the answer; the metal is only part of it. The gas's 1.6 g is in there too: 21.7 − 1.6 = 20.1 g."
 },
 {
  "value": 1.6,
  "misconception": "you repeated the gas's mass — the metal's mass is what remains of the total",
  "feedback": "This answer is wrong — you repeated the gas's mass; the metal's mass is what remains of the total. 21.7 − 1.6 = 20.1 g."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nmass of red powder = 21.7 g\nmass of gas = 1.6 g\nWrite down the equation:\ntotal mass before = total mass after\nIn this problem's substances:\nmass of metal before + mass of gas before = mass of red powder after\nMake the mass of metal the subject:\nmass of metal = mass of red powder − mass of gas\nSubstitute in the values, and calculate:\nmass of metal = 21.7 − 1.6\nmass of metal = 20.1 g",
 "anticipatedWrong": [
  {
   "value": 23.3,
   "misconception": "you added instead of subtracting — the 21.7 g of red powder is the total after, so the metal is that total minus the gas",
   "feedback": "This answer is wrong — you added instead of subtracting; the 21.7 g of red powder is the total after, so the metal is that total minus the gas. 21.7 − 1.6 = 20.1 g."
  },
  {
   "value": 21.7,
   "misconception": "you gave the mass of the new substance as the answer — the metal is only part of it",
   "feedback": "This answer is wrong — you gave the mass of the new substance as the answer; the metal is only part of it. The gas's 1.6 g is in there too: 21.7 − 1.6 = 20.1 g."
  },
  {
   "value": 1.6,
   "misconception": "you repeated the gas's mass — the metal's mass is what remains of the total",
   "feedback": "This answer is wrong — you repeated the gas's mass; the metal's mass is what remains of the total. 21.7 − 1.6 = 20.1 g."
  }
 ]
}
MPM-054 · medium · application · seq 15 · authored (fresh open-container loss account; parallel to the seeds' structure and the lesson's misconception classes) · mcq4
A freshly poured fizzy drink stands in an open glass on a balance. Bubbles keep rising through it and popping at the surface, and over an hour the reading slowly falls. Why does the reading fall?
The gas from the popped bubbles escapes into the room, and the escaping gas carries its mass away with it. KEY
Each bubble that pops destroys the gas that was inside it, so that matter is gone from existence.
A drink cannot lose mass just standing in a glass, so the balance itself must be faulty.
The fizzing turns some of the drink's matter into the sound and motion of the bursting bubbles.
MPM-055 · medium · application · seq 16 · seed:U01-G4/pool[35] (= MPM-055 gateItems[2], James curated demo_curated[8]; stem + distractor (d) + all misconception classes kept; key instance freshened vinegar-fizz -> phone-battery (see flags), distractors (b)/(c) replaced per must_freshen_instance - article's own law/theory exemplars -> fresh sunrise law + MPM-003 solid-shape rule) · mcq4
Which statement is a hypothesis?
'I think my phone's battery drains overnight because an app keeps running — closing every app at night should slow the drain.' KEY
'The moon runs through the same cycle of phases, month after month, wherever on Earth you watch it.'
'A solid keeps its own shape because its particles are locked in fixed positions and can only vibrate in place.'
'Gold is more beautiful than silver, whatever anyone says.'
MPM-044 · hard · transfer · seq 17 · authored (fresh alloy instance, parallel to the seed's structure and misconception classes) · mcq4
A low-temperature solder used to join electronic parts is a solid mixture of bismuth atoms and indium atoms mixed throughout. Which statement must be true?
The bismuth and indium each keep their own properties, and a physical change could in principle separate them. KEY
Melting the solder, which happens every time it is used, would chemically join the bismuth and indium into a compound.
The bismuth and indium atoms are chemically joined, so the solder is a new substance with neither bismuth nor indium left in it.
Separating the solder into bismuth and indium would be a chemical change, because the mixture is a solid.
MPM-048 · hard · transfer · seq 18 · authored (fresh sample + run-time instance, parallel to the seed's structure and misconception classes) · mcq4
A student dissolves an egg-decorating tablet and runs the dye mixture on a paper strip twice — once for four minutes and once for sixteen. In the longer run every spot sits higher, but the order of the spots is unchanged. Why is the order fixed?
Each dye keeps its own strength of hold on the paper, and that strength sets the order — more time moves every spot, but cannot swap them. KEY
Extra time changes which dye holds to the paper most strongly, so the order is a matter of luck.
The dyes all stopped moving after the first four minutes, so the extra time changed nothing.
A longer run usually gives the dyes enough time to trade places on the strip, and these particular dyes simply did not get that far.
MPM-052 · hard · transfer · seq 19 · authored (fresh instance, parallel to pool[24]'s structure and misconception classes) · mcq4
A sealed vial of deep violet vapor holds a few small silvery metal pellets. Kept warm, the vapor fades while red-brown crystals build up on the pellets. The vial's total mass stays constant, yet the pellets themselves get heavier. Explain.
Atoms from the vial's own vapor joined the pellets, moving mass from the vapor to the solid. KEY
The red-brown crystals created brand-new atoms as they built up on the pellets.
Heat from the gentle warming soaked into the pellets and added its mass to them.
Moisture from the room seeped in through the vial's walls and stuck to the crystals.
MPM-054 · hard · transfer · seq 20 · authored (fresh combined two-flow instance; no MPM-054 hard seed exists) · mcq4
Soft, dark gray, needle-like crystals are roasted on an open tray. All through the roasting, a gas from the surroundings joins the solid while a different gas with a choking smell streams off. By the end, the solid on the tray is white and weighs slightly less than the crystals did. Which statement correctly accounts for the mass change?
Nothing was destroyed — the gas that streamed off carried away more mass than the joining gas added, so the solid on the tray ended slightly lighter. KEY
The heat of the roasting destroyed the missing matter outright, so that mass has simply stopped existing.
Because the tray is open, this change sits outside the law of conservation of mass entirely.
A gas was joining the crystals as they roasted, so the solid must actually have gained mass and the final measurement is a mistake.
MPM-050 · medium · application · seq 21 · authored (ADJ-G4-3; fresh rotation - recover the dissolved solid AND the liquid) · frq
In a confectioner's kitchen, a pot holds a three-component mixture: ground walnut shell, a scrubbing powder that does not dissolve; isomalt, a sweetener that has dissolved completely; and the liquid both solids are in. The isomalt must be recovered clean and dry, and the pure liquid must be recovered for reuse. The walnut-shell powder is not needed and will be discarded.
In a confectioner's kitchen, a pot holds a three-component mixture: ground walnut shell, a scrubbing powder that does not dissolve; isomalt, a sweetener that has dissolved completely; and the liquid both solids are in. The isomalt must be recovered clean and dry, and the pure liquid must be recovered for reuse. The walnut-shell powder is not needed and will be discarded. (a) Plan the separation. Name the technique for each step of your plan, in the order you would carry them out. (b) Justify each step of your plan. For each technique you named, state the property difference between the components that makes it work here. (c) Track every component. State where each of the three components - the walnut-shell powder, the isomalt, and the liquid - ends up when your plan is finished, including any component that is not kept.
Part a. Plan the separation. Name the technique for each step of your plan, in the order you would carry them out.
Model: Step 1 - filtration: pour the whole mixture through filter paper. Step 2 - distillation: distill the liquid that passed through the paper.
Part b. Justify each step of your plan. For each technique you named, state the property difference between the components that makes it work here.
Model: Filtration works because the walnut shell does not dissolve - its particles are too large to pass through the filter paper's holes, while the liquid, still carrying the dissolved isomalt, passes through. Distillation is chosen for the second step because BOTH remaining components must be kept: the liquid boils away, its gas is cooled back into a liquid and collected, and the isomalt stays behind in the heated flask. An open dish would keep the isomalt but lose the liquid to the air.
Part c. Track every component. State where each of the three components - the walnut-shell powder, the isomalt, and the liquid - ends up when your plan is finished, including any component that is not kept.
Model: Walnut-shell powder - collected on the filter paper and discarded, which the goal allows. Isomalt - stays behind in the heated flask when the liquid boils away, recovered dry. The liquid - leaves as a gas, is cooled back into a liquid, and is collected in the collecting flask.
Full model answer. (a) Step 1 - filtration: pour the whole mixture through filter paper. Step 2 - distillation: distill the liquid that passed through the paper. (b) Filtration works because the walnut shell does not dissolve - its particles are too large to pass through the filter paper's holes, while the liquid, still carrying the dissolved isomalt, passes through. Distillation is chosen for the second step because BOTH remaining components must be kept: the liquid boils away, its gas is cooled back into a liquid and collected, and the isomalt stays behind in the heated flask. An open dish would keep the isomalt but lose the liquid to the air. (c) Walnut-shell powder - collected on the filter paper and discarded, which the goal allows. Isomalt - stays behind in the heated flask when the liquid boils away, recovered dry. The liquid - leaves as a gas, is cooled back into a liquid, and is collected in the collecting flask.

Form D

MPM-044 · easy · recall · seq 1 · authored · mcq4
A chef stirs flecks of dried basil into soft butter to make an herb spread; the green flecks stay visible throughout. Why can the basil and the butter still be separated from each other?
Mixing changed neither ingredient — the basil and the butter each keep their own properties, so a physical change can pull them apart. KEY
Stirring joined the basil and the butter into one new substance, and taking the spread apart reverses that change.
The basil and the butter each lose their own properties inside the spread and get them back only once they are apart.
Picking the basil flecks back out of the butter is a chemical change that re-forms the two original ingredients.
MPM-046 · easy · recall · seq 2 · authored (fresh instance, parallel to the seed's structure and misconception classes) · mcq4
An open bowl of citric acid solution — a crystalline solid dissolved in a liquid — dries out on a sunny bench over a few days. Which particles leave the bowl as it dries?
The liquid's particles only KEY
Particles of both the liquid and the dissolved citric acid
The dissolved citric acid's particles only
No particles leave the bowl
MPM-051 · easy · recall · seq 3 · authored · mcq4
A change happens inside a container that is sealed from start to finish. What does the law of conservation of mass say about the total mass of the contents?
The total mass stays the same, whether the change is physical or chemical. KEY
The total mass stays the same if the change is physical, but a chemical change lowers it slightly.
The total mass stays the same only if the container is kept at a steady temperature the whole time.
Nothing can be said about the total mass until the contents are weighed again.
MPM-055 · easy · recall · seq 4 · authored · mcq4
What is the difference between a law and a theory in science?
A law describes what always happens; a theory explains why things happen. KEY
A law explains why things happen; a theory describes what always happens.
A theory turns into a law once enough evidence piles up behind it.
A law is completely certain; a theory is a guess that has not been tested.
MPM-045 · medium · application · seq 5 · authored · mcq4
A fruit punch is made by stirring a powdered drink mix until every last grain has dissolved. The punch is then poured into a filter-paper cone. Which statement gives the result?
Nothing collects on the paper — the liquid below is still fruit punch. KEY
The drink-mix powder collects on the paper, and a plain, unflavored liquid drips through.
Only the heaviest particles of the drink mix collect on the paper; the rest pass through.
The powder collects on the paper only when the punch is poured slowly enough for the paper to catch it.
MPM-047 · medium · application · seq 6 · authored · mcq4
Raw pine resin is a solution: a solid, called rosin, dissolved in a liquid, called turpentine. The resin is distilled. Predict the result.
The turpentine collects in the collecting flask; the rosin stays behind in the heated flask. KEY
Cloudy turpentine, with the rosin still dissolved in it, collects in the collecting flask.
The rosin collects in the collecting flask and the turpentine stays behind in the heated flask.
Nothing separates, because the resin's two components leave the flask together or not at all.
MPM-051 · medium · application · seq 7 · authored · numeric
A sealed plastic pouch holds 32.4 g of frozen mango pulp and 45.9 g of a chilled fruit smoothie. The pouch sits on a counter until the frozen pulp melts completely. What is the total mass of the sealed pouch's contents after the melting? Give your answer in grams to one decimal place.
Answer: 78.3 g KEY
also accepted: 78.3 g
scaffold
[
 "Write down the values in the question:",
 "mass of mango pulp = 32.4 g",
 "mass of smoothie = 45.9 g",
 "The pouch is sealed, so the law of conservation of mass applies:",
 "total mass before = total mass after",
 "In this problem's substances:",
 "mass of mango pulp + mass of smoothie = total mass after",
 "Substitute in the values, and calculate:",
 "total mass after = 32.4 + 45.9",
 "total mass after = 78.3 g"
]
wrongValueDiagnostics
[
 {
  "value": 45.9,
  "misconception": "you dropped the frozen pulp's mass from the total — everything sealed inside counts, solid or melted",
  "feedback": "This answer is wrong — you dropped the frozen pulp's mass from the total; everything sealed inside counts, solid or melted. The pouch holds the pulp's 32.4 g and the smoothie's 45.9 g: 32.4 + 45.9 = 78.3 g."
 },
 {
  "value": 13.5,
  "misconception": "you subtracted the pulp's mass instead of adding it — both foods are inside the sealed pouch",
  "feedback": "This answer is wrong — you subtracted the pulp's mass instead of adding it; both foods are inside the sealed pouch. Total mass before = total mass after: 32.4 + 45.9 = 78.3 g."
 },
 {
  "value": 32.4,
  "misconception": "you carried over the pulp's mass alone — the total covers everything in the pouch",
  "feedback": "This answer is wrong — you carried over the pulp's mass alone; the total covers everything in the pouch. The smoothie's 45.9 g counts too: 32.4 + 45.9 = 78.3 g."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nmass of mango pulp = 32.4 g\nmass of smoothie = 45.9 g\nThe pouch is sealed, so the law of conservation of mass applies:\ntotal mass before = total mass after\nIn this problem's substances:\nmass of mango pulp + mass of smoothie = total mass after\nSubstitute in the values, and calculate:\ntotal mass after = 32.4 + 45.9\ntotal mass after = 78.3 g\nMelting is a physical change, and the law covers any physical or chemical change — sealed in, the total cannot change.",
 "anticipatedWrong": [
  {
   "value": 45.9,
   "misconception": "you dropped the frozen pulp's mass from the total — everything sealed inside counts, solid or melted",
   "feedback": "This answer is wrong — you dropped the frozen pulp's mass from the total; everything sealed inside counts, solid or melted. The pouch holds the pulp's 32.4 g and the smoothie's 45.9 g: 32.4 + 45.9 = 78.3 g."
  },
  {
   "value": 13.5,
   "misconception": "you subtracted the pulp's mass instead of adding it — both foods are inside the sealed pouch",
   "feedback": "This answer is wrong — you subtracted the pulp's mass instead of adding it; both foods are inside the sealed pouch. Total mass before = total mass after: 32.4 + 45.9 = 78.3 g."
  },
  {
   "value": 32.4,
   "misconception": "you carried over the pulp's mass alone — the total covers everything in the pouch",
   "feedback": "This answer is wrong — you carried over the pulp's mass alone; the total covers everything in the pouch. The smoothie's 45.9 g counts too: 32.4 + 45.9 = 78.3 g."
  }
 ]
}
MPM-049 · medium · application · seq 8 · authored · mcq4
The figure shows the chromatogram of the green coloring used in a mint-flavor candy. How many dyes does the coloring contain?
FIGURE (chromatogram · stimulus) — startLineLabel: "start line (pencil)" · waterLineLabel: "highest water level" · spots: [{"color": "green", "position": "high on the strip"}, {"color": "green", "position": "middle of the strip, clearly separate from the higher green spot"}, {"c… · renderStyle: "single strip, well-separated round spots, two spots deliberately the same color, labels in-diagram"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "chromatogram",
  "startLineLabel": "start line (pencil)",
  "waterLineLabel": "highest water level",
  "spots": [
   {
    "color": "green",
    "position": "high on the strip"
   },
   {
    "color": "green",
    "position": "middle of the strip, clearly separate from the higher green spot"
   },
   {
    "color": "yellow",
    "position": "low on the strip"
   }
  ],
  "renderStyle": "single strip, well-separated round spots, two spots deliberately the same color, labels in-diagram"
 }
}
Three KEY
Two
Four
One
MPM-050 · medium · application · seq 9 · authored (forward technique-pick; target technique = distillation; goal keeps the liquid, so the open-dish option is cleanly wrong) · mcq4
A greenhouse barrel holds liquid plant feed, made by dissolving a solid feed in a clear liquid. The grower needs a supply of the pure liquid, with nothing dissolved in it, for misting delicate seedlings. Which technique should the grower choose?
Distillation KEY
Evaporation in an open dish
Filtration
Paper chromatography
MPM-050 · medium · application · seq 10 · authored · mcq4
On a potting bench, a scoop of urea fertilizer and a scoop of perlite granules both tip into an open pail of a liquid. The urea dissolves completely; the perlite does not dissolve at all. The grower wants the urea back as one clean, dry solid; the perlite will be discarded. Which plan recovers the urea?
Filter out the perlite first, then gently evaporate what passed through — the urea stays behind in the dish as the liquid escapes. KEY
Distill the pail first to drive off the liquid, then pour the leftover solids through filter paper to part the urea from the perlite.
Filter twice — a first paper to catch the perlite, then a second, finer paper that catches the dissolved urea.
Evaporate the whole pail straight away — as the liquid leaves, the urea and the perlite settle into two separate layers.
MPM-052 · medium · application · seq 11 · authored (fresh abstract instance, parallel to the seed's structure and misconception classes) · mcq4
In a sealed vial, a yellow solution reacts with a colorless one, and a deep-red solid forms. Why must the total mass after the change equal the total before?
Because the atoms are only rearranged — no atoms are created or destroyed, so the total mass stays the same. KEY
Because the deep-red solid weighs exactly what the yellow solution weighed before the change.
Because any atoms destroyed in the change are always made up for by an equal number of freshly created ones.
Because a mass change would need a gas to form, and no gas formed in the vial.
MPM-053 · medium · application · seq 12 · authored (fresh instance, parallel to the seed's structure and misconception classes) · numeric
Heated in a sealed tube, 2.9 g of tin reacts completely with 12.4 g of iodine to form tin iodide, the only new substance. What mass of tin iodide forms in the tube? Give your answer in grams to one decimal place.
Answer: 15.3 g KEY
also accepted: 15.3 g
wrongValueDiagnostics
[
 {
  "value": 9.5,
  "misconception": "you subtracted the masses — both starting substances end up inside the new substance, so add them",
  "feedback": "This answer is wrong — you subtracted the masses — both starting substances end up inside the new substance, so add them"
 },
 {
  "value": 2.9,
  "misconception": "you carried over the tin's mass alone — the iodine's atoms are in the tin iodide too",
  "feedback": "This answer is wrong — you carried over the tin's mass alone — the iodine's atoms are in the tin iodide too"
 },
 {
  "value": 12.4,
  "misconception": "you carried over the iodine's mass alone — the tin's atoms are in the tin iodide too",
  "feedback": "This answer is wrong — you carried over the iodine's mass alone — the tin's atoms are in the tin iodide too"
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nmass of tin = 2.9 g\nmass of iodine = 12.4 g\nWrite down the equation:\ntotal mass before = total mass after\nIn this problem's substances:\nmass of tin before + mass of iodine before = mass of tin iodide after\nMake the mass of tin iodide the subject:\nmass of tin iodide = mass of tin + mass of iodine\nSubstitute in the values, and calculate:\nmass of tin iodide = 2.9 + 12.4\nmass of tin iodide = 15.3 g\nSanity check: the answer must exceed each starting mass, and 15.3 g does.",
 "anticipatedWrong": [
  {
   "value": 9.5,
   "misconception": "you subtracted the masses — both starting substances end up inside the new substance, so add them",
   "check": {
    "expr": "12.4-2.9",
    "expected": 9.5
   },
   "feedback": "This answer is wrong — you subtracted the masses — both starting substances end up inside the new substance, so add them"
  },
  {
   "value": 2.9,
   "misconception": "you carried over the tin's mass alone — the iodine's atoms are in the tin iodide too",
   "check": {
    "expr": "2.9",
    "expected": 2.9
   },
   "feedback": "This answer is wrong — you carried over the tin's mass alone — the iodine's atoms are in the tin iodide too"
  },
  {
   "value": 12.4,
   "misconception": "you carried over the iodine's mass alone — the tin's atoms are in the tin iodide too",
   "check": {
    "expr": "12.4",
    "expected": 12.4
   },
   "feedback": "This answer is wrong — you carried over the iodine's mass alone — the tin's atoms are in the tin iodide too"
  }
 ]
}
MPM-053 · medium · application · seq 13 · authored · numeric
Heated strongly in a closed tube, 18.9 g of manganese oxalate breaks down into a single pale-green solid and two gases: 3.7 g of one gas and 5.8 g of the other. What mass of the pale-green solid is left in the tube? Give your answer in grams to one decimal place.
Answer: 9.4 g KEY
wrongValueDiagnostics
[
 {
  "value": 15.2,
  "misconception": "you subtracted only the lighter gas — subtract every known substance formed, the heavier gas included",
  "feedback": "This answer is wrong — you subtracted only the lighter gas — subtract every known substance formed, the heavier gas included"
 },
 {
  "value": 9.5,
  "misconception": "you added the two known masses and stopped — subtract that sum from the starting mass",
  "feedback": "This answer is wrong — you added the two known masses and stopped — subtract that sum from the starting mass"
 },
 {
  "value": 28.4,
  "misconception": "you added everything together — the substances formed must total the starting mass, not exceed it",
  "feedback": "This answer is wrong — you added everything together — the substances formed must total the starting mass, not exceed it"
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nmass of manganese oxalate = 18.9 g\nmass of first gas = 3.7 g\nmass of second gas = 5.8 g\nWrite down the equation:\ntotal mass before = total mass after\nIn this problem's substances:\nmass of manganese oxalate before = mass of pale-green solid after + mass of first gas after + mass of second gas after\nMake the mass of the pale-green solid the subject:\nmass of pale-green solid = mass of manganese oxalate − (mass of first gas + mass of second gas)\nSubstitute in the values, and calculate:\nmass of pale-green solid = 18.9 − (3.7 + 5.8)\nmass of pale-green solid = 18.9 − 9.5\nmass of pale-green solid = 9.4 g",
 "anticipatedWrong": [
  {
   "value": 15.2,
   "misconception": "you subtracted only the lighter gas — subtract every known substance formed, the heavier gas included",
   "check": {
    "expr": "18.9-3.7",
    "expected": 15.2
   },
   "feedback": "This answer is wrong — you subtracted only the lighter gas — subtract every known substance formed, the heavier gas included"
  },
  {
   "value": 9.5,
   "misconception": "you added the two known masses and stopped — subtract that sum from the starting mass",
   "check": {
    "expr": "3.7+5.8",
    "expected": 9.5
   },
   "feedback": "This answer is wrong — you added the two known masses and stopped — subtract that sum from the starting mass"
  },
  {
   "value": 28.4,
   "misconception": "you added everything together — the substances formed must total the starting mass, not exceed it",
   "check": {
    "expr": "18.9+3.7+5.8",
    "expected": 28.4
   },
   "feedback": "This answer is wrong — you added everything together — the substances formed must total the starting mass, not exceed it"
  }
 ]
}
MPM-053 · medium · application · seq 14 · authored (unnamed substances; real basis ammonia + hydrogen chloride -> ammonium chloride, exact x0.2 scaling) · numeric
Two colorless gases are sealed together in a glass vessel, where they mix and react completely, forming 10.7 g of a single white solid, the only new substance, from 3.4 g of one of the gases. What mass of the other gas reacted? Give your answer in grams to one decimal place.
Answer: 7.3 g KEY
also accepted: 7.3 g
scaffold
[
 "Write down the values in the question:",
 "mass of white solid = 10.7 g",
 "mass of the known gas = 3.4 g",
 "Write down the equation:",
 "total mass before = total mass after",
 "In this problem's substances:",
 "mass of the known gas before + mass of the other gas before = mass of white solid after",
 "Make the mass of the other gas the subject:",
 "mass of the other gas = mass of white solid − mass of the known gas",
 "Substitute in the values, and calculate:",
 "mass of the other gas = 10.7 − 3.4",
 "mass of the other gas = 7.3 g"
]
wrongValueDiagnostics
[
 {
  "value": 14.1,
  "misconception": "you added instead of subtracting — the 10.7 g of white solid is the total after, so the other gas is that total minus the known gas",
  "feedback": "This answer is wrong — you added instead of subtracting; the 10.7 g of white solid is the total after, so the other gas is that total minus the known gas. 10.7 − 3.4 = 7.3 g."
 },
 {
  "value": 10.7,
  "misconception": "you gave the mass of the new substance as the answer — the other gas is only part of it",
  "feedback": "This answer is wrong — you gave the mass of the new substance as the answer; the other gas is only part of it. The known gas's 3.4 g is in there too: 10.7 − 3.4 = 7.3 g."
 },
 {
  "value": 3.4,
  "misconception": "you repeated the known gas's mass — the other gas's mass is what remains of the total",
  "feedback": "This answer is wrong — you repeated the known gas's mass; the other gas's mass is what remains of the total. 10.7 − 3.4 = 7.3 g."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nmass of white solid = 10.7 g\nmass of the known gas = 3.4 g\nWrite down the equation:\ntotal mass before = total mass after\nIn this problem's substances:\nmass of the known gas before + mass of the other gas before = mass of white solid after\nMake the mass of the other gas the subject:\nmass of the other gas = mass of white solid − mass of the known gas\nSubstitute in the values, and calculate:\nmass of the other gas = 10.7 − 3.4\nmass of the other gas = 7.3 g",
 "anticipatedWrong": [
  {
   "value": 14.1,
   "misconception": "you added instead of subtracting — the 10.7 g of white solid is the total after, so the other gas is that total minus the known gas",
   "feedback": "This answer is wrong — you added instead of subtracting; the 10.7 g of white solid is the total after, so the other gas is that total minus the known gas. 10.7 − 3.4 = 7.3 g."
  },
  {
   "value": 10.7,
   "misconception": "you gave the mass of the new substance as the answer — the other gas is only part of it",
   "feedback": "This answer is wrong — you gave the mass of the new substance as the answer; the other gas is only part of it. The known gas's 3.4 g is in there too: 10.7 − 3.4 = 7.3 g."
  },
  {
   "value": 3.4,
   "misconception": "you repeated the known gas's mass — the other gas's mass is what remains of the total",
   "feedback": "This answer is wrong — you repeated the known gas's mass; the other gas's mass is what remains of the total. 10.7 − 3.4 = 7.3 g."
  }
 ]
}
MPM-054 · medium · application · seq 15 · authored (fresh open-container loss account; parallel to the seeds' structure and the lesson's misconception classes) · mcq4
A small bottle of perfume is left open on a sensitive balance in a shop. Day after day the reading falls, while the whole shop takes on the perfume's scent. What explains the falling reading?
Perfume keeps leaving the open bottle as a gas, and the escaping gas carries its mass away with it. KEY
The scent that spreads through the shop is not matter, so nothing that has mass is leaving the bottle.
Light shining into the open bottle destroys a little of the perfume each day.
A liquid that is simply left standing cannot lose mass, so the balance must be out of adjustment.
MPM-055 · medium · application · seq 16 · authored (fresh everyday instance; classify-format hypothesis - the bare-label 'A hypothesis' key no seed exercises; misconception classes from the lesson's designed set) · mcq4
A student says: 'I think our classroom thermometer reads too high because direct sunlight hits it every afternoon — moving it to a shaded wall should lower its readings.' Classify the student's statement.
A hypothesis KEY
A theory
A law
An untestable opinion
MPM-044 · hard · transfer · seq 17 · authored (fresh alloy instance, parallel to the seed's structure and misconception classes) · mcq4
The polished metal cylinder kept near Paris that once defined the kilogram is a solid mixture of platinum atoms and iridium atoms mixed throughout. Which statement must be true?
The platinum and iridium each keep their own properties, and a physical change could in principle separate them. KEY
The platinum and iridium atoms are chemically joined, so the cylinder is made of a new substance with no platinum or iridium left in it.
Melting the cylinder would chemically join the platinum and iridium into a compound.
Separating the cylinder's metal into platinum and iridium would be a chemical change, because the mixture is a solid.
MPM-048 · hard · transfer · seq 18 · authored (fresh sample + run-time instance, parallel to the seed's structure and misconception classes) · mcq4
A student runs the same rollerball-pen ink twice — once for eight minutes and once for twenty-five. In the longer run every spot sits higher, but the order of the spots is unchanged. Why is the order fixed?
Each dye keeps its own strength of hold on the paper, and that strength sets the order — more time moves every spot, but cannot swap them. KEY
The dyes all stopped moving after the first eight minutes, so the extra time changed nothing.
Extra time changes which dye holds to the paper most strongly, so the order is a matter of luck.
A longer run usually gives the dyes enough time to trade places on the strip, and these particular dyes simply did not get that far.
MPM-052 · hard · transfer · seq 19 · authored (fresh instance, parallel to pool[24]'s structure and misconception classes) · mcq4
A bead of soft silvery metal is sealed into a bottle of dense red-brown vapor. The vapor thins while a white crystalline crust spreads over the bead. The bottle's total mass stays constant, yet the bead itself gets heavier. Explain.
Atoms from the bottle's own vapor joined the bead, moving mass from the vapor to the solid. KEY
The white crust created brand-new atoms as it spread over the bead's surface.
Heat released by the change soaked into the bead and added its mass to it.
Gas from the room slowly leaked in through the glass and joined the bead's crust.
MPM-054 · hard · transfer · seq 20 · authored (fresh combined two-flow instance; no MPM-054 hard seed exists) · mcq4
Slippery, dark gray flakes are roasted in an open pot over a strong flame. As the flakes turn into a pale powder, a gas from the surroundings combines with them while a different, sharp gas escapes. The pale powder weighs slightly less than the flakes did. Which statement correctly accounts for the mass change?
Nothing was destroyed — the escaping sharp gas removed more mass than the combining gas added, so the pot's contents ended slightly lighter. KEY
Some of the flakes' matter was destroyed by the strong heating and simply stopped existing.
The law of conservation of mass holds only for sealed containers, so it says nothing about the open pot.
The combining gas made the flakes heavier as they roasted, so the pale powder cannot really weigh less than the flakes did.
MPM-050 · medium · application · seq 21 · authored (ADJ-G4-3; fresh rotation - recover the insoluble solid AND the liquid) · frq
In a gem-cutting workshop, a tray holds a three-component mixture: garnet powder, a hard solid that never dissolves; dextrin, a binder that has dissolved completely; and the liquid both solids are in. The costly garnet powder must be recovered on its own, and the pure liquid must be recovered for reuse. The dextrin is not needed. A solid caught on the filter paper counts as recovered once it has dried there.
In a gem-cutting workshop, a tray holds a three-component mixture: garnet powder, a hard solid that never dissolves; dextrin, a binder that has dissolved completely; and the liquid both solids are in. The costly garnet powder must be recovered on its own, and the pure liquid must be recovered for reuse. The dextrin is not needed. A solid caught on the filter paper counts as recovered once it has dried there. (a) Plan the separation. Name the technique for each step of your plan, in the order you would carry them out. (b) Justify each step of your plan. For each technique you named, state the property difference between the components that makes it work here. (c) Track every component. State where each of the three components - the garnet powder, the dextrin, and the liquid - ends up when your plan is finished, including any component that is not kept.
Part a. Plan the separation. Name the technique for each step of your plan, in the order you would carry them out.
Model: Step 1 - filtration: pour the whole mixture through filter paper. Step 2 - distillation: distill the liquid that passed through the paper.
Part b. Justify each step of your plan. For each technique you named, state the property difference between the components that makes it work here.
Model: Filtration works because the garnet powder never dissolves - its particles are too large to pass through the filter paper's holes, while the liquid, still carrying the dissolved dextrin, passes through. Filtering first captures the garnet on the paper before any heating. Distillation is chosen for the second step because the liquid must be kept: the liquid boils away, its gas is cooled back into a liquid and collected, while the dissolved dextrin stays behind in the heated flask. An open dish would lose the liquid to the air.
Part c. Track every component. State where each of the three components - the garnet powder, the dextrin, and the liquid - ends up when your plan is finished, including any component that is not kept.
Model: Garnet powder - collected on the filter paper and left to dry there, recovered on its own. Dextrin - stays behind in the heated flask when the liquid boils away, and is discarded, which the goal allows. The liquid - leaves as a gas, is cooled back into a liquid, and is collected in the collecting flask.
Full model answer. (a) Step 1 - filtration: pour the whole mixture through filter paper. Step 2 - distillation: distill the liquid that passed through the paper. (b) Filtration works because the garnet powder never dissolves - its particles are too large to pass through the filter paper's holes, while the liquid, still carrying the dissolved dextrin, passes through. Filtering first captures the garnet on the paper before any heating. Distillation is chosen for the second step because the liquid must be kept: the liquid boils away, its gas is cooled back into a liquid and collected, while the dissolved dextrin stays behind in the heated flask. An open dish would lose the liquid to the air. (c) Garnet powder - collected on the filter paper and left to dry there, recovered on its own. Dextrin - stays behind in the heated flask when the liquid boils away, and is discarded, which the goal allows. The liquid - leaves as a gas, is cooled back into a liquid, and is collected in the collecting flask.

Form E

MPM-044 · easy · recall · seq 1 · authored · mcq4
Crushed almonds are stirred through a jar of honey until the nut pieces are spread evenly. Why can the almonds and the honey still be separated from each other?
Mixing changed neither food — the almonds and the honey each keep their own properties, so a physical change can pull them apart. KEY
Stirring joined the almonds and the honey into one new substance, and separating them means undoing that change.
The almonds and the honey each lose their own properties in the jar and regain them once they are taken apart.
Lifting the almond pieces back out of the honey is a chemical change that turns each food back into its original substance.
MPM-046 · easy · recall · seq 2 · authored (fresh instance, parallel to the seed's structure and misconception classes) · mcq4
A flat tray of alum solution — a solid fully dissolved in a liquid — is left near an open window and gradually evaporates. Which particles leave the tray?
The liquid's particles only KEY
Particles of both the liquid and the dissolved alum
The dissolved alum's particles only
No particles leave the tray
MPM-051 · easy · recall · seq 3 · authored · mcq4
Which of these claims is guaranteed by the law of conservation of mass?
In a closed container, the total mass stays the same during any physical or chemical change. KEY
In a closed container, the total mass stays the same until a new substance starts to form.
In a closed container, the mass of each separate substance stays the same during any physical or chemical change.
In a closed container, a change may create a little new matter, as long as none is destroyed.
MPM-055 · easy · recall · seq 4 · authored · mcq4
A hypothesis survives test after test for many years, and the evidence behind it keeps growing. What can it eventually become?
A theory, but never a law. KEY
A law, but never a theory.
First a theory, and then, with even more evidence, a law.
Nothing more — a hypothesis stays a hypothesis forever.
MPM-045 · medium · application · seq 5 · authored · mcq4
A candlemaker melts down old candle stubs; the liquid wax is flecked with charred wick bits, which do not dissolve in it. The warm liquid is run through a paper filter. What collects where?
The wick bits collect on the paper, and clear liquid wax drips through into the container below. KEY
Nothing drips through — the paper's holes are too small for any part of the mixture to pass.
The trapped wick bits slowly dissolve into the wax passing by, so the liquid below ends up flecked again.
The liquid wax is held in the paper while the wick bits wash through into the container below.
MPM-047 · medium · application · seq 6 · authored · mcq4
A fuels laboratory slowly distills a mixture of two liquids: heptane, which boils at 98 °C, and octane, which boils at 126 °C. What collects first?
Mostly heptane. KEY
Mostly octane.
Both liquids together, in their original proportions.
Nothing.
MPM-051 · medium · application · seq 7 · authored · numeric
A sealed plastic bag holds 28.4 g of the base paste of a two-part repair putty and 13.1 g of its hardener. The bag is kneaded so the two pastes mix, react, and set hard. What is the total mass of the sealed bag's contents after the change? Give your answer in grams to one decimal place.
Answer: 41.5 g KEY
also accepted: 41.5 g
scaffold
[
 "Write down the values in the question:",
 "mass of base paste = 28.4 g",
 "mass of hardener = 13.1 g",
 "The bag is sealed, so the law of conservation of mass applies:",
 "total mass before = total mass after",
 "In this problem's substances:",
 "mass of base paste + mass of hardener = total mass after",
 "Substitute in the values, and calculate:",
 "total mass after = 28.4 + 13.1",
 "total mass after = 41.5 g"
]
wrongValueDiagnostics
[
 {
  "value": 13.1,
  "misconception": "you dropped the base paste's mass from the total — everything sealed inside counts",
  "feedback": "This answer is wrong — you dropped the base paste's mass from the total; everything sealed inside counts, before and after. The bag holds the base paste's 28.4 g and the hardener's 13.1 g: 28.4 + 13.1 = 41.5 g."
 },
 {
  "value": 15.3,
  "misconception": "you subtracted the hardener instead of adding it — both pastes are inside the sealed bag",
  "feedback": "This answer is wrong — you subtracted the hardener instead of adding it; both pastes are inside the sealed bag. Total mass before = total mass after: 28.4 + 13.1 = 41.5 g."
 },
 {
  "value": 28.4,
  "misconception": "you carried over the base paste's mass alone — the total covers everything in the bag",
  "feedback": "This answer is wrong — you carried over the base paste's mass alone; the total covers everything in the bag. The hardener's 13.1 g counts too: 28.4 + 13.1 = 41.5 g."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nmass of base paste = 28.4 g\nmass of hardener = 13.1 g\nThe bag is sealed, so the law of conservation of mass applies:\ntotal mass before = total mass after\nIn this problem's substances:\nmass of base paste + mass of hardener = total mass after\nSubstitute in the values, and calculate:\ntotal mass after = 28.4 + 13.1\ntotal mass after = 41.5 g\nSetting hard is a chemical change — the new substance is made entirely from the matter already sealed inside, so the total cannot change.",
 "anticipatedWrong": [
  {
   "value": 13.1,
   "misconception": "you dropped the base paste's mass from the total — everything sealed inside counts",
   "feedback": "This answer is wrong — you dropped the base paste's mass from the total; everything sealed inside counts, before and after. The bag holds the base paste's 28.4 g and the hardener's 13.1 g: 28.4 + 13.1 = 41.5 g."
  },
  {
   "value": 15.3,
   "misconception": "you subtracted the hardener instead of adding it — both pastes are inside the sealed bag",
   "feedback": "This answer is wrong — you subtracted the hardener instead of adding it; both pastes are inside the sealed bag. Total mass before = total mass after: 28.4 + 13.1 = 41.5 g."
  },
  {
   "value": 28.4,
   "misconception": "you carried over the base paste's mass alone — the total covers everything in the bag",
   "feedback": "This answer is wrong — you carried over the base paste's mass alone; the total covers everything in the bag. The hardener's 13.1 g counts too: 28.4 + 13.1 = 41.5 g."
  }
 ]
}
MPM-049 · medium · application · seq 8 · authored · mcq4
The figure shows the chromatogram of the ink from a teal washable felt-tip pen. How many dyes does the ink contain?
FIGURE (chromatogram · stimulus) — startLineLabel: "start line (pencil)" · waterLineLabel: "highest water level" · spots: [{"color": "blue", "position": "high on the strip"}, {"color": "green", "position": "lower middle of the strip"}] · renderStyle: "single strip, two well-separated round spots, no spot on the start line, labels in-diagram"
raw spec
{
 "figureRequired": true,
 "figureShape": "stimulus",
 "figureSpec": {
  "figureType": "chromatogram",
  "startLineLabel": "start line (pencil)",
  "waterLineLabel": "highest water level",
  "spots": [
   {
    "color": "blue",
    "position": "high on the strip"
   },
   {
    "color": "green",
    "position": "lower middle of the strip"
   }
  ],
  "renderStyle": "single strip, two well-separated round spots, no spot on the start line, labels in-diagram"
 }
}
Two KEY
Three
Four
One
MPM-050 · medium · application · seq 9 · authored (inverse job-pick, instance-free; target technique = evaporation — adjudicated repeat, different task shape from C) · mcq4
Which separation job calls for evaporation rather than any other technique you have seen?
Getting a dissolved solid back from a solution when the liquid is not wanted KEY
Getting the liquid itself back from a solution, with nothing dissolved in it
Taking an insoluble powder out of a liquid so that both the powder and the liquid are kept
Working out how many colored substances are blended in one bright liquid
MPM-050 · medium · application · seq 10 · authored · mcq4
A jar in a food lab holds powdered pumice — a solid that never dissolves — stirred through a liquid that also carries dissolved fructose. A student needs the pumice back and the pure liquid too; the fructose is not needed. Which plan recovers both?
Filter out the pumice, then distill the liquid that passed through — the liquid is collected past the cooled tube and the fructose stays behind. KEY
Distill the whole jar first to collect the liquid, then pour the leftovers from the heated flask through filter paper to recover the pumice.
Filter out the pumice, then evaporate the rest from an open dish — the fructose dries in the dish, and the liquid can then be poured back off.
Filter out the pumice, then run the liquid through a second, finer paper so the dissolved fructose is caught and the liquid comes through pure.
MPM-052 · medium · application · seq 11 · authored (fresh abstract instance, parallel to the seed's structure and misconception classes) · mcq4
A deep purple solution and a colorless liquid react in a sealed tube; the purple slowly fades and a dark brown solid appears. Why must the total mass after the change equal the total before?
Because the atoms are only rearranged — no atoms are created or destroyed, so the total mass stays the same. KEY
Because the dark brown solid weighs exactly what the deep purple solution weighed before.
Because the change destroys some atoms and creates others, and the two amounts always balance exactly.
Because mass changes happen only in gas-making reactions, and this reaction made no gas.
MPM-053 · medium · application · seq 12 · authored (fresh instance, parallel to the seed's structure and misconception classes) · numeric
In a sealed container, 1.4 g of lithium reacts completely with 3.9 g of fluorine gas to form lithium fluoride, the only new substance. What mass of lithium fluoride forms in the container? Give your answer in grams to one decimal place.
Answer: 5.3 g KEY
also accepted: 5.3 g
wrongValueDiagnostics
[
 {
  "value": 2.5,
  "misconception": "you subtracted the masses — both starting substances end up inside the new substance, so add them",
  "feedback": "This answer is wrong — you subtracted the masses — both starting substances end up inside the new substance, so add them"
 },
 {
  "value": 1.4,
  "misconception": "you carried over the lithium's mass alone — the fluorine's atoms are in the lithium fluoride too",
  "feedback": "This answer is wrong — you carried over the lithium's mass alone — the fluorine's atoms are in the lithium fluoride too"
 },
 {
  "value": 3.9,
  "misconception": "you carried over the fluorine's mass alone — the lithium's atoms are in the lithium fluoride too",
  "feedback": "This answer is wrong — you carried over the fluorine's mass alone — the lithium's atoms are in the lithium fluoride too"
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nmass of lithium = 1.4 g\nmass of fluorine = 3.9 g\nWrite down the equation:\ntotal mass before = total mass after\nIn this problem's substances:\nmass of lithium before + mass of fluorine before = mass of lithium fluoride after\nMake the mass of lithium fluoride the subject:\nmass of lithium fluoride = mass of lithium + mass of fluorine\nSubstitute in the values, and calculate:\nmass of lithium fluoride = 1.4 + 3.9\nmass of lithium fluoride = 5.3 g\nSanity check: the answer must exceed each starting mass, and 5.3 g does.",
 "anticipatedWrong": [
  {
   "value": 2.5,
   "misconception": "you subtracted the masses — both starting substances end up inside the new substance, so add them",
   "check": {
    "expr": "3.9-1.4",
    "expected": 2.5
   },
   "feedback": "This answer is wrong — you subtracted the masses — both starting substances end up inside the new substance, so add them"
  },
  {
   "value": 1.4,
   "misconception": "you carried over the lithium's mass alone — the fluorine's atoms are in the lithium fluoride too",
   "check": {
    "expr": "1.4",
    "expected": 1.4
   },
   "feedback": "This answer is wrong — you carried over the lithium's mass alone — the fluorine's atoms are in the lithium fluoride too"
  },
  {
   "value": 3.9,
   "misconception": "you carried over the fluorine's mass alone — the lithium's atoms are in the lithium fluoride too",
   "check": {
    "expr": "3.9",
    "expected": 3.9
   },
   "feedback": "This answer is wrong — you carried over the fluorine's mass alone — the lithium's atoms are in the lithium fluoride too"
  }
 ]
}
MPM-053 · medium · application · seq 13 · authored · numeric
Heated strongly inside a sealed tube, 16.1 g of cobalt oxalate, a pink powder, breaks down into one gray solid and two gases, with 3.1 g of one gas and 4.8 g of the other collected. What mass of the gray solid remains at the end? Give your answer in grams to one decimal place.
Answer: 8.2 g KEY
wrongValueDiagnostics
[
 {
  "value": 13.0,
  "misconception": "you subtracted only the lighter gas — subtract every known substance formed, the heavier gas included",
  "feedback": "This answer is wrong — you subtracted only the lighter gas — subtract every known substance formed, the heavier gas included"
 },
 {
  "value": 7.9,
  "misconception": "you added the two known masses and stopped — subtract that sum from the starting mass",
  "feedback": "This answer is wrong — you added the two known masses and stopped — subtract that sum from the starting mass"
 },
 {
  "value": 24.0,
  "misconception": "you added everything together — the substances formed must total the starting mass, not exceed it",
  "feedback": "This answer is wrong — you added everything together — the substances formed must total the starting mass, not exceed it"
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nmass of cobalt oxalate = 16.1 g\nmass of first gas = 3.1 g\nmass of second gas = 4.8 g\nWrite down the equation:\ntotal mass before = total mass after\nIn this problem's substances:\nmass of cobalt oxalate before = mass of gray solid after + mass of first gas after + mass of second gas after\nMake the mass of the gray solid the subject:\nmass of gray solid = mass of cobalt oxalate − (mass of first gas + mass of second gas)\nSubstitute in the values, and calculate:\nmass of gray solid = 16.1 − (3.1 + 4.8)\nmass of gray solid = 16.1 − 7.9\nmass of gray solid = 8.2 g",
 "anticipatedWrong": [
  {
   "value": 13.0,
   "misconception": "you subtracted only the lighter gas — subtract every known substance formed, the heavier gas included",
   "check": {
    "expr": "16.1-3.1",
    "expected": 13.0
   },
   "feedback": "This answer is wrong — you subtracted only the lighter gas — subtract every known substance formed, the heavier gas included"
  },
  {
   "value": 7.9,
   "misconception": "you added the two known masses and stopped — subtract that sum from the starting mass",
   "check": {
    "expr": "3.1+4.8",
    "expected": 7.9
   },
   "feedback": "This answer is wrong — you added the two known masses and stopped — subtract that sum from the starting mass"
  },
  {
   "value": 24.0,
   "misconception": "you added everything together — the substances formed must total the starting mass, not exceed it",
   "check": {
    "expr": "16.1+3.1+4.8",
    "expected": 24.0
   },
   "feedback": "This answer is wrong — you added everything together — the substances formed must total the starting mass, not exceed it"
  }
 ]
}
MPM-053 · medium · application · seq 14 · authored (unnamed substances; real basis ethene + bromine -> 1,2-dibromoethane, the bromine addition demo, ratio-true at one decimal) · numeric
A sealed flask holds a red-brown liquid and a colorless gas. Shaken together, they react completely, forming 17.3 g of a single colorless oily liquid, the only new substance, from 2.6 g of the gas. What mass of the red-brown liquid reacted? Give your answer in grams to one decimal place.
Answer: 14.7 g KEY
also accepted: 14.7 g
scaffold
[
 "Write down the values in the question:",
 "mass of oily liquid = 17.3 g",
 "mass of gas = 2.6 g",
 "Write down the equation:",
 "total mass before = total mass after",
 "In this problem's substances:",
 "mass of red-brown liquid before + mass of gas before = mass of oily liquid after",
 "Make the mass of red-brown liquid the subject:",
 "mass of red-brown liquid = mass of oily liquid − mass of gas",
 "Substitute in the values, and calculate:",
 "mass of red-brown liquid = 17.3 − 2.6",
 "mass of red-brown liquid = 14.7 g"
]
wrongValueDiagnostics
[
 {
  "value": 19.9,
  "misconception": "you added instead of subtracting — the 17.3 g of oily liquid is the total after, so the red-brown liquid is that total minus the gas",
  "feedback": "This answer is wrong — you added instead of subtracting; the 17.3 g of oily liquid is the total after, so the red-brown liquid is that total minus the gas. 17.3 − 2.6 = 14.7 g."
 },
 {
  "value": 17.3,
  "misconception": "you gave the mass of the new substance as the answer — the red-brown liquid is only part of it",
  "feedback": "This answer is wrong — you gave the mass of the new substance as the answer; the red-brown liquid is only part of it. The gas's 2.6 g is in there too: 17.3 − 2.6 = 14.7 g."
 },
 {
  "value": 2.6,
  "misconception": "you repeated the gas's mass — the red-brown liquid's mass is what remains of the total",
  "feedback": "This answer is wrong — you repeated the gas's mass; the red-brown liquid's mass is what remains of the total. 17.3 − 2.6 = 14.7 g."
 }
]
feedback
{
 "keyExplanation": "Write down the values in the question:\nmass of oily liquid = 17.3 g\nmass of gas = 2.6 g\nWrite down the equation:\ntotal mass before = total mass after\nIn this problem's substances:\nmass of red-brown liquid before + mass of gas before = mass of oily liquid after\nMake the mass of red-brown liquid the subject:\nmass of red-brown liquid = mass of oily liquid − mass of gas\nSubstitute in the values, and calculate:\nmass of red-brown liquid = 17.3 − 2.6\nmass of red-brown liquid = 14.7 g",
 "anticipatedWrong": [
  {
   "value": 19.9,
   "misconception": "you added instead of subtracting — the 17.3 g of oily liquid is the total after, so the red-brown liquid is that total minus the gas",
   "feedback": "This answer is wrong — you added instead of subtracting; the 17.3 g of oily liquid is the total after, so the red-brown liquid is that total minus the gas. 17.3 − 2.6 = 14.7 g."
  },
  {
   "value": 17.3,
   "misconception": "you gave the mass of the new substance as the answer — the red-brown liquid is only part of it",
   "feedback": "This answer is wrong — you gave the mass of the new substance as the answer; the red-brown liquid is only part of it. The gas's 2.6 g is in there too: 17.3 − 2.6 = 14.7 g."
  },
  {
   "value": 2.6,
   "misconception": "you repeated the gas's mass — the red-brown liquid's mass is what remains of the total",
   "feedback": "This answer is wrong — you repeated the gas's mass; the red-brown liquid's mass is what remains of the total. 17.3 − 2.6 = 14.7 g."
  }
 ]
}
MPM-054 · medium · application · seq 15 · authored (fresh open-container loss account, claim-critique case; solid-to-gas change stated in the stem - see JUDGMENT CALL flag) · mcq4
A mothball hung in a wardrobe slowly shrinks away, turning straight from a solid into an invisible gas without ever melting. Weighed week by week, its mass steadily falls. A student claims the mothball's matter is being destroyed. What actually happens?
The mothball's matter leaves it as a gas, and the escaping gas carries its mass away with it — nothing is destroyed. KEY
The mothball really does turn into a gas, but a gas weighs nothing, so the vanished mass no longer exists anywhere.
The student is right — a solid that turns straight into a gas is destroyed a little at a time as it changes.
The mothball's matter is gradually changing into the energy that keeps the insects away.
MPM-055 · medium · application · seq 16 · authored (fresh everyday instance; classify-format law on an everyday surface, complementing form A's in-course statement; misconception classes from the lesson's designed set) · mcq4
Classify the statement, which matches every recorded observation: 'A stone let go anywhere on Earth falls toward the ground.'
A law KEY
A theory
A hypothesis
Not a scientific statement
MPM-044 · hard · transfer · seq 17 · authored (fresh alloy instance, parallel to the seed's structure and misconception classes) · mcq4
Flexible eyeglass frames are often bent from beta titanium, a solid mixture of titanium atoms and molybdenum atoms mixed throughout. Which statement must be true?
The titanium and molybdenum each keep their own properties, and a physical change could in principle separate them. KEY
Separating the frames' metal into titanium and molybdenum would be a chemical change, because the mixture is a solid.
The titanium and molybdenum atoms are chemically joined, so beta titanium is a new substance with no titanium or molybdenum left in it.
Melting the frames would chemically join the titanium and molybdenum into a compound.
MPM-048 · hard · transfer · seq 18 · authored (fresh sample + run-time instance, parallel to the seed's structure and misconception classes) · mcq4
A student runs the dissolved coloring from a gelatin dessert mix on a paper strip twice — once for twelve minutes and once for thirty-five. In the longer run every spot sits higher, but the order of the spots is unchanged. Why is the order fixed?
Each dye keeps its own strength of hold on the paper, and that strength sets the order — more time moves every spot, but cannot swap them. KEY
A longer run usually gives the dyes enough time to trade places on the strip, and these particular dyes simply did not get that far.
The dyes all stopped moving after the first twelve minutes, so the extra time changed nothing.
Extra time changes which dye holds to the paper most strongly, so the order is a matter of luck.
MPM-052 · hard · transfer · seq 19 · authored (fresh instance, parallel to pool[24]'s structure and misconception classes) · mcq4
A silvery metal bar is sealed in a heavy glass tube of colorless gas and heated until it glows. After cooling, the bar wears a thin coating with a yellow metallic sheen. The tube's total mass stays constant, yet the bar itself gets heavier. Explain.
Atoms from the tube's own gas joined the bar, moving mass from the gas to the solid. KEY
The yellow coating created brand-new atoms as it formed across the bar's surface.
Heat from the strong heating soaked into the bar and stayed there as extra mass.
Moisture from the room seeped in through the hot glass and soaked into the coating.
MPM-054 · hard · transfer · seq 20 · authored (fresh combined two-flow instance; no MPM-054 hard seed exists) · mcq4
A violet powder is heated strongly in a shallow, open porcelain boat until it turns deep black. Tests show that a gas from the surroundings combines with the solid during the change, while a second, odorless gas escapes. The black solid weighs slightly less than the violet powder did. Which statement correctly accounts for the mass change?
Nothing was destroyed — the odorless gas that escaped carried off more mass than the arriving gas added to the solid, so the boat's contents ended slightly lighter. KEY
The strong heating destroyed a little of the violet powder's matter, and that matter no longer exists.
A change in an open boat like this one is an exception that the law of conservation of mass cannot cover.
Since a gas kept combining with the solid as it blackened, the boat's contents should weigh more at the end, so the final weighing must be in error.
MPM-050 · medium · application · seq 21 · authored (ADJ-G4-3; fresh rotation - recover the dissolved solid only) · frq
In a leather workshop, a vat holds a three-component mixture: fine emery powder from the blade-sharpening bench, a solid that never dissolves; tannin, a powder that has dissolved completely; and the liquid both solids are in. Only the tannin must be recovered, clean and dry. Neither the emery powder nor the liquid is needed, and nothing besides the tannin should be kept.
In a leather workshop, a vat holds a three-component mixture: fine emery powder from the blade-sharpening bench, a solid that never dissolves; tannin, a powder that has dissolved completely; and the liquid both solids are in. Only the tannin must be recovered, clean and dry. Neither the emery powder nor the liquid is needed, and nothing besides the tannin should be kept. (a) Plan the separation. Name the technique for each step of your plan, in the order you would carry them out. (b) Justify each step of your plan. For each technique you named, state the property difference between the components that makes it work here. (c) Track every component. State where each of the three components - the emery powder, the tannin, and the liquid - ends up when your plan is finished, including any component that is not kept.
Part a. Plan the separation. Name the technique for each step of your plan, in the order you would carry them out.
Model: Step 1 - filtration: pour the whole mixture through filter paper. Step 2 - evaporation: gently heat the liquid that passed through the paper in an open dish until only dry tannin is left.
Part b. Justify each step of your plan. For each technique you named, state the property difference between the components that makes it work here.
Model: Filtration works because the emery powder never dissolves - its particles are too large to pass through the filter paper's holes, while the liquid, still carrying the dissolved tannin, passes through. Evaporation is chosen for the second step because the dissolved tannin must be kept and the liquid is not needed: the liquid's particles escape into the air as a gas while the tannin's particles stay behind in the dish.
Part c. Track every component. State where each of the three components - the emery powder, the tannin, and the liquid - ends up when your plan is finished, including any component that is not kept.
Model: Emery powder - collected on the filter paper and discarded, which the goal allows. Tannin - left as a dry solid in the dish when the last of the liquid has gone. The liquid - lost to the air as a gas, which the goal allows.
Full model answer. (a) Step 1 - filtration: pour the whole mixture through filter paper. Step 2 - evaporation: gently heat the liquid that passed through the paper in an open dish until only dry tannin is left. (b) Filtration works because the emery powder never dissolves - its particles are too large to pass through the filter paper's holes, while the liquid, still carrying the dissolved tannin, passes through. Evaporation is chosen for the second step because the dissolved tannin must be kept and the liquid is not needed: the liquid's particles escape into the air as a gas while the tannin's particles stay behind in the dish. (c) Emery powder - collected on the filter paper and discarded, which the goal allows. Tannin - left as a dry solid in the dish when the last of the liquid has gone. The liquid - lost to the air as a gas, which the goal allows.